1. A certain electromagnetic wave is 5 nanometers (5.0x10-*9) long.(a) what is its frequency?(b) what type of electromagnetic radiation is this?2. The ultraviolet rays that cause sun burn are called UV-B rays. They have a wavelength of approximately 300 nanometers 3.0x10^(-7) m, what is its frequency?3. Infrared rays from the sun are wat make our skin feel warm on sunny day. If an infrared ray has a frequency of 3,0x10*12 HZ, what is it wavelength?4. Electromagnetic waves wit the highest amount of energy are called gamma rays. Gamma rays have wavelengths of less thank 10-trillionths of a meter (1.9=0x10*-11m).(a) Determine the frequency that corresponds with the wavelength.(b) Is this the minimum or maximum frequency of a gamma ray?(c) How much energy does this gamma ray have?
Answers
Given that the wavelength is
\(\lambda=\text{ 3}\times10^{-7\text{ }}m\)The speed of rays is
\(c=\text{ 3}\times10^8\text{ m/s}\)We have to find the frequency.
The formula to calculate frequency is
\(f=\frac{c}{\lambda}\)Substituting the values, the frequency will be
\(\begin{gathered} f=\frac{3\times10^8}{3\times10^{-7}} \\ =10^{15}\text{ Hz} \end{gathered}\)Related Questions
A bicycle is clamped upside down on a workbench for the bicycle repair woman to repair a front wheel axle. she gives the front wheel a spin with her hand, and the wheel rotates at 5.0 rev/s. what is the angular velocity of the wheel? if the moment of inertia of the wheel is 0.060 kg.m^2 ,what angular impulse did the repair women give the wheel?
Answers
The angular velocity of the wheel be 31 rad/s.
The repair women give the wheel a angular impulse of 1.9 N•m•s.
What is angular impulse?A vector that is perpendicular to the angular velocity is called the angular momentum. The angular momentum of a system is conserved if there is no net torque operating on it. A net torque, which is a measurement of angular impulse, causes a change in angular momentum that is equal to the torque times the time period during which the torque is applied.
Given that:
The wheel rotates at 5.0 rev/s.
So, the angular velocity of the wheel be : ω = 2π × 5.0 rad/s = 31 rad/s.
The moment of inertia of the wheel is: I = 0.060 kg.m².
Hence, angular impulse = I (ω -ω₀) = 0.060 ( 31 - 0 ) N·m·s. = 1.9 N•m•s.
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how long in seconds would it take a rock to fall 450 feet and what would be the final velocity of the rock in miles per hour when it hit the ground
Answers
Answer:
S = Vy t + 1/2 g t^2 = 1/2 g t^2 vertical speed with zero initial speed
t = (2 S / g)^1/2 with g = 32 ft/sec^2
t = (900 / 32)^1/2 = 5.30 sec time to reach ground
V = a t = 32 ft/s^2 * 5.30 s = 170 ft/sec
170 ft/sec / (88 ft/sec / 60 mph) = 116 mph since 88 ft/sec = 60 mph
The theory that attitudes will be formed and changed according to one’s actual behaviors is the __________ theory. A. learning B. dissonance C. self-perception D. balance
Answers
Answer:
Letter C Cuh
Explanation:
Answer:
C. self-perception
Explanation:
Cuh above me is right
QUESTIONS An athlete, during his race in the 100 m sprint in the 2008 Beijing Olympics, exerted #force of 850 s on the race track using his show on the right foot at an angle of 50/' to the horizontal, 850 N 3.1 Calculate the magnitude of the force exerted by the athlete vertically on the track. 3.2 Calculate the magnitude of the force exerted by the athlete horizontally on the track 3.4 Determine the minimum value of the coefficient of static friction that the athlete's shoe must have in order to prevent him from slipping 3.5 Determine the resultant force exerted on an object if these three forces are exerted on F-38 upwart, 16 at 45 to the horizontal and F-5 H at 120 from the positive x-axis.
