6 →
If an object goes from 30 to 25 degrees Celcius, what is the change in Temperature?
7
How much energy is needed to heat 35 g of gold from 10 to 50 Degrees celcius?
129
40
1806
0. 35
8
Specific heat is.
a
Answers
6. The change in temperature is -5°C, which indicates a decrease of 5°C. and 7. The energy needed is 180.6 Joules.
6. To find the change in temperature, you need to subtract the final temperature from the initial temperature:
Change in temperature = Final temperature - Initial temperature
Change in temperature = 25°C - 30°C
Change in temperature = -5°C
The change in temperature is -5°C, which indicates a decrease of 5°C.
7. To calculate the energy needed to heat 35g of gold from 10 to 50°C, you need to use the formula:
Energy = mass × specific heat × change in temperature
The specific heat of gold is 0.129 J/(g·°C). First, find the change in temperature:
Change in temperature = Final temperature - Initial temperature
Change in temperature = 50°C - 10°C
Change in temperature = 40°C
Now, plug in the values into the formula:
Energy = (35g) × (0.129 J/(g·°C)) × (40°C)
Energy = 180.6 J
The energy needed is 180.6 Joules.
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Related Questions
Pls answer it ASAP I need it today
Activity 6: Write the uses of each cleaning compound.
1. Detergent-
2. Solvent cleaners-
3. Avid cleaners-
4. Abrasives-
Answers
Cleaning solvents are used to remove oil, grease, solder flux, and other contaminants.
Acid cleaners are generally used to remove mineral deposits and are useful for descaling dishwashers or removing rust from restroom facilities.
Abrasive uses
* Buffing.
* Honing.
* Drilling.
* Grinding.
* Sanding.
* Polishing.
* Cutting.
* Sharpening.
difference between MKS system and CGS system
Answers
Answer:
MKS stands for Meter, Kilogram and second. In this system of unit mass is given in Kilogram, length in meter and time in second. ... CGS system stands for Centimeter- Gram- Second system. In CGS system, length is measured in centimeters mass is measured in grams and time is in seconds.
a ball is kicked at an angle of 40 degrees with the ground with the initial velocity of 15m/s. the ball reaches point b after 1.5 seconds. 1. what is the initial velocity in the y-direction? 2. what is the final velocity in the x-direction (at point b)? 3. what is the range, xb, in meters? 4. what is the height, hb, when the ball reaches point b, in meters?
Answers
(1) The initial velocity in the y-direction is 9.64 m/s.
(2) The final velocity in the x-direction is 11.5 m/s.
(3) The range, xb, of the ball is 22.6 m.
(4) The maximum height reached by the ball is 4.74 m.
What is the initial vertical component of the velocity?The initial vertical component of the velocity is calculated using the following kinematic equation.
Vy = V sinθ
where;
V is the initial velocity θ is the angle of projection of the ballVy = V sinθ
Vy = ( 15 m/s ) x ( sin 40 )
Vy = 9.64 m/s
The final velocity in the x-direction is calculated as follows;
Vₓf = Vxi = V cosθ
where;
Vₓf is the final horizontal velocity Vₓi is the initial horizontal velocityVₓf = ( 15 m/s ) x ( cos 40 )
Vₓf = 11.5 m/s
The range of the ball is calculated as follows;
R = v² sin (2θ) / g
R = ( 15² sin (2 x 40) ) / 9.8
R = 22.6 m
The maximum height reached by the ball is calculated as;
H = v² sin²θ / 2g
H = ( 15² x ( sin 40 )² ) / (2 x 9.8)
H = 4.74 m
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Jaune moves North 15 meters, South 5 meters, then North 8 meters. How far is Jaune DISPLACED?
Answers
Answer:
Displacement = 7 meters
Explanation:
Given that,
Jaune moves North 15 meters, South 5 meters, then North 8 meters. We need to find the displacement of Jaune.
The attached figure shows the motion of Jaune.
We know that, Displacement = final position - initial position
Initially, Jaune traveled 15 meters due North and finally, he travel 8 meters North.
