The mobility when both scattering mechanisms exist at the same time is 166.67 cm2 /v-s.
When both scattering mechanisms exist at the same time in a semiconductor, the total mobility can be calculated using Matthiessen's rule which states that the total mobility is the reciprocal of the sum of the reciprocals of the individual mobilities. Therefore, the total mobility (μ_total) can be calculated as:
1/μ_total = 1/μ_1 + 1/μ_2
where μ_1 is the mobility due to the first scattering mechanism and μ_2 is the mobility due to the second scattering mechanism.
Substituting the given values, we get:
1/μ_total = 1/250 + 1/500
Simplifying this expression, we get:
1/μ_total = 1/250 * 2/2 + 1/500 * 2/2
1/μ_total = 4/1000 + 2/1000
1/μ_total = 6/1000
μ_total = 1000/6
μ_total = 166.67 cm2 /v-s
Therefore, the mobility when both scattering mechanisms exist at the same time is 166.67 cm2 /v-s.
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this si a 2 part question84) A shock absorber is designed to quickly damp out the oscillations that a car would otherwise make because it is suspended on springs. (a) Find the period of oscillation of a 1610-kg car that is suspended by springs that make an effective force constant of 5.75×104 N/m. (b) Find the damping constant b that will reduce the amplitude of oscillations of this car by a factor of 5.00 within a time equal to half the period of oscillation.
Given data
*The given mass of the car is m = 1610 kg
*The given effective force constant is k = 5.75 × 10^4 N/m
(a)
The formula for the period of oscillation of a 1610 kg car is given as
\(T=2\pi\sqrt[]{\frac{m}{k}}\)Substitute the known values in the above expression as
\(\begin{gathered} T=2\times3.14\times\sqrt[]{\frac{1610}{5.75\times10^4}} \\ =1.05\text{ s} \end{gathered}\)Hence, the time period of oscillation of a 1610 kg car is T = 1.05 s
(b)
As from the given data, the amplitude of the oscillation of the car decreases by a factor of 5.00. Then, the expression for the amplitude of the oscillation, and the damping constant (b) is calculated as
\(A=A_0e^{-\frac{bt}{2m}}\)Substitute the known values in the above expression as
\(\begin{gathered} \frac{A_0}{5.0}=A_0e^{-\frac{bt}{2m}} \\ bt=2m\ln (5.0)_{} \\ b(\frac{T}{2})=2m\ln (5.0) \\ b=\frac{4m\ln (5.0)}{T} \\ =\frac{4\times1610\times\ln (5.0)}{1.05} \\ =9871.2\text{ kg/s} \end{gathered}\)Hence, the damping constant is b = 9871.2 kg/s
You push a box 3.5 m across the floor with a constant force of 12.4 N. How much work do you do on the box?
Answer:
43.4 N (newton)
A student lifts a basketball to a height of 6 feet and lets the ball drop to the ground. Which statement accurately compares the ball's energy at a height of 6 feet (at rest) and at a height of 2 feet (falling)?
A.
The ball's kinetic energy is the same at both heights, but its potential energy is different.
B.
The ball has less potential energy and more kinetic energy at 6 feet than at 2 feet.
C.
The ball's potential energy is the same at both heights, but its kinetic energy is different.
D.
The ball has more potential energy and less kinetic energy at 6 feet than at 2 feet.
Answer:C
Explanation:
If you are holding the ball that would be the ball would have potential energy since it it not moving. Once you drop the ball it will have kinetic energy since it’s moving. If you drop the ball from 6ft it will have more kinetic since it will have more time to accelerate. If you drop the ball from 2ft then it will have less kinetic energy since it is closer to the ground and won’t have beeping time to accelerate and get rid of the potential energy.
Answer:
c
Explanation:
¿cuantos colores existen?
Answer:
Los 11 colores básicos (negro, azul, marrón, gris, verde, naranja, rosa, púrpura, rojo, blanco y amarillo) y los 28 adicionales (turquesa, verde oliva, verde menta, borgoña, lavanda, magenta, salmón, cian, beige, rosado, verde oscuro, verde oliva, lila, amarillo pálido, fucsia, mostaza, ocre, trullo, malva, púrpura
hope that helps bby<3
Answer:
10 millones
Explanation:
En primer lugar, los científicos han determinado que en el laboratorio podemos ver unos 1.000 niveles de luz oscura y unos 100 niveles de rojo-verde y amarillo-azul. Eso es alrededor de 10 millones de colores ahí mismo.
