To calculate the velocity of liquid flow, we need to use the equation Q = A*v, where Q is the volumetric flow rate, A is the cross-sectional area of the pipe, and v is the velocity of the liquid.
Given that 3.5g of liquid flows in 4mins, we need to convert it into volumetric flow rate. 1g of water is equal to 1mL, therefore 3.5g is equal to 3.5mL. Since 4mins is equal to 240s, the volumetric flow rate is 3.5/240 = 0.0146mL/s.
To calculate the velocity of the liquid, we need to use the pressure gradient of 10cm. The pressure gradient is the change in pressure per unit distance along the pipe. 1cm of water column is equal to 0.098kPa, therefore the pressure gradient is 0.098*10 = 0.98kPa/m.
Using the equation ΔP = ρgh, where ΔP is the pressure difference, ρ is the density of the liquid, g is the acceleration due to gravity, and h is the height of the pressure gradient, we can calculate the velocity of the liquid. Rearranging the equation to solve for v, we get v = √(2ΔP/ρ), where ΔP is the pressure difference across the pipe.
Assuming the density of water is 1000kg/m³, the velocity of the liquid is v = √(2*0.98/1000) = 0.044m/s.
Therefore, the velocity of liquid flow is 0.044m/s, given that 3.5g of liquid flows in 4mins with a pressure gradient of 10cm.
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5. Explain the law of conservation of energy using a relevant example from every day life.
The law of conservation of energy states that energy is neither created nor destroyed but is transformed from one form to another.
What is law of conservation of energy?The law of conservation of energy is the law that states that energy is neither created nor destroyed but is transformed from one form to another.
Examples of activities of everyday life that shows the conservation of energy include the following:
For loudspeaker, electrical energy is converted into sound energy.For a microphone, sound energy is converted into electrical energy.For a generator, mechanical energy is converted into electrical energy.When fuels are burnt, chemical energy is converted into heat and light energyLearn more about energy here:
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An example of the law of conservation of energy is a roller coaster.
What is the law of conservation of energy?The law of conservation of energy states that energy cannot be created or destroyed, only transferred or transformed from one form to another. This means that the total amount of energy in a closed system remains constant over time.
A roller coaster car gains kinetic energy as it moves down the track, but it also loses potential energy. At the bottom of the track, the car has the most kinetic energy and the least potential energy, while at the top of the track, it has the most potential energy and the least kinetic energy. However, the total amount of energy in the system remains constant.
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After a point charge, 7 Q, is placed inside the cavity of a conductor, electrostatic equilibrium is attained. After an additional charge of amount, -5Q, is placed on the surface of the inner cavity, electrostatic equilibrium is attained once again. What is the net charge on the inner and outer surfaces of the conductor, respectively
The net charge on the inner surface of the conductor is 7Q, while the net charge on the outer surface of the conductor is -5Q.
In electrostatic equilibrium, charges distribute themselves on the surface of a conductor in such a way that the electric field inside the conductor is zero. Based on this principle, we can analyze the situation step by step:
1. Initially, when the point charge of 7Q is placed inside the cavity of the conductor, the charge redistributes itself on the inner and outer surfaces of the conductor. In order to achieve electrostatic equilibrium, the charges on the inner and outer surfaces of the conductor must be such that the electric field inside the conductor is zero.
2. Since the conductor is electrically neutral, the net charge on the outer surface of the conductor will be equal in magnitude but opposite in sign to the charge inside the cavity. Therefore, the net charge on the outer surface is -7Q.
3. When an additional charge of -5Q is placed on the surface of the inner cavity, the charge redistributes again to achieve electrostatic equilibrium. The charge on the inner surface of the conductor will now be equal in magnitude but opposite in sign to the additional charge placed on the inner cavity. Hence, the net charge on the inner surface is -(-5Q), which simplifies to +5Q.
The net charge on the inner surface of the conductor is 5Q, while the net charge on the outer surface of the conductor is -7Q.
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Describe a ways car manufacturers try to reduce drag and why.
Aerodynamics is a way to reduce drag that uses car manufacturers.
What is aerodynamic ?
Aerodynamics is the motion of the air. airplane flies cause of aerodynamics.
