Answer:
\(\mathbf{1.51\times10^{-15}N}\)
Explanation:
The computation of the weight of the paper in newtons is shown below:
On the paper, the induced charge is of the same magnitude as on the initial charges and in sign opposite.
Therefore the paper charge is
\(q_{paper}=-4.1\times10^{-15}C\)
Now the distance from the charge is
\(r=1cm=0.01m\)
Now, to raise the paper, the weight of the paper acting downwards needs to be managed by the electrostatic force of attraction between both the paper and the charge, i.e.
\(mg=\frac{k_{e}q_{1}q_{2}}{r^{2}}\)
\(\Rightarrow W=mg\)
\(=\frac{9\times10^{9}\times(4.1\times10^{-15})^{2}}{0.01^{2}}\)
\(=\mathbf{1.51\times10^{-15}N}\)
Where should be the best fit line be drawn on a scatterplot?
A. In the center of the data
b. below the data
c. above the data.
d. none of these
A line of best fit is a straight line drawn through the most points on a scatter plot, with an equal number of points above and below the line. It is used to investigate the nature of the relationship between two variables. The correct option is d.
What is line of best fit?A straight line with the best fit is one that minimizes the distance between it and some data.
In a scatter plot of varying data points, the line of best fit is used to express a relationship. It is a result of regression analysis and can be used to forecast indicators and price movements.
It is important to note that your line does not need to pass through any of the points on the plot; it only needs to bisect the area that contains the data points.
Thus, none of the options are correct, the correct one is d.
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si el valor de la masa 1 es de 76kg y rl coeficiente de friccion cinetica es de 0.37. ¿Cual seria el valor maximo de la masa2 que se puede colgar en el sistema manteniondolo en reposo?
Answer:
B
Explanation:
The answer is B
A certain satellite travels in an approximately circular orbit of radius 8.8 × 10^6 m with a period of 6 h 12 min. Calculate the mass of its planet from this information.
The mass of the planet is 5.98 × 10^24 kg.
To calculate the mass of the planet, we can use Kepler's Third Law of Planetary Motion. This law states that the square of the period of revolution of a planet around the sun is directly proportional to the cube of the semi-major axis of its orbit.
First, we need to convert the period of the satellite's orbit to seconds. We know that there are 60 minutes in an hour, so the period can be expressed as (6 × 60 + 12) minutes, which equals 372 minutes. Multiplying this by 60 seconds, we get a period of 22,320 seconds.
Next, we need to find the semi-major axis of the orbit. In a circular orbit, the semi-major axis is equal to the radius of the orbit. Therefore, the semi-major axis is 8.8 × 10^6 m.
Now, we can apply Kepler's Third Law to calculate the mass of the planet. The formula is T^2 = (4π^2/GM) × a^3, where T is the period of revolution, G is the gravitational constant, M is the mass of the planet, and a is the semi-major axis of the orbit.
Rearranging the formula, we can solve for the mass of the planet:
M = (4π^2/G) × a^3 / T^2
Plugging in the values, we get:
M = (4 × π^2 / 6.67430 × 10^-11) × (8.8 × 10^6)^3 / (22,320)^2
Evaluating this expression, we find that the mass of the planet is approximately 5.98 × 10^24 kg.
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A 193.4 g sample of water at 13.5°C is heated to steam at 131.1°C. How much heat was absorbed?
A 193.4 g sample of water at 13.5°C is heated to steam at 131.1°C. The amount of heat absorbed will be 96000 KJ.
What is Heat energy?Thermal energy refers to the energy which is contained within a system that is responsible for the temperature. Heat is the flow of thermal energy in the system.
Given that,
Mass, m = 193.4 g
We know that,
Q₁ = mcΔt
Q₁ = 193.4 × 4200 × (131.1 - 13.5)
Q₁ = 193.4 × 4200 × 117.6
Q₁ = 95,524,128 Joules
Now, the latent heat
Q₂ = mL
Q₂ = 193.4 × 2260
Q₂ = 437,084 Joules
Now, the total heat energy required,
Q = Q₁ + Q₂
Q = 95,524,128 + 437,084
Q = 95,961,212 Joules
Therefore, the heat energy is approximately 96000 KJ.
