2. A bar magnet is divided in two pieces . Which of the following statements is true about the force between the broken pieces if they face each other with a small separation ? A. There is an electric repulsive force between the broken pieces B. There is an electric attractive force between the broken pieces C. There is a magnetic repulsive force between the broken pieces D. There is a magnetic attractive force between the broken pieces .

Answer:

Frequency of wave = 2.16 Hz (Approx)

Explanation:

Given:

Speed of tsunami = 970 km/h

Wavelength = 450 km

Find:

Frequency of wave

Computation:

Frequency = Speed / Wavelength

Frequency of wave = Speed of tsunami / Wavelength

Frequency of wave = 970 / 450

Frequency of wave = 2.16 Hz (Approx)

A large stony/icy object would likely cause more damage if it struck near an urban area than a small metallic one.

This is because the kinetic energy of an object is proportional to its mass and velocity squared, so a larger object will have more kinetic energy than a smaller one, all else being equal. Additionally, stony/icy objects tend to be denser than metallic objects, meaning they have more mass per unit volume, which also contributes to their higher kinetic energy.

When a large object such as a stony or icy meteoroid strikes the Earth, it can generate a powerful shockwave that can cause widespread damage to surrounding areas. The shockwave can lead to ground shaking, structural damage, and even cause fires due to the high heat generated upon impact.

In contrast, a small metallic object would have less mass and therefore less kinetic energy, and may not generate enough force to cause significant damage. However, it is important to note that the specific size and composition of the object, as well as the location and angle of impact, will all play a role in determining the amount of damage caused.

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Answer:

where is the question ??/dude

Answer:

Force = 3 Newton

Explanation:

Given the following data;

Mass = 200 g to kilograms = 200/1000 = 0.2 kg

Acceleration = 15 m/s²

To find the force;

Force = mass * acceleration

Force = 0.2 * 15

Force = 3 Newton

The maximum possible efficiency of the engine is 54.1%. This means that the engine is able to convert 54.1% of the heat energy it absorbs into work, while the rest is expelled to the low temperature source. It is important to note that no heat engine can have an efficiency greater than 100%, as this would violate the laws of thermodynamics.

To find the maximum possible efficiency of the engine, we need to use the formula for efficiency, which is:
Efficiency = (1 - (T_Low/T_High)) x 100%
where T_Low is the temperature of the low temperature source in Kelvin and T_High is the temperature of the high temperature source in Kelvin.
First, we need to convert the temperatures from Celsius to Kelvin:
T_High = 365 + 273 = 638 K
T_Low = 20 + 273 = 293 K
Now we can plug in the values into the formula:
Efficiency = (1 - (293/638)) x 100%
Efficiency = 54.1%
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The maximum possible efficiency of a heat engine is given by the formula. Therefore, the correct answer is: 94.5%.

efficiency = (1 - Tlow/Thigh)
where Tlow is the temperature of the low temperature source and Thigh is the temperature of the high temperature source.
In this case, Tlow = 20.0 OC and Thigh = 365 OC.
So,
efficiency = (1 - 20.0/365)
efficiency = 0.945 or 94.5%
Therefore, the correct answer is: 94.5%.

To find the maximum possible efficiency of a heat engine that absorbs 350 J of heat from a 365°C high-temperature source and expels 225 J of heat to a 20.0°C low-temperature source per cycle, you can use the formula for the Carnot efficiency, which represents the highest possible efficiency for a heat engine operating between two temperature reservoirs.
Carnot efficiency = 1 - (T_low / T_high)
First, convert the temperatures from Celsius to Kelvin:
T_high = 365°C + 273.15 = 638.15 K
T_low = 20°C + 273.15 = 293.15 K
Now, calculate the Carnot efficiency:
Carnot efficiency = 1 - (293.15 K / 638.15 K) ≈ 0.541 or 54.1%
So, the maximum possible efficiency of the heat engine is 54.1%.

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Voltage amplifiers use a voltage input signal and a current output signal. This statement is false.

A voltage amplifier uses a voltage input and a voltage output.

In an electric circuit, the job of a voltage amplifier is to amplify the high input voltage as compared to the low input voltage.

In general, transistor function as voltage amplifiers in a circuit and are used to increase the power, voltage, and current of a signal.

Generally, these amplifiers are used in audio devices and equipment, radio and television broadcasting, wireless communications, and so on.

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The work needed if a force of 3N is used to move a table 25 metres is 75Nm (joules).

Work is a measure of energy expended in moving an object. This means that no work is done if the object does not move.

Force is a physical quantity that denotes the ability to push, pull, twist or accelerate a body and which has a direction and is measured in Newtons.

