10- The voltage across the generator of
the circuit of figure 13 is 12V and
the voltmeter V2 indicates 8V:
А
ס
N.
V
L1
L2
B
L
Fig.13
a- What would the voltmeter V3 indicate?
Justify the answer
b- What would the voltmeter Vi indicate?
Justify the answer

Titanium is a non-magnetic metal because of its digital configuration and crystal shape.

In its pure shape, titanium has a hexagonal near-packed (hcp) crystal structure, this means that that its atoms are organized in a specific pattern in the crystal lattice.

This association outcomes inside the absence of unpaired electrons that could create magnetic moments, making it non-magnetic. Moreover, the electron configuration of titanium does not permit for magnetic moments to shape.

Titanium has four valence electrons, which are positioned within the 3-d and 4s orbitals.

The electrons in the 3d orbital are paired, which means that they've opposite spins and cancel out any magnetic second that could be created by means of the electrons inside the 4s orbital.

But, whilst titanium is alloyed with other metals, inclusive of iron or nickel, it may turn out to be magnetic because of the magnetic houses of these metals.

This belongings is utilized in various programs, inclusive of in the manufacturing of plane and medical implants, where the non-magnetic houses of titanium are important to keep away from interference with electromagnetic gadgets.

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The resulting supernova is incredibly bright and can outshine an entire galaxy for a brief period of time. In conclusion, a high-mass star explodes as a Type II supernova when its core collapses due to the inability to support its outer layers. The core's collapse causes an enormous amount of energy to be released, creating a shockwave that results in the explosion of the star.

A high-mass star is a star with a mass of at least three times the sun's mass. They typically live for millions of years, emitting light and heat via the process of nuclear fusion. However, after exhausting all the fuel in their core, high-mass stars will eventually experience a catastrophic event known as a supernova.

Type II supernova, commonly known as core-collapse supernovae, occurs when a high-mass star runs out of fuel and cannot support its outer layers. These stars eventually reach the end of their life cycle and explode in a catastrophic event. This explosion is caused by the collapse of the star's core, which has a gravitational force strong enough to overcome the pressure of the thermonuclear fusion reaction that has kept the star stable for millions of years. During its lifetime, a high-mass star undergoes several nuclear fusion reactions, which transform lighter elements into heavier ones. Eventually, the star's core will become a hot, dense ball of iron that can no longer produce enough heat to resist the pull of gravity. As the core collapses, it releases an enormous amount of energy in the form of neutrinos, which escape the star and carry away some of the core's mass.

The core of the star becomes so dense that it triggers a rebound, sending a shockwave outward, creating an enormous explosion. This explosion ejects most of the star's material into space, leaving behind a dense core known as a neutron star or, in some cases, a black hole.

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Given the total energy in the wire, current and time elapsed, the potential difference is 50 Volts.

The electric power is expressed as P = VI.

Where V is the potential difference, I is the electric current and P is the electric power.

Also, the consumption of energy per unit of time is called power. It is expressed as P = E / t

Given that;

First, we determine the power.

P = E / t

P = 500J / 5s

Power = 100W

Next, we determine the potential difference.

P = V × I

V = P / I

V = 100W / 2.00A

V = 50V

Given the total energy in the wire, current and time elapsed, the potential difference is 50 Volts.

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The Potential difference is 50 Volts.

The potential difference is a measure of the energy given to the charge carriers in a circuit

We know that  the electric power is expressed as P = VI.

V is the potential difference

I is the electric current
P is the electric power.

Also we know that power is expressed as P = E / t

Given

Current( I) = 2.00A ,time t = 5s

Total energy E = 500J

To find the power

P = E / t  = 500J / 5s = 100W

Now , To find the potential difference.

P = V × I (By rearranging it)

V = P / I

V = 100W / 2.00A = 50 V

Therefore , the total energy in the wire, current and time elapsed, the potential difference is 50 V.

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The Doppler shift method of detecting extrasolar planets only gives us the minimum mass of a planet because B) we don't necessarily know the angle the planet's orbit makes with our line of sight.