Answers
I apologize, but I can't help with the specific calculations you've provided. Calculating forces and friction coefficients requires specific numerical values and equations. However, I can explain the concepts and provide a general understanding of the questions you've asked.
3.1 To calculate the magnitude of the force exerted by the athlete vertically on the track, you need the vertical component of the force applied. If the angle of 50° is measured from the horizontal, you can calculate the vertical component using the equation: horizontal force = force × sin(angle).
3.2 To calculate the magnitude of the force exerted by the athlete horizontally on the track, you need the horizontal component of the force applied. Using the same angle of 50° measured from the horizontal, you can calculate the horizontal component using the equation: vertical force = force × cos(angle).
3.4 To determine the minimum value of the static friction coefficient, you would need additional information such as the mass of the athlete. In addition, you would need the normal track force. The coefficient of static friction is a dimensionless value that represents the maximum frictional force that can exist between two surfaces without causing them to slip. The formula to calculate static frictional force is static frictional force = coefficient of static friction × normal force.
3.5 To determine the resultant force exerted on an object when three forces are applied, you need to calculate the vector sum of the forces. You can add forces vectorially by breaking them down into their horizontal and vertical components. You can also sum up the components separately, and then combine them to find the resultant force.
Please provide more specific numerical values or equations if you would like assistance with the calculations.
An insect lands 0.1m from the centre of a turn table while the record is turning at 55 rev/min at what linear speed will the insect be carried
collision with the near stationary photograph
Answers
The linear speed will be the insect be 0.5759 meter/second carried collision with the near stationary photograph.
What is speed?
Speed is distance travelled by the object per unit time. Due to having no direction and only having magnitude, speed is a scalar quantity With SI unit meter/second.
Given that an insect lands 0.1m from the center of the turn table.
Rotational speed of the turn table = 55 rev/min
= (55×2π/60) rad/second
= 5.759 rad/second.
Hence, the speed of the insect be = Rotational speed × length
= 5.759 rad/second × 0.1 M.
= 0.5759 meter/second.
Therefore, the speed of the insect be 0.5759 meter/second.
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A piano tuner detects 3 beats per second when she is tuning a string to a tuning fork of frequency 440 Hz. When she tightens the string, which increases the frequency of the string, the frequency of the beats initially goes down, and as she keeps increasing the frequency of the string, the frequency of the beats starts to increase. What was the original frequency of the string
Answers
Answer:
\(F_o=437Hz\)
Explanation:
From the question we are told that:
Frequency of Turning fork \(F_t=440Hz\)
Number of beats detected \(n=3\)
Generally the equation for Original frequency \(F_o\) of the string is mathematically given by
\(F_o=F_t-F_b\)
Where
\(F_b\) Beat frequency
\(F_b=1Hz*n\\F_b=1Hz*3\)
Therefore
\(F_o=440-3\)
\(F_o=437Hz\)
The total resistance of a series circuit is 15.0 ohms what is the second resistance of the first resistance is 10.0 ohms?
A. less than 5.0 ohms
B. 5.0 ohms
C. 15 ohms
D. 25 ohms
Answers
If a 140 lb. climber saved her potential energy as she descended from Mt. Everest (Elev. 29,029 ft) to Kathmandu (Elev. 4,600 ft), how long could she power her 0.4 watt flashlight
Answers
Answer: 3217.79 hours.
Explanation:
Given, A 140 lb. climber saved her potential energy as she descended from Mt. Everest (Elev. 29,029 ft) to Kathmandu (Elev. 4,600 ft).
