Answer:
5 kg
or 11 lbs
Explanation:
Jackie studied stresses that affect earth's crust. How is compression of rock different from shearing?.
"Compression of rock is nothing but squeezing the rock together and shearing is pushing the rock in opposing directions."
It squeezes the boulder as a whole and should cause the pulls to shear. This is because compression causes the weight necessary for rocks to be squeezed. Additionally, the rock's draws shouldn't be spaced apart. It shouldn't be going in opposing ways either.
When rocks are compressed together, they fold, fracture, or even shatter. Compression stress is the most prevalent stress at convergent plate boundaries. There is stress when rocks are being torn apart. Under stress, rocks either lengthen or fragment.
Due to the compression pushing the hanging wall up in relation to the footwall, if the fault arises in a scenario of compression, it will be a reverse fault.
Compressional stresses cause a rock to shorten. A rock elongates or pulls apart as a result of tensional pressures. Shear forces cause rocks to slide past one another.
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An insect lands 0.1m from the centre of a turn table while the record is turning at 55 rev/min at what linear speed will the insect be carried
collision with the near stationary photograph
The linear speed will be the insect be 0.5759 meter/second carried collision with the near stationary photograph.
What is speed?
Speed is distance travelled by the object per unit time. Due to having no direction and only having magnitude, speed is a scalar quantity With SI unit meter/second.
Given that an insect lands 0.1m from the center of the turn table.
Rotational speed of the turn table = 55 rev/min
= (55×2π/60) rad/second
= 5.759 rad/second.
Hence, the speed of the insect be = Rotational speed × length
= 5.759 rad/second × 0.1 M.
= 0.5759 meter/second.
Therefore, the speed of the insect be 0.5759 meter/second.
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The diagram below shows the velocity vectors for two cars that are moving
relative to each other.
45 m/s west
25 m/s east
Car 1
Car 2
From the frame of reference of car 1, what is the velocity of car 2?
OA. 20 m/s west
OB. 70 m/s east
C. 70 m/s west
D. 20 m/s east
The relative velocity of the car 2 with respect to car 1 is 70 m/s west. So, the correct option is C.
Velocity of the car 1 with respect to the ground, v₁ = 45 m/s west
Velocity of the car 2 with respect to the ground, v₂ = 25 m/s east
Let the direction towards the east be positive and the opposite direction towards the west be negative.
The expression for the relative velocity of the car 2 with respect to car 1 is given by,
v₂₁ = v₂ - v₁
v₂₁ = 25 - (-45)
Therefore, the relative velocity,
v₂₁ = 70 m/s west
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Attaching the image file here.
Three identical reservoirs, A,B, and C, are represented above, each with a small pipe where water exits horizontally. The pipes are set at the same height above a pool of water. The water in the reservoirs is kept at the levels shown. Which of the following correctly ranks the horizontal distances d that the streams of water travel before hitting the surface of the pool? (A) dA > dB > dC
(B) dA = dB = dCâ
(C) (dA = dB) > dC
â (D) dC > dB > dA
Correctly ranks the horizontal distances d that the streams of water travel before hitting the surface of the pool is (A) i.e. dA > dB > dC
The horizontal distances that a stream of water travels before hitting the surface of the pool is determined by the height of the water in the reservoir and the height of the pipe above the pool. The higher the water level in the reservoir, the greater the downward force on the water and the greater the horizontal distance that the water will travel. The higher the pipe is above the pool, the less distance the water has to fall and the shorter the horizontal distance that the water will travel. Correct ranking of the horizontal distances d that the streams of water travel before hitting the surface of the pool. Reservoir A has the highest water level, followed by reservoir B, and then reservoir C. The pipes in all three reservoirs are set at the same height above the pool. Therefore, the stream of water from reservoir A will have the greatest downward force and will travel the greatest horizontal distance before hitting the pool. The stream of water from reservoir B will have a lesser downward force and will travel a shorter horizontal distance before hitting the pool. The stream of water from reservoir C will have the least downward force and will travel the shortest horizontal distance before hitting the pool.
Therefore, the correct ranking is (A) dA > dB > dC.
