1. A car runs into a fence, and the fence dents the car.


2. Karen drops a marble on the ground, and it rolls across the floor in a straight line.


3. Matthew lets go of a recently blown up balloon, and it flies across the room as the air escapes.


4. Pushing your baby brother on the swing makes him go higher.


5. You place a pencil on your desk, and it stays there.


Which laws of motion are each one?

Answer:

Explanation:

True

The car's acceleration while assuming no resistance. 4000 N of net force are required.

Speed and direction changes in velocity with time. When a point or object moves faster or slower along a straight line, it is said to be accelerated. Even if the speed is constant, motion on a circle accelerates because the direction is always shifting.

The pace at which displacement changes is known as velocity. The rate at which velocity changes is known as acceleration. Because it includes both magnitude and direction, velocity is a vector quantity. As acceleration is merely the rate at which velocity changes, acceleration is likewise a vector quantity.

To know more about Acceleration visit:

https://brainly.com/question/30660316

#SPJ1

The new stretch in the rod is \(\rm \(x_2 = 0.025\)\) meters or 2.5 cm.

To calculate the new amount of stretch in the rod, we can use Hooke's Law, which states that the amount of stretch in a material is directly proportional to the applied force.

Let's denote the original stretch of the rod as \(\(x_1\)\) and the reduced force as \(\(F_2 = \frac{F_1}{4}\), where \(F_1\)\) is the original force.

According to Hooke's Law, the stretch in a rod is given by the equation:

\(\[x = \frac{F \cdot L}{A \cdot E}\]\)

where:

\(\(x\)\) is the stretch,

\(\(F\)\) is the force applied,

\(\(L\)\) is the length of the rod,

\(\(A\)\) is the cross-sectional area of the rod, and

\(\(E\)\) is Young's modulus of the material.

We are given that the original stretch of the rod is 10 cm (0.1 m). Let's assume the original force applied is \(\(F_1\)\) and the original cross-sectional radius is \(\(r_1\)\). Therefore, the original cross-sectional area \(\(A_1 = \pi r_1^2\)\).

Now, the reduced force is \(\(F_2 = \frac{F_1}{4}\)\), and the new cross-sectional radius is \(\(r_2 = 3r_1\)\). Hence, the new cross-sectional area \(\(A_2 = \pi (3r_1)^2\)\).

To find the new stretch, we can set up the following proportion:

\(\[\frac{x_1}{F_1} = \frac{x_2}{F_2}\]\)

Substituting the values, we get:

\(\[\frac{0.1}{F_1} = \frac{x_2}{\frac{F_1}{4}}\]\)

Simplifying the equation, we find:

\(\[x_2 = \frac{0.1}{4}\]\)

Therefore, the new stretch in the rod is \(\rm \(x_2 = 0.025\)\) meters or 2.5 cm.

Hence, the rod will stretch by 2.5 cm when the force is reduced by a factor of 4 and the radius of the cross-sectional area is tripled.

Know more about Hooke's Law:

https://brainly.com/question/30379950

#SPJ12

Answer:

A.) 18 m/s

B.) 12 m/s

Explanation:

Given that a school bus moves at 15 m/s relative to an outside observer. If a student walks toward the front of the bus at 3 m/s relative to the bus, how fast is the student moving relative to the observer ?

Since the student direction is in the direction of the bus, the student velocity relative to the bus velocity will be:

15 + 3 = 18 m/s

Therefore, the observer will see the student moving very fast at a speed of 18 m/s

 If the same student turns around and walks to the back of the bus at 3 m/s, the student will be moving in an opposite direction. The relative velocity of the student to the observer will be 15 - 3 = 12 m/s

Therefore, the observe will see the student moving very fast at a speed of 12 m/s

the work done on the object is 20000 J.

The conversion factor from horsepower to watts is 1 hp = 746 watts.

Therefore, the Ford Shelby GT 500's horsepower of 760 hp can be converted to watts as follows:

760 hp × 746 watts/hp = 567760 watts

To convert horsepower to watts, you simply need to multiply the number of horsepower by the conversion factor of 746 watts/hp.So, the numeric answer for 760 hp in watts is 567760.