Displcement = 15 m - 8 m
Displacement = 7 m
So, the displacement of Jaune is 7 meters.
Challenge Exercises: The following exercises are of a greater difficulty than the earlier ones, though still matched to our course objectives. These exercises are not intended to prepare you for test questions, instead they expose you to more complex, real-world scenarios. You may struggle more with these questions than the Routine exercises. Remember your problem solving strategies! Read carefully and repeatedly. What words are familiar in the problem statement? What terms have been defined in the class, versus what is being provided to you within the exercise itself? Who can you work with for assistance? 8. The power generated by a stationary cyclist depends on both the resistance on the fly-wheel and the cadence (i.e. how fast the cyclist is pedaling). A University of Calgary study looked at fixed levels of exertion and drew curves for the relationship between resistance and cadence. Let's examine the relationship between resistance and cadence at a fixed activity level (i.e. perceived level of exertion). The article cites that they used a Hill function of the form (R+a) · (v + b) = b(Ro + a), where R is the resistance and Ro is the maximal resistance (both in Newtons), v is the cadence (in revolutions per minute), and a and b are other constants. (a) For the lowest activity level used in the study, the maximal resistance was 75 Newtons. Also, when resistance dropped to 0, cadence was 180 rpm; when resistance was 10 Newtons, cadence dropped to 100 rpm. Use this data to find values of the constants a and b. (b) Including the constants from part (a), express the formula from the article explicitly in the form of R as a function of v. (c) What is the long-term behavior of R? Is this behavior meaningful in context?
Answers
a) Given that the Hill function is (R+a) · (v + b) = b(Ro + a)Here, R = resistance, Ro = maximal resistance, v = cadence, a, b are constantsGiven, maximal resistance, Ro = 75 Newtons,Resistance, R = 0, cadence, v = 180 rpmResistance, R = 10 Newtons, cadence, v = 100 rpmWe have to calculate a and b.For R = 0, v = 180, 10a + 180b = 75b, and b = (10a/−100 + 9/2)For R = 10, v = 100, 20a + 100b = 750 − 75
a.Substitute the value of b in the above equation.20a + 100(10a/−100 + 9/2) = 750 − 75a20a − 10a + 450 = 750 − 75a10a = 300a = 30Substitute the value of a in the equation (10a/−100 + 9/2) = b(10/−100 + 3/2)b = 15/16Therefore, the value of a is 30 and the value of b is 15/16. Hence, we got the value of a and b.b) Here the Hill function is (R+a) · (v + b) = b(Ro + a)Substituting the value of a and b in the equation, we get (R + 30) (v + (15/16)) = (15/16)(75+30)R + 30 = (15/16)105R = (105(v + (15/16)) − 2475)/15R = (7(v + (15/16)) − 165)/15
Therefore, the formula for R as a function of v is given by R = (7(v + (15/16)) − 165)/15.c) Long-term behavior of R is the value of R when v approaches infinity. Thus, the limiting value of R when v approaches infinity is Ro, i.e. 75 Newtons. Thus, the long-term behavior of R is that as the cadence increases, the resistance approaches its maximal value. This behavior is meaningful in the context of a stationary bicycle since maximal resistance represents the level of physical resistance that a cyclist may face.
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A girl rides her cycle round a circular track of diameter 60 m. The track is banked at 15 ∘
to the horizontal. The coefficient of friction between the track and the tyres of the cycle is 0.25. Modelling the girl and her cycle as a particle of mass 60 kg moving in a horizontal circle, find the minimum speed at which she can travel without slipping.
Answers
A girl rides her cycle round a circular track of diameter 60 m. The track is banked at 15° to the horizontal. The coefficient of friction between the track and the tyres of the cycle is 0.25. Modelling the girl and her cycle as a particle of mass 60 kg moving in a horizontal circle, the minimum speed at which she can travel without slipping is 13.64 m/s.
To find the minimum speed at which the girl can travel without slipping, we need to consider the forces acting on her and her cycle as they move in a circular track.