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Some dragonflies splash down onto the surface of a lake to clean themselves. After this dunking, the dragonflies gain altitude, and then spin rapidly at about 1100 rpm to spray the water off their bodies. When the dragonflies do this "spin-dry," they tuck themselves into a "ball" with a moment of inertia of 2.0×10−7kg⋅m2 . How much energy must the dragonfly generate to spin itself at this rate?
The dragonfly must generate approximately 4.8 × 10^-4 Joules of energy to spin itself at a rate of 1100 rpm.
Start by converting the rotational speed from rpm (revolutions per minute) to rad/s (radians per second). Since 1 revolution is equal to 2π radians, we can use the conversion factor:
Angular speed (ω) = (1100 rpm) × (2π rad/1 min) × (1 min/60 s)
ω ≈ 115.28 rad/s
The moment of inertia (I) is given as 2.0 × 10^-7 kg⋅m².
Use the formula for rotational kinetic energy:
Rotational Kinetic Energy (KE_rot) = (1/2) I ω²
Substituting the given values:
KE_rot = (1/2) × (2.0 × 10^-7 kg⋅m²) × (115.28 rad/s)²
Calculate the value inside the parentheses:
KE_rot ≈ (1/2) × (2.0 × 10^-7 kg⋅m²) × (13274.28 rad²/s²)
KE_rot ≈ 1.331 × 10^-3 J
Round the result to the proper number of significant figures, which in this case is three, as indicated by the given moment of inertia.
KE_rot ≈ 4.8 × 10^-4 J
Therefore, the dragonfly must generate approximately 4.8 × 10^-4 Joules of energy to spin itself at a rate of 1100 rpm.
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Part F
Imagine you were a sportscaster at the Olympics. You'd created a mathematical model similar to the one you just did. Imagine that you had a
computer program that could do an instantaneous analysis of video motion using that model. How could you use it in your sportscast?
A program that could do an instantaneous analysis of video motion will be useful it in a sportscast to analyze events as they occur.
Why will a program be needed?A motion video is defined as the display of video images at a rate (such as thirty frames per second) that causes objects to appear to move smoothly and continuously.
Sports inherently involve fast and accurate motion, which can be difficult for competitors to master but also for coaches and trainers to analyze and audiences to follow. Because of the nature of most sports, monitoring with sensors or other devices attached to players or equipment is generally not possible. This opens up a plethora of opportunities for the use of computer vision techniques to assist competitors, coaches, and the audience
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Question 6 (5 points)
(03.04 MC)
What is the name of N2CI4? Explain how you determined the bond type and the steps you used to determine the naming convention for the
compound, (5 points)
Pleaseeeeeee helpppp meeeeeeeee
The molecule N2Cl2 has the name dinitrogen dichloride and contains a double bond and two single bonds.
What is N2Cl2?The molecule N2Cl2 is dinitrogen dichloride. It is a covalent molecule has a double bond between the two nitrogen atoms and a single bond linking each nitrogen atom to a chlorine atom.
The structure of the molecule is shown in the image attached. Hence, the compound contains a double bond and two single bonds.
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The valid digits in a measurement are called the significant digits. True or False
i think
Answer:
physics. The ______ is a systematic way to observe, experiment, and analyze the world. scientific method. The valid digits in a measurement are called the. significant digits.
Explanation:
truth'
There are two space ships traveling next to each other. The first one is 500
Kg and the second one is 498 Kg. Since they are 35 meters apart, what is
the force of gravity between the two space ships?
This question involves the concept of Newton's law of gravitation.
The force of gravity between the two spaceships is "1355.78 N".
Newton's Law Of GravitationAccording to Newton's Law of Gravitation:
\(F=\frac{Gm_1m_2}{r^2}\)
where,
F = force of gravity between ships = ?G = Universal Gravitational Constant = 6.67 x 10⁻¹¹ N.m²/kg²m₁ = mass of first ship = 500 kgm₂ = mass of second ship = 498 kgr = distance between ships = 35 mTherefore,
\(F=\frac{(6.67\ x\ 10^{-11}\ N.m^2/kg^2)(500\ kg)(498\ kg)}{(35\ m)^2}\\\\\)
F = 1355.78 N = 1.356 KN
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Two space ships traveling next to each other. The first one is 500 kg and the second one is 498 kg. They are 35 meters apart, the Force of gravity between the two spaceships is 1355.78 N.
