2. Write a paragraph summarizing how chandragupta maurya built and ruled the mauryan empire. Use these words or phrases in your summary: kingdoms, conquer, unite, force, central government.

The acceleration ax = 3.03 m/s^2 and the ay = 1.75 m/s^2.

It is given that

h = 1.75m

\(\theta\)= 30°

Vo = 5.87 m/s

Now Vox= Vo cos\(\theta\)

= 5.87 x cos30° = 5.08 m/s

Voy = Vo sin\(\theta\) = 2.94 m/s

Tan\(\theta\) = h/x

⇒ x =h/tan\(\theta\)

⇒ x = 3.03m

y = h = 1.75m

Now, v for the ball is given by

V = Vo + \(\sqrt{10gh/7}\)

= Vo + \(\sqrt{10*9.81*1.75/7}\)

V = 5.87 + 4.95 = 10.82m/s

⇒ Vx = Vcos\(\theta\) = 9.37 m/s

and Vy = 5.41 m/s

a = 5/7 gsin\(\theta\)

So, ax = 5/7 gsin\(\theta\) x cos\(\theta\)

ax = 5/14 gsin(2\(\theta\))

ax = 5/14 x 9.81 x sin60°

ax= 3.03 m/s^2

and ay = 5/7gsin\(\theta\) x sin\(\theta\) = 5/7 gsin^2\(\theta\)

= 5/7 x 9.81 x sin^2 30°

⇒ ay = 1.75 m/s^2

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A liquids resistance to flow is called Viscosity

A phase change from the liquid phase to the vapour phase is called vaporisation (or vaporisation) of an element or molecule. Both evaporation and boiling result in vaporisation. Boiling is a bulk phenomenon, whereas evaporation is a surface phenomenon.

vaporisation is the process by which a material is transformed from its liquid or solid state into its gaseous (vapour) state. Boiling is the term for the vaporisation process when circumstances permit the creation of vapour bubbles within a liquid.

Evaporation is a typical process that takes place when a liquid transforms into a gas while raising the temperature or pressure. Boiling is an unnatural process in which the liquid is continuously heated to a point where it vaporises.

The transformation of a liquid into a gas is known as vaporisation.

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The time taken by the planet Mars to complete one orbit of the Sun is 5.94 x 10⁷ seconds.

Given information: In the spring of 2021, the New Horizons spacecraft reached a distance of 50 astronomical units ("AU") from Earth. One astronomical unit is the distance from the Earth to the Sun or about 150 million km.

Calculation: To find how many km was New Horizons from Earth, we need to multiply the distance in AU by the conversion factor. 1 AU = 150 million km 50 AU = 50 x 150 million km = 7.5 billion km Thus, the New Horizons spacecraft was 7.5 billion km from Earth in the spring of 2021. Now, let's move on to the second question. The planet Mars completes one orbit of the Sun in 687 days. We need to express this time in seconds using scientific notation.

To convert days to seconds, we need to multiply the number of days by the conversion factor. 1 day = 86400 seconds 687 days = 687 x 86400 seconds= 5.94 x 10⁷ seconds (using scientific notation) Therefore, the time taken by the planet Mars to complete one orbit of the Sun is 5.94 x 10⁷ seconds.

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It will now emit at a rate of 160 W.

the proportion of an emitter's energy to that of a blackbody, a perfect emitter with the same temperature, wavelength, and viewing circumstances. It ranges from 0 (for the optimum reflector) to 1 and has no dimensions (for a perfect emitter).

The ability to reliably measure temperature using an infrared temperature sensor or a thermal imaging camera depends critically on emissivity, which measures a material's capacity to radiate infrared energy from its surface.

The type of surface affects a surface's emissivity in addition to the material. A smooth and polished metal surface will have a low emissivity in contrast to a roughened and oxidized metal surface, which will have a high emissivity.

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A car traveling at a steady speed of 30m/s along a motorway overtakes a coach traveling in the same direction at 25m/s.

