3. a cone has surface area in2 and volume in3. the cone is dilated, and the surface area of the dilated cone is in2. what is the dilated cone's volume?

Answer:

hmmmm

Explanation:

Thermodynamics can be said to be a branch of Physics which involves the transfer of heat and other energy forms.

Thermal energy is the energy possesed by a system due to its temperature.

In thermodynamics, during the transfer of thermal energy, energy is wasted due to entryopy. And entropy is the measure of disorder of a system.

Therefore, in amy thermodynamic system that deals with the transfer of thermal energy, the most ideal state for that system is Entropy

ANSWER:

A. Entropy

The distance between the two charges is 3.12 m.

The distance between the two charges is determined by applying Coulomb's law of electrostatic force.

F = kq₁q₂ / r²

where;

The distance between the two charges is calculated as;

r² = kq₁q₂  / F

r = √ ( kq₁q₂  / F )

r = √ ( 9 x 10⁹ x 40 x 10⁻⁶ x 108 x 10⁻⁶ / 4 )

r = 3.12 m

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Answer: Any particle, whether an atom, molecule or ion, that contains less electrons than protons is said to be positively charged. Conversely, any particle that contains more electrons than protons is said to be negatively charged.

Explanation: If there are more electrons than protons in a piece of matter, it will have a negative charge, if there are fewer it will have a positive charge, and if there are equal numbers it will be neutral.

The wavefunction number for the specified function is:Ψ(x) = \([2/(\alpha (1 - e^{(-4nm/\alpha )))}]e^{(-x/\alpha )}\)

The wavefunction given is:

Ψ(x) = A\(e^{(-x/\alpha )}\)

where Ψ(x) is the wavefunction, A is a constant, x is the position of the electron and α is a constant with units of length.

The normalization condition is:

∫|Ψ(x)|² dx = 1

Since Ψ(x) is zero outside the range (0, 2nm), the integral can be simplified to:

∫\(0^(2nm)|Ae^{(-x/\alpha )}|\) ²dx = 1

Simplifying the integral further:

\(|A|^{2} (-\alpha /2) (e^{(-4nm/\alpha ) - 1)} = 1\)

Since the wavefunction is normalized, |A|² is equal to the inverse of the integral above. Solving for |A|², we get:

|A|² = \([-2/(\alpha (e^{(-4nm/α) - 1))}]\)

Thus, the wavefunction is:

Ψ(x) = \([2/(\alpha (1 - e^{(-4nm/\alpha )))}]e^{(-x/\alpha )}\)

So, the value of the wavefunction for this given function is:

\([2/(\alpha (1 - e^{(-4nm/\alpha )))}]e^{(-x/\alpha )}\)

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Answer:

24° north of east

Explanation:

tan(x)=90/200 ie x=arctan(90/200)=24°

So the plane took off 24° east.

Answer:

24° north of east

Explanation:

Hope this will help

0.77 m/s2 directed 35° south of west

net force = (-17,-12)

net force = mass * acceleration

(-17,-12) = 27 * (x-acceleration,y-acceleration)

(x-acceleration,y-acceleration) = (-17/27,-12/27) = (-0.629629629..., -0.444...)

angle of acceleration = tan^-1 (-0.444.../-0.629629...) = 35.21759 degrees below negative x-axis.

magnitude of acceleration = sqrt((-0.629629...)^2 + (-0.444...)^2) = 0.77069 (5dp)

Gravity depends on the mass of objects and distance.

The more mass the more gravitational force, the more distance between two objects the less gravitational force.

The angular momentum of the satellite remains constant at the labeled locations (A, B, C, D).

How do quantities change in orbit?

Let's analyze the quantities that remain constant at the labeled locations (A, B, C, D):

A. The tidal force on the satellite: This force depends on the gravitational gradient and the satellite's position relative to the primary. Since the position changes along the elliptical orbit, the tidal force is not constant. Therefore, it does not remain constant at any labeled location.