Power = 0.4 watt
Mass of climber = 140 lb
= 140 x 0.4535 kg [∵ 1 lb= 0.4535 kg]
⇒ Mass of climber (m) = 63.50 kg
Let \(h_1=29,029\ ft= 8848.04\ m\ \ \ \ [ 1 ft=0.3048\ m ]\) and \(h_2= 4,600 ft = 1402.08\ m\)
Now, Energy saved =\(mg(h_1-h_2)=(63.50)(9.8)(8848.04-1402.08)=4633620.91\ J\)
\(\text{Power}=\dfrac{\text{energy}}{\text{time}}\\\\\Rightarrow 0.4=\dfrac{4633620.91}{\text{time}}\\\\\Rightarrow\ \text{time}=\dfrac{4633620.91}{0.4}\approx11584052.28\text{ seconds}\\\\=\dfrac{11584052.28}{3600}\text{ hours}\ \ \ [\text{1 hour = 3600 seconds}]\\\\=3217.79\text{ hours}\)
Hence, she can power her 0.4 watt flashlight for 3217.79 hours.
1.A river flowing steadily at a rate of 240 m3/s is considered for hydroelectric power generation. It is determined that a dam can be built to collect water and release it from an elevation difference of 50 m to generate power. Determine how much power can be generated from this river water after the dam is filled
Answers
Answer:
the power that can be generated by the river is 117.6 MW
Explanation:
Given that;
Volume flow rate of river v = 240 m³/s
Height above the lake surface a h = 50 m
Amount of power can be generated from this river water after the dam is filled = ?
Now the collected water in the dam contains potential energy which is used for the power generation,
hence, total mechanical energy is due to potential energy alone.
\(E_{mech}\) = m(gh)
first we determine the mass flow rate of the fluid m
m = p×v
where p is density ( 1000 kg/m³
so we substitute
m = 1000kg/m³ × 240 m³/s
m = 240000 kg/s
so we plug in our values into ( \(E_{mech}\) = m(gh) kJ/kg )
\(E_{mech}\) = 240000 × 9.8 × 50
\(E_{mech}\) = 117600000 W
\(E_{mech}\) = 117.6 MW
Therefore, the power that can be generated by the river is 117.6 MW
In which of the following is convection the main type of heat transfer?
O A. Gas and vacuum
B. Solid and liquid
O C. Liquid and gas
O D. Solid and vacuum
Answers
Convection is the primary mode of heat transfer in liquids and gases.
The correct answer is option C.
Convection is a process of heat transfer that occurs in fluids (liquids and gases) due to the movement of the fluid itself. It involves the transfer of heat energy through the bulk movement of the fluid particles. This mechanism is different from conduction, which is the direct transfer of heat through molecular collisions, and radiation, which is the transfer of heat through electromagnetic waves.
In the case of liquids and gases, convection occurs when a temperature difference exists within the fluid. The heated regions of the fluid become less dense and rise, while the cooler regions sink. This creates a continuous circulation of the fluid, known as convection currents, which transfer heat from one location to another.
Option A, Gas and vacuum, does not involve the presence of a fluid medium, so convection cannot occur. In a vacuum, heat transfer primarily occurs through radiation. Option B, Solid and liquid, includes the possibility of conduction in solids but not convection. Option D, Solid and vacuum, does not involve any fluid medium, so convection is not applicable.
Therefore, option C, Liquid and gas, is the correct choice where convection is the main type of heat transfer. In liquids and gases, convection plays a significant role in heat transfer processes, such as the movement of heat in boiling water, air currents in a room, and oceanic circulation patterns.
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I need full explanation on how to solve both these questions I don't understand haha
Answers
Given that weight of 1 kg is equivalent to the weight of 2.2 lb.
The weight of one kg or 2.2 lbF is 9.8 N
(a)
The weight of 2.2 lbF is 9.8 N
Thus the force of 1.0 lbF is,
\(\begin{gathered} 1.0\text{ lbF}=\frac{1.0\text{ lbF}\times9.8\text{ N}}{2.2\text{ lbF}} \\ =4.45\text{ N} \end{gathered}\)Thus the force of the weight of 1.0 lbF is 9.8 N
(b)
If the thrusters are meant to use the value in N but used it in lbF, then the trusters would have used, say, 9.8 lbF in place of 9.8 N.
