6 Fig. 6.1 is a full-scale diagram that represents a sound wave travelling in air
direction of travel
Fig. 6.1
(a) On Fig. 6.1, mark two points, each at the centre of a different compression. Label both of the
points C.
(b) The speed of sound in air is 330 m/s.
Measure the diagram and determine the frequency of the sound.

Answers

Answer 1

From  the measured wavelength from diagram, the frequency of the sound is 6660 Hz.

What is the frequency of a wave?

The frequency of a wave is the number of complete oscillation per second completed by a wave.

Frequency is related to wavelength and speed by the following formula:

Frequency = velocity/wavelength

Velocity of sound in air = 330 m/s

The measured wavelength = 5.0 cm = 0.05 m

Frequency = 330/0.05 = 6660 Hz

Therefore, based on the measured wavelength from diagram, the frequency of the sound is 6660 Hz.

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6 Fig. 6.1 Is A Full-scale Diagram That Represents A Sound Wave Travelling In Airdirection Of TravelFig.

Related Questions

What does the cosmological principle allow cosmologists to assume?

A. Exactly what the specific fate of the universe will be and when

B. The galaxies are organized clusters of billions of stars, gas, dust, and matter in all other forms.

C. That the small portion of the space we can see is truly representative of all the rest of the universe that we cannot see.

D. How the helium clouds impact human health and life expectancy.

Answers

Answer:

C. That the small portion of the space we can see is truly representative of all the rest of the universe that we cannot see.

Explanation:

The Cosmological Principle assumes that the small portion of the universe that we can see is representative of the entire universe, even though we can only directly observe a tiny fraction of it. It's an assumption used by Cosmologists to simplify their models of the universe.

What 3 ways can the number of species increase?

Answers

Answer:

Darwin's On the Origin of Species has led to a theory of evolution with a mass of empirical detail on population genetics below species level, together with heated debate on the details of macroevolutionary patterns above species level. Most of the main principles are clear and generally accepted, notably that life originated once and has evolved over time by descent with modification. Here, I review the fossil and molecular phylogenetic records of the response of life on Earth to Quaternary climatic changes. I suggest that the record can be best understood in terms of the nonlinear dynamics of the relationship between genotype and phenotype, and between climate and environments. ‘The origin of species’ is essentially unpredictable, but is nevertheless an inevitable consequence of the way that organisms reproduce through time. The process is ‘chaotic’, but not ‘random’. I suggest that biodiversity is best considered as continuously branching systems of lineages, where ‘species’ are the branch tips. The Earth's biodiversity should thus (1) be in a state of continuous increase and (2) show continuous discrepancies between genetic and morphological data in time and space.

Explanation:

The nearest neighboring star to the Sun is about 4 light-years away. If a planet happened to be orbiting this star at an orbital radius equal to that of the Earth-Sun distance, what minimum diameter would an Earth-based telescope's aperture have to be in order to obtain an image that resolved this star-planet system? Assume the light emitted by the star and planet has a wavelength of 550 nm
. The Earth-Sun distance is 149.6×106km
, and 1ly=9.461×1015m
.

Answers

To resolve the star-planet system at a distance of 4 light-years, a telescope on Earth would need an aperture with a minimum diameter of 55.88 mm.

What does microscopy's Rayleigh criterion mean?

In optical microscopy, the Rayleigh criterion is frequently used to estimate the resolution of the microscope. The resolution limit imposed by this criterion has long been regarded as a roadblock to using an optical microscope to study biological phenomena at the nanoscale.

We can use the Rayleigh criterion,

θ = 1.22 λ / D

θ = angular resolution

λ = wavelength of light

D = diameter of the telescope's aperture

θ = arctan (r / d)

r = radius of the planet's orbit

d = distance to the star

Now, we use the given values,

r = 149.6×106 km = 149.6×109 m

d = 4 × 9.461×1015 m = 3.7844×1016 m

λ = 550 nm = 550×10-9 m

θ = arctan (r / d)

   =arctan (149.6×109 / 3.7844×1016) = 0.000012 radians

we can use the Rayleigh criterion,

θ = 1.22 λ / D

D = 1.22 λ / θ

D = 1.22 × 550×10-9 / 0.000012

D = 55.88 mm

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Look at the picture below and identify the atmospheric pressure found within the valley:

please help it is due in 10 min

Look at the picture below and identify the atmospheric pressure found within the valley: please help

Answers

Look at what I found

40 POINTS!!!

A wave travels along a stretched horizontal rope. The vertical distance from crest to trough for this wave is 18 cm and the horizontal distance from crest to trough is 26cm.