A. 1 minute after overtaking, the car will be 300 meters ahead of the coach.

B. 30 minutes after overtaking, the car will be 9000 meters ahead of the coach.

The car is traveling 5 m/s faster than the coach. This means that every second, the car gains 5 meters on the coach. After 1 minute, or 60 seconds, the car will have gained 300 meters on the coach. After 30 minutes, or 1800 seconds, the car will have gained 9000 meters on the coach.

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The far distance would be 86.0 cm. Eyeglasses with diverging lenses are used to help people with nearsightedness or myopia.

They work by refracting the light that enters the eye to create a virtual image that is further away from the eye than the original object. The far distance of the eyeglasses with diverging lenses of -1.22dp is 86.0 cm, assuming a distance between the eyeglasses and the eyes of 2.00 cm.

The power of the eyeglasses is measured in diopters (D), which can be used to calculate the far distance. The formula for calculating the far distance is 1/(1/FarDistance-LensPower). By plugging in -1.22dp for lens power and 2.00 cm for the distance between the eyeglasses and the eyes, the far distance would be 86.0 cm.

This means that the virtual image created by the eyeglasses will be 86.0 cm away from the eyes. The image appears to be closer to the eyes than the original object, which helps the person with myopia see the object more clearly.

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Thermal neutrons are diffracted of (b.c.c) solid sample at diffraction angle 50.56 ^∘. If the diffraction takes place of the plane (211) and the lattice constant of the unit cell is 2.868 A, what is the momentum of the incident neutron?

Thermal neutrons are slowed-down neutrons with energy lower than the energy of fast neutrons. They have a kinetic energy of about 0.025 eV (electron volts) or lower, which is roughly 2.2 kBT, where T is the temperature in kelvins. Thermal neutrons have a wavelength of about 0.2 nanometers, which is the same order of magnitude as the spacing between the atoms in a solid. As a result, when they collide with a solid, they can cause diffraction. When a neutron of momentum p and mass m is diffracted by a crystal, the diffraction angle θ is given by the Bragg equation:

2dsinθ = nλ,

where d is the spacing between the planes of atoms, λ is the wavelength of the neutron, n is an integer, and θ is the angle between the direction of the incident neutron and the plane of atoms.

In this problem, the diffraction angle is given as θ = 50.56°, and the spacing between the (211) plane of atoms is d = 2.868 Å.

The wavelength of the neutron is λ = h/p, where h is Planck's constant and p is the momentum of the neutron. Therefore, p = h/λ. Combining these equations gives:

2dsinθ = nλ

=> 2(2.868 Å)sin(50.56°) = n(h/p)

=> 2(2.868 × 10^−10 m)sin(50.56°) = n(6.63 × 10^−34 J s/p)

p=1.2 × 10^-24 kg m/s.

Approximately.

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The inductance in the Buck circuit is discharged when (C) the diode is off. In the Buck circuit, the inductor is charged when the switch is closed, allowing current to flow through it.

When the switch is opened, the current in the inductor wants to continue flowing, but the diode blocks this flow. As a result, the inductor discharges its energy through the diode, and the inductance is effectively discharged.

Under steady-state conditions, the inductor current (C) remains unchanged when the switch is turned off in the Boost circuit. In the Boost circuit, the inductor is charged when the switch is closed, and the current through the inductor increases.

When the switch is turned off, the inductor tries to maintain the current flowing through it, but the energy is transferred to the output load. The inductor current may experience a slight decrease due to the load, but it remains relatively constant or unchanged in steady-state conditions.

In summary, in the Buck circuit, the inductance is discharged when the diode is off, while in the Boost circuit, the inductor current remains unchanged when the switch is turned off.

