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NMR are not included for these products (contained one haloalkane compound and alcohol compound). Why might NMR not be an ideal way to determine structures in a mixture? In other words, why is NMR not used to determine structure in a mixture?

Answer:

the process of carrying light

Generally, Equilibrium is defined as a state in which opposing forces or actions are balanced so that one is not stronger or greater than the other.

Concentration of CH₄ = 1.39

So X here is = -1.39 + 4 = 2.61

So concentration of,

H₂S = 8 - 2 × (2.61) = - 2. 78 M

Cs₂ = 4 - 2.61 = 1.39 M

H₂ = 8 - 4 (2.61) = -2.44 M

Concentration is defined as the amount of a substance, such as a salt, that is in a certain amount of tissue or liquid, such as blood. When less water is present in a substance it usually becomes more concentrated.

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Answer:

1.  Chloro(methylchloranuidyl)methane

2.   1-Chloro-3,3-dimethylbutane

3.  2-bromobutane

For a concentration of PBDEs in herring gull eggs, doubling time for PBDEs in this source is 0.778 yrs. The concentration in 2010 is equals to 44.16 ppm.

We have a concentration of PBDEs in herring gull eggs from the Great Lakes was about 1100 ppb in 1990.

Concentration in 2000 = 7000 ppm

= 7000 × 10³ ppb

We have to doubling time for PBDEs in this source and concentration in 2010.

Time = 10 yr

The rate constant is \(k = \frac{ 2.303 }{t} \frac{ log[a]}{log[a - x]}\),

Plugging the values, \(k = \frac{ 2.303 }{10} log( \frac{ 7000× 10³ }{1100})\)

= 0.875/yr

Doubling time = 0.69/k

= 0.778 yrs.

Now, the we determine the concentration in 2010. Let the concentration be equal x.

\(0.778 = \frac{ 2.303 }{10} log(\frac{ x}{7000 })\)

=> \(\frac{ x}{7000 \: ppm} = 10^{3.8}\)

=> x = 44.16

Hence, required value is 44.16 ppm.

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Answer:

I feel like the answer is A) true

Explanation:

you create a model to help your audience understand your complex idea. There have been models made to represent ideas that we cannot see.

The total mass of sodium chloride is 58.44 g/mol.

The mass of sodium is 22.99 g/mol.

To find the percent sodium in sodium chloride can be found by dividing the amounts.

Therefore, the percent sodium is 39%.

6.03% (m/v) solution of glucose Solution of 2.6% (m/v) nacl 5.0 m/v glucose and 0.9% m/v nacl were present.

In hemolytic anemia, red blood cells are lost more quickly than they are produced. Hemolysis is the term for the breakdown of red blood cells. Oxygen is transported throughout your body by red blood cells. You have anemia if your red blood cell count is below normal.

A blood condition known as hemolytic anemia is when your red blood cells degrade or expire more quickly than your body can produce new blood cells to replace them. People may inherit genetic disorders that lead to anemia, certain illnesses, or they may develop hemolytic anemia.

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Answer:

3 moles

Explanation:

Answer:

The final volume, occupied by the gas at 20° C (293.15 K) and 5.60 atm, is approximately 27.65 L

Explanation:

The given parameters are;

The initial volume, V₁ = 35.0 L

The initial temperature, T₁ = 25 °C = 298.15 K

The initial pressure, P₁ = 4.50 atm

The final volume, V₂ = Required

The final temperature, T₂ = 20 °C = 293.15 K

The final pressure, P₂ = 5.60 atm

From the combined gas equation, we have;

P₁·V₁/T₁ = P₂·V₂/T₂

∴ V₂ = (P₁·V₁/T₁) × T₂/P₂

By substituting the known values, we get;

V₂ = (4.50 × 35.0/298.15) × 293.15/5.60 ≈ 27.65

Therefore, the final volume, occupied by the gas at 20° C (293.15 K) and 5.60 atm, V₂ ≈ 27.65 L

Answer: By reacting with the hydrogen ions.