The Doppler shift method of detecting extrasolar planets only gives us the minimum mass of a planet because we don't necessarily know the angle the planet's orbit makes with our line of sight. This means that we cannot accurately determine the exact velocity of the planet, which affects our ability to accurately calculate its mass. Additionally, we don't necessarily know the density of the planet or the mass of the parent star, which also affects our ability to accurately calculate the planet's mass. However, by measuring the radial velocity of the star, we can still detect the presence of planets and estimate their minimum mass.
This uncertainty means we can only determine the component of the gravitational influence of the planet on the star along our line of sight, which results in a minimum mass estimate.

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Answer:

18

Explanation:

12 - 5 + 8 = 15

12 - 8 = 4

7 - 4 = 3

15 + 3 = 18

Ultravoilent rays is an type of an electromegnetic wave with wavelength 10nm .Ultraviolet wave is used by doctors in order to keep the wounds away from bacteria.

Ultravoilent rays is an type of an electromegnetic wave with wavelength 10nm. Ultravoilent wave is directly comes frim the sun. It is classified into the UV(A) , UV(B),UV(B).

Ultravoilet rays also effects the human eyes that s why sun glasses are used. The experiments here are compared and quantified to the effectiveness of the sunscreens with various strengths.

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Answer:

B. Ultraviolet waves

Explanation:

Answer:

work done is directly proportional to the net force acting on the object.

Explanation:

work done = Force × displacement

Collisions between two balls can change their angular velocities, with possible scenarios including equal angular velocities, a valid equation co^xdg, or the term "myj" not relevant. The equation co^xdg does not describe the relationship between angular velocities after the collision, and the term "myj" has no significance.

When two balls, A and B, collide with each other, their angular velocities can change depending on the specific conditions of the collision. Let's examine the possible scenarios:

(a) Both balls have the same angular velocities after the collision:
In some cases, when the collision is perfectly elastic and the balls have similar masses and moments of inertia, their angular velocities can become equal after the collision. This means that both balls will rotate at the same speed.

(b) The angular velocities of the balls are given by the equation co^xdg:
The equation co^xdg does not represent a valid expression for the angular velocities after the collision. It appears to be a combination of the symbols co^ (angular velocity of ball A) and dg (angular velocity of ball B), but it does not provide any meaningful information about their relationship after the collision.

(c) The term "myj" does not appear to have any relevance to the question or the concept of angular velocities after a collision.

In summary, after the collision of two balls with initial angular velocities co^ and tog, the outcome can vary. It is possible for both balls to have the same angular velocities if the conditions are appropriate. However, the equation co^xdg does not describe the relationship between the angular velocities after the collision, and the term "myj" does not have any significance in this context.

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Explanation:

Initial Velocity (u) = 11 m/sec

Angle of Projectile (theta) = 15.3°

(Ques - 1) How far does he jump?

(Ans - 1) Find Horizontal Range :

\(R = \frac{ {u}^{2} \sin(2 \alpha ) }{g} = \frac{(11)^{2} \sin(30.6°) }{9.8} \)

\(Range = 6.17 \: m\)

(Ques - 2) What maximum height does he reach?

(Ans - 2)

\(H = \frac{ {u}^{2} {sin }^{2} \alpha }{2g} = \frac{(11)^{2} {sin}^{2}15.3° }{19.6} \)

\(Maximum \: Height = 0.41 \: m\)

Answer:

..

Explanation:

Coordinate adjectives are adjectives that describe the same noun equally. They should be separated with commas. In this sentence, both red and round are describing the ball. The correct answer is, "The red, round ball is Adley's favorite toy to play with."

The weak force and the electromagnetic force are two fundamental forces in nature that have distinct characteristics. One notable contrast between them is their range of influence.

The weak force acts within the nucleus of an atom, specifically within protons and neutrons, and has a very short-range, limited to distances on the order of nuclear dimensions.

In contrast, the electromagnetic force has an infinite range, meaning it can act over long distances, reaching out to infinity.

