68) The Pitot tube is commonly used to measure the air speed of an aircraft. Air flows into a small opening at the end of a tube that is closed at the other end, bringing the air to rest and allowing the measurement of the pressure difference between air at rest inside the tube and air moving rapidly just outside the tube. If the high-altitude air density is 0.364 kg/m3, and the pressure difference between inside and outside the tube is 9460 Pa, what is the airplane’s speed relative to the air?

Answer:

The meaning of the name “Birendra” is: “Great warrior”.

Explanation:

The meaning of the name "Birendra" is "Great warrior"

Explanation:

Categories: Hindi names, Hindu names, Indian names, Sanskirt names.

Here, we are given with:

\({:\implies \quad \longrightarrow \begin{cases}\sf E_{0}= 50\: V/m\\ \sf \nu = 2\times 10^{7}Hz\end{cases}}\)

(a) So now, we can thus obtain

\({:\implies \quad \sf \omega =2\pi \nu}\)

\({:\implies \quad \sf \omega =2\pi (2\times 10^{7})}\)

\({:\implies \quad \boxed{\bf{\omega = 4\pi \times 10^{7}\: s^{-1}}}}\)

Now, finding \(\lambda\)

\({:\implies \quad \sf \lambda =\dfrac{c}{\omega}=\dfrac{3\times 10^{8}}{4\pi \times 10^{7}}}\)

\({:\implies \quad \boxed{\bf{\lambda \approx 2.39\:m}}}\)

Now, finding k

\({:\implies \quad \sf k=\dfrac{2\pi}{\lambda}=\dfrac{200\pi}{239}}\)

\({:\implies \quad \boxed{\bf{k\approx 2.63\:m^{-1}}}}\)

Thus, expression for the electric field is:

\({:\implies \quad \boxed{\bf{E=50\sin \bigg(4\pi \times 10^{7}t-\dfrac{263x}{100}\bigg)}}}\)

(b) Now, here

\({:\implies \quad \sf B_{0}=\dfrac{E_{0}}{c}=\dfrac{50}{3\times 10^{8}}}\)

\({:\implies \quad \boxed{\bf{B_{0}\approx 16.67×10^{-7}\:T}}}\)

Thus, expression for the magnetic field:

\({:\implies \quad \boxed{\bf{B_{y}=16.67\times 10^{-7}\sin \bigg(4\pi \times 10^{7}t-\dfrac{263x}{100}\bigg)\:T}}}\)

(c) The electromagnetic wave propagates along Z-axis

The orbital speed of an ice cube in the rings of Saturn is 355358.97m/s

According to the gravitation law, the force of gravitation is directly proportional to the product of the masses and inversely proportional to the distance between them. Mathematically;

F = GMm/r²

where

m = mass of ice cube and

s = Gm1/r^2

Hence,

F = sm2

On rearranging,

s = m2/F

let V = orbital speed

centripetal acceleration = V^2/r

Such that;

V²/r = Gm/r²

V² = Gm/r

V = √Gm/r

Substitute the given parameters

V =  √6.67×10^-11 *  5.68 x 10^26 / 3.00 x 10^5

V = 355358.97m/s

Hence the orbital speed of an ice cube in the rings of Saturn is 355358.97m/s

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The free body diagram of the bas is shown below:

The torque is given by:

where F is the force and:

is the perpendicular distance between the rotation axis and the line of action of the force, which we called the moment arm. We know that the torque follows the principle of superposition then to find the total torque we need to add the torque each force exert. Before we do this we need to find the correct sign of the torque so we need to remember that if a force makes an object rotate counterclockwise then the torque is positive; otherwise it is negative. In this case Force two will exert a positive torque while the other two forces acting on the bar exert a negative torque.

For force one and the weight the moments arms are 5 m and 2.5 m, respectively. This comes from the fact that the forces are perpendicular to the rod.

For force two the moment arm is given as:

Hence the total torque is given by:

Therefore, the total torque on the bar is -3.9 Nm (this means that the bar will rotate clockwise).