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Your question is incomplete, most probably the complete question is:
Calculate the heat energy required to convert completely a 193.4 g sample of water at 13.5°C is heated to steam at 131.1°C, given that the specific heat capacity of water is 4200 J/(kg°C) and the specific latent heat of vaporization of water is 2260 kJ/kg.
One day, the distance between the crests of the waves at sea is 2.5m. The shortest time between the lowest and highest positions of the floating boat was 0.625 seconds.
a) Calculate the wave period.
b) Calculate the speed of the wave.
Answer:
1.25 sec, 2 m/s
Explanation:
Period = 2 * 0.625 sec = 1.25 sec
speed = 2.5/1.25 = 2 m/s
HELP WILL GIVE BRAINLEST!!
Imagine you could interview the earth as it revolves around the Sun. think of four questions for each season you could ask the Earth. The imagine how Earth would answer these questions.
Answer:
y hu
Explanation:
What are the 5 Stages of Child Development?
Newborn (0-3 months)
Infant (3-12 months)
Toddler (1-3 years)
Preschool age (3-4 years)
School age (4-5 years).
.
.Ages and Stages is a term used to outline significant periods in the human development timeline. During each stage, growth and development occur in the primary developmental domains, including physical, intellectual, language and social-emotional.The Sun radiates energy at a rate of about 4×1026W. At what rate is the mass decreasing?
4.44×\(10^{9}\) kg/s is the rate at which the sun mass is decreasing.
The Sun radiates energy through a process called nuclear fusion, where hydrogen atoms combine to form helium, releasing a tremendous amount of energy in the process. According to Einstein's mass-energy equivalence principle (E=mc²), this energy release corresponds to a decrease in mass.
To calculate the rate at which the Sun's mass is decreasing, we can use the formula ΔE = Δmc², where ΔE is the change in energy, Δm is the change in mass, and c is the speed of light.
Given that the Sun radiates energy at a rate of 4×10^26 W, we can substitute this value into the equation as ΔE and solve for Δm.
ΔE = 4×10^26 W
c = 3×10^8 m/s (speed of light)
Using the equation ΔE = Δmc² and rearranging it, we get Δm = ΔE / c².
Substituting the values, we have:
Δm = (4×10^26 W) / (3×10^8 m/s)²
Evaluating this expression, we find that the rate at which the Sun's mass is decreasing is approximately 4.44×10^9 kg/s.
This calculation demonstrates that the Sun's mass is gradually decreasing as it continuously radiates energy into space, primarily through the process of nuclear fusion in its core.
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A continental polar air mass forms in
a. the Pacific Ocean.
b. northern Canada.
c.
the Gulf of Mexico.
the desert Southwest.
d.
Please select the best answer from the choices provided
А
B
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my uq xbbbnxnjjxjxusjhhhwhhhnn he c x. Yes suhsjjdhhehy yes eirui
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Answer:
B. Northern Canada
Explanation:
A continental polar air mass can form over the land during the winter months. In the Northern Hemisphere, it originates in northern Canada or Alaska. As it moves southward, it brings dry weather conditions to the United States. Temperature and humidity levels are both low. Hope this helps :)
Which vector is the sum of vectors à and b?
The vectors addition permits locating the perfect result for the sum of the two vectors in option B). See attached and the vector is directed to the right and up.
Vector addition is the operation of adding or extra vectors together into a vector sum. The so-known as parallelogram regulation gives the rule for vector addition of or greater vectors. for two vectors and, the vector sum is received via placing them head to tail and drawing the vector from the loose tail to the unfastened head.
A vector is an amount or phenomenon that has impartial residences: importance and direction. The time period also denotes the mathematical or geometrical representation of the sort of quantity. Examples of vectors in nature are velocity, momentum, force, electromagnetic fields, and weight.
Vectors are used in technological know-how to describe something that has a direction and a magnitude. they're commonly drawn as pointed arrows, the length of which represents the vector's importance
Disclaimer: your question is incomplete, please see below for the complete question.
The image shows the complete question.
Which vector is the sum of vectors à and b?
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what is the net charge when you rub a plastic ruler with fur
The net charge when you rub a plastic ruler with fur would be infinitesimal or zero
How to detect the net chargeThe effect of friction between a plastic ruler and fur is evident when electrons are transferred from the hairy surface to the ruler's plane, ending with the ruler possessing a negative charge while the fur taking on a positive one.
