1. Which property distinguishes all electromagnetic waves from mechanical waves, such as sound waves and water waves?
A. The ability to travel in a vacuum
B. Very short wavelength
C. Oscillations that are perpendicular to the direction of motion
D. Oscillations that are parallel to the direction of motion
PLEASE HELP
Answers
The property that distinguishes all electromagnetic waves from mechanical waves, such as sound waves and water waves, is A. The ability to travel in a vacuum.
Electromagnetic waves, such as light, radio waves, and microwaves, are composed of oscillating electric and magnetic fields that are perpendicular to each other and to the direction of wave propagation. Unlike mechanical waves, which require a medium to transmit energy (like air for sound waves or water for water waves), electromagnetic waves can propagate without a medium. This means they can travel through the vacuum of space, allowing us to receive light from the sun and observe distant stars and galaxies.
In contrast, mechanical waves require a material medium to transfer energy. Sound waves, for example, are created by the vibration of particles in the air, water, or another medium. These vibrations cause a chain reaction of particle movement, carrying the wave's energy from one location to another. If there were no medium to carry the wave, it could not propagate. This is why sound cannot travel in a vacuum, while electromagnetic waves can.
In summary, the ability to travel in a vacuum distinguishes electromagnetic waves from mechanical waves like sound and water waves. The correct option is A. The ability to travel in a vacuum.
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Related Questions
A force F=12i-10j acts on an object. How much work does this force do as the object moves from the origin to the point r=13i+11j
Answers
Therefore, the work done by the force F=12i-10j on an object as it moves from the origin to the point r=13i+11j is 203.06i + 171.82j.
The formula for calculating the work done by a force F when an object is moved from point A to point B is:
W = F. d
Where, W = work done by the force F, F = magnitude of the force, d = displacement vector of the object from point A to point B
Therefore, the work done by the force F=12i-10j on an object as it moves from the origin (point A) to the point
r=13i+11j (point B) can be calculated as follows:
First, we need to find the displacement vector (d) of the object from point A to point B. This is given as:
r - r0 = 13i + 11j - 0i - 0jr - r0 = 13i + 11j - 0 - 0j (where r0 = 0i + 0j is the position vector of the origin
So, the displacement vector of the object from point A to point B is
d = 13i + 11j.
Next, we need to find the magnitude of the force F, which is given as:
F = 12i - 10j
Magnitude of F = √(12² + (-10)²) = √(144 + 100) = √244 = 15.62 (approximately)
Now, we can use the formula W = F. d
to find the work done by the force
F.W = F. d= (15.62)(13i + 11j) (since F = 12i - 10j)
W = (15.62)(13i) + (15.62)(11j)
W = 203.06i + 171.82j
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laundry uses an elevator to move items from one level to another. The elevator has a mass of 500 kg and moves upward with constant acceleration for 3.00 s until it reaches its cruising speed of 1.75 m/s. (Note: 1hp=746 W.) (a) What is the average power (in hp) of the elevator motor during this time interval? Pave =hp (b) What is the motor power (in hp) when the elevator moves at its cruising speed? Pcruising =hp
Answers
To calculate the average power of the elevator motor, we need to find the work done by the motor and divide it by the time interval. The work done can be calculated using the formula: Work = Force × Distance.
Initially, the elevator is at rest, so the net force acting on it is the force required to overcome its own weight. The weight is given by the formula: Weight = mass × acceleration due to gravity = 500 kg × 9.8 m/s^2 = 4900 N.
To accelerate the elevator, an additional force is required. This force can be calculated using Newton's second law: Force = mass × acceleration. The acceleration is given as 1.75 m/s^2, and the mass is 500 kg, so the force is 500 kg × 1.75 m/s^2 = 875 N.
The distance traveled during acceleration can be found using the formula: Distance = (1/2) × acceleration × time^2. Plugging in the values, we get Distance = (1/2) × 1.75 m/s^2 × (3.00 s)^2 = 7.875 m.
Now we can calculate the work done by the motor: Work = (Force × Distance) + (Weight × Distance) = (875 N + 4900 N) × 7.875 m = 40,987.5 J.
The average power can be calculated by dividing the work done by the time interval: Average Power = Work / Time = 40,987.5 J / 3.00 s = 13,662.5 W.
