Answer:
\( \boxed{a_n \: = \: 64 \: \times \: ( - \frac{3}{4} ) ^{n \: - \: 1} }\)
Step-by-step explanation:
We first compute the ratio of this geometric sequence.\(r \: = \: \frac{ - 48}{64} \\ \\ r \: = \: \frac{36}{ - 48} \\ \\ r \: = \: \frac{ - 27}{36} \)
We simplify the fractions:\(r \: = \: - \frac{3 }{4} \\ \\ r \: = \: - \frac{3 }{4} \\ \\ r \: = \: - \frac{3 }{4}\)
We deduce that it is the common ratio because it is the same between each pair.\(r \: = \: - \frac{3 }{4}\)
We use the first term and the common ratio to describe the equation:\(a_1 \: = \: 64; \: r \: = \: - \frac{3 }{4}\)
We apply the data in this formula:\( \boxed{a_n \: = \: a_1 \: \times \: {r}^{ n \: - \: 1} }\)
_______________________
We apply:\( \boxed {\bold{a_n \: = \: 64 \: \times \: {( - \frac{3}{4} )}^{ n \: - \: 1} }}\)
Data: The unknown "n" is the term you want
MissSpanishWhat are the roots of 2x² – 5x + 2 = 0?
d. A pair of scissors forms the angles shown.
What is the value of x?
(84)*
X
116
Answer:
x=8
Step-by-step explanation:
the line is 180 degrees,
so 180-116=64
and 64=8x
x=8
Miguel plots points A, B, and C in the coordinate plane.
PART A What is the distance
between points A and B?
Explain your reasoning.
B(-6,-2)
An equilateral triangle has all three sides of equal length.
PART B Is AABC an equilateral triangle? Explain your reasoning.
-A(-3,2)-
~
2
0
2
4
C(0, -2)
Answer:
part a: 5
part b: no, ABC is not an equilateral triangle
Step-by-step explanation:
part a: if you do the distance formula for points A and B, you get 5
part b: using the distance formula again, points A to B and points A to C are both 5, but points B to C is 6, therefore it's not equilateral because all the sides have to be the same length
delivered.
a. What is the constant rate of change? What does it represent?
b. What is the initial value? What might that represent?
The constant rate of change and initial value for the given graph are 40 and 20 respectively. the initial value might represent the fixed cost of the soil.
What is the slope of straight line?The slope of a straight line is the tangent of the angle formed by it with the positive x axis as the reference. The negative slope indicates the rate of decrease while the positive shows the rate of increase.
The given problem can be solved as follows,
(a) The graph given is a straight line that passes through (0, 40) and (10, 240).
The constant rate of change is equivalent to the the slope of the line given as,
⇒ (240 - 40)/(10 - 0) = 20
(b) The initial value of the graph is given as the y-intercept of the line.
Which is given as 40.
It might represent the fixed cost.
Hence, the constant rate of change is given as 40 and the initial value is 20 which might represent the fixed cost.
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The missing graph is attached here.
American airlines requires that total outside dimensions (length+width+height) of a checked bag not exceed 62 inches.Suppose you want to check a bag whose height is same as its width.What is the biggest volumn bag of this shape that you can check on an american flight
Answer:
The maximum volume is 35316.4 in^3.
Step-by-step explanation:
Length + width + height is less than equal to 62 inches
Height = width = W
Let the length is L .
\(L + W + W = 62 \\\\L= 62 - 2 W\\\\Volume, V = L W H\\\\V = (62 - 2 W)\times W \times W\\\\V = 62 W^2 - 2 W^3\\\\\frac{dV}{dW}=124 W - 6 W^2\\\\So, \frac{dV}{dW} =0\\\\124 = 6 W\\\\W = 20.67 inches\)
So, the maximum volume is
\(V =124\times 20.67\times 20.67 - 2 \times 20.67^3\\\\V =52978.86 - 17662.46 = 35316.4 inch^3\)
a hexadecimal number is a number written in the base 16 number system.
t
f
True. Hexadecimal numbers are written using the base 16 number system, where digits range from 0 to 9 and A to F. They are commonly used in computer systems for concise representation and easy conversion to binary.
In the hexadecimal number system, there are 16 symbols used to represent values, namely 0-9 and A-F. Each digit in a hexadecimal number represents a multiple of a power of 16.