Aerodynamics is the study of forces that are resulted by motion of the air.
To reduce the aerodynamic drag further, the manufacturers use character lines on the exteriors of the car's body right from its concept stage. These lines help the air to pass smoothly over the body and thus, reducing the air resistance.
cars have flat vertical face in front. When it moves through air, drag force directly proportional to the velocity applies on the car which opposes motion of the car. after studding aerodynamics when we make triangular like shape to the front body of the car, it cuts the air and front air goes from side of the car which reduces oppose to the motion, and car can have more speed.
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Assume a simply supported beam with span of 15m. It will be exposed to a dead load of 20kN/m (including self-weight) and a live load of 2kN/m along the full span. At the same time, it will be experiencing a concentrated dead load of 23kN + a live load of 1kN at midspan, as well as an additional dead load of 15kN located at 4m from the right support.
The beam has a rectangular cross-section with a width of 600mm and total height of 1000mm. The beam is reinforced with 10- 25M tensions bars at effective depth of 920 mm. The maximum aggregate size used is 20mm, and has the following material properties: f’c = 25MPa ,fy = 400 MPa.
Please perform the following task:
1) Draw the governing shear and bending moment diagram for the factored load.
2) Calculate the moment resistance of the cross section.
3) Comment if this cross section is adequately designed to resist the factored bending moment. (LRFD)
The values of all sub-parts have been obtained.
(1). The maximum factored load the beam can withstand is 45.2 kN/m.
(2). The moment resistance of the cross-section is 291735.65 Nm.
(3). The factored moment demand is 27939.6 Nm
1) To draw the governing shear and bending moment diagram for the factored load, we need to first calculate the maximum factored load that the beam can withstand.
The maximum factored load on the beam is given by:
Dead Load = 20 kN/m + 15 kN
= 35 kN/m.
Live Load = 2 kN/m + 1 kN
= 3 kN/m.
Total Factored Load = 1.2 x Dead Load + 1.6 x Live Load
= 1.2 x 35 kN/m + 1.6 x 3 kN/m
= 45.2 kN/m.
The maximum factored load the beam can withstand is 45.2 kN/m.
The shear force and bending moment diagrams for the given factored load can be obtained as shown below:
Shear Force Diagram:
Bending Moment Diagram:
2) To calculate the moment resistance of the cross-section, we can use the formula:
MR = σst A'(d - a/2) + 0.85f'c A''(d - a/2)
Where, σst = yield stress of tension steel [σst = fy / γst],
γst = safety factor for tension steel [γst = 1.15A']
A' = area of tension steel, [A'' = b(d - a)].
Where,
b = width of the beam [b = 600 mm],
d = total height of the beam [d= 1000 mm],
a = effective depth of tension steel [a = 920 mm]
f'c = compressive strength of concrete [f'c = 25 MPa],
MR = σst A'(d - a/2) + 0.85f'c A''(d - a/2)
MR = (400 / 1.15) x 10 x (1000 - 920/2) + 0.85 x 25 x 590 x (1000 - 920/2)
MR = 291735.65 Nm
The moment resistance of the cross-section is 291735.65 Nm.
3) To check if this cross-section is adequately designed to resist the factored bending moment (LRFD), we need to calculate the factored moment demand and compare it with the moment resistance.
The factored moment demand is given by:
MF = ϕ x Mu
Where,ϕ = resistance factor = 0.9, Mu = factored bending moment
Mu = 1.2 x Dead Load x L2 / 8 + 1.6 x Live Load x L2 / 8 + 1.2 x (Dead Load + Live Load) x L2 / 2
= 1.2 x 35 x 152 / 8 + 1.6 x 3 x 152 / 8 + 1.2 x 38 x 152 / 2
= 31044 Nm
MF = ϕ x Mu
= 0.9 x 31044
= 27939.6 Nm
The factored moment demand is 27939.6 Nm, which is less than the moment resistance of the cross-section, i.e., 291735.65 Nm.
Therefore, this cross-section is adequately designed to resist the factored bending moment.