The forces acting on the girl and her cycle are the gravitational force (mg), the normal force (N), and the frictional force (f). The frictional force provides the centripetal force necessary to keep the girl moving in a circular path.
The normal force can be resolved into two components: the vertical component (N⊥) and the horizontal component (N∥). The vertical component balances the gravitational force, while the horizontal component provides the centripetal force.
Mass of the girl and cycle (m) = 60 kg
Diameter of the circular track (d) = 60 m
Bank angle (θ) = 15 degrees
Coefficient of friction (μ) = 0.25
Find the normal force components:
N⊥ = mg cos(θ)
N∥ = mg sin(θ)
The frictional force:
f = μN⊥
The frictional force (f) provides the centripetal force required for circular motion:
f = m(v² / r)
Here, v is the velocity and r is the radius of the circular track. The radius is:
r = d / 2
Combining the equations, we have:
μN⊥ = m(v² / r)
Substituting the values we have:
μmg cos(θ) = m(v² / (d / 2))
v² = (μmg cos(θ) / m) * (d / 2)
v² = (μg cos(θ)) * (d / 2)
v = √((μg cos(θ)) * (d / 2))
v = √((0.25 * 9.8 * cos(15)) * (60 / 2))
v ≈ 13.64 m/s
Therefore, the minimum speed at which the girl can travel without slipping is approximately 13.64 m/s.
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a ball is thrown directly downward with an initial speed of 8.85 m/s, from a height of 29.9 m. after what time interval does it strike the ground?
Answers
It takes approximately 0.902 seconds time interval for the ball to strike the ground.
To determine the time interval it takes for the ball to strike the ground, we can use the equations of motion. Since the ball is thrown directly downward, we can assume that the initial velocity (u) is negative (-8.85 m/s), and the acceleration due to gravity (g) is positive (9.8 m/s²).
The equation to calculate the time of flight (t) is
t = (v - u) / g
Where:
v = final velocity (when the ball strikes the ground)
u = initial velocity
g = acceleration due to gravity
In this case, the final velocity when the ball strikes the ground is 0 m/s (as it comes to rest). So, substituting the given values into the equation, we have
t = (0 - (-8.85)) / 9.8
t = 8.85 / 9.8
t = 0.902 seconds
Therefore, it takes approximately 0.902 seconds for the ball to strike the ground.
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A very light small ball (with a speed of 5m/s) collides with a bowling ball that is at rest. The small ball bounces back, and the bowling ball moves very slowly. Which one, small ball or bowlling ball experiences the greater magnitude impulse during the collision
Answers
The bowling ball experiences the greater magnitude impulse during the collision since it is initially at rest and is given the momentum of the small ball which has a speed of 5m/s.
The impulse of the bowling ball can be calculated using the equation impulse = change in momentum = mvf - mvi, where m is the mass of the bowling ball, vf is its final velocity, and vi is its initial velocity.
Since the bowling ball is initially at rest (vi = 0), the impulse can be calculated as mvf = m(5m/s) = 5m^2/s. The impulse of the small ball can be calculated in the same way, giving an impulse of 5m^2/s. Therefore, the bowling ball experiences a greater magnitude impulse during the collision.
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Help quick
How does the ramp produce mechanical advantage?
A it reduces the amount of input force needed to do a certain amount of work
B it reduces the distance over which the input force needs to be applied
C it reduces the amount of useful work done on objects move it up the ramp
D what is the overall amount of work done on object moving up the ram
Answers
C it reduces the amount of useful work done on objects move it up the ramp
Mark needs to clean up a broken glass on the floor. He can use a hand brush or a broom. Why should he choose the broom?
He will apply force to the broom over a shorter distance than he would to the brush.
He will have to move the broken glass less distance with the broom than he would with the brush.
He will do less work with the broom than he would with the brush.
He will use less force with the broom than he would with the brush.
Answers
When a car comes to a stop its kinetic energy is converted to internal energy in its brakes, heating them up. true or false?
