Answer:
The thread will experience a force on it .
Explanation:
When thread is tied to pen it will experience force. Because the pen is Abit heavy , there is a force that is applied to it which will cause it to elongate , after a while the thread will stretch, elongate and can later experience deformation. When it experience that, the thread can break after deformation and it has losses it elasticity.
How harmful are the emissions from cosmetics, hygiene, and cleaning products? Claim
Evidence 1
Evidence 2
Evidence 3
Reasoning
The claim can be Cosmetics, hygiene, and cleaning product emissions may be dangerous.
Evidence 1: Effect of Air Quality
Volatile organic compounds (VOCs), including formaldehyde, benzene, and toluene, can be found in a variety of cosmetic, hygiene, and cleaning goods. These VOCs have the potential to evaportate and cause indoor air pollution.
Environmental impact is evidence number two
Cosmetics, hygiene, and cleaning goods can have a detrimental environmental impact during manufacturing, usage, and disposal. Microplastics and certain chemicals are among the substances present in these items that may find their way into rivers and endanger aquatic life.
Evidence 3: Worker health effects
Occupational health risks can be present for workers who manufacture and produce hygiene, cleaning, and cosmetic items.
Reasoning: It is clear from the research that emissions from cosmetic, hygiene, and cleaning goods have the potential to be harmful.
Thus, this way, harmful are the emissions from cosmetics, hygiene, and cleaning products.
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Please help. I need to know why B is the correct answer. I will mark you as brainiest and I can help you with something you need help with, I just really need help on this
B The glider moves to the right because the magnitude of the change in momentum of the rubber ball is greater than the magnitude of the changes in momentum of the clay ball.
How does the force occur?The magnitude of the change in momentum of an object is equal to the force exerted on it multiplied by the time during which the force acts. Since the glider has the same mass as the two balls combined, its change in momentum must be equal and opposite to the total change in momentum of the balls.
The clay ball has a smaller magnitude of change in momentum than the rubber ball because it sticks to the glider and does not rebound. Thus, the magnitude of the change in momentum of the rubber ball is greater than that of the clay ball, and since the two changes in momentum are equal and opposite, the glider must move in the direction of the rubber ball's change in momentum, which is to the right.
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Image transcribed:
A day hall and a rubber ball of identical mass are moving toward a gider that is at rest in a frictionless air track The balls have the same speed, with the rubber ball moving toward the left as shown above. The balls strike the glider at the same time. The day ball sticks to the glider and the rubber ball bounces off it.
Which of the following indicates the direction of motion of the glider after the collisions and explains why it moves in that direction?
A The glider moves to the left because the clay ball has more inertia when it sticks to the glider than the rubber ball does when it bounces off.
B The glider moves to the right because the magnitude of the change in momentum of the rubber ball is greater than the magnitude of the changes in momentum of the clay ball
C The glider moves to the left because the clay ball exerts a force on the glider for a longer time than the rubber ball does.
D The glider moves to the right because the collision with the rubber ball is elastic and conserves energy
INSTRUCTION:Refer your TWO answers in diagram/picture above with explanation please
>Which combination of elements would likely form a covalent bonds?
a. W and Y
b. Y and Z
c. V and W
d. X and Y
>Which combination of elements would likely form a covalent bonds?
a. V and Z
b. Z and W
c. V and Y
d. Y and X
#1
W and Y
Y has 6electrons-->2electrons to complete octet.
W has 2electrons-->6electrons to complete octet.
#2
Z and V
V needs 7electrons to complete octet.
Z needs 1 electron to complete octet.
W and Y, Y has 6electrons-->2electrons to complete octet. W has 2 electrons --> 6 electrons to complete the octet. Z and V, V needs 7 electrons to complete the octet. Z needs 1 electron to complete the octet.
How are covalent bonds formed?A covalent bond is formed when two atoms exchange one or more pairs of electrons. The two atomic nuclei are concurrently drawing these electrons to them. The sharing of electron pairs between atoms occurs in covalent bonds.
In contrast to polar covalent bonds, which are formed when electrons are exchanged between atoms with uneven electronegativity, electron pairs shared between atoms with equal or very similar electronegativity form nonpolar covalent bonds, such as H-H or C-H. (e.g., H–O).