Part A
What is the wavelength of this wave?
Express your answer using two significant figures

Part B
What is the amplitude of this wave?
Express your answer using two significant figures.

Answers

part a.  the wavelength of this wave  is 26 cm

part b. The amplitude (A) of a wave is 9 cm

What is wavelength?

The wavelength (λ) of a wave is described as the distance between two consecutive points on the wave that are in phase.

In this scenario, the distance between two corresponding points on the wave will be equal to the horizontal distance from crest to trough, which is 26 cm.

Hence, the wavelength of the wave is: λ = 26 cm

The amplitude (A) of a wave is described as the maximum displacement of a particle from its rest position as the wave passes through it.

In this scenario, the vertical distance from crest to trough is 18 cm, which is equal to twice the amplitude.

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Describe the functions of fluids in the body?


Help​

Answers

Explanation:

The function of body fluid

They deliver oxygen and nutrients to the cells, and take away waste materials, which are then eliminated with urination. When the body temperature rises, blood circulation to the skin increases, enabling heat dissipation though sweating, helping to keep the body at a constant temperature.

From a height of 30 meters we throw an object vertically downwards with a speed of 2 m/s. How long will it take to reach the ground and with what speed?

Answers

1. The time taken for the object to reach the ground is 2.47 s

2. The speed with which the object will reach the ground is 26.206 m/s

1. How do I determine the time taken?

We can obtain the time taken for the object to reach the ground as      follow:

Height (h) = 30 metersAcceleration due to gravity (g) = 9.8 m/s²Time taken to reach the ground (t) = ?

h = ½gt²

30 = ½ × 9.8 × t²

30 = 4.9 × t²

Divide both side by 4.905

t² = 30 / 4.9

Take the square root of both side

t = √(30 / 4.9)

t = 2.47 s

Thus, the time taken to reach the ground is 2.47 s

2. How do i determine the speed?

The speed the object will use to reach the ground can be obtained as follow:

Initial speed (u) = 2 m/sTime (t) = 2.47 sAcceleration due to gravity (g) = 9.8 m/s²Final speed (v) =?

v = u + gt

v = 2 + (9.8 × 2.47)

v = 2 + 24.206

v = 26.206 m/s

Thus, the speed is 26.206 m/s

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6) Find the speed a spherical raindrop would attain by falling from 4.00 km. Do this:a) In the absence of air dragb) In the presence of air dragc) Assume that the diameter of the drop is 3 mm and the density of the water is 0.98x10^3 kg/m^3

Answers

We are asked to determine the velocity of a rain drop if it falls from 4 km.

To do that we will use the following formula:

\(2ah=v_f^2-v_0^2\)

Where:

\(\begin{gathered} a=\text{ acceleration} \\ h=\text{ height} \\ v_f,v_0=\text{ final and initial velocity} \end{gathered}\)

If we assume the initial velocity to be 0 we get:

\(2ah=v_f^2\)

The acceleration is the acceleration due to gravity:

\(2gh=v_f^2\)

Now, we take the square root to both sides:

\(\sqrt{2gh}=v_f\)

Now, we substitute the values:

\(\sqrt{2(9.8\frac{m}{s^2})(4000m)}=v_f\)

solving the operations:

\(280\frac{m}{s}=v\)

Therefore, the velocity without air drag is 280 m/s.

Part B. we are asked to determine the velocity if there is air drag. To do that we will use the following formula:

\(F_d=\frac{1}{2}C\rho_{air}Av^2\)

Where:

\(\begin{gathered} F_d=drag\text{ force} \\ C=\text{ constant} \\ \rho_{air}=\text{ density of air} \\ A=\text{ area} \\ v=\text{ velocity} \end{gathered}\)

We need to determine the drag force. To do that we will use the following free-body diagram:

Since the velocity that the raindrop reaches is the terminal velocity and its a constant velocity this means that the acceleration is zero and therefore the forces are balanced:

\(F_d=mg\)

Now, we determine the mass of the raindrop using the following formula:

\(m=\rho_{water}V\)

Where:

\(\begin{gathered} \rho_{water}=\text{ density of water} \\ V=\text{ volume} \end{gathered}\)

The volume is the volume of a sphere, therefore:

\(m=\rho_{water}(\frac{4}{3}\pi r^3)\)

Since the diameter of the raindrop is 3 millimeters, the radius is 1.5 mm or 0.0015 meters. Substituting we get:

\(m=(0.98\times10^3\frac{kg}{m^3})(\frac{4}{3}\pi(0.0015m)^3)\)

Solving the operations:

\(m=1.39\times10^{-5}kg\)

Now, we substitute the values in the formula for the drag force:

\(F_d=(1.39\times10^{-5}kg)(9.8\frac{m}{s^2})\)

Solving the operations:

\(F_d=1.36\times10^{-4}N\)

Now, we substitute in the formula:

\(1.36\times10^{-4}N=\frac{1}{2}C\rho_{air}Av^2\)

Now, we solve for the velocity:

\(\frac{1.36\times10^{-4}N}{\frac{1}{2}C\rho_{air}A}=v^2\)

Now, we substitute the values. We will use the area of a circle:

\(\frac{1.36\times10^{-4}N}{\frac{1}{2}(0.45)(1.21\frac{kg}{m^3})(\pi r^2)}=v^2\)

Substituting the radius:

\(\frac{1.36\cdot10^{-4}N}{\frac{1}{2}(0.45)(1.21\frac{kg}{m^{3}})(\pi(0.0015m)^2)}=v^2\)

Solving the operations:

\(70.67\frac{m^2}{s^2}=v^2\)

Now, we take the square root to both sides:

\(\begin{gathered} \sqrt{70.67\frac{m^2}{s^2}}=v \\ \\ 8.4\frac{m}{s}=v \\ \end{gathered}\)

Therefore, the velocity is 8.4 m/s

6) Find the speed a spherical raindrop would attain by falling from 4.00 km. Do this:a) In the absence

You can use the curved part of a spoon as a mirror because it ________ light.

Which best completes the statement?

reflects
refracts
absorbs
enhances

Answers

Answer:

Reflects

Explanation:

A metal spoon looks very shiny because its surface is very smooth, which is why it acts like a mirror and reflects light very well.

You can use the curved part of the spoon as a mirror because it reflects light. Thus, the correct option is A.

What is reflection of light?

Reflection is the phenomena of light, when the ray of light bounces off an object. If the surface is smooth and shiny, just like a glass, water or polished metal surface, the light will reflect at the same angle as it hit the surface of the object. This is called as specular reflection.

The laws of reflection states that the incident ray, the reflected ray, and the normal ray all lie at the same point of incidence, and lie in the same plane of the surface. And, the angle of incidence is equal to the angle of reflection of light.


Therefore, the correct option is A.

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Please help

A lightning flash may transfer up to 17 C of charge through a potential difference of 10? V
How much energy does this involve?

Answers

Answer:

170 energy

Explanation:

I don't know the answer

Need help with this assignment please

Need help with this assignment please

Answers

Torque is a measure of the turning force applied to an object about a rotational axis. It is calculated as the product of the force applied to the object and the distance from the axis of rotation at which the force is applied.

How to explain the information

Use the equation slope = mod to calculate the unknown mass (mo) for parcels A and C, setting d = 1.0 m, and parcels G and H, setting d = 1.5 m.

Record all data, tables, and four graphs for analysis.

The experiment demonstrates the application of torque in determining unknown masses and provides valuable insights into the concept of torque in physics.

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the two forces to the right are friction which one would be the force of kinetic friction?

the two forces to the right are friction which one would be the force of kinetic friction?

Answers

Answer:

40 N

Explanation:

Both forces to the right are friction forces.  The 40 N force has to be the kinetic friction force because kinetic friction is always less than static friction.  So, the 80 N force has to be the static friction force, which is always greater than the kinetic friction.

What is the economic term for the act of sacrificing one good or service to purchase or produce another?

Answers

Answer:

Trade-off. sacrificing one good or service to purchase or produce another.

A projectile leaves the muzzle of a projectile launcher with a speed of 35m/s [the
launcher is oriented vertically].

a) What is the maximum height reached by the projectile?

b) How long did it take the projectile to reach its maximum height?

c) How long was the projectile in the air [ttot]?

