6. A mother and daughter are walking through a revolving door together. The door has a rotational speed of 12 rpm. The mother has a tangential velocity of 6 m/s and she is 3 meters from the center of the door. The daughter is 1 meter from the center of the door. If the mother experiences a centripetal force of 900 N, what is her mass?

2A

Given ,

Resistance=60

V=12

V=IR

I=V/R

I=120/60=2A

The pace at which electrons flow past a location in a complete electrical circuit is defined as current. At its most fundamental, current Means flow.

An ampere (AM-pir), sometimes known as an amp, is the international unit for measuring current. It denotes the number of electrons (also known as "electrical charge") that pass across a location in a circuit over a specific time period.

A current of one ampere indicates that one coulomb of electrons—that is, 6.24 billion billion (6.24 x 1018) electrons—moves across a circuit in one second. The method is comparable to determining how many gallons move through a single spot in a pipe in one minute (gallons per minute, or GPM).

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Answer:

The bag of sand

Explanation:

I think it is the bag of sand because according to the definition of impulse, impulse is the average force acting on a particule when an external force is being acted on it.

The electric force between two point charges is given by the equation

\(F=k*q_1*q_2/r^2\)

The interaction between two things is measured by the physical quantity known as force. It is a vector quantity, and the sign F is frequently used to denote it. When an object interacts with another object, it feels a push or a pull.

where r is the distance between the charges, q1 and q2 are their magnitudes, and k is the Coulomb constant.

When we enter the problem's specified values, we obtain

\(2.2N=8.99*10^9\ N*m^2/C^2*q*-2q/(1.4 m)^2\)

which simplifies to

q = -0.500 N/C.

Thus, the magnitude of charge q is 0.500 N/C.

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The speed of light is the fastest anything in the universe can go if it is traveling through space. Much faster than light can break that speed limit.

We can never go faster than light. Or, to be more precise, in a vacuum, we can never travel at the speed of light. In other words, the 299,792,458 m/s upper limit of the universe's speed is the speed at which all other particles must move in order to exist.

In a vacuum, light travels at a speed of 3 108 m/s. About 8 minutes pass before sunlight reaches Earth.

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The work-energy theorem states that the change in the kinetic energy of an object will be equal to the net work done on the object.

Mathematically, it can be expressed as;

ΔKE = W

Where; ΔKE represents the change in kinetic energy of the object,

W represents the net work done on the object.

This theorem states that when work is done on an object, it results in a change in its kinetic energy. If work is done on an object, its kinetic energy increases, and if work is done by an object, its kinetic energy decreases.

This theorem is a fundamental principle in physics that relates the concepts of work and energy, and it is often used to analyze the motion and behavior of objects in various physical systems.

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The moment M applied to the disc to hold the system in equilibrium is 0.09 Nm.

To calculate the moment M applied to the disc that holds the system in equilibrium, we can use the principle of moments. The principle of moments states that the sum of the clockwise moments about a point is equal to the sum of the counterclockwise moments about the same point.

Let's consider point C as the pivot point. The clockwise moments are produced by the weight of BC and the unknown moment M, while the counterclockwise moments are produced by the weight of AB.

The weight of BC can be calculated as W_BC = linear density * length = 1 kg/m * 0.3 m = 0.3 kg.

The clockwise moment is given by M_clockwise = W_BC * BC = 0.3 kg * 0.3 m = 0.09 Nm.

Since the system is in equilibrium, the clockwise moments must balance the counterclockwise moments. Therefore, the counterclockwise moment produced by the weight of AB is also 0.09 Nm.

Hence, the moment M applied to the disc to hold the system in equilibrium is 0.09 Nm.

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Answer:

The parents and offspring all have phenotype ww. That leaves 100% probability of short wings and 0% long wings.

Explanation:

If long wings are a dominant trait, that means short wings are recessive. If two short winged flies are crossed, each of their phenotypes are ww. Therefore, each of their offspring also have phenotype ww, or short wings.