Therefore, when the difference between the electronegativities of two atoms is too tiny for an electron transfer to take place to create ions, a covalent bond is formed.
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If this bubble is illuminated perpendicularly with sunlight, what wavelength of visible light will be absent in the reflected light? assume that the index of refraction of the soap film is 1. 33.
When a soap bubble is illuminated perpendicularly with sunlight, the wavelength of visible light that will be absent in the reflected light depends on the thickness of the soap film.
In general, when light reflects off a thin film, interference occurs between the light waves reflecting off the front and back surfaces of the film. If the thickness of the film is an integer multiple of half the wavelength of a particular color of light, destructive interference occurs for that color and it is absent in the reflected light.
Assuming the index of refraction of the soap film is 1.33, the thickness of the film necessary for destructive interference of a particular color can be calculated using the equation t = (m + 1/2)λ/n.
Where t is the thickness of the film, m is an integer representing the number of half-wavelengths in the film, λ is the wavelength of the color, and n is the index of refraction of the film.
To determine which color of visible light will be absent in the reflected light, we would need to know the thickness of the soap film.
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Are three coefficients of expansion alpha bita and gamma universal constant?
Answer:
As the temperature increases, the volume of the material also increases. This is known as thermal expansion. It can also be explained as the fractional change in the length or volume per unit change in the temperature.
The relation between alpha, beta, and gamma is given in the form of a ratio and the ratio is 1:2:3 and can be expressed as:
alpha=fracbeta2=fracgamma3
Following is the relation between the three:
L = L (1 + α.ΔT)
Where, α is the coefficient of linear expansion
A = A (1 + β.ΔT)
Where, β is the coefficient of aerial expansion
V = V (1 + γ.ΔT)
Where, γ is the coefficient of cubical expansion
V = V + γV.ΔT
V = V (1 + γ.ΔT)
L3 = L3 (1 + α.ΔT)3
L3 = L3 (1 + 3α.ΔT + 3α2.ΔT2 + α3.ΔT3)
L3 = L3 (1 + 3α.ΔT)
Alpha, beta, and gamma are related to one another in the form of a ratio, and that ratio is 1:2:3, and yes they are universal constants.
What is expansion?A substance's volume expands while its mass stays constant. Heating is typically the cause of expansion. When a substance is heated, the molecular bonds separating its particles weaken, the particles move more quickly, and the substance expands as a result.
Determine the relation as shown below,
L = L (1 + α × Δ T)
here, α is the coefficient of linear expansion
A = A (1 + β × Δ T)
here, β is the coefficient of aerial expansion
V = V (1 + γ × Δ T)
here, γ is the coefficient of cubical expansion
V = V + γ × V × Δ T
V = V (1 + γ × ΔT)
L3 = L3 (1 + α × Δ T)3
L3 = L3 (1 + 3α × ΔT + 3α2 × ΔT2 + α3 × ΔT3)
L3 = L3 (1 + 3α × Δ T)
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At what point does the ball have the most gravitational potential energy?
Which statement is true about a pseudoscientific idea? A It is biased in its results. b It can be tested and observed. c It can be replicated and verified. d It is improved with new information.
Answer:
It can be replicated and verified.
(c) is correct option.
Explanation:
Given that,
The following statements about a pseudoscientific idea.
(a). It is biased in its results.
(b). It can be tested and observed.
(c). It can be replicated and verified.
(d). It is improved with new information.
We know that,
Pseudo science :
In a pseudoscience, such as statements, trusts and facts about whom it is said these are scientific and logical but these statements is anomalous through the scientific method.
So, we can say that the statement is true about a pseudoscientific idea that is It can be replicated and verified
Hence, It can be replicated and verified.