According to the work-energy principle, the work done on an object is equal to the change in kinetic energy. Mathematically, the work-energy principle can be represented as follows:

W = ΔKHere, W represents the work done on the object, and ΔK represents the change in kinetic energy of the object.

The change in kinetic energy can be calculated using the following formula:

ΔK = (1/2)mvf² - (1/2)mvi²

Here, m represents the mass of the object, vi represents the initial velocity of the object, and vf represents the final velocity of the object. In this case, the object is initially at rest (vi = 0), so the formula can be simplified to

:ΔK = (1/2)mvf²

Now, we can use the following kinematic equation to calculate the final velocity of the object:

vf² = vi² + 2ax

Here, a represents the acceleration of the object, x represents the displacement of the object, and vi represents the initial velocity of the object. Plugging in the given values, we get:

vf² = 0 + 2(10 m/s²)(30 m - 10 m)vf² = 400 m²/s²vf = 20 m/s

Now, we can plug in the values of m and vf to calculate the change in kinetic energy:

ΔK = (1/2)(100 kg)(20 m/s)²ΔK = 20000 JSo, the numeric answer for the work done on the object is 20000 J.

learn more about work done here

https://brainly.com/question/25573309

#SPJ11

Answer:

The stone thrown upward lands farther away from the building.

Explanation:

Given that,

Angle = 30° above the horizontal

Speed = 18.0 m/s

Angle = 30° below the horizontal

Suppose, Which stone lands farther away from the building ?

We need to find which stone lands farther away from the building

Using formula of range

\(R=v_{x}t\)

The horizontal velocity for the both stones is equal but the time will be different.

The time of stone thrown upward will be greater than that of downward.

Hence, The stone thrown upward lands farther away from the building.

False. According to Faraday's law of electromagnetic induction, the magnitude of the induced electromotive force (emf) in a coil is determined by the rate at which the magnetic field passing through the coil changes.

Faraday's law states that the induced emf in a coil is directly proportional to the rate of change of magnetic flux through the coil. Magnetic flux is a measure of the total magnetic field passing through a given area.

Therefore, the induced emf in a coil will be greater if there is a faster rate of change of magnetic flux, regardless of whether the magnetic field is strong or weak. It is the change in the magnetic field or the movement of the coil with respect to the magnetic field that determines the induced emf, not the absolute strength of the magnetic field alone.

So, the statement that a coil in a strong magnetic field must have a greater induced emf is false.

Learn more about magnitude here

https://brainly.com/question/30337362

#SPJ11

Answer:

Point A

Explanation:

Because it reaches maximum height

Answer:D

Explanation:

Because u have to make observation then ask a question

Answer:

Im not really sure lemme ask my friend he knows about this subject and when he gives me answer ill edit this

Explanation:

Answer:

i dont even know

Explanation:

I just dont know

The plan being discussed is called as the 'district plan'.

The plan being proposed is commonly referred to as the district plan, which would revise the way in which a state's electoral college votes are distributed. Under the current system, all of a state's electoral votes are awarded to the presidential candidate who wins the state's popular vote, with the exception of Nebraska and Maine, which award electoral votes based on both statewide and district-wide results.

Under the district plan, each state's electoral votes would be distributed by giving one vote to the candidate who wins a plurality of the vote in each congressional district and two votes to the winner of the statewide popular vote. This would mean that in states with multiple congressional districts, the electoral votes would be split between the candidates based on the results of each district's election.

The proposed plan is intended to make the electoral college more reflective of the popular vote in each state, rather than awarding all of a state's electoral votes to a single candidate based on the statewide popular vote.

Click the below link, to learn more about District plan:

https://brainly.com/question/14395198?

#SPJ11

It is not necessary to turn the heater on when the motor runs at full load as  the rate at which the motor dissipates heat is greater than the rate at which the room is heated.