As a result, the whole system presents with a net charge that is negative it converges due to the excess electrons now found on the ruler. However, occasionally, the magnitude of this charge is very small, consequently making it difficult to probe without reliable technology or instruments.
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If velocity is positive, which would most likely yield a negative acceleration?
O A final velocity that is gfaster than an initial velocity.
O Atime that is less than a half hour.
O An initial velocity that is faster than a final velocity.
O A time that is greater than a half hour.
The correct answer for velocity if acceleration is opposite is:
* An initial velocity that is faster than a final velocity
The given parameters are acceleration and initial velocity, it is asked to find the final speed of the body
In kinematics, position, velocity, and acceleration are quantities that are related.
The magnitude and direction of the acceleration are given by the resultant force on the body, in many cases the resultant force is constant in various time intervals, therefore the is acceleration is constant in these intervals even though it may have a different value in each one.
The velocity of the body is defined by the change in position of the body in the unit of time, in the most common case of a system with constant acceleration the velocity is given by
\(v_f\) = v₀ + a t
where v₀ and \(v_{f}\) are the initial and final velocities of the body, a is the acceleration and t is a time scalar: the bold letters indicate vectors.
If the velocity has a direction and the acceleration is contrary to the equation, we can see that the final velocity must decrease as time advances. Therefore the correct statement is: O An initial velocity that is faster than a final velocity.
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A man whose mass is 69 kg and a woman whose mass is 52 kg sit at opposite ends of a canoe 5 m long, whose mass is 20 kg. Suppose that the man moves quickly to the center of the canoe and sits down there. How far does the canoe move in the water
Answer:
the canoe moved 1.2234 m in the water
Explanation:
Given that;
A man whose mass = 69 kg
A woman whose mass = 52 kg
at opposite ends of a canoe 5 m long, whose mass is 20 kg
now let;
x1 = position of the man
x2 = position of canoe
x3 = position of the woman
Now,
Centre of mass = [m1x1 + m2x2 + m3x3] / m1 + m2 + m3
= ( 69×0 ) + ( 52×5) + ( 20× 5/2) / 69 + 52 + 20
= (0 + 260 + 50 ) / ( 141 )
= 310 / 141
= 2.19858 m
Centre of mass is 2.19858 m
Now, New center of mass will be;
52 × 2.5 / ( 69 + 52 + 20 )
= 130 / 141
= 0.9219858 m { away from the man }
To get how far, the canoe moved;
⇒ 2.5 + 0.9219858 - 2.19858
= 1.2234 m
Therefore, the canoe moved 1.2234 m in the water
The canoe move in the water will be 1.2234 m. The canoe move depending on the center of mass of the bodies.
What is the center of mass?The center of mass of an item or set of objects is a place specified relative to it. It's the average location of all the system's components, weighted by their mass.
The centroid is the location of the center of mass for simple rigid objects with homogeneous density. The center of mass of a uniform disc shape, for example, would be at its center.
The given data in the problem is;
m₁ is the mass of man = 69 kg
m₂ is the mass of woman whose= 52 kg
m₃ is the mass of canoe = 20 kg
L is the length of canoe = 5 m
x₁ is the position of the man
x₂ is the position of the canoe
x₃ is the position of the woman
The center of mass will be;
\(\rm COM= \frac{[m_1x_1 + m_2x_2 + m_3x_3]}{ m1 + m2 + m3} \\\\ \rm COM= \frac{[69 \times 0 +52 \times 5 + 20 \times 2.5]}{ 69+ 52 + 20} \\\\ \rm COM= (0 + 260 + 50 ) / ( 141 )\\\\ \rm COM = 310 / 141 \\\\ \rm COM = 2.19858 m\)
The new center of mass is;
\(\rm COM= \frac{52 \times 2.5 }{69+52+20} \\\\ \rm COM=\frac{130}{141} \\\\ \rm COM= 0.9219 m\)
The distance to find how the canoe moved will be found by;
\(\rm x= 2.5+0.9219-2.1985 = 1.2234\)
Hence the canoe move in the water will be 1.2234 m.
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How much POWER is used in 30 seconds when you complete 150 Joules of work?