What task requires the most work, lifting a 12-kg sack 2 meters or lifting a 25-kg sack 1 meter?
a.) the 12-kg sack
b.) the 25-kg sack
c.) Both require the same amount of work.
d.) Impossible to determine without knowing the contents of the sack
Please answer ASAP!! Thank you!!
Multiply the masses by the respective distances:
(12 kg) (2 m) = 24 J
(25 kg) (1 m) = 25 J
so the heavier bag takes more work to lift, and (b) is the answer.
(d) is technically correct if the sacks are carrying different contents whose masses are not equal, but since we don't know what's inside each sack, assume 12 kg and 25 kg are the masses of each sack *and* their contents.
a computer simulation is an example of what?
a hypothesis
a scientific law
a scientific theory
a model
A model can be a virtual OR physical representation of an object, movement, etc. A model is used to have a visual view of an item.
Hope this helps and please mark brainliest!
do you expect an echo to return to you more quickly on a hot day or a cold day?
Answer:
more quickly on a hot day
Explanation:
Brainliest if right
Two kids are roller skating. Amy, with a mass of 55 kg, is traveling forward at 3 m/s. Jenny, who has a mass of 40 kg, is traveling in the opposite direction at 5 m/s. They crash into each other and hold onto each other so that they move as one mass. How fast are they traveling?
Answer:
-0.37m/s
Explanation:
work out the momentum of both kids
amy : 55 x 3 = 165kg m/s
jenny: 40x - 5 = -200kg m/s
add the momentum then divide it by the total weight so its
-35/95 = -0.37 m/s
hope this helps!!
Four views of a horseshoe magnet and a current-carrying wire are shown in the drawing. The wire is perpendicular to the screen, and the current is directed out of the screen toward you. In which one or more of these situations does the magnetic force on the current point due north?.
Four views of a horseshoe magnet and a current-carrying wire are shown in the drawing. The wire is perpendicular to the screen, and the current is directed out of the screen towards you.
The magnetic force acting on a current-carrying wire is influenced by the direction of the current flow and the direction of the magnetic field, which is decided by the magnetic pole it is near. The magnetic field lines created by a bar magnet, for example, run from the north to the south pole.In the given figure, the magnetic field lines are moving from north to south, as shown by the white arrow.
When the direction of the current is perpendicular to the direction of the magnetic field, a magnetic force is exerted on the current-carrying wire. According to the right-hand rule, the magnetic force on the wire will be perpendicular to both the current-carrying wire and the direction of the magnetic field.
According to the right-hand rule, magnetic force will be directed north in the first view (A), and magnetic force will be directed east in the third view (C).
Therefore, magnetic force on the current points due north in the first view (A).Hence, the answer is the first view (A).
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What is the flux through any closed surface surrounding a cylinder with surface charge densityσ = k sin φ , where k is a constant. Its height is H , and its radius is R.
The flux through any closed surface surrounding a cylinder with height H and radius R having surface charge density σ = k sin φ, where k is a constant, is φ₀=2πRLk sin φ/ε₀.
Since the cylinder's surface charge density is given by σ = k sin φ
Therefore, the total charge on the cylinder's curved surface
Q = σ(2πRL)
Where L is the height of the cylinder, Q = 2πRLk sin φ .
From Gauss's Law, the total flux through a closed surface surrounding a cylinder with height H and radius R is given by φ₀=Qε₀ .Here, ε₀ represents the vacuum permittivity. Now, substituting the value of Q, we get
φ₀ = (2πRLk sin φ)/ε₀
Therefore, the flux through any closed surface surrounding a cylinder with height H and radius R having surface charge density σ = k sin φ, where k is a constant, is φ₀=2πRLk sin φ/ε₀.
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In space, the input/output of heat energy between an object and the outside (outer space) is done only by "radiation". Give the reason.
In space, the transfer of heat energy between an object and the outside environment primarily occurs through radiation. This is because space is a vacuum, devoid of any medium for conduction or convection, which are the other two modes of heat transfer commonly observed in terrestrial environments.
Radiation is the process by which heat is transferred through electromagnetic waves, such as infrared radiation. All objects with a temperature above absolute zero emit thermal radiation. In the case of an object in space, it radiates heat energy in the form of electromagnetic waves in all directions. These waves carry the energy away from the object into the surrounding space.
