3) Calculate the kinetic energy of a 7 kg mass traveling at a velocity of 4 m/sec.
Formula
Work with Units
Answer with Units

Answers

Answer 1

\(▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪\)

Let's solve ~

Given terms :

Mass (m) = 7 kg

velocity (v)= 4 m/s

The formula to find kinetic Energy is ~

\( \boxed{ \boxed{ \sf{ \frac{1}{2} m{v}^{2} }}} \)

Now, apply the formula according to given situation

\({ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \: \dfrac{1}{2} \times 7 \times ( {4)}^{2} \)

\({ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \: \dfrac{1}{2} \times 7 \times 16\)

\({ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:7 \times 8\)

\({ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:56 \: \: joules\)

Therefore, the kinetic Energy of the car is 56 joules

Answer 2

Answer:

56 J

Explanation:

Formula to find the kinetic energy is :

\(E_k\) = \(\frac{1}{2} \)  × m × v²

Here ,

m ⇒ mass

v ⇒  velocity

Let us solve now

 \(E_k\) = \(\frac{1}{2} \) × m × v²

     = \(\frac{1}{2} \) × 7 kg × ( 4 ms⁻¹ )²

     = \(\frac{1}{2} \) × 7 × 16

     = \(\frac{1}{2} \) × 112

     = 56 J

Hope this helps you :-)

Let me know if you have any other questions :-)


Related Questions

an object has a mass of 4kg and an average acceleration of 10m/s/s what is the force​

Answers

Force = mass x acceleration
Force = 4kg x 10m/s^2
Force = 40N

what is the energy (in j) of a photon required to excite an electron from n = 2 to n = 8 in a he⁺ ion? submit an answer to three signficant figures.

Answers

Answer:

Approximately \(5.11 \times 10^{-19}\; {\rm J}\).

Explanation:

Since the result needs to be accurate to three significant figures, keep at least four significant figures in the calculations.

Look up the Rydberg constant for hydrogen: \(R_{\text{H}} \approx 1.0968\times 10^{7}\; {\rm m^{-1}\).

Look up the speed of light in vacuum: \(c \approx 2.9979 \times 10^{8}\; {\rm m \cdot s^{-1}}\).

Look up Planck's constant: \(h \approx 6.6261 \times 10^{-34}\; {\rm J \cdot s}\).

Apply the Rydberg formula to find the wavelength \(\lambda\) (in vacuum) of the photon in question:

\(\begin{aligned}\frac{1}{\lambda} &= R_{\text{H}} \, \left(\frac{1}{{n_{1}}^{2}} - \frac{1}{{n_{2}}^{2}}\right)\end{aligned}\).

The frequency of that photon would be:

\(\begin{aligned}f &= \frac{c}{\lambda}\end{aligned}\).

Combine this expression with the Rydberg formula to find the frequency of this photon:

\(\begin{aligned}f &= \frac{c}{\lambda} \\ &= c\, \left(\frac{1}{\lambda}\right) \\ &= c\, \left(R_{\text{H}}\, \left(\frac{1}{{n_{1}}^{2}} - \frac{1}{{n_{2}}^{2}}\right)\right) \\ &\approx (2.9979 \times 10^{8}\; {\rm m \cdot s^{-1}}) \\ &\quad \times (1.0968 \times 10^{7}\; {\rm m^{-1}}) \times \left(\frac{1}{2^{2}} - \frac{1}{8^{2}}\right)\\ &\approx 7.7065 \times 10^{14}\; {\rm s^{-1}} \end{aligned}\).

Apply the Einstein-Planck equation to find the energy of this photon:

\(\begin{aligned}E &= h\, f \\ &\approx (6.6261 \times 10^{-34}\; {\rm J \cdot s}) \times (7.7065 \times 10^{14}\; {\rm s^{-1}) \\ &\approx 5.11 \times 10^{-19}\; {\rm J}\end{aligned}\).

(Rounded to three significant figures.)

When astronomers say that the groups of galaxies are distributed isotropically, they mean that?

Answers

When astronomers say that the groups of galaxies are distributed isotropically, they mean that the group of galaxies appears to be similar when viewed through any directions.

Isotropy of galaxies means that the arrangement of galaxies doesn't differ in any directions. That is ,the galaxies are arranged in such a way that it seems same even if viewed from different directions. The word isotropy refers to the lack of preference to the direction.

In Cosmology, the universe is also said to have isotropy and homogeneity. Homogeneity also refers to the uncertainty of location.

In astronomy, the isotropy of galaxies simply means there will be no difference in the galaxies viewed from different directions.  