Let us first compute the electrical energy in to electrical energy out using the efficiency of the motor:

Efficiency = Electrical energy out / Electrical energy in

88/100 = Electrical energy out / Electrical energy in

Electrical energy out = (88/100) × Electrical energy in

Electrical energy in = Shaft power output of the motor = 20 kW

So, electrical energy out = (88/100) × 20 = 17.6 kW

P = Electrical energy in - Electrical energy out

P = 20 - 17.6 = 2.4 kW

The heat dissipated by the motor to the room is the difference between the electrical energy in and the shaft power output. Therefore, the rate at which the motor dissipates heat to the room it operates in at full load is 2.4 kW.

During winter, the room is heated by a 2 kW resistance heater. Since the rate at which the motor dissipates heat is greater than the rate at which the room is heated, it is not necessary to turn the heater on when the motor runs at full load.

An electric motor has a shaft power output of 20 kW and an efficiency of 88%. The rate at which the motor dissipates heat to the room it operates in at full load is 2.4 kW.

During winter, the room is heated by a 2 kW resistance heater. Since the rate at which the motor dissipates heat is greater than the rate at which the room is heated, it is not necessary to turn the heater on when the motor runs at full load.

To learn more about heater, refer below:

https://brainly.com/question/11863285

#SPJ11

Answer:

30N is the correct answer

When an airplane travels 640 miles from Topeka to Houston in 3. 2 hours, going against the wind. The return trip is with the wind and takes only 2 hours. Then the rate of the airplane with no wind is 260 miles/hr, and the rate of the wind is 100 miles/hr

Let Va is the velocity of the airplane

Va is the velocity of the wind

When flying against the wind then

(Va+Vw)*(3.2 hours) = 640

3.2Va + 3.2Vw = 640

3.2Vw = 640 - 3.2Va

Vw = 200 - Va----------------(1)

When flying with the wind:

(Va-V)*(2 hours) = 640km

2Va - 2Vw = 640

Va - Vw = 320 ----------------(2)

Putting the value of VW in equation (2) we get

Va - (200-Va) = 320

2Va = 320 +200

2Va = 520

Va = 260

Putting this value in equation (2)

Vw =Va - 360

Vw = 100

Therefore the rate of the airplane with no wind is 260 miles/hr, and the rate of the wind is 100 miles/hr

Learn more about rates:

https://brainly.com/question/26046491

#SPJ4

If a child tries to stand on the right hand end of the plank. the maximum mass of the child that can stand on the right-hand end of the plank without tipping it over is 60 kg.

In order for the plank to remain at rest, the torques on the plank must balance. The torque due to the weight of the plank can be calculated as:

τ_plank = (1/2)Mg*L

where g is the acceleration due to gravity.

Since the sawhorses are located at equal distances from the center of the plank, the torque due to the weight of the plank is evenly distributed between them, and each sawhorse must support half of the weight of the plank:

F_plank = (1/2)Mg

where F_plank is the force that each sawhorse must exert on the plank.

When the child stands on the right-hand end of the plank, they will create an additional torque on the plank. The magnitude of this torque can be calculated as:

τ_child = F_child * (L/2)

where F_child is the force that the child exerts on the plank, and L/2 is the distance from the child to the center of the plank.

For the plank to remain at rest, the torque due to the child's weight must be balanced by the torque due to the sawhorse forces:

τ_child = τ_sawhorses

F_child * (L/2) = F_plank * D

Substituting the expressions for F_plank and τ_plank, we get:

F_child * (L/2) = (1/2)Mg*D

Solving for the maximum mass of the child, we get:

M_child = 2*F_child/g

M_child = 2*(L/2)F_plank/(gD)

M_child = LF_plank/(gD)

Substituting the values for L, M, D, and g, we get:

M_child = (6 m)(1/2)(90 kg9.81 m/s^2)/(1.5 m9.81 m/s^2)

M_child = 180/3

M_child = 60 kg

Therefore, the maximum mass of the child that can stand on the right-hand end of the plank without tipping it over is 60 kg.

Learn more about maximum mass here:https://brainly.com/question/29770054

#SPJ1

When the Earth was primarily liquid, it separated into layers. The density of Earth's different layers may be predicted. For instance, it is assumed that the outermost layer, or crust, is less dense than the inner layers.

