1/10^-2 A. 1/100 B. 1/10 C. 100 D. 1,000,000

Answer:

\( \boxed{ \bold{ \huge{ \boxed{ \sf{ \frac{1}{12} }}}}}\)

Step-by-step explanation:

\( \sf{ \frac{5}{12} \times \frac{4}{20}}\)

To multiply one fraction by another, multiply the numerators for the numerator , and multiply the denominators for its denominator and reduce the fraction obtained after multiplication into lowest term.

\( \longrightarrow{ \sf{ \frac{5 \times 4}{12 \times 20}}} \)

\( \longrightarrow{ \sf{ \frac{20}{240}}} \)

\( \longrightarrow{ \sf{ \frac{1}{12} }}\)

Hope I helped!

Best regards! :D

Answer:

x=3

Step-by-step explanation:

please mark me as brainliest

Answer:

x = 2

Step-by-step explanation:

first we solve inside brackets (x-5) = 20 so it be -12 = 4x -20

then we add 20 to both sides so it be -12 + 20 = 4x -20 +20

then we simplify so it be 8 = 4x

then we divide both sides with 4 so it be 8/4 = 4x/4

then we simplify so it be x=2

SO THE ANSWER IS x=2 OR 2

hope that helps!! pls brainliey if u dont mind! :))

The answer would be 19/15 or in other words 1  4/15

Answer:

exact form: 19/15

decimal form: 1.26

mixed number form: 1 4/15

The hamburger is one of the most common fast food items in the United States. A food concessionaire sold an average of 8000 hamburgers at a city sports area on a game night when hamburgers cost \($3.40\)each.

The hamburger sales fell to an average of 6000 when the price was raised to \($13.30.\) Find the price of a hamburger that will maximize the righty hamburger (a) and (b) revenue. If the concessionaire had fixed costs of\($2000\) per night and variable costs of \($1.40\)per hamburger, what would be the hamburger price that would maximize the righty hamburger revenue

Simplifying the above equation, we get\(:Q(X - 1.4) = 2000\) Multiplying and expanding the equation, we get\(:QX - 1.4Q = 2000QX = 2000 + 1.4Q\) Substituting the demand function and the optimal quantity, we get:\(X = 2000/Q + 1.4

Substituting Q = 3846.15, we get:X = 1.94\) Therefore, the price of the hamburger that will maximize the righty hamburger revenue is\($1.94 + $1.40 = $3.34.\)

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Remember: a^2 + b^2 = c^2

1

64 + 49 = 113

√113 = \(\sqrt{113}\)

2

100 - 25 = 75

square root of 75 = 5 \(\sqrt{3}\)

Answer: 4y

Step-by-step explanation:

\(3x^{2} + 4y - 2x^{2} -1x^{2}\)  To  

3x^2 - 2x^2 -1x^2 = 0  

0 +4y = 4y  

Answer:

It is graph C

Step-by-step explanation:

Answer: Graph C

Step-by-step explanation: On Edge

Answer:

x = 5

y = 3

Step-by-step explanation:

x + 4y = 17

2x + 5y = 25

We multiply the first equation by -2

-2x - 8y = -34

2x + 5y = 25

-3y = -9

y = 3

Now we put 3 in for y and solve for x

x + 4(3) = 17

x + 12 = 17

x = 5

Let's Check the answer

5 + 4(3) = 17

5 + 12 = 17

17 = 17

So, x = 17 and y = 3 is the correct answer.

In a case whereby emf of a cell is balanced by a length of 120cm of potentiometer wire and when the cell is shunted by a resistance of 10 ohms,the balancing length is reduced by 20cm the internal resistance of the cell is 2Ω.

Frm the question we were given;

R = 10 Ω

l(1) = 120 cm

I(2) = (120 – 20) = 100 cm

The formula for the internal resistance can be written as ;

R=r(l1 - l2)/l2

=10(120 - 100)/100

=2Ω

Therefore, the internal resistance of the cell is 2Ω

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Answer:

Step-by-step explanation:

Least to greatest :

-3/5,-2/3,0,0.7

The statement "The mean decreases as the degrees of freedom increase" is not true about chi-square distributions.

In fact, the mean of a chi-square distribution is equal to its degrees of freedom. It does not decrease as the degrees of freedom increase.

The mean remains constant regardless of the degrees of freedom. This is an important characteristic of chi-square distributions.

Regarding the other statements:

In summary, the statement that is not true about chi-square distributions is that the mean decreases as the degrees of freedom increase.