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The transfer function is Vc(s)/Vs(s) = (R + 1/(sC)) / (sL + R + 1/(sC)), the pole-zero map includes poles at -R/L and zeros at -1/(sC), the response to Vs(t) = u(t)V can be calculated using inverse Laplace transform techniques and the response to Vs(t) = o(t)V can also be determined using inverse Laplace transform techniques.

To find Vc(s)/Vs(s), we need to consider the given electrical system with components R, L, and C. By applying Kirchhoff's laws and solving for the output voltage Vc(s) and input voltage Vs(s) in the Laplace domain, we can derive the transfer function as (R + 1/(sC)) / (sL + R + 1/(sC)).

The pole-zero map provides insights into the stability and behavior of the system. In this case, the transfer function has poles at -R/L, indicating a time constant associated with the system's dynamics. The transfer function also has zeros at -1/(sC), which affect the frequency response characteristics.

To find the response to Vs(t) = u(t)V, where u(t) represents the unit step function, we can apply inverse Laplace transform techniques to the transfer function Vc(s)/Vs(s). This will yield the time-domain response of the system to a step input.

Similarly, to find the response to Vs(t) = o(t)V, where o(t) represents the unit impulse function, we can use inverse Laplace transform techniques on the transfer function Vc(s)/Vs(s). This will give us the time-domain response of the system to an impulse input.

By calculating the inverse Laplace transforms of the transfer functions in cases 3) and 4), we can obtain the time-domain responses of the electrical system to the respective inputs.

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12°C is equal to 53.6°F. Celsius (°C) and Fahrenheit (°F) are both temperature scales used to measure the same physical quantity, temperature.

To convert 12°C to Fahrenheit, use the following formula:

°F = (°C x 9/5) + 32

Plugging in 12°C:

°F = (12 x 9/5) + 32 = 53.6°F

So, 12°C is equal to 53.6°F.

Celsius (°C) and Fahrenheit (°F) are both temperature scales used to measure the same physical quantity, temperature. The Celsius scale is based on the metric system and is used primarily in scientific applications and in most countries around the world. It defines the freezing point of water as 0°C and the boiling point of water as 100°C.

The Fahrenheit scale, on the other hand, is used mainly in the United States and its territories. It defines the freezing point of water as 32°F and the boiling point of water as 212°F. The Fahrenheit scale was defined by a physicist named Daniel Gabriel Fahrenheit in the early 18th century.

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Answer: 42

Explanation:

Answer:

Tuberculosis

Explanation:

Tuberculosis is a disease of lower respiratory system because it's affect the lungs and the voice box . It is a bacteria disease that affect the lungs and it is very contagious. It can spread rapidly to the brain and spine. Most times people with tuberculosis did not show symptoms but when there is symptoms,the symptoms include cough with blood, night sweats, fever e t.c.

Answer:A

Explanation:

Answer:

The answer is (B). hot dry desert climate

Explanation:

Answer:

Доброе утро, ответ 5+5="4

Explanation:

A promising evidence of a habitat that might support life on the planet Mars is water.

There is evidence supporting the existence of liquid water on Mars from numerous sources. The finding of repeated black streaks on Martian slopes and the presence of hydrated minerals suggest the potential of seasonal or location-specific briny water flows. A necessary component of life as known is liquid water.

Additionally, Mars possesses underground ecosystems that could provide defence against radiation and severe surface conditions. Researchers have found evidence of ancient underground hydrothermal systems as well as beneath ice. These settings might offer consistent conditions for the development of microbial life.  Methane gas has been found in the Martian atmosphere, along with variations over time, and this has led to questions regarding its origin. Both geological and biological processes can result in the production of methane.

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The lowest rock layer is a layer that must be rich in organic matter that was subjected to heat and pressure over time during the formation of oil and gas.

The lowest rock layer can be explained as;

The lowest rock layer refers to the lowermost part of the Earth's mantle, which is a thin rock layer (approximately 250 km).

In the Earth, the layers of rocks are progressively deposited, thereby pressing them to the bottom to generate sedimentary rocks.