B. The kinetic energy of the satellite: The kinetic energy of the satellite changes as it moves along its elliptical orbit. It is highest at the perigee (closest point to the primary) and lowest at the apogee (farthest point from the primary). Therefore, it does not remain constant at any labeled location.

C. The mechanical energy of the satellite: The mechanical energy of the satellite is the sum of its kinetic energy and gravitational potential energy. Since both of these quantities change along the elliptical orbit, the mechanical energy is not constant at any labeled location.

D. The work done by the force of gravitational attraction on the satellite: The work done by the force of gravitational attraction is given by the change in gravitational potential energy. As the satellite moves along its elliptical orbit, the distance from the primary changes, causing the gravitational potential energy to vary.

Therefore, the work done by the force of gravitational attraction is not constant at any labeled location.

E. The angular momentum of the satellite: The angular momentum of the satellite remains constant throughout its motion if no external torques act upon it. This is known as the conservation of angular momentum. Therefore, the angular momentum remains constant at all labeled locations (A, B, C, D).

F. The gravitational potential energy of the satellite: The gravitational potential energy of the satellite changes as it moves along its elliptical orbit. It is highest at the apogee and lowest at the perigee. Therefore, it does not remain constant at any labeled location.

In summary, the quantities that remain constant at the labeled locations (A, B, C, D) are:

The angular momentum of the satellite.

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According to Fleming's left-hand rule, the direction of the force is parallel to the directions of the magnetic field and current.

Here, the current is flowing upward while the magnetic field is to the right (opposite to the flow of electron). When a charge particle moves through the magnetic field, a force known as the magnetic force is exerted on the charge particle. The magnetic force acts perpendicular to the velocity at every time when a charged particle moves perpendicular to a uniform magnetic field, causing the particle to proceed on a circular path with a constant velocity v. As a result, although the direction of the velocity changes, its magnitude does not.

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The work done by the elevator motor to lift the elevator is given by:

W = mgh

where m is the mass of the elevator, g is the acceleration due to gravity, and h is the height the elevator is lifted.

Plugging in the given values, we get:

W = (1300 kg) x (9.81 \(m/s^2\)) x (200 m) = 2.54 x \(10^6 J\)

Therefore, the elevator motor does 2.54 x \(10^6\) Joules of work to lift the 1300 kg elevator a height of 200 m.

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(A) The electric field midway between two charges are \(-2.5*10^{7} N/C\). (B) The electric field at the point x = -2.5nm, y = 0, is \(-3.38*10^{7} N/C\). (C)  The electric field at the point x = -20nm , y = 0, is  \(-8.6*10^{6} N/C\).

A) The electric field midway between the two charges is given by \(E=(kq_{1}q_{2} )/r^{2}\), where k is the Coulomb's constant \((8.99*10^{9} Nm^{2} /C^{2})\)

\(q_{1}\) is the charge on the electron \((-1.6*10^{-19} C)\)

\(q_{2}\) is the charge on the proton \((-1.6*10^{-19} C)\) and

r is the distance between them (1.4nm).

Therefore, the electric field midway between the two charges is \(E_{x} , E_{y} = (8.99*10^{9} *1.6*10^{-19} *(-1.6*10^{-19} )/(1.4*10^{-9} )^{2} = -2.5*10^{7} N/C\)

B) The electric field at the point x = -2.5nm, y = 0 can be found by applying the same formula, with r now being the distance between the point and each charge, i.e. \(r_{1}\) = 2.2nm and \(r_{2}\) = 4.2nm.

Therefore, the electric field at this point is \(E_{x}, E_{y}\)

\(=(8.99*10^{9} *1.6*10^{-19} *(-1.6*10^{-19} ))/(2.2*10^{-9})^{2} + (8.9*10^{9} *1.6*10^{-19} * (-1.6*10^{-19} ))/(4.2*10^{-9})^{2}\)

= \(-3.3*10^{7} N/C\)

C) The electric field at the point x = -20nm, y = 0 can be found by applying the same formula, with r now being the distance between the point and each charge, i.e. \(r_{1}\)= 21.4nm and \(r_{2}\) = 19.4nm.