Answer:

All of the above

Explanation:

At start it has only PE

 PE is converted to KE

        at bottom all of the PE is now KE

            KE and PE along the way = PE at the start

Answer: Velocity is a vector; the word decreasing only applies to its magnitude (not its direction) which is called speed. If speed is increasing and direction is not changing, then acceleration is positive. If speed is constant then acceleration is zero. If speed is decreasing then acceleration is negative.

Explanation:

Answer:

static friction

Explanation:

which is told in the question that its in rest.

The vector showing an upward force is the normal force on the box on the table. The vector A which is downward to the box is static friction. Hence, option c is correct.

Friction is the resistive force to the motion of an object. The term static friction refers to friction between two or more stationary solid objects. Static friction, for instance, can stop an object from rolling down a sloped surface.

The coefficient of kinetic friction is typically lower than the coefficient of static friction, commonly abbreviated as s. According to certain theories, solid surfaces' many length scales of surface roughness are what cause static friction.

As a result of these characteristics, which are referred to as asperities, which are present at nanoscale dimensions, only a small portion of the apparent or nominal contact area is really covered by true solid-to-solid contact.

Here, the box is at rest and it can be affected by the static friction from the surface of the table.

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Answer:

wavelength is = 0.05m

frequency is = 639.65 Hz

Explanation:

F= 3V/4L

(3 x 342)/(4 x 0.401) = 639.65Hz

Wavelenght =4L/3

wavelength =(4x0.401)/3 = 0.05m

The characteristics of standing waves in tubes allows to find the results for the third harmonic of the clarinet are:

Standing waves are formed when a wave collides with an obstacle and is reflected, the sum of the incident wave and the reflected wave forms a standing wave that does not move in time. There are several types of obstacles:

They indicate that the clarinet is approximated to a tube with one end open and the other closed, therefore at the closed end we have a node and at the open end a antinode, in the adjoint we see a diagram of the resonance, the expression for the resonance should be:

      L = \(\frac{\lambda}{4}\)                1st harmonic

       L = \(3 \frac{\lambda}{4}\)             3th harmonic

      L = \((2n-1) \frac{\lambda}{4}\)    General term

where L is the length of the tube, λ the wavelength and n an integer.

Ask for the wavelength of the third harmonic m = 3

     λ = \(\frac{4L}{3}\)

     λ  = \(\frac{4 \ 0.401}{3}\)  

     λ  = 0.5365 m

The speed of the wave is related to the product of the wavelength and the frequency.

     v = λ f

     f = \(\frac{v}{\lambda}\)  

Let's calculate.

     f = \(\frac{342}{0.5365}\)  

     f = 639.7 Hz

In conclusion, using the characteristics of standing waves in tubes we can find the results for the third harmonic of the clarinet are:

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Answer:

this stuff hard no cap

Explanation:stop cheating cuhhh

When Sally puts on wool socks and rubs her feet on a nylon carpet, static electricity builds up through a process involving the movement of electrons. The friction between the wool socks and the nylon carpet causes electrons from the wool socks to move to the carpet, resulting in Sally and her socks gaining a negative charge.

The correct answer would be the friction causes electrons from the wool socks to move to Sally, giving Sally a negative charge.

The friction between the wool socks and the nylon carpet causes electrons from the wool socks to move to the carpet, resulting in Sally and her socks gaining a negative charge. This is due to the phenomenon known as the triboelectric effect.

The triboelectric effect occurs when two materials come into contact and then separate. During the rubbing process, the atoms in the two materials interact, causing the transfer of electrons between them. In this case, the wool socks have a greater affinity for electrons compared to the nylon carpet. As a result, electrons from the socks are transferred to the carpet, leaving the socks with a positive charge and the carpet with a negative charge.