Answers
True. When a car comes to a stop, its kinetic energy is converted into internal energy, primarily in the form of heat, in its brakes.
This process is known as braking or deceleration. As the brakes apply frictional force to the moving wheels, the kinetic energy of the car is transferred to the brake components, causing them to heat up. This conversion of energy from kinetic to internal energy is necessary to bring the car to a stop. The heat generated in the brakes is dissipated into the surrounding environment, typically through conduction, convection, and radiation, allowing the car to cool down.
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A box rests on a horizontal, frictionless surface. A girl pushes on the box with a force of 18 N to the right and a boy pushes on the box with a force of 12 N to the left.The box moves 4.0 m to the right. Find the work done by (a) the girl, (b) the boy, and (c) the net force
Answers
The work done by the boy is 0 N
The work done by the girl is 72 N
The Net force is 6 N
What frictional force?The force preventing sliding against one another of solid surfaces, fluid layers, and material components is known as friction.
There are various kinds of friction such as dry and fluid friction.
Two solid surfaces in touch are opposed to one another's relative lateral motion by dry friction.
Work done = force * distance
The work done by the boy = 12 * 0
The work done by the boy = 0 N
The work done by the girl = 18 * 4
The work done by the girl = 72 N
Net force = 18 - 12
Net force = 6 N
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Nina and ryan each ran at a constant speed for a 100-meter race. Each runner’s distance for the same section of the race is displayed on the left. Who had a head start, and how big was the head start?.
Answers
"Nina and Ryan each ran at a constant speed for a 100-meter race. Each runner’s distance for the same section of the race is displayed on the left." In the event of things, Ryan had a headstart of 10min. This is further explained below.
What is headstart?Generally, headstart is simply defined as a head start is a benefit received or awarded from the outset.
In conclusion, "When racing 100 meters, both Nina and Ryan maintained a steady pace. On the left is a chart showing the distance covered by each runner during the same segment of the race." Whatever the case may be, Ryan was given a 10-minute head start.
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Answer: Ryan had a head start of 10 meters.
Explanation: Trust me
Consider the formula d=\dfrac{m}{V}d= V m d, equals, start fraction, m, divided by, V, end fraction, where ddd represents density, mmm represents mass and has units of kilograms \left( \text{kg}\right)(kg)left parenthesis, k, g, right parenthesis, and VVV represents volume and has units of cubic meters \text{(m}^3)(m 3 )left parenthesis, m, start superscript, 3, end superscript, right parenthesis. Select an appropriate measurement unit for density
Answers
Density is a physical property and is measured in a wide variety of units. However, the most suitable measurement unit for density is the kg/m³. The formula to measure the density of an object is given byd = m/VWhere d represents density, m represents mass, and V represents volume.
The units of density will depend on the units of mass and volume. For example, if the mass is measured in kilograms and the volume is measured in cubic meters, the density will be measured in kilograms per cubic meter (kg/m³). The kg/m³ measurement is the most suitable for density because it gives the mass of an object per unit of volume in a standardized form.
In general, density is expressed in terms of mass per unit volume and the SI units of mass and volume are kilograms and cubic meters, respectively. Therefore, the appropriate measurement unit for density is kg/m³.
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What is dark energy? How is dark energy related to the theory of the multiverse?
Answers
Answer:
In the 1980s, astronomers turned to multiverse theory to explain the “luckily small” amount of dark energy in our universe. According to cosmologist's theories, this small amount of dark energy appeared to enable our universe to host life, while most universes in the multiverse couldn't.
Explanation:
Which equation correctly relates mechanical energy, thermal energy, and total
energy when there is friction present in the system?
A. Ethermal
Ethermal
=
ME
B. Ethermal = Etotal - ME
C. Ethermal = ME - Etotal
D. Ethermal = Etotal + ME
Answers
Answer:
B
This is because frictional energy is similar to thermal energy in a system. Therefore the thermal energy produced is equal to
describe the reflection of the pulse from a fixed point
Answers
When a pulse encounters a fixed point, such as a wall or a rigid boundary, it undergoes reflection. Reflection occurs when the pulse bounces back upon reaching the fixed point.
