1) Which of the following is considered an effective treatment for someone with hearing loss based on nerve damage?

TAD
Cochlear implant
Hearing aid
OBI
No treatment available


2) Sylvester is dealing with hearing loss. The doctor informs him that his basilar membrane is damaged. What type of hearing loss is Sylvester experiencing?

Nerve deafness
Conduction hearing loss
Cochlear hearing loss
Conduction deafness
Sensory hearing loss

A 2.3 N rock being thrown in a sling experiences a centripedal acceleration of 7.30 cm/s.

The value of the centripetal acceleration, symbolized by the letter ac, is equal to the square of the body's speed along the curve divided by the circle's radius. This is sometimes referred to as the equation ac = v2/r.

The equation ac=v2r determines the acceleration of an object travelling at a speed of v inside a circle of radius r. Therefore, as you have probably noticed while driving a car, centripetal acceleration is larger at high speeds and in acute curves (lower radius).

aC = 2vr

2.3 C = 2 × 0.7 × 12

C = 2 × 0.7 × 12 / 2.3

C = 7.30

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Answer:

Vy = 4.43 m/s

Explanation:

given data

velocity = 9 m/sec

angle horizontal = 29.5 degrees

solution

we get here ball initial vertical velocity will be here

Vy = v sinθ       ...........................1

put here value and we get

Vy = 9 × sin(29.5 )  

Vy = 4.43 m/s

Answer:

If there are more molecules present, or there's a bigger surface area on which the reaction happens, there will be more successful collisions and the reaction will go faster. Also, if the temperature is higher, more molecules will have enough energy to react, and the reaction will be faster.

Answer:

2.11 m/s

Explanation:

Take north to be positive and south to be negative.

Average velocity = displacement / time

v = (82 m + -44 m) / (14 s + 4 s)

v = 2.11 m/s

The velocity is positive, so it is 2.11 m/s north.  The magnitude of the velocity is 2.11 m/s.

The identification requires a record of the prints of all 10 fingers of a person made using ink or digital imaging is Fingerprint identification.

The print of fingers are taken by the digital imaging to recognize a specific person, specially used to detect criminals.

Therefore, Fingerprint identification requires a record of the prints of all 10 fingers of a person made using ink or digital imaging.

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A material in which electrons are not able to move easily is known as an insulator, on the other hand, the material in which electrons are able to move easily is known as the conductor, therefore the correct answer is option B.

The elements of the periodic tables that behave as metals, as well as the nonmetal in some chemical or physical aspects, are known as metalloids. Some examples of metalloids are Boron, silicon, germanium, arsenic, antimony, tellurium, etc.

As given in the problem we have to find out the term for material for which electrons are not able to move easily,

The term "insulator" refers to a substance in which electrons cannot move around freely, whereas the term "conductor" refers to a substance in which electrons may flow around freely. Therefore, option B is the right response.

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Answer:

The value is  \(m = 69.24 \ kg\)

Explanation:

From the question we are told that

   The value of the external force is  \(F = 59.0 \ N\)

    The magnitude of the astronaut's acceleration is  \(a = 0.852 \ m/s\)

Generally Newton's Second Law of Motion from the mass of the astronauts is mathematically represented as

            \(m = \frac{F}{a}\)

=>         \(m = \frac{59 }{0.852 }\)

=>         \(m = 69.24 \ kg\)  

Answer:

4.8E-19C

Explanation:

Charge is calculated by getting the net sum of protons and electrons

So

87protons - 84electrons= +3

So the charge of the ion is +3

But 1proton= 1.6*10^-19C

So charge will be 3 x 1.6E-19C

4.8x10^-19C

Answer:

A

For Yanni, the speed of the ball is 23 m/s, and for the quarterback, the speed of the ball is 15 m/s.

Explanation:

Right on edge 2021

The statement supported by this scenario is, for Yanni, the speed of the ball is 23 m/s, and for the quarterback, the speed of the ball is 15 m/s.

The relative speed of the ball is determined with respect to frame of reference.

Vr/b = va + vb

Vr/b = 8 + 15 = 23 m/s

Vr/b = va + vb

Vr/b = 0 + 15 = 15 m/s

Thus, the statement supported by this scenario is, for Yanni, the speed of the ball is 23 m/s, and for the quarterback, the speed of the ball is 15 m/s.