The symbols 0-9 represent the values 0-9, respectively. The symbols A-F represent the values 10-15, respectively, where A represents 10, B represents 11, C represents 12, D represents 13, E represents 14, and F represents 15.
For example, the hexadecimal number "3F" represents the value (3 * 16^1) + (15 * 16^0) = 48 + 15 = 63 in decimal.
Similarly, the hexadecimal number "AB8" represents the value (10 * 16^2) + (11 * 16^1) + (8 * 16^0) = 2560 + 176 + 8 = 2744 in decimal.
Hexadecimal numbers are commonly used in computer systems, as they provide a convenient way to represent large binary numbers concisely. Each hexadecimal digit corresponds to a four-bit binary number, allowing for easy conversion between binary and hexadecimal representations.
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In parallelogram LMNO, what is the measure of angle N?
50°
70°
110°
130
The measure of the angle N is equal to 110 degrees
What is a parallelogram?
A parallelogram is the name given to a quadrilateral in geometry. In a parallelogram, the opposing sides are parallel and of equal length. The rhombus, rectangle, and square are just a few shapes that are parallelograms.
Having two sets of parallel sides makes a quadrilateral a parallelogram. A parallelogram has opposite sides that are the same length and angles that are the same size. Additionally, the internal angles on the same transverse side are supplementary. 360 degrees are equal to the total of all internal angles.
we know that
In a parallelogram opposite angles are congruent and consecutive angles are supplementary.
So
m∠O=m∠M
m∠L=m∠N
m∠O+m∠L= 180
Step
Find the value of x
(x+20)+(2x+10)=180
3x=150
x=150/3 = 50 degrees
Step
Find the value of angle L
m∠L = 2x+10
m∠L=2*50+10
m∠L=110 degrees
Remember that
m∠N=m∠L = 110 degrees
m∠N= 110 degrees
therefore
the answer is
the measure of the angle N is equal to 110 degrees
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Find an answer to match the equation:8p+5=-6p+1A.3B.-10C.60D.4E.20F.38G.-2/7H.-10.4I.0
The first thing we need to do is collect like terms; move all the terms in p to one side of the equation and move the rest to the other side of the equation;
\(\begin{gathered} 8p+6p=1-5 \\ 14p=-4 \end{gathered}\)We'll now divide both sides of the equation by 14, which will give us the below;
\(\begin{gathered} \frac{14p}{14}=\frac{-4}{14} \\ \\ p=\frac{-2}{7} \end{gathered}\)Therefore, the correct answer is option G which is -2/7 as seen in our answer.
preform the operation indicated 3x^2(2x^2-5x+1)
Answer:
6x^4 -15x^3 + 3x^2
Step-by-step explanation:
What we want to do here is to multiply what is outside the bracket with what is inside
That would be;
3x^2(2x^2 -5x + 1)
= 3x^2(2x^2) -5x(3x^2) + 1(3x^2)
Opening the brackets, we have;
6x^4 -15x^3 + 3x^2
Mr. Parker wants to rent a cargo van for a day. It will cost a one time daily fee of $50 plus $0.35 per mile driven. Part A was 50m+0.35 now for Part B Evaluate the expression to find out how much Mr. Parker will pay if he drives 80 miles.
Answer:
78
Step-by-step explanation:
Plz help!!
Why were the Central Powers considered a threat to democracy and freedom? Why were the allied powers viewed as supporters of Democracy and Freedom?
Answer:
Are political systems related to collective violence and war? This is now fundamentally answered in one of three ways: yes, democracies are least violence prone; yes, socialist equalitarianism assures peace; and no, political systems and violence are unrelated.
Recent theoretical and empirical research confirms the first answer: those political systems that maximize and guarantee individual freedom (democracies) are least violence prone; those that maximize the subordination of all individual behavior to state control (totalitarian systems) the most, whether socialist or not; and wars do not occur between democracies.
Known for centuries, a tenet of classical liberalism, the pacific nature of democracy has became largely forgotten or ignored in the last half-century. That democracy is inherently peaceful is now probably believed by no more than a few prominent peace researchers. In part this has been due to the intellectual defection of Western intellectuals from classical liberalism to some variant of socialism, with its emphasis on the competitive violence and bellicosity of capitalist freedoms. Many intellectuals, and in particularly European and Third World peace researchers, have come to believe that socialist equalitarianism is the answer to violence; others, particularly American liberals, believe that if the socialist are wrong, then at least democracies are no better than other political systems in promoting peace.