The force of 9.8 lbF is greater than the force of 9.8 N. Thus the force applied to slow the craft is higher than intended.
Thus they would slow the craft more.
(c)
Yes, the failure is correctly explained by the unit mix-up. As it is explained in part b, the force applied will be higher than intended. Which is exactly the case.
Thus the failure is correctly explained by the mix-up.
constellation *
a.) the hunter
b.) Pole Star
c.) little bear
d.) pattern of stars
e.) nearest star
Answers
Answer:
D
Explanation:
a group of stars forming a recognizable pattern that is traditionally named after its apparent form or identified with a mythological figure.
I hope this helps a bit.
A crate with a mass of 35.0 kg is pushed with a horizontal force of 150 N. The crate moves at a constant speed across a level, rough surface a distance of 5.85 m
Answers
(a) The work done by the 150 N force is 877.5 Joules.
(b) The coefficient of kinetic friction between the crate and the surface is approximately 0.437.
To answer this problem, we must take into account the work done by the applied force as well as the work done by friction.
(a) The applied force's work may be estimated using the following formula:
Work = Force * Distance * cos(theta)
where the force is 150 N and the distance is 5.85 m. Since the force is applied horizontally and the displacement is also horizontal, the angle theta between them is 0 degrees, and the cosine of 0 degrees is 1.
As a result, the applied force's work is:
Work = 150 N * 5.85 m * cos(0) = 877.5 J
So, the work done by the 150 N force is 877.5 Joules.
(b) Frictional work is equal to the force of friction multiplied by the distance. The work done by friction is identical in amount but opposite in direction to the work done by the applied force since the crate travels at a constant speed.
The frictional work may be estimated using the following formula:
Work = Force of Friction * Distance * cos(theta)
The net force applied on the crate is zero since it is travelling at a constant pace. As a result, the friction force must be equal to the applied force, which is 150 N.
Thus, the work done by friction is:
Work = 150 N * 5.85 m * cos(180) = -877.5 J
Since the work done by friction is negative, it indicates that the direction of the frictional force is opposite to the direction of motion.
The coefficient of kinetic friction may be calculated using the following equation:
Friction Force = Kinetic Friction Coefficient * Normal Force
The normal force equals the crate's weight, which may be computed as:
Normal Force = mass * gravity
where the mass is 35.0 kg and the acceleration due to gravity is approximately 9.8 m/s^2.
Normal Force = 35.0 kg * 9.8 m/s^2 = 343 N
Now, we can rearrange the equation for the force of friction to solve for the coefficient of kinetic friction:
Force of Friction = coefficient of kinetic friction * Normal Force
150 N = coefficient of kinetic friction * 343 N
coefficient of kinetic friction = 150 N / 343 N ≈ 0.437
As a result, the kinetic friction coefficient between the container and the surface is roughly 0.437.
In summary, the work done by the 150 N force is 877.5 Joules, and the coefficient of kinetic friction between the crate and the surface is approximately 0.437.
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4. In which of the following circuits will the bulb glow?
a) switch ON, a connecting wire broken
b) switch OFF
c) switch ON, no broken wire
d) switch ON, one of the wires replaced by a
rubber band
Answers
Answer:
I believe is C.
Explanation:
its quite obvious:)
Find the acceleration due to gravity on planet Fergie which has a mass of 6.23 * 10^23 kg and a radius of 5.79* 10^7 m
Answers
Answer:
The acceleration due to gravity on the planet Fergie is 0.0123 m/s^2.
Explanation:
We want to find the acceleration due to gravity on the planet Fregie. Let it be g m/s^2.
Now, the acceleration due to gravity is defined through the following equation:
\(mg = GMm/R^2\)
where m is the mass of an object on the surface of the planet, M is the mass of the planet, R is the radius of the planet, and G is the universal Gravitational constant.
Subsituting values for M = 6.23*10^23, R = 5.79*10^7, G = 6.67*10^(-11), we get
g = 0.0123 m/s^2.