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if jupiter was about the size of a basketball, which planet(s) would be about the size of a baseball?

Answers

If Jupiter was about the size of a basketball, Venus would be about the size of a baseball.

If Jupiter was about the size of a basketball (approximately 9.4 inches or 24 centimeters in diameter), then a planet about the size of a baseball (approximately 2.9 inches or 7.4 centimeters in diameter) would be roughly 1/3 the diameter of Jupiter.

There are four planets in our solar system that are smaller than Jupiter and roughly 1/3 its diameter: Saturn, Uranus, Neptune, and Venus. Of these, Venus is the closest in size to a baseball, with a diameter of approximately 7,520 miles (12,104 kilometers), making it slightly larger than a baseball but still in the same size range.

So, if Jupiter was the size of a basketball, Venus would be the planet in our solar system that is closest in size to a baseball. Saturn, Uranus, and Neptune would be slightly larger, but still much smaller than Jupiter.

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When studying atoms, scientists can ignore the ______ force between charged particles that make up the atoms because it is many millions of times smaller than other forces in the atom.

Gravitational
Constant
Normal
Fricitional

Answers

Answer:

Gravitational

Explanation:

When studying atoms, scientists can ignore the  gravitational force between charged particles that make up the atoms because it is many millions of times smaller than other forces in the atom.

Answer:

Gravitational

Explanation:

when a battery charges a capacitor what happens to the conduction electrons

Answers

Answer:

When a battery charges a capacitor, the conduction electrons flow from the battery to the plates of the capacitor. As the capacitor becomes charged, the electrons accumulate on the plates, creating a potential difference between the plates. This potential difference causes the flow of electrons to stop once the capacitor is fully charged, and the capacitor can hold a charge.

During the charging process, the voltage across the capacitor increases as more charge accumulates on the plates, while the current decreases as the flow of electrons slows down. When the capacitor is fully charged, the voltage across the capacitor is equal to the voltage of the battery, and the current stops flowing.

In summary, when a battery charges a capacitor, the conduction electrons flow from the battery to the plates of the capacitor, creating a potential difference that charges the capacitor. Once the capacitor is fully charged, the flow of electrons stops.

The conduction electrons in a battery charging a capacitor will flow from the negative terminal of the battery to the positive terminal.

This flow of electrons is known as an electric current. As the electrons move, they transfer energy to the capacitor, which causes the capacitor to become more positively charged. This process of charging continues until the capacitor reaches the same electrical potential as the battery.

Once the capacitor is fully charged, the electrons will no longer flow and the capacitor will remain at the same voltage as the battery.

The conduction electrons have transferred energy from the battery to the capacitor, allowing the capacitor to store electrical energy.

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a 3) How far will 20 N of force stretch a spring with a spring constant of 140 N/m?​

a 3) How far will 20 N of force stretch a spring with a spring constant of 140 N/m?

Answers

Answer:

I think the answer is

Explanation:

140N/m/20N =

7m is the answer

Answer:

140n/20n

=7N

Explanation:

you will divide 140 by 20

Compare and contrast instantaneous and average speed.

Answers

Answer:

instantaneous velocity is a velocity covered at an instant while average velocity is the change in distance/ the change in time taken

Give five important things any physic’s student ahould know?

Answers

Answer:

students need to take courses in math, such as calculus, linear algebra, and statistics. Computer science classes also are essential, because physicists and astronomers often develop specialized computer programs that are used to gather, analyze, and model data.

draw two circuit diagrams showing the correct connection of voltmeter to measure the potential different across a resistor

Answers

In a series circuit, components are connected end-to-end in a single path, so the current flows through each component in turn. And in a parallel circuit, components are connected in multiple paths, so the current can flow through more than one path simultaneously.



1. Series Circuit:
To measure the potential difference across a resistor in a series circuit, follow these steps:

a. Turn off the power source.
b. Connect the positive terminal (red) of the voltmeter to one end of the resistor.
c. Connect the negative terminal (black) of the voltmeter to the other end of the resistor.
d. Turn on the power source.
e. Read the voltmeter to determine the potential difference across the resistor.

2. Parallel Circuit:
To measure the potential difference across a resistor in a parallel circuit, follow these steps:

a. Turn off the power source.
b. Connect the positive terminal (red) of the voltmeter to the node where the resistor is connected to the power source.
c. Connect the negative terminal (black) of the voltmeter to the node where the resistor is connected to the ground or the return path of the circuit.
d. Turn on the power source.
e. Read the voltmeter to determine the potential difference across the resistor.

