1. Determinar cuanta fuerza es necesaria para empujar un móvil que se encuentra en reposo para que alcance una velocidad de 15 m/s en un tiempo de 20 segundos, considerando que dicho móvil tiene una masa de 1000Kg. No considere que existe fricción.

By using uniform motion, the average force is 3106.89 N.

We need to know about the uniform motion to solve this problem. The uniform motion is an object's motion under acceleration. It should follow the rule

vt = vo + a . t

vt² = vo² + 2a . s

s = vo . t + 1/2 . a . t²

where vt is final velocity, vo is initial velocity, a is acceleration, t is time and s is displacement.

From the question above, we know that

vo = 0 m/s

vt = 10.6 m/s

m = 0.85 kg

t = 2.9 ms = 2.9 x 10¯³ second

Find the acceleration by using the first equation

vt = vo + a . t

10.6 = 0 + a. 2.9 x 10¯³

a = 3655.17 m/s²

Find the average force

F = m . a

F = 0.85 . 3655.17

F = 3106.89 N

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In this case, the electric field is 340 N/C, and the area vector is normal to the surface, so the dot product of the two is 0.

Electric flux is a measure of the amount of electric field that passes through a given area. It is measured in units of coulombs per meter squared (C/m2). Electric flux is important in electric circuits and fields, as it allows for the calculation of electric field strength, current, and other electrical properties. Electric flux is related to the concept of electric field lines, which represent the direction of the electric field at any point.

The electric flux through the surface shown in the figure is 0 N ⋅ m2/C. This is because the electric field is perpendicular to the surface and so no electric flux is passing through it. The electric flux is calculated as the dot product of the electric field and the area vector, and since the two are perpendicular, the result is 0.

Mathematically, electric flux is given by the formula Φ = E · A, where E is the electric field and A is the area vector.

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Answer:

You decide to drop two different objects from a tall building and discover that one of the objects lands on the ground five seconds before the other object. What can you conclude? Newton's second law is not valid because each object should experience the same force of gravity and therefore should land at the same time.

Explanation:

You decide to drop two different objects from a tall building and discover that one of the objects lands on the ground five seconds before the other object. What can you conclude? Newton's second law is not valid because each object should experience the same force of gravity and therefore should land at the same time.

You decide to drop two different objects from a tall building and discover that one of the objects lands on the ground five seconds before the other object. What can you conclude? Newton's second law is not valid because each object should experience the same force of gravity and therefore should land at the same time.

The temperature at the nozzle's discharge was approximately 586.2 K.

Back-pressure is the term for the pressure at which the steam emerges from the nozzle. When steam is passing through a nozzle, neither heat is being provided nor rejected. As a result, it is regarded as an adiabatic flow, and the associated expansion is also so regarded.

To approximate the temperature at the exit for an isentropic process, we can solve the following equation for T2s:

T2s = T1 - (h1 - h2s)/cp

s1 = s2s

Now we can solve for h2s:

h2s = h1 - (s2 - s1) * T1

Substituting this expression into the equation for T2s, we get:

T2s = T1 - (h1 - (h1 - (s2 - s1) * T1))/cp

Simplifying this expression, we get:

T2s = T1 - (h1/cp) + ((s2 - s1)/cp) * T1

Now we can substitute the given values into this equation and calculate T2s:

T1 = 975 K

p1 = 546 kPa

p2 = 101 kPa

cp = 2.01 kJ/(kgK) (specific heat at constant pressure for steam at 975 K)

s1 = 7.704 kJ/(kgK) (specific entropy at the inlet)

s2 = 7.704 kJ/(kg*K) (specific entropy at the outlet for an isentropic process, since s1 = s2s)

h1 = 3475 kJ/kg (specific enthalpy at the inlet)

h2s = h1 - (s2 - s1) * T1

= 3475 - (7.699 - 7.704) * 975

= 3265.5 kJ/kg

T2s = T1 - (h1/cp) + ((s2 - s1)/cp) * T1

= 975 - (3475/2.01) + ((7.704 - 7.699)/2.01) * 975

= 586.2 K

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The net momentum of the system before the collision is given by the expression: Momentum before = m1v1 + m2v2where m1 and v1 are the mass and velocity of the cue ball respectively and m2 and v2 are the mass and velocity of the eight ball respectively.

