Given data
*The given force is F = 583 N
*The given distance is s = 1.5 m
*The given time is t = 2.1 s
The formula for the power it takes for a 583 N student to climb up 1.5 m stairs in 2.1 seconds is given as
\(P=\frac{F\mathrm{}s}{t}\)Substitute the known values in the above expression as
\(\begin{gathered} P=\frac{(583)(1.5)}{(2.1)} \\ =416.42\text{ W} \end{gathered}\)Hence, the power it takes for a 583 N student to climb up 1.5 m stairs in 2.1 seconds is P = 416.42 W
How much gravitational potential energy is lost when a rock of mass 3, point, 0, k, g,3.0kg falls to the foot of a 250, m,250m cliff on the Moon where 'g,g' is 1, point, 6, N, slash, k, g,1.6N/kg?
Answer:
E = 1200 JExplanation:
Data:
m = 3 kg
h = 250 m
g = 1,6 H/kg
Find:
E - ?
-----------------------------------
Solution:
E = mgh
Calculations:
E = 3 kg · 250 m · 1,6 H/kg = 1200 J
Answer: E = 1200 J.
A car is moving with a uniform speed of 15.0 m/s along a straight path. What is the distance covered by the car in 12.0 minutes? Question 7 options: 1.02 × 10–3 km 1.80 × 10–1 km 8.00 × 10–5 km 1.08 × 101 km
12.0 min = 720. s
so the distance covered moving at a constant 15.0 m/s is
(15.0 m/s) (720. s) = 10,800 m = 10.8 km = 1.08 × 10¹ km
Answer:
2.0 min = 720. s
so the distance covered moving at a constant 15.0 m/s is
(15.0 m/s) (720. s) = 10,800 m = 10.8 km = 1.08 × 10¹ km
Explanation:
What is the angular acceleration of a clock's second hand? What is the angular acceleration of a clock's minute hand?
The average angular acceleration of the second hand is zero because the angular speed is constant. The angular speed is 360 degrees/hour.
The angular acceleration of a clock's minute hand on a clock is π1800rad/s
What is an angular acceleration?Angular acceleration means the time rate of change of angular velocity. The second hand of a clock involves an angular displacement of 2π per minute. Its angular speed is w = 2p/60s = 0.105/s. The direction of w is perpendicular to the face of the clock, directing to the face of the clock. The average angular acceleration of the second hand is zero.
Therefore, the correct answer is as given above
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hita's Question Bank- CTEVT
Baishakh] Q.No. 12 What is radiocarbon dating?
VER QUESTIONS
"Radiocarbon dating is a method for determining the age of an object containing organic material by using the properties of radiocarbon."
Answer:
well for me I think
Explanation:
The use of carbon 12 to tell the age of substances
your father brought you a pairof shoes when you wore the shoes you realized there was problem the shoes were too long why might such a problem arise and how can it be mitigated
The shoes were two long because the accurate measurement of the foot size was not carefully by your father.
What are shoes?It is a type of footwear used to protect the human foot completely.
Given is that your father brought you a pair of shoes when you wore the shoes you realized there was problem the shoes were too long.
The shoes were two long because the accurate measurement of the foot size was not carefully by your father.
Therefore, the shoes were two long because the accurate measurement of the foot size was not carefully by your father.
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For which planet is the length of the plants day longer than the planets year
Which statement is true about the geologic timescale?
A. it starts with the existence of humans
B. each eon is one million years
C. time increments relate to evolution of organisms
D. each eon is one billion years
la respuesta es la letra: a
7. An electric train moving at 20km/hrs
. Accelerates to a speed of 30km/hrs. in
20 sec, find the distance travelled in meters during the period of
acceleration
Answer
NB:
- speed, U is measure in m/s
- acceleration, a is measured in m/s²
-time t in seconds , s
Therefore conversation must be made
Speed U = 20km/hrs
=20km÷1hr
But 20km= 20×1000=20000m
1hr= 1×60min×60sec=3600s
U=20000÷3600=5.56m/s
a=30km/hrs
=30km÷1hr
But 30km=30×1000=30000
1hr=3600s
a=30000÷3600=8.33m/s²
From the equation of motion
S=Ut + ½ at².
Where s= distance
S = 5.56m/s × 20s + ½(8.33m/s²)(20s)²
S = 1777.3m
A student stands on the ground with an egg in his hand. He throws the
egg vertically upwards. The egg rises to a height of 10 m. Then the egg
falls and lands on the ground.
Describe the energy changes of the egg during this sequence of events.