To convert the power from watts to horsepower, we divide by 746: Pave = 13,662.5 W / 746 = 18.33 hp.
When the elevator reaches its cruising speed, it is moving at a constant velocity, which means there is no net force acting on it. Therefore, the motor power required to maintain the cruising speed is zero. Thus, Pcruising = 0 hp.
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Details The force on a particle is described by 10x³ - 5 at a point x along the x-axis. Find the work done in moving the particle from the origin to x = 2.
Answers
Answer:
To find the work done in moving the particle from the origin to x = 2, we need to integrate the force over the given interval.
The work done (W) is calculated by integrating the force function with respect to displacement (dx) from the initial position (0) to the final position (2):
W = ∫(0 to 2) (10x³ - 5) dx
Integrating the force function, we get:
W = ∫(0 to 2) (10x³ - 5) dx = [2.5x⁴ - 5x] evaluated from 0 to 2
Now, substituting the upper limit (2) and lower limit (0) into the equation:
W = [2.5(2)⁴ - 5(2)] - [2.5(0)⁴ - 5(0)]
= [2.5(16) - 10] - [0 - 0]
= 40 - 10
= 30
Therefore, the work done in moving the particle from the origin to x = 2 is 30 units of work.
Explanation:
Need help on this or I’ll completely fail the last semester
Answers
Answer:
Its A I'm 99.9% sure
Explanation:
1. State any ten examples of good conductors of heat.
2. Write down five uses of good conductors.
Answers
Answer:
Examples of Good conductors of heat are,Gold
Sliver
Copper
Mercury
brass
bronze
Lead
Aluminum
Uses of good conductors of heatUsed for making kettles
Used for making sauce pans
Good Uses:
Utensils Food can be cooked Water can be boiledHomes can be warmed Shirts can be ironedConductors of Heat:
AluminumLeadBrassBronze MercuryGoldSliver Copper
A bicyclist travels 60.0 kilometers in 3.5 hours. What is the cyclist's average speed? Note: Average speed is the total distance divided by the total time taken.
Answers
Answer:
The average speed of the cyclist is 17.14 km/hr
Explanation:
Given;
total distance traveled by the cyclist's, d = 60 km
time taken by the cyclist, t = 3.5 hours
The average speed of the cyclist is given by;
average speed = total distance traveled / total time taken
average speed = 60 km / 3.5 hr
average speed = 17.14 km/hr
Therefore, the average speed of the cyclist is 17.14 km/hr
4) from the plots, determine the short-circuit current corresponding to the same value of field current which produced the rated open-circuit voltage.
Answers
Short circuit current vs field current slope from the curve for If=0.2 and If=0.4.
Slope = (Isc(If=0.4)-Isc(If=0.2))/2
An electric current modern-day is a circulation of charged debris, which include electrons or ions, transferring through an electrical conductor or space. it's miles measured because the net charge of go with the flow of electrical charge thru a floor or into a manipulated volume.
The current flowing in a circuit may be utilized in a diffusion of approaches from producing warmness to inflicting circuits to exchange, or statistics to be stored in an integrated circuit.
There are three simple currents utilized in business healing electric stimulation units: direct cutting-edge, alternating contemporary, and pulsed modern-day.
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Students conducted a lab investigation in which they applied 10,000 J of heat to 50 g samples of three different materials and measured the temperature change in each material. Which material has the highest specific heat?