Explanation:

Answer:

The last one

Explanation:

Answer:

what is super hard?

Explanation:

what?

The following statements are true from the given options: Therefore, the correct option is b) 1,2 , and 3.

In the case of diluting a strong acid, it is always recommended to add acid to water because it produces less heat as compared to the addition of water to acid. The heat generated during the process can cause the solution to splash, which can lead to a harmful situation.

When the strong acids come in contact with the metal plumbing, they cause corrosion due to they produce a higher concentration of hydrogen ions.

When weak acids are exposed to air, they can produce vapors that are harmful to the eyes. These vapors can cause irritation, burning, and damage to the eyes. Some examples of weak acids are acetic acid, formic acid, and benzoic acid.

Therefore, the correct option is d) 1,3 and 4.

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The true statements are about diluting strong acids, corrosion caused by strong acids in plumbing, and the potential irritation and damage caused by vapors of weak acids. The correct option is d) 1,3 , and 4.

The true statements from the given options are:

So, the correct option is d) 1,3 , and 4.

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Answer:

2

Explanation:

The compound H2CCH2 has the condensed formula C2H4. The name of the compound is ethene. The compound is unsaturated, that is, it contains multiple bonds. The compound has a formula which fits into the general molecular formulae of alkenes (olefins) which his CnH2n.

Olefins have a double bonds between the carbon atoms. That is , the two carbon atoms in Olefins are connected via a double covalent bond. This now implies that the two carbon atoms in ethene (C2H4) are connected by two covalent bonds in the lewis structure of the molecule as is common for Olefins.

In the Lewis dot structure for \(\rm H_2CCH_2\), there is one covalent bond present between the carbon atoms. The correct answer is option c.

A dot structure is a method of depicting an atom's valence electrons by placing dots around the atomic symbol. One valence electron is represented by each dot.

In the Lewis dot structure of \(\rm H_2CCH_2\), there is one bond between the carbon atoms. This is because each carbon atom has two electrons in its valence shell, and each hydrogen atom has one electron in its valence shell.

The two carbon atoms share two electrons to form one covalent bond, and each carbon atom also shares one electron with a hydrogen atom to form two additional covalent bonds.

Therefore, the correct answer is option c. There is one bond (covalent bond) between the carbon atoms in the Lewis dot structure for \(\rm H_2CCH_2\).

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Answer: Please find answer in explanation column

Explanation:

Numbering the steps in the correct order to show how ice changes into gas, we have that

1.Ice molecules vibrate in a fixed place.

2. Ice is heated and the molecules speed up

3. The molecules gain enough kinetic energy to leave their solid form.

4.The water becomes liquid and gets hotter.

5. The molecules leave their liquid form and enter the air as a gas.

Ice is the solid form of water  which cannot freely move around in this form  so  it vibrates  about its fixed position.When heated,its molecules acquire energy and its vibration  speeds up  causing it to overcome its  binding forces (that makes it vibrate about a fixed position) and becomes mobile as it leaves its solid form to acquire a liquid state.    With continuous heating, the liquid gets hotter making the molecules vibrate more rapidly, spread out and move freely at high speeds to form Water vapour - The gaseous state of water.

Answer:

D

Explanation:

Cuz i got it wrong and this was the right answer : )

The best reaction  that would possibly make a good  airbag inflator is the reaction in which CO2 is produced.

An airbag refers to certain objects that are put into vehicles to ensure that the occupants of the vehicle do not bump against objects that are within or outside the vehicle when there is a collision.

Since a good airbag must contain substances that quickly react to produce a non-combustible gas that fills up the airbag in order to cushion the effect of a collision, the best reaction that would possibly make a good  airbag inflator is the reaction in which CO2 is produced.

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One liter of this solution could be converted into a buffer by the addition of 0.25mol NH₄Cl, and 0.12 mol HCl.

A buffer is a substance that can withstand a pH change when acidic or basic substances are added. Small additions of acid or base can be neutralized by it, keeping the pH of the solution largely constant. For procedures and/or reactions that call for particular and stable pH ranges, this is significant. The pH range and capacity of buffer solutions determine how much acid or base can be neutralized before pH changes and how much pH will vary.