Remember that the voltmeter should always be connected in parallel with the component (in this case, the resistor) to accurately measure the potential difference.

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Considering that an up quark has a charge of + 2/3 and a down quark has charge of - 1/3, which of the following represents the correct quark combination for a proton? a)2 down, 1 up b)2 up, 1 down c) 0 up, 3 down d)3 down, 3 up

Answers

The correct quark combination for a proton is b) 2 up, 1 down. This is because a proton is made up of three quarks, specifically two up quarks and one down quark. The up quark has a charge of +2/3 and the down quark has a charge of -1/3, which when combined give the overall charge of a proton, which is +1. This combination of quarks is what gives the proton its properties and allows it to interact with other particles in the universe.

A proton has a net charge of +1. In order to achieve this charge, we need to combine the charges of the quarks.
With the combination of 2 up quarks and 1 down quark, we get:
(+2/3) + (+2/3) + (-1/3) = +4/3 - 1/3 = +3/3 = +1

This combination gives us the net charge of +1, which matches the charge of a proton.

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Design your own roller coaster

Design your own roller coaster

Answers

Answer:

roller coaster is very nice to see

would iron and carbon form metallic bonds

Answers

Answer:

NO.

Explanation:

METALLIC BOND IS ONLY IN METALS.

Since iron is a metal and carbon a non- metal, they cannot form a metallic bond.

A process adds 250 J of heat to a gas in a cylinder, and then the gas does 140 J of work on the two circular surfaces of the cylinder. What is the change in internal energy of the gas

Answers

The change in internal energy of the gas can be determined using the first law of thermodynamics, which states that the change in internal energy (ΔU) is equal to the heat added (Q) minus the work done (W) by the gas.



ΔU = Q - W

Given that the heat added is 250 J and the work done is 140 J, we can substitute these values into the equation to find the change in internal energy.

ΔU = 250 J - 140 J

ΔU = 110 J

Therefore, the change in internal energy of the gas is 110 J.

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Select each correct answer. More than one answer may be correct.
Which of the following forces between two objects can be repulsive?
gravitational force
magnetic force
electrostatic force

Answers

Electrostatic force
Not sure if there is any others


A current of 0.4 A flows through a wire. How many electrons flow through a cross section of
the wire in one hour?
(Ans. e = 1.6 x 10-¹9 C
diameter? mm carries a steady current of 0.3142 A. Find the magnitude of

Answers

9 × 10²¹ electrons flow through a cross section of the wire in one hour.

What is the relation between current and charge?Mathematically, current = charge / timeIn S.I. unit, Charge is written in Coulomb and time in second.

What is the amount of charge flown through a wire for one hour if it carries 0.4 A current?Charge= current × timeCurrent= 0.4 A, time = 1 hour= 3600 sCharge= 0.4× 3600

= 1440 C

How many numbers of electrons present in 1440C of charge?One electron= 1.6 × 10^(-19) CSo, 1440 C = 1440/1.6 × 10^(-19)

= 9 × 10²¹ electrons

Thus, we can conclude that the 9 × 10²¹ electrons flow through a cross section of the wire in one hour.

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See screen shot...momentum in collision

See screen shot...momentum in collision

Answers

Please find attached photographs for your answer.

Hope it helps.

Do comment if you have any query.

See screen shot...momentum in collision
See screen shot...momentum in collision

when passing an array byval to a ____ procedure, the original array may be changed by the procedure.

Answers

When passing an array by value to a "reference" procedure, the original array may be changed by the procedure.

In some programming languages, like C++, when an array is passed by value to a procedure that accepts a reference to an array, the procedure can modify the elements of the original array. This is because passing by reference allows the procedure to directly access and modify the memory locations of the original array.

On the other hand, when an array is passed by value to a "value" procedure, the procedure receives a copy of the array, and any modifications made within the procedure do not affect the original array.

Therefore, when passing an array by value to a reference procedure, it is important to be aware that the procedure has the potential to change the original array, while passing by value to a value procedure ensures that the original array remains unchanged.

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Which of the following graphs best illustrates how the intensity of sound varies as a detector is moved further and further from a stationary source projecting sound in all directions

Answers

The graph that best illustrates how the intensity of sound varies as a detector is moved further and further from a stationary source projecting sound in all directions would be an inverse square law graph. This graph would show that the intensity of sound decreases as the distance from the source increases. The intensity of sound is inversely proportional to the square of the distance from the source.

This means that if the distance from the source is doubled, the intensity of sound is decreased by a factor of four. This relationship is commonly observed in physics and engineering and is known as the inverse square law of sound propagation. This law states that the intensity of sound decreases as the distance from the source increases in a manner that is inversely proportional to the square of the distance.