Answer:
Power of 5 watts is used
Explanation:
Mechanical Work and Power
Mechanical work is the amount of energy transferred by a force.
Being F the force vector and s the displacement vector, the work is calculated as:
\(W=\vec F\cdot \vec s\)
If both the force and displacement are parallel, then we can use the equivalent scalar formula:
W=F.s
Power is the amount of energy converted per unit of time. The SI unit of power is the watt, equal to one joule per second.
The power can be calculated as:
\(\displaystyle P=\frac {W}{t}\)
Where W is the work and t is the time.
It's required to calculate the power used in t=30 seconds when W=150 Joules of work are completed. Substitute in the formula:
\(\displaystyle P=\frac {150}{30}\)
P = 5 Watt
Power of 5 watts is used
A football shrinks slightly when taken outside on a winter's day.
Answer:the molecules in the football move slower causing them to get closer together and take up less space, which causes the volume to decrease and allows the football to shrink.
Explanation:
During a certain nuclear reaction the total mass of the products is less than the total mass of reactants what happened to the missing mass
Answer: it turns into energy
Explanation: In a nuclear fusion reaction, two reactants combine, and form new products. But the mass of the products is less than total mass of the reactants. This is because a part of mass is lost as energy. This can be seen in an example shown below. You can see that mass is of the products is less than that of the reactants.
Hope This Helps :)
7. Particle A (mass = m, charge = Q) and B (mass = m, charge = 5 Q) are released from rest with the distance between them equal to 1.0 m. If Q = 12 C, what is the kinetic energy of particle B at the instant when the particles are 3.0 m apart?
Ans: 4.32J
The kinetic energy of particle B at the instant when the particles are 3.0 m apart is 4.32 J.
How to determine kinetic energy?The total energy of the system is conserved. The initial energy of the system is the electrostatic potential energy, which is given by:
U = k × (Q₁ × Q₂) / r
where:
U = potential energy in joules
k = Coulomb's constant (8.988 x 10⁹ N m²/C²)
Q₁ and Q₂ = charges in coulombs
r = distance between the charges in meters
In this case:
U = 8.988 x 10⁹ N m²/C² × (12 C × 5 Q) / (1.0 m) = 5.375 x 10⁻⁷ J
The final energy of the system is the kinetic energy of particle B. The kinetic energy is given by:
KE = 1/2 × m × v²
where:
KE = kinetic energy in joules
m = mass in kilograms
v = velocity in meters per second
Solve for the velocity of particle B using the conservation of energy equation:
KE = U
Substituting the expressions for KE and U gives:
1/2 × m × v² = 5.375 x 10⁻⁷ J
Solving for v gives:
v = √(2 × 5.375 x 10⁻⁷ J / m)
= 1.53 m/s
The kinetic energy of particle B is then:
KE = 1/2 × m × v²
= 1/2 × m × (1.53 m/s)²
= 4.32 J
Therefore, the kinetic energy of particle B at the instant when the particles are 3.0 m apart is 4.32 J.
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14. A 5.00 kg ball hits a 75.0 kg man standing at rest on ice. The man catches the ball
How fast does the ball need to be moving in order to send the man off at a speed of
3.00 m/s?
Answer:
V₁ = 48 m/s
Explanation:
Using the Conservative Law of Momentum:
∑Qₓ = 0
Q₁ + Q₂ = 0
Q₁ = Q₂ (In absolute values)
Where:
Q₁: right before the impact
Q₂: right after the impact
So:
Q₁ = Q₂
m₁*V₁ + m₂*V₂ = m₁*V + m₂*V (Because both ball and man moves together)
5 * V₁ + 75 * 0 = (5 + 75)*3
5V₁ = 80 * 3
V₁ = 240/5
V₁ = 48 m/s
Help me with the writing i really need help !!
Answer:
i really dont know im so sorry i wish i could help u out my friend
A box with a mass of 6.25kg is sliding along a horizontal surface at constant velocity. It is pulled by a horizontal force, and the coefficient of kinetic friction between the box and the surface is 0.431. What is the work done, in joules, by the force of friction on the box as the box moves a distance of 0.497m?
The work done, by the force of friction on the box as the box moves a distance is 13.12 J.
What is work done by the force of friction?