Since there is no air or other material in space to conduct or convect heat, radiation becomes the dominant mode of heat transfer. The object's temperature and its emissivity (the ability to emit radiation) play key roles in determining the amount of heat energy radiated. This radiation can travel through the vacuum of space without the need for a physical medium, allowing heat to be exchanged between objects and their surroundings.
Therefore, in the absence of a medium for conduction or convection, radiation becomes the primary mechanism for the input and output of heat energy between objects in space and the outer space environment.
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Calculate the amount of extension of a spring with a spring constant of 3 kN/m, if the amount of work done in extending it is 35 N. Give your answer in m.
The extension of the spring is 4.83 m, if work done is 35 Newton and spring constant is 3 k N/m.
The spring constant, k, is a measure of the stiffness of the spring. it's far one of a kind for unique springs and materials. the larger the spring regular, the stiffer the spring and the greater.
Spring constant of 3 k N/m,
The amount of work done in extending is 35 N
WORK DONE by spring force = 1/2 k X²
⇒0.5 * 3 * X²
35 N = 0.5 * 3 * X²
X² = 35/1.5
x = \(\sqrt{23.33}\)
X = 4.83 m
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The extension of the spring is can be found out by using the Work Done due to extension in Spring Constant K. The extension in the spring is 4.83m.
The spring constant, k, is a measure of the stiffness of the spring. It is for springs and materials which measures the ratio of force that affects the spring and the displacement caused by the force action.
Spring constant depends on the stiffness of the spring, wire thickness, number of turns in wound coil, length of spring and diameter of the coil.
Given:
Spring constant = 3000 N/m
Work Done in extension= 35 N
Let the extension in spring by x.
∴ Work Done by spring force = 1/2 kx²
Work done = 0.5 × 3 × x²
⇒ 35 N = 0.5 × 3 × x²
⇒ x² = 35/1.5
⇒ x = 4.83m
Hence, the extension of spring is 4.83m.
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Should Native Americans be allowed to use peyote in their religious rituals? Why or why not? Provide support for
your position.
Answer:
Native Americans should be allowed to use peyote in their religious rituals. The United States should not restrict access to peyote and should not interfere with the use of peyote in Native American rituals. Many religious communities use a substance that can cause a change in consciousness during their ceremonies, including Christian communities who use wine as part of their sacrament. Native Americans use the peyote responsibly and should not be restricted from its use.
Explanation:
yup
Adding white to a color creates a shade. Adding black to a color produces a tint. TRUE OR False
False. Adding white to a color produces a tint, while adding black to a color creates a shade.
When we talk about colors, the terms “tint” and “shade” refer to specific changes in their appearance. Adding white to a color creates a tint. This happens because white is the lightest color and has the ability to lighten other colors. When white is mixed with a color, it increases the lightness and creates a paler version of that color. Tints are often associated with a softer and more delicate aesthetic.
On the other hand, adding black to a color creates a shade. Black is the darkest color and has the ability to darken other colors. When black is mixed with a color, it reduces the lightness and creates a darker version of that color. Shades tend to have a deeper, richer, and more intense appearance compared to the original color.
It's important to note that the terms “tint” and “shade” are specifically used when referring to the effects of adding white or black to a color. Other color-related terms such as tone, saturation, and hue describe different aspects of color manipulation.
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a force of 1.21 x 103 n is needed to bring a car moving at 22.0 m/s to a halt in 20.0 s. what is the mass of the car?
According to the statement, If a force 1.21 x 103 N is needed to bring a car moving at 22.0 m/s to a halt in 20.0 s then the mass of the car is 1.10 x 10³ kg.
What is force?The push or draw motion is the simplest definition of force. Contact forces and non-energies are two different kinds of forces. Nuclear force, gravitational force, mechanical force, electrostatic force, electrical force, spring force, and others are a few instances of forces.
According to formula
force = mass x acceleration
When the car is brought to a halt, its final velocity is 0 m/s.
[(Final velocity) – (Initial velocity)] / Time = acceleration
acceleration = (0 - 22.0 m/s) / 20.0 s
acceleration = -1.10 m/s²
Note that we have used a negative sign because the acceleration is opposite to the direction of the initial velocity.