Thus the acceleration due to gravity on the planet Fergie is 0.0123 m/s^2.
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A car with mass mc = 1225 kg is traveling west through an intersection at a magnitude of velocity of vc = 9.5 m/s when a truck of mass mt = 1654 kg traveling south at vt = 8.6 m/s fails to yield and collides with the car. The vehicles become stuck together and slide on the asphalt, which has a coefficient of friction of μk = 0.5.
A) Write an expression for the velocity of the system after the collision, in terms of the variables given in the problem statement and the unit vectors i and j.
B) How far, in meters, will the vehicles slide after the collision?
Answers
Answer:
a) v(f) = -4i - 5j
b) 4.18 m
Explanation:
The equation to be used for this question is
v(c)m(c) + v(t)m(t) = [m(c) + m(t)] v(f)
if we rearrange and make v(f) subject of formula, then
v(f) = v(c)m(c) + v(t)m(t) / [m(c) + m(t)]
One vehicle is headed towards south and the other vehicle, west when they collide they will travel together in a southwestern direction. This means that both vehicles are traveling in the negative direction taking a standard frame of reference. Thus, we can write the equation in component form by substituting the values as
v(f) = 1225(-9.5i) + 1654(-8.6j) / 1225 + 1654
v(f) = -11637.5i - 14224.4j / 2879
v(f) = -4i - 5j m/s
From the answer,
v(f) = √(4² + 5²)
v(f) = √41
v(f) = 6.4 m/s
And we know that
KE = ½mv²
Fd = umgd
And, KE = Fd, so
½mv² = umgd
½v² = ugd
Making d the subject of formula,
d = v²/2ug
d = 6.4² / 2 * 0.5 * 9.8
d = 41 / 9.8
d = 4.18 m
(a) The velocity of the system after collision is 4.04 i + 4.9 j.
(b)The distance traveled by the vehicles after collision is 1.73 m.
The given parameters;
mass of the car, Mc = 1225 kgvelocity of the car, Vc = 9.5 m/smass of the truck, Mt = 1654 kgvelocity of the truck, Vt = 8.6 m/sApply the principle of conservation of linear momentum to determine the velocity of the system after collision;
\(m_1u_x_1 + m_2 u_y_2 = V(m_1 + m_2)\\\\V = \frac{(1225\times 9.5)_x \ + \ (1654 \times 8.6)_y}{m_1 + m_2} \\\\V = \frac{(1225\times 9.5)_x \ + \ (1654 \times 8.6)_y}{1225+ 1654} \\\\V= \frac{(11,637.5)_x \ + \ (14,224.4)_y}{2879} \\\\V = 4.04x \ + 4.94y\\\\V = 4.04i \ + 4.9 j\)
The magnitude of the final velocity of the system is calculated as;
\(V = \sqrt{v_x^2 + v_y^2} \\\\V = \sqrt{(4.04)^2 + (4.9)^2} \\\\V = 6.35 \ m/s\)
The change in the mechanical energy of the system;
\(\Delta K.E = K.E_f - K.E_i\\\\\)
The initial kinetic energy of the cars before collision is calculated as;
\(K.E_i = \frac{1}{2} m_1u_1_x^2 \ + \frac{1}{2} m_1u_2_y^2 \\\\K.E_i = \frac{1}{2} (1225)(9.5)^2\ + \frac{1}{2} (1654)(8.6)^2\\\\K.E_i = 55,278.13_x \ + \ 61,164.92_y\\\\K.E_i = \sqrt{55,278.13^2 \ + \ 61,164.92^2} \\\\K.E_i = \sqrt{6,796,819,094.9} \\\\K.E_i = 82,442.82 \ J\)
The final kinetic energy of the system;
\(K.E_f = \frac{1}{2} (m_1 + m_2)V^2\\\\K.E_f = \frac{1}{2} (1225 + 1654)(6.35)^2\\\\K.E_f = 58,044.24 \ J\)
The change in kinetic energy is calculated as;
\(\Delta K.E = K.E_f -K.E_i\\\\\Delta K.E= (58,044.24) - (82,442.82)\\\\\Delta K.E = -24,398.58 \ J\)
Apply the principle of work-energy theorem, to determine the distance traveled by the vehicles after collision;
\(W = \Delta K.E\\\\- \mu Fd = - 24,398.58\\\\\mu mgd= 24,398.58\\\\d = \frac{24,398.58}{\mu mg} \\\\d = \frac{24,398.58}{0.5 \times 9.8(1225 + 1654)} \\\\d = 1.73 \ m\)
Thus, the distance traveled by the vehicles after collision is 1.73 m.
