Answer:
Greater thab 10 m/s
Explanation:
As the rollercoaster moves in
Help!!!!!!!!! Attached question
QUICK WILL GIVE BRAINLIEST
PLS HELP! Answer these questions pls. I will mark BRAINLIEST, FIVE STARS AND THANKS. The second question in the pic has three answers. *50 POINTS!*
Answer:
First one is hydrogen and oxygen
Second one is color change, solid dissolves, and temperature increases
Explanation:
Electrolysis is the process of using electricity to decompose water into hydrogen and oxygen.
Odors and change of states are physical changes while the rest are chemical changes.
Hope this helped!
You want to build a generator to light a bulb. You have a fairly large permanent magnet, some wire, and a lightbulb. You may build it as follows. Wind the wire for about 200 turns into a coil of 15 cm radius. Tape up the coil and place it in the region between the poles of the magnet that produces a 0.10 T magnetic field. Connect a hand crank to the coil and rotate it at a rotational speed ω.
What is the required rotational speed ω to generate a peak voltage of 6 V?
The required rotational speed ω to generate a peak voltage of 6 V is 4.24 rad/s
The induced peak voltageThe induced peak voltage in the generator is given by ε = NABω where
N = number of turns of coil = 200, A = area of coil = πr² where r = radius of coil = 15 cm = 0.15 m, B = magnetic field strength = 0.10 T and ω = rotational speed of coilRotational speed
Making ω subject of the formula, we have
ω = ε/NAB
ω = ε/Nπr²B
Substituting the values of the variables into the equation, we have, given that ε = 6 V
ω = ε/Nπr²B
ω = 6 V/(200 turns × π(0.15 m)² × 0.10 T)
ω = 6 V/(200 turns × 0.0225π m² × 0.10 T)
ω = 6 V/(200 turns × 0.0225π m² × 0.10 T)
ω = 6 V/0.45π turns-m²T
ω = 6 V/1.4137 turns-m²T
ω = 4.244 rad/s
ω ≅ 4.24 rad/s
The required rotational speed ω to generate a peak voltage of 6 V is 4.24 rad/s
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2 A rectangular storage tank 4 m long by 3 m wide is filled with paraffin to a depth
of 2 m. Calculate:
a the volume of paraffin
c the weight of paraffin
b the mass of paraffin
d the pressure at the bottom of the tank due
to the paraffin
1m
For a rectangular storage tank filled with paraffin to a depth of 2 m, the volume, weight, mass of paraffin, and pressure at the bottom of the tank are:
a. The volume is 24 m³.
b. weight is 240,000 N,
c. mass is 24,490 kg, and
d. pressure is 23,530 Pa.
a) The volume of paraffin in the rectangular storage tank can be calculated using the formula:
Volume = Length x Width x Depth
Given:
Length = 4 m
Width = 3 m
Depth = 2 m
Substituting the values into the formula, we have:
Volume = 4 m x 3 m x 2 m
Volume = 24 m³
Therefore, the volume of paraffin in the tank is 24 cubic meters.
b) The weight of the paraffin can be calculated using the formula:
Weight = Volume x Density x Acceleration due to gravity
The density of paraffin varies, but we can assume a typical value of 10,000 kg/m³. The acceleration due to gravity is approximately 9.8 m/s². Substituting these values into the formula:
Weight = 24 m³ x 10,000 kg/m³ x 9.8 m/s²
Weight = 240,000 N
Therefore, the weight of the paraffin in the tank is 240,000 Newtons.
c) The mass of the paraffin can be calculated using the formula:
Mass = Density x Volume
Substituting the given values:
Mass = 10,000 kg/m³ x 24 m³
Mass = 24,490 kg
Therefore, the mass of the paraffin in the tank is 24,490 kilograms.
d) The pressure at the bottom of the tank due to the paraffin can be calculated using the formula:
Pressure = Weight / Area
The area of the bottom of the tank is equal to the length multiplied by the width. Substituting the values:
Area = 4 m x 3 m
Area = 12 m²
Pressure = 240,000 N / 12 m²
Pressure = 20,000 Pa
Therefore, the pressure at the bottom of the tank due to the paraffin is 20,000 Pascals (Pa).
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What real-world examples show not work being done? Can you think of examples other than resisting the force of gravity?