(6 marks)
The maximal potential energy is present at the highest point, and there is no kinetic energy due to the zero ultimate velocity at the lowest point.
What is potential energy?
The potential energy is due to the virtue of the position and the height. The unit for the potential energy is the joule.
The potential energy is mainly depending upon the height of the object.
When the egg is at the highest position, the height is maximum. Therefore, the potential energy is also maximum.
When the egg lands on the ground at the striking point only the kinetic energy exists the potential energy is zero.
According to the law of conservation of energy, total energy is defined as the sum of kinetic energy and potential energy.
Total energy = kinetic energy+potential energy
Also, the energy can not be created nor destroyed and can be transferred from one form to another form.
Hence, at the highest point potential energy is the maximum and the kinetic energy is zero. because the final velocity is zero.
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At the highest point, the maximum potential energy is present. But kinetic energy is not present because of zero velocity at the lowest point.
What is potential energy?Potential energy is the energy posses by an object due to its position relative to other objects , which it stresses within itself.
Potential energy depends upon the height of the object. its SI unit is joule.
When egg rises to the maximum height from the ground surface, the potential energy is also maximum.
When the egg falls and lands on the ground , the potential energy will be zero. It posses only kinetic energy.
By the law of conservation of energy ,
The energy is neither be created nor be destroyed and cannot be transferred from one form to another.
Therefore, At the highest point the potential energy is maximum. But kinetic energy is zero.
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Tension force ........... throughout a string that changes direction over a pulley.
(Fill in the blank)
Answer:
"is constant"
Three persons wants to push a wheel cart in the direction marked x in Fig. The two person push with horizontal forces F1 and F2 as F1 = 45 N 70degree And F2 = 75 N , 20 Degree (a) Find the magnitude and direction of the force that third person should exert to stop this cart. You can ignore the effects of friction. (b) If the third person exerts the force found in part (a), the cart accelerates at 200 m/S2 in the (+) x-direction. What is the weight of the cart
Answer:
a) F₃ = 109.5 N , θ₃ = 38.35, b) m = 0.429 kg
Explanation:
For this force addition exercise, let's decompose the forces into a coordinate system
strength 1
cos 70 = F₁ₓ / F₁
sin 70 = \(F_{1y}\) / F₁
F₁ₓ = F₁ cos 70
F_{1y} = F₁ sin 70
F₁ₓ = 45 cos 70 = 15.39 N
F_{1y} = 45 sin70 = 42.29 N
Strength 2
cos 20 = F₂ₓ / F₂
sin 20 = F_{2y} / F₂
F₂ₓ = F₂ cos 20
F_{2y} = F₂ sin20
F₂ₓ = 75 cos 20 = 70.48 N
F_{2y} = 75 sin 20 = 25.65 N
a) in the first part we are asked to find the magnitude of force 3 so that the body is in equilibrium
X axis
∑ Fₓ = 0
F₁ₓ + F₂ₓ + F₃ₓ = 0
F₃ₓ = - F₁ₓ - F₂ₓ
F₃ₓ = - 15.39 - 70.48
F₃ₓ = - 85.87 N
Y Axis
∑ F_{y} = 0
F_{1y} + F_{2y} +F_{3y} = 0
F_{3y} = - F_{1y} -F_{2y}
F_{3y} = - 42.29 - 25.65
F_{3y} = - 67.94 N
the magnitude of this force can be found using the Pythagorean theorem
F₃ = √ (F₃ₓ² + F_{3y}^2)
F₃ = √ (85.87² + 67.94²)
F₃ = 109.5 N
The direction of this force can be found using trigonometry
tan θ = F₃ = \(F_{3y}\) / F₃ₓ
θ₃ = Tan⁻¹ (67.94 / (85.87))
θ₃ = 38.35º
since the two vectors are negative this angle is in the third quadrant, measured from the positive side of the x axis is
θ₃ = 180 + 38.53
θ₃ = 218.35º
b) I think you have an error in your statement, we have two possibilities:
1) If we eliminate the third force, what is the mass
it should say: "if we apply the third force force ...", they ask that we find the masses of the vehicle, let's use Newton's second law
X axis
F₁ₓ + F₂ₓ = m a
15.39 + 70.48 = m 200
m = 85.87 / 200
m = 0.429 kg
2) If the force F3 is in the first quadrant
F1x + F2x + F3x = m a
m = (15.39 + 70.48 + 85.87) / 200
m = 0.8587 kg
Two objects with massesof 1.0 kg and 2.0 kg are 1.0 m apart. the magnitude of the gravitational force between these masses is 1.33 x 10 ^-10 NIf the distance between the two masses weretripled, by what factor would the mutual gravitation force changed?