Socialism aside, there also has been a rejection of Western values, of which individual freedom is prominent, and acceptance of some form of value-relativism (thus, no political system is better than any other). In some cases this rejection has turned to outright hostility and particularly anti-Americanism, and thus opposition to American values, such as freedom. To accept, therefore, that democratic freedom is inherently most peaceful, is to the value-relativist, to say the unacceptable--that it is better. For another, to accept that this freedom promotes non-violence seems to take sides in what is perceived as the global ideological struggle or power game between the United States and Soviet Union.
Independent of different ideological or philosophical perspectives, several interacting methodological errors have blinded intellectuals and peace researchers to the peacefulness of democracies. One of these is the strong, general tendency to see only national characteristics and overall behavior. Then a nation is rich or poor, powerful or weak, belligerent or pacific. But most important for identifying the relationship between freedom and violence is rather the similarities and differences between two states and their mutual behavior. Thus should be observed a lack of violence and war between democracies; and the most severe violence occurring between those nations with the least freedom.
Another error has been to selectively focus upon the major powers, which include among them not only several democracies having many wars, but also Great Britain having the most. However, a systematic comparison among all the belligerents and neutrals in wars, would uncover the greater peacefulness of democracies.
Along with this selective attention is the tendency to count equally against democracies all of its wars, no matter how mild or small. Thus, the American invasion of Grenada would be one mark against democracy; Hitler's invasion of Poland that initiated World War II would be a similar mark against non-democracies. This stacks any such accounting against democracy.
Finally, while a systematic survey of the literature shows significant support for the inverse relationship between democracy and violence, researchers have done little theoretical testing of this relationship, thus resulting in their overlooking or ignoring it when it appears in their results.
Step-by-step explanation:
calculate the partial derivatives ∂∂∂u∂t and ∂∂∂t∂u using implicit differentiation of (−)2ln(−)=ln(2)(tu−v)2ln(w−uv)=ln(2) at (,,,)=(1,1,2,4).
Therefore, at the given point (1, 1, 2, 4), ∂u/∂t = (ln(2) / 2) × ∂t/∂u, and ∂t/∂u cannot be determined from the given equation.
To calculate the partial derivatives ∂u/∂t and ∂t/∂u using implicit differentiation of the given equation, we'll differentiate both sides of the equation with respect to the variables involved, treating the other variables as constants.
Let's break it down step by step:
Given equation: (-2ln(-x) = ln(2)(tx - v) × 2ln(w - uv) = ln(2)
We'll differentiate both sides of the equation with respect to u and t, treating x, v, and w as constants.
Differentiating with respect to u:
Differentiate the left-hand side:
d/dt (-2ln(-x)) = d/dt (ln(2)(tx - v))
-2(1/(-x)) × (-1) × dx/du = ln(2)(t × du/dt - 0) [using chain rule]
Simplifying the left-hand side:
2(1/x) × dx/du = ln(2)t × du/dt
Differentiating with respect to t:
2ln(w - uv) × d/dt (w - uv) = 0 × d/dt (ln(2))
2ln(w - uv) × (dw/dt - u × dv/dt) = 0
Since the second term on the right-hand side is zero, we can simplify the equation further:
2ln(w - uv) × dw/dt = 0
Now, we substitute the given values (1, 1, 2, 4) into the equations to find the partial derivatives at that point.
At (1, 1, 2, 4):
-2(1/(-1)) × dx/du = ln(2)(1 × du/dt - 0)
2 × dx/du = ln(2) × du/dt
dx/du = (ln(2) / 2) × du/dt
2ln(w - uv) × dw/dt = 0
Since the derivative is zero, it doesn't provide any information about ∂t/∂u.
Therefore, at the given point (1, 1, 2, 4):
∂u/∂t = (ln(2) / 2) × ∂t/∂u
∂t/∂u cannot be determined from the given equation.
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I WILL GIVE BRAINLIEST
For which equation is x = 5 a solution
A. 2 + x = 3
B. 3x = 15
C. x/2 = 10
D. x - 7 = 12
Answer:
B
Step-by-step explanation:
too easy
Answer:
B
Step-by-step explanation:
Trust me
PLZ HELP AGAIN RN DUE TMR ASAP I REALLY APPRECIATE IT TX
Answer:
91.106
Step-by-step explanation:
I used the equation c=2(3.14)R
R = Radius.