Time (min)
Temperature (°C)
Material A
Material B
Material C
0
25°C
25°C
25°C
5
27°C
37°C
31°C
10
29°C
49°C
37°C
15
31°C
61°C
43°C
20
33°C
73°C
49°C
Claim
Evidence
Reasoning
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"Please include all relevant working out as detailed as possible
and all relevant diagram to find the answer. Much appreciated! I
will upvote! Thank you so much"
Find total response of the system (transient+steady state). Do not solve for coefficients. Determine the frequency of applied force at which resonance will occur? M = 20 kg F, = 90 N Given: -6 rad/s M
Answers
Given the following information:Mass of the system, m = 20 kg.Damping coefficient, b = 6 Ns/m.Force, F = 90 N.Frequency of applied force, f = ?Applied force angular frequency, w = 6 rad/s.Forced vibration equation:F(t) = F0 sin(wt)where F0 = 90 N and w = 6 rad/s.Under the action of the force F, the mass m will oscillate.The equation of motion for the mass-spring-damper system is given by:$$\mathrm{m\frac{d^{2}x}{dt^{2}}} + \mathrm{b\frac{dx}{dt}} + \mathrm{kx = F_{0}sin(\omega t)}$$where k is the spring constant.x(0) = 0 and x'(0) = 0.As we have the damping coefficient (b), we can calculate the damping ratio (ζ) and natural frequency (ωn) of the system.Damping ratio:$$\mathrm{\zeta = \frac{b}{2\sqrt{km}}}$$where k is the spring constant and m is the mass of the system.Natural frequency:$$\mathrm{\omega_{n} = \sqrt{\frac{k}{m}}}$$where k is the spring constant and m is the mass of the system.Resonant frequency:$$\mathrm{\omega_{d} = \sqrt{\omega_{n}^{2}-\zeta^{2}\omega_{n}^{2}}}$$At resonance, the amplitude of the system will be maximum when forced by a sinusoidal force of frequency equal to the resonant frequency.Resonant frequency:$$\mathrm{\omega_{d} = \sqrt{\omega_{n}^{2}-\zeta^{2}\omega_{n}^{2}}}$$$$\mathrm{\omega_{d} = \sqrt{(6.57)^{2}-(-2.88)^{2}} = 6.98 rad/s}$$Hence, the frequency of applied force at which resonance will occur is 6.98 rad/s.
The frequency of the applied force at which resonance will occur is ω = 2√5 rad/s.
To determine the frequency of the applied force at which resonance will occur, resonance happens when the frequency of the applied force matches the natural frequency of the system. The natural frequency can be determined using the formula:
ωn = √(K / M),
where ωn is the natural frequency, K is the spring constant, and M is the mass of the system.
Substituting the given values of K = 400 N/m and M = 20 kg into the equation, we can calculate the natural frequency ωn.
ωn = √(400 N/m / 20 kg) = √(20 rad/s²) = 2√5 rad/s.
Therefore, the frequency of the applied force at which resonance will occur is ω = 2√5 rad/s.
The correct question is given as,
M= 20kg
Fo = 90 N
ω = 6 rad/s
K = 400 N/m
C = 125 Ns/m
Determine the frequency of applied force at which resonance will occur?
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what must happen in order for a metaphoric rock to be transformed into a igneous rock
Answers
Answer:
If the newly formed metamorphic rock continues to heat, it can eventually melt and become molten (magma). When the molten rock cools it forms an igneous rock.
Explanation:
these waves are slower than those that originate at the focus.
Answers
The waves that are slower than those that originate at the focus are called surface waves. Surface waves are seismic waves that propagate along the surface of the Earth.
These waves are the slowest seismic waves, but they are also the most destructive.Surface waves are responsible for the majority of the damage caused by earthquakes. They move in a rolling, swaying motion that can cause the ground to rise and fall like ocean waves, which can cause buildings and other structures to collapse.Surface waves are divided into two types: Love waves and Rayleigh waves.
Love waves cause horizontal shaking, while Rayleigh waves cause both vertical and horizontal shaking. Both types of waves can cause significant damage to buildings and other structures, particularly those that are not designed to withstand the horizontal shaking that is caused by Love waves.
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what is the correct answer?
Answers
Answer:
D) 4
Explanation:
Roots of a polynomial must be factors of the last term.
In this case, the factors of 6 are +1, -1, +2, -2, +3, -3, +6, -6. The only factor that doesn't show up, given the options, is 4. This means that D is the correct answer.
1. A 5 kg block is pulled across a table by a horizontal force of 40 N with a frictional force of 8 N
opposing the motion. Calculate the acceleration of the object.
Answers
The acceleration of the block is 6.4 m/s².
To calculate the acceleration of the block, we need to consider the forces acting on it.
The applied force is 40 N, and since it is the only horizontal force in the direction of motion, it is the net force acting on the block.
The frictional force opposing the motion is 8 N.
The acceleration, we can use Newton's second law, which states that the net force acting on an object is equal to its mass multiplied by its acceleration (F = ma).
The net force is the difference between the applied force and the frictional force:
40 N - 8 N = 32 N.
Now, we can plug the values into Newton's second law:
32 N = 5 kg × a.
Solving for the acceleration (a), we get
a = 32 N / 5 kg
a = 6.4 m/s².