Answers

Answer:

a. 62.44 m

b. 3.57 sec

c. 7.12 sec

Explanation:

The leaving speed is given as = 35 m/s

The launcher is oriented vertically, thus the angle is = 0 degrees

a) The maximum height reached is given as;

h= v²₀y / 2g

h=35² / 2 * 9.81

h= 62.44 m

b) Time the projectile reaches maximum height is given as;

 t=v₀y / g

 t=35/9.81

 t= 3.57 sec

c) The trip up is a mirror of the trip down

   This means the time the projectile will be in the air is ;

    t= 2 * 3.57

     t= 7.12 sec

Six cousins sit down at the table for their annual Thanksgiving feast. Each child has a favorite food. Match each child with their favorite food.
Cousins are: Jeff, Tara, Susie, Lynne, Laura, Kyle
Foods are: corn, ham, pumpkin pie, dressing, turkey, sweet yams
1. The identical male twins do not like anything sweet.
2. The children whose names begin with the same letter do not consider meat their favorite food.
3. The oldest child prefers a "fowl" odor in the kitchen.
4. The twins are younger than Laura, who is not the eldest.
5. The youngest child loves dessert best.
6. Jeff is a clown at Thanksgiving dinner, and the others have nicknamed him after his favorite food.
7. Tara is neither the eldest nor the youngest; and she doesn't like sweets, eat, or dressing.

Answers

In this situation, Jeff's favorite food is ham, Tara's favorite food is corn, Susie's favorite food is turkey, Lynne's favorite food is pumpkin pie; Laura's favorite food is sweet yams and Kyle's favorite food is dressing.

This situation requires you to carefully analyze and relate the information provided to find out the favorite food of each cousin. The first facts we can determine are:

Jeff and Kyle are the male teens because these are the only names that are predominantly male names.Jeff's favorite food is ham because this is word is also a synonym for a clown.

Moreover, to determine the other favorite foods, you need to understand how old or young is each kid. Based on analysis you can determine this is the order from youngest to oldest:

Lyme, Tara, Jeff/Kyle, Laura, Susie

Now, we can assign the food to each of the kids:

Lyme: Pumpkin pie because as the youngest she prefers dessert.Jeff: Ham, this information is already known.Susie: Turkey because she likes a "fowl" smellTara: Corn because she does not like sweet foods or dressings, and corn is the only option left.Kyle: Dressing because as a twin he does not like anything sweet and the only remaining options are sweet yams or dressing.Laura: Sweet yams because this is the only food left.

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How do compounds differ from mixtures such as lemonade

Answers

Answer:

A mixture is a combination of two or more substances in any proportion. This is different from a compound, which consists of substances in fixed proportions. ... The lemonade pictured above is a mixture because it doesn't have fixed proportions of ingredients.

Explanation:

A rocket fires two engines simultaneously. One produces a thrust of 725Ndirectly forward while the other gives a 513N thrust at 32.4° above the forward direction. Find the magnitude and direction (relative to the forward direction) of the resultant force which these engines exert on the rocket.

Answers

The magnitude of the resultant force, F = 1,190.3 acting at a direction X = 13.35°.

What is the resultant force the two engines exert on the rocket?

The resultant force on the rocket is calculated thus:

The 513N thrust is resolved into vertical and horizontal components;

Horizontal component: 513N cos(32.4°) = 433.14 N

Vertical component: 513N sin(32.4°) = 274.88 N

Total forward force on the rocket = 725 N + 433.14 N = 1,158.14 N

Total force at right angles:

0 + 274.88 N = 274.88 N

The resultant force (F) is then given as follows:

F² = a² + b²

F² = (1158.14 N)² + (274.88 N)²

F = √1,416,847.27

F = 1,190.3

To find the direction:

tan X 274.88 N / 1,158.14 N

X = tan⁻¹ 0.237346089419241

X = 13.35°

Therefore, the magnitude of the resultant force, F = 1,190.3 acting at a direction X = 13.35°.

In conclusion, the resultant force is obtained by resolving the forces into vertical and horizontal components.

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Ice is placed in cool water. What happens to the temperature of the ice and the water?