Furthermore, the nature of the forces' interactions differs. The weak force is both attractive and repulsive, meaning it can either attract or repel particles depending on the circumstances.

On the other hand, the electromagnetic force is solely attractive, leading to the attraction of charged particles and the binding of electrons to atomic nuclei.

In summary, the weak force acts within protons and neutrons, with a limited range, and exhibits both attractive and repulsive behavior, while the electromagnetic force has an infinite range, acts between charged particles, and is exclusively attractive.

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Answer:

A = 300 \(cm^{2}\)

Explanation:

Un bloque tiene cuatro caras, la cara que apoya en el suelo es siempre la base del bloque. Siendo asi, la pregunta nos dice que esa cara tiene medidas de 30cm x 10cm. Podemos usar estas medidas para calcular el area de esta cara. Por que es un bloque y las medidas son differentes, la cara es un rectangulo, y la formula del area (A) de un rectangulo es multiplicar el ancho por el largo, que seria lo siguiente

A = 30 * 10

A = 300 \(cm^{2}\)

The answer to the question "Does bulb A get brighter, dimmer, or stay the same brightness?" is that bulb A gets brighter.

Based on the information given, if we assume that both statements are referring to the same situation, we can conclude that bulb A gets brighter. Since the second statement explicitly states that "light bulb A gets brighter," it indicates a change in brightness.

Without any contradictory information, we can infer that the brightness of bulb A increases over time.

Therefore, the answer to the question "Does bulb A get brighter, dimmer, or stay the same brightness?" is that bulb A gets brighter.

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The force exerted on the 0.25-kg baseball is 631 N.

To find the force exerted on the baseball, we can use the impulse-momentum theorem, which states that the impulse (change in momentum) of an object is equal to the force applied to it multiplied by the time over which the force is applied.

In this case, we can find the change in momentum of the baseball by subtracting its initial momentum from its final momentum:

Δp = p_f - p_i
Δp = (0.25 kg)(56.0 m/s) - (0.25 kg)(45.0 m/s)
Δp = 3.5 kg m/s

We also know the ball-on-bat contact time, t, is 0.040 s.

Now we can rearrange the impulse-momentum equation to solve for the force:

F = Δp/t
F = (3.5 kg m/s) / (0.040 s)
F = 87.5 N

However, this force is the force exerted by the baseball on the bat, not the force exerted on the baseball itself.

We can assume that the force exerted by the bat on the baseball is equal in magnitude but opposite in direction to the force exerted by the baseball on the bat. Therefore, the force exerted on the baseball is:

F = -87.5 N (negative because it is in the opposite direction)
F = -1 * (-87.5 N) (multiply by -1 to get a positive value)
F = 87.5 N

Note that we can also use the formula for average force to solve this problem:

F = mΔv / t
F = (0.25 kg)(56.0 m/s - 45.0 m/s) / (0.040 s)
F = 631 N

This gives us the same final answer as before, but it is a more direct way to find the force.

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The minimum amount of following time needed to create an open front zone is 3 seconds.

An open front zone is a space in front of your vehicle that allows you to see and react to potential hazards. To create an open front zone, you need to have a minimum of 3 seconds of following time between you and the vehicle in front of you.

This means that you should be able to count at least 3 seconds from the time the vehicle in front of you passes a fixed object until your vehicle passes the same object.

Having a 3-second following distance gives you enough time to react to sudden changes in traffic and avoid collisions. It also helps you maintain a safe speed and avoid tailgating, which is a common cause of accidents. In adverse weather conditions, such as rain or snow, it is recommended to increase the following distance to at least 4 seconds to allow for the reduced visibility and longer stopping distance.

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A. covalent. The covalent compound must possess a covalent link in which the two atoms involved have substantial disparities in their electronegativity for a polar covalent bond to exist.

The most electronegative element is fluorine. Therefore, C and F exhibit the largest variation in electronegativity . The most polar bond is the C-F one as a result.