1.21 x 10³ N = mass x (-1.10 m/s²)
mass = 1.21 x 10³ N / (-1.10 m/s²)
mass = -1.10 x 10³ kg
The negative mass value doesn't make sense physically, so we need to use the absolute value:
mass = 1.10 x 10³ kg
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Help :(((((((((((((((((((
From the given position -time graph it is clear that, Amiya covers a distance of 40 meters within 12 seconds.
What is position -time graph ?A position - time graph is used to determine the change in position with respect to the time. We can calculate the average speed of the object from the position -time graph.
Speed is the measure of distance covered within unit time. Hence, it is the ratio of change in position to the change in time. Speed has the unit of m/s .It can also defined as the rate of displacement of an object.
From the given plot, it is clear that the Amiya is 40 meters far after 12 seconds run. After that she stops and the position gets constant. Hence, option A is correct.
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Which of the following provide electrical resistance in a simple circuit? *
a battery
a wall outlet
a voltage source
a light bulb
Answer:
A light bulb
Explanation:
Sorry of it wrong
what is the volume
you have to multiply this
1.50*1.25*1.50*1.25
Answer:
3.515625 is your answer
Explanation:
(no idea why you wouldn't use a calculator but here ya go haha)
Does kinetic energy stay the same at all heights? pls help I have 12 minutes to finish the project and the teacher won't help me :(
Answer:
Kinetic energy does not stay the same at all heights
Explanation:
Well as the height and wind increase so does the kinetic energy it's like when you fall as you are about to hit the floor you speed increases
HOPE THIS HELPS YA :)
a pbx switch is considered part of the pstn and not part of the customer premises equipment (cpe). true or false
False. A PBX switch is considered part of the customer premises equipment (CPE) and not part of the Public Switched Telephone Network (PSTN).
Any equipment that is situated on the customer's premises and utilised in the functioning of a telecommunications system is referred to as customer premises equipment (CPE), which includes PBX switches.
The public switched telephone network, or PSTN for short, is the world's network of phone lines, switches, and other hardware used for speech and data transmission. Even though a PBX switch is connected to the PSTN, it is still regarded as belonging to the client.
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Which object provides an inertial frame of reference?.
Answer:
a skydiver falling at terminal (constant) velocity
Explanation:
A 12-ohm lamp is plugged into a 90 v outlet. what is the current?
When a 12-ohm lamp is plugged into a 90 V outlet, the current flowing through the circuit can be calculated using Ohm's Law. Ohm's Law states that the current (I) is equal to the voltage (V) divided by the resistance (R). So, the current flowing through the lamp is 7.5 Amperes.
In this case, the voltage is 90 V and the resistance is 12 ohms.
Substituting these values into the formula, we get:
I = 90 V / 12 Ω = 7.5 A.
Therefore, the current flowing through the lamp is 7.5 Amperes.
This means that a rate of 7.5 Coulombs of charge flows through the lamp per second.
It is important to ensure that the lamp and the electrical circuit are designed to handle this current to prevent overheating or other safety issues.
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1-D Kinematics
A car starts at a position of -153 m
and undergoes a displacement of
512 m. What is its final position?
(Unit = m)
Answer:
hope it helps you...........
2. You will need a magnifying glass and a small piece of scrap paper for this demonstration. a. Go outside on a sunny day and put the piece of paper on a patch of asphalt, concrete, or a large flat rock. Make sure there is no other combustible material or debris in the vicinity. b. Hold the magnifying glass so it is close to the paper, with rays of sunlight shining through it. Move the magnifying glass side to side and close or away from the paper until the most concentrated ray of light is shining on the paper. This is the focal point for that magnifying glass. c. Measure the distance between the focal point and magnifying glass. This is the focal length for that magnifying glass. (Be careful; if you hold the magnifying glass in that place for long enough, the paper will catch fire. Do not ever do this on your skin or clothing, as it can cause serious burns.) d. Now take the magnifying glass inside and use it to look at the words in a book. What is the focal length now?
The focal length of a magnifying glass is the distance between the focal point and optical centre of the magnifying glass.
Focal lengthThe focal length, f is the distance from a lens or mirror to the focal point, F.
This is the distance from a lens or mirror at which parallel light rays will meet for a converging lens or mirror or appear to diverge from for a diverging lens or mirror.
A magnifying glass is a converging lens which produces a enlarged, erect and virtual image when an object is placed between the focal point and optical centre.