Answer: C= 91.1 m
Hope this helps.
what sample size would be required to detect a true mean speed as low as 94 meters per second if you wanted the power of the test to be at least 0.85
To calculate the sample size required to detect a true mean speed of 94 meters per second with a power of at least 0.85, we need to know the significance level and the standard deviation of the population.
Assuming a 5% significance level (alpha = 0.05) and a standard deviation of 10 meters per second, we can use the following formula:
n = (Z_beta + Z_alpha/2)^2 * σ^2 / d^2
where:
Z_beta is the Z-score for the desired power (0.85) from the standard normal distribution, which is approximately 1.04.
Z_alpha/2 is the Z-score for the desired significance level (0.05/2 = 0.025) from the standard normal distribution, which is approximately 1.96.
σ is the standard deviation of the population, which is 10 meters per second.
d is the difference between the true mean speed and the hypothesized mean speed, which is 100 - 94 = 6 meters per second.
Substituting these values into the formula, we get:
n = (1.04 + 1.96)^2 * 10^2 / 6^2
≈ 49.56
Therefore, a sample size of at least 50 would be required to detect a true mean speed as low as 94 meters per second with a power of at least 0.85, assuming a 5% significance level and a standard deviation of 10 meters per second.
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cual es la inversa de la funcion f(x) = -1/2 (x + 3 )
Answer:
-2x - 3
Step-by-step explanation:
f(x) = -1/2(x + 3) is the same as y = -1/2(x + 3)
change all y terms to x terms and all x terms to y terms
So change y = -1/2(x + 3) to x = -1/2(y + 3)
Now use the new equation and slove for y
x = -1/2(y + 3)
-2x = -2· -1/2 (y + 3)
-2x = y + 3
-2x - 3 = y
Rewrite your answer y = -2x - 3
Write the equation in the inverse
how to multiply matrices with different dimensions
The number of columns in the first matrix must equal the number of rows in the second matrix in order to multiply matrices with different dimensions.
First, jot down each matrix's dimensions. Let's imagine, for illustration, that we have a matrix A that is 2 by 3 and a matrix B that is 3 by 4. Create a new matrix C with the dimensions 2x4 in step 2. This is what the multiplication will ultimately produce.3. Determine the dot product of the corresponding row in matrix A and the corresponding column in matrix B for each element in matrix C.
4: The final response is matrix C, which is the union of the 2x3 matrix A and the 3x4 matrix B.
Therefore, the result is a 2x4 matrix, which is produced by taking the dot product of the rows and columns of matrix A and matrix B.
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answer the question picture is there
Answer:
Step-by-step explanation:
1. 500
2. 10
3. 25000
Please help i would appreciate it alot. PLEASE
Answer:I think it’s A or B
Step-by-step explanation:
Annual returns on the S&P 500 index are normally distributed with a mean of 11% and a standard deviation of 20%. What is the probability that the market return goes down between 5% and 25%? That is, if X is the return, calculate Pr(-25% < X < -5%). Answer in percent with ONE decimal place -- so if the answer is 25.4% just put in 25.4.
The probability that the market return goes down between -25% and -5% is approximately 13.3%.
To calculate the probability that the market return goes down between -25% and -5%, we need to find the area under the normal distribution curve between these two values.
First, we need to standardize the values using the Z-score formula:
Z = (X - μ) / σ
Where X is the value we are interested in (-25% and -5%), μ is the mean of the distribution (11%), and σ is the standard deviation (20%).
For -25%:
Z1 = (-25 - 11) / 20 = -0.8
For -5%:
Z2 = (-5 - 11) / 20 = -0.8
Next, we need to find the corresponding area under the standard normal distribution curve for these Z-scores. This can be done using a Z-table or a statistical software.
Using a Z-table, we can find that the area to the left of Z1 is approximately 0.2119 and the area to the left of Z2 is approximately 0.3446. To find the area between these two Z-scores, we subtract the smaller area from the larger area:
Pr(-25% < X < -5%) = 0.3446 - 0.2119 ≈ 0.1327
So, the probability that the market return goes down between -25% and -5% is approximately 13.3%.