During reflection, the pulse experiences a change in direction but retains its original shape and properties. The incident pulse approaches the fixed point and interacts with it. As a result, an equal and opposite pulse is generated and travels back in the opposite direction.
The behavior of the reflected pulse depends on the nature of the incident pulse and the properties of the medium it travels through. If the pulse is inverted (upside-down) before reflection, the reflected pulse will also be inverted. Similarly, if the incident pulse is right-side-up, the reflected pulse will maintain the same orientation.
The reflection process follows the law of reflection, which states that the angle of incidence (the angle between the incident pulse and the normal to the fixed point) is equal to the angle of reflection (the angle between the reflected pulse and the normal). This law ensures that energy and momentum are conserved during the reflection process.
In conclusion, when a pulse encounters a fixed point, it undergoes reflection, resulting in the generation of an equal and opposite pulse traveling in the opposite direction. The reflected pulse retains the same shape and properties as the incident pulse, following the law of reflection.
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If a car traveled 100 km in 2 hr, what was its average speed in km/hr?
average speed =
d =
t =
Answers
Answer:
Average speed will be 50km/hr
Explanation:
Distance/Time
100/2
50kmph
plz mark as brainliest
Answer:
50km/hr
Explanation:
avgspeed=Δdistance/Δtime
Δd=100km
Δt=2hr
=100km/2hr
=50km/hr
A naval station sees waves with 5.6 meters between crests, and these waves hit the station every 4.25 seconds.
What is the speed of these water waves??
Answers
Answer:
the formula v = f×lambda.
v= 4.25× 5.6
therefore speed is
23.8 meters per second
Two astronauts (each with mass 70 kg) push off each other in space. One astronaut carries 46.7 kg of equipment and moves away with a speed of 0.3 m/s.
Calculate the velocity of the other astronaut.
Answers
Answer:
Kindly, Refer to the attachment...
will the particle move to the right (in the positive x -direction) or to the left (in the negative x -direction), and why?
Answers
Yes, the particle moves in the positive x-direction (to the right) or the negative x-direction (to the left) due to the forces of attraction and repulsion.
When the particle's velocity is positive, it is travelling to the right. When the velocity is negative, it also moves to the left. A body with a higher mass may have a lower moment of inertia than a body with a lower mass. This relies on the mass distribution and axis with respect to which we are computing the moment of inertia. In real-world situations, we frequently avoid dealing with particles.
The time it takes for a constant force to bring a particle to rest, on the other hand, is represented by its momentum.
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Will mark brainliest
Answers
Answer:
v = u +at
Explanation:
The equation that relates the final velocity and the average acceleration is written as follows :
v = u +at
Where
v is final velocity
u is initial velocity
a is acceleration
t is time
This equation is valid when the motion is with constant acceleration.
How do scientists know that seafloor spreading occurs?Explain how this spreading causes the continents to seperate.
Answers
For the Betz limit, what is the ratio of flow areas for the stream tube encompassing the rotor at the rotor plane just upstream and downstream of the rotor? Note: Everything goes back to fundamentals (conservation of mass; conservation of momentum; and/or conservation of energy)
Answers
The ratio of flow areas for the stream tube encompassing the rotor at the rotor plane just upstream and downstream of the rotor, according to the Betz limit, is approximately 0.707 or 1:√2.
The Betz limit, also known as the Betz limit or Betz's law, is a fundamental principle in wind turbine aerodynamics. It states that the maximum possible energy extraction from the wind by a wind turbine is limited to 59.3% of the total kinetic energy in the wind stream.
To understand the ratio of flow areas for the stream tube encompassing the rotor at the rotor plane just upstream and downstream of the rotor, we need to consider the concept of stream tube conservation.
In wind turbine operation, a stream tube refers to the imaginary tube of air that passes through the rotor area. It is used to analyze the flow and energy extraction within the wind turbine.