Answer:

You need the definition of acceleration (a=Vf-Vi/t) and 1 equation of linear motion (deltaX = Vi×t + 1/2×a×t^2). Since you know a is constant (gravity) and you know your initial Vi to be 40 m/s and your final velocity Vf to be zero (maximum height), then you can use thhe definition of acceleration to find time.

-9.81m/s^2 = (0-40m/s)/t

t = (-40)/(-9.81) s

t = 4.077s

Now that you have time, you should know all but deltaX in the equation of linear motion.

dX = (40m/s)(4.077s) + (1/2)(-9.81m/s^2)(4.077s)^2

dX = (163.099m) — (81.549m)

dX = 81.55m

The net force on particle q₂, located between particles q₁ and q₃, is approximately 189000 N. The force exerted by particle q₁ on q₂ is positive and equals 252000 N, while the force exerted by particle q₃ on q₂ is negative and equals -63000 N.

To find the net force on particle q₂, we need to calculate the individual forces exerted on q₂ by particles q₁ and q₃ and then determine their sum.

The force between two charged particles can be calculated using Coulomb's law:

F = k * |q₁ * q₂| / r²

Where F is the force between the particles, k is the electrostatic constant (k ≈ 9.0 x \(10^9\) Nm²/C²), q₁ and q₂ are the charges of the particles, and r is the distance between them.

First, let's calculate the force exerted on q₂ by q₁:

F₁₂ = k * |q₁ * q₂| / r₁₂²

F₁₂ = (9.0 x \(10^9\) Nm²/C²) * |(8.0 μC) * (3.5 μC)| / (0.10 m)²

F₁₂ ≈ 252000 N

The force is positive because q₁ and q₂ have opposite charges.

Next, let's calculate the force exerted on q₂ by q₃:

F₂₃ = k * |q₂ * q₃| / r₂₃²

F₂₃ = (9.0 x \(10^9\)Nm²/C²) * |(3.5 μC) * (-2.5 μC)| / (0.15 m)²

F₂₃ ≈ -63000 N

The force is negative because q₂ and q₃ have the same charge.

Finally, we can find the net force on q₂ by summing the individual forces:

Net force = F₁₂ + F₂₃

Net force = 252000 N + (-63000 N)

Net force ≈ 189000 N

The net force on particle q₂ is approximately 189000 N.

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Move numbers to the boxes to show the factor pairs of 14:

Blank space 1: 1

Blank space 2: 1

Blank space 3: 2

Blank space 4: 7

A factor pair of a number is a pair of whole numbers that can be multiplied together to give the original number. For the number 14, the factor pairs are (1,14) and (2,7). So, we can put 1 in the first blank, 14 in the second blank, 2 in the third blank, and 7 in the fourth blank to show the factor pairs of 14.

To show the factor pairs of 14 in the given response area with 4 blank spaces, we need to find the two numbers that can be multiplied together to give 14. These two numbers are called factor pairs of 14.

To begin, we can start listing the factors of 14. The factors of 14 are 1, 2, 7, and 14. We can then use these factors to form factor pairs by multiplying them together. The factor pairs of 14 are (1, 14) and (2, 7).

To show these factor pairs in the given response area, we can put the first factor of each pair in the first and third blank spaces, and the second factor of each pair in the second and fourth blank spaces. Therefore, we can put 1 in the first blank, 14 in the second blank, 2 in the third blank, and 7 in the fourth blank to show the factor pairs of 14.