It is given that the First spaceship's weight (\(m_{1}\)) is 500 kg,
The second spaceship's weight (\(\rm m_{2}\)) is 498 kg.
The distance between spaceships (r) is 35 meters.
It is required to find the Force of gravity between these spaceships.
What is Gravitational force?It is defined as the force which attracts any two masses in the universe.
By Newton's law of Gravitation:
\(\rm F= \frac{Gm_1m_2}{r^2}\) , Where
\(\rm F = The\ force \ of \ gravity \ between \ the \ spaceships\\\rm G= Universal\ Gravitational \ Constant = 6.67 \times 10^{-11} N.m^2/kg^2\)
Putting values in the above formula:
\(\rm F = \frac{(6.67\times 10^{-11} N.m^2/kg^2)(500kg)(498kg)}{(35m)^2}\)
F = 1355.78 N = 1.356 KN
Thus, Two spaceships travel next to each other. The first one is 500 kg and the second one is 498 kg. They are 35 meters apart, the Force of gravity between the two spaceships is 1355.78 N.
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Two objects are dropped from a bridge, an interval of 1.0 s apart, and experience no appreciable air resistance. As time progresses, the DIFFERENCE in their speeds
a.
increases.
b.
remains constant.
c.
decreases.
d.
increases at first, but then stays constant.
e.
decreases at first, but then stays constant.
Answer: a
Explanation:
A rocket takes off from Earth's surface, accelerating straight up at 63.2 m/s2. Calculate the normal force (in N) acting on an astronaut of mass 84.4 kg, including her space suit. (Assume the rocket's initial motion parallel to the +y-direction. Indicate the direction with the sign of your answer.)
______N
From the calculation, the normal force is 6161.2 N.
What is the normal force?The normal force is given by the expression;
N - mg = ma
Then;
N = mg + ma
m = 84.4 kg
g = 9.8 m/s^2
a = 63.2 m/s2
Now we have;
N = m(g + a)
N = 84.4 (9.8 + 63.2)
N = 6161.2 N
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We are observing wasted heat in everyday life for example in Pakistan heavy generated are installed, during their supply of electricity an excessive amount of wasted heat is produced in its surrounding, similarly when we drive a vehicle a heat is available in the surrounding of engine of that vehicle, we can also see many more such examples of wastage of heat. This heat is effecting the environment of Pakistan badly.
Is it conceivable to convert this wasted heat into some useful work/energy/electricity or not. If yes how? If no why
Yes, it is possible to convert wasted heat into useful energy. This process is called thermoelectric conversion and it is based on the Seebeck effect.
What is thermoelectric?Thermoelectricity is the production of electricity from temperature differences. It is a direct energy conversion process, which converts thermal energy directly into electrical energy.
In this process, a temperature difference between two materials (usually semiconductors) is used to generate a flow of electric current. By using an array of these materials, it is possible to convert wasted heat into electricity. This process is already being used in several industries, such as the automotive and aerospace industry, to convert heat from engines into electricity. Additionally, it is also being used in power plants to convert heat from the exhaust gases into usable electricity.
The advantages of thermoelectric conversion are that it is relatively simple and is not affected by environmental conditions. Furthermore, it is an environmentally friendly technology as it does not produce any emissions and can help reduce energy wastage.
However, the main disadvantage of thermoelectric conversion is its low efficiency. This is because a large amount of energy is needed to generate a small amount of electricity. As such, thermoelectric conversion is not suitable for large-scale electricity generation.
Overall, thermoelectric conversion is a viable solution for converting wasted heat into usable energy. It is a relatively simple technology that has low environmental impact and can help reduce energy wastage. However, its low efficiency means that it is not suitable for large-scale electricity generation.
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For example, we can take Water
In (A) Water has same mass and great volume
In (B) Water has same mass and lower volume
Will there be any change in its density then?
Answer:
yes there will be change in its density
please help PLEASE NOW
Journal prompt to be answered in 2 fully developed paragraphs
Prompt: What are some products (or programs) that you could purchase to help your performance in your current physical activity? How would the product (or program help)? Do you really think it is effective? Use specific examples from your experience.
You could purchase a fitness tracker to help your performance in your current physical activity.
Fitness tracker would help you in the area of goal setting.
Fitness trackers are effective because they have helped my friends to improve workout routine.