According to the principle of stream tube conservation, the mass flow rate of air should be conserved between the upstream and downstream sections of the rotor plane. This means that the ratio of flow areas must be equal to the ratio of wind velocities upstream and downstream of the rotor.
Mathematically, we can express this as:
(A₁ / A₂) = (V₂ / V₁)
Where:
A₁ is the flow area just upstream of the rotor,
A₂ is the flow area just downstream of the rotor,
V₁ is the wind velocity just upstream of the rotor,
V₂ is the wind velocity just downstream of the rotor.
Now, in the case of the Betz limit, we know that the maximum possible energy extraction is 59.3% of the total kinetic energy. This means that the wind velocity just downstream of the rotor (V₂) should be reduced to 70.7% of the wind velocity just upstream of the rotor (V₁).
Using this information, the ratio of flow areas can be determined:
(A₁ / A₂) = (V₂ / V₁)
(A₁ / A₂) = 0.707
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Navigate to the Uniform Circular Motion Interactive in the Physics Interactives section of The Physics Classroom website. https://www.physicsclassroom.com/Physics-Interactives/Circular-and -Satellite Motion Uniform-Circular-Motion/Uniform-Circular-Motion Interactive Experiment with the on-screen buttons in order to gain familiarity with the control of the animation. The object speed, radius of the circle, and object mass can be varied using the sliders or the buttons. The vector nature of velocity and acceleration can be displayed on the screen. A trace of the object's motion is shown. The acceleration of and the net force values are displayed in the animation window. The animation can be started, paused, continued or rewound. After gaining familiarity with the program, use it to answer the following questions.
Answers
The Uniform Circular Motion Interactive is a tool that allows users to explore the physics of uniform circular motion. The user can change the radius of the circle, the speed of the object, and the mass of the object.
When an object moves in a circle at a constant speed, it is said to be in uniform circular motion. The velocity of the object is constantly changing direction, even though the speed is constant. This means that the object is accelerating.
The acceleration of an object in uniform circular motion is directed towards the center of the circle. The magnitude of the acceleration is equal to the square of the speed of the object divided by the radius of the circle.
The net force on an object in uniform circular motion is always directed towards the center of the circle. The magnitude of the net force is equal to the mass of the object times the acceleration of the object.
The Uniform Circular Motion Interactive is a valuable tool for understanding the physics of uniform circular motion. It allows users to explore the effects of changing the radius of the circle, the speed of the object, and the mass of the object on the velocity, acceleration, and net force of the object.
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A train traveled at an average speed of 80 mph for 4.2 hours. Then, it traveled at an average speed of 60 mph for 1.5 hours. What was the total distance covered by the train?
Answers
Answer:
The answer is four hundred twenty six or 426
Answer:
426
Explanation:
which term refers to how high or low a sound seems to a person
Answers
Pitch refers to how high or low a sound seems to a person. It is the degree of highness or lowness of a sound, which is determined by the frequency of a sound wave.
Pitch is a sound's quality that enables us to discern between a low and a high sound. It is the degree of highness or lowness of a sound and is determined by the frequency of a sound wave. A high-pitched sound is a sound that has a high frequency. A low-pitched sound, on the other hand, is a sound that has a low frequency. Sound pitch is an important aspect of music and voice tone.Pitch can be described as the rate of vibration of sound waves, measured in Hertz (Hz), with higher frequencies indicating a higher pitch. The pitch of a sound can be altered by changing the frequency of the sound wave. Pitch and volume are two of the most important qualities of sound that are utilized in music and speech to express various emotions and convey meaning.The pitch of a sound is generally increased by increasing the frequency and decreased by decreasing the frequency. The pitch of a sound can also be affected by other factors, such as the size, shape, and material of the object producing the sound. For instance, a guitar string that is tight will create a high-pitched sound, while a loose guitar string will create a low-pitched sound. Similarly, a small bell will produce a high-pitched sound, while a large bell will produce a low-pitched sound.
