2(5x + 3) - 2(2x - 3)

The first quantity as a fraction of the second quantity 5 days ; 1 non-leap =  \(\frac{1}{73}\)

The first quantity as a fraction of the second quantity 42 minutes ; 2 hours  = \(\frac{7}{20}\)

Fraction:

                A numerical quantity which is not a whole number is called fraction.

   Example :     1/2  ,  3/5

Now,

a. The first quantity as a fraction of the second quantity 5 days ; 1 non-leap

       we know,

                        1 non-leap year =  365 days

Required fraction will be

                                   =  \(\frac{5 days}{365 days}\)

                                  =  \(\frac{1}{73}\)

A fraction of the second quantity 5 days ; 1 non-leap =  \(\frac{1}{73}\)

b. The first quantity as a fraction of the second quantity 42 minutes ; 2 hours

                             we know,

                                             1 hour    = 60 minutes

                                              2 hours  = 60 x 2 minutes

                                                             = 120 minutes

Required fraction will be

                                =  \(\frac{42 minutes}{120minutes}\)

                                = \(\frac{7}{20}\)

The first quantity as a fraction of the second quantity 42 minutes ; 2 hours  = \(\frac{7}{20}\)

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Answer:

4 x 4 + 5= 21

Step-by-step explanation:

Answer:

Draw your y and x axis , the y axis is going to be a vertical line while the x axis is going to be a horizontal line

Therefore, the balance on 15 March will be £686.00.

In mathematics, an expression is a combination of numbers, variables, and operators (such as +, -, ×, ÷, etc.) that represents a value or a quantity. Expressions can be simple or complex, and they can involve arithmetic operations, functions, and algebraic operations. Expressions can be evaluated, simplified, or manipulated using mathematical rules and techniques. They are used in many areas of mathematics, including algebra, calculus, and geometry, as well as in other fields such as physics, engineering, and economics.

Here,

a) The total income is the sum of all the "Money in" entries, which are:

Sales from 22-28 February: £35.00

Sales from 1-7 March: £200.00

Online bulk order: £30.00

Total income = £35.00 + £200.00 + £30.00

= £265.00

b) The total expenditure is the sum of all the "Money out" entries, which are:

Wages - overtime: £15.00

Stall hire fee: £120.00

Supplies - tea and coffee: £50.00

Sales - extra weekend opening: £4.00

Materials - trade purchase: £200.00

Total expenditure = £15.00 + £120.00 + £50.00 + £4.00 + £200.00

= £389.00

c) The balance on 15 March can be found by subtracting the total expenditure from the balance carried forward on 1 March, and then adding the total income.

Balance on 15 March = Balance carried forward - Total expenditure + Total income

Balance on 15 March = £810.00 - £389.00 + £265.00

= £686.00

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Answer:

I'll give you some clues in the solution. Please read them so you can do the rest faster.

Solution:

First thing you do is write the vertex. The vertex is basically the last number in the absolute value bars and the number outside of them (to the right of the bars). The vertex is the opposite of the last number in the absolute value brackets and if there is no number to the right, assume it is 0.

We start at (2,0).

The domain is 99% of the time all real numbers. Write that for domain.

The range is the y value where things start to increase (the y value of the vertex). The range is 0.

The type of function is absolute value function btw

Answer:

384 oz per hr

Step-by-step explanation:

3 gal per hr

1gal= 128oz

3×128= 384 oz per hr

The upper bound is 1842 and lower bound is 1692. By using these boundaries and t-table, the sample mean is 1767 and sample standard deviation = 133.98.

Here, the two boundaries are 1692 and 1842.

Mean = (1692+1842) /2 = 1767

Here the degree of freedom, df = (n-1) = 25-1 =24

Margin of error = (1842-1692)/2 = 75

Confidence level = 99%

From the t table, value of T with confidence level 99% and df= 24 is 2.80

The equation for margin of error is M = Ts/√n

            M= 75 , T= 2.80, n =25

75 = (2.80 × s) / √25

75 = 2.80s/ 5

s = (75×5)/2.80 = 133.928 = 133.93

So the sample mean is 1767 and the standard deviation is 133.93.

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The total area of the blue figure is  56.25 ft².

We can decompose the figure in 3 simpler ones.

First, a rectangle of 5 ft by 10ft, the area of that is the product between the two dimensions, so we will get the area:

A = 5ft*10ft = 50ft²

And the area of a triangle of base B and height H is:

A =B*H/2

For the triangle in the left, the area is:

A' = 1ft*5ft/2 = 2.5ft²

For the one in the left we get:

A'' = 1.5ft*5ft/2 =  3.75ft².

Adding all that we will get a total area of:

T = 50ft² + 2.5ft² + 3.75ft²

T = 56.25 ft².