Therefore, the acceleration of the block is 6.4 m/s².
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The image above shows a crash test dummie's head traveling at -1.005 m/s while striking a headrest from a car traveling 4.524 m/s with a mass of 2005.6 kg. If the crash test dummie's head head bounces off the headrest with a 9.965 m/s and the car continues traveling at 4.487 m/s, calculate the mass of the crash test dummie's head?
Answer:
Answers
From the calculation, the mass of the dummies head is 1647.44 Kg
What is the mass of the crash test dummies head?We know that the momentum after collision is equal to the momentum before collision.
Mass of the headrest = 2005.6 kg
Initial velocity of the head rest = 4.524 m/s
Final velocity of the head rest = 4.487 m/s
Mass of the dummy = m
Initial velocity of the dummy = -1.005 m/s
Final velocity of the dummy = 9.965 m/s
Then;
(m * -1.005) + (2005.6 * 4.524 ) = (2005.6 * 4.487) + (m * 9.965)
-1.005m + 9073.33 = 8999.13 + 9.965m
9073.33 - 8999.13 = 9.965m + 1.005m
18072.46 = 10.97m
m = 18072.46/ 10.97
m = 1647.44 Kg
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A 1.5-m diameter circular footing has its base buried at a depth of 2.5 m from the natural grade line while the water table is located a depth of 1.2 m below the natural grade line. The soil above the water table is 21.437 kN/ms while the saturated unit weight is 23.309 kN/m3. The soil has a cohesion of 25 kPa. Assuming local shear failure, a factor of safety of 3.2, and bearing capacity factors Nc=11.85. Nq-3.88 and Ny- 1.12 a. Compute the ultimate bearing capacity of the soil. b. Compute the allowable bearing capacity of the soil. C. Compute the allowable load on the footing.
Answers
The allowable bearing capacity, obtained by dividing the ultimate bearing capacity by the factor of safety, is determined as 116.787 kN/m². Consequently, the allowable load on the footing is found to be 206.224 kN.
a. The ultimate bearing capacity of the soil can be calculated using the Terzaghi's bearing capacity equation for a circular footing. The equation is given as:
Qu = cNc + qNq + 0.5γBNγ
Where:
Qu = Ultimate bearing capacity
c = Cohesion of the soil = 25 kPa
Nc = Bearing capacity factor = 11.85
q = Effective vertical stress = γ × (Df - Dw)
Nq = Bearing capacity factor = 3.88
γ = Unit weight of soil above the water table = 21.437 kN/m³
B = Width or diameter of the footing = 1.5 m
Nγ = Bearing capacity factor = 1.12
Df = Depth of the footing = 2.5 m
Dw = Depth of the water table = 1.2 m
Let's calculate the values and plug them into the equation:
q = γ × (Df - Dw)
= 21.437 kN/m³ × (2.5 m - 1.2 m)
= 15.5575 kN/m²
Qu = cNc + qNq + 0.5γBNγ
= 25 kPa × 11.85 + 15.5575 kN/m² × 3.88 + 0.5 × 21.437 kN/m³ × 1.5 m × 1.12
= 296.25 kN/m² + 60.396 kN/m² + 17.076 kN/m²
= 373.722 kN/m²
Therefore, the ultimate bearing capacity of the soil is 373.722 kN/m².
b. The allowable bearing capacity of the soil can be determined by dividing the ultimate bearing capacity by the factor of safety (FOS). The equation is given as:
qa = Qu / FOS
Where:
qa = Allowable bearing capacity
Qu = Ultimate bearing capacity = 373.722 kN/m²
FOS = Factor of safety = 3.2
Let's calculate the allowable bearing capacity:
qa = Qu / FOS
= 373.722 kN/m² / 3.2
= 116.787 kN/m²
Therefore, the allowable bearing capacity of the soil is 116.787 kN/m².
c. The allowable load on the footing can be calculated by multiplying the allowable bearing capacity by the area of the circular footing. The equation is given as:
Pa = qa × A
Where:
Pa = Allowable load on the footing
qa = Allowable bearing capacity = 116.787 kN/m²
A = Area of the footing = π × (B/2)²
Let's calculate the allowable load:
A = π × (B/2)²
= 3.14159 × (1.5 m / 2)²
= 1.76715 m²
Pa = qa × A
= 116.787 kN/m² × 1.76715 m²
= 206.224 kN
Therefore, the allowable load on the footing is 206.224 kN.