The work done by force of friction is calculated from the product of force of friction and distance through which the object travelled and it is given as;
W = Fₙd
where;
Fₙ is the force of frictiond is the distance travelled by the objectW = μmg x d
Where;
μ is coefficient of kinetic frictionm is mass of the boxg is acceleration due to gravityd is the distance travelledW = 0.431 x 6.25 x 9.8 x 0.497
W = 13.12 J
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A parachutist of mass 56.0 kg jumps out of a balloon at a height of 1400 m and lands on the ground with a speed of 5.60 m/s. How much energy was lost to air friction during this jump?
kJ
process and answer please
Answer:
Efriction = 768.23 [kJ]
Explanation:
In order to solve this problem we must use the principle of energy conservation. Where it tells us that the energy of a system plus the work applied or performed by that system, will be equal to the energy in the final state. We have two states the initial at the time of the balloon jump and the final state when the parachutist lands.
We must identify the types of energy in each state, in the initial state there is only potential energy, since the reference level is in the ground, at the reference point the potential energy is zero. At the time of landing the parachutist will only have potential energy, since it reaches the reference level.
The friction force acts in the opposite direction to the movement, therefore it will have a negative sign.
\(E_{pot}-E_{friction}=E_{kin}\)
where:
\(E_{pot}=m*g*h\\E_{kin}=\frac{1}{2}*m*v^{2}\)
m = mass = 56 [kg]
h = elevation = 1400 [m]
v = velocity = 5.6 [m/s]
\((56*9.81*1400)-E_{friction}=\frac{1}{2}*56*(5.6)^{2}\\769104 -E_{friction}= 878.08 \\E_{friction}=769104-878.08\\E_{friction}=768226[J] = 768.23 [kJ]\)
According to the principal of superposition,
Answer:
the resultant wave is the algebraic sum of all the waves reaching that particular point at a given time.
Explanation:
imagine two or three waves reaching a particular particle x at the same time. The particle will vibrate those waves and give out or transmit a resultant wave which is the algebraic sum of the incoming two waves. If both the waves have the same amplitude and phase, the resultant wave will be amplified. However if the waves have the same amplitude and equal but opposite phase then the resultant wave will be a straight line
What kind of wave interactions is caused by a change in the speed of the wave
Answer:Refraction
Explanation:
or the bending of the path of the waves, is accompanied by a change in speed and wavelength of the waves.
Light of wavelength 656 nm and 410 nm emitted from a hot gas of hydrogen atoms strikes a grating with 5300 lines per centimeter. a) Determine the angular deflection of both wavelengths in the 1st and 2nd order.
Answer:
\(20.32^{\circ}\) and \(44.08^{\circ}\)
\(12.56^{\circ}\) and \(25.77^{\circ}\)
Explanation:
\(\lambda\) = Wavelength
\(\theta\) = Angle
m = Order
Distance between grating is given by
\(d=\dfrac{1}{5300}\\\Rightarrow d=0.0001886\ \text{cm}\)
\(\lambda=656\ \text{nm}\)
We have the relation
\(d\sin\theta=m\lambda\\\Rightarrow \theta=\sin^{-1}\dfrac{m\lambda}{d}\)
m = 1
\(\theta=\sin^{-1}\dfrac{1\times 656\times 10^{-9}}{0.0001886\times 10^{-2}}\\\Rightarrow \theta=20.35^{\circ}\)
m = 2
\(\theta=\sin^{-1}\dfrac{2\times 656\times 10^{-9}}{0.0001886\times 10^{-2}}\\\Rightarrow \theta=44.08^{\circ}\)
The first and second order angular deflection is \(20.32^{\circ}\) and \(44.08^{\circ}\)
\(\lambda=410\ \text{nm}\)
m = 1
\(\theta=\sin^{-1}\dfrac{1\times 410\times 10^{-9}}{0.0001886\times 10^{-2}}\\\Rightarrow \theta=12.56^{\circ}\)
m = 2
\(\theta=\sin^{-1}\dfrac{2\times 410\times 10^{-9}}{0.0001886\times 10^{-2}}\\\Rightarrow \theta=25.77^{\circ}\)
The first and second order angular deflection is \(12.56^{\circ}\) and \(25.77^{\circ}\).
Baseball A and B have masses 250g and 300g respectively.