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The seventh term of the geometric sequence is -7/32. The nth term of the sequence, a1 is the first term, r is the common ratio, and n is the position of the term

To find the seventh term of a geometric sequence, we can use the formula:

\(an = a1 * r^(n-1),\)

where an represents the nth term of the sequence, a1 is the first term, r is the common ratio, and n is the position of the term we want to find.

In this case, we are given a2 = -7 and r = 1/2.

Using the formula, we can find a1 by substituting n = 2:

a2 = a1 * (1/2)^(2-1).

We know that a2 = -7, so we can rewrite the equation:

-7 = a1 * (1/2)^1,

-7 = a1 * (1/2).

Now, let's solve for a1:

a1 = -7 * (2/1),

a1 = -14.

We have found that the first term, a1, is equal to -14.

Now, we can find the seventh term, a7, by substituting n = 7 into the formula:

a7 = (-14) * (1/2)^(7-1),

a7 = (-14) * (1/2)^6,

a7 = (-14) * (1/64),

a7 = -14/64,

a7 = -7/32.

Therefore, the seventh term of the geometric sequence is -7/32.

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If G is not a PRG, then Construction 3.17 cannot be EAV-secure. This shows the contrapositive of Theorem 3.18.

To prove the opposite, we need to show that if G is not a pseudorandom generator (PRG), then Construction 3.17 cannot be EAV-secure (indistinguishable encryptions in the presence of an eavesdropper).

Let's assume that G is not a PRG. This means that there exists some efficient algorithm D that can distinguish the output of G from random strings with non-negligible advantage. We will use this assumption to construct an adversary A that can break the EAV-security of Construction 3.17.

The adversary A works as follows:

1. A receives a security parameter n.

2. A runs the key generation algorithm Gen and obtains the key k.

3. A chooses two distinct messages m0 and m1 of length ℓ(n).

4. A computes the ciphertexts c0 = G(k) ⊕ m0 and c1 = G(k) ⊕ m1.

5. A chooses a random bit b and sends cb to the challenger.

6. The challenger encrypts cb using the encryption algorithm Enc with key k and obtains the ciphertext c*.

7. A receives c* and outputs b' = D(G(k) ⊕ c*).

8. If b = b', A outputs 1; otherwise, it outputs 0.

We analyze the probability that A can distinguish between encryptions of messages m0 and m1. Since G is not a PRG, D has a non-negligible advantage in distinguishing G's output from random strings. Therefore, there exists a non-negligible function negl such that:

|Pr[D(G(k)) = 1] - Pr[D(U) = 1]| ≥ negl(n),

where U denotes a truly random string of length ℓ(n).

Now, consider the probability of A winning the PrivK game:

Pr[PrivK_A,Π

eav

(n) = 1] = Pr[b = b']

           = Pr[D(G(k) ⊕ c*) = D(G(k))]

           = Pr[D(G(k)) = 1]

           ≥ Pr[D(U) = 1] - negl(n).

Since negl(n) is non-negligible, we have:

Pr[PrivK_A,Π

eav

(n) = 1] ≥ 2^(-1) + negl(n).

Thus, if G is not a PRG, then Construction 3.17 cannot be EAV-secure. This shows the contrapositive of Theorem 3.18.

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As per normalization, the session table uses the third normal form

Normalization is an important step in designing a database, as it helps to eliminate issues such as data integrity and redundancy. This is achieved through a series of steps, known as normalization.

The Sports Physical Therapy Center database has a table named Session that keeps track of all therapy appointments at the center. The table contains various pieces of information such as the session number, date, patient number, length of session, therapist ID, therapist's last and first name, and the therapy code.

The Session table is used to check if there are any design issues and to apply the necessary normalization steps to fix these issues and ensure data is stored in an organized manner.

Thorough this we have identified that the 3rd normal for is used here.

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Step-by-step explanation:

given data:

hours worked weekly = 39

pay/her = $10.95

insurance withheld weekly = $20

percentage put into Retirement = 4%

Solution:

Gross pay

= hrs worked weekly x pay/hr

= 39 x $10.95

= $427.05.

Deductions

insurance deduction

= $427.05 – $20

= $407.05

Amount put into retirement account

= 4% of $427.05

= 4/100 x $427.05

= $17.082

NET PAY

= $427.05 – $20 –$17.082

= $389.97

Answer:

D

Step-by-step explanation:

Answer:

The Answer is D) Just did the test!!