Answer:
Work is defined as a force doing a movement, for example, if with a force F we move an object a distance D, the work done is:
W = F*D
(note, the force is causing the movement, the product here is a dot product, this means that if the force and the displacement are perpendiculars, the product is zero)
So the examples where there are not work being done may be:
We do not have any movement:
For example, you can go to a wall in your house and push it really hard.
There is a force, but the wall will not move, so we have D = 0
and W = F*D = F*0 = 0
Because we have no motion.
Another case is where the force and the direction of motion are perpendiculars.
If we have for example a car, moving at a constant speed, and you push it sidewise (perpendicular to the direction of movement) we have a force being applied and movement, but those are in different directions (so the force does not cause the movement) so we dont have work being done.
A steel column is 3 m long and 0.4 m diameter. It carries a load of 50 MN. Given that the
modulus of elasticity is 200 GPa. Calculate the compressive stress.
The compressive stress in the steel column is found to be approximately 397.6 MPa.
The formula for calculating the area of a circle can be used to determine the steel column's cross-sectional area (A),
A = π*(d/2)², diameter of the column is d,
A = π*(0.4/2)²
A = 0.1257m²
The compressive stress (σ) in the column can be calculated using the formula, σ = F/A, F is the load carried by the column is F.
σ = 50 MN/0.1257m²
σ = 397.6 MPa
Therefore, the compressive stress in the steel column is approximately 397.6 MPa.
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Stefan pushes a cart with three books so it just reaches the end of a track. He puts six books onto the cart. What must he use next time so the cart reaches the end of the track?
Answer:
if its adding its 9 if its multiplying its 18 if its division its 2
On the water surface, there are two sources of oscillating waves of the same phase located at A and B, emitting two coherent waves of wavelength λ. Let Δ be the line perpendicular to AB at B. On Δ there are 16 interference maxima, the distance between the two closest and farthest interference maxima is 2.71 cm and 229.55 cm, respectively. . Which of the following is the length of line segment AB closest to?
Two or greater sources are said to be coherent if they emit waves that have the identical wavelength (or frequency) and amplitude and which maintain a steady phase difference.
Do two coherent sources have equal wavelength?If two sources have the identical wavelength, frequency, and segment difference, they are said to be coherent. Therefore, we can conclude that coherent sources have the identical wavelength.
Two microwave coherent factor sources emitting waves of wavelenths λare positioned at 5λdistance apart. The interference is being observed on a flat non-reflecting surface alongside a line passing through on sources ,in a course perpendicular to the line joining the two sources
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https://brainly.com/question/12495315#SPJ1When the applied force is 150 N and the friction is 94 N, what is the motion? A. Accelerated motion b. Decelerated motion c. No motion D. Uniform motion
Answer:
the answer to this question is Accelerated motion
Who won Miami Dolphins or Las Vegas raiders
Answer:
miami dolphins.
Explanation:
......
Answer:
miami :(
Explanation:
You are observing the poles along the side of the road as described in the opening storyline of the chapter. You have already stopped and measured the distance between adjacent poles as 40.0 m. You are now driving again and have activated your smartphone stopwatch. You start the stopwatch at t 5 0 as you pass pole #1. At pole #2, the stopwatch reads 10.0 s. At pole #3, the stopwatch reads 25.0 s. Your friend tells you that he was pressing the brake and slowing down the car uniformly during the entire time interval from pole #1 to pole #3.
(a) What was the acceleration of the car between poles #1 and #3?
(b) What was the velocity of the car at pole #1?
(c) If the motion of the car continues as described, what is the number of the last pole passed before the car comes to rest?
(a) The acceleration of the car between poles #1 and #3 is - 0.106 m/s²
(b) The velocity of the car at pole #1 is 4.533 m/s
What is the difference between acceleration and velocity and speed?Speed is defined as the rate of change of distance, or, more simply, the amount of distance (m) traveled in a specific amount of time (s). Acceleration is defined as the rate of change of velocity per unit of time, while velocity is the rate of change of displacement (change of distance in a given direction with regard to time).