The Earth's crust is mostly composed of silicates (such as quartz, feldspar, and mica) and rocks, which are less dense than the mantle, core, or outer core.

The mantle is composed of solid rock, which is denser than the Earth's crust.

The core is the most dense layer, and it is composed of a liquid outer core and a solid inner core.

Most of the Earth's layers are composed of different types of rock and minerals.

The layers were formed from the molten material that cooled and solidified.

The Earth's layers are divided into four groups, or spheres, that represent different levels of density.

The lithosphere is the outermost layer, which includes the crust and upper mantle.

The asthenosphere is the soft layer beneath the lithosphere.

The mantle is a solid layer that surrounds the core.

The core is the Earth's central layer, consisting of a liquid outer core and a solid inner core.

For more questions on density

https://brainly.com/question/28853889

#SPJ8

Answer: -2.5

Explanation:

1/2(-5)= -2.5

-2.5(1)= -2.5

Got it right in Khan Academy. You’re welcome.

A 2500-lb vehicle has a drag coefficient of 0.31 and a frontal area of 20 ft2, and the minimum tractive effort  = 214.051 lb.

To find the minimum tractive effort,

Vehicle weight  is 2500 lb

Drag coefficient is 0.31

Frontal area 20 ft^2

Vehicle speed is 50 mi/hr = 73.33 ft/sec

Gradient - 5%

Air density = 0.002045 slugs/ft^3

Drag force is a type of fluid force that opposes the motion of an object moving through a fluid (liquid or gas). It is a frictional force that acts in the direction opposite to the velocity of the object.

The magnitude of the drag force depends on several factors, including the velocity of the object, the density of the fluid, the cross-sectional area of the object, and the shape of the object.

In aerodynamics, drag force is a major factor in the design and performance of aircraft, as it can significantly affect the lift-to-drag ratio, fuel efficiency, and overall speed of the aircraft.

Drag force is given as,

Fd = 1/2CdρAV²

=  0.5× 0.31 × 0.002045× 20× 88²

= 49.093 lb.

Force due to vehicle weight,

Fw = 0.01 ( 1+ υ/147)W

= 0.01 ( 1 + 88/147) 2500

= 39.965 lb.

Force due to gradient

Fg = W × g

= 2500 × 0.05

= 125 lb

Minimum tractive effort

F = Fd + Fw +Fg

= 49.093 + 39.965 + 125

= 214.051 lb

Therefore, A 2500-lb vehicle has a drag coefficient of 0.31 and a frontal area of 20 ft2, and the minimum tractive effort  = 214.051 lb.

To know more about drag force refer to:

brainly.com/question/13512865

#SPJ4

Answer:

Longitudinal waves

Explanation:

With sound waves, the energy travels along in the same direction as the particles vibrate. This type of wave is known as a longitudinal wave , so named because the energy travels along the direction of vibration of the particles.

LL Bean shifted from collecting structured data to unstructured data because the volume of data collected over time remained consistent.

Collecting structured data typically involves organizing and storing data in a predefined format, such as a data warehouse. However, LL Bean's decision to shift to unstructured data suggests that their existing data warehouse, which is likely designed for structured data, may not have been capable of efficiently handling the increasing volume of data collected over time.

Unstructured data, on the other hand, does not adhere to a specific format and can accommodate a larger and more diverse range of data types, allowing LL Bean to effectively manage the growing volume of data they were collecting.

Please note that the provided options A and B are not directly relevant to the reason stated for LL Bean's shift to unstructured data.

Learn more about the shift from structured to unstructured data here:

brainly.com/question/28333364

#SPJ11

Answer: 5.44 m/s

Explanation:

Given:

Mass of cart: 160 kg

Momentum of cart: 870 kg•m/s

\($$Momentum $|\rho|=m \times v$$$\begin{aligned}&870 \ kg\cdot m/s=160 \mathrm{~kg} \times v \\&v=5.44 \mathrm{~m} / \mathrm{s}\end{aligned}$$\)

Answer:

The momentum is defined as :

P=mv

Where m is the mass and v is the velocity. In this case we know the mass is 160 kg and the momentum is 870 kg plugging in this equation above and solving for the velocity we have

870=160V

V=870÷160

V=5.44

Therefore, the velocity of the cart is 5.44 m/s.

