3) Draw vectors to represent these motions:

a) moving 3 cm to the right

b) moving 2 cm to the left

Answer:

hes actually kinda hot tho

Explanation:

Answer:

he's a literal daddy  

Explanation:

his parents

\(\\ \rm\longmapsto Distance=Speed(Time)\)

\(\\ \rm\longmapsto Distance=25(2700)\)

\(\\ \rm\longmapsto Distance=67500m\)

The object travelling at 25 m/s, will travel a distance of 67500 m in 45 mins.

1 min = 60 s

Therefore,

45 mins = 45 × 60

Time = 2700

Speed = 25 m/s

Distance = speed × time

Distance = 25 × 2700

Therefore, the object will cover a distance of 67500 m in 2700 s (i.e 45 mins)

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According to the given statement is The pH of the resulting solution is 3.28.

In a neutralization reaction, an acid and a base mix chemically to yield salt and water as the final products. In a neutralization process, water is produced when H+ and OH- ions are combined. In a neutralization reaction, which takes place when an acid and a base combine to generate water and a salt, the interaction of H+ ions and OH- ions results in the production of water. The pH of a strong acid and strong base when they are neutralized by one another is 7.

Final Volume = 41.84 mL + 250 mL = 291 mL

= 291 mL / 1000

= 0.291 L

[HCOO⁻] = 0.029 mol / 0.294 L = 0.098 M

[HCOOH] = 0.086 mol / 0.294 L = 0.292 M

So, the pH should be

= 3.75 + log0.098/0.292

= 3.28

The pH of the resulting solution is 3.28.

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Answer:

I am pretty sure it has 10 kernel electrons!?!?!?

Hope this helps!!!

Have a great day!!! :)

The temperature of the room water and the block will be the same. The energy being transferred from the block to the water is heat energy.

The hot metal block is dropped into another beaker of water having room temperature after being placed in the boiling water. The flow of energy from the higher-temperature matter to the lower-temperature matter is called heat.

Now, the heat is transferred from the metal block to the water which is at room temperature. After some time, the metal block will have a low temperature and the water will have a high temperature.

This process will be carried down until both objects will have the same temperature. It is known as thermal equilibrium. The heat transfer from the hot water to the normal or cold water through a metal block is said to be conduction.

Therefore, the energy that is being transferred from the metal block to the water is heat energy.

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Answer:

Explanation:

Ground state electron configuration of potassium (K) is 1s2 2s2 2p6 3s2 3p6 4s1. The valency of the element is determined by electron configuration in the excited state. This electron configuration shows that the last shell of the potassium atom has an unpaired electron (4s1). So the valency of potassium is 1.

Because of Avogardo Hypothesis, volumes can be used in gas phase reaction stoichiometry at constant temperature and pressure.

Avogadro's Law (also known as Avogadro's Hypothesis or Avogadro's Principle) is an experimental gas law that relates the volume of gas to the amount of gaseous matter present.

Avogadro's law states that "equal volumes of all gases at the same temperature and pressure have the same number of molecules". At constant temperature and pressure, (mol) of a gas is directly proportional.

For example, if two ideal gases, hydrogen and nitrogen, are mixed in equal amounts, they contain the same amount of molecules. This only happens if they are kept at the same pressure and temperature. This shows the ideal behavior of gases.

Let's look at this law mathematically: the overall law can be written as

V is directly proportional to n

or V = nK , K (a constant)

Amount of gas; “n” is the gaseous substance measured in moles. "k" is a constant defined for a specific pressure and temperature.

Comparing the same gas under different conditions, the law is : V₁/ n₁=V₂/ n₂

The equation shows that the number of moles of gas increases in proportion to the increase in gas volume. Therefore, the total number of atoms or molecules present in a given volume of gas is completely independent of the molar mass or size of the gas.