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Given:

Then:

It is true that the eigenvectors of the covariance matrix are equal to the principal components. Concretely, the first principal component (i.e. the largest eigenvector and associated largest eigenvalue) gives you the direction of the maximum variability in your data

The covariance matrix's eigenvectors are identical to its major components, which is a well-known fact. In more concrete terms, the direction of the most variability in your data is provided by the first principal component, which is represented by the largest eigenvector and related largest eigenvalue. After that, each primary component provides you decreasingly variable output. The fact that each primary component is orthogonal to the others is also important to note.

The above picture was taken from the Principal Component Analysis article on Wikipedia, which I previously referred to. This is a scatter plot of samples having a bivariate Gaussian distribution with a center at (1,3), a standard deviation of 3 roughly in the (0.878, 0.478) direction, and a standard deviation of 1 roughly in the orthogonal direction. The first principal component is the one with a standard deviation of 3, and the second is the orthogonal component. The shown vectors are the eigenvectors of the covariance matrix scaled by the relevant eigenvalue's square root and moved to place their tails at the mean.

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Answer:

(f+g)(x) > 3 for all values of x

Answer: 11.75

Step-by-step explanation:

47 / 4= 11.75

Answer: each ticket cost $11.75

Step-by-step explanation:

47.00/4=11.75

Hope this helps!

The distribution in residence is different today at a 0.05 level of significance can be conclude because the p-value = 0.0172

from the data given we can make the table below:

Categories       Observed(fo)        Expected (fe)        (fo-fe)²/fe

NW Oregon        3109           4357*0.727=3167.539       1.082

SW Oregon        902             4357*0.207=901.899           0

Central Oregon    244          4357*0.048=209.136         5.812

Eastern Oregon    102           4357*0.028=121.996         3.277

Sum =                    4357        4357                                   10.171

first,  null and alternative hypotheses need to be tested:

H0​:p1​=0.727,p2​=0.207,p3​=0.048,p4​=0.028

Ha​: The population proportion partially deviates from the value given by the null hypothesis

This corresponds to a Chi-Square test for Goodness of Fit.

then, Based on the data provided, the significance level is α=0.05, the number of degrees of freedom is df=4−1=3, so then the rejection region for this test is R={\(X^{2}X^{2}\)>7.815}.

after that we should do test statistic

The Chi-Squared statistic is calculated as follows:

∑\(^{n} _{i=1}\)\(\frac{(Oi-Ei)}{y} \\\) =   1.082+0+5.812+10.171 +3.277= 10.171

the we can make a decision about the null hypothesis by

\(X^{2} = 10.71 > X^{2} _{c} = 7.815\)

it is then concluded that the null hypothesis is rejected.

Therefore, there is enough evidence to claim that some of the population proportions differ from those stated in the null hypothesis, at the α=0.05 significance level.

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Answer: $1.54

Step-by-step explanation:

One scoop of ice cream is $1.54. Kinda cheap for Ice cream. Can I get two scoops of vanilla ice cream please? With sprinkles!

Two scoops of ice cream is $3.08. If you divide that, you get $1.54.

Hope this helps! :D

- Anna

Answer:

1. R

2.I

3. I

4.R

Step-by-step explanation:

Answer:

-120 is a negative and 400 is a positive

Step-by-step explanation:

also there is a 520 difference

Answer:WAIT HE IS TELLING THE TIME

Step-by-step explanation:

Answer:

price of adult ticket=$8

price of child ticket=$14

Step-by-step explanation:

let number of adult tickets=x

child tickets=y

3x+1y=38

3x+2y=52

subtract first from second

y=52-38=14

from first

3x+14=38

3x=38-14=24

x=24/3=8

The area of the regular polygons with 12 sides(dodecagon) and 5 sides (pentagon) are 389.06 in² and 19.87 in² respectively.

Area of regular polygon = 1/2 × apothem × perimeter

perimeter = (s)side length of octagon × (n)number of side.

apothem = s/[2tan(180/n)].

11 = s/[2tan(180/12)]

s = 11 × 2tan15

s = 5.8949

perimeter = 5.8949 × 12 = 70.7388

Area of dodecagon = 1/2 × 11 × 70.7388

Area of dodecagon = 389.0634 in²

Area of pentagon = 1/2 × 5.23 × 7.6

Area of pentagon = 19.874 in²

Therefore, the area of the regular polygons with 12 sides(dodecagon) and 5 sides (pentagon) are 389.06 in² and 19.87 in² respectively.

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Storekeepers in electronics companies deal with various types of materials. Five classes of materials include electronic components, raw materials, finished products, packaging materials, and maintenance supplies.

Electronic Components: Storekeepers are responsible for managing a wide range of electronic components such as resistors, capacitors, integrated circuits, connectors, and other discrete components. These components are essential for assembling electronic devices and are typically stored in organized bins or cabinets for easy access.