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what state in the us tried to pass a law to legislate the value of pi
Answer: The fact is, there's only one known case in American history where someone actually tried to get his state legislature to redefine the value of pi. It happened in Indiana in 1897, and it had nothing to do with biblical values or building children's self-esteem through exactitude.
Tom drives on a highway and never changes his speed for the whole journey. He drives for 300 miles and it takes him 5 hours. What is Tom's speed on the highway?
Answer:
QESARDFRGTSRTATFREVERSRvrvqwqv
Explanation:
vfqfvcafbraf w rfdsd AEWvd a
find the direction of the dune of these two vectors
Given:
Vector A = 63.5 m at 90 degrees
Vector B = 101 m at 57.0 degrees
Let's find the direction of the sum of these two vectors.
To find the direction, let's first find the x- and y-components of the vectors.
• Vector A:
\(\begin{gathered} A_x=65.3cos90=0\text{ m} \\ A_y=63.5sin90=63.5\text{ m} \end{gathered}\)• Vector B:
\(\begin{gathered} B_x=101cos57.0=55\text{ m} \\ B_y=101sin57=84.7\text{ m} \end{gathered}\)For the sum of components, we have:
x = Ax + Bx = 0 + 55 = 55 m
y = Ay + By = 63.5 + 84.7 = 148.2 m
Now, to find the direction of the sum, we have:
\(\theta=tan^{-1}(\frac{y}{x})\)Plug in the values and solve for θ.
We have:
\(\begin{gathered} \theta=tan^{-1}(\frac{148.2}{55}) \\ \\ \theta=69.6^o \end{gathered}\)Therefore, the direction of the sum of the vectors is 69.6 degrees.
ANSWER:
69.6 degrees.
As shown in the diagram below, a 1 kg rock tied to a rope is
swung by a boy. This rock has a constant speed of 5 m/s,
and the length of the rope is 1 m. The rock's angular
momentum is
Answer:
Explanation:
Angular momentum has a formula of L = mvr. Fillingin:
L = (1.0)(5.0)(1.0)
L = 5.0 kg*m/s
A baseball is thrown 50.0m in 3.0s, what is the average speed of the baseball? Calculated answer is 16.666667! What is the correct answer when using significant figures?
Answer:
20m/s
Explanation:
Given parameters:
Distance of throw = 50m
Time = 3s
Unknown:
Average speed = ?
Solution:
Average speed is distance divided by time;
Average speed = \(\frac{distance }{time}\)
Insert the parameters and solve;
Average speed = \(\frac{50}{3}\) = 16.66667m/s = 20m/s
The resistivity of gold is 2.44 × 10-8 ohm · m at a temperature of 20°C. A gold wire, 0.5 mm in diameter and 44 cm long, carries a current of 380 ma. The number of electrons per second passing agiven cross section of the wire is closest to:
A) 6.3 × 10^15 B) 2.4 × 10^17 C) 1.2 × 10^22 D) 2.8 × 10^14 E) 2.4 × 10^18
The number of electrons per second passing a given cross section of the wire is closest to is 2.4 × 10¹⁷, so option (b) is correct.
What is current?It derived the namesake Ampère's law from this finding, which connects the size of the force between two conductors to the length of the wires and the current's strength. It designated the energy charge flow as "intensity courant," which is French for "current intensity," and assigned it the letter "I."
What is temperature ?
Temperature is a unit used to represent how hot or cold something is. It can be stated using the Celsius or Fahrenheit scales, among others. Temperature shows which way heat energy will naturally flow, i.e., from a hotter (body with a higher temperature) to a colder (body with a lower temperature) (one at a lower temperature) according to the energy.
Therefore, The number of electrons per second passing a given cross section of the wire is closest to is 2.4 × 10¹⁷, so option (b) is correct.
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!!! i'll give brainliest to whoever can answer this for me !!!
you have to match the letters in the picture to the list of energy types
Answer:
you have to match the letters in the picture to the list of energy types
An engineer is designing a small toy car that will be launched from rest. The engineer wants to maximize the kinetic energy of the car when it is launched by a compressed spring. He can only make one adjustment to the initial conditions of the car. Which of the following modifications to the car design would have the greatest effect on increasing the kinetic energy of the car?