Answers

Answer:

Explanation:

ice absorbs heat from the water. As the water molecules lose energy, they begin to slow down, and consequently to cool. So, it's kind of the opposite of what we might think: when we put ice in water, the ice doesn't give its cold to the water, it takes heat from the water.

What is it known as when a force is applied to an object for an amount of time?


momentum


impulse


inertia


acceleration

Answers

Answer:

Impulse. Impulse is when a force is applied to an object for an amount of time.

Explanation:

It can't be momentum because momentum is the motion of a moving body, that is measured as a product of its mass and velocity.

It' cant be inertia because inertia is when an object doesn't move/ it does nothing as well as an object remaining unchanged.

And it can't be acceleration because acceleration is when how fast an object can go/ there velocity.

And that leaves us with impulse, so that's the correct one.

Hope this helped!

Answer:

impulse

Explanation:

took the test

Explain why your PE and KE are usually not both high at the same time (If PE is high then usually KE is low)

Answers

might help:

an object can have both kinetic and potential energy at the same time. for example, an object which is falling, but has not reached the ground has kinetic energy because it is moving downwards, and potential energy because it is able to move downwards even further than it already has. as an object falls its potential energy decreases, while its kinetic energy increases. the decrease in potential energy is exactly equal to the increase in kinetic energy.

A body of mass 12kg travelling at 4.2m/s² collides with a second body of mass 18kg at rest. Calculate their common velocity of the two bodies coalesce after collision

Answers

When a body of mass 12kg travelling at 4.2m/s² collides with a second body of mass 18kg at rest, their common velocity after the collision is 1.68 m/s.

When two objects of different masses collide, they can exchange momentum. An object's mass and velocity together make up its momentum. When two objects collide, their momentum is conserved, meaning that the total momentum of the two objects before the collision equals the total momentum of the two objects after the collision. This principle can be used to calculate the velocity of the two objects after a collision.A body of mass 12 kg is travelling at a velocity of 4.2 m/s and collides with a second body of mass 18 kg at rest. The total mass of the system is 12 kg + 18 kg = 30 kg. To determine the velocity of the two objects after the collision, we need to use the conservation of momentum principle. Before the impact, the system's entire momentum is:momentum before = \((mass_1 x velocity_1) + (mass_2 x velocity_2)\)where mass1 is the mass of the first object, velocity1 is the velocity of the first object, \(mass_2\) is the mass of the second object, and \(velocity_2\) is the velocity of the second object. In this case,\(mass_1 = 12 kg, velocity_1 = 4.2 m/s, mass_2 = 18 kg\), and \(velocity_2 = 0\) (because the second object is at rest). Substituting these values into the equation above, we get: momentum before = (12 kg x 4.2 m/s) + (18 kg x 0)momentum before = 50.4 kg m/sFollowing the collision, the system's overall momentum is:momentum after =\((mass_1 + mass_2) * velocity\)where mass1 + mass2 is the total mass of the system, and velocity is the velocity of the two objects after the collision. Let's call this velocity "v". Substituting the values we know into the equation above, we get: momentum after = (12 kg + 18 kg) x vmomentum after = 30 kg x vUsing the conservation of momentum principle, we know that momentum before = momentum after. Therefore, we can set these two equations equal to each other and solve for v.50.4 kg m/s = 30 kg x vv = 50.4 kg m/s ÷ 30 kgv = 1.68 m/sFollowing the impact, the two bodies' common velocity is 1.68 m/s. Hence, the answer to this problem is that when a body of mass 12kg travelling at 4.2m/s² collides with a second body of mass 18kg at rest, their common velocity after the collision is 1.68 m/s.

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100 g of water at 25 °C is poured into an insulating cup. 50 g of ice at 0 °C is added to the water. The water is stirred until the temperature of the water has fallen to 0 °C. 18 g of ice remains unmelted. The specific heat capacity of water is 4.2 J / g °C. Which value does this experiment give for the specific latent heat of fusion of ice? ​

Answers

The specific latent heat of fusion of ice obtained from this experiment is approximately 583.33 J/g.