Given:
Distance between adjacent poles = 40m
The stopwatch reads 10s at pole 2
The stopwatch reads 25s at pole 3
a) Acceleration of the car between the poles
P₁ P₂ P₃
← 40 m → ← 40 m →
V₁ V₂ V₃
For P₁ to P₂
and 40m = V₁ × T₁ - 1/2 at²
40 m = V₁ × 10 - 1/2 a(10s) t²
10 v₁ - 50 a = 40 ⇒ (1)
For P₁ to P₃
80 = V₁ × 25 - 1/2 × a (25)²
25 V₁ - 312 - 5a = 80 ⇒ (2)
By solving the above 2 equations
V1 = 4533 m/s and a = 0.106667 m/s²
a) Acceleration = - 0.106 m/s²
b) Velocity of the pole is 4.533 m/s
c) The last pole passed before the car comes to rest is pole 3.
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If in the figure below, the friction between the block and the incline is negligible, (a) how much must the object on the right weigh if the 200-N block is to remain at rest? Ans: 115 N (b) if the system remains at rest when F= 220 N. What are the magnitude and direction of the friction force on the 200-N block? Ans: 105 N down the incline 200 N Fw 35.0⁰
The magnitude of the acceleration and its direction however depends on the resultant force.
What is the resultant force?
In a system of forces, the resultant force is the force that has the same effect in magnitude and direction as all the forces acting together.
In an inclined plane, the friction, weight and applied force all act together on the object. The magnitude of the acceleration and its direction however depends on the resultant force.
This question is incomplete as the diagrams are missing hence the numerical values can not be computed.
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what is scientific learning
Answer:
the learning which is gained through observation and experimentation
1.
How does centripetal force due to gravity keep a satellite in orbit?
It continuously changes the direction of the satellite.
It provides the thrust to launch the satellite into space.
It prevents the satellite from falling toward Earth.
It keeps increasing the speed of the satellite.
Answer:
1st one,.
It changes the direction,
And satellite falls in earth infinity,
Its total workdone is zero
Answer:
It continuously changes the direction of the satellite.
Explanation:
our Welcome (; (:
One of the frequencies used to transmit and receive cellular telephone signals in the United States is 985 MHz. What is the wavelength in meters of these radio waves
Answer:
approximately 304358
Explanation:
wavelength = speed / frequency
speed of an electromagnetic wave is 299,792,458 m/s in a vacuum
Jackie studied stresses that affect earth's crust. How is compression of rock different from shearing?.
"Compression of rock is nothing but squeezing the rock together and shearing is pushing the rock in opposing directions."
It squeezes the boulder as a whole and should cause the pulls to shear. This is because compression causes the weight necessary for rocks to be squeezed. Additionally, the rock's draws shouldn't be spaced apart. It shouldn't be going in opposing ways either.
When rocks are compressed together, they fold, fracture, or even shatter. Compression stress is the most prevalent stress at convergent plate boundaries. There is stress when rocks are being torn apart. Under stress, rocks either lengthen or fragment.
Due to the compression pushing the hanging wall up in relation to the footwall, if the fault arises in a scenario of compression, it will be a reverse fault.
Compressional stresses cause a rock to shorten. A rock elongates or pulls apart as a result of tensional pressures. Shear forces cause rocks to slide past one another.
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A 2000 kg car moves at a speed of 30 m/s. To reach this speed, it was necessary to burn 0.1 l of gas. Burning gas provides 30 MJ/l of source energy. Determine the energy efficiency (in %) of this car.
The energy efficiency of the car is approximately 16.7%.
The energy efficiency of a car is the ratio of the useful work output (in this case, the kinetic energy of the car) to the total energy input (in this case, the energy released by burning the gasoline). The equation for energy efficiency is:
Efficiency = Useful work output / Total energy inputThe useful work output can be calculated as the kinetic energy of the car using the equation:
KE = 0.5mv²where m is the mass of the car and v is its velocity.
Substituting the given values:
KE = 0.5 x 2000 kg x (30 m/s)² = 900,000 JThe total energy input is the energy released by burning 0.1 L of gasoline, which is:
Total energy input = 0.1 L x 30 MJ/L = 3 MJ = 3,000,000 JSubstituting these values into the equation for efficiency:
Efficiency = (900,000 J / 3,000,000 J) x 100% = 0.3 x 100% = 16.7%Therefore, the energy efficiency of the car is approximately 16.7%.