A. Decrease the mass of the car slightly.
B. Increase the mass of the car slightly.
C. Decrease the launch speed of the car slightly.
D. Increase the weight of the car slightly.
The modifications to the car design that would have the greatest effect on increasing the kinetic energy of the car is to increase the mass of the car slightly (option B).
What is kinetic energy?Kinetic energy is the energy possessed by an object because of its motion. The kinetic energy equal (nonrelativistically) to one half the mass of the body times the square of its speed.
According to this question, an engineer is designing a small toy car that will be launched from rest. The engineer wants to maximize the kinetic energy of the car when it is launched by a compressed spring.
However, he can only make one adjustment to the initial conditions of the car. Considering the fact that the mass of an object is directly proportional to the kinetic energy.
This suggests that the modifications to the car design that would have the greatest effect on increasing the kinetic energy of the car is to increase the mass of the car slightly.
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the horizontal surface which the 1 block of mass 2kg slides frictionless the force of 29N acts on the block in a horizontal direction and the force of 87 N acts on the block at an angle as shown what is the magnitude of the resulting acceleration of the block (1) 5 (2) 2.2549 (3) 4.5 (4) 3.63636 (5) 5.90909(6) 6.89819 (7) 2.75 (8) 14.5455 (9)7.25 (10) 4.10714
The magnitude of the resulting acceleration of the block is (8), 14.5455 m/s²
How to determine magnitude?Use Newton's second law to solve this problem:
ΣF = ma
where ΣF = net force acting on the block, m = mass of the block, and a = acceleration of the block.
Resolve the force of 87 N into its horizontal and vertical components.
F_horizontal = F cosθ = 87 cos 30° = 75.366 N
F_vertical = F sinθ = 87 sin 30° = 43.5 N
The net force in the horizontal direction is:
ΣF_horizontal = 29 N
Using ΣF = ma, find the acceleration:
a = ΣF / m = 29 N / 2 kg = 14.5 m/s²
Therefore, the magnitude of the resulting acceleration of the block is:
a = 14.5 m/s²
The answer is (8) 14.5455, which rounds to 14.5 m/s².
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of the five masses in orbit around the central mass, the one that would require the most energy to escape from its orbit is
The energy required to escape an orbit is dependent on the mass of the object and the velocity at which it orbits.
Therefore, the mass that would require the most energy to escape from its orbit is the one with the greatest mass and the fastest velocity.
In this case, we know that there are five masses orbiting a central mass. Assuming that they are all at the same distance from the central mass, the mass that would require the most energy to escape its orbit would be the one with the greatest mass.
This is because the gravitational force between two masses is proportional to the product of their masses. The greater the mass of an object, the greater the gravitational force it exerts on other objects.
Therefore, the object with the greatest mass would require the most energy to overcome its gravitational pull and escape its orbit.
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Two forces of magnitude 10n and 20n acting at an angle of 30 degree. what will be the x component of their resultant force?
The resultant of the forces is 29 N. Option D
What is the resultant force?The resultant force is the force that acts in a given direction. Now we have two forces as enumerated in the question.
Thus;
Resultant = √(10)^2 + (20)^2 - [2 * 10 * 20 * cos (60 - 30))
Resultant = 29 N
Thus, the resultant of the forces is 29 N.
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Missing parts;
Two forces of magnitude 10N and 20N act on a body in directions making angles 30° and 60° respectively with x-axis what is the resultant force
A.17N
B. 19N
C. 23N
D. 29N
E. 37N
what is the direction of acceleration in uniform circular motion
The direction of acceleration in uniform circular motion is towards the center of the circle. The acceleration is always perpendicular to the velocity and is constantly changing the direction of motion.
The acceleration in uniform circular motion is constant in magnitude but changes its direction with the change in direction of velocity. It acts towards the center of the circle. The net force responsible for this acceleration is known as the centripetal force. The direction of centripetal force is always towards the center of the circle.
In uniform circular motion, the velocity vector of an object moving along a circular path changes continuously. However, the magnitude of velocity remains constant, i.e., it moves with constant speed. The direction of velocity changes because the direction of the object's motion changes. The acceleration in uniform circular motion is given by the equation:
a = v² / r
Where, v is the velocity of the object and r is the radius of the circular path. This equation implies that the magnitude of acceleration increases as the speed of the object increases or the radius of the circular path decreases. But the direction of acceleration is always towards the center of the circle.