Therefore, the electric field at this point is \(E_{x}, E_{y}\) =

\(=(8.99*10^{9} *1.6*10^{-19} *(-1.6*10^{-19} ))/(21.4*10^{-9} )^{2} +(8.99*10^{9} *1.6*10^{-19} *(-1.6*10^{-19} ))/(19.4*10^{-9} )^{2}\)

\(=-8.6*10^{6} N/C\)

Therefore, the electric field in each of the given points can be calculated using the formula for the electric field of a dipole, which is

\(E=(kq_{1} q_{2} )/r_{2}\)

where k is the Coulomb's constant \((8.99*10^{9} Nm^{2} /C^{2})\)

\(q_{1}\) is the charge on the electron \((-1.6*10^{-19} C)\)

\(q_{2}\) is the charge on the proton \((-1.6*10^{-19} C)\) and

r is the distance between them.

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The two protostars form at the same time, the 10MSun star will end its main-sequence life before the 0.5MSun star even completes its protostar stage, and 10MSun will be much more luminous than the 0.5MSun protostar. Thus, options C and E are correct.

More massive stars have shorter lifetimes because they burn through their nuclear fuel more quickly.

Therefore, the 10MSun star will end its main-sequence life before the 0.5MSun star even completes its protostar stage. Thus, option C is correct.

The luminosity of a star depends on its mass.

More massive stars have higher luminosities than less massive stars. Therefore, option E is correct.

Thus, options C and E are correct.

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The power of the transmitter and receiver and the height of the broadcast and receiving antennas determine the Distance a radio signal will travel.

A sinusoidal voltage at 147.5 MHz is applied by the transmitter to the dipole antenna that serves as its antenna. With a matching oscillating magnetic field perpendicular to the antenna, this creates an oscillating electric field across the antenna. These travel as one electromagnetic wave, or radio wave, from the antenna.

With the oscillating magnetic field perpendicular to the antenna axis and the oscillating electric field parallel to it, this wave propagates in all directions in a plane that passes through the transmitter's antenna's center. It moves at the speed of light, and as was previously mentioned, its wavelength and oscillation frequency are connected by the formula = c/v.

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The magnitude of the torque that will bring the balls to a halt in 4.0 s is 2.9425 Nm, counterclockwise.

To solve this problem, we need to use the principle of conservation of angular momentum. The angular momentum of the system before the torque is applied is equal to the angular momentum after the torque is applied.

The angular momentum of a rigid body rotating about an axis is given by the formula:

L = Iω

where;

The moment of inertia of a system of particles is given by the formula:

I = Σmr²

where;

The angular velocity is related to the rotational speed by the formula:

ω = 2πn

where;

Given the mass and length of the rod, we can calculate the moment of inertia of the system as follows:

I = m1r1² + m2r2²

Therefore, we can use the formula for the moment of inertia of a rod about its center:

I = (1/12)ml²

I = (1/12)(6 kg)(3.0 m)² = 4.5 kg m²

The angular velocity is given as 25 rpm, which is equivalent to 2.617 rad/s.

Therefore, the initial angular momentum of the system is:

L = Iω = (4.5 kg m²)(2.617 rad/s) = 11.77 kg m²/s

To bring the system to a halt in 4.0 s, we need to apply a torque that will reduce the angular velocity to zero in that time. The magnitude of the torque is given by the formula:

τ = ΔL/Δt

where;

Since the final angular momentum is zero, the change in angular momentum is equal to the initial angular momentum. Therefore:

ΔL = -11.77 kg m²/s

Δt = 4.0 s

Substituting these values, we get:

τ = (-11.77 kg m²/s) / (4.0 s) = -2.9425 Nm

Since torque is a vector quantity, we should specify the direction of the torque. Since the system is rotating clockwise, the torque should be applied counterclockwise.

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A spring of force constant 120 N/m acted up by a constant force of 240N. Then, the elastic potential energy stored in the spring is 240 Nm.

The elastic potential energy stored in the spring is formulated as follows

                                                 PE = ½kx²

Where PE is the elastic potential energy, x is the displacement of the spring from its equilibrium position, and k is the spring force constant.