(c) is correct option.
an object is dropped from the top of a building which is 75 meters high. what's it's velocity before it reaches ground
Hi there! :)
\(\large\boxed{38.34 m/s}\)
Use the following kinematic equation to solve:
\(v_{f}^{2} = v_{i}^{2} + 2ad\)
Where:
vf = final velocity (?)
vi = initial velocity (0 m/s, object started at rest)
a = acceleration (gravity = 9.8 m/s)
d = distance travelled (75 m)
Plug in the given values into the equation:
\(v_{f}^{2} = 0^{2} + 2(9.8)(75)\)
Simplify:
\(v_{f}^{2} = 2(9.8)(75)\\\\v_{f}^{2} = 1470\)
Take the square root of both sides:
\(v_{f} = \sqrt{1470} = 38.34 m/s\)
The grades received by 10 college sophomores in a test are A, B, D, A, A, A, C, B, C, and A. From this data, it can be inferred that the mode is _____.
It can be inferred that the mode is A from the data about grades.
In statistics, the mode in a given data set is the value or set of values that occur most frequently in the data set. The grades received by ten college sophomores in a test are A, B, D, A, A, A, C, B, C, and A. From this data, it can be inferred that the mode is A, which occurs five times.
It can also be noticed that the frequency of sophomores receiving grades B, C, and D is 2, 2, and 1, respectively. Since grade A occurs most frequently (5 times) in the given data set, therefore, it can be inferred that the mode of the data set is A.
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connection by means of wire binding screws or studs and nuts having upturned lugs or equibalent shall be permitted for ___ AWG or smaller conductors
Connection by means of wire binding screws or studs and nuts having upturned lugs or equibalent shall be permitted for conductors of 10 AWG or smaller.
The National Electrical Code (NEC) governs wiring requirements in the United States, and it establishes the maximum conductor size that can be used with a particular connector type.Wire binding screws, studs, and nuts are devices that are used to connect electrical conductors to terminals.
These devices operate by clamping down on the wire to establish a connection. They can be used with a variety of wire sizes, but the NEC specifies the maximum wire size for each type of connector.The use of wire binding screws or studs and nuts with upturned lugs or equivalents is permissible for conductors of 10 AWG or smaller.
This type of connector is commonly used for wiring light fixtures, switches, and outlets. It is important to follow the NEC's guidelines when selecting connectors to ensure that they are rated for the wire size being used.The NEC is updated every three years to reflect changes in technology and best practices in the electrical industry.
It is important to stay up to date with the latest edition of the NEC to ensure that wiring is installed safely and meets the latest standards. Local building codes may also have additional requirements that must be followed when installing wiring and electrical devices.
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explain chamical enargy
Answer:Chemical energy
Explanation:, Energy stored in the bonds of chemical compounds. Chemical energy may be released during a chemical reaction, often in the form of heat; such reactions are called exothermic.
Answer:
Hope this helps
Explanation:
Chemical energy, Energy stored in the bonds of chemical compounds Chemical energy may be released during a chemical reaction, often in the form of heat such reactions are exothermic. The chemical energy in food us converted by the body into mechanical energy and heat .
What term is used to describe the amount of energy it takes for 1 gram of a substance to be raised one degree in temperature?
A.
Specific energy
B.
Specific mass
C.
Specific gravity
D.
Specific heat
Answer:
The answer is specific heat.
Explanation:
The amount of energy for 1 gram of a substance to be raised one degree is called specific heat because it involves energy and temperature going up.
Heat is a form of energy, so it is the most appropriate name.
I hope this helps! :)
The amount of heat required to increase the temperature of 1 gram of a substance by 1 degree Celsius (°C) is known as specific heat. Since water has a higher specific heat than other substances, it requires more energy to raise its temperature. Thus, option D is correct.
What are the characteristics of Specific heat?One gram of a substance's temperature can be raised by one degree Celsius by applying a certain amount of heat, or specific heat.
Calories or joules per gram per Celsius degree are typically used as the units of specific heat. One calorie (or 4.186 joules) per gram per degree Celsius, for instance, is the specific heat of water.
Specific heat is the quantity of energy required to raise a substance's temperature by one degree in order to raise a gram of it.
Therefore, Specific heat term is used to describe the amount of energy it takes for 1 gram of a substance to be raised one degree in temperature.
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please help, i will mark brainliest.
The valid combinations are:
a) 5, 12, and 4b) 7, 7, and 7Total resistance for a circuit in series is R_T = R1 + R2 + R3 + ...