Given
Object 1
m = 1kg
Object 2
m = 2 kg
Gravitational force
Fg = 1.33 x 10^-10 N
Procedure
Newton's law of universal gravitation is usually stated as that every particle attracts every other particle in the universe with a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers
As the distance is tripled the gravitational force would change by a factor of 1/9
An average person is 175 cm tall. How
many people could you stack one on top of
another to reach the top of the CN Tower
(553 m)?
The number of people you will stack to reach the top of the CN Tower (553 m) is 316 people
Hor to convert 175 centimeters to metersWe'll begin by converting 175 cm to m. This can be obtained as illustrated below:
100 cm = 1 m
Therefore,
175 cm = (175 cm × 1 m) / 100 cm
175 cm = 1.75 m
Thus, 175 cm is equivalent to 1.75 m
How to determine the number of people neededThe number of people needed to be stacked to get to the top of the CN tower can be o btained asfollow:
Height of tower = 553 mHeight of a person = 1.75 mNumber of people needed =?Number of people needed = Height of tower / height of a person
Number of people needed = 553 / 1.75
Number of people needed = 316 people
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Which light behavior does this reperesent
Answer:
Refraction
Explanation:
because the pencil looks magnified or distorted in water
Answer:
(B) Refraction
Explanation:
the fact or phenomenon of light being deflected in passing obliquely through the interface between one medium and another or through a medium of varying density.
In physics, refraction is the redirection of a wave as it passes from one medium to another. The redirection can be caused by the wave's change in speed or by a change in the medium.
Hope this helps!! :) (Also there is an example attached :D)
The low-frequency speaker of a stereo set produces 10.0 W of acoustical power. If the speaker projects sound uniformly in all directions, at what distance from the speaker is the intensity level 80.0 dB
Answer:
the required distance is 89.125 m
Explanation:
Given the data in the question;
we know that, sound intensity B in decibels of sound is;
β(dB) = 10log₁₀( \(I\) / \(I_0\) )
where intensity \(I\) = power / area carried by wave
\(I_0\) = 10⁻¹² W/m² { minimum threshold intensity }
Now,
intensity \(I\) = power / area carried by wave = P/A = P/4πr² { spherical }
given that; β = 80.0 dB and P = 10 W
so
β(dB) = 10log₁₀( \(I\) / \(I_0\) )
we substitute
80 = 10log₁₀( P / 4πr²× \(I_0\))
80 = 10log₁₀( 10 / 4πr²× 10⁻¹² )
8 = log₁₀(10) - log₁₀( 4πr²× 10⁻¹² )
8 = 1 - log₁₀( 4πr²× 10⁻¹² )
8 - 1 = -log₁₀( 4πr²× 10⁻¹² )
7 = -log₁₀( 1.2566 × 10⁻¹¹ × r² )
7 = -[ log₁₀( 1.25 × 10⁻¹¹) + log₁₀( r² ) ]
7 = -[ -10.9 + log₁₀( r² ) ]
7 = 10.9 - log₁₀( r² )
-log₁₀( r² ) = 7 - 10.9
-log₁₀( r² ) = - 3.9
log₁₀( r² ) = 3.9
2log₁₀r = 3.9
log₁₀r = 3.9 /2
log₁₀r = 1.95
r = 89.125 m
Therefore, the required distance is 89.125 m
As an admirer of Thomas Young, you perform a double-slit experiment in his honor. You set your slits 1.15 mm apart and position your screen 3.93 m from the slits. Although Young had to struggle to achieve a monochromatic light beam of sufficient intensity, you simply turn on a laser with a wavelength of 647 nm . How far on the screen are the first bright fringe and the second dark fringe from the central bright fringe
Answer:
a) y = 2.21 10⁻³ m, b) y = 5.528 10⁻³ m
Explanation:
In the double-slit experiment the interferences occur at the positions
d sin θ = m λ constructive interference
d sin θ = (m + ½) λ destructive interference
let's use trigonometry for the angle
tan θ = y / L
as in this experiment the angles are very small
tan θ = sin θ/cos θ = sin θ
sin θ = y / L
we substitute
d y / L = m λ constructive interference
d y / L = (m + ½) λ destructive interference
Let's answer the questions
a) first line of constructive interference me = 1
y = m λ L / d
y = 1 647 10⁻⁹ 3.93 /1.15 10⁻³
y = 2.21 10⁻³ m
b) second dark band m = 2
y = (m + ½) λ L / d
y = (2 + ½) 647 10⁻⁹ 3.93 /1.15 10⁻³
y = 5.528 10⁻³ m
answer and solution to this question
Frequency= 30 Hz, Period= 0.0333 s, Wave Number=15.708 rad/m, Wave Function= y(x, t) = 0.05 sin(15.708x - 94.248t), Transverse displacement= -0.013 m, Time= 0.297 s.