Hi there!

1. Both forces are in the SAME direction, so:

25 N + 25 N = 50 N

2. The forces are in opposite directions, so:

20 N to the right (+) and 20 N to the left (-)

20 N - 20 N = 0 N

3. The forces are in opposite directions, so:

20N to the right (+) and 30 N to the left (-)

20 N - 30 N = -10 N

Answer:

4 Ohms

Explanation:

Apply the formula:

Voltage = I (current) . Resistance

You can change it the way you want to use for your purpose.

In this case...

R = V/I

R = 12/3

R = 4 Ohms (Ohm is the unit of measurement of eletrical resistance)

The production function will have constant returns to scale if 2αβ = 1

Constant returns to scale (CRS) implies that if all inputs increase by a factor of λ, the output increases by λ as well. The requirement for constant returns to scale (CRS) in a Cobb-Douglas production function with a new input factor is given by the sum of exponents on all variables equal to 1.

In this case, Y = AKαLβMγ.

Thus, we have that α + β + γ = 1 for constant returns to scale in K, L, and M, because the sum of the exponents is 1.

If the sum of the exponents is less than 1, it indicates decreasing returns to scale. If the sum of the exponents is greater than 1, it indicates increasing returns to scale. If we take γ = 0, we obtain the production function used in class, which is Y = AKαLβ, thus α + β = 1 for constant returns to scale in K and L.

When γ = 0, the answer we get is consistent with what we learned in class. Now, we consider the constant elasticity of substitution (CES) technology, where Y = [aKα + bLα]β. The production function will have constant returns to scale (CRS) in K and L if the sum of the exponents of K and L is equal to 1.

Therefore, αβ + αβ = 1, implying 2αβ = 1.

Learn more about  production function from the given link:

https://brainly.com/question/13755609

#SPJ11

The charge is inversely proportional to the potential differential and capacitance, the charge on the capacitor stays constant.

If we push the plates of a parallel plate capacitor together so that the distance between them is halved, the charge on the capacitor does not change. This is because the charge on the capacitor is directly proportional to the potential difference across its plates and the capacitance of the capacitor. The capacitance of a parallel plate capacitor is given by:

C = εA/d

where ε is the permittivity of the material between the plates, A is the area of each plate, and d is the distance between the plates. If we reduce the distance between the plates by a factor of 2, the capacitance of the capacitor increases by a factor of 2, according to the above equation. However, the potential difference across the plates remains constant since the capacitor is connected to a battery that produces a constant potential difference.

Therefore, the charge on the capacitor remains the same, as the charge is directly proportional to the potential difference and capacitance.

To learn more about capacitor click here :

brainly.com/question/17176550

#SPJ4

The differences between 'Otto' and 'Diesel' cycles is Compression ratio, Intake process, Ignition process, Expansion process and Exhaust process.

The thermodynamic cycles Otto and Diesel both describe how internal combustion engines work. The primary variations are as follows:

For such more question on Diesel:

https://brainly.com/question/21890885

#SPJ11

Answer: the velocity is -2

Explanation: good luck don't think its wrong everyone calls me the human calculator

The weight of a sheet of aluminum that is 36" long, 24" wide, and thick would be 7.776 lbs.

We need to first find the volume of the aluminum sheet in cubic inches, and then use its density to calculate its weight.

The volume of the aluminum sheet can be calculated as:

V = l x w x h = 36 in x 24 in x 0.1 in = 86.4 cubic inches

where l is the length, w is the width, and h is the thickness of the sheet.

The density of aluminum is 0.090 lb/in^3, as given in the problem.

Therefore, the weight of the aluminum sheet can be calculated as:

W = V x density = 86.4 cubic inches x 0.090 lb/in^3 = 7.776 lbs

Therefore, the weight of the aluminum sheet is 7.776 lbs.

More on aluminum can be found here: https://brainly.com/question/9496279

#SPJ1