How to determine combinations and total resistance?Question 1
To determine the valid combinations of resistors for a circuit with a total resistance of 21, find combinations where the sum of the individual resistances equals 21. Analyze each option:
5, 12, and 4:
Total resistance = 5 + 12 + 4 = 21 (Valid combination)
7, 7, and 7:
Total resistance = 7 + 7 + 7 = 21 (Valid combination)
3, 3, and 3:
Total resistance = 3 + 3 + 3 = 9 (Invalid combination)
5, 5, and 5:
Total resistance = 5 + 5 + 5 = 15 (Invalid combination)
Therefore, the valid combinations are:
5, 12, and 4
7, 7, and 7
Question 2:
Regarding the second question, the equation that calculates the total resistance for a circuit in series is:
R_T = R1 + R2 + R3 + ...
So, the correct option is:
R_T = R1 + R2 + R3 + ...
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wind blowing across suspended power lines may cause the power lines to vibrate at their natural frequecny. this often produces audible sound waves. this phenomenon, often called an aeolian harp, is an example of
The phenomenon of wind blowing across suspended power lines causing them to vibrate at their natural frequency and producing audible sound waves is commonly referred to as an aeolian harp.
When wind flows across a power line, it sets up alternating areas of high and low pressure on either side of the line. These pressure differences can cause the line to vibrate back and forth, much like a guitar string being plucked. If the frequency of the wind-induced vibration matches the natural frequency of the power line, resonance can occur, resulting in a sustained and amplified sound wave.
The sound produced by an aeolian harp can vary in pitch and volume depending on the wind speed and direction, the size and shape of the power line, and other environmental factors. In some cases, the sound can be loud enough to be heard from a significant distance away, leading to complaints from nearby residents.
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to resolve an object in an electron microscope the wavelength
To resolve an object in an electron microscope, the wavelength of the electron beam should be smaller than the size of the object being observed. This is known as the de Broglie wavelength.
The de Broglie wavelength is given by the equation:λ = h/pwhere λ is the wavelength, h is Planck's constant, and p is the momentum of the electron. The momentum of an electron is given by the equation:p = mvwhere m is the mass of the electron and v is its velocity.To obtain a smaller de Broglie wavelength, either the velocity or the mass of the electron must increase. However, increasing the velocity of the electron can lead to aberrations in the image due to diffraction effects. Therefore, the mass of the electron is typically increased by using heavier elements such as uranium as the source material.
To resolve an object in an electron microscope, the wavelength of the electron beam should be smaller than the size of the object being observed. The de Broglie wavelength can be decreased by increasing the mass of the electron, but this is limited by practical considerations. The velocity of the electron should be high enough to provide good resolution, but not so high as to cause aberrations due to diffraction effects. The de Broglie wavelength of the electron beam should be smaller than the size of the object being observed to resolve it in an electron microscope.
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An Earth observer notes that clocks on a passing spacecraft run slowly. The person on the spacecraft
Check all that apply.
a. agrees her clocks move slower than those on Earth.
b. observes that Earth clocks are moving slowly.
c. feels normal, and her heartbeat and eating habits are normal.
d. The real time is in between the times measured by the two observers.
Agrees her clocks move slower than those on Earth., c. feels normal, and her heartbeat and eating habits are normal, d. The real time is in between the times measured by the two observers due to time dilation.
The observer on the passing spacecraft would agree that their clocks move slower than those on Earth due to time dilation effects caused by their relative motion.
They would still experience their own time as normal, with normal bodily functions such as heartbeat and eating habits.
However, due to the time dilation, the time measured by the observer on Earth would be different from the time measured by the observer on the spacecraft. The "real time" would be somewhere in between the times measured by the two observers.
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Clouds that appear dark in visible light often glow when observed at long infrared wavelengths
T/F
True. cloud may appear dark in visible light, it may still emit radiation at longer infrared wavelengths, leading to a glowing appearance when observed with infrared instruments.