Substituting in the given values, we have:Momentum before = (0.6 kg) (3.0 m/s) + (0.55 kg) (2.0 m/s) = 1.80 kg m/s + 1.10 kg m/s = 2.90 kg m/s. The net momentum of the system after the collision is given by the expression:Momentum after = m1v1' + m2v2'where v1' and v2' are the velocities of the cue ball and eight ball respectively after the collision.

Substituting in the given values, we have: Momentum after = (0.6 kg) (2.0 m/s cos 40°) + (0.55 kg) (v2')Momentum after = 1.20 cos 40° kg m/s + (0.55 kg) (v2')Momentum after = 0.92 kg m/s + 0.55 kg v2'Conservation of momentum principle states that the total momentum before the collision must equal the total momentum after the collision: Momentum before = Momentum after2.90 kg m/s = 0.92 kg m/s + 0.55 kg v2'Solving for v2', we get:v2' = (2.90 kg m/s - 0.92 kg m/s) / 0.55 kgv2' = 4.71 m/s.

The north component (y-component) of the momentum of the cue ball after collision is given by the expression:py = m1v1' sin θSubstituting the given values, we have:py = (0.6 kg) (2.0 m/s sin 40°)py = 0.78 kg m/sTherefore, the final velocity of the eight ball is 4.71 m/s.

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Answer:

They form ions, or charged particles

Explanation:

Some atoms become more stable by gaining or losing an entire electron (or several electrons). When they do so, atoms form ions, or charged particles. Electron gain or loss can give an atom a filled outermost electron shell and make it energetically more stable.

hope it helped please tell me if im wrong.

infrared

true

infrared

true

infrared

A block is hanging from a cord that is 10 meters long. A second cord is tied to the midpoint of the first cord, and a horizontal pull equal to half the weight of the block is exerted on it.

When a horizontal force is applied to the midpoint of the first cord, the system will reach a new equilibrium position. This is because the horizontal force introduces a horizontal component of tension in the first cord. This horizontal tension creates a net torque about the point of suspension of the block, causing it to rotate.

The block will move to one side until the torque exerted by the horizontal tension is balanced by the torque due to the gravitational force acting on the block. The torque due to the gravitational force is produced by the weight of the block acting at its center of mass.

By setting the torques equal to each other, the distance the block will be pulled to one side can be determined. The torque due to the gravitational force can be calculated by multiplying the weight of the block by the distance from the point of suspension to the center of mass.

The torque due to the horizontal tension can be calculated by multiplying the horizontal component of tension by the distance from the point of suspension to the block.By solving the torque equation and considering the given values, the distance to which the block will be pulled to one side can be determined.

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A) The mass of 28.76 mL of acetone is approximately 22.7 g.

B) The volume of 6.40 g of acetone is approximately 8.12 mL.

A) To determine the mass of 28.76 mL of acetone, we need to know the density of acetone. The density of acetone is approximately 0.789 g/mL. Therefore, we can calculate the mass as follows:

Mass = Volume * Density

Mass = 28.76 mL * 0.789 g/mL

Performing the calculation:

Mass ≈ 22.67564 g

Rounding the result to the correct number of significant figures, the mass of 28.76 mL of acetone is approximately 22.7 g.

B) To determine the volume of 6.40 g of acetone, we can rearrange the formula:

Volume = Mass / Density

Volume = 6.40 g / 0.789 g/mL

Performing the calculation:

Volume ≈ 8.116 g/mL

Rounding the result to the correct number of significant figures, the volume of 6.40 g of acetone is approximately 8.12 mL.

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Answer:

B. She could have a higher risk of skeletal fractures

Explanation:

She needs to maintain her bone health and B is the only answer that involves a consequence with bones.

I hope this helps

Answer:

D.400 watt

Explanation:

where Pave = average power

Irms=RMS current &

Vrms=RMS voltage

Rahul should change the lengths of the vectors that point tangent to the circle so that each is the same length.

Uniform Circular Motion:

A uniform circular motion is a motion in a circle where the tangential speed of the object is constant.