A weak acid and its conjugate base, or vice versa, are combined in solution to form a buffer.

The conjugate base of ammonia (NH3), which is a weak base, is NH4+. Therefore, adding 0.25 mol of NH4Cl will change the solution into a buffer. Additionally, NH3 and HCl interact to form NH4+. Therefore, 0.12 mol of HCl added will result in NH4+. All of the NH3 is consumed by 0.25 mol HCl.

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A high specific heat tells us that it is hard to change the temperature of the substance. This means that it takes a lot of energy to raise the temperature of the substance by even a small amount.

In other words, the substance can absorb a lot of heat energy without a significant change in temperature. This property is important in many biological and environmental processes. For example, water has a high specific heat which helps to regulate the temperature of the Earth's oceans. In summary, a high specific heat is indicative of a substance that is difficult to heat up or cool down quickly.

A high specific heat tells about a substance that it is hard to change the temperature of the substance. In this context, the correct answer is option A. A high specific heat means that it takes a significant amount of energy to raise the temperature of the substance, making it more resistant to temperature changes. This property is useful in various applications, such as in temperature regulation and thermal energy storage.

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Answer:

1.053 grams of HCl.

Explanation:

1st) It is necessary to make sure that the equation is balanced:

From the balanced equation we know that 1 mole of Al(OH)3 react with 3 moles of HCl.

2nd) With the stoichiometry of the reaction and the molar mass of Al(OH)3 (78g/mol) and HCl (36.5g/mol) we can calculate the grams of HCl that can react with 0.750g:

So, 1.053 grams of HCl can react with 0.750g of Al(OH)3.

The concentration of A decreases and then levels out. Option A

In many chemical reactions, a reactant is consumed as the reaction progresses, leading to a decrease in its concentration over time. The reactant molecules are transformed into products, and as the reaction proceeds, the concentration of the reactant gradually diminishes.

At equilibrium, the concentrations of both reactants and products remain relatively constant over time, although they can coexist.

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Answer:

the balanced equation for the above reaction is as follows;

3NiCl₂ + 2K₃PO₄ ---> Ni₃(PO₄)₂ + 6KCl

stoichiometry of NiCl₂ to K₃PO₄ is 3:2

the number of NiCl₂ moles reacted - 0.0102 mol/L x 0.134 L = 0.00137 mol

according to molar ratio  

if 3 mol of NiCl₂ reacts with 2 mol of K₃PO₄

then 0.00137 mol of NiCl₂ reacts with - 2/3 x 0.00137 = 0.000911 mol of K₃PO₄

molarity of given K₃PO₄ solution - 0.205 M

there are 0.205 mol in 1000 mL  

therefore volume of 0.000911 mol - 0.000911 mol / 0.205 mol/L = 4.44 mL  

volume of K₃PO₄ needed is 4.44 mL

Answer:

The entropy and the systems surrounding it tend to increase.

Answer: The entropy in a system and its surroundings tends to increase.

Explanation:

3.3.2 Quiz: Entropy (a p e x)

a. Weight fraction of each component: n-C4H10 = 0.50, n-C5H12 = 0.30, n-C6H14 = 0.20

b. Mole fraction of each component: n-C4H10 = 0.5708, n-C5H12 = 0.2781, n-C6H14 = 0.1511

c. Mole percent of each component: n-C4H10 = 57.08%, n-C5H12 = 27.81%, n-C6H14 = 15.11%

d. Average molecular weight of the mixture: 67.95 g/mol

e. Mass density and molar density under ambient temperature and 3 bar:

  Mass density: n-C4H10 = 8.179 g/L, n-C5H12 = 8.732 g/L, n-C6H14 = 10.469 g/L, total = 8.8029 g/L

  Molar density: n-C4H10 = 0.1443 mol/L, n-C5H12 = 0.1443 mol/L, n-C6H14 = 0.1443 mol/L, total = 0.1445 mol/L

Given:

Mass composition:

n-C4H10 (n-butane): 50%

n-C5H12 (n-pentane): 30%

n-C6H14 (n-hexane): 20%

Now, let's perform the calculations:

Step 1: Weight fraction

W_n-C4H10 = 0.50

W_n-C5H12 = 0.30

W_n-C6H14 = 0.20

Step 2: Mole fraction

n-C4H10 moles = W_n-C4H10 / M_n-C4H10 = 0.50 / 58.12 = 0.0086 mol

n-C5H12 moles = W_n-C5H12 / M_n-C5H12 = 0.30 / 72.15 = 0.0042 mol

n-C6H14 moles = W_n-C6H14 / M_n-C6H14 = 0.20 / 86.18 = 0.0023 mol

Total moles = n-C4H10 moles + n-C5H12 moles + n-C6H14 moles = 0.0086 + 0.0042 + 0.0023 = 0.0151 mol

X_n-C4H10 = n-C4H10 moles / Total moles = 0.0086 / 0.0151 = 0.5708

X_n-C5H12 = n-C5H12 moles / Total moles = 0.0042 / 0.0151 = 0.2781

X_n-C6H14 = n-C6H14 moles / Total moles = 0.0023 / 0.0151 = 0.1511

Step 3: Mole percent

Mol%_n-C4H10 = X_n-C4H10 * 100% = 0.5708 * 100% = 57.08%

Mol%_n-C5H12 = X_n-C5H12 * 100% = 0.2781 * 100% = 27.81%

Mol%_n-C6H14 = X_n-C6H14 * 100% = 0.1511 * 100% = 15.11%

Step 4: Average molecular weight

M_avg = W_n-C4H10 * M_n-C4H10 + W_n-C5H12 * M_n-C5H12 + W_n-C6H14 * M_n-C6H14

      = 0.50 * 58.12 + 0.30 * 72.15 + 0.20 * 86.18

      = 29.06 + 21.65 + 17.24

      = 67.95 g/mol

Step 5: Mass density and molar density

Let's assume the temperature is 298 K.

Mass density (ρ) = (P * M_avg) / (R * T)

Molar density (ρ_m) = P / (R * T)

Mass density of n-butane:

ρ_n-C4H10 = (3 bar * 67.95 g/mol) / (0.08314 L bar/mol K * 298 K)

         = 8.179 g/L

Mass density of n-pentane:

ρ_n-C5H12 = (3 bar * 72.15 g/mol) / (0.08314 L bar/mol K * 298 K)

         = 8.732 g/L

Mass density of n-hexane:

ρ_n-C6H14 = (3 bar * 86.18 g/mol) / (0.08314 L bar/mol K * 298 K)

         = 10.469 g/L

Total mass density:

ρ_total = W_n-C4H10 * ρ_n-C4H10 + W_n-C5H12 * ρ_n-C5H12 + W_n-C6H14 * ρ_n-C6H14

        = 0.50 * 8.179 + 0.30 * 8.732 + 0.20 * 10.469

        = 4.0895 + 2.6196 + 2.0938

        = 8.8029 g/L

Molar density of n-butane:

ρ_m,n-C4H10 = 3 bar / (0.08314 L bar/mol K * 298 K)

           = 0.1443 mol/L

Molar density of n-pentane:

ρ_m,n-C5H12 = 3 bar / (0.08314 L bar/mol K * 298 K)

           = 0.1443 mol/L

Molar density of n-hexane:

ρ_m,n-C6H14 = 3 bar / (0.08314 L bar/mol K * 298 K)

           = 0.1443 mol/L

Total molar density:

ρ_m,total = X_n-C4H10 * ρ_m,n-C4H10 + X_n-C5H12 * ρ_m,n-C5H12 + X_n-C6H14 * ρ_m,n-C6H14

         = 0.5708 * 0.1443 + 0.2781 * 0.1443 + 0.1511 * 0.1443

         = 0.0825 + 0.0402 + 0.0218

         = 0.1445 mol/L

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Answer:

\({ \bf{from \: ionic \: product \: of \: water : }} \\ { \boxed{ \tt{k _{w} = [H _{3} O {}^{ + } ][OH {}^{ - } ]}}} \\ \\ { \tt{1 \times {10}^{ - 14} = (1 \times {10}^{ - 5} ) [OH {}^{ - } ]}} \\ \\ { \tt{[OH {}^{ - } ] = 1 \times {10}^{ - 9} }} \: M\)

A solution has an [H3O+] of 1 × 10−5 M the [OH−] of the solution will be 1 × 10−9 M and option C is correct.