Clouds that appear dark in visible light may contain small particles or droplets that absorb visible light and scatter it in different directions, making the cloud appear dark or opaque. However, these same particles may also emit radiation in the long infrared range, causing the cloud to glow when observed at those wavelengths. Infrared radiation has longer wavelengths than visible light and can penetrate through some of the opaque materials that block visible light. When infrared radiation encounters the small particles or droplets within a cloud, it can cause them to vibrate, which in turn causes them to emit radiation in the infrared range.
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Calculate the intrinsic carrier concentration, ni, at T=200K,400K, and 600K
for:
a) Silicon
b) Germanium
c) Gallium arsenide
the intrinsic carrier concentration, ni, at T=200K,400K, and 600K
a) Silicon:
ni(200K) ≈ \(1.5 x 10^10 /cm^3\)
ni(400K) ≈ \(4.4 x 10^12 /cm^3\)
ni(600K) ≈\(3.3 x 10^14 /cm^3\)
b) Germanium:
ni(200K) ≈ \(2.4 x 10^13 /cm^3\)
ni(400K) ≈ \(2.2 x 10^15 /cm^3\)
ni(600K) ≈ \(3.3 x 10^16 /cm^3\)
c) Gallium Arsenide:
ni(200K) ≈\(2.2 x 10^6 /cm^3\)
ni(400K) ≈ \(3.8 x 10^8 /cm^3\)
ni(600K) ≈\(1.1 x 10^10 /cm^3\)
Intrinsic carrier concentration, ni, is a measure of the density of electrons and holes in an intrinsic semiconductor, where the number of electrons is equal to the number of holes. At a given temperature T, the value of ni can be calculated using the following equations:
For Silicon: ni =\(1.45 x 10^10 √(T^3) exp(-Eg / 2kT) cm^-3\)
where Eg is the bandgap energy of silicon (1.12 eV), k is the Boltzmann constant\((8.617 x 10^-5 eV/K)\), and T is the temperature in Kelvin.
For Germanium: ni = \(2.4 x 10^13 √(T^3) exp(-Eg / 2kT) cm^-3\)
where Eg is the bandgap energy of germanium (0.67 eV).
For Gallium Arsenide: ni =\(1.63 x 10^16 (m*/m^)^(3/2) T^(3/2) exp(-Eg / 2kT) cm^-3\\\)
where m is the effective mass of the electron and hole, and Eg is the bandgap energy of gallium arsenide (1.43 eV).
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Tiny mass of 67kg and tubby mass of 83 kg are now on the opposite ends of a see saw and are both 1.4m from the balance point where should their sister teeny whose mass is 32 kg sit so the see saw balances
Answer:
0.7 m between the balance point and Tiny
Explanation:
It's intuitive to say she sould be on the side the smaller mass is placed. How far from the balance point?
Let's call x that distance. and assume that the contraption is "oriented" so that being on the side with tiny (and teeny) gives you a positive distance from the balance point, and negative on the other side.
At equilibrium, the sum of all momentums (momenta?) will be zero:
\(67\times 1.4 +32\times x + 83 \times (-1.4) = 0\\32x -16(1.4) = 0 \rightarrow 2x=1.4 x= 0.7\)
In layman's term, she has to be halfway between the balance point and Tiny.
A penny is dropped from a cell phone tower, after about 2s of free fall the acceleration of the penny is:________
A penny is dropped from a cell phone tower, after about 2s of free fall the acceleration of the penny is 8 m/s^2 east.
What is acceleration?If the velocity of an object changes, it is said to be accelerated. An object's velocity can change due to an increase or decrease in speed or a change in direction of motion. Acceleration can be seen in the fall of an apple, the moon orbiting the earth, or a car stopped at a traffic light. Through these examples, we can see that acceleration occurs when a moving object's direction changes or its speed increases or decreases.
Because it has both magnitude and direction, acceleration is a vector quantity. It is also the second derivative of position relative to time or the first derivative of velocity relative to time.
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if the distance from the center of the earth to the satellite at perigee is 2.53×104 km , what is the corresponding distance at apogee?
The corresponding distance at apogee is 2.71 × 10⁴ km.
Apogee and perigee are the highest and lowest points, respectively, in the orbit of an object that revolves around Earth. The distance from the center of the earth to the satellite at perigee is 2.53 × 10⁴ km.Given that the distance from the center of the earth to the satellite at perigee is 2.53 × 10⁴ km, we can determine the corresponding distance at apogee.