What are some products and programs that do help to physical activity?Wearable fitness trackers can monitor data like heart rate, number of steps taken, distance traveled, and number of calories burned.
Supplements including protein powders, creatine, and beta-alanine can enhance recovery, muscular growth, and endurance.
Working with a coach or personal trainer can help you attain your fitness objectives by offering personalized training regimens, comments on form and technique, and accountability.
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Heather drives her Super-Beetle around a turn on a circular track which has a radius of 200 m. The Super-Beetle has a mass of 1500 kg and the coefficient of static friction between the road and tires is 0.6.
a. What is the force of static friction the road can apply batore the car starts to selon (use Ft= uFn).
b. What is the maximum speed the car can travel before it would start to slide?
Answer:
a) The force of static friction the road can apply before the car starts to move is 8826.3 newtons.
b) The maximum speed that a car can travel before it would start to slide is approximately 34.305 meters per second.
Explanation:
a) Let suppose that the car is on a horizontal ground and travels at constant speed. The vehicle experiments a centripetal acceleration due to friction, which can be seen in the Free Body Diagram (please see image attached for further details). By Newton's Laws, we construct the following equations of equilibrium:
\(\Sigma F_{x} = \mu_{s}\cdot N = m\cdot \frac{v^{2}}{R}\) (1)
\(\Sigma F_{y} = N -m\cdot g = 0\) (2)
Where:
\(\mu_{s}\) - Static coefficient of friction, dimensionless.
\(N\) - Normal force from ground to the car, measured in newtons.
\(v\) - Maximum speed of the car, measured in meters per second.
\(R\) - Radius of the circular track, measured in meters.
\(m\) - Mass, measured in kilograms.
\(g\) - Gravitational acceleration, measured in meters per square second.
By applying (2) in (1):
\(\mu_{s}\cdot m\cdot g = m\cdot \frac{v^{2}}{R}\) (3)
The force of static friction the road can apply in the car (\(f\)), measured in newtons, is: (\(\mu_{s} = 0.6\), \(m = 1500\,kg\), \(g = 9.807\,\frac{m}{s^{2}}\))
\(f = \mu_{s}\cdot m \cdot g\)
\(f = (0.6)\cdot (1500\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)\)
\(f = 8826.3\,N\)
The force of static friction the road can apply before the car starts to move is 8826.3 newtons.
b) Then, we calculate the maximum speed of the car by (3):
\(\mu_{s}\cdot m\cdot g = m\cdot \frac{v^{2}}{R}\)
\(\mu_{s}\cdot g = \frac{v^{2}}{R}\)
\(v = \sqrt{\mu_{s}\cdot g\cdot R}\)
If we know that \(\mu_{s} = 0.6\), \(g = 9.807\,\frac{m}{s^{2}}\) and \(R = 200\,m\), then the maximum speed of the car can travel before it would start to slide is:
\(v =\sqrt{(0.6)\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (200\,m)}\)
\(v \approx 34.305\,\frac{m}{s}\)
The maximum speed that a car can travel before it would start to slide is approximately 34.305 meters per second.
1. Which of the following does not affect the resistance of a wire?
a) Length
b) Temperature
c) Usage time
d) Cross-sectional area
2. If a 12V battery is passing current through a resistor with a current of 2A, what is the value of the resistor?
a 24resistance
b) 14resistance
c) 10resistance
d) 6resistance
3. Describe the differences between series and parallel circuits.
4. A circuit contains resistors of 8resistance and 4resistance,what is combined resistance if the resistors are combined:
a) In series
b) In parallel
5. A 0.5A current is passing across three resistors of 8resistance, 4resistance and 12resistance that are linked in series.
What is the potential difference of the circuit?
6. Wire A has a resistance of 24resistance. If wire B is double the length and has a diameter four times as large as wire A, what is the resistance of wire B?
2020 State of the Bay Summary PLS HELP PLS ILYSM IF U DO!!!!
What are your first feelings or impressions when looking at the tables above?
Which indicators do you believe are most important for the health of the Bay? Explain.
Chesapeake Bay Report Grade vs. Year Graph
From your viewpoint, 1) what does the graph reveal about the current state of the Chesapeake Bay? 2) Do you believe your community contributes to the Chesapeake Bay’s condition? Explain your answer.