In the motion map:

In this motion map,  the length of the vectors pointing tangent to the circle is not constant: this means that the speed is not constant. In order to have a uniform circular motion, the speed must be constant, therefore the lengths of the vectors that point tangent to the circle must be the same.

Thus, we can conclude that Rahul should change the lengths of the vectors that point tangent to the circle so that each is the same length.

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Answer:

Explanation:idk

It is a False statement, because the acceleration arrow points forward, but the velocity arrow is reversed.

What is meant by acceleration?

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Answer:

The magnitude of the boy's displacement is 24.698 paces which is in the direction of approximately 58.24° North of East

Explanation:

The given parameters are;

The distance West the boy on a treasure hunt walks = 12 paces

The distance North the boy on a treasure hunt then walks = 21 paces

The distance East the boy on a treasure hunt then walks = 25 paces

Writing the displacement in vector format, gives;

d = -12·i + 21·j + 25·i

Which gives

d = 13·i + 21·j

The magnitude of the boy's resultant displacement is given as follows;

\(\left | \mathbf{d} \right | = \sqrt{d_x^2 + d_y^2}\)

Where;

\(d_x = 13, \ d_y = 21\)

\(\left | \mathbf{d} \right | = \sqrt{13^2 + 21^2} = \sqrt{610} \approx 24.698 \ paces\)

The magnitude of the boy's displacement is 24.698 paces

The direction of the displacement is tan⁻¹(21/13) ≈ 58.24° North of East.

The winds aloft chart for the Great Lakes (Michigan is fine) region displays the wind direction and speed at several altitudes. At 3000 feet, the wind speed is approximately 17 knots.

At 12,000 feet, the wind speed is about 44 knots. The wind speed at FL350 is approximately 67 knots.Surface friction has an effect on the winds close to the ground, slowing them down due to the frictional force exerted on the ground by air molecules. The winds shift direction with altitude, veering to the right of the direction of travel in the northern hemisphere. The approximate location of the Jetstream can be obtained by examining the wind/temperature plot chart. The fastest wind speed at FL360 appears to be approximately 145 knots, traveling towards the northeast. Flight to the east or southeast would benefit from this wind speed.Seasonally, winds aloft change depending on the position of the jet stream, which moves towards the poles during the summer months and towards the equator during the winter months.

The current surface analysis chart (Prog chart) shows the major frontal activity passing through the Midwest states. Precipitation is what leads the frontal passage in general, with both temperature and wind speed/direction changing from behind to ahead of the front.

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When the mass is at its equilibrium position (which corresponds to x=0), the velocity of the mass will be maximum.

Instantaneous center:

It is the center about a body moves in planer motion. The velocity of Instantaneous center is zero and Instantaneous center can be lie out side or inside the body. About this center every particle of a body rotates.

From the diagram

Where these two lines will cut then it will the I-Center. Point A and B is moving perpendicular to the point I.

If we take three link link1,link2 and link3 then I center of these three link will be in one straight line It means that they will be co-linear.

Therefore, when the mass is at its equilibrium position (which corresponds to x=0), the velocity of the mass will be maximum.

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The correct answer is d. Neither the tensile modulus (E) nor the cross-section moment of inertia (1₂₂) is inversely proportional to the beam's curvature.

The beam's curvature at a given point along its length is inversely proportional to the cross-section moment of inertia (1₂₂) of the beam.

The curvature of a beam is influenced by both the internal moment and the cross-section moment of inertia. The internal moment generates bending in the beam, while the cross-section moment of inertia determines the beam's resistance to bending. The larger the cross-section moment of inertia, the smaller the curvature for a given internal moment, indicating greater stiffness and resistance to bending.

On the other hand, the tensile modulus (E), which represents the material's stiffness, does not directly affect the beam's curvature. The tensile modulus is related to the material's ability to resist deformation under tensile or compressive loads but does not have a direct influence on the beam's bending behavior.

Therefore, the correct answer is d. Neither the tensile modulus (E) nor the cross-section moment of inertia (1₂₂) is inversely proportional to the beam's curvature.

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Answer:

it has 3 electrons. brainliest please

The mass of Deimos is approximately 9.52 x 10^15 kg.