Kepler's first law states that the path of each planet around the sun is an ellipse with the sun at one focus. As a result, Earth's orbit is elliptical rather than circular, with the sun at one focus.Let's take a look at the formula:
r₁ + r₂ = 2a
Where, r₁ is the distance from the center of the earth to the satellite at perigee.
r₂ is the corresponding distance at apogee.
a is the semi-major axis.
2a = r₁ + r₂⇒ 2a - r₁ = r₂
Distance at apogee r₂ = 2a - r₁
Substituting the given values, we get
;r₂ = 2 × 2.53 × 10⁴ km - 2.53 × 10⁴ km= 2.71 × 10⁴ km
Therefore, the corresponding distance at apogee is 2.71 × 10⁴ km.
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How fast does a apple fall if it falls at 5mph?
The apple will fall in 0.00014 seconds
The branch of physics that defines motion with respect to space and time, ignoring the cause of that motion, is known as kinematics. Kinematics equations are a set of equations that can derive an unknown aspect of a body’s motion if the other aspects are provided.
u = 5 m/h = 0.00139 m/s
using kinematic equation
v = u + at
v = final velocity = 0
g = acceleration due to gravity
t = time = ?
using
v = u - g*t
0 = 0.00139 - 9.8 t
t = 0.00139 / 9.8 = 0.00014 seconds
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how to burn your module?
sabog na sabog nako eh
Answer:
get some
get some ⛽⛽⛽⛽⛽
pour the ⛽ on the module,
get that on itttttt and booooooommmm
Explanation:
What happens to the speed of a ball after it is thrown upward into the air neglect air resistance?
The speed of a ball that is thrown upward into the air, neglecting air resistance, changes over time due to the force of gravity. The ball's velocity decreases as it rises, reaches zero at the peak of its trajectory, and then increases as it falls back towards the ground.
The motion of an object under the influence of gravity can be described by the laws of physics. When a ball is thrown upward into the air, it initially moves with a certain velocity. However, as the ball rises, its velocity changes due to the force of gravity acting on it. In this answer, we will neglect the effect of air resistance and focus solely on the effect of gravity.
When a ball is thrown upward, it has an initial velocity, which is equal to the magnitude of the velocity with which it was thrown. This velocity is positive, meaning that it points in the upward direction. However, as the ball rises, it is slowed down by the force of gravity, which acts in the downward direction. As a result, the velocity of the ball decreases over time.
The acceleration due to gravity, g, is a constant 9.8 m/s^2, and it acts in the downward direction. The equation for velocity, v, as a function of time, t, can be expressed as v = v0 - gt, where v0 is the initial velocity. This equation shows that the velocity of the ball decreases linearly with time as it rises into the air.
At the peak of its trajectory, the ball has zero velocity. This means that it is momentarily at rest, and from this point on, it begins to fall back towards the ground. The velocity of the ball at this point is negative, meaning that it points in the downward direction. As the ball falls, its velocity increases due to the force of gravity, and it continues to increase until it reaches the ground.
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You weigh 580 N on Earth. If you were to go to Mars, where its gravitational pull is 3 . 7 11 m /s 2 , what would you weigh? (Hint: gravity on Earth is 9.8 m /s 2 .
Answer:
59.18 kg
Explanation:
use f=ma
f= 580 N
a = 9.8 m/s 2
weigh(m) doesn't change only force(F) changes
Answer: 219.6N
Explanation:
Find the mass of this person by dividing his weight by the accelleration. Remember, F=ma
580 = m*9.8
m = 59.18kg
Then multiply the mass by the new gravitational acceleration on Mars.
59.18*3.711 = 219.6N
11. A car drives 60 mph for 5 hours and then turns around and drives another hour back at the same speed. What is the
distance
Answer:
240 miles
Explanation:
The car drove 60mph for 5 hours, so that's 60x5, which is 300. You then subtract 60 and get your answer: 240 miles.
A 1kg cart is accelerating at 2 m/s2 due to a constant force. If that same net force was applied to a cart with twice as much mass, what acceleration would it have?