In this question, the spring force constant is 120 N/m, and the constant force acting on the spring is 240 N. To find the spring displacement, we can use the formula:

F = kx

Where F is the force acting on the spring, x is the displacement, and k is the force constant,

So that:

F = kx

240 N = 120 N/m . x

x = 240 N/120 N/m

x = 2 m

Once x is known, then we can calculate the potential energy of the spring:

PE = ½kx²

PE = ½ (120) (2²)

PE = 60 x 40

PE = 240 Nm

So, the elastic potential energy stored in the spring is 240 Nm.

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A decigram is a unit of weight measurement that is equivalent to one-tenth of a gram or 100 milligrams.

Therefore, a decigram is ten times more in weight than a milligram. This means that if an object weighs one milligram, it will weigh ten decigrams if the weight is converted to decigrams. The use of these units of measurement is essential in various fields such as medicine, chemistry, and physics, where accurate and precise weight measurements are necessary.

Understanding the relationship between different units of measurement is vital in converting and calculating weight measurements. It is important to note that proper conversion of units of measurement is crucial in ensuring accurate and consistent results in scientific experiments, laboratory work, and medication dosages.

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When a volume of air expands against the environment and no heat enters or leaves, the air temperature will decrease - TRUE.

When a volume of air expands, it does work against the environment. The work done is extracted from the internal energy of the gas. In an adiabatic process, no heat is exchanged with the surroundings, so the internal energy of the gas decreases, which causes a decrease in temperature. This happens because the kinetic energy of the gas molecules decreases as the gas expands. As the temperature is a measure of the average kinetic energy of the molecules, the temperature also decreases. This phenomenon is described by the ideal gas law, which relates the pressure, volume, and temperature of an ideal gas. Specifically, the law states that when the volume of a gas increases at constant pressure, its temperature decreases. This is known as adiabatic cooling and is responsible for the formation of clouds in the atmosphere.

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I am not sure of this, but it is either the third option or the last option.

The correct options are (a) and (c) .Increasing the average speed of gas molecules in a closed rigid container will result in an increase in the gas pressure and a decrease in its density. This is due to the increased frequency and force of molecular collisions.

If the average speed of the gas molecules in a closed rigid container is increased, it will have several effects on the gas properties. The gas will first become less dense.

This is because the increased speed of the molecules will cause them to spread out more, resulting in a decrease in the number of molecules per unit volume.

Second, the pressure of the gas will increase. The increased speed of the molecules will result in more frequent and forceful collisions with the walls of the container, leading to an increase in the overall pressure exerted by the gas.

Third, the temperature of the gas will increase. The increase in average speed of the molecules is directly related to an increase in kinetic energy, which is a measure of temperature.

Therefore, as the speed of the molecules increases, the temperature of the gas will also increase.

In conclusion, if the average speed of gas molecules in a closed, rigid container increases, the density of the gas decreases, the pressure of the gas rises, and the temperature of the gas rises.

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Work done is given by the change in kinetic energy of an object

Reason:

Work is done when the total energy of object is affected by the application of force on the object over a distance

Therefore;

Therefore, work is done in the given processes

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The high pressure exerted by the water hitting the driveway while cleaning it with a garden hose is considered dynamic pressure, as it is a result of the fluid's motion.

When cleaning a driveway with a garden hose, the water hitting the driveway has a high dynamic pressure. Dynamic pressure refers to the pressure exerted by a fluid in motion. In this scenario, as water is being expelled from the garden hose and directed towards the driveway, it possesses kinetic energy, causing it to move and collide with the surface. The force exerted by the moving water onto the driveway creates dynamic pressure.

Hydrostatic pressure, on the other hand, refers to the pressure exerted by a fluid at rest due to the force of gravity. This type of pressure is not applicable in the given scenario because the water is in motion rather than being at rest.

Static pressure refers to the pressure exerted by a fluid that is at rest or in equilibrium. It is determined by the weight of the fluid and the depth at which it is located. Since the water from the garden hose is in motion and not at rest, static pressure is not relevant in this context.