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A train is traveling at a constant speed in miles per hour. Hours (x) Miles (y) Which equation models the data in the table? 1 20 2 100 O y=20x 3 180 O y = x + 80 4 260 5 340 Oy=60x – 80 O y = = 80x — 60
Given:
A train is traveling at a constant speed in miles per hour.
The table of value is:
Hours (x) Miles (y)
1 20
2 100
3 180
4 260
5 340
To find:
The equation for the given data table.
Solution:
It is given that the train is traveling at a constant speed in miles per hour. So, it is a linear relationship.
Choose any two point from the given table of value. Let the two points are (1,20) and (2,100). So, the equation of the line is:
\(y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)\)
\(y-20=\dfrac{100-20}{2-1}(x-1)\)
\(y-20=\dfrac{80}{1}(x-1)\)
\(y-20=80(x-1)\)
Add 20 on both sides.
\(y=80(x-1)+20\)
\(y=80x-80+20\)
\(y=80x-60\)
Therefore, the correct option is D.
Which of the following ordered pairs is a solution to the equation 2x+6y=6? Select all that apply.
elect all that apply:
(−6,3)
(10,4)
(−3,2)
(12,12)
(−3,−4)
Age
Two groups of students, Group A and Group B, have the age distributions shown.
Which statement about the distributions is true?
(5 Points)
Distribution B has a larger mean, but the medians of both distributions are the same.
Distribution B has both a larger mean and a larger median than distribution A.
o
Distribution B has a smaller mean, but the medians of both distributions are the same.
Distribution B has both a smaller mean and a smaller median than distribution A.
Answer:
the third distribution
How many solutions does the system have?
y=3x+3
y=−2x+3
choose 1 answer
A) Exactly one solution
B) No solutions
C) Infinitely many solutions
Answer:
A
Step-by-step explanation:
Given the 2 equations
y = 3x + 3 → (1)
y = - 2x + 3 → (2)
Substitute y = 3x + 3 into (2)
3x + 3 = - 2x + 3 ( add 2x to both sides )
5x + 3 = 3 ( subtract 3 from both sides )
5x = 0 , then
x = 0
Substitute x = 0 into (1)
y = 3(0) + 3 = 0 + 3 = 3
solution is (0, 3 ) → A
What is the product of 5/8 and 4?
We can calculate the product of 5/8 and 4 to be 5/2 using multiplication.
What is multiplication?Multiplication is one of the four basic mathematical operations, along with addition, subtraction, and division.
The result of a multiplication operation is a product.
There are four different methods for multiplying: addition, long multiplication, grid multiplication, and drawing lines.
So, we have:
5/8 and 4
5/8 is in the form p/q which represents the fraction that must be multiplied by 4.
Now, calculate the product as follows:
5/8 * 4
5/2
Therefore, we can calculate the product of 5/8 and 4 to be 5/2 using multiplication.
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jerimiah can type 300 words in 1/5 of an hour. How many words can he type in 1 hour
Answer:
1500 words
Step-by-step explanation:
300 times 5 equals 1500.
The following algebraic expression is given: 1 xy + 5y + 2x + 10 2.1 What do you notice about all 4 terms?
Answer: linear combo of terms involving x & y, with respective numbers determining their contribution to the expression
The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the eighth grade level. Step 2 of 2 : Suppose a sample of 1042 tenth graders is drawn. Of the students sampled, 834 read above the eighth grade level. Using the data, construct the 90% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level. Round your answers to three decimal places.
The 90% confidence interval for the population proportion of tenth graders reading at or below the eighth-grade level is (0.179, 0.220).
Firstly, determine the sample proportion:
The number of students reading at or below the eighth-grade level = Total students sampled - Students reading above the eighth-grade level
The number of students reading at or below the eighth-grade level = 1042 - 834
The number of students reading at or below the eighth-grade level= 208 students.
Sample proportion (p) = 208/1042
p = 0.1996 (rounded to four decimal places).
Now, we will determine the standard error (SE) for the sample proportion:
SE = √(p * (1 - p) / n)
= √(0.1996 * (1 - 0.1996) / 1042)
≈ 0.0124 (rounded to four decimal places)
Now, determine the z-score corresponding to the 90% confidence interval:
Since it is a 90% confidence interval, we will look for the z-score that has 0.05 in each tail (1 - 0.90 = 0.10, and 0.10 / 2 = 0.05). The z-score for a 90% confidence interval is 1.645.