Answer:1m/s2
Explanation:
A charge q = 8 μC is moving with a velocity v = [31 +43]x 106 m/s. If the charge enters a magnetic. field B=0.4k T, then the magnitude of the magnetic force (in N) on the charge is: F=qvx B (A) 4 F=9/15 9 [37+ ujjxk (16 (B) 8 (C) 12 (D) 16 (E) 20 Q7- A charge q = 8 μC is moving with a velocity v = [31 +43]x 106 m/s. If the charge enters a magnetic. field B=0.4k T, then the magnitude of the magnetic force (in N) on the charge is: F=qvx B (A) 4 F=9/15 9 [37+ ujjxk (16 (B) 8 (C) 12 (D) 16 (E) 20 an спо A particle with a charge of 5.0c travels at 2.0 m/s and encounters a magnetic field of 0.0100 T that makes an angle of 46.0 with respect to the x-axis in the xy-plane. Find the force the magnetic field exerts on the particle. FONTEINONA -0.069 N 0.072 N -0.072 N 0.069 N Q7: A positively charged particle q=2 µC enters a uniform magnetic field B= 21 +31 T with a velocity v=4x106 m/s. The magnetic force F(in N) on the particle is: a) -12 1-8 k b) 24 k c) -16 k d) -12 k e) 12î-16ĵ
The force the magnetic field exerts on the particle is 0.072 N with velocity
Charge q = 8 μC is moving with a velocity v = [31 +43] x 106 m/s. If the charge enters a magnetic field B=0.4k T, then the magnitude of the magnetic force (in N) on the charge is given by
F = q x v x B
Given thatq = 8 μC
= 8 x 10-6 C
Velocity v = [31 +43] x 106 m/s
= [31,000,000 + 43,000,000] m/s
= [74,000,000] m/s
Magnetic field B = 0.4k T
= 0.4 x 103 T
TeslaSubstituting these values in the above equation, we get
F = (8 x 10-6) x (74 x 106) x (0.4 x 103)
F = 2.95 N
Therefore, the magnitude of the magnetic force (in N) on the charge is 2.95 N.
Another problem:
Given that a particle with a charge of 5.0 C travels at 2.0 m/s and encounters a magnetic field of 0.0100 T that makes an angle of 46.0 with respect to the x-axis in the xy-plane. We need to find the force the magnetic field exerts on the particle.
The force F on the particle is given by:
F = q x v x B x sin(θ)Where q is the charge of the particle, v is the velocity of the particle, B is the magnetic field and θ is the angle between the velocity of the particle and the magnetic field.
F = 5.0 C x 2.0 m/s x 0.0100 T x sin(46.0)
F = 0.072 N
Therefore, the force the magnetic field exerts on the particle is 0.072 N.
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Photographs of the surface of Mars provides evidence that liquid water once flowed on its surface. T/F
True, photographs of the Martian surface reveal features like channels, valleys, and deltas, suggesting that liquid water once flowed there.
Mars has been a subject of interest for scientists in understanding the presence of water and the potential for life. Orbital and rover missions to Mars have captured images of the planet's surface that show geological features, such as channels, valleys, and deltas, which are typically formed by the flow of liquid water.
Moreover, analysis of the mineral composition of Martian rocks provides further evidence of past water activity. While the current Martian atmosphere is too thin and cold to support liquid water, these findings suggest that Mars once had a warmer and wetter environment, possibly capable of hosting life.
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now consider the gaussian surface s2. with the charge still inside the cavity, what is the electric flux, in newton squared meters per coulomb, through surface s2?
Gauss's law states that the total electric flux through any closed surface is proportional to total electric charge inside the surface.
The electric flux is the measure of the electric field through a given surface. The electric field is the gradient of the potential. The density of the lines corresponds to the electric field strength, which could also be called the electric flux density. Electric flux is proportional to the total number of electric field lines going through the surface.
Electric flux has SI units of volt meters or equivalently newton meters squared per coulomb. Thus, the SI base units of electric flux are kg m3s -3*A-1.
The quantity EA1 is the electric flux through S1. We represent the electric flux through an open surface like S1. Electric flux is a scalar quantity.
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