There is likely to be eutrophication in the water
There are less turbid substances deposited in the water within the time.
The decrease of water grasses means the primary productivity reduced.
What does increase in nitrogen and phosphorus content mean for Chesapeake Bay ?An increase in nitrogen and phosphorus content in Chesapeake Bay can have significant environmental impacts. Chesapeake Bay is an estuary that is highly sensitive to nutrient pollution, which can cause the growth of harmful algal blooms and oxygen depletion in the water.
When excess nitrogen and phosphorus from fertilizers, animal waste, and sewage enter the Bay, they can cause an overgrowth of algae. As these algae die and decompose, they consume oxygen in the water, leading to low oxygen conditions known as "hypoxia" or "dead zones". This can harm fish, shellfish, and other aquatic life, and can also have economic impacts on the fishing and tourism industries.
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A long, uninsulated steam line with a diameter of 89 mm and a surface emissivity of 0.8 transports steam at 200C and is exposed to atmospheric air and large surroundings at an equivalent temperature of 20C. (a) Calculate the heat loss per unit length for a calm day. (b) Calculate the heat loss on a breezy day when the wind speed is 8 m/s. (c) For the conditions of part (a), calculate the heat loss with a 20-mm-thick layer of insulation (k 0.08 W/m K). Would the heat loss change significantly with an appreciable wind speed
Answer:
\(Q_net=534.67\frac{w}{m}\)
Explanation:
From the question we are told that:
Steam line diameter \(D=89mm \approx 0.089m\)
Surface emissivity \(\mu=0.8\)
Steam temp \(T_s=200\textdegree C \approx 200+273=473k\)
Surrounding temp \(T_a=20 \textdegree C \aprrox 20+273= 293k\)
Generally the equation for heat loss per unit length due to radiation \(Q_{net}\) is mathematically given by
\(Q_net=\sigma*\mu>(\pi *d)*(T_s^4-T_a^4)\)
\(Q_net=5.6*10^8*0.8*(\pi *0.089)*(473^4-293^4)\)
\(Q_net=534.67\frac{w}{m}\)
Batman and Robin are attempting to escape that dastardly villain, the Joker, by hiding in a large pool of water (refractive index nwater = 1.333). The Joker stands gloating at the edge of the pool. (His makeup is watersoluble.) He holds a powerful laser weapon y1 = 1.49 m above the surface of the water and fires at an angle of θ1 = 27◦ to the horizontal. He hits the Boy Wonder squarely on the letter "R", which is located y2 = 3.77 m below the surface of the water. θ x y y 1 1 2 R J Batplastic surface Mirrored Surface water B How far (horizontal distance) is Robin from the edge of the pool? (Fear not, Batfans. The "R" is made of laser-reflective material.) Answer in units of m.
Answer:
x_total = 4.29m
Explanation:
To solve this exercise we must work in parts. Let's use the law of refraction to find the angle of the refracted ray and trigonometry to find the distances.
Let's start by looking for the angles that the laser refracts
n₁ sin θ₁ = n₂ sin θ₂
where n₁ is the air refraction compensation n₁ = 1, n₂ the water refractive index n₂ = 1,333
θ₂ = sin⁻¹ (n₁ sin θ₁/n₂)
θ₂ = sin⁻¹ (1 sin 27 / 1,333)
θ₂ = sin⁻¹ 0.34057
θ₂ = 19.9º
now let's find the distance from the edge of the pool to the point where the ₂lightning strikes the water
tan θ₁ = y₁ / x₁
x₁ = y₁ / tan θ₁
x₁ = 1.49 / tan 27
x₁ = 2,924 m
Now let's look for the waterfall in the water as far as Robin
tan θ₂₂ = y₂ / x₂
x₂ = y₂ / tan θ₂
x₂ = 3.77 / tan 19.9
x₂ = 1,364
the distance from the edge of the pool to Robin is
x_total = x₁ + x₂
x_total = 2,924 + 1,364
x_total = 4.29m
what is the springs constant?
The spring constant, symbolized k, is a proportionality constant that shows the relationship between the force applied to a spring and the amount of stretch or compression it undergoes in response.
In simple terms, the spring constant relates the force that is required to extend or compress a spring by a certain distance.
This is what is known as Hooke's Law, named after the scientist Robert Hooke.