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Which of the following has both kinetic and potential energy?
A. A bug crawling on the ground
B. A ball rolling on the ground
C. A hot air balloon flying
D. A book sitting on a shelf
PLEASE HURRY
Answers
Answer:
c
Explanation:
an object weights 0.250 kgf in air 0.150 in water and 0.125 in an oil.find out the density of the object and the oil
Answers
Answer:
1) The density of the object = 2500 kg/m³
2) The density of the oil = 1250 kg/m³
Explanation:
1) The information relating to the question are;
The mass of the object in air = 0.250 kgf
The mass of the object in water = 0.150 kgf
The mass of the object in the oil = 0.125 kgf
By Archimedes's principle, we have;
The upthrust on the object in water = Mass in air - mass in water = The weight of the water displaced
The upthrust on the object in water = 0.250 - 0.150 = 0.1 kgf
∴ The weight of the water displaced = 0.1 kgf
Given that the object is completely immersed in the water, we have;
The volume of the water displaced = The volume of the object
The volume of 0.1 kg of water water displaced = Mass of the water/(Density of water)
The volume of 0.1 kg of water = 0.1/1000 = 0.0001 m³
The density of the object = (Mass in air)/ volume = 0.250/0.0001 = 2500 kg/m³
The density of the object = 2500 kg/m³
2) Whereby the mass of the object in the oil = 0.125 kgf
The upthrust of the oil = The weight of the oil displaced
The upthrust of the oil on the object = Mass of the object in air - mass of the object in the oil
The upthrust of the oil on the object = 0.250 - 0.125 = 0.125 kgf
The weight of the oil displaced = The upthrust of the oil
Given that the volume of the oil displaced = The volume of the oil, we have;
The volume of the oil displaced = 0.0001 m³
The mass of the 0.0001 m³ = 0.125 kg
Therefore the density of the oil = 0.125/0.0001 = 1250 kg/m³.
The density of the oil = 1250 kg/m³.
the weight of a body is usually measured by disregarding the buoyant force applied by the air. consider a 22-cm-diameter spherical body of density 7800 kg/m3. what is the percentage error associated neglecting air buoyancy? take the density of air to be 1.2 kg/m3.
Answers
The percentage error associated with neglecting air buoyancy when measuring the weight of the spherical body is approximately 0.0155%.
These steps can be used to determine the percentage inaccuracy that results from weighing a spherical body without accounting for air buoyancy: Determine the spherical body's volume.
The following formula can be used to determine a sphere's volume:
V = (4/3)× π ×r³
where r denotes the sphere's radius. If the spherical body's diameter is 22 cm, we may determine its radius (r) by dividing it by two:
r = 22 cm / 2 = 11 cm = 0.11 m.
Substituting the value of r into the formula for volume, we get:
V = (4/3) × π × (0.11 m)³
V = 0.0017433 m³
Calculate the weight of the body in vacuum.
The weight of an object can be calculated using the formula:
Weight = Mass * Acceleration due to gravity (g).
Mass = Density * Volume
Mass = 7800 kg/m³ * 0.0017433 m³
Mass = 13.587 kg
Acceleration due to gravity (g) is usually taken as 9.8 m/s².
Weight = 13.587 kg * 9.8 m/s²
Weight = 133.0236 N
Calculate the buoyant force of air on the body.
The buoyant force of air on the body can be calculated using the formula:
Buoyant force = Density of air ×Volume of body × Acceleration due to gravity
Buoyant force = 1.2 kg/m³× 0.0017433 m³ ×9.8 m/s²
Buoyant force = 0.02058 N (rounded to 5 decimal places)
Calculate the percentage error.
The percentage error can be calculated using the formula:
Percentage error = (Buoyant force / Weight) ×100
Percentage error = (0.02058 N / 133.0236 N) × 100
Percentage error = 0.0155%
So, the percentage error associated with neglecting air buoyancy when measuring the weight of the spherical body would be approximately 0.0155%.
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which will have longer shadow: ben whose height is 5 feet tall and 2 inches or his brother mike who is 6 feet and 2 inches when they both stand under the sun around 10am? i need help asap and anyone get my answer now i will give branliest
Answers
Answer: I believe his brother, Mike, who is 6'2, will have the longer shadow.