Both are hit by the same amount of force equal to 100 N(Newton).
Which of the two baseballs has greater acceleration?
The baseball with the greater acceleration is baseball A
Relationship between force and accelerationForce and acceleration are related according to the following formula:
Force (F) = mass (m) × acceleration (a)
F = ma
How to determine the acceleration of baseball AForce (F) = 100 NMass of A (m) = 250 g = 250 / 100 = 0.25 KgAcceleration of A (a) =?F = ma
Divide both sides by m
a = F / m
a = 100 / 0.25
Acceleration of A = 400 m/s²
How to determine the acceleration of baseball BForce (F) = 100 NMass of A (m) = 300 g = 300 / 100 = 0.3 KgAcceleration of B (a) =?F = ma
Divide both sides by m
a = F / m
a = 100 / 0.3
Acceleration of B = 333.33 m/s²
From the above calculations, we obtained:
Acceleration of A = 400 m/s²Acceleration of B = 333.33 m/s²Thus, baseball A has the greater acceleration
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How would I solve for KE with only mass no velocity?
Answer:
K.E = (p)^2 / 2m
Explanation:
the first method is : K.E = (p)^2 / 2m where p is the momentum of the object. so here u should be given the momentum and the mass of the object.
A sample of vegetable oil with density 913 kg/m3 is found to have a mass of 0.0365 kg. Find the volume of this sample
The volume of the vegetable oil is 0.00003998 m³.
The density of vegetable oil,
ρ = 913 kg/m³
The mass of vegetable oil,
m = 0.0365 kg
To find: The volume of the vegetable oil, V Solution: The density of any substance is defined as the mass of the substance per unit volume.
The formula for density is:
ρ = m/V
where, ρ is the density of the substancem is the mass of the substance V is the volume of the substance We can rearrange the above formula to find the volume of the substance:
V = m/ρSubstituting the given values of mass and density in the above formula,
We get:
V = 0.0365 kg / 913 kg/m³ = 0.00003998 m³ (approx)
Therefore, the volume of the vegetable oil is approximately 0.00003998 m³.
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prepare a report on why a vehicle needs to be maintained/serviced after a certain period of time. How is servicing different in a petrol/diesel and electric vehicle?
Vehicles need to be serviced for several reasons such as preventing costly repairs and improving fuel economy.
Why should cars be maintained and / or serviced ?First, regular maintenance can help to prevent costly repairs down the road. Second, maintenance can help to improve fuel economy and emissions. Third, maintenance can help to keep your vehicle safe and reliable.
The servicing requirements for petrol/diesel and electric vehicles differ in a number of ways. Petrol/diesel vehicles require oil changes more frequently than electric vehicles. This is because petrol/diesel engines use oil to lubricate the moving parts, while electric motors do not. Petrol/diesel vehicles also require tune-ups more frequently than electric vehicles.
This is because petrol/diesel engines have more moving parts that need to be synchronized, while electric motors have fewer moving parts.
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A falling object with a mass of 2.55 kg encounters 4.0 N of air resistance. What is the acceleration of the object? (Choose up to be the positive direction, and remember the definition of weight).
The acceleration of the falling object with a mass of 2.55 kg that encounters 4.0 N of air resistance is 1.57m/s².
How to calculate acceleration?Acceleration is change of velocity with respect to time (can include deceleration or changing direction).
The acceleration of a body can be calculated by using the following expression;
a = F/m
Where;
a = acceleration (m/s²)F = force (N)m = mass (kg)According to this question, a mass of 2.55 kg encounters 4.0 N of air resistance. The acceleration of the object can be calculated as follows:
a = 4N ÷ 2.55kg
a = 1.57m/s²
Therefore, 1.57m/s² is the acceleration of the object.
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What variables affect the gravitational force between two objects? Select 2 choices.
A
mass
B
speed
C
distance between them
D
volume
E
air pressure
HELP ME ASAPPPPPPPPPPP
A penny sinks to the bottom of a wishing well
What type of frictional force is that?
The frictional force involved when a penny sinks to the bottom of a wishing well is primarily due to viscous drag or fluid friction. As the penny moves through the water, it experiences resistance from the surrounding fluid. This resistance is caused by the frictional forces between the water molecules and the penny's surface.