Sally, wearing the wool socks, experiences an accumulation of excess electrons on her feet, giving her a negative charge. This excess negative charge on her body can lead to static electricity-related phenomena, such as experiencing a shock when touching a metal object or seeing her hair stand on end when near certain surfaces.

It's important to note that the movement of electrons determines the charge distribution during the triboelectric effect. In this scenario, electrons move from the wool socks to the nylon carpet, resulting in Sally and her socks gaining a negative charge.

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Let velocity of larger car = v;

mass of larger car = 30 kg;

mass of smaller car = 20 kg

velocity of smaller car = 6.0 m/s

Now according to law of conservation of momentum---

using this formula ,we get

Therefore velocity of larger car after collision is 4 m/s in opposite direction of smaller car .

Final answer is 4.0 m/s

The potential energy of the roller coaster is 176,400 J (joules).

The potential energy of an object is given by the formula PE = mgh, where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height or vertical position of the object.

In this case, the roller coaster is at a peak of 20m and has a mass of 900kg. The acceleration due to gravity, g, is approximately 9.8 \(m/s^2\).

Using the formula, we can calculate the potential energy:

PE = mgh

= (900 kg)(9.8 \(m/s^2\))(20 m)

= 176,400 J

Therefore, the potential energy of the roller coaster is 176,400 J (joules).

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The net force on an object will be equal to 27.1 N. The net force is in the right direction.

Force can be described as the influence that changes the state of the body of motion or rest. The SI unit of force is Newton and force is a vector quantity. Force can change the direction as well as the speed of the moving object.

The force can be calculated from the product of the mass (m) and acceleration (a) of an object. The mathematical equation of the second law of motion for force is written as:

F = ma

The force P is acting in the left direction or pulling the object in the left direction. The force Q pulls the object in the right direction.

The net force  \(=F_{P} -F_{Q}\) = 12.5 - 39.6

The net force = 27.1 N   in the right direction.

Therefore, the net force of 27.1 N  on the object is pulling the object in the right direction.

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Your question is incomplete, most probably complete question was,

An object is pushed to the left with a force of P and pushed to the right with a force of Q. where P = 12.5 and Q = 39.6.

What is the net force on the object? If the net force is to the right, enter a positive value and if it is to the left, enter a negative value.

The direction of this vector is 135° (measured counterclockwise from +x-axis).

Direction is a set of instructions or guidelines that provide a means of achieving a goal. It is a form of communication that can be used to motivate, inform, and lead people in a particular direction. Direction can come from a variety of sources, such as a leader, a manager, or an individual who is seeking to accomplish something. Direction is often used to help people find the right path to success and can be used to provide clarity and focus in order to achieve desired outcomes. Direction can also involve setting expectations and providing feedback or coaching to help people stay on track and reach their goals.

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The AMA is the quotient between the input and output forces and is given by:

Where:

Therefore, the AMA is decreased if the input force is increased. If in a machine the friction force increases due to low maintenance then the required input force would increase and therefore, the AMA would decrease.

In a first-class lever we have the following:

We can calculate the ratio between input and output forces by adding the torque around the fulcrum:

Adding the product of the input force and input distance:

Now, we divide both sides by the input force:

Now, we divide both sides by the output distance:

Therefore, the AMA is:

Therefore, if in the lever we increase the input distance or decrease the output distance we would increase the AMA.

Answer:

How do you find the net force?

Explanation:

i think this is want you asked for?

Answer:

strontium has 50 neutrons

Answer:

the answer is 50 hope it helps =)

Explanation:

Answer:

The value is \(E = 3.5619 *10^{5} V/m \)

Explanation:

From the question we are told that

The height of the airplane is \(h = 2010 \ m\)

The first charge concentration is \(Q = 46.9 \ C\)

The height of the first charge concentration is \(h_1 = 4090 \ m\)

The second charge concentration is \(Q_2 = −59.7 \ C\)

The height of the second charge concentration is \(h_1 = 570 \ m\)