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The weight of the rover vehicle on Earth, given that it weighs 37 N on Mars is 99.5 N

We'll begin by obtaining the mass of the rover vehicle. This is shown below:

Weight (W) = mass (m) × Acceleration due to gravity (g)

W = mg

Divide both sides by g

m = W /g

m = 37 / 3.72

m = 9.95 Kg

Now, we shall determin the weight of the rover vehicle on Earth. Details below:

Weight (W) = mass (m) × Acceleration due to gravity (g)

Weight (W) = 9.95 × 10

Weight = 99.5 N

Thus, we can conclude that the weight on Erath is 99.5 N

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The given problem can be exemplified in the following diagram:

To determine the extension force we will use the definition of pressure:

Where "F" is the force, and "A" is the area. To determine the area we will use the following equation:

Where "D" is the diameter. The force acts over the area of the 10 inches diameter alone, therefore we don't need to have into account the area of the rod. Replacing the value of the diameter we get:

Solving the operation:

Replacing in the formula for the pressure we get:

Since we are required to determine the force, we will multiply both sides by the area:

Replacing the given value of the pressure we get:

Solving the operations we get:

Therefore, the extension force is 107756.62 lbf.

The answer is  energy 3 times as much. option A.

To calculate the amount of energy released when a 5 kg object is converted to pure energy, we can use Einstein's famous equation: E = mc². In this equation, E represents energy, m represents mass, and c represents the speed of light.

Given that the mass of the object is 5 kg, we can calculate the energy using the equation:

E = (5 kg) * (c²)

Now, to compare this energy with the amount of energy the Earth receives from the Sun every second, we need to determine the Earth's solar energy input.

The solar constant is the amount of solar radiation received per unit area at the Earth's distance from the Sun. Its average value is approximately 1361 Watts per square meter (W/m²). Multiplying this value by the surface area of the Earth (approximately 510 million square kilometers), we can estimate the total energy received by the Earth from the Sun every second.

Energy from the Sun = (1361 W/m²) * (510,000,000,000 m²)

To compare the energy released from converting a 5 kg object to energy with the energy received from the Sun, we divide the former by the latter:

Energy conversion / Energy from the Sun = [(5 kg) * (c²)] / [(1361 W/m²) * (510,000,000,000 m²)]

Simplifying the equation, we find:

Energy conversion / Energy from the Sun = (5 kg * c²) / (1361 W/m² * 510,000,000,000 m²)

The value of c² is approximately (3x10^8 m/s)² = 9x10^16 m²/s².

Plugging in the values, we get:

Energy conversion / Energy from the Sun = (5 kg * 9x10^16 m²/s²) / (1361 W/m² * 510,000,000,000 m²)

Simplifying further:

Energy conversion / Energy from the Sun ≈ 3.52

Therefore, the amount of energy released when a 5 kg object is converted to pure energy is approximately 3.52 times larger than the amount of energy the Earth receives from the Sun every second.

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The schrodinger's equation for \((A\phi_1+AU\Psi_1)+(B\phi_2+BU\Psi_2)\) for the particular U and E can be expressed as \((A\phi_1+AU\Psi_1)+(B\phi_2+BU\Psi_2)=E(A\Psi_1+B\Psi_2)\).

The solution to the equation is based on Fourier's Eigen Values method. This is the expression for any mathematical function as the sum of an infinite series of other periodic functions. The trick is to find the right functions with the right amplitudes so that when they are superimposed, they give the desired solution.

As a result, the solution to Schrondinger's equation, the system's wave function, was replaced by the wave functions of the individual series, natural harmonics of each other, resulting in an infinite series. Shrodinger discovered that replacement waves described individual states of the quantum system, and their amplitudes indicated the relative importance of that state to the entire system.

The schoringer 's equation is

\(-\frac{h^2}{2m}\frac{d\psi^2}{dx^2}+U(x) \psi=E\psi\)

here, the E is the energy of the particle.

since the wave function \(\psi_1\) is the solution of the schrodinger's equation,

\(-\frac{h^2}{2m}\frac{d\psi_1^2}{dx^2}+U(x) \psi=E\psi_1\)

Since, the wave function \(\psi_2\) is the solution of the schrodinger's equation,

\(-\frac{h^2}{2m}\frac{d\psi_2^2}{dx^2}+U(x) \psi=E\psi_2\)