A Ferris wheel with a diameter
of 40 m makes one revolution
every 20 minutes. What is its
average speed in meter/min?
Answers
Answer:
6.3 m/min
Explanation:
Circumference of a circle = 2πr
r = D/2 = 40m/2 = 20m
C = 2π(20m) = 125.7 m
speed = distance/time = (125.7 m) / (20 min) = 6.3 m/min
Question 7 of 25Concave lenses havefocal lengths and always formimages.O A. negative; virtualO B. positive; virtualO C. positive; realO D. negative; realSUBMIT
Answers
Concavelenses have negative focal length and tlways form virtual images.
The focal length is negative as it lies on the left side of lenses.
An indicator that orients you when describing a motion is called the_____
A. time
B. Speed
C. reference point
D. point of motion
Answers
An indicator that orients you when defining a motion is called the reference point. The reference point provides a fixed framing of reference for monitoring and describing the position, velocity, and acceleration of an object.
How can you explain the use of reference point?If you are describing the motion of a car on a highway, you can use the side of the road or a specific landmark as the reference point. By using a reference point, you can determine the position, velocity, and acceleration of the car.
How can you determine an object is in motion?An object is considered to be in motion if its position changes relative to a reference point over time. There are several ways to resolve if an object is in motion like Heeding its position, measuring its velocity and observing its acceleration.
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The classification of spiral galaxies is based on three properties:
Answers
Spiral galaxies are classified based on spiral arm tightness, bulge size, and amount of gas and dust present. This allows astronomers to categorize them into subtypes such as Sa, Sb, and Sc.
The classification of spiral galaxies is based on three properties:
1. Spiral arm tightness: This refers to how tightly wound the spiral arms are around the galaxy's center. Galaxies with more tightly wound arms are classified as "Sa," while those with more loosely wound arms are classified as "Sc."
2. Bulge size: The central bulge of a spiral galaxy can vary in size. Larger bulges are typically found in early-type spiral galaxies (such as Sa), while smaller bulges are found in late-type spiral galaxies (like Sc).
3. Amount of gas and dust: The presence and distribution of gas and dust within a spiral galaxy also play a role in its classification. Early-type spiral galaxies generally have less gas and dust compared to late-type spiral galaxies.
By considering these three properties, astronomers can classify spiral galaxies into various subtypes (such as Sa, Sb, and Sc) within the broader spiral galaxy category.
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Light from two different flashlights does not produce an interference pattern because it is incoherent. Is this true or false?
Answers
The given statement is true because the light from two different flaslihgts do not produce interference pattern because it's incoherent.
Therefore, the statement is true.A small car of mass M travels along a straight,horizontal track. As suggested in the figure, the track then bendsinto a vertical circle of radius R.
What is the minimum acceleration that the car must have at the topof the track if it is to remain in contact with the track?
A) 4. 9 m/s2,upward
B) 9. 8 m/s2,downward
C) 4. 9 m/s2,downward
D) 9. 8 m/s2,upward
E) 19. 6 m/s2,upward
Answers
According to the given statement the correct answer will be option ( D ) 9.8 m/s², upward.
The minimum acceleration that the car must have at the top of the track in order to remain in contact with the track can be determined by considering the forces acting on the car.
When the car is at the top of the track, it is in circular motion and experiences two forces:
its weight (mg) acting downward and the normal force (N) exerted by the track acting upward.
To remain in contact with the track, the net force acting on the car must be directed towards the center of the circle.
This means that the net force should be the difference between the normal force and the weight, and it should be directed downward.
The net force is given by:
Net force = N - mg
At the top of the track, the net force is equal to the centripetal force required to keep the car moving in a circle of radius R.
The centripetal force is given by:
Centripetal force = mv² / R
where m is the mass of the car and v is its velocity.
Setting the net force equal to the centripetal force, we have:
N - mg = mv² / R
Solving for v², we get:
v² = gR
where g is the acceleration due to gravity.
The minimum acceleration at the top of the track is when v is at its maximum value, which is when v = √(gR).
Therefore, the minimum acceleration that the car must have at the top of the track is:
a = v² / R = (gR) / R = g
The minimum acceleration that the car must have at the top of the track in order to remain in contact with the track is equal to the acceleration due to gravity (g).