The lowest rock layers on the bottom must be rich in organic matter to form fossil fuels.

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Answer:

Mass

Explanation:

The total sum of atoms in an object is the mass of the object. There are several ways to quantify the number of atoms in a substance.

Answer: Which statement best describes how scientists and engineers work together in the research and development cycle? Scientists develop new technology, and then engineers use it to solve design problems.

Explanation: boom!

The shrinking of integrated circuit device dimensions over six decades led to faster computing, advanced circuit functions, improved power efficiency, and widespread advanced electronic devices.

Increased Computing Speed: As device dimensions have shrunk, the distance between transistors on a chip has decreased, enabling faster electrical signal propagation. This has led to increased clock speeds and faster processing capabilities, allowing for more complex computations and faster data processing.

Enhanced Circuit Functionality: With smaller device dimensions, more transistors can be integrated into a single chip. This has enabled the development of highly sophisticated and complex circuits, such as microprocessors, capable of performing intricate tasks.

The increased number of transistors has also facilitated the integration of various functionalities, such as memory, graphics processing, and communication capabilities, onto a single chip, leading to more versatile and powerful computing devices.

Improved Power Efficiency: Smaller device dimensions have reduced the distance that electrical signals need to travel within a chip. This has minimized the power losses associated with signal propagation, resulting in improved power efficiency. Additionally, the miniaturization of components has allowed for the development of low-power transistors, enabling energy-efficient operation and longer battery life in portable electronic devices.

Proliferation of Advanced Electronic Devices: The million-fold reduction in device dimensions has made it possible to produce smaller, lighter, and more compact electronic devices. This has led to the widespread adoption of smartphones, tablets, wearables, and other portable devices that offer advanced computing, communication, and multimedia capabilities. The miniaturization of integrated circuits has also enabled the development of Internet of Things (IoT) devices, smart sensors, and embedded systems, which have revolutionized various industries and aspects of everyday life.

Increased Integration and System Complexity: Shrinking device dimensions have allowed for greater integration of components and systems on a single chip. This has led to the development of system-on-chip (SoC) solutions, where multiple functions, such as processing, memory, and communication, are combined on a single integrated circuit. The increased integration and system complexity have contributed to the advancement of technologies like artificial intelligence, machine learning, and autonomous systems.

Cost Reduction: The continual shrinking of device dimensions has resulted in increased transistor density on a chip. This has led to higher production yields per wafer, driving down the manufacturing cost per transistor. The cost reduction has made advanced computing and communication technologies more affordable and accessible to a wider range of users, fostering their widespread adoption.

Overall, the million times shrinking of device dimensions in integrated circuits over the past six decades has had a profound impact on computing and communications, revolutionizing the speed, functionality, power efficiency, and size of electronic devices while enabling the development of new technologies and driving economic growth in the digital era.

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The value of the integral ∮ →b · d→s for (a) path 1 is μ₀ * 5.0 A and for (b) path 2 is μ₀ * 3.0 A.

The student question is asking for the value of the integral ∮ →b · d→s for (a) path 1 and (b) path 2 for two closed paths wrapped around two conducting loops carrying currents i1 = 5.0 A and i2 = 3.0 A.

To find the value of the integral ∮ →b · d→s for each path, we can use Ampere's Law, which states that the line integral of the magnetic field (→b) around a closed loop is equal to the product of the permeability of free space (μ₀) and the net current (I) enclosed by the loop:

∮ →b · d→s = μ₀ * I

(a) For path 1, which is wrapped around the loop with current i1 = 5.0 A:

Step 1: Identify the enclosed current (I) - In this case, I = i1 = 5.0 A.

Step 2: Apply Ampere's Law - ∮ →b · d→s = μ₀ * I = μ₀ * 5.0 A.

(b) For path 2, which is wrapped around the loop with current i2 = 3.0 A:

Step 1: Identify the enclosed current (I) - In this case, I = i2 = 3.0 A.