Now, calculating the margin of error (ME):
ME = z-score * SE
= 1.645 * 0.0124 ≈ 0.0204 (rounded to four decimal places)
Lastly, constructing the 90% confidence interval:
Lower limit = p - ME
= 0.1996 - 0.0204
= 0.179 (rounded to three decimal places)
Upper limit = p + ME
= 0.1996 + 0.0204
= 0.220 (rounded to three decimal places)
So, the 90% confidence interval for the population proportion of tenth graders reading at or below the eighth-grade level is (0.179, 0.220).
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Tuesday 4. 4. 1 Subtraction Life Skills Language Wednesday 4. 4. 2 Length Solve grouping word problems with whole numbers up to 8 Recognise symmetry in own body Recognise number symbol Answer question about data in pictograph Thursday Question 4. 3 Number recognition 4. 4. 3 Time Life Skills Language Life Skills Language Life Skills Language Friday 4. 1 Develop a mathematics lesson for the theme Wild Animals" that focuses on Monday's lesson objective: "Count using one-to-one correspondence for the number range 1 to 8" Include the following in your activity and number the questions correctly 4. 1. 1 Learning and Teaching Support Materials (LTSMs). 4. 12 Description of the activity. 4. 1. 3 TWO (2) questions to assess learners' understanding of the concept (2)
4.1 Develop a mathematics lesson for the theme "Wild Animals" that focuses on Monday's lesson objective: "Count using one-to-one correspondence for the number range 1 to 8".
Include the following in your activity and number the questions correctly:
4.1.1 Learning and Teaching Support Materials (LTSMs):
Animal flashcards or pictures (with numbers 1 to 8)
Counting objects (e.g., small animal toys, animal stickers)
4.1.2 Description of the activity:
Introduction (5 minutes):
Show the students the animal flashcards or pictures.
Discuss different wild animals with the students and ask them to name the animals.
Counting Animals (10 minutes):
Distribute the counting objects (e.g., small animal toys, animal stickers) to each student.
Instruct the students to count the animals using one-to-one correspondence.
Model the counting process by counting one animal at a time and touching each animal as you count.
Encourage the students to do the same and count their animals.
Practice Counting (10 minutes):
Display the animal flashcards or pictures with numbers 1 to 8.
Call out a number and ask the students to find the corresponding animal flashcard or picture.
Students should count the animals on the flashcard or picture using one-to-one correspondence.
Assessment Questions (10 minutes):
Question 1: How many elephants are there? (Show a flashcard or picture with elephants)
Question 2: Can you count the tigers and tell me how many there are? (Show a flashcard or picture with tigers and other animals)
Conclusion (5 minutes):
Review the concept of counting using one-to-one correspondence.
Ask the students to share their favorite animal from the activity.
4.1.3 TWO (2) questions to assess learners' understanding of the concept:
Question 1: How many lions are there? (Show a flashcard or picture with lions)
Question 2: Count the zebras and tell me how many there are. (Show a flashcard or picture with zebras and other animals)
Note: Adapt the activity and questions based on the students' age and level of understanding.
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You were given 40 shares of stock the day you turned 18.
Financial Weekly listed the stock today at $32. 67.
On your birthday, the value of the stock was $15. 10 per share. If you were to sell the stock today, determine the total amount you would receive
The total amount received from selling the 40 shares of stock today, given a current value of $32.67 per share, would be $702.80.
To determine the total amount you would receive if you were to sell the stock today, we need to calculate the current value of the 40 shares.
Given that the stock is listed at $32.67 per share today, the current value of one share is $32.67. Therefore, the current value of 40 shares would be:
Current value = $32.67 * 40 = $1,306.80.
On your birthday, the value of the stock was $15.10 per share. Therefore, the value of one share at that time was $15.10. The total value of 40 shares on your birthday would be:
Value on birthday = $15.10 * 40 = $604.00.
To determine the total amount you would receive from selling the stock, you need to calculate the difference between the current value and the value on your birthday:
Total amount received = Current value - Value on birthday
= $1,306.80 - $604.00
= $702.80.
Therefore, if you were to sell the stock today, you would receive a total amount of $702.80.
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