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To draw the planes indicated by the Miller indices (121) and (212) in a unit cell of a cubic lattice, we follow these steps:

 To find the perpendicular distance between the origin and each plane, we can use the formula:

  Distance = sqrt((x-intercept)^2 + (y-intercept)^2 + (z-intercept)^2)

1. Determine the intercepts:

  For the Miller indices (hkl), the intercepts on the x, y, and z axes are determined by taking the reciprocals of the indices:

  Intercept on x-axis = 1/h

  Intercept on y-axis = 1/k

  Intercept on z-axis = 1/l

2. Scale the intercepts:

  Multiply the intercepts by the lattice constant parameter (a) to scale them to the appropriate size.

  Scaled intercept on x-axis = (1/h) * a

  Scaled intercept on y-axis = (1/k) * a

  Scaled intercept on z-axis = (1/l) * a

3. Draw the planes:

  Place the plane on each axis by drawing lines perpendicular to the axes at the scaled intercepts. The points where the lines intersect will determine the position of the plane in the unit cell.

4. Determine the perpendicular distance:

  To find the perpendicular distance between the origin and each plane, we can use the formula:

  Distance = sqrt((x-intercept)^2 + (y-intercept)^2 + (z-intercept)^2)

By following these steps, you can draw the planes and calculate the perpendicular distances between the origin and each of them in the given unit cell.

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Answer: group 1A (or IA)

Explanation:

The half-life of this substance is 30.13 minutes.

Half-life is the duration of time it takes for a radioactive element to decay to half of its initial value. This suggests that a source's activity has a half-life when it takes time for it to decrease to half its initial value.

Expression for rate law for first order kinetics is given by:

K = 2.303/t log a/a-x

where,

k = rate constant  = ?

t = time passed by the sample  = 60.1 min

a = initial amount of the reactant = 400

a - x = amount left after decay process = 100

Therefore, K= 2.303/60.1 log 400/100

k= 2.3 x 10^ -2 min-1

Now we have to calculate the half-life of substance, we use the formula :

k = 0.693 / t

t = 30.13 min

Therefore, the half-life of this substance will be, 30.13 minutes.

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**Check for proof photos at the bottom.**

**Answers are in bold.**

__________________________________________________________

A student places three ice cubes in a beaker and allows them to partially melt. If she measures the temperature of the water in the beaker, what will she most likely observe? Explain your answer.

She will see that the temperature of the water is 0 degrees Celsius and it stays at that temperature until all the ice cubes completely melt.

__________________________________________________________

Use the table on the right to calculate each required quantity. Record values to 3 significant digits.

First answer: 35.8 kJ

Second answer: 871 g

Third answer: Fe

__________________________________________________________

An iron sphere with a mass of 75.00 g is heated to a temperature of 385.0°C. It is then placed in a beaker containing 150.0 g H2O at 100.0°C.

First answer: 339 kJ

Second answer: 9.02  kJ

Third answer: No

__________________________________________________________

A sample of water has a mass of 100.0 g. Calculate the amount of heat required to change the sample from ice at –45.00°C to water vapor at 175.0°C. Relevant constant values are given to the right.

First answer: 325  kJ

Second answer: boiling the water

__________________________________________________________

Identify the correct description for each part labeled on the diagram.  

A: ✔ heating solid

B: ✔ melting

C: ✔ heating liquid

D: ✔ boiling

E: ✔ heating gas

F: ✔ melting point

G: ✔ boiling point

Where are the particles closest together?

✔ A

When ice partially melts, the surrounding water remains at 0° Celsius. This is because ice melting only involves the water molecules overcoming intermolecular forces, or forces holding molecules together. The water molecules themselves aren't increasing in kinetic energy when turning into liquid. Since temperature measures kinetic energy, the temperature in this case, remains at 0°.

To find how much energy it takes to cause a phase change in a substance, you must find the number of moles, and determine whether to use ΔHvap and ΔHfus. ΔHvap is used to show how much energy is involved in evaporation and condensation, and ΔHfus is the same but used for melting and freezing. To find number of moles of a given substance, use the formula: mass of given substance divided by atomic mass. Both numbers have to use the same mass unit. Then, multiply number of moles by ΔHvap or ΔHfus to get kJ.