Raw Materials: Electronics companies require various raw materials for manufacturing processes. Storekeepers handle materials like metals, plastics, circuit boards, cables, and other materials needed for production. These materials are usually stored in designated areas or warehouses and are monitored for inventory levels.

Finished Products: Storekeepers are also responsible for storing and managing finished products. This includes fully assembled electronic devices such as smartphones, computers, televisions, and other consumer electronics. They ensure proper storage, tracking, and distribution of these products to customers or other departments within the company.

Packaging Materials: Packaging plays a crucial role in protecting and shipping electronic products. Storekeepers handle packaging materials such as boxes, bubble wrap, foam inserts, tapes, and labels. They ensure an adequate supply of packaging materials and manage inventory to meet packaging requirements.

Maintenance Supplies: Electronics companies often require maintenance and repair supplies for their equipment and facilities. Storekeepers handle items like tools, lubricants, cleaning agents, safety equipment, and spare parts. These supplies are necessary to support ongoing maintenance activities and ensure the smooth operation of machinery and infrastructure.

Overall, storekeepers in electronics companies deal with a diverse range of materials, including electronic components, raw materials, finished products, packaging materials, and maintenance supplies. Effective management of these materials is crucial to ensure smooth operations, timely production, and customer satisfaction.

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The solution to the linear system is:

x = 4

y = -7

z = -44/29

To solve this linear system using row reduction, we need to write the augmented matrix:

[ 1   1   0   | 2 ]

[-2   2   -5 | -28 ]

[-5  -6  -6  | 7  ]

[ 3   5  -2  | 33 ]

Our goal is to use elementary row operations to transform this matrix into a reduced row echelon form, which will allow us to read off the solution directly.

First, we can add twice the first row to the second row:

[ 1    1    0   | 2 ]

[ 0    4   -5   | -24 ]

[-5   -6   -6   | 7  ]

[ 3    5   -2   | 33 ]

Next, we can add five times the first row to the third row:

[ 1    1   0   | 2 ]

[ 0    4  -5   | -24 ]

[ 0   -1  -6   | 17 ]

[ 3    5  -2   | 33 ]

Now, we can add three times the first row to the fourth row:

[ 1    1   0   | 2 ]

[ 0    4  -5   | -24 ]

[ 0   -1  -6   | 17 ]

[ 0    8  -2   | 39 ]

We can divide the second row by 4:

[ 1    1    0   | 2 ]

[ 0    1   -5/4| -6  ]

[ 0   -1   -6   | 17 ]

[ 0    8   -2   | 39 ]

Next, we can add the second row to the third row:

[ 1    1   0   | 2 ]

[ 0    1  -5/4 | -6 ]

[ 0    0  -29/4| 11 ]

[ 0    8   -2  | 39 ]

We can divide the third row by -29/4:

[ 1    1     0   | 2 ]

[ 0    1  -5/4   | -6 ]

[ 0    0     1   | -44/29 ]

[ 0    8    -2   | 39 ]

Now, we can subtract eight times the third row from the fourth row:

[ 1    1     0    | 2         ]

[ 0    1  -5/4    | -6        ]

[ 0    0     1    | -44/29   ]

[ 0    0    6/29  | 351/29   ]

Finally, we can subtract the third row from the second row and then subtract the first row from the second row:

[ 1    0   0    | 4       ]

[ 0    1   0    | -7      ]

[ 0    0   1    | -44/29 ]

[ 0    0   6/29 | 351/29 ]

Therefore, the solution to the linear system is:

x = 4

y = -7

z = -44/29

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Answer:

50kmph

Step-by-step explanation:

average speed = distance / time

as = 150 kilometers / 3 hour

as = 50 kmph

some times we have one of these information in other scales. that we have to change them to main scales.

for example:

if information that given to you is meter/hour you have to due to what is needed in question, change meters to kilometers or hour to seconds

the main format is:

meter per seconds

kilometers per hour

.

.

.

Answer:

divide d by 2 r should be 5

There are 27 males and 14 females in the Spanish class.

There are 41 understudies in a Spanish class and the number of females is 13 not exactly the number of males. How about we call the number of males x? The number of females can then be communicated as x-13.

To find the number of males and females in the class, we can set up a situation to address the all-out number of understudies in the class which is 41.

The condition would be x + (x-13) = 41.

Settling for x, we view that as x = 27, which addresses the number of males in the class.

The number of females can then be determined as x-13 = 27-13 = 14.

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The question is -

A Spanish class has a total of 41 students. The number of females is 13 less than the number of males. How many males and how many females are in the class?