To determine the specific latent heat of fusion of ice using the given experiment, we need to consider the energy transferred during the process.First, we need to calculate the energy lost by the water to cool down from 25 °C to 0 °C. The energy lost is given by:

Q1 = m1 * c * ΔT1

Where:

m1 = mass of water = 100 g

c = specific heat capacity of water = 4.2 J/g °C

ΔT1 = change in temperature = (0 °C - 25 °C) = -25 °C

Q1 = 100 g * 4.2 J/g °C * (-25 °C) = -10,500 J

Next, we calculate the energy released by the water to freeze and cool the remaining ice. The energy released is given by:

Q2 = m2 * Lf

Where:

m2 = mass of ice = 18 g

Lf = specific latent heat of fusion of ice (to be determined)

Q2 = 18 g * Lf

Since energy is conserved in the system, the energy lost by the water (Q1) is equal to the energy released by the water (Q2):

-10,500 J = 18 g * Lf

Solving for Lf:

Lf = -10,500 J / 18 g = -583.33 J/g

The negative sign indicates that energy is being released during the process of freezing.

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A 6.0 kg block is pushed 8.0m up a rough 37° inclined plane by a force of 75N that is parallel to the inclined plane. If the initial speed of the block is 2.2 m/s up the plane and a constant kinetic friction force of 25N opposes the motion, calculate (a) the initial kinetic energy of the block; (b) the work done by the 75N force; (c) the work done by the friction force; (d) the work done by gravity; (e) the work done by the normal force; (f) the final kinetic energy of the block.

Answers

Given

m = 6kg

x = 8m

F = 75 N

vo = 2.2 m/s up

Ff = 25 N

Procedure

(a) Initial kinetic energy of the block

In physics, the kinetic energy of an object is the energy that it possesses due to its motion. It is defined as the work needed to accelerate a body of a given mass from rest to its stated velocity.

\(\begin{gathered} K=\frac{1}{2}mv^2 \\ K=\frac{1}{2}6\operatorname{kg}\cdot(2.2m/s)^2 \\ K=14.5\text{ J} \end{gathered}\)

(b) the work done by the 75N force;

\(\begin{gathered} W=F\cdot d \\ W=75N\cdot8m \\ W=600\text{ J} \\ \end{gathered}\)

(c) the work done by the friction force

\(\begin{gathered} W=F\cdot d \\ W=-25N\cdot8m \\ W=-200J \end{gathered}\)

(d) the work done by gravity

\(\begin{gathered} W=\text{mg}\cdot d\cdot\sin (37) \\ W=6\operatorname{kg}\cdot9.8m/s^2\cdot8m\cdot\sin (37) \\ W=-283\text{ J} \end{gathered}\)

(e) the work done by the normal force

0J, perpendicular force to the motion

(f) the final kinetic energy of the block.​

\(\begin{gathered} W_T=14.5\text{ J}+600J-200J-283\text{ J} \\ W_T=131.5J \end{gathered}\)

A 6.0 kg block is pushed 8.0m up a rough 37 inclined plane by a force of 75N that is parallel to the

A vector starts at point (9,-6) and ends at point (-1,-5) what is the vertical component of the vector?

Answers

The points are (9, -6) and (-1, -5). To find the vertical component of the vector, we have to subtract the vertical components of the points.

\(-6-(-5)=-6+5=-1\)

Therefore, the vertical component of the vector is

\(\bar{v_y}=-1j\)

Observe that we use the letter j because it refers to a vertical component.

A pitcher throws a baseball from the pitcher's mound to home plate in 0.46 s. The
distance is 18.4 m. What was the average speed of the baseball?
a. 40 m/s
b. - 40 m/s
c. 0.03 m/s
d. 8.5 m/s

Answers

The average speed of the baseball is  option  a. 40 m/s .

To calculate the average speed of the baseball, we use the formula:

Average Speed = Distance / Time

Given:

Distance = 18.4 m

Time = 0.46 s

Plugging in the values, we have:

Average Speed = 18.4 m / 0.46 s = 40 m/s

Therefore, the average speed of the baseball is 40 m/s.

Option a, 40 m/s, is the correct answer. This means that the baseball traveled an average distance of 40 meters per second from the pitcher's mound to home plate.

Average speed is a scalar quantity that represents the total distance traveled divided by the total time taken. It gives us an idea of how fast an object is moving on average over a given distance.

In this case, the baseball covered a distance of 18.4 meters in a time of 0.46 seconds. Dividing the distance by the time gives us the average speed of 40 m/s.