Then,

\((A\phi_1+AU\Psi_1)+(B\phi_2+BU\Psi_2)=(A(-\frac{h^2}{2m}\frac{d\Psi_1^2}{dx^2})+AU\Psi_1)+(B(-\frac{h^2}{2m}\frac{d\Psi^2}{dx^2})+BU\Psi_2)\\\\=A(-\frac{h^2}{2m}\frac{d\Psi_1^2}{dx^2}+U\Psi_1)+B(-\frac{h^2}{2m}\frac{d\Psi_1^2}{dx^2}+U\psi_2)\\\\=A(-\frac{h^2}{2m}\frac{d\Psi_1^2}{dx^2}+U(x)\Psi_1)+B(-\frac{h^2}{2m}\frac{d\Psi_1^2}{dx^2}+U(x)\psi_2)\\\\=A(E\Psi_1)+B(E\Psi_2)\\\\=E(A\Psi_1+B\Psi_2)\)

Thus, the schrodinger's equation  for particular U and E can be expressed as \(E(A\Psi_1+B\Psi_2)\).

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Your question is incomplete, here is the complete question in the figure,

Answer:

In psychology, a drive theory, theory of drives or drive doctrine is a theory that attempts to analyze, classify or define the psychological drives. A drive is an instinctual need that has the power of driving the behavior of an individual; an "excitatory state produced by a homeostatic disturbance".

The carbon has a mass of 3.0 g and a volume of 10 cm³. So we will calculate the density. The formula to calculate its density is:

d = m/v

We substitute the data in the formula and solve:

d = 3.0 g/10 cm³

d = 0.3 g/cm³

Therefore the density of the carbon sample is 0.3 g/cm³. Opction "A".

Many of the properties of galaxies (including the galaxy color–magnitude diagram) indicate that there are fundamentally two types of galaxies. These groups divide into blue star-forming galaxies that are more like spiral types, and red non-star forming galaxies that are more like elliptical galaxies.

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Answer:

by counting each individual atom and making sure the number of each kind of atom is the same in the reactants and the products. - This is the answer.

Explanation:

Answer:

its A(by counting each individual atom and making sure the number of each kind of atom is the same in the reactants and the products

Explanation:

All the equations of motion are as follows, Displacement (s) equation, Final velocity (v) equation, Average velocity (v_avg) equation, Displacement (s) equation with average velocity, and Displacement (s) equation.

In terms of its motion as a function of time, equations of motion define how a physical system behaves. In more detail, the equations of motion define how a physical system behaves as a collection of mathematical functions expressed in terms of dynamic variables.

In conclusion, equations of motion define how a physical system behaves in terms of how its motion changes over time.

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Answer:

Explanation:

The mass of cube = 700 kg

volume = 1 m³

density = 700 kg / m²

Its density is less than that of water so it will try to float on the surface .

Tension in rope will be equal to net upward force

upthrust = volume x density of water x g

= 1 x 10³ x 9.8

= 9800 N

weight of cube = mass x g

= 700 x 9.8

= 6860 N .

Net upward force = 9800 - 6860

= 2940 N.

Tension in the rope = 2940 N.

Rope will hold the cube inside and not allow it to go outside water .

b )

If rope is cut , cube being lighter , will float on surface of water .

Part of cube inside water while floating

= 6860 / 9800

= .7

.7 m will remain inside water

part floating outside

= 1 - 0.7

= 0.3 m .

Answer:

not clear pic...but it's definitely not A)

a) The speed of the bead at B is 11.79m/s.

b) The change in mechanical energy due to friction as it  moves from B to C is 36.064 J.  

If we drop the object from the shelf or release the spring, that potential energy is converted back into kinetic energy. Kinetic energy can also be transferred from one body to another in a collision, which can be elastic or inelastic.

a)

Potential energy is converted  to kinetic energy

\(\frac{1}{2} mv^2=mgh\\\\v=\sqrt{2gh} \\\\v_B=\sqrt{2(9.8)(7.1-0)} \\\\v_B=11.79m/s\)

The speed of the bead at B is 11.79m/s.

b)

\(W = mg(h_A) - mg(h_B) = 0.8(9.8)(7.1 - 2.5) = 36.064 J\\\\W=36.064J\)

The change in mechanical energy due to friction as it  moves from B to C is 36.064 J.