According to Hooke's Law, the force required to compress or stretch a spring is directly proportional to the distance that the spring has been compressed or stretched.
Hooke's law can be expressed mathematically as: F = -kx, where F is the force being applied to the spring, x is the distance the spring is stretched or compressed from its equilibrium position, and k is the spring constant.
The negative sign in the equation indicates that the direction of the force is opposite to the direction of displacement of the spring.
The units of the spring constant depend on the units of the force and displacement used in the equation.
In SI units, the spring constant is measured in Newtons per meter (N/m).
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The half-life of a radioactive isotope is 210 d. How many days would it take for the decay rate of a sample of this isotope to fall to 0.58 of its initial rate?
It would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.
1. The decay rate of a radioactive isotope is proportional to the number of radioactive atoms present in the sample at any given time.
2. The decay rate can be expressed as a function of time using the formula: R(t) = R₀ * \(e^{(-\lambda t\)), where R(t) is the decay rate at time t, R₀ is the initial decay rate, λ is the decay constant, and e is the base of the natural logarithm.
3. The half-life of a radioactive isotope is the time it takes for half of the radioactive atoms in a sample to decay. In this case, the half-life is given as 210 days.
4. Using the half-life, we can find the decay constant (λ) using the formula: λ = ln(2) / T₁/₂, where ln(2) is the natural logarithm of 2 and T₁/₂ is the half-life.
5. Substituting the given half-life into the formula, we have: λ = ln(2) / 210.
6. Now, we need to find the time it takes for the decay rate to fall to 0.58 of its initial rate. Let's call this time "t".
7. Using the formula for the decay rate, we can write: 0.58 * R₀ = R₀ * e^(-λt).
8. Simplifying the equation, we get: 0.58 = \(e^{(-\lambda t\)).
9. Taking the natural logarithm of both sides, we have: ln(0.58) = -λt.
10. Substituting the value of λ from step 5, we get: ln(0.58) = -(ln(2) / 210) * t.
11. Solving for t, we have: t = (ln(0.58) * 210) / ln(2).
12. Evaluating the expression, we find: t ≈ 546.
13. Therefore, it would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.
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A Typical operating voltage of an electron microscope is 50 kV. A Typical experimental operating voltage range of a Scanning electron microscope is 1kV to 30kV. Higher voltages can penetrate and causes deformation on the sample. Lets assume it operates at 10kV. (i)What is the smallest distance that it could possibly resolve
Answer:
y =\(\frac{1.22L}{D}\) \(\sqrt{\frac{h^2 m}{2eV} }\)
Explanation:
Let's solve this exercise in parts. Let's start by finding the wavelength of the electrons accelerated to v = 10 103 V, let's use the DeBroglie relation
λ= \(\frac{h}{p} = \frac{h}{mv}\)
Let's use conservation of energy for speed
starting point
Em₀ = U = e V
final point
Em_f = K = ½ m v²
Em₀ = Em_f
eV = ½ m v²
v =\(\sqrt{\frac{2eV}{m} }\)
we substitute
λ= \(\sqrt{ \frac{h^2 m}{2eV}}\)
the diffraction phenomenon determines the minimum resolution, for this we find the first zero of the spectrum
a sin θ = m λ
first zero occurs at m = 1, also these experiments are performed at very small angles
sin θ = θ
θ = λ / a
This expression is valid for linear slits, in the microscope the slits are circular, when solving the polar coordinates we obtain
θ = 1.22 λ / D
where D is the diameter of the opening
we substitute
θ = \(\frac{1.22}{D}\) \sqrt{ \frac{h^2 m}{2eV}}
this is the minimum angle that can be seen, if the distance is desired suppose that the distance of the microscope is L, as the angles are measured in radians
θ = y / L
when substituting
where y is the minimum distance that can be resolved for this acceleration voltage
y =\(\frac{1.22L}{D}\) \(\sqrt{\frac{h^2 m}{2eV} }\)
Identify two fields where physical quantities are used in motion calculations
The two fields were physical quantities are used in motion calculations are length and mass with time.
The physical quantity in a field is referred as every point in a particular space time.
How physical quantities are used in motion calculations?