Work done on an object can be calculated by multiplying the force applied to move the object by the distance the object moves as follows:

Work done = Force (N) × distance (m)

According to this question, a force of 3 Newtons is used to move a table over a distance of 25 meters. The work done on the table can be calculated as follows;

W = 3N × 25metres

W = 75Nm

Therefore, 75Nm is the work done on the table.

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Answer:

To calculate the magnitude of a vector, just find the square root of the sum of components squared.

Explanation:

so square 2.6 and add it to the square of 6.8 and then the square of five and then find the square root of that answer

The waves with a frequency f = 10.0 kHz lie in the radio part of the electromagnetic spectrum.

The electromagnetic spectrum is the range of all types of electromagnetic radiation. It includes radio waves, microwaves, infrared radiation, visible light, ultraviolet radiation, X-rays, and gamma rays. The position of a wave on the spectrum is determined by its frequency and wavelength. The waves with a frequency f = 10.0 kHz have a wavelength of approximately 30,000 meters, which falls within the radio part of the spectrum.

Radio waves have the longest wavelengths and the lowest frequencies in the electromagnetic spectrum. They are used for broadcasting and communications, such as radio and TV signals. Therefore, the waves with a frequency f = 10.0 kHz belong to the radio part of the electromagnetic spectrum.

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Answer:

a) The period of the satellite is approximately 5,425.305 seconds (1.507 hours)

b) The orbital velocity of the satellite is approximately 7,725.8565 m/s

Explanation:

The given parameters are;

The mass of the satellite, m = 1,000 kg

The altitude at which the satellite is orbiting, h = 300 km

a) The period of the satellite is given as follows;

\(T = 2 \times \pi \times \sqrt{\dfrac{(R + h)^3}{g \times R^2} }\)

Where;

R = The radius of the Earth = 6.371 × 10⁶ m

g = The acceleration due to gravity = 9.81 m/s²

h = The altitude of the orbit of the satellite = 300 km = 300,000 m

By substitution, we have;

\(T = 2 \times \pi \times \sqrt{\dfrac{((6.371 + 0.3)\times 10^6)^3}{9.81 \times (6.371 \times 10^6)^2} } \approx 5,425.305\)

T ≈ 5,425.305 seconds ≈ 1.507 hours

b) The orbital velocity of the satellite is given as follows;

\(v_0 = \sqrt{\dfrac{G \times M_{central}}{R + h} } = \sqrt{\dfrac{g \times R^2}{R + h} }\)

Where;

v₀ = The orbital velocity of the satellite

Which by substitution gives;

\(v_0 = \sqrt{\dfrac{9.81 \times (6.371 \times 10^6)^2}{(6.371 + 0.3) \times 10^6} } = 7,725.8565\)

The orbital velocity, v₀ = 7,725.8565 m/s.

The electric field due to this charge distribution can be found by applying Gauss' law. The electric field at any point in space is the net sum of all the electric fields due to the individual charges.

Gauss' law states that the electric flux through any closed surface is equal to the charge enclosed by the surface divided by the permittivity of free space.

To calculate the electric field due to the charge distribution, the first step is to divide the quarter-circle into small segments. Each segment will have a charge q, and will be of width dx. The total charge in the quarter-circle is then given by the integral of q multiplied by dx from 0 to 2πa.

The electric field at any point P in the first quadrant is then given by the integral of q/4πε0 r2 multiplied by dx from 0 to 2πa, where r is the distance from the point P to the center of the quarter-circle. This gives the electric field at P to be:

E = (1/4πε0)∫ 0 to 2πa q/r2 dx

The electric field due to the charge distribution is therefore a function of the distance from the point P to the center of the quarter-circle, and is inversely proportional to the square of this distance.

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The correct statement is "I only." One of the pre-loss objectives of risk managers is to meet any legal requirements the company may face.

The use of fire-resistive materials when constructing a building is an example of risk control. This is because risk control involves taking proactive steps to reduce the likelihood or severity of loss when an incident occurs. Fire-resistive materials are designed to withstand fire, and they are meant to slow down or contain the spread of fire in a building, thus reducing the risk of loss or damage.

In risk management, risk control is one of the four basic methods used to handle or mitigate risks. The other methods include risk transfer, risk avoidance, and risk retention. Risk transfer involves shifting the risk of loss to another party, such as through insurance or contract agreements. Risk avoidance involves eliminating the activity that could lead to loss or harm, while risk retention involves accepting the risk and dealing with any losses that may occur. As for the second question, the correct statement is "I only."

One of the pre-loss objectives of risk managers is to identify, assess, and evaluate potential risks that could negatively affect an organization. They also work to develop strategies to manage these risks and to ensure that the company is meeting any legal or regulatory requirements. On the other hand, one of the post-loss objectives of risk managers is to minimize the impact of losses that occur. They work to evaluate the effectiveness of the company's risk management strategies and to ensure that the company recovers from the loss as quickly as possible. Maximizing the risk manager's wealth is not a post-loss objective of risk managers.