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Which of the following graphs best illustrates how the intensity of sound varies as a detector is moved

The mass of the object is 95kg. What is the coefficient of kinetic frictions

Answers

The coefficient of kinetic friction is approximately 0.102.

What is the  coefficient of kinetic frictions?

The  coefficient of kinetic friction is calculated by using the following formula;

frictional force = coefficient of kinetic friction x normal force

Since the object is not accelerating, we know that the force of gravity pulling down on the object is equal and opposite to the normal force pushing up on the object. Therefore, we can use the formula:

normal force = weight of the object = mass x gravity

where;

the acceleration due to gravity is approximately 9.8 m/s^2.

So, the normal force on the object is:

normal force = 95 kg x 9.8 m/s^2 = 931 N

Now we can substitute the values we have into the formula for coefficient of kinetic friction:

95 N = coefficient of kinetic friction x 931 N

Solving for the coefficient of kinetic friction, we get:

coefficient of kinetic friction = 95 N / 931 N ≈ 0.102

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The complete question is below:

The mass of the object is 95kg. What is the coefficient of kinetic frictions, if the frictional force is 95N.

1. When is the object in motion?​

Answers

Answer:

An object is in motion when its distantance from another object is changing

Answer:

when an object is moving..

Explanation:

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What would the kinetic energy of a 20kg person running at a velocity of 2.5m/s?

Answers

Answer:

62.5 J

Explanation:

The kinetic energy of an object can be found by using the formula

\(k = \frac{1}{2} m {v}^{2} \\ \)

m is the mass in kg

v is the velocity in m/s

From the question

m = 20 kg

v = 2.5 m/s

From the question we have

\(k = \frac{1}{2} \times 20 \times {2.5}^{2} \\ = 10 \times 6.25 \\ = 62.5\: \: \: \: \: \: \: \: \: \: \)

We have the final answer as

62.5 J

Hope this helps you

A soccer ball is kicked upward from a height of 6 ft with an initial velocity of 96 ft/s. How high will it go? Use -32 ft/s? forthe acceleration caused by gravity. Ignore air resistance.

A soccer ball is kicked upward from a height of 6 ft with an initial velocity of 96 ft/s. How high will

Answers

Given,

The initial height of the soccer ball, h₁=6 ft

The initial velocity of the ball, u=96 ft/s

The acceleration due to gravity, g=-32 ft/s

When the ball reaches the maximum height, its velocity will reduce to zero.

Thus the velocity of the ball when it is at its maximum height is v=0 ft/s

From the equation of motion,

\(v^2-u^2=2gh_2\)

Where h₂ is the total height covered by the ball from its initial height to reach its maximum height.

On substituting the known values,

\(\begin{gathered} 0-96^2=2\times-32\times h_2 \\ \Rightarrow h_2=\frac{-96^2}{2\times-32} \\ =144\text{ ft} \end{gathered}\)

Thus the maximum height reached by the ball is,

\(\begin{gathered} H=h_1+h_2 \\ =6+144 \\ =150\text{ ft} \end{gathered}\)

Thus the maximum height reached by the ball is 150 ft.

What occurs when air moves from an area of high pressure to an area of lower pressure

Answers

Air flowing from areas of high pressure to low pressure creates wind.

Mr. Doyle is pulling his friend up a 25. 0° hill in a sled. He is pulling with a force of 676 N at an angle of 30. 0° to the incline. The sled starts from rest and has an acceleration of 1. 24m/s^2. If the normal force is 328. 8 N, what is the mass of the sled? What is the coefficient of friction between the sled and the snow? How fast is the sled moving at the top of a 25. 0 m hill? How long does it take Mr. Doyle to transport his passenger to the top of the hill?

Answers

The mass of the sled is 65.5 kg. The coefficient of friction between the sled and the snow is 0.147. The sled is moving at 10.6 m/s at the top of the hill.

It takes Mr. Doyle approximately 10.6 seconds to transport his passenger to the top of the hill. To find the mass of the sled, we use the equation F_net = m * a, where F_net is the net force acting on the sled, m is the mass of the sled, and a is the acceleration. Rearranging the equation, we have m = F_net / a. Plugging in the values, we get m = 676 N / 1.24 m/s^2 = 545.16 kg. However, since the sled is on an incline, we need to consider the component of the force parallel to the incline, so the mass of the sled is 545.16 kg * sin(25°) = 65.5 kg.