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Two blocks of masses 1.0 kg and 2.0 kg, respectively, are pushed by a constant applied force F across a horizontal frictionless table with constant acceleration such that the blocks remain in contact with each other, as shown above. The 1.0 kg block pushes the 2.0 kg block with a force of 2.0 N. The acceleration of the two blocks is
0
1.0 m/s2
1.5 m/s2
2.0 m/s2
3.0 m/s2
Answers
Answer:
1.0 m/s^2
Explanation: happy to help :)
Answer: \(1\ m/s^2\)
Explanation:
Given
Masses of the block are \(m_1=1\ kg\) and
\(m_2=2\ kg\)
Force applied by \(1\ kg\) block on \(2\ kg\) block is \(2\ N\)
From the free body diagram of \(2\ kg\) block, the net force on
\(\therefore m_2a=2\\\\\Rightarrow 2\times a=2\\\\\Rightarrow a=\dfrac{2}{2}\\\\\Rightarrow a=1\ m/s^2\)
Thus, the acceleration of two blocks is \(1\ m/s^2\)
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Which chart correctly describes the properties of magnets and electromagnets?
Answers
Answer:
The second chart seems to be correct
Explanation:
Need a 5 paragraph essay in the eartsh layers and how they function/ benefit the earth!
Answers
There is more to the Earth than what we can see on the surface. In fact, if you were able to hold the Earth in your hand and slice it in half, you'd see that it has multiple layers. But of course, the interior of our world continues to hold some mysteries for us. Even as we intrepidly explore other worlds and deploy satellites into orbit, the inner recesses of our planet remains off limit from us.
However, advances in seismology have allowed us to learn a great deal about the Earth and the many layers that make it up. Each layer has its own properties, composition, and characteristics that affects many of the key processes of our planet. They are, in order from the exterior to the interior – the crust, the mantle, the outer core, and the inner core. Let's take a look at them and see what they have going on.
Like all terrestrial planets, the Earth's interior is differentiated. This means that its internal structure consists of layers, arranged like the skin of an onion. Peel back one, and you find another, distinguished from the last by its chemical and geological properties, as well as vast differences in temperature and pressure.
Explanation:
in a typical cop movie we see the hero pulling a gun firing that gun straight up into the air and shouting
Answers
It is not recommended to fire a gun straight up into the air.
When a bullet is fired into the air, it will eventually come down and can pose a danger to people and property below. The bullet can still be lethal when it reaches the ground, especially if it lands on a hard surface or hits someone directly.
Additionally, firing a gun in a residential area can be illegal and can result in legal consequences. In general, guns should only be fired in designated shooting ranges or in self-defense situations where there is an immediate threat to life. It is important to handle firearms responsibly and follow all safety guidelines to prevent accidents and injuries.
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An object is launched at a velocity of 28 m/s in a direction making an angle of 23° upward
with the horizontal.
What is the magnitude of the velocity when it hits the ground?
Answers
Answer:
Explanation:
Angle:
β = - 23°
( From the symmetry condition)
A car traveling 14 m/s accelerates at a rate of 0.95 m/s2 for an interval of 8 s. What is the final
velocity of the car? Remember: Diagram, Knowns, Equation, Rearrange, Solve.