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Answer:

Gravity is an ever present force, and therefore acceleration is guaranteed to happen at every single one of those points (and in fact, everywhere in the universe).

On top of that, friction will be present in all four spots (friction with the rails, with the air, with the axles, etc.), and friction is a perfectly acceptable force that will cause acceleration, slowing the roller coaster down.

So the correct answer is every single point, regardless of what answer the teacher expects.

The object will be moving faster if the acceleration and velocity are pointing in the same direction. The object will also slow down if the acceleration is pointing in the opposite direction as the velocity.

When an object's speed, direction of motion, or both change, it accelerates. Even while it may appear to be virtually immediate in some circumstances, such as when a golf ball is struck by a club or during car collisions, changes in an object's speed are always continuous.

Since gravity is a constant force, acceleration will unavoidably occur at each of those locations and throughout the whole universe.

Therefore, In addition, there will be friction at all four locations—friction with the axles, the air, the rails, etc.—and friction is a completely normal force that will accelerate the roller coaster, slowing it down.

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Answer:25

Explanation:

Formula(77°F − 32) × 5/9 = 25°C

Answer: The answer is C. 298 K

Explanation:

Answer: Heyo Kenji Here! Here's your answer- A planet is most likely to have tectonic activity.

Explanation: Hope this helps!

Have a nice day!

- Kenji ^^

To find the charge on the sphere, we need to use the formula q = CkV, where q is the charge, C is the capacitance of the sphere, k is the Coulomb constant, and V is the potential at the surface of the sphere. We can assume that the sphere is uniformly charged and spherically symmetric. The capacitance of a sphere is given by the formula C = 4πεr, where ε is the permittivity of free space and r is the radius of the sphere.

Substituting the given values, we get:
C = 4πεr = 4π(8.85 × 10^-12 F/m)(0.17 m) = 1.50 × 10^-10 F
Now, using the formula q = CkV and substituting the given value of V, we get:
q = (1.50 × 10^-10 F)(9 × 10^9 Nm^2/C^2)(4.0 V) = 5.4 × 10^-8 C
Therefore, the charge on the sphere is 5.4 × 10^-8 C, rounded to two significant figures.

In summary, to find the charge on the sphere, we used the formula q = CkV and assumed the sphere is uniformly charged and spherically symmetric. We found the capacitance of the sphere using the formula C = 4πεr and then substituted the given values to get the charge on the sphere. The answer is 5.4 × 10^-8 C, rounded to two significant figures.

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Based on the explanation deduced, we can conclude that the work vector points in the negative direction. Hence, the first option aligns with the a

In the given problem, the work done by a force on an object is calculated to be -16 Joules. This means that the object moved in the negative direction, and the work vector points in the negative direction. It doesn't necessarily imply that the force vector also pointed in the negative direction.

The object's displacement and the force vector not pointing in the same direction doesn't also imply that the work done will be negative. The formula for work is given as:

Work = Force x Distance x cos θ, where,θ is the angle between the force vector and displacement vector of the object. If the force and displacement vectors are in the opposite direction, then the angle between them will be 180°.

In that case, cos 180° = -1, which makes the work done negative. This is why we have a negative work done value in the given problem. 

Therefore, we can conclude that the work vector points in the negative direction, but we cannot determine the direction of the force vector without knowing the angle between the force vector and displacement vector.

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Answer:

C.

Explanation:

""""""" Twice,Half """"""

A big wheel with twice the circumference of a small wheel will rotate with the force and the speed of the small wheel.

C) twice, half

A big wheel with twice the circumference of a small wheel will rotate with twice the force and half the speed of the small wheel.

It is the round circle found on the outside angle of the machine.

It is the adjusted barrel or rod-like portion put on the interior of the machine that's connected to the wheel and makes a difference to advance development.

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For the wood crate to move, the force applied (minimum horizontal force) must be greater than the static friction between the wood crate and the wood floor

Given that Jim wishes to push a 100. N wood crate across a wood floor.

The weight of the wood = 100N

The weight will produce a normal reaction N which is equal in magnitude to the magnitude of the weight. That is,

N = mg = 100N

For the wood crate to move, the force applied must be greater than the static friction between the wood crate and the wood floor.

Static friction = μN

Where μ = static friction.

Therefore, the minimum horizontal force that would be required to start the crate moving depend on the nature of the surface of the wood floor.

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The reaction exhibited an exothermic reaction.

Considering the energy values: The energy of the resulting products is lower compared to that of the initial reactants, indicating the liberation of energy throughout the reaction. This exemplifies the characteristic behavior of an exothermic reaction.

Analyzing the shape of the graph: If we were to plot the energy of the reaction as a function of time, the graph would display a downward trajectory, signifying a decrease in the system's energy. This aligns with the typical features associated with an exothermic reaction.