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Two capacitors C1 = 1.5 μF and C2 = 5 μF are in series. If the charge stored by C1 is 10 C, determine the charge stored by C2. a. 4 C b. 1.5 C c. 10 C d. 3 C
Answer: I buleve it’s B 1.5C
Explanation: I took the quiz
Hope this helps and have a nice day!
What is scintillator
Answer:
Scintillators are materials that are able to convert high energy radiation such as X or gamma-rays to a near visible or visible light. They are widely used as detectors in medical diagnostics, high energy physics and geophysical exploration (ref. Knoll).
https://web.stanford.edu › scintillators
What are scintillator materials? - Stanford: Advanced Optical Ceramics Laboratory
What is the displacement Δx of the particle?
The change in the displacement is 70 m
What is the change in displacement?Recall that the displacement is obtained as the product of the velocity and time. We have the velocity at two intervals.
At v1, the displacement can be obtained from;
x1 = 0.5 * 20 = 10 m
At v2, the displacement can be obtained as;
x2 = 2 * 40 = 80 m
Now
Δx = 80 m - 10 m = 70m
Thus the change in the displacement is 70 m
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Can you use an adjustable gas lift leg (Similar to office chair) on the moon?
Heather and Matthew take 45 s to walk eastward along a straight road to a store 72 m away. What is their average velocity?
Answer:
v = 1.6 m/s
Explanation:
Given that,
Distance, d = 72 m
Time taken, t = 45 s
We need to find their average velocity. Average velocity of an object is given by total distance divided by total time taken.
\(v=\dfrac{d}{t}\\\\v=\dfrac{72\ m}{45\ s}\\\\v=1.6\ m/s\)
So, their average velocity is 1.6 m/s.
21. If € = 8.0 V, at what rate is the emf providing energy to the circuit shown?
15 2
10 22
12 V
+
1022.
a. 8.4 W
b. 7.6 W
C.5.6 W
d. 11 W
e. 2.0 W
Answer:
c. 5.6 W
Explanation:
We can write the Kirchoff's voltage law (KVL) equations for the circuit using i1 for the clockwise current in the left loop, and i2 for the clockwise current in the right loop. Then the circuit equations are ...
i1 (10 +10) -i2(10) = 12
-i1(10) +i2(10 +15) = 8
Using Cramer's rule to find i2, we have ...
i2 = (12(-10) -8(20))/((-10)(-10) -(25)(20)) = -280/-400 = 0.7
The power supplied by the Emf is ...
(8 V)(0.7 A) = 5.6 W . . . . . matches choice C
Shannon and Chris push on blocks with identical force. SHannon's block is twice as massive as Chris'. After pushing for 5 seconds, who did more work?
An 8.0 Kg mass is placed at = 3 where should a 10 Kg mass be placed along the − so that the center of mass will be located ay = 4.5?
Answer:
Therefore, the 10 kg mass should be placed at x = 5.7 m along the x-axis to achieve a center of mass located at y = 4.5 m.
Explanation:
To find the position along the x-axis where a 10 kg mass should be placed such that the center of mass is located at y = 4.5, we can use the formula for the center of mass:
x_cm = (m1 * x1 + m2 * x2) / (m1 + m2)
Here, m1 and x1 represent the mass and position of the 8 kg mass, respectively. m2 is the mass of the 10 kg mass, and we need to find x2, its position.
Given:
m1 = 8 kg
x1 = 3 m
x_cm = unknown (to be found)
m2 = 10 kg
y_cm = 4.5 m
Since the center of mass is at y = 4.5, we only need to consider the y-coordinate when calculating the center of mass position along the x-axis.
To solve for x2, we can rearrange the formula as follows:
x2 = (x_cm * (m1 + m2) - m1 * x1) / m2
Substituting the given values:
x2 = (x_cm * (8 kg + 10 kg) - 8 kg * 3 m) / 10 kg
Simplifying:
x2 = (x_cm * 18 kg - 24 kg*m) / 10 kg
Now, we can set the y-coordinate of the center of mass equal to 4.5 m and solve for x_cm:
4.5 m = (8 kg * 3 m + 10 kg * x2) / (8 kg + 10 kg)
Simplifying:
4.5 m = (24 kg + 10 kg * x2) / 18 kg
Multiplying both sides by 18 kg:
81 kg*m = 24 kg + 10 kg * x2
Subtracting 24 kg from both sides:
10 kg * x2 = 81 kg*m - 24 kg
Dividing both sides by 10 kg:
x2 = (81 kg*m - 24 kg) / 10 kg
Simplifying:
x2 = 8.1 m - 2.4 m
x2 = 5.7 m
(brainlest?) ples:(
Answer:
the 10 kg mass should be placed at x = -2.4 m to achieve a center of mass at y = 4.5 m.