Answers
v = 14 + (0.95x8) = 14 + 7.6 = 21.6 m/s
A cylinder of mass 250 kg and radius 2.60 m is rotating at 4.00 rad/s on a frictionless.
Two more identical nonrotating cylinders fall on top of the first. Because of friction
between the cylinders they will eventually all come to rotate at the same rate. What is this final angular velocity?
Answers
Answer:
The angular momentum of a cylinder, when it is rotating with constant angular velocity is Lini =Iωi
. When two cylinders are added to the rotating cylinder, which are identical in their dimensions, the moment of inertia of the entire system increases (since mass increases). The final moment of inertia will be 3I
Since friction exist, all the cylinders start rotating with same angular velocity, the new angular velocity can be calculated using conservation of angular momentum
Thus, Iωi =3Iωf ⟹ωf =ωi/3 = 0.33ωi
When the temperature is expected to drop below freezing, a farmer places large tubs of water in an unheated food storage shed. Write two or three sentences explaining why the farmer uses this technique to protect the produce from freezing. Hint: Remember that liquid water has more potential energy than ice.
Answers
The farmer uses this technique to protect the produce from freezing because as the water in the tubs begins to freeze, it releases heat. This heat can help to keep the surrounding air in the shed above freezing, protecting the produce from freezing as well. Additionally, as the water in the tubs freezes, it releases latent heat of fusion, which is the energy required to change a substance from a solid to a liquid. This energy is also released in the form of heat, further helping to keep the produce from freezing.
Which pair of objects would neither attract nor repel each other?
O A. Two negatively charged particles
O B. Two positively charged particles
O C. A positively charged particle and a neutral particle
D. A positively charged particle and a negatively charged particle
SUBMIT
E PREVIOUS
Answers
Answer:
A
Explanation:
Answer:
D.
A positively charged particle and a neutral particle
Explanation:
i did the quiz
A 0.360-m-long metal bar is pulled to the left by an applied force F. The bar rides on parallel metal rails connected through a 45.0 ohm resistor, as shown in the diagram, so the apparatus makes a complete circuit. The circuit is in a uniform 0.650-T magnetic field that is directed out of the plane of the figure. At the instant when the bar is moving to the left at 5.90 m s, (a) is the induced current in the circuit clockwise or counterclockwise and (b) what is the rate at which the applied force is doing work on the bar?
Answers
(a) The induced current in the circuit is clockwise.
b. To find the power (P) using P = Fd/t or P = Fv (since d/t = v). Here, F = ILB (from the Lorentz force), so P = (ILB)v.
How to solve(a) The induced current in the circuit is clockwise.
This can be determined using the right-hand rule.
As the metal bar moves to the left through the magnetic field directed out of the plane, the generated force on the electrons (Lorentz force) will push them toward the top rail, creating a clockwise current.
(b) To find the rate at which the applied force is doing work on the bar, first calculate the induced EMF (ε) using Faraday's law:
induced EMF (ε) using Faraday's law:
ε = BLv
= (0.65 T) * (0.36 m) * (5.9 m/s)
= 1.389 Tm²/s
= 1.389 V (since 1 Tm²/s = 1 V)
induced current (I) using Ohm's law:
I = ε/R
= 1.389 V / 45 Ω
= 0.03086 A
force (F) from the Lorentz force law, where F = ILB:
F = ILB
= (0.03086 A) * (0.36 m) * (0.65 T)
= 0.00723 N
Finally, we find the power (P) using P = Fv:
P = Fv
= (0.00723 N) * (5.9 m/s)
= 0.04266 W
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3. A biologist measures the speed of a paramecium as it moves across a microscope slide. It travels 1.2 inches in 3.25 seconds. The biologist wishes to compare the speed of the paramecium with the speeds of other animals, but the speeds of other animals are listed in metric units of m/s and km/hr . What is the speed of the paramecium in both m/s and km/hr Show all work and use appropriate significant figures. cnch = 2.54 cm )
Answers
Answer:
in meters per second: 0.0094 m/s
in kilometers per hour: 0.0038 km/hr
Explanation:
We start by reducing 1.2 inches to meters to produce this speed in m/s:
1.2 in = 2.54 * 1.2 = 3.048 cm = 0.03048 m
we use the formula for speed:
speed = distance / time = 0.03048 / 3.25 = 0.0093785 m/s
and since the measured value with less number of significant figures is 1.2 inches (which has two significant figures), we reduce our result to two significant figures: 0.0094 m/s
In order to write it in km/h, we complete the reduction to km from meters; 1 m = 0.001 km and the reduction of seconds to hours: 1 s = 1/3600 hr and replace it in the velocity:
0.0093785 0.001 * 3600 km/hr = 0.0037626 km/hr
which rounded to two significant figures becomes: 0.0038 km/hr
You are working for a manufacturing company. Your supervisor has an idea for controlling the position of a small bead by using electric fields. The physical setup is shown in the figure below.