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Answer:

sbdjhdjrjrjrjrjrbdhhrhejejejejejejejejdndndjsj

Answer: My hypothesis was that the future results of the experiment would show a correlation. According to my data, my hypothesis was correct. The file uploaded to this assignment shows that the graph is a correlation but not a 100% positive correlation because if you imagined there was a straight line there, the points would be completely aligned. The correlation is simply a “positive correlation”. Some of the difficulties I had when performing the experiment was distinguishing which type of luster was for each mineral because the light almost looked the same with other minerals. You might change the procedure to avoid this problem in the way of getting all the rest of the results for that specific mineral and then look at which of the graph with the answers was most alike and then you can see why the luster is that certain result in that data which is the correct one. A graphical analysis can be used to explore the relationship between any two scientific variables by changing the numerical data of the experiment into a graph, which is a much more effective and easier way of interpreting the gathered results. It's easier to visualize a graph data than read all the tables with numbers.

The graph is in the attachment below and the 6 minerals also with their names, their density, and their hardness

The picture shown in the figure represents the Milky Way Galaxy. The Galaxy in which the entire solar system is present.

The million and trillion of stars in the universe form Galaxy. The galaxy in which the entire solar system is present is called Milky Way Galaxy. The Milky Way Galaxy is spiral in shape. This Galaxy has four major arms. The major arms have both old and young stars and the minor arms have the gas and star formation activity. This galaxy also has a black hole at its center. Galileo Galilei was the first to see the Galaxy.

The Milky Way Galaxy is made up of a dense cloud of gas that stretches across the sky as seen from the Earth. The age of the Milky Way Galaxy is 13.61 billion years ago and the Andromeda Galaxy is the nearest galaxy to the Milky Way Galaxy.

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Answer: 25%

Explanation:

From the question, we are informed that the temperature of source and sink of cannot engine are 400K

and 300K respectively.

The efficiency will be calculated as:

= 1 - t/T

= 1 - 300/400

= 1 - 3/4

= 1/4

= 25%

At 30°C, the rms speed of a sample of oxygen with a molar mass of 16 g/mol is approximately 482.34 m/s.

The root mean square (rms) speed of a gas molecule is a measure of the average speed of the gas particles in a sample. It can be calculated using the formula:

vrms = √(3kT/m)

Where:

vrms is the rms speed

k is the Boltzmann constant (1.38 x 10^-23 J/K)

T is the temperature in Kelvin

m is the molar mass of the gas in kilograms

To calculate the rms speed of oxygen at 30°C (303 Kelvin) with a molar mass of 16 g/mol, we need to convert the molar mass to kilograms by dividing it by 1000:

m = 16 g/mol = 0.016 kg/mol

Substituting the values into the formula, we have:

vrms = √((3 * 1.38 x 10^-23 J/K * 303 K) / (0.016 kg/mol))

Calculating this expression yields the rms speed of the oxygen sample:

vrms ≈ 482.34 m/s

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To determine the magnitude of the lift force ⃗ and the force of air resistance ⃗ acting on the jet, we need to resolve the weight ⃗ and the forward thrust ⃗ into their horizontal and vertical components.

The weight ⃗ can be resolved into two components:

- the vertical component, Wsin(30°), acting downward

- the horizontal component, Wcos(30°), acting to the left

The forward thrust ⃗ can also be resolved into two components:

- the vertical component, Tsin(30°), acting upward

- the horizontal component, Tcos(30°), acting to the right

Since the jet is flying at a constant speed, the lift force ⃗ must be equal in magnitude to the weight component acting downward, Wsin(30°). Therefore, the magnitude of ⃗ is 86,500 Nsin(30°) = 43,250 N.

The force of air resistance ⃗ is equal in magnitude to the horizontal component of the weight, Wcos(30°), minus the horizontal component of the forward thrust, Tcos(30°). Therefore, the magnitude of ⃗ is (86,500 Ncos(30°)) - (103,000 Ncos(30°)) = -8,715 N, where the negative sign indicates that the force of air resistance is acting in the opposite direction to the motion of the jet.

Therefore, the magnitude of the lift force ⃗ is 43,250 N and the magnitude of the force of air resistance ⃗ is 8,715 N.

Answer:

211.2 kg:m/s

Explanation:

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Answer:

Ts = 3.0×10¯² sec

Explanation:

From the question given:

Ts = 2π √(4.5×10¯² Kg / 2.0×10³ Kg/s²)

The above expression can be evaluated as follow:

Pi (π) = 3.14

Ts = 2π √(4.5×10¯² / 2.0×10³)

Ts = 2 × 3.14 √(4.5×10¯² / 2.0×10³)

Ts = 6.28 × √(2.25×10¯⁵)

Ts = 6.28 × 4.74×10¯³

Ts = 3.0×10¯² sec