In a heating curve graph, the flat lines represent no change in energy, or the phase changes. The steep lines are change in energy, which are either heating or cooling. The bottom line is a heating/cooling solid. A heating/cooling solid is the coldest phase, which is why the line is at the bottom.

Here are photos of Edge to make things easier.

The initial (before equilibrium) concentration of  \(NH_{3}\) was 0.51 M (option c).

To find the initial concentration of \(NH_{3}\) before equilibrium, we can use the concept of the equilibrium constant (Kb) for  \(NH_{3}\), which relates the concentration of  \(NH_{3}\) and its conjugate base (NH4+) in a basic solution.

Step 1: Calculate [OH-]
pOH = 14 - pH = 14 - 11.48 = 2.52
[OH-] = 10^(-pOH) = 10^(-2.52) = 3.02 x 10^-3 M

Step 2: Use the Kb expression
Kb = [NH4+][OH-] / [ \(NH_{3}\)]
1.8 x 10^-5 = [(3.02 x 10^-3)^2] / [ \(NH_{3}\)]

Rearranging to find the initial concentration of  \(NH_{3}\):
[NH3] = [(3.02 x 10^-3)^2] / (1.8 x 10^-5) = 0.51 M

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The value of Ksp for AglO₃, if it is found that up to 0.0980 g of Aglo₃ dissolves in 2.00 L of aqueous solution at a certain temperature, is 0.2625 mol/L

To determine the value of Ksp for AglO₃, we must find the concentration of Ag⁺ ion and IO₃⁻ ion in the saturated solution of AglO₃ be x M. Since one mole of AglO₃ produces one mole of Ag⁺ ion and one mole of IO₃⁻ ion. The balanced chemical equation for the dissociation of AglO₃ is as follows:

AglO₃(s) ⇌ Ag+ (aq) + IO₃⁻(aq)

Initially, the concentration of AglO₃ is x M. As the AglO₃ is completely dissociated in the aqueous solution, the concentration of Ag⁺ ion and IO₃⁻ ion also become x M at the equilibrium. Hence, the equilibrium concentration of Ag⁺ ion and IO₃⁻ ion is x M.

The Ksp expression for the dissociation of AglO₃ is as follows:

Ksp = [Ag⁺][IO₃⁻]

Ksp = x × x = x²

Ksp = 0.0980 g/ (2.00 L) × 1000 g/ 1 kg × 1 mol/ 187.81 g

= 0.2625 mol/L (approx)

Thus, the value of Ksp for AglO₃ is 0.2625 mol/L.

ICE table is shown below:

              AglO₃(s) ⇌ Ag⁺ (aq) + IO₃⁻(aq)

Initial (M)       x              0                 0

Change (M) -x              +x               +x

Equilibrium (M) x          x                 x

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Answer:

Yes

Explanation:

Some environmental factors- chemical, physical (UV), and biological (poisonous plants)- have the capability to damage DNA. This can lead to mutation, cell death, and several ailments.

Chemicals such as pesticides and heavy metals can be found in the environment (air, water) or in some consumer products.

The presence of Lead and a reactive oxygen species can result in DNA damage. Arsenic is classified as a carcinogen (cancer-causing substance).

More details are found in scientific articles online, but here's a helpful snippet- "heavy metal exposure can contribute to genetic damage by inducing double strand breaks (DSBs) as well as inhibiting critical proteins from different DNA repair pathways"

Lead and arsenic are heavy metals that are considered carcinogens. These metals cause alteration and damage to the genetic material and protein synthesis.

Carcinogens are said to be a substance that can lead to cancer in an organism and are produced naturally from viruses and ultraviolet rays or mna made by cigarette smoking and chemicals.