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Answer:

afrcrftftgyfygygygygygygyvyvuguvy5vyvycycy

shdhdggxshjwhwywsd dccefc

Answer:

the third one

Explanation:

she is using a card instead of paper

Answer:

To find the resulting velocity when the two asteroids stick together, we can use the principle of conservation of momentum.

The initial momentum of the first asteroid before the collision is given by the product of its mass (m1) and its velocity (v1):

Initial momentum of asteroid 1 = m1 * v1

Since the second asteroid is stationary, its initial momentum is zero.

After the collision, the two asteroids stick together and move with a common velocity (v2). The total mass of the system after the collision is the sum of the masses of the two asteroids (m1 + m2).

According to the conservation of momentum, the initial momentum of the system is equal to the final momentum of the system:

Initial momentum = Final momentum

m1 * v1 + 0 = (m1 + m2) * v2

Given:

m1 = m2 = 4723 kg

v1 = initial velocity of the first asteroid (unknown)

v2 = final velocity of the combined asteroids (unknown)

We can substitute these values into the equation and solve for v2:

4723 kg * v1 + 0 = (4723 kg + 4723 kg) * v2

4723 kg * v1 = 9446 kg * v2

Dividing both sides by 9446 kg:

v1 = 2 * v2

Therefore, the initial velocity of the first asteroid (v1) is twice the final velocity of the combined asteroids (v2).

Since the initial velocity of the first asteroid is not given, we cannot determine the resulting velocity (v2) without additional information.

The momentum flow rate through the pipe carrying liquid ammonia is 1 × \(10^6\) kg·m/s.

The flow rate of momentum (Ṁ) through the pipe can be calculated by multiplying the mass flow rate (ṁ) by the velocity (v). The speed can be determined using the equation v = ṁ / (ρA), where ρ is the density of the liquid ammonia and A is the pipe's cross-sectional area.

Given:

ṁ = 100 kg/s

A = 0.01 m²

Assuming the density (ρ) of liquid ammonia is 700 kg/m³, we can calculate the velocity (v):

v = ṁ / (ρA)

v = 100 kg/s / (700 kg/m³ × 0.01 m²)

v = 10000 m/s

Now, we can calculate the flow rate of momentum (Ṁ):

Ṁ = ṁv

Ṁ = 100 kg/s × 10000 m/s

Ṁ = 1 × \(10^6\) kg·m/s

Therefore, the momentum flow rate through the pipe is 1 × \(10^6\) kg·m/s.

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Answer: Yes, because the force of air resistance must be equal to the force of gravity, since the ball is not accelerating (constant velocity). Since the net forces acting on the object is zero, the object is in translational equilibrium.

No, a ball falling with constant velocity is not in translational equilibrium.

Translational equilibrium means that the net force acting on an object is zero, and this is not the case for a ball falling with constant velocity. Gravity is still acting on the ball, so there is a force pulling it downwards. However, the ball is moving at a constant velocity because the force of gravity is balanced by the force of air resistance. So, while the ball is not in translational equilibrium, it is in a state of dynamic equilibrium where the forces acting on it are balanced, resulting in a constant velocity.

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Answer:

The answer should be C. some mass was consumed in the reaction

A powder and a liquid with a total mass of 20 grams are combined in an open beaker, then the best explanation for the difference in mass is that some mass was consumed in the reaction. Hence, option C is correct.

A chemical reaction is the process by which any or more compounds, known as reagents, change into one or more new ones, known as products. Active ingredients or compounds make up substances. The atoms that make up the reactants are reorganized in a chemical reaction to create various products.

Technology, society, and even life itself depend on chemical interactions in one way or the other and. Chemical reactions have been recognized and employed for thousands of years in a wide variety of activities, including burning fuels, smelting iron, creating pottery and pottery, brewing beer, making wine, and manufacturing cheese. There are countless examples of complicated chemical reactions in all living systems, as well as in the Earth's geology, atmosphere, and oceans.

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