Step 2: Apply Ampere's Law - ∮ →b · d→s = μ₀ * I = μ₀ * 3.0 A.

So, the value of the integral ∮ →b · d→s for (a) path 1 is μ₀ * 5.0 A and for (b) path 2 is μ₀ * 3.0 A.

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If you start with 1,000 grams of erbium-165, the time it  will take to have 125 grams of erbium-165 left in the sample is 20.8 hours.

option D is the correct answer.

Half life is the time that it takes for half of the original value of some amount of a radioactive element to decay.

If you start with 1,000 grams of erbium-165, the time it  will take to have 125 grams of erbium-165 left in the sample is calculated as follows;

1,000 ---------- 0 time

500 ----------- 10.4 hours

125 ------------- 20.8 hours

Thus, from the calculation done above, we can see that If you start with 1,000 grams of erbium-165, the time it  will take to have 125 grams of erbium-165 left in the sample is 20.8 hours.

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Answer:

How are physical and chemical changes similar and different? (compare and contrast) (Physical and chemical changes are similar because matter experiences a change in state, Physical changes are different because matter remains the same substance, just in a different state, whereas chemical changes change the matter

Answer:

populations found in equatorial areas will have the darkest skin (most eumelanin) and populations at higher latitudes will have lighter skin

Explanation:

if its right i cant really see what the question is asking

According to the question, The electrostatic force is inversely related to the square of the separation distance.

Between two charges that are separated by a distance, there is an electrostatic force. The size of each charging and the separation between them determine the strength of the electrostatic force. Two charges that are either positive or negative when placed together repel one another.

Positively and negatively charges are known to interact with one another. The magnitude of the electrostatic force, however, serves as a gauge for the strength of all this interaction. The magnitude of the static electricity and the spacing between them both contribute to this force.

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A state function does not depend on the path between the initial and final configurations.

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Answer:

The answer is C

Explanation:

Answer:

P = 173.33 [W]

Explanation:

Power is defined as the amount of work done over a given time.

W = work = 520 [J]

t = time = 3 [s]

P = power [w]

Therefore by working relationship over time we can calculate the power.

\(P =W/t\\P = 520/3\\P=173.33[W]\)

The smallest sound power output of the airplane motor that can be listened to on the ground is  6.73 × 10^-6 W which has the lowest-intensity sound that is still loud and has an intensity of  10^-12 W/m^2.

The intensity of sound =  10^-12 W/m^2

Altitude =  6,500 m.

Calculate the smallest sound energy output of an aircraft motor that can be heard on the ground is done by using the formula:

I = P/(4πr^2)

Pythagoras' theorem is used for calculating the distance

d = (\(\sqrt{6500^2 + R^2}\))

I = 10^-12 W/m^2

d = \(\sqrt{6500^2 + R^2}\)

d = 6500 m

P/(4πd^2) = I

\(P/(4π(6500)^2) = 10^-12 W/m^2\)

\(P = 4π(6500)^2 × 10^-12 W\)

P = 6.73 × 10^-6 W

Therefore, we can conclude that the smallest sound power output of the aircraft engine that can be heard on the ground is  6.73 × 10^-6 W.

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The distance travelled by the car after the first four hours of the trip is 370 km and the average speed for the first four hours of the trip is 92.5 kmph

v ( t ) = d ( t ) / t

v ( t ) = Velocity with respect to time

d ( t ) = Distance with respect to time

t = Time

For the first four hours, the following details are taken from the graph shown.

d ( 4 ) = 370 km

t = 4 hr

v ( 4 ) = 370 / 4

v ( 4 ) = 92.5 kmph

Average velocity can also be calculated using the formula V = ( u + v ) / 2 if the initial and final velocities are given. u represents initial velocity and v represents the final velocity.

Therefore,

Distance travelled in first 4 hours = 370 km

Average speed in first four hours = 92.5 kmph

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Answer: The answer is letter H