To find the mass of Deimos, we can use the formula for gravitational force:F = G * (m1 * m2) / r^2. where F is the gravitational force between two objects, G is the gravitational constant, m1 and m2 are the masses of the two objects, and r is the distance between their centers of mass.

In this problem, we know the radius of Deimos (r = 6.3 km = 6.3 x 10^3 m), the mass of the rock on its surface (m1 = 3.0 kg), and the gravitational force between them (F = 2.5 x 10^-2 N). We can also look up the value of G: G = 6.674 x 10^-11 N(m/kg)^2.

We want to solve for the mass of Deimos (m2). Rearranging the formula, we get: m2 = (F * r^2) / (G * m1). Substituting the given values, we get: m2 = (2.5 x 10^-2 N) * (6.3 x 10^3 m)^2 / (6.674 x 10^-11 N(m/kg)^2 * 3.0 kg). m2 = 9.52 x 10^15 kg.Therefore, the mass of Deimos is approximately 9.52 x 10^15 kg.

It is worth noting that this calculation assumes that the rock on Deimos' surface is not affecting its orbit significantly. In reality, the gravitational force between the rock and Deimos would cause some perturbations in Deimos' orbit, but they are likely to be very small due to the small mass of the rock compared to Deimos.

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To find the mass of Deimos, we can use the gravitational force formula:
F = G * (m1 * m2) / r^2

Where F is the gravitational force (2.5 * 10^(-2) N), G is the gravitational constant (6.674 * 10^(-11) Nm^2/kg^2), m1 is the mass of Deimos (which we want to find), m2 is the mass of the rock (3.0 kg), and r is the distance between their centers, which is equal to Deimos' radius (6.3 km or 6300 m).

Rearranging the formula to solve for m1 (the mass of Deimos):

m1 = (F * r^2) / (G * m2)

m1 = (2.5 * 10^(-2) N * (6300 m)^2) / (6.674 * 10^(-11) Nm^2/kg^2 * 3.0 kg)

After calculating, we find that the mass of Deimos is approximately 1.0 * 10^15 kg.

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The object's kinetic energy at this high speed v, KE =(1/2)mv² - m₀c².The correct option is (e).

This is due to the theory of relativity, which states that as an object approaches the speed of light, its mass increases. This increase in mass is given by the equation m = m₀/√(1-(v/c)²), where c is the speed of light.

Using this equation,

we can calculate the kinetic energy of the object at high speed v as KE = (m-m₀)c²/2 = [ m₀/√(1-(v/c)²)) - m₀)]c²/2

= (1/2)m₀[(1/√(1-(v/c)²))-1]c² = (1/2)mv² - m₀c²

   Rest Mass- the actual mass that an observer will observe when both the observer and body are in the same frame

   of reference and the body is at rest with respect to the observer.

  The correct answer is e. KE =(1/2)mv² - m₀c².

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Answer:

sunspots

Explanation:

Answer:

3m/s is the answer.

Explanation:

f = c/λ

f = frequency

c = speed (m/s)

λ = wavelength

f = c/λ

1.5 = c/2

c = 3m/s

A runner jack 12km north then turns and runs 16km in 3hours Therefore his average velocity is 1.3 km/h.

What is average velocity?

The change in position or displacement (x) divided by the time intervals (t) during which the displacement happens is the definition of average velocity. Based on the direction of the displacement, the average velocity might either be positive or negative. Meters per second (m/s or ms-1) is the SI measure for average velocity.

Given:

A runner jack 12km north then turns and runs 16km in 3hours .

Therefore average velocity= (16 - 12)/ 3 km/h

=1.3 km/h

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The phenomenon that occurs when the time on the clock of an astronaut on a spaceship passing at 0.25c runs slower than does time on a patent clerk's clock is called time dilation.

Time dilation:Time dilation is a phenomenon in which time passes at a slower rate for an observer in relative motion compared to a stationary observer, as predicted by the theory of relativity.

It also is a consequence of the theory of relativity, which predicts that time appears to run slower for objects that are moving relative to an observer.

In this case, the astronaut's clock appears to be running slower than the patent clerk's clock because the astronaut is moving relative to the patent clerk.