A magnifying glass will bring to focus at a point sun rays which can cause the paper to catch fire if it is held in place for long.
This point at which the most concentrated ray of light is shining on the paper, is the focal point for that magnifying glass.
Therefore, the focal length of a magnifying glass is the distance between the focal point and optical centre of the magnifying glass.
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if the change in thermal energy is 140j mass is 27kg and temperature change is 11゚C what is the specific heat capacity
The specific heat capacity formula is used to determine the quantity of heat required to alter the temperature of a unit mass of a substance by one degree Celsius.
The symbol c represents specific heat, and its SI unit is J/kg °C. The formula is:Q = mc∆THere, Q represents the change in thermal energy, m represents the mass of the object, c represents the specific heat, and ∆T represents the change in temperature.In order to determine the specific heat of a substance, we can substitute the given values into the above formula.Q = mc∆T140 J = (27 kg) c (11°C)c = 140 J / (27 kg × 11°C)Therefore, the specific heat capacity of the substance is approximately 0.479 J/kg °C.For such more question on Celsius
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Two cars, A and B, are 400. meters apart. Car A travels due east at 30. meters per
second on a collision course with car B, which travels due west at 20. meters per second. How much time elapses before the two cars collide?
We want to find how much time will pass before the two cars collide. By using one as a frame of reference, we will see that 8 seconds elapse before the two cars collide.
Defining the frame of reference:The frame of reference is the point where the observer is at. For example, if we define one of the cars as a frame of reference, we will see that the selected car does not move (because we move with it, so we can't notice the movement).
Then the velocity of the selected car is "passed on" to the other car.
This means that if we select car A as our frame of reference, which moves at 30 m/s, then we will see that car A does not move, while car B moves with a speed of:
S = 20m/s + 30m/s = 50m/s
The velocities are added because the two cars move in opposite directions (So car A sees that car B comes faster than it actually does).
Now that we are on this frame of reference, we just need to see how long will take car B to travel 400 meters when it moves at 50 m/s
So we need to solve:
Distance/speed = time
With:
distance = 400mspeed = 50m/s.(400m)/( 50 m/s) = 8s
This means that 8 seconds elapse before the two cars collide.
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A weightlifter slowly lifts a large amount of weight with a force of 500 N and an acceleration
m/s2. What is the amount of weight being lifted in grams?
Explanation:
Given parameters:
Force = 500N
Acceleration =
Unknown:
Weight can be used to this problem = ?
Solution:
Weight is the vertical force on a body;
Weight = mass x acceleration
So from this we can find the mass and then convert to the second wealth.
On a horizontal frictionless surface a mass M is attached to two light elastic strings both having length l and both made of the same material. The mass is displaced by a small displacement Δy such that equal tensions T exist in the two strings, as shown in the figure. The mass is released and begins to oscillate back and forth. Assume that the displacement is small enough so that the tensions do not change appreciably. (a) Show that the restoring force on the mass can be given by F = -(2T∆y)/l (for small angles) (b) Derive an expression for the frequency of oscillation.
Answer:
(a) By small angle approximation, we have;
F = -2×T×Δy/l
(b) \(The \ frequency \ of \ oscillation, \ f = \dfrac{1}{2\cdot \pi }\cdot\sqrt{\dfrac{2 \cdot T}{l \cdot M} }\)
Explanation:
(a) The diagram shows the mass, M, being restored by two equal tension, T acting on the elastic strings l, such the restoring force, F acts along the path of motion of the mass, with distance Δy
Therefore, the component of the tension T that form part of the restoring force is given as follows;
Let the angle between the line representing the extension of the elastic strings T and the initial position of the string = ∅
Then we have;
String force, \(F_{string}\) = T×sin∅ + T×cos∅ + T×sin∅ - T×cos∅ = 2×T×sin∅
Whereby the angle is small, we have;
sin∅ ≈ tan∅ = Δy/l
Which gives;
\(F_{string}\) = 2×T×sin∅ = 2×T×Δy/l (for small angles)
Restoring force F = \(-F_{string}\) = -2×T×Δy/l
F = -2×T×Δy/l
(b) Given that the the tensions do not change appreciably as the mass, M, oscillates from Δy we have;
By Hooke's law, F = -k×x
Whereby Δy corresponds to the maximum displacement of the mass, M from the rest position, which gives;
Which gives;
F = M×a = -k×Δy
a = -k×Δy/M
d²(Δy)/dt² = -k×Δy/M
When we put angular frequency as follows;
ω² = k/M
We get;
d²(Δy)/dt² = -ω²×Δy
Which gives;
Δy(t) = A×cos(ωt + Ф)
The angular frequency is thus, ω = √(k/M)
Period of oscillation = 2·π/ω = 2·π/√(k/M)
The frequency of oscillation, f = 1/T = √(k/M)/(2·π)
Where:
k = 2·T/l, we have;
f = √(k/M)/(2·π) = √(2·T/l)/m)/(2·π)
The frequency of oscillation is given as follows;
\(f = \dfrac{1}{2\cdot \pi }\cdot\sqrt{\dfrac{2 \cdot T}{l \cdot M} }\)
A 1210 kg car is driving NE
(at 45.0°) at 15.2 m/s when it is
struck by a moving 1540 kg car.