How to calculate the frequency?(a) To find the frequency (f), we can use the equation: wave speed = frequency x wavelength. Rearranging this equation, we get:
frequency = wave speed / wavelength
Substituting the given values, we get:
frequency = 12 m/s / 0.4 m = 30 Hz
Therefore, the frequency of the wave is 30 Hz.
To find the period (T), we can use the equation:
period = 1 / frequency
Substituting the frequency value we just calculated, we get:
period = 1 / 30 Hz = 0.0333... s (rounded to four decimal places)
Therefore, the period of the wave is approximately 0.0333 s.
To find the wave number (k), we can use the equation:
wave number = 2π / wavelength
Substituting the given values, we get:
wave number = 2π / 0.4 m = 15.708 rad/m (rounded to three decimal places)
Therefore, the wave number of the wave is approximately 15.708 rad/m.
(b) The wave function for a transverse wave on a string is given by:
y(x, t) = A sin(kx - ωt + φ)
where A is the amplitude, k is the wave number, x is the position of the point on the string, t is the time, ω is the angular frequency, and φ is the phase constant.
We already know the values of A, k, and ω from the previous calculations. To find φ, we can use the given initial condition: "at t = 0 end of the string has zero displacement and is moving upward". This means that y(0,0) = 0 and ∂y/∂t(0,0) > 0. Substituting these conditions into the wave function, we get:
0 = A sin(0 + φ)
∂y/∂t = -Aω cos(0 + φ)
Since sin(0 + φ) = sin(φ) = 0 (because sin(0) = 0), we get:
φ = nπ, where n is an integer
Since cos(0 + φ) = cos(φ) = 1 (because cos(0) = 1) and ∂y/∂t(0,0) > 0, we get:
n = 0 or 2
Therefore, the possible values of φ are 0 or 2π.
Substituting the values of A, k, ω, and φ, we get:
y(x, t) = 0.05 sin(15.708x - 94.248t)
Therefore, the wave function describing the wave is:
y(x, t) = 0.05 sin(15.708x - 94.248t)
(c) To find the transverse displacement of a wave at x = 0.25 m and t = 0.15 s, we can use the wave function we just found:
y(0.25, 0.15) = 0.05 sin(15.708(0.25) - 94.248(0.15))
y(0.25, 0.15) ≈ -0.013 m (rounded to three decimal places)
Therefore, the transverse displacement of the wave at x = 0.25 m and t = 0.15 s is approximately -0.013 m.
(d) To find how much time must elapse from the instant in part (c) until the point at x = 0.25 m has zero displacement,
From part (c), we know that the transverse displacement of the wave at x = 0.25 m and t = 0.15 s is approximately -0.013 m. We need to find the time it takes for this point to return to zero displacement.
We can use the wave function we found in part (b) and set y(0.25, t) = 0:
0 = 0.05 sin(15.708(0.25) - 94.248t)
Since sin(θ) = 0 when θ = nπ (where n is an integer), we get:
15.708(0.25) - 94.248t = nπ
Solving for t, we get:
t = (15.708(0.25) - nπ) / 94.248
To find the smallest positive value of t that satisfies this equation, we need to use the smallest positive value of n that makes the right-hand side of the equation positive (because we want to find the time it takes for the point at x = 0.25 m to return to zero displacement, which happens after the point has completed a full cycle). We can see from the equation that n must be an even integer to make the right-hand side positive. The smallest even integer greater than zero is 2. Substituting n = 2, we get:
t = (15.708(0.25) - 2π) / 94.248
t ≈ 0.297 s (rounded to three decimal places)
Therefore, the time it takes for the point at x = 0.25 m to return to zero displacement is approximately 0.297 s.
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What is the correct answer option for question 14?
Based on the information provided in the second paragraph of "On a Mountain Trail," the correct option would be "The pack surrounding the sleigh is a very real threat to the two men on the trail." The correct option is C.