This effect becomes more pronounced as the speed of the spaceship approaches the speed of light.

At speeds close to the speed of light, time dilation becomes significant and can have practical implications, such as the need for correction factors in GPS systems that account for the time dilation effects of satellites in orbit.

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The Nutrition Facts panel must include the grams of monounsaturated fat, grams of total fat, and total calories from saturated fat.

a. The total calories from trans fat are not required to be included in the Nutrition Facts panel. Trans fat is listed separately under "Total Fat" and does not have its own specific calorie value.

b. The grams of monounsaturated fat are required to be included in the Nutrition Facts panel. Monounsaturated fat is a type of fat that is beneficial for health, and its quantity is provided to help consumers make informed choices.

c. The grams of total fat are required to be included in the Nutrition Facts panel. Total fat represents the sum of all types of fats present in the food product.

d. The total calories from saturated fat are required to be included in the Nutrition Facts panel. Saturated fat is a type of fat that is associated with an increased risk of certain health conditions, and providing the calorie value helps consumers monitor their intake.

Therefore, the Nutrition Facts panel must include b. grams of monounsaturated fat, c. grams of total fat, and d. total calories from saturated fat.

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Answer: C Alternative

Explanation:

Hope this helps

Another name for non-traditional sports is Alternative. Alternative sports often involve unconventional or niche activities that may appeal to specific groups or subcultures. The correct option is option (c).

Another name for non-traditional sports is "alternative sports." These are sports or physical activities that may not be as mainstream or commonly recognized as traditional sports like football, basketball, or tennis.

Alternative sports often involve unconventional or niche activities that may appeal to specific groups or subcultures.

They provide alternatives to more traditional sports and can include activities like parkour, skateboarding, rock climbing, ultimate frisbee, and many others. Therefore, The correct option is option (c).

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The deceleration for a car traveling at 55 km/h can be interpolated to be 7.06 m/s².

A) To find whether the car will stop in time or not, we have to use the below formula:Where,

t = time taken to stop

v = initial velocity

u = final velocity

a = deceleration distance = vt + 0.5at²

We can use the above formula and find the distance covered by the car before stopping.

If the distance covered by the car is less than 40 m, then the car will stop in time and the child will be saved. If the distance is greater than or equal to 40 m, then the car will not be able to stop in time and the child will be hit.

For a car traveling at 55 km/h, the speed is 15.28 m/s. The deceleration values for different cars can be found from the table below:Speed (m/s) Braking Distance Toyota Corolla
(m) Nissan 200SX
(m) Mercedes C36
(m) Ferrari550 Maranello
(m) Lexus LS400
(m)60 14.9 17.2 20.1 24.8 16.070 20.3 23.4 27.4 33.8 21.880 26.5 30.6 35.8 44.1 28.490 33.6 38.7 45.3 55.8 36.0100 41.5 47.8 55.9 68.9 44.4110 50.2 57.8 67.7 83.4 53.8120 59.7 68.8 80.5 99.2 64.0

Therefore, Interpolation shows that the deceleration for an automobile moving at 55 km/h is 7.06 m/s2. .

Using the formula for deceleration with initial velocity of 15.28 m/s, we get the distance covered by the car before stopping to be:distance = (15.28)² / 2 * 7.06 = 19.68 m

As the distance covered by the car is less than 40 m, the car will stop in time.

B) The limitations of this model are:This model assumes that the car is traveling on a flat surface and the road conditions are good.

The model does not take into account the reaction time of the driver and assumes that the driver reacts immediately to the child running onto the road.

The model does not take into account the age of the vehicle, the weight of the vehicle, the condition of the brakes and tires, and other factors that may affect the braking distance of the car.

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Answer:

0.25

Explanation:

According to newtons law of motion

\sum F_x = ma

F_f =  ma

nR = ma

nmg = ma

ng = a

n = a/g

g is the acceleration due to gravity

Given

a = 2.42m/s²

g = 9.8m/s²

Substitute into the formula;

n = 2.42/9.8

n = 0.25

Hence the coefficient of kinetic friction is 0.25

Answer:

0.247

Explanation:

I had the same question and this is the correct answer.

Answer:

1.55

Explanation:

that it is the standard refractive index.