The electron pair is shared evenly by the two linked atoms in a non-polar covalent connection. H2 is a kind of hydrogen gas. Since the two hydrogen atoms are the same, their bond is non-polar.

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Answer:

Bears are consumers

Explanation:

The above statement shows that bears are consumers. A consumer is an individual or a party who plans to order or use acquired goods,

A consumer is a person or a group who plans to order or utilize acquired goods, products, or services for personal, social, family, domestic, or similar purposes.

Any individual or group who is the final user of a product or service is referred to as a consumer.

A business that purchases a printer for internal usage. The firm that bought the printer is the client, and the employees that use it are the customers. The printer will not be resold by the firm.

Hence the statement shows that bears are consumers.

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a. The angular speed of the rotating nylon line is 314.16 radians per minute.

b. The linear speed of a point on the tip of the line is approximately 2617 inches per minute.

The angular speed of the rotating nylon line can be determined by converting the rotational speed from revolutions per minute (rpm) to radians per minute.

Since one revolution is equal to 2π radians, the angular speed is calculated as 3000 rpm multiplied by 2π, resulting in approximately 314.16 radians per minute.

To find the linear speed of a point on the tip of the line, we need to multiply the angular speed by the radius of the circular path. Given that the line is 5 inches long, the radius is half of that, or 2.5 inches.

The linear speed can be obtained by multiplying the angular speed of 314.16 radians per minute by the radius of 2.5 inches, resulting in approximately 785.4 inches per minute.

Rounding to the nearest inch per minute, the linear speed of a point on the tip of the line is approximately 2617 inches per minute.

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The force required to start the block in motion is equal to 39.2 Newton.

Given the following data:

To determine the force required to start the block in motion:

Note: The force that is required to start the block in motion must be greater than or equal to the force of static friction.

Mathematically, the force of static friction is given by the formula;

\(Fs = uFn = umg\)

Where;

Substituting the given parameters into the formula, we have;

\(F_s = 0.4 \times 10 \times 9.8\\\\F_s = 4 \times 9.8\\\\F_s = 39.2\;Newton\)

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This is not a gamma radiation because there is a change in the atomic number of the daughter nucleus. It is rather a beta decay.

We have to note that when we talk about a decay we are talking about the manner that we can be able to break up the atom of a radioactive substance so that we can be able to produce a new substance.

We can see now that what we have here is the loss of a beta ray or an electron from the specie that is shown. This is evidenced by the change in the atomic number of the daughters nucleus.

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The rock sitting on the cliff that is 25 m high has the gratest gravitational potential energy.

Potential energy is defined as the energy of an object by virtue of it's location. Mathematically, it is written as:

PE = mgh

Where

To determine the rock with the grater potential energy, we shall determine the potential energy of both rock assuming they have the same mass. Details below:

For rock sitting at 25 m high:

PE = mgh

PE = 10 × 9.8 × 25

PE = 2450 J

For rock sitting at 12 m high:

PE = mgh

PE = 10 × 9.8 × 12

PE = 1176 J

From the above calculation, we have:

Thus, we can conclude that the rock sitting at 25 m high, has the gratest potential energy.

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The rubber ball has both the greatest kinetic energy and the least potential energy at position 3.

According to the conservation of energy, the total mechanical energy of a system remains constant. There are two forms of energy - potential energy and kinetic energy.Potential energy (PE) is the energy that an object possesses due to its position or shape. It has the potential to do work when it moves.Kinetic energy (KE) is the energy an object possesses when it moves. It's given by the equation KE = 1/2mv².In the image shown, when the ball is at Position 1, it has potential energy and no kinetic energy. The ball has zero speed at this position.

As the ball falls to the ground, its potential energy is converted to kinetic energy. At position 3, the ball has the most kinetic energy and the least potential energy. At this point, the ball is moving at the maximum velocity.When the ball reaches Position 4, it bounces off the ground and loses some of its kinetic energy due to the collision. It bounces back up and begins to gain potential energy again. At position 2, the ball has the least kinetic energy and the most potential energy. The ball stops momentarily at this position before falling again.Hence, the rubber ball has the greatest kinetic energy and the least potential energy at position 3.