Pitch is the degree of highness or lowness of a sound and is determined by the frequency of a sound wave. A high-pitched sound is a sound that has a high frequency. A low-pitched sound, on the other hand, is a sound that has a low frequency. Pitch can be described as the rate of vibration of sound waves, measured in Hertz (Hz), with higher frequencies indicating a higher pitch. The pitch of a sound can be changed by adjusting the frequency of the sound wave.
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8. An electron is accelerated from rest through a potential difference of 50.0 kV. What is the speed of the electron? (c = 3.00 × 108 m/s, e = 1.60 × 10-19 C, mel = 9.11 × 10-31 kg) A) 1.24 × 108 m/s B) 1.33 × 108 m/s C) 3.24 × 108 m/s D) 3.33 × 108 m/s E) 4.12 × 108 m/s
Answers
The speed of the electron is 1.33 * 10^{8} m/s
When an electron is accelerated through a potential difference, it gains kinetic energy. This energy can be calculated using the formula E = qV, where E is the energy gained, q is the charge of the electron, and V is the potential difference. In this case, the potential difference is given as 50.0 kV, which is equivalent to 50,000 volts. The charge of an electron is given as 1.60 × 10^-19 C. Therefore, the energy gained by the electron is:
E = (1.60 * 10^{-19} C) * (50,000 V) = 8.00 * 10^{-15} J
Using the formula for kinetic energy, KE = (\frac{1}{2})mv^{2}, where m is the mass of the electron and v is its speed, we can solve for v. Rearranging the formula, we get:
v = sqrt(\frac{(2KE)}{m})
Plugging in the values we have calculated, we get:
v = sqrt(\frac{(2 * 8.00 * 10^{-15} J) }{ 9.11 * 10^{-31} kg}) = 1.33 * 10^{8} m/s
Therefore, the answer is option B) 1.33 * 10^{8} m/s
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Can someone pretty please help? will give brainliest and thats a promise
What type of cooling would a scientist determine formed an igneous rock found with large crystals?
Medium rate cooling
Slow cooling
Quick cooling
Super-fast cooling
Answers
Answer:
slower cooling
Explanation:
Slower cooling cause the rock is very hot it will take time to cool
Hope it helps
A thermometer is taken from a room where the temperature is 19
∘
C to the outdoors, where the temperature is −5
∘
C. After one minute the thermometer reads 11
∘
C. (a) What will the reading on the thermometer be after 3 more minutes? (b) When will the thermometer read −4
∘
C ? minutes after it was taken to the outdoors.
Answers
The reading on the thermometer after 3 more minutes will be -13∘C. The thermometer will never read -4∘C after being taken outdoors.
To solve this problem, we can assume that the rate of change in temperature follows a linear pattern.
Let's first calculate the rate of change in temperature per minute:
Rate of change = (Final temperature - Initial temperature) / Time
a) After one minute:
Rate of change = (11∘C - 19∘C) / 1 minute = -8∘C/minute
To find the reading on the thermometer after 3 more minutes, we can multiply the rate of change by the time:
Change in temperature = Rate of change × Time
After 3 more minutes:
Change in temperature = -8∘C/minute × 3 minutes = -24∘C
The initial temperature was 11∘C, so the final temperature after 3 more minutes will be:
Final temperature = Initial temperature + Change in temperature = 11∘C - 24∘C = -13∘C
b) To find when the thermometer will read -4∘C, we need to determine the time it takes for the temperature to change from -5∘C to -4∘C.
Rate of change = (-4∘C - (-5∘C)) / Time
Rate of change = 1∘C / Time
We can rearrange the equation to solve for time:
Time = 1∘C / Rate of change
Substituting the given rate of change:
Time = 1∘C / (-8∘C/minute) = -1/8 minute
Since time cannot be negative, we can conclude that the thermometer will never read -4∘C after being taken outdoors.
Please note that this calculation assumes a linear rate of change in temperature, which might not hold true in all situations.
Learn more about thermometer here: https://brainly.com/question/33462606
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