Explanation:
To find the position along the x-axis where the 10 kg mass should be placed so that the center of mass is located at y = 4.5, we can use the principle of the center of mass.
The center of mass of a system is given by the equation:
x_cm = (m1x1 + m2x2) / (m1 + m2),
where x_cm is the x-coordinate of the center of mass, m1 and m2 are the masses, and x1 and x2 are the positions along the x-axis.
Given:
m1 = 8 kg,
x1 = 3 m,
m2 = 10 kg,
y_cm = 4.5 m.
To solve for x2, we need to find the x-coordinate of the center of mass (x_cm) by using the y-coordinate:
y_cm = (m1y1 + m2y2) / (m1 + m2),
where y1 and y2 are the positions along the y-axis.
Rearranging the equation and substituting the given values:
4.5 = (83 + 10y2) / (8 + 10).
Simplifying the equation:
4.5 = (24 + 10*y2) / 18.
Multiplying both sides by 18:
81 = 24 + 10*y2.
Rearranging the equation:
10*y2 = 81 - 24,
10*y2 = 57.
Dividing both sides by 10:
y2 = 5.7.
Therefore, the y-coordinate of the 10 kg mass should be 5.7 m.
To find the x-coordinate of the 10 kg mass, we can use the equation for the center of mass:
x_cm = (m1x1 + m2x2) / (m1 + m2).
Substituting the given values:
x_cm = (83 + 10x2) / (8 + 10).
Since the center of mass is at x_cm = 0 (the origin), we can solve for x2:
0 = (83 + 10x2) / (8 + 10).
Rearranging the equation:
83 + 10x2 = 0.
24 + 10*x2 = 0.
10*x2 = -24.
Dividing both sides by 10:
x2 = -2.4.
How much force is needed accelerate a 35 kg sled from 30 m/s to 65 m/s in 0.4 seconds?
Answer:
F = 3062.5 N
Explanation:
Given that,
The mass of a sled, m = 35 kg
The speed increase from 30 m/s to 65 m/s in 0.4 seconds.
We need to find the force needed to accelerate the car.
Net force is given by :
F = ma
where
a is acceleration of the car.
\(F=\dfrac{m(v-u)}{t}\\\\F=\dfrac{35\times (65-30)}{0.4}\\\\F=3062.5\ N\)
So, the net force is 3062.5 N.
Rosa uses a spring scale to pull a cart along a track for 2 meters. The spring scale shows the force exerted on the cart while being pulled. She uses metal plates to vary the mass of the cart, and motion sensors to calculate the average speed and acceleration of the cart.
She records the results in a table.
Rosa claims that the force needed to accelerate an object is proportional to the mass of the object. Which statement BEST supports or disproves Rosa’s claim using the data from the table?
A- Rosa’s claim is false. When the mass of the cart increases by 1.0 kg, the force on the cart increases by more than 1.0 kilogram.
B- Rosa’s claim is false. Even though the mass and the force increase in each trial, the acceleration of the object remains the same.
C-Rosa’s claim is true. The acceleration for each trial is the same. Doubling the mass of the cart causes the force to double in order to maintain the same rate of acceleration.
D-Rosa’s claim is true. Each time the mass increases by 1.0 or 2.0 kilograms, the force increases by 1.0 or 2.0 newtons respectively. This causes the rate of acceleration to remain constant.
Rosa’s claim is true. The acceleration for each trial is the same. Doubling the mass of the cart causes the force to double in order to maintain the same rate of acceleration.
According to Newton's second law of motion, the force applied to an object is directly proportional to the product of the mass and acceleration of the object.