It's important to note that average speed is a measure of the overall rate of motion and does not provide information about the direction of motion. Therefore, negative values such as option b (-40 m/s) or extremely small values such as option c (0.03 m/s) are not appropriate in this context.

Option d (8.5 m/s) is also incorrect as it does not match the calculated average speed of 40 m/s.

Therefore, the correct answer is option a, 40 m/s, as it accurately represents the average speed of the baseball.

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A the cannon recoils from firing a cannonball. The speed of the cannon's recoil is small because a. cannon has more mass than the ball b. momentum of the cannon is smaller. c. force against the cannon is smaller than against the ball. d. momentum is mainly concentrated in the ball. e. none of these

Answers

The cannon has more mass than the ball.

option A is the correct answer.

Why is the speed of the cannon's recoil small?

The recoil of a cannon after firing a cannonball is a consequence of the conservation of momentum. According to this principle, the total momentum of a closed system is conserved, which means that the momentum of the cannon and cannonball before the firing must be equal to the momentum of the cannon and the cannonball after the firing.

Thus,  the cannon has more mass than the ball, which means that it has a greater inertia and will be more resistant to acceleration. This results in a smaller speed of recoil compared to the cannonball.

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What does potential energy depend on?a.gravity b.speed c.location d.size

Answers

Potential Energy:

The potential energy of an object is the energy due to its position.

Mathematically,

\(PE=m\cdot g\cdot h\)

The potential energy depends on three factors,

1. Mass

2. Gravity

3. Height

The potential energy is directly proportional to the mass, gravity, and height of the object.

The options speed and size are straight-away wrong.

Assuming that here location doesn't mean height.

The correct answer would be gravity

Which example represents a class 2 lever? (1 point)
O salad tongs picking up salad
O tweezers plucking hairs
O a car door being opened and shut
a screwdriver opening a paint can

Answers

The  example that represents a class 2 lever is: D. a screwdriver opening a paint can.

Which example represents a class 2 lever?

The load is situated in a class 2 lever halfway between the fulcrum and the effort. The screwdriver's resting place against the paint can's rim serves as the fulcrum in this scenario.

The paint can's lid serves as the load, and the force exerted by the hand on the screwdriver's handle serves as the effort. A class 2 lever can be identified by the load being situated between the fulcrum and the effort.

Tweezers, salad tongs, and opening and closing a car door are not examples of class 2 levers. Class 1 levers include things like tweezers and salad tongs, whereas class 3 levers include things like car doors that open and close.

Therefore the correct option is D.

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When a skater pulls her arms in, it
reduces her moment of inertia from
2.12 kg m² to 0.699 kg-m². If she was
initially spinning 3.25 rad/s, what is
her final angular velocity?

Answers

The skater's final angular velocity is approximately 9.86 rad/s.

The skater's final angular velocity can be calculated using the principle of conservation of angular momentum. The equation for angular momentum is given by:

L = Iω

where L is the angular momentum, I is the moment of inertia, and ω is the angular velocity.

Initially, the skater has an angular momentum of:

L_initial = I_initial * ω_initial

Substituting the given values:

L_initial = 2.12 kg m² * 3.25 rad/s

The skater's final angular momentum remains the same, as angular momentum is conserved:

L_final = L_initial

The final moment of inertia is given as 0.699 kg m². Therefore, the final angular velocity can be calculated as:

L_final = I_final * ω_final

0.699 kg m² * ω_final = 2.12 kg m² * 3.25 rad/s

Solving for ω_final:

ω_final = (2.12 kg m² * 3.25 rad/s) / 0.699 kg m²

Hence, the skater's final angular velocity is approximately 9.86 rad/s.

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If and object undergoes a change in momentum of 12 kg*m/s over a 10
second interval, what was the force exerted?

Answers

The magnitude of the force exerted on this object is 1.2 Newton.

Given the following data:

Change in momentum = 12 Kgm/s.Time = 10 seconds.

What is impulse?

In Science, the impulse that is experienced by an object is always equal to the change in momentum of the object, due to the force acting on an object.

Mathematically, impulse is given by this formula:

\(Impulse = change\;in\;momentum\\\\Force \times time = m \Delta V\)

Substituting the given parameters into the formula, we have:

\(Force \times 10=12\\\\Force =\frac{12}{10}\)

Force = 1.2 Newton.

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