Their high exposure causes the breaking of the double strand of the DNA molecule in the cells that inhibits and prevents protein formation leading to interference with the DNA repair pathways.

Cadmium, lead, arsenic, etc., are heavy metals that are released by human activities and alter the genetic mechanism and composition leading to mutation and disorders like skin cancers, lung cancer, etc.

Therefore, lead and arsenic is carcinogens that damage DNA.

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Combustion reaction is a common reaction used to produce energy. The reaction that describes the combustion of ethanol, C₂H5OH is as follows:

C₂H5OH + 3O₂ → 2CO₂ + 3H₂O
The energy released by the combustion reaction is used to generate electricity or to power machines and vehicles.

This reaction is a chemical process in which a fuel reacts with oxygen to produce heat and light energy. Ethanol is a colorless liquid with a formula of C₂H₅OH. It is an important biofuel and is commonly used as a fuel additive to gasoline. In the combustion process, ethanol reacts with oxygen to produce carbon dioxide and water vapor.Combustion reactions are exothermic reactions that release energy in the form of heat and light. They are commonly used in engines and power plants to produce energy from fuels. The energy released by the combustion reaction is used to generate electricity or to power machines and vehicles.

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Answer:

Describes its potential to undergo some chemical change or reaction by virtue of its composition

Fresh water collection areas is the area where you can find most of the

world's drinking water.

This is the type of water which contains low amount of dissolved salts and

solid particles which makes it very suitable for drinking.

Examples of Freshwater collection areas include the following:

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The cathode half cell will have no maximum reduction potential and the engineer can choose an appropriate cathode that will deliver atleast 0.13V or more power

What is a cathode ?

An electrical device with polarized current has a metallic electrode called a cathode through which current is discharged. The electrode in a polarized electrical device via which current enters from an external circuit is known as an cathode, on the other hand.

what is an half-reaction?

The portion of a larger reaction known as a half-reaction constitutes either an oxidation or a reduction on its own. For a redox reaction to be fully described, it requires two half-reactions, one oxidation and one reduction.

The given half cell will work as the anode of the galvanic cell. Oxidation occurs at the anode and the standard oxidation potential E0ox = -E0red. Therefore, the given half cell will have oxidation potential E0ox = -(-1.07 V) = +1.07 V.

The cell potential is given as E0cell = E0red + E0ox and the cell potential will have a value of atleast 1.20 V. Therefore, put E0cell = 1.20 V and get

E0red = E0cell – E0ox = (1.20 V) – (1.07 V) = 0.13 V.

If the cathode half cell has a reduction potential less than 0.13 V, then the cell potential of the galvanic cell will fall below 1.20 V. Hence, the cathode half cell must have a minimum standard reduction potential of +0.13 V

The cell is supposed to deliver atleast 1.20 V power. However, the cell can deliver more than 1.20 V power. Say, the cell delivers 1.30 V power. Then putting E0cell = 1.30 V, we have,

E0red = (1.30 V) – (1.07 V) = 0.23 V.

Hence, the cathode half cell will have no maximum reduction potential and the engineer can choose an appropriate cathode that will deliver atleast 0.13V or more power.

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Answer:

Temperature

Explanation:

Answer:

wind and humidity

Explanation:

ocean and tides are not charectiristics of describing the weather

Answer: A. Winds

C. Humidity

Explanation: because wind blows air and humidity is heat like warm fog or warm.

The given chemical reactions include decomposition and double displacement reactions.

A decomposition reaction is characterized by a single reactant breaking down into two or more components. In the first reaction, 2NH3 H2SO4, the reactant ammonia (NH3) and sulfuric acid (H2SO4) decompose to form ammonium sulfate ((NH4)2SO4). This reaction fits the definition of a decomposition reaction because the reactant breaks down into two different compounds.