F = ma
\(a = \frac{F}{m} \\\\\frac{F_1}{m_1} = \frac{F_2}{m_2} \\\\\frac{2}{1} = \frac{F_2}{2} \\\\F_2 = 4 \ N \\\\when \ the \ mass \ increases \ by \ 2\\\\m_1 = 2 \ kg,\ \ m_2 = 2(m_1) = 2(2) = 4 \ kg\\\\F_1 = 4 \ N, \ \ F_2 = 2(F_1) = 2(4) = 8 \ N\)
Thus, we can conclude that from the table, Rosa’s claim is true. The acceleration for each trial is the same. Doubling the mass of the cart causes the force to double in order to maintain the same rate of acceleration.
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Answer:
is C
Explanation:
A student is standing on a skateboard that is not moving. The total mass of the student and the skateboard is 50 kilograms. The student throws a ball with a mass of 2 kilograms forward at 5 m/s. Assuming the skateboard wheels are frictionless, how will the student and the skateboard move?
Therefore, the student and the skateboard will move backward by 5m/s to counterbalance the forward momentum.
Momentum explained.
According to to law of conservation of momentum, the total momentum before the ball is thrown is equal to the final momentum after the ball is thrown.
Momentum is mass × velocity.
The initial momentum is
mass of student + mass of skate ball * velocity.
50kg * 0 = 0kh m/s
Final momentum
mass of student + mass of skate ball * velocity.
The velocity is 5m/s
According to the question, the student and the skateboard move backward which counter balance the forward movement.
mass * -v
momentum = 50kg * -v
Therefore, the student and the skateboard will move backward by 5m/s to counterbalance the forward momentum.
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-0,32 m - 4.2 At the instant the marble leaves the canon, the canon starts moving backwards (recoils) at a constant velocity. 4.1 State the principle of conservation of linear momentum in words. that is stationary canon is placed 0,32 m from a fixed bare After firing, the canon takes 0,33 s to collide with a barrier at a distance of 0,32 m. Calculate the speed the: W< 1 >E S 4.2.1 Canon collides with the barrier
The cannon will completely stop when it collides with the barrier.
To calculate the speed at which the cannon collides with the barrier, we can follow these step-by-step calculations:
Determine the initial momentum of the system.
Since the cannon is initially stationary, the initial momentum is zero.
Apply the conservation of linear momentum.
According to the principle of conservation of linear momentum, the initial momentum of the system (zero) is equal to the final momentum of the system. The final momentum is the momentum of the cannon after firing.
Calculate the final momentum of the system.
Let's assume the mass of the cannon is represented by 'm' and the final velocity of the cannon is represented by 'v'. The final momentum of the system is given by: final momentum = m × v.
Set up the equation.
Since the initial momentum is zero, we have: 0 = m × v.
Solve for the final velocity of the cannon.
Dividing both sides of the equation by 'm', we get: v = 0.
Interpret the result.
The calculation shows that the final velocity of the cannon is zero. This means that the cannon comes to a complete stop when it collides with the barrier.
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for a creep test, sketch and explain the response of the following models including the initial (elastic) strain, the final strain before unloading, and the final strain a long time after unloading: A. Two Spring in series, B. Maxwell Mode C. Burgers Models (Maxwell model in series with Kevin Model)
In the creep test the specimen is subjected to a constant state of stress and the resulting variation in the strain as a function of time(t) is determined. The first and the third model can only be solved.
How does the Burgers model work?A typical viscoelastic material is commonly described using the Burgers Model, a general model of viscoelasticity. The term "creep" refers to plastic deformation under a constant force that is time- and temperature-dependent. In order to depict the viscoelastic behavior of polymers, the Burgers model, a traditional linear viscoelastic model, is utilized. The Maxwell model and the Kelvin-Voigt model combine to create this model, which is also referred to as the "four-element model" (connected in series).
The strain variation after the stress is removed corresponds to the recovery test in the creep test.
The sketch is attached below (29):
A) Two spring series tests:
It is also a linear relationship between strain before and after will be the same. It simply says that the spring fola jook of two springs. The strain is linear.
The sketch is attached below (30):
C) Linear elements used to capture the "minimum amount of behavior for many polymers/tunes are elastic recovery, and molecular ship. Rubber elasticity, related elasticity
The sketch is attached below (31):
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