In the second paragraph, it is mentioned that the wolves had stopped running and were now "moving at a dogtrot, leisurely and methodically encircling the sleigh." This description implies that the wolves are actively surrounding the sleigh, which suggests a potential threat to the two men on the trail. The word "encircling" indicates a deliberate and coordinated action by the wolves, which implies predatory behavior.
Now let's examine why the other options are not true:
A. The surrounding pack should not be concerning to the two men.
This option is not true because the description in the paragraph clearly implies that the pack of wolves surrounding the sleigh is a cause for concern.
B. The wolves will eventually tire and will return to the safety of the underbrush.
This option is not supported by the information provided in the paragraph. There is no mention of the wolves becoming tired or retreating to the safety of the underbrush. The description implies that the wolves are actively encircling the sleigh, indicating an ongoing threat.
D. Once a sleigh is surrounded by a pack of wolves, there is no chance for human survival.
This option is an extreme statement and goes beyond the information provided in the paragraph. The paragraph does not provide any conclusive information about the chances of human survival in such a situation. It simply describes the current state of the wolves surrounding the sleigh, but it does not make a definitive statement about the outcome for the two men.
Therefore, The correct option is C.
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A car going .80m/s accelerates uniformly at .20m/s^2 . What is the distance covered in 1.3 minutes?
Answer:
670.8 m
Explanation:
Using the equation s = ut + ½at^2,
*s is the distance, u is initial velocity, a is acceleration and t is time*
s = 0.8 (1.3x60) + ½ (0.20)(1.3x60))^2
s = 670.8 m
A 2.15-nC charged particle located at the origin is separated by a distance of 0.0690 m from a 3.78-nC charged particle located farther along the positive x axis. If the 2.15-nC particle is kept fixed at the origin, where along the positive x axis should the 3.78-nC particle be located so that the magnitude of the electrostatic force it experiences is twice as great as the magnitude of the electrostatic force it experiences at 0.0690 m?
The new distance of the 3.78 nC particle when the electrostatic force is doubled is 0.049 m.
What is the electrostatic force between the two particles?
The magnitude of the electrostatic force experienced by the 3.78 n C particle when it is 0.069 m from the 2.15 nC particle is calculated as follows;
F = kq₁q₂ / r²
where;
k is the Coulomb's constantq₁ is the magnitude of particle 1q₂ is the magnitude of particle 2r is the distance between the particlesF = ( 9 x 10⁹ x 2.15 x 10⁻⁹ x 3.78 x 10⁻⁹ ) / ( 0.069² )
F = 1.536 x 10⁻⁵ N
When this electrostatic force is doubled, the new distance of 3.78 nC particle from the 2.15 nC is calculated as;
r² = kq₁q₂ / 2F
r = √ ( kq₁q₂ / 2F )
r = √ [ ( 9 x 10⁹ x 2.15 x 10⁻⁹ x 3.78 x 10⁻⁹ ) / ( 2 x 1.536 x 10⁻⁵ ) ]
r = 0.049 m
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Consult Multiple-Concept Example 11 for background material relating to this problem. A small rubber wheel on the shaft of a bicycle generator presses against the bike tire and turns the coil of the generator at an angular speed that is 40 times as great as the angular speed of the tire itself. Each tire has a radius of 0.330 m. The coil consists of 163 turns, has an area of 3.23 x 10-3 m2, and rotates in a 0.0948-T magnetic field. The bicycle starts from rest and has an acceleration of 0.601 m/s2. What is the peak emf produced by the generator at the end of 6.72 s
Answer:
\(Emf=24.4V\)
Explanation:
From the question we are told that:
Angular speed \(\omega=40*\omega'\)
Radius \(r=0.33m\)
No. Turns \(N=163\)
Area \(A= 3.23 * 10^{-3} m^2\)
Magnetic field. \(B=0.0948T\)
Acceleration \(a=0.60m/s^2\)
Time \(t=6.72s\)
Generally the equation for momentum is mathematically given by
\(\omega'=\omega_o+\frac[a}{r}t\)
\(\omega'=0+\frac{0.60}{0.33}*6.72\)
\(W=12.22rad/s^2\)
Therefore
\(\omega=Aw\)
\(\omega=12.22*40\)
\(\omega=488.7rads/s\)
Generally the equation for Peak emf is mathematically given by
\(Emf=NBA \omega\)
\(Emf=163*0.0948* 3.23 * 10^{-3} m^2*488.7rads/s\)
\(Emf=24.4V\)
How do the frequencies and the speeds of yellow light and blue light compare?