The conclusion is that acceleration in uniform circular motion is towards the center of the circle. It is constant in magnitude but changes its direction with the change in direction of velocity. The net force responsible for this acceleration is known as the centripetal force. The direction of centripetal force is always towards the center of the circle.
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You pushes a 25kg box with 40 N of force, but the friction on the crate is 15 N. What is the net
force?
Answer:
25 N in the direction of your push
Explanation:
The friction force acts against your pushing force....it reduces the net amount of force you are exerting
Net force = 40 - 15 = 25 N
A car is sitting at a traffic light. When the light turns green, the car begins moving, accelerating at a constant rate. After 14.9 seconds the car has moved 266 meters. What is the acceleration of the car?
Answer:
The acceleration 2.4 m/s²
Explanation:
Given:
V₀ = 0 m/s - Initial vehicle speed
t = 14.9 s - Time
D = 266 m - Distance traveled by car
__________
a - ? - the acceleration
D = V₀·t + a·t² / 2;
V₀ = 0
D = a·t² / 2;
a = 2·D / t² = 2·266 / 14.9² ≈ 2.4 m/s²
An inclined plane of length 12m is used to pull a load of 3000N to height of 3m by applying an effort of 1000N. Calculate its MA, VR and efficiency. Also, find the work done in the machine
Answer:
MA = 4
VR = 3
e = 0.75 or 75%
work = 12000 [J]
Explanation:
The mechanical advantage in an inclined plane is defined as the relationship between the length of the inclined plane and the height of the plane with respect to the ground.
MA = L/h
MA = 12/3 = 4
Now the real advantage can be calculated as the relationship between the weight of the body and the force being applied.
VR = W/F
VR = 3000/1000
VR = 3
Efficiency can be calculated as the relationship between the real mechanical advantage over the ideal mechanical advantage.
e = VR/MA
e = 3/4
e = 0.75 or 75%
The work is defined as the product of the force by the distance, therefore we have:
work = F*d
work = 1000*12
work = 12000 [J]
If the lead can be extracted with 92.5fficiency, what mass of ore is required to make a lead sphere with a 7.00 cm radius? the density of lead is 11.4 g/c
If the lead can be extracted with 92.5 efficiency, the mass of ore is required to make a lead sphere with a 7.00 cm radius is 17.707 kg.
To find the mass of ore, the given values are,
The radius of the lead sphere is r = 7.0 cm,
The lead can be extracted with, η = 92.5% = 0.925 efficiency.
What is the Density?Density is the substance's mass per unit of volume.
We know the density of lead as,
⇒ p = 11.4 g/cm³ .
The volume of the lead sphere is,
V = 4/3πr³
= 4/3π(7)³
V = 1436.7 cm³.
Mass of the lead present in the lead sphere is,
m = p . V
= 11.4 × 1436.7
= 16379 g
m = 16.379 kg
From the expression of efficiency, we calculate the mass of the ore,
η = Mass of lead obtained / Mass of the ore to be taken
0.925 = 16.379 kg / Mass of the ore to be taken
Mass of the ore to be taken = 17.707 kg
If the lead can be extracted with 92.5 efficiency, the mass of ore is required to make a lead sphere with a 7.00 cm radius is 17.707 kg.
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How long does it take for the entire pattern of moon phases to be completed?.
Answer:
it takes our Moon about 29.5 days to complete one cycle of phases (from new Moon to new Moon).
It averages 29.531 days.
Is vaping bad for u?
Random
Answer:
yes
Explanation:
it damages your lungs
Answer:
yes it can mess you lungs up real bad
Mercury at 25°c flows over a 3-m-long and 2-m-wide flat plate maintained at 75°c with a velocity of 0. 01 m/s. Determine the rate of heat transfer from the entire plate?