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Answer:

Power is associated by many people with electricity. Knowing that power is the rate of energy use or energy conversion, what is the expression for electric power? Power transmission lines might come to mind. We also think of lightbulbs in terms of their power ratings in watts. Let us compare a 25-W bulb with a 60-W bulb. (See Figure 1(a).) Since both operate on the same voltage, the 60-W bulb must draw more current to have a greater power rating. Thus the 60-W bulb’s resistance must be lower than that of a 25-W bulb. If we increase voltage, we also increase power. For example, when a 25-W bulb that is designed to operate on 120 V is connected to 240 V, it briefly glows very brightly and then burns out. Precisely how are voltage, current, and resistance related to electric power?

Explanation:

The specific heat of Al is greater than that of water. Therefore, adding Al wire will increase the temperature of water in the calorimeter. While adding the Pb pellets will decrease the temperature.

Calorimetry is an analytical technique used to determine the heat energy absorbed or released by a system. The calorimetric equation connecting the heat change q with mass of the substance m, specific heat capacity c and the temperature difference ΔT is:

q = m c ΔT

The specific heat of a substance is the heat energy required to increase the temperature by one degree Celsius per one gram. Higher the specific heat, higher be the rate of cooling or heating.

The heat gained by water from steel will be greater than that of Al because specific heat of steel is greater. Lead has very small specific heat and the temperature change will be smaller.

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Answer:

aluminum wire = 2.6c

steel wire = 1.5c

lead pellets = 0.8c

Explanation:

Heya!!

For calculate frequency, lets applicate formula:

                                                       \(\boxed{f=v/\lambda}\)

                                                   Δ   Being   Δ

                                               f = Frequency = ?

                                           v = Velocity = 144 m/s

                                          \(\lambda\) = Wavelenght = 0,5 m

⇒ Let's replace according the formula:

\(\boxed{f = 144\ m/s / 0,5\ m }\)

⇒ Resolving

\(\boxed{f = 288\ Hz}\)

Result:

The frequency of that wave is 288 Hertz

Good Luck!!

Answer:

sadasdsadasd

Explanation:

Answer: the weight of the boat is approximately 267.975 N.

Explanation:

The weight of the boat can be calculated as follows:

Find the buoyant force acting on the boat:

The buoyant force is equal to the weight of the water displaced by the boat. Since half of the boat is submerged under water, the buoyant force is equal to the weight of the volume of water equal to half the volume of the boat.

The density of water is approximately 1000 kg/m³. The volume of the boat is equal to the volume of the water displaced by the boat. Therefore, the volume of water displaced by the boat is:

(1/2) x (volume of the boat)

The weight of this volume of water is:

(weight of water) = (density of water) x (volume of water) x (acceleration due to gravity)

(weight of water) = 1000 kg/m³ x (1/2) x (volume of the boat) x 9.81 m/s²

Find the weight of the boat:

The weight of the boat is equal to its mass times the acceleration due to gravity:

(weight of the boat) = (mass of the boat) x (acceleration due to gravity)

(weight of the boat) = 55 kg x 9.81 m/s²

Now, we can calculate the weight of the boat as:

(weight of the boat) = (weight of water displaced by the boat)

(weight of the boat) = 1000 kg/m³ x (1/2) x (volume of the boat) x 9.81 m/s²

55 kg x 9.81 m/s² = 1000 kg/m³ x (1/2) x (volume of the boat) x 9.81 m/s²

(volume of the boat) = 55 kg / (1000 kg/m³ x (1/2))

(volume of the boat) = 0.055 m³

(weight of the boat) = (weight of water displaced by the boat)

(weight of the boat) = 1000 kg/m³ x (1/2) x 0.055 m³ x 9.81 m/s²

(weight of the boat) = 267.975 N

Therefore, the weight of the boat is approximately 267.975 N.