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Complete question:

In a particular chemical reaction, the energy of the reactants is 30 kJ and the energy of the products is 5 kJ. The maximum energy of the system is 40 kJ.

D. Is this reaction endothermic or exothermic? Explain your answer in two ways: first, using the energy values, and second, by referring to the shape of the graph.

That identical spaceship takes around a year to get to mars.

The Earth's axial wobble is stabilized by the Moon, the biggest and brightest object in our night sky, leading to a typically stable climate. As a result, Earth is a more hospitable planet. Moreover, it produces tides, which result in a rhythm that has guided mankind for a very long time. The following calculation must be performed to determine how long it will take the same spacecraft to reach Mars given that Mars is 140 times further away from Earth than the Moon and that a spacecraft can traverse the 386,400 kilometers between the Earth and the Moon in 3 days:

140 x 3 = 420 days

This spaceship will travel from Earth to Mars in just about one year and two months, assuming a year has 365 days.

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Answer:

what do u mean?

Explanation:

Answer:

But where is the a Question???

The speed of 5 kg ball is 10.2 m/s

Given data:

The mass of cart 1 is m₁=3 kg.

The speed of cart 1 moving east is v₁=17 m/s.

The mass of other cart is m₂=5 kg.

Since the carts stick together, and comes to rest their final velocity is zero, i.e., v=0.

Applying the conservation of momentum between the carts as,

Here, v₂ is the speed of 5kg cart. Since the cart 2 moving in west direction therefore v₂=-v₂.

Substitute all the values in above equation,

Thus, the speed of 5 kg ball is 10.2 m/s.

Final answer: 10.2 m/s

The value of the resistor is 24Ω.

A resistor is a passive two-terminal electrical component used in circuits to implement electrical resistance. Resistors have a variety of purposes in electronic circuits, including lowering current flow, adjusting signal levels, dividing voltages, biassing active components, and terminating transmission lines.

We are given that,

Voltage = δv =8v

Current = i =6a

So that , the resistance can be calculated by the formula by,

R = Vi

R = 8v × 6a

R = 24 Ω

Therefore , the of resistor would be 24Ω.

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Health literacy is knowing about health and knowledge of of right healthcare and services, taking care of diseases or just knowledge or taking care of your own health.

At a depth of 500 meters in the mine, the estimated vertical stress is 13.5 MPa, and the estimated horizontal stress is 11.57 MPa. Specific details to consider are Chalk Strength, Chalk Permeability, Chalk Heterogeneity.

Before proceeding with the excavation of the cavern beneath the sea, the main geological information that would be important to have includes the properties and characteristics of the chalk formation. Some specific details to consider are:

a) Chalk Strength: It is essential to determine the strength and stability of the chalk formation to ensure that it can support the excavation without collapsing or experiencing excessive deformation. This would involve assessing parameters such as the cohesion, friction angle, and compressive strength of the chalk.

b) Chalk Permeability: Understanding the permeability of the chalk is crucial, especially since the cavern will be beneath the sea. The permeability will impact the water flow within the chalk and may affect stability, seepage, and potential groundwater inflow into the excavation.

c) Chalk Heterogeneity: Chalk formations can exhibit variations in their composition, including the presence of layers or discontinuities such as faults or joints. Understanding the geological structure and heterogeneity of the chalk will help in assessing the potential for rock mass instability, water ingress, or the presence of other geological hazards.

To estimate the vertical and horizontal in-situ stresses at a depth of 500 meters in the mine, we can use the principles of rock mechanics and consider the given parameters.

Vertical Stress:

The vertical stress is the stress component acting vertically downward due to the weight of the overlying rock. It can be calculated using the average unit weight of the rock and the depth.

Vertical Stress = Unit Weight of Rock × Depth

Vertical Stress = 27 kN/m³ × 500 m

Vertical Stress = 13,500 kN/m² or 13.5 MPa

Horizontal Stress:

The horizontal stress can be estimated using the in-situ stress ratio, which is influenced by Poisson's ratio. The relationship between the horizontal and vertical stresses can be expressed as:

Horizontal Stress = Vertical Stress × (2 × Poisson's Ratio) / (1 - Poisson's Ratio)

Horizontal Stress = 13.5 MPa × (2 × 0.3) / (1 - 0.3)

Horizontal Stress = 13.5 MPa × 0.6 / 0.7

Horizontal Stress = 11.57 MPa

Therefore, at a depth of 500 meters in the mine, the estimated vertical stress is 13.5 MPa, and the estimated horizontal stress is 11.57 MPa.

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Answer:

3m/s

Explanation:

momentum=mass x velocity

to find velocity...

we change subjects and make velocity the subject,thus , velocity=momentum/mass

v=12/4 =3m/s.