The rate of heat transfer from the entire plate is 710.8 kW
The properties of mercury at the film temperature of (75+25)/2= 50°C
k = 8.83632 W/m °C
v = 1.056 × \(10^-^7\) m²/s
Pr = 0.0223
The local Nusselt number relation for liquid metals is given by
\(N_u =\frac{h_sx}{k} = 0.565 9Re_x Pr)^\frac{1}{2}\)
The average heat transfer coefficient for the entire surface can be determined from
\(h = \frac{1}{L} \int\limits^1_0 {h_x} \, dx\)
Substituting the local Nusselt number relation into the above equation and performing the integration we obtain
\(N_u = 1.13 (Re_s Pr)^\frac{1}{2}\)
The Reynolds number is
\(Re_L = \frac{VL}{v} = \frac{(0.01)(3m)}{1.056 * 10^-^7 m^2/s} = 0.028 * 10^7\)
Using the relation for the Nusselt number, the average heat transfer coefficient and the heat transfer rate are determined to be
Q = 710.8 kW
Therefore, the rate of heat transfer from the entire plate is 710.8 kW
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what is the wavelength of light that must be absorbed to accomplish this process?
The wavelength of light must be absorbed to accomplish photosynthesis process is blue light.
Photosynthesis is a process in which green plants, blue-green algae capture light energy and convert into chemical energy. Photosynthesis depends on absorption of light by pigments in the leaves.
Wavelength is distance between successive crests of a wave especially in electromagnetic waves. Most important is the chlorophyll a, which is the universal pigment but there are several accessory pigments which helps in the process of photosynthesis.
Plant pigment absorb light in the wavelength range of 700 nanometer to 400 nanometer. It is said to be as photo-synthetically active radiation. Violet and Blue have the shortest wavelength and most energy while red has the longest wavelength and carries the least amount of energy.
One photon with just right amount of energy bump an electron between orbitals and can excite a pigment. This is why different pigments absorb different wavelength of light.
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The complete question is,
What is the wavelength of light that must be absorbed to accomplish this photosynthesis process?
Answer:
Instead, photosynthetic organisms contain light-absorbing molecules called pigments that absorb only specific wavelengths of visible light, while reflecting others. The set of wavelengths absorbed by a pigment is its absorption spectrum.
A cessna 172 plane that is used to transport up to four VIPs in 2km in the air. If the potential energy of the VIP plane with three VIP onboard is 800 J, what is the combined massof the cessna and passanger
The combined mass of the cessna plane and the passangers, with a potential energy of 800 J is 0.041 kg.
What is mass?Mass can be defined as the quantity of matter a body contains.
To calculate the combined mass of the cessna plane and passangers, we use the formula below
Formula:
P.E = Mgh......... Equation 1Where:
P.E = Potetial energy M = Combined mass of the cessna plane and the passangersg = Acceleration due to gravityh = Height.Make M the subject of the equation
M = P.E/gh............. Equation 2From the question,
Given:
P.E = 800 Jh = 2 km = 2000 mg = 9.8 m/s²Substitute these values into equation 2
M = (800)/(200×9.8)M = 0.041 kgHence, the combined mass of the cessna plane and the passangers is 0.041 kg.
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I need some help with this.
\(I = \frac{V}{R} \\ \)
Thus :
\(I = \frac{160}{2} \\ \)
\(I = 80 \: \: A\)
So :
\(V = 160\)
\(I = 80\)
\(R = 2\)
The stars of the milky way are all near a great circle on the celestial sphere. This great circle.
The stars of the milky way are all near a great circle on the celestial sphere. This great circle is called milky circle.
Milky Way Galaxy, large spiral system consisting of several hundred billion stars, one of which is the sun.It takes its name from the Milky Way, the irregular luminous band of stars and gas clouds that stretches across the sky as seen from Earth.Although Earth lies well within the Milky Way Galaxy, astronomers do not have as complete an understanding of its nature as they do of some external star systems. Although most stars in the Galaxy exist either as single stars like the Sun or as double stars.Milky circle is the great circle in which all stars of milky way are present.To know more about galaxy visit:
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The stars of the milky way are all near a great circle on the celestial sphere. This great circle is called milky circle.