Similarly, in the second reaction, 3Pb2H3PO4 ⟶ 3H2 Pb3(PO4)2, the reactant lead(II) hydrogen phosphate (Pb2H3PO4) decomposes to form water (H2) and lead(II) phosphate (Pb3(PO4)2). Again, this reaction qualifies as a decomposition reaction as the reactant breaks down into two different compounds.

In the third reaction, 2 NO2 ⟶ 2O2 N2, the reactant nitrogen dioxide (NO2) decomposes to form oxygen gas (O2) and nitrogen gas (N2). This reaction follows the definition of a decomposition reaction, as the reactant breaks down into two different compounds.

Lastly, the fourth reaction, 2NaBr Ca(OH)2 ⟶ CaBr2 2NaOH, is a double displacement reaction. In this reaction, the sodium bromide (NaBr) and calcium hydroxide (Ca(OH)2) react to form calcium bromide (CaBr2) and sodium hydroxide (NaOH). This reaction involves the exchange of ions between the reactants, leading to the formation of two different compounds. It does not fall under the category of a decomposition reaction.

Among the given chemical reactions, the first three reactions are examples of decomposition reactions. These reactions involve a single reactant breaking down into two or more components, resulting in the formation of different compounds. The fourth reaction is a double displacement reaction, where the reactants exchange ions to form two different compounds.

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Judging by the behavior of the 2 substances in water according to the illustration, the accurate statement would be that both substances are insoluble in water.

Substances that are soluble in water completely dissolve without forming any solid or suspension. Such substances cannot be retrieved or separated from water by mere filtration. In order to retrieve soluble solutes from water, the water would need to be evaporated off.

Water-insoluble substances can easily be separated from water by filtration or by decanting the water off. They form a kind of suspension or solid in water.

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Answer:

C

Explanation:

Slime can be made without glue or activator with shampoo by mixing shampoo and cornstartch in a bowl.  If desired, colour the two parts cornflour to one part water mixture using food colouring. Without glue or borax, this mixture might result in a slimy, goopy texture.

Two parts of  cornflour to one part water, then add food colouring if desired. This mixture has the ability to produce a slimy, sticky texture without glue or borax. You can make slime without glue, borax, or cornflour by mixing cornflour and water. Use 2 parts cornflour with 1 part water to produce the mixture, and you may also add food colouring if you like. The resulting slurry feels sticky and slimy and may be shaped and moulded like conventional slime. This type of slime is also entirely safe to use because it has no harmful chemicals. You may adjust the consistency of the slime by adding more or less water or cornflour, as desired.

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Answer:

73 days

Explanation:

From the question given above, the following data were obtained:

Half life (t½) = 18.2 day.

Original amount (N₀) = 0.70 g

Amount remaining (N) = 0.04375 g

Time (t) =.?

Next, we shall determine the rate of decay of the isotope. This can be obtained as follow:

Half life (t½) = 18.2 day.

Decay constant (K) =.?

K = 0.693 / t½

K = 0.693 / 18.2

K = 0.038 /day

Finally, we shall determine the time taken for the isotope to decay to 0.04375 g. This can be obtained as follow:

Original amount (N₀) = 0.70 g

Amount remaining (N) = 0.04375 g

Decay constant (K) = 0.038 /day

Time (t) =.?

Log(N₀/N) = kt /2.303

Log (0.70/0.04375) = (0.038 × t) /2.303

Log 16 = (0.038 × t) /2.303

1.2041 = (0.038 × t) /2.303

Cross multiply

1.2041 × 2.303 = 0.038 × t

Divide both side 0.038

t = (1.2041 × 2.303) / 0.038

t = 72.97 ≈ 73 days

Therefore, it will take approximately 73 days for the isotope to decay to 0.04375 g

Answer:

17.1 Liters

Explanation:

It's a gas law question (more specifically a Charles's Law question). Formula is V1/T1 = V2/T2. You're given V1 and T1 and T2. However, in order to use the equation, temperature needs to be in Kelvins (by subtracting the degrees C from 273) for the numbers to work (among other reasons, the 0 degrees C will always give you an answer of zero or undefined). Placing all temps in kelvins makes the answers come out right. So 20L/273K = xL/233K gives you the answer when you cross-multiply.