If we consider an object, the physical property of the object is considered as physical quantity and to measure that object is known as units. The Physical quantity can be classified as elemental physical quantity and derived physical quantity. Length, mass, time, etc.. are elemental physical quantity, momentum, density, acceleration, etc... are derived physical quantity. Only for charge and temperature the physical quantity will be less than zero.
Length, mass and time are the physical quantities used in motion calculations.
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PLEASE SAVE ME FROM THIS PHYSICS QUESTION (WILL MARK BRAINLIEST)
A 21 kg child is riding a 5.9 kg bike with a velocity of 4.5 m/s to the northwest.
- What is the total momentum of the child and the bike together?
- What is the momentum of the child?
- What is the momentum of the bike?
Answer:
See Below
Explanation:
Mass of child = 21 kg
Mass of bicycle = 5.9 kg
Total mass = 22 + 5.9 = 27.9 kg
Velocity = 4.5 m/s
1) Total momentum of the child and the bike together
= Total mass * Velocity
= 27.9*4.5
= 125.55 kg m per second
2) Momentum of the child
= Mass of child*Velocity
= 21*5.9
= 123.9 kg m per second
3) Momentum of the bike
= Mass of bike*Velocity
= 5.9*4.5
= 26.55 kg m per second
When the temperature is expected to drop below freezing, a farmer places large tubs of water in an unheated food storage shed. Write two or three sentences explaining why the farmer uses this technique to protect the produce from freezing. Hint: Remember that liquid water has more potential energy than ice.
The farmer uses this technique to protect the produce from freezing because as the water in the tubs begins to freeze, it releases heat. This heat can help to keep the surrounding air in the shed above freezing, protecting the produce from freezing as well. Additionally, as the water in the tubs freezes, it releases latent heat of fusion, which is the energy required to change a substance from a solid to a liquid. This energy is also released in the form of heat, further helping to keep the produce from freezing.
Masses m and 2m are joined by a light inextensible string which runs without slipping over a uniform circular pulley of mass 2m and radius a. Using the angular position of the pulley as generalized coordinate, write down the Lagrangian function and Lagrange's equation. Find the acceleration of the masses.
Answer: the acceleration of the masses is given by = 0, which means the angular acceleration of the pulley is zero. This implies that the masses m and 2m move with constant velocity, they are in equilibrium.
Discuss why a physically active job does not guarantee better physical fitness. Compare and contrast lifestyle choices that positively affect physical fitness with those that negatively affect physical fitness.
Answer:
Like a personal trainer? Personal trainers don't do a lot of physical activity, they mostly warm up their clients and tell them what kind of workouts to do. But their are also coaches, and they don't do much either. So you're not benefiting much out of that.
Explanation:
Is it possible for an object to be accelerating and at rest at the same time? Explain.
Answer:
Yes
Explanation:
acceleration is a change in velocity, so an object might be momentarily at rest but a split-second later have some speed, i.e. it can be changing its velocity even if it is momentarily at rest.
The earth has a vertical electric field at the surface,pointing down, that averages 102 N/C. This field is maintained by various atmosphericprocesses, including lightning.
What is the excess charge on the surface of the earth? inC
Answer:
\(q = -461532.5 \ C\)
Explanation:
From the question we are told that
The electric filed is \(E = 102 \ N/C\)
Generally according to Gauss law
=> \(E A = \frac{q}{\epsilon_o }\)
Given that the electric field is pointing downward , the equation become
\(- E A = \frac{q}{\epsilon_o }\)
Here \(q\) is the excess charge on the surface of the earth
\(A\) is the surface area of the of the earth which is mathematically represented as
\(A = 4\pi r^2\)
Where r is the radius of the earth which has a value \(r = 6.3781*10^6 m\)
substituting values
\(A = 4 * 3.142 * (6.3781*10^6 \ m)^2\)
\(A =5.1128 *10^{14} \ m^2\)
So
\(q = -E * A * \epsilon _o\)
Here \(\epsilon_o\) s the permitivity of free space with value
\(\epsilon_o = 8.85*10^{-12} \ m^{-3} \cdot kg^{-1}\cdot s^4 \cdot A^2\)
substituting values
\(q = -102 * 5.1128 *10^{14} * 8.85 *10^{-12}\)
\(q = -461532.5 \ C\)
Please help this question
Answer:
Kantians would say that Sharkeisha acted immorally since she increased overall pain.