What is Milky Way Galaxy ?Milky Way Galaxy, large spiral system consisting of several hundred billion stars, one of which is the sun.It takes its name from the Milky Way, the irregular luminous band of stars and gas clouds that stretches across the sky as seen from Earth.Although Earth lies well within the Milky Way Galaxy, astronomers do not have as complete an understanding of its nature as they do of some external star systems.Although most stars in the Galaxy exist either as single stars like the Sun or as double stars.Milky circle is the great circle in which all stars of milky way are present.To know more about Milky Way visit: https://brainly.com/question/13956361
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The box is applying 22 N of force on the table, but the box is not moving 22 N If there is a downward force of 22 N, why is the box not moving downward?
Answer:
A reaction force
Explanation:
The box is not moving downward because the table is applying an equal and opposite amount of force on the box.
This is the premise of Newton's third law of motion which states that "action and reaction are equal and opposite".
The action force impacted by the downward pull on the table is being cancelled out by the upward force of the table.
The net force in the vertical direction will therefore be 0N This way, the box does not move downward.What is the magnetic force on a proton that is moving at 2.5 × 107 m/s up
through a magnetic field that is 0.12 T and pointing toward you? The charge
on a proton is 1.6 x 10-19 C. Use F = qvx B sin(e).
A. 4.8 x 10-13 N left
OB. 4.0 × 10-12 N down
x
C. 4.8 x 10-13 N right
D. 4.0 × 10-12 N up
X
4.8× 10^-11 weber is the magnetic force on a proton that is moving at 2.5 × 10^7 m/s up through a magnetic field that is 0.12 T
F=qBv
q=1.6 x 10^-19 C
v=2.5 × 10^7 m/s
B=0.12T
F=qBv
F=1.6 x 10^-19 C×2.5 × 10^7 m/s×0.12T
F=4.8× 10^-11 weber
A magnetic force, attraction, or repulsion is produced by the motion of electrically charged particles. It is the underlying force that causes phenomena like the operation of electric motors and the attraction of magnets to iron. There are electric forces acting on stationary electric charges, and there are magnetic and electric forces acting on moving electric charges. The magnetic force between two moving charges is the effect of a magnetic field produced by one charge on another charge.
The intensity of the magnetic field B1 produced by the first moving charge, the sine of the angle theta, the second particle's charge q2, its velocity v2, and the magnetic force F are all inversely related in this hypothesis.
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A car traveling at 35.6m/s crashes into a concert barrier and comes to a stop in 0.35 seconds. Calculate the average force applied to the 75kg driver.A 3.2kg steel ball traveling at 4.1m/s strikes a second ball of a mass 2.3kg Initially at rest. Calculate the velocity of the second ball when the first one continues traveling in the same direction with a speed of 1.5m/s2 balls of putty are shot towards one another. Ball 1 has a mass of 4.3kg and is moving at 18.6m/s . Ball 2 has a mass of 5.8kg and is moving at 9.5m/s. They collide and stick together. Calculate their final combine velocity.I really appreciate those attempting the problems. I do know the answers but I’m unaware of the steps to get there. Please include all formulas in your response and steps so I can learn and understand.Check your answer:7629N3.6m/s2.46m/sThank you all!
The force on the driver is 7629 N. The velocity of the second ball is 3.6 m/s. The combined velocity of the balls is 13.37 m/s.
We have to find the acceleration using;
v = u - at
v = final velocity = 0 m/s
u = initial velocity = 35.6m/s
a = acceleration = ?
t = time = 0.35 s
u = at
a = u/t = 35.6m/s / 0.35 s
a = 101.7 ms-2
The force on the driver = 75kg × 101.7 ms-2 = 7629 N
Using the principle of conservation of momentum;
Momentum before collision = momentum after collision
m1u1 +m2u2 = m1v1 + m2v2
Hence
(3.2 × 4.1) + 0 = (3.2 × 1.5) + 2.3v2
13.12 = 4.8 + 2.3v2
13.12 - 4.8 = 2.3v2
v2 = 13.12 - 4.8/2.3
v2 = 3.6 m/s
Using the principle of conservation of linear momentum;
m1u1 + m2u2 = m1v1 + m2v2
(4.3 × 18.6) + (5.8 × 9.5) = (4.3 + 5.8) v
v = 79.98 + 55.1/10.1
v = 13.37 m/s
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