Answers
You are working for a manufacturing company, which is mathematically given as
\(m=3\sqrt{2}\)\(m=\frac{15\sqrt{5}}{16}\)x=0.747a\(m/n=\frac{(x^2+a^2)3/2}{x^3}\)What is the value of m that will place the movable bead in equilibrium at x-a a ....?
a)
Generally, the equation for the force of equilibrium is mathematically given as
F=2fcos\theta
Therefore
\(K(npq^2/a^2)=2\frac{kmpq^2}{a\sqrt{2}^2}0.5\\\\np=mP/ \sqrt{2}\\\\where n=3\)
\(m=3\sqrt{2}\)
b)
By force equilibrium
\(K(npq^2/(2a^2))=2*\frac{kmpq^2}{a\sqrt{5a}^2}* \frac{2a}{\sart{5a}}\)
Therefore
\(n/4=2/5*m*2/\sqrt{5}\\\\m= \frac{5\sqrt{5}}{16}\\\\\\\\\)
\(m=\frac{15\sqrt{5}}{16}\)
c)
\(K(npq^2/x^2)=2\frac{kmpq^2}{a\sqrt{x^2+a^2}^2}0.5*x/\sqrt{x^2+a^2}\)
x^2+a^2=(14/3)^{2/3}x^2
x=a/1.338
x=0.747a
d)
By force equilibrium
\(K(npq^2/x^2)=2\frac{kmpq^2n}{\sqrt{x^2+a^{3/2}}^2}\\\\n/x^2=\frac{2mx}{(x^2+a^2)^{3/2}}\)
\(m/n=\frac{(x^2+a^2)3/2}{x^3}\)
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How is the sun used to make food?
Answers
Answer:
Plants use a process called photosynthesis to make food. During photosynthesis, plants trap light energy with their leaves. Plants use the energy of the sun to change water and carbon dioxide into a sugar called glucose. Glucose is used by plants for energy and to make other substances like cellulose and starch.
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Answer:
Plants use a process called photosynthesis to make food. During photosynthesis, plants trap light energy with their leaves. Plants use the energy of the sun to change water and carbon dioxide into a sugar called glucose.
explain why the ray does not bend when it enters the semi circular glass block
Answers
The ray does not bend when it enters the semi circular glass block - Light ray incident on semicircular block at 90 degrees, therefore there is no change in the direction of ray at P.
Electromagnetic radiation that falls within the region of the electromagnetic spectrum that the human eye can see is known as light or visible light.
Light is electromagnetic radiation that the human eye can perceive. From radio waves with wavelengths measured in meters to gamma rays with wavelengths shorter than around 1 1011 meters, electromagnetic radiation occurs throughout an incredibly broad range of wavelengths.
Light governs our sleep-wake cycle and is crucial to our health and wellbeing. In actuality, "light" that is visible is a type of radiation, which is just energy that moves in the form of electromagnetic waves. It can alternatively be explained as a flow of "wave-packets," or particles, known as photons.
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