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A force of 75 N at an angle of 15° to the direction of motion moves a chair 3 m. Which change would result in more work being done on the chair?
Answers
Answer:
Decreasing the angle to 10
Explanation:
Edge 2020
this si a 2 part question84) A shock absorber is designed to quickly damp out the oscillations that a car would otherwise make because it is suspended on springs. (a) Find the period of oscillation of a 1610-kg car that is suspended by springs that make an effective force constant of 5.75×104 N/m. (b) Find the damping constant b that will reduce the amplitude of oscillations of this car by a factor of 5.00 within a time equal to half the period of oscillation.
Answers
Given data
*The given mass of the car is m = 1610 kg
*The given effective force constant is k = 5.75 × 10^4 N/m
(a)
The formula for the period of oscillation of a 1610 kg car is given as
\(T=2\pi\sqrt[]{\frac{m}{k}}\)Substitute the known values in the above expression as
\(\begin{gathered} T=2\times3.14\times\sqrt[]{\frac{1610}{5.75\times10^4}} \\ =1.05\text{ s} \end{gathered}\)Hence, the time period of oscillation of a 1610 kg car is T = 1.05 s
(b)
As from the given data, the amplitude of the oscillation of the car decreases by a factor of 5.00. Then, the expression for the amplitude of the oscillation, and the damping constant (b) is calculated as
\(A=A_0e^{-\frac{bt}{2m}}\)Substitute the known values in the above expression as
\(\begin{gathered} \frac{A_0}{5.0}=A_0e^{-\frac{bt}{2m}} \\ bt=2m\ln (5.0)_{} \\ b(\frac{T}{2})=2m\ln (5.0) \\ b=\frac{4m\ln (5.0)}{T} \\ =\frac{4\times1610\times\ln (5.0)}{1.05} \\ =9871.2\text{ kg/s} \end{gathered}\)Hence, the damping constant is b = 9871.2 kg/s
a solid sphere, a solid cylinder, and a hollow cylinder are placed at the top of an inclined plane. if all are made of the same material and are released at the same time, which one will reach the bottom first? group of answer choices the solid cylinder. the sphere. the hollow cylinder.
Answers
The solid sphere will reach the bottom of the inclined plane first. The reason for this is that the sphere has the smallest surface area to volume ratio which means that there is less friction acting on it as it rolls down the incline.
Which moves more quickly, a sphere or a cylinder?Solid sphere moves more quickly than solid cylinder because it has a lower moment of inertia and more kinetic energy during translation. Comparable solid objects move more slowly than hollow ones.
Which reaches the bottom first, the cylinder or the sphere?If a cylinder and a sphere have the same mass and radius, the cylinder will have a greater moment of inertia due to its greater mass at its edges. Because the sphere's moment of inertia is smaller, it will move faster and arrive at the bottom first.
What causes a hollow cylinder to roll more slowly?The process by which potential energy (PE) is transformed into kinetic energy is the cause of the solid cylinder's faster descent than the hollow cylinder. Some of the PE is transformed to rotating kinetic energy (RKE), not simply linear kinetic energy, because the cylinder is rolling (LKE).
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What happens to form the brown spots on a tlc plate when you place the developed tlc plate in an iodine chamber?.
Answers
Iodine sublimates and reacts with the compounds on the produced TLC plate when it is placed in the chamber and covered, producing yellow-brown spots.
Iodine interacts with many different chemical molecules to produce colorful complexes, which causes coloration. About half of the possible chemicals will work with this stain. For every step see attached file.
Because complexation is reversible and the original chemical will eventually remain on the TLC plate when the iodine has evaporated, this procedure is regarded as "semi-destructive." It is potentially feasible to utilize a different visualization method on the TLC plate after the coloring fades, though it's likely the compound may already have evaporated by then.
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Jailah needs a replacement for lithium for a science experiment. She tries silicon, but it does not work. Using what you know about patterns in the periodic table, which advice would you give Jailah?
A. Try a lanthanide series element.
B. Try a non-metal from the halogen group.
C. Try an element in the same group as lithium.
D. Try an element in the same period as lithium.
Answers
Answer:
C. Try an element in the same group as lithium.
Explanation:
Answer:
The answer is C.
Explanation:
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