To find the coefficient of friction, we use the equation F_friction = μ * F_normal, where F_friction is the force of friction, μ is the coefficient of friction, and F_normal is the normal force. Rearranging the equation, we have μ = F_friction / F_normal. Plugging in the values, we get μ = 676 N * cos(30°) / 328.8 N = 0.147.

To find the velocity at the top of the hill, we can use the equation v^2 = u^2 + 2as, where v is the final velocity, u is the initial velocity (0 m/s since the sled starts from rest), a is the acceleration, and s is the distance. Rearranging the equation, we have v = sqrt(2as). Plugging in the values, we get v = sqrt(2 * 1.24 m/s^2 * 25.0 m) = 10.6 m/s.

To find the time it takes to transport the passenger to the top of the hill, we can use the equation s = ut + (1/2)at^2, where s is the distance, u is the initial velocity, a is the acceleration, and t is the time. Rearranging the equation, we have t = sqrt(2s/a). Plugging in the values, we get t = sqrt(2 * 25.0 m / 1.24 m/s^2) = 10.6 s.

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A snow boarder weights 300 N. The area of snow border is 0.5 m2. What is pressure on the snow?

Answers

Answer:

600 Pa

Explanation:

see attachment

hope this helps

A snow boarder weights 300 N. The area of snow border is 0.5 m2. What is pressure on the snow?

The voltage drop across R1 is

The voltage drop across R1 is

Answers

Answer:

I think the answer is C/ Tell me If you got it right

Describe the crust (in more than 1 sentence). Include a discussion of how the temperature changes on the crust.

Answers

Solution :

Crust

In the field of geology, the crust may be defined as the outermost solid shell of a planet. It forms the topmost outer hard layer of the earth surface. Earth has three layers. They are the crust, mantle and the core.

When we go deeper and deeper inside the earth's crust, the temperature rise. In the crust, on the surface of the earth, the temperature is normal and is atmospheric. As we go deep down the core, the temperature rise and it is highest at the core where all the rock and the iron is in the form of the molten lava.

According to the Geologist, beneath the earth's crust, for every mile we go inside the temperature rises by 15 degree Fahrenheit.

8.
A microscopic view of a sheet of paper is shown in the diagram at the
right. Would you expect this sheet of paper to cause light to undergo
regular or diffuse reflection?
Explain.
9.
From what type of surface do you think it would be easier to read?
From pages, which are rough, or from pages which are smooth and
glossy?
Explain your answer.
A microscopic view
of a sheet of paper.
10. Driving at night offers a great example of diffuse vs. regular reflection. A dry road is a diffuse
reflector, while a wet road is not. On the diagrams below, sketch the reflected light off a wet and dry
surface.
Dry Surface
Wet Surface
Why would the wet road appear to the driver to be darker than the dry road?
11. The diagram below contrasts the reflection of light off a smooth surface (left) with the reflection of
light off a rough surface (right). Compare the two diagrams and explain why the reflected rays for a
rough surface do not result in the formation of an image.

Answers

Based on the nature of reflection of light from surfaces, smooth surfaces produce regular reflection while rough surfaces produce diffuse reflection.

What is reflection of light waves?

Reflection of light waves refers tobtye bouncing back of light waves when they hit a shiny surface.

Depending on the nature of the surface, reflection of light waves can either be regular if diffuse.

Smooth surfaces produce regular reflection while rough surfaces produce diffuse reflection.

Based on the properties of reflection:

A microscopic view of a sheet of paper shows that the surface is rough, thus it would produce diffuse reflection. Rough pages are easier to read from than smooth and glossy surfaces because they produce diffuse reflection while reading off smooth surface causes a glare due to intense regular reflectionA wet road appears darker because more light passes through and it reflects less light and looks darkerdiffuse reflection do not all pass through the principal focus, thus an image is not formed off a rough surface

Therefore, it can be concluded that the rough surfaces produce diffuse reflection while smooth and glossy surfaces produce regular reflection.

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What is the first step necessary to allow calculation of voltages in a combination circuit containing resistive loads in series and parallel?

Answers

The first step necessary to allow calculation of voltages in a combination circuit containing resistive loads in series and parallel is to simplify the circuit using Ohm's law and Kirchhoff's laws.

This involves identifying the resistors in series and parallel, and then using the appropriate circuit laws to calculate the total resistance of the circuit.

Once the total resistance is calculated, the current flowing through the circuit can be found using Ohm's law.

From there, the voltage drop across each resistor can be calculated using the current and the resistance.

By combining the voltage drops across the resistors, the total voltage of the circuit can be found.

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