Answer: The frequency of yellow light is greater that blue light
Explanation: Hope this helps :)
Find the Magnitude of the resultant vector (the actual
path of the boat).
The picture is a little blurry, so here are the stats:
Velocity of the boat is 0.75 m/s
Velocity of the river is 1.2 m/s
The magnitude of the resultant vector, representing the actual path of the boat, is approximately 1.42 m/s.
To find the magnitude of the resultant vector, we need to consider the boat's velocity and the velocity of the river. The boat's velocity is given as 0.75 m/s, and the river's velocity is given as 1.2 m/s.
Since the boat is moving in a river, we can think of the boat's velocity as a combination of two velocities: its own velocity and the velocity of the river. The resultant vector represents the actual path of the boat, considering both velocities.
To calculate the resultant vector, we can use vector addition. The magnitude of the resultant vector can be found by taking the square root of the sum of the squares of the boat's velocity and the river's velocity. Mathematically, we have:
Resultant magnitude = √(boat velocity^2 + river velocity^2)
Plugging in the given values, we have:
Resultant magnitude = √(0.75^2 + 1.2^2)
= √(0.5625 + 1.44)
= √2.0025
≈ 1.42 m/s
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2. A car of mass 1000kg is being tied along the horizontal road by a rope making an angle of 30° with the horizontal. If the tension in the north rope is 200N and what is the acceleration
The acceleration of the car is determined as 0.35 m/s².
What is the acceleration of the car?The acceleration of the car is calculated by applying the formula for Newton's second law of motion as follows;
F(net) = ma
where;
F(net) is the net forcem is the mass of the cara is the acceleration of the carFy = F sinθ
200 = F x sin(30)
F = 200 / sin(30)
F = 400 N
The tension in horizontal direction;
Fₓ = 400 N x cos(30)
Fₓ = 346.4 N
The acceleration of the car is calculated as;
a = Fₓ / m
a = 346.4 / 1000
a = 0.35 m/s²
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When an MRI machine are use to capturing images of a person's body the produce extremely powerful magnetic fields what might be some issues that an MRI technician would need to work on around due to these magnetic fields
Answer:
Technique to reduce Noise, magnetic attraction and Twitching sensation
Explanation:
Changing magnetic fields cause loud knocking noise this can be overcome by ear protection.
Strong and Static magnetic fields attract magnetic objects that can be avoided by screening of people and objects before entering in that area.
Twitching Sensation due to nerve stimulation can be avoided by reducing the exposure to magnetic field.
Please mark branliest if you are satisfied with the answer. Thanking you in anticipation.
Which factor indicates the amount of charge on the source charge?
A. the number of field lines on the test charge
B. the number of field lines on the source charge
C. the direction of lines on the source charge
D. the direction of lines on the test charge
Answer:
B. the number of field lines on the source charge
Explanation:
As we know that electric flux is defined as the number of electric field lines passing through a given area.
So here electric flux due to a point charge "q" is given by
so here we know that flux depends on the magnitude of charge and hence we can say that number of filed lines originating from a point charge will depends on the magnitude of the charge.
The factor indicates the amount of charge on the source charge is the number of field lines on the source charge.
What is electric flux?The electric flux is defined as the number of electric field lines passing through a given area.
The electric flux due to a point charge q is given by the number of filed lines through particular closed area.
We know that flux depends on the magnitude of charge and number of field lines starting from a point charge will depends on the magnitude of the charge.
Thus, the correct option is B.
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A transformer has an output coil with 6 times as many turns as the input coil. If the input frequency is f then the output frequency will be:_______
a. 9f
b. 6f
c. 1/6 f
d. f
Answer:
d. f
Explanation:
Based on the principle of operation of transformer, when a.c voltage is applied at the terminal of the primary coil (input coil), an alternating magnetic flux is produced in the iron core which links the secondary coil (output coil).
Also, an alternating e.m.f of the same frequency as that of primary coil (input coil) will be induced in the secondary coil (output coil) by mutual inductance.
Thus, If the input frequency is "f" then the output frequency will be "f" (since the frequency will be the same).
The correct option is "D"
This story makes use of personification as one of the main figures of speech.
2 Examples of adverse events (AE) include which of the following?
A. Damaged wheelchair.
OB. Anxiety.
C. Decreased blood sodium.
D. Enlarged thyroid on physical examination.
OE. B, C, and D only
OF. All the above are adverse events (AES).
does the mass of a parachute affect terminal velocity?
Answer:
The greater weight increases the terminal velocity by acting as an extra force against gravity and air resistance.