Afterward, they stick together and
move directly east (at 0°) at 23.3
m/s. What was the y-component
of the second car's initial velocity?
Answer:
To find the y-component of the second car's initial velocity, we can use the principle of conservation of momentum. This principle states that the total momentum of a system remains constant unless there is an external force acting on the system.
In this case, we can consider the two cars as a system, and we can use the principle of conservation of momentum to find the y-component of the second car's initial velocity.
We can write the equation for conservation of momentum as follows:
m1v1 + m2v2 = (m1+m2)*v
Where:
m1 is the mass of the first car (1210 kg)
v1 is the velocity of the first car (15.2 m/s, NE at 45.0°)
m2 is the mass of the second car (1540 kg)
v2 is the velocity of the second car (the unknown we are trying to find)
v is the velocity of the system after the collision (23.3 m/s, E at 0°)
We can use this equation to solve for the y-component of the second car's initial velocity (v2). First, we need to express the velocities in the x and y directions.
For the first car, we have:
v1x = v1 * cos(45°) = 15.2 m/s * cos(45°) = 10.6 m/s
v1y = v1 * sin(45°) = 15.2 m/s * sin(45°) = 10.6 m/s
For the second car, we have:
v2x = v2 * cos(0°) = v2 * 1 = 0 m/s
v2y = v2 * sin(0°) = v2 * 0 = 0 m/s
For the system after the collision, we have:
vx = v * cos(0°) = v * 1 = 23.3 m/s
vy = v * sin(0°) = v * 0 = 0 m/s
Now we can substitute these values into the equation for conservation of momentum and solve for v2y:
m1v1x + m2v2x = (m1+m2)vx
1210 kg * 10.6 m/s + 1540 kg * 0 m/s = (1210 kg + 1540 kg) * 23.3 m/s
12776.6 kgm/s + 0 kgm/s = 2750 kg * 23.3 m/s
12776.6 kgm/s = 2750 kg * 23.3 m/s
m1v1y + m2v2y = (m1+m2)vy
1210 kg * 10.6 m/s + 1540 kg * v2y = (1210 kg + 1540 kg) * 0 m/s
12776.6 kgm/s + 1540 kg * v2y = 0 kgm/s
12776.6 kgm/s = -1540 kg * v2y
v2y = -12776.6 kg*m/s / 1540 kg
v2y = -8.28 m/s
Therefore, the y-component of the second car's initial velocity is approximately -8.28 m/s.
Explanation:
what is the longest wavelength of electromagnetic radiation that will ejectphotoelectrons from sodium metal for which the work function is 2.28 ev?
The longest wavelength of electromagnetic radiation that will eject photo-electron from the sodium metal is 544 nm.
What is electromagnetic radiation ?Electromagnetic radiation consists of waves of electromagnetic field, which propagates through space and carries momentum and electromagnetic radiant energy.
Minimum energy required to knock out an electron from the surface of the metal is called the work function.
As we know that, W= hc/λ
h -- Planck's constant ; c -- Speed of light
and λ is Longest wavelength
Given, work function of sodium metal is 2.28 eV
As 1 eV = 1.6021 * 10^-19 J
=2.28 * 1.6021 * 10^-19
= 3.65 *10^-19 J
W= hc/ λ
3.65 *10^-19 = 6.62 *10^-34 * 3 *10^8/ λ
λ = 5.44 * 10 ^-7m
λ =544 nm
The longest wavelength of electromagnetic radiation that will eject photo-electron from the sodium metal is 544 nm.
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