The water is made up of H2O only and when the pH of it is 7 then the concentration of all the ions would be the same while dissociation the water will get dissociate into H+ ions and OH- ions.

The concentration of OH- ions will be

OH- = Kw {H3O+}

{H3O+} = 1 × 10−5 M.

Kw = 14

substituting the value in the equation,

OH = 14 { 1 × 10−5 M.}

OH = 1 × 10−9 M

Therefore, the solution has an [H3O+] of 1 × 10−5 M the [OH−] of the solution will be 1 × 10−9 M and option C is correct.

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Answer:

H2O: 100°C

N2O: -88.5°C

NaF: 1414°C

Explanation:

H2O is a covalent molecule with strong hydrogen bonds between its molecules, giving it a high boiling point.

N2O - Because N2O has a weaker intermolecular force than H2O, it has a lower boiling point.

NaF is an ionic compound with no covalent bonds, only electrostatic forces between its ions, and thus has the lowest boiling point of the three.

These compounds' boiling points are:

H2O: 100°C

N2O: -88.5°C

NaF: 1414°C

Answer:i forgor

Explanation:i dont remember

Answer:

Plants consume carbon dioxide and release oxygen.

Answer: Photosynthesis

Animals consume oxygen and release carbon dioxide.

Answer: Respiration

The temperature of the nitrogen gas is  33.92 Kelvin

How to solve:

To get the temperature of the nitrogen gas, we will use the ideal gas equation:

PV = nRT

where:

P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature. First, let's change the equation to account for temperature:

T = PV/(nR)

Presently, we can connect the given qualities:

The ideal gas constant, R, is 0.0821 L-atm/(mol-K), with P = 0.975 atm and V = 1.68 L and n = 0.589 mol.

Adding the following values to the equation:

T = (0.975 atm * 1.68 L) / (0.589 mol * 0.0821 L atm/(mol K)) T = 1.6332 atm L / (0.04813 L atm/(Kmol))

The nitrogen gas's temperature is 33.92 Kelvin because;

T = 1.6332 / 0.04813 K

T = 33.92 K.

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To determine which term is greater in magnitude for the vaporization of benzene at 100 ∘c and 1 atm, we would need to know the specific values of δh and tδs for benzene at those conditions.

At 100 ∘c and 1 atm, benzene will vaporize and undergo a phase change from liquid to gas. During this process, energy is required to break the intermolecular forces holding the molecules together in the liquid phase. This energy is supplied by heat, and the enthalpy change δh represents the amount of heat required to vaporize a certain amount of benzene.

On the other hand, the change in entropy tδs represents the increase in disorder or randomness during vaporization multiplied by the temperature. Entropy is a measure of the number of ways in which a system can be arranged, and the increase in entropy during vaporization indicates that the molecules in the gas phase have more freedom to move around and occupy different positions than in the liquid phase.

Now, coming back to your question, at 100 ∘c and 1 atm, both δh and tδs will be positive as energy is required to vaporize benzene and there is an increase in disorder during the process. However, it is difficult to determine which term is greater in magnitude without knowing the exact values of δh and tδs.

In general, δh tends to be larger than tδs for most substances as the energy required to break the intermolecular forces is usually larger than the increase in entropy. However, there may be cases where tδs is larger than δh, especially at higher temperatures where the increase in entropy becomes more significant.

Therefore, to determine which term is greater in magnitude for the vaporization of benzene at 100 ∘c and 1 atm, we would need to know the specific values of δh and tδs for benzene at those conditions.

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