Considering the Charles's law, a weather balloon calibrated at 0.00 °C to have a volume of 20.0 L has  17.07 L at -40.0 °C, assuming pressure is held constant.

The gas laws are a set of chemical and physical laws that allow determining the behavior of gases in a closed system. The parameters evaluated in these laws are pressure, volume, temperature and moles.

Charles's law is one of the gas laws. It relates the volume and the temperature of a certain quantity of ideal gas, kept at a constant pressure.

This law states that, at constant pressure, the volume of a gas is directly  proportional to its temperature. In other words, for a given sum of gas at constant pressure, as the temperature increases, the volume of the gas increases, and as the temperature decreases, the volume of the gas decreases.

Mathematically, Charles's law says that the quotient that exists between the volume and the temperature will always have the same value:

\(\frac{V}{T}=k\)

Being an initial state 1 and a final state 2, it is true:

\(\frac{V1}{T1}=\frac{V2}{T2}\)

In this case, you know:

Replacing:

\(\frac{20 L}{273 K}=\frac{V2}{233 K}\)

Solving:

\(V2=233 K x\frac{20 L}{273 K}\)

V2=17.07 L

Finally, a weather balloon calibrated at 0.00 °C to have a volume of 20.0 L has  17.07 L at -40.0 °C, assuming pressure is held constant.

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Answer:

10.54 M

Explanation:

First you multiply 154.9 by 262 to get the mols and then you divide that number by 3850.45540796906 L and you get 10.54 M.

The only option that would increase the pressure of a gas in a container is B. Increasing the temperature of the gas. Option B

To understand which factor would increase the pressure of a gas in a container, we need to consider the relationship between pressure and various variables in the ideal gas law and the kinetic theory of gases.

The ideal gas law states that pressure (P) is directly proportional to the number of gas particles (n), the temperature (T), and inversely proportional to the volume (V) of the container. Mathematically, it can be expressed as:

PV = nRT

where R is the ideal gas constant.

Based on this equation, we can analyze the options given:

A. Decreasing the kinetic energy of the gas: According to the ideal gas law, temperature is directly proportional to pressure. Therefore, decreasing the kinetic energy (which is related to temperature) would decrease the pressure, not increase it.

B. Increasing the temperature of the gas: As mentioned above, temperature is directly proportional to pressure. Increasing the temperature of the gas would increase its kinetic energy, resulting in more frequent and energetic collisions with the container walls, thus increasing the pressure.

C. Decreasing the number of gas particles: According to the ideal gas law, the number of gas particles (n) is directly proportional to pressure. Therefore, decreasing the number of gas particles would decrease the pressure, not increase it.

D. Increasing the volume of the container: According to the ideal gas law, volume (V) is inversely proportional to pressure. Increasing the volume of the container would decrease the pressure, not increase it.

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The particular ending temperature will depend on the masses and individual heat capacities of the blocks as well as the starting heat content of each block.

Heat will transfer from the lead block to the titanium block when the titanium block is in touch with the lead block, which is at 30°C, until they attain thermal equilibrium, or the same temperature. Until two objects achieve the same temperature, heat moves from the hotter to the cooler.

The lead block will be colder than it was initially because it has given up part of its heat to the titanium block as they reach thermal equilibrium. Until it achieves thermal equilibrium with the iron block, the lead block will now begin to absorb heat from the iron block. Up until they reach the same temperature, heat will transfer from the hotter iron block to the colder lead block.

Titanium, lead, and iron will all eventually approach thermal equilibrium and reach the same temperature. Since the process of heat transmission between the blocks will continue until they are all the same temperature, the system's final temperature will fall between 20°C and 70°C.

The particular ending temperature will depend on the masses and individual heat capacities of the blocks as well as the starting heat content of each block.

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