The electric field due to the first charge concentration is

\(E_1 = \frac{k * |Q_1|}{(h_1 -h)^2}\)

Here k is the Coulomb constant given in the question

\(E_1 = \frac{8.98755*10^9 * |46.9|}{(4090 - 2010)^2}\)

\(E_1 = 9.7429 *10^{4} \ V/m\)

The electric field due to the second charge concentration is

\(E_2 = \frac{k * |-59.7|}{(h -h_2)^2}\)

\(E_2 = \frac{8.98755*10^9 * |-59.7|}{(2010 - 570)^2}\)

\(E_2 = 2.5876 *10^{5} V/m\)

Generally the superposition principle can be applied in this question as follows

\(E = E_1 + E_2\)

=> \(E = 9.7429 *10^{4}+ 2.5876 *10^{5} \)

=> \(E = 3.5619 *10^{5} V/m \)

The diameter and the radius of the field that Victoria ran around would be = 80m and 40m respectively.

The total distance covered by Victoria = 750meters

The number of time she ran around the field = 3

Therefore the circumference of the field = 750/3 = 250m

The formula for the circumference of circle = 2πr

That is ;

250 = 2×3.14 ×r

make r the subject of formula;

r = 250/ 6.28

r = 39.8 = 40 cm

Therefore the diameter = 2×40 = 80m

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Answer:

Objects between the source and observer produce possible shadows known as the umbra and the penumbra.

The umbra is a totally shadowed area, no light travels directly from the source to the observer.

The penumbra is a partially shadowed are where some of the source light travels directly to the observer an some of the source light is blocked from the observer (the object blocking the light is not a point object).

The question apparently refers to the differences seen by the observers.

Given what we know, we can confirm that the bands indicate that the canyon was carved due to erosion caused by moving water.

The bands are the result of sediments being deposited as the canyon was being formed. These sediments are deposited by the running water that carves the canyon. This results in horizontal bands that can tell us much about the history of the canyon as well as the river that formed it.

Therefore, we can confirm that the bands indicate that the canyon was carved due to erosion caused by moving water.

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Answer:

λ = V / f      the wavelength versus the frequency

V = f λ      and V (speed) proportional λ    for a fixed frequency

F = f^2 * (M / L) * λ^2 = (f * λ)^2 * (M / L)^2    force (tension) on string at a given frequency

F2 / F1 = (λ2 / λ1)^2    other items are constant

Let λ1  = 6   then λ2 must be 3/2 λ1   for a constant length

F2 / F1 = (6 / 4)^2 = 9/4

The tension must be increased to 9 / 4 of  the original tension

Check: if the frequency is fixed then V will be larger for a larger wavelength  (situation 2)

One can also write V = (F / (M / L))^1/2

Then for fixed M  L    

F2 / F1 = (V2 / V1)^2

Since V = f λ      Velocity is proportional to λ  for a fixed frequency

Then if V2 / V1 = 3 / 2     F2 = 9/4 F1

Answer: The lowest outside temperature for which the sleeping bag provides adequate protection is approximately 89.61°C below the hiker's skin temperature of 34°C.

Explanation:

To find the lowest outside temperature for which the sleeping bag provides adequate protection, we need to determine the rate of heat loss through conduction and compare it to the heat loss the hiker can safely tolerate.

The rate of heat loss through conduction can be calculated using the formula:

Q = (k * A * ΔT) / d

Where:

Q is the rate of heat transfer (in Watts)

k is the coefficient of thermal conductivity (0.019 Wm¹¹°C-¹ in this case)

A is the surface area (1.3 m² in this case)

ΔT is the temperature difference (in this case, the difference between the skin temperature and the outside temperature)

d is the thickness of the sleeping bag (30 mm, which needs to be converted to meters by dividing by 1000)

Let's plug in the values:

Q = (0.019 * 1.3 * ΔT) / (30 / 1000)

The hiker can safely lose 85 W of heat, so we can set up the equation:

85 = (0.019 * 1.3 * ΔT) / (30 / 1000)

To solve for ΔT, we can rearrange the equation:

ΔT = (85 * (30 / 1000)) / (0.019 * 1.3)

ΔT ≈ 89.61°C

0.0041m/s and 0.00917 mile/hr. is the average velocity.