Step-by-step explanation:

Answer:

\(\sin(105) = \frac{\sqrt 2 + \sqrt 6}{4}\)

Step-by-step explanation:

Given

\(\sin(105^o)\)

Required

Solve

Using sine rule, we have:

\(\sin(A + B) = \sin(A)\cos(B) + \sin(B)\cos(A)\)

This gives:

\(\sin(105^o) = \sin(60 + 45)\)

So, we have:

\(\sin(60 + 45) = \sin(60)\cos(45) + \sin(45)\cos(60)\)

In radical forms, we have:

\(\sin(60 + 45) = \frac{\sqrt 3}{2} * \frac{\sqrt 2}{2} + \frac{\sqrt 2}{2} * \frac{1}{2}\)

\(\sin(60 + 45) = \frac{\sqrt 6}{4} + \frac{\sqrt 2}{4}\)

Take LCM

\(\sin(60 + 45) = \frac{\sqrt 6 + \sqrt 2}{4}\)

Rewrite as:

\(\sin(60 + 45) = \frac{\sqrt 2 + \sqrt 6}{4}\)

Hence:

\(\sin(105) = \frac{\sqrt 2 + \sqrt 6}{4}\)

The constant of variation given that  r varies directly with p and inversely with the product of s and t is one-half

r ∝ p ∝ 1/st

r ∝ p / st

r = Kp / st

Cross multiply

r × st = Kp

Divide both side by p

K = rst / p => constant of variation

K = rst / p

K = (18 × 1/6 × 2) / 12

K = 6 / 12

K = 1 / 2 = one-half

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Answer:  12.5%

Step-by-step explanation:  Find the difference , 81-72=9

      then find the percentage of the original score 9%   9/72 =  12.5

That adds up to the answer 12.5%

Hoped this helped :)

Step-by-step explanation:

The percent change formula is

\( \frac{new - old}{ |old| } = \frac{81 - 72}{ |72| } = \frac{9}{72} = 12.5\)

Answer: C

Step-by-step explanation:

C becuase they kept the fee so thats +4 so now were looking for x. Last year it was 6 and they doubled it so its 12

Answer:

C, y = 12x + 4

Step-by-step explanation:

If they double the ticket price, aka 6, then it would be 12. They also kept the convenience charge the same, so that remains 4.

Answer:

hi

Step-by-step explanation:

area of square is a²

14²=196 m

haveca nice day

Answer:

Ill be back let me solve it

Step-by-step explanation:

Answer:

The formula is: A = B * H where B is the base, H is the height, and * means multiply. The base and height of a parallelogram must be perpendicular. However, the lateral sides of a parallelogram are not perpendicular to the base.

Step-by-step explanation:

The simplest form of the square root of \(243x^7\) is \(9x^3\sqrt{3x}\).

We know that, we can write the number and expression as,

243 = 3*3*3*3*3 = \(3^5=3^4*3^1\)

\(x^7=x^6*x^1\)

Hence,

Square root of 243 is \(\sqrt{3^4*3^1}=3^2*\sqrt{3}=9\sqrt{3}\).

Square root of \(x^7\) is \(\sqrt{x^6*x^1}=x^3\sqrt{x}\)

Hence,

Simplest form of square root of \(243x^7\) is \(9\sqrt{3}*x^3\sqrt{x} = 9x^3\sqrt{3x}\).

Square root

Square root of a number is a value, which on multiplication by itself, gives the original number. The square root is an inverse method of squaring a number.

The square root symbol is usually denoted as ‘√’. It is called a radical symbol. To represent a number ‘x’ as a square root using this symbol can be written as: \(\sqrt{x}\).

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The possible key design is 262144.

Algebra is a branch of mathematics that uses mathematical expressions to aid in the representation of problems or situations. In algebra, we use numbers with definite or fixed values, such as 2, -1, 0.5, and so on. In algebra, variables such as x, y, and z are used in addition to numbers.

Given that keys for antique cars had nine parts, with four patterns for each part

We have to determine how many different key designs are possible for these cars

Number of designs possible

= 4x4x4x4x4x4x4x4x4

= 4^9

= 262144

Therefore the possible key design is 262144

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Answer:

27, 29, 36, 43, 79

Step-by-step explanation:

27 = the lowest data point = minimum

29 = quartile 1

36 = median = middle number

43 = quartile 2

79 = highest data point = maximum

A five number summary is a rought idea of what the data set is. you can make this by finding the highest and lowest data point, the middle data point, and quartile 1 and 3 (these are the middle numbers in between the lowest and the median, and the highest and the median).

Hope this helps!

Answer:

$1,372.80

Step-by-step explanation:

I =Prt

I =(5,720)(0.06)(4)=1,372.8

Answer:

Angle 1 = 128

Angle 2 = 52

Angle 3 = 47

Angle 4 = 133

Angle 5 = 81

Step-by-step explanation:

Angle 5 is 81

Angle 3 is 47

Angle 4 is 133

Angle 2 is 52

Angle 1 is 128

Answer:

k = ±6

Step-by-step explanation:

guess your question is 4k²–144 = 0??

4k² = 144

k² = 36

k²–36 = 0

(k+6)(k–6) = 0

k+6 = 0 | k–6 = 0

k = –6, k = 6.

Alternatively; k = ±6.