If an object moves with an average speed of v for time t, then the distance traveled by this object is s= v.t

Average speed and time are given in the task. So you can use this formula to calculate the marathon distance.

Velocity or speed  is defined as: The rate of change of the object's position in any direction. Velocity is measured as the ratio of distance traveled and time traveled. Velocity is a scalar quantity because it has only direction and not magnitude.

time =2hr, 1min, 39s  s= 0.030km

t= 7299s    s=30m

v=s/t=30/7299

=0.0041m/s.

in mile per hour = 0.00917 mile/hr

So feom the above equations solved the answer is 0.0041m/s and 0.00917 mile/hr.

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\({\mathfrak{\underline{\purple{\:\:\: Given:-\:\:\:}}}} \\ \\\)

\(\:\:\:\:\bullet\:\:\:\sf{Initial \ velocity \ (u) = 13 \ m/s }\)

\(\:\:\:\:\bullet\:\:\:\sf{Distance \ (s) = 400 \ m }\)

\(\:\:\:\:\bullet\:\:\:\sf{ Acceleration = 4 \ m/s^2}\)

\(\\\)

\({\mathfrak{\underline{\purple{\:\:\:To \:Find:-\:\:\:}}}} \\ \\\)

\(\:\:\:\:\bullet\:\:\:\sf{The \:Final \:velocity \:of \:the\: body }\)

\(\\\)

\({\mathfrak{\underline{\purple{\:\:\: Calculation:-\:\:\:}}}} \\ \\\)

☯ Using 3rd equation of motion

\(\\\)

\(\dashrightarrow\:\: \sf{ {v}^{2} = {u}^{2} +2as }\)

\(\\\)

\(\dashrightarrow\:\: \sf{ {v}^{2} = {13}^{2} + 2 \times 4 \times 400 }\)

\(\\\)

\(\dashrightarrow\:\: \sf{{v}^{2} = 169 + 3200 }\)

\(\\\)

\(\dashrightarrow\:\: \sf{ {v}^{2} = 3369 }\)

\(\\\)

\(\dashrightarrow\:\: \sf{ v = \sqrt{3369} }\)

\(\\\)

\(\dashrightarrow\:\: \underline{\boxed{\sf{ v = 58.04 \: m/s }}}\)

\(\\\)

\({\mathfrak{\underline{\purple{\:\:\:Additional \:Information:-\:\:\:}}}} \\ \\ \)

☢ Equations Of Motion

\(\\\)

\(\boxed{

\begin{minipage}{3 cm}$\\

\sf{\:\:\star\:\:v = u +at} \\ \\

\sf{\:\:\star\:\:s = ut + \dfrac{1}{2}\:at^{2} }\\ \\

\sf{\:\:\star\:\:v^{2} = u^{2} + 2as}\\ \\

\sf{\:\:\star\:\:s = \dfrac{1}{2} (u + v)t}\\$

\end{minipage}

} \)

\(\\\)

\(\sf{Where,}\)

\(\:\:\:\:\bullet\:\:\:\textsf{v = Final velocity}\)

\(\:\:\:\:\bullet\:\:\:\textsf{u = Initial velocity}\)

\(\:\:\:\:\bullet\:\:\:\textsf{a = Acceleration}\)

\(\:\:\:\:\bullet\:\:\:\textsf{s = Distance}\)

\(\:\:\:\:\bullet\:\:\:\textsf{t = Time taken}\)

Answer:

256 N

Explanation:

formula of centripetal force = mv²/r

m= 2kg

v= 8m/s

r= 0.5m

mv²/r = 2×8²/0.5 = 256N