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Answer:

(a) the mechanical energy of the system, U = 0.1078 J

(b) the maximum speed of the object, Vmax = 0.657 m/s

(c) the maximum acceleration of the object, a_max = 15.4 m/s²

Explanation:

Given;

Amplitude of the spring, A = 2.8 cm = 0.028 m

Spring constant, K = 275 N/m

Mass of object, m = 0.5 kg

(a) the mechanical energy of the system

This is the potential energy of the system, U = ¹/₂KA²

U = ¹/₂ (275)(0.028)²

U = 0.1078 J

(b) the maximum speed of the object

\(V_{max} =\omega*A= \sqrt{\frac{K}{M} } *A\\\\V_{max} = \sqrt{\frac{275}{0.5} } *0.028\\\\V_{max} = 0.657 \ m/s\)

(c) the maximum acceleration of the object

\(a_{max} = \frac{KA}{M} \\\\a_{max} = \frac{275*0.028}{0.5}\\\\a_{max} = 15.4 \ m/s^2\)

The characteristics of the simple harmonic motion allows to find the results for the questions of the oscillating mass are:

     a) The total energy is: Em = 0.1078 J

     b) The maximum speed is: v = 0.657 m / s

    c) the maximum acceleration is: a = 15.4 m / s²

Given parameters

To find

    a) Mechanical energy

    b) Maximum speed

    c) Maximum acceleration

the simple harmonic movement is an oscillatory movement where the restoring force is proportional to the displacement, it is described by the expression:

         x = A cos (wt + Ф)

         w² = k / m

Where x is the displacement, A the amplitude w the angular velocity, t the time, Ф a phase constant, k the spring constant and m the mass.

A) The mechanical energy is

        Em = ½ k A²

Let's calculate.

       Em = ½ 275 (2.8 10⁻²) ²

       Em = 0.1078 J

b) Velocity is defined as the change of position with respect to time.

       v = \(\frac{dx}{dt}\)  = - Aw sin ( wt + fi)

To obtain the maximum velocity, the sine function must be ±1

        \(v_{max}\) = w A

Let's calculate

        w = \(\sqrt{\frac{275}{0.5} }\)  

        w = 23.45 rad / s

        \(v_{max}\) = 23.45 2.8 10⁻²

        \(v_{max}\) = 0.657 m / s

c) maximum acceleration.

Acceleration is defined as the change in velocity withtrspect to time.

       a = \(\frac{dv}{dt}\)  = - A w² cos (wt + fi)

To have the maximum value, the cosine function must be maximum, that is ±1

      a = A w²

let's calculate

       a = 2.8 10⁻²  23.45²

       a = 15.4 m / s²

In conclusion using the characteristics of the simple harmonic motion we can find the results for the questions of the oscillating mass are:

     a) The total energy is:  Em = 0.1078 J

     b) The maximum speed is:  v = 0.657 m / s

     c) the maximum acceleration is: a = 15.4 m / s²

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The magnitude of the electric flux through the sheet is 4.05 N m² C⁻¹ (Option E).

The electric flux through a surface is given by the product of the electric field strength and the area of the surface projected perpendicular to the electric field.

In this case, the electric field strength is 18 N C⁻¹, and the area of the sheet projected perpendicular to the electric field is 0.450 m²

(since the normal to the sheet makes an angle of 60° with the electric field). Multiplying these values gives the electric flux:

Electric flux = Electric field strength × Area

Electric flux = 18 N C⁻¹ × 0.450 m²

Electric flux = 8.1 N m² C⁻¹

In summary, the magnitude of the electric flux through the sheet is 4.05 N m² C⁻¹. This value is obtained by multiplying the given electric field strength by the projected area of the sheet perpendicular to the electric field.

The angle of 60° is taken into account to determine the effective area for calculating the flux.(Option E).

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Answer:

The weight of the planet is 29083.5 N .

Explanation:

mass of satellite, m = 6463 kg

height of orbit, h = 4.82 x 10^5 m

period, T = 2 h

radius of planet, R = 4.29 x 10^6 m

Let the acceleration due to gravity at the planet is g.

\(T = 2\pi\sqrt\frac{(R+h)^3}{gR^2}\\\\2\times 3600 = 2\times3.14\sqrt\frac{(4.29+0.482)^3\times10^{18}}{g\times 4.29\times 4.29\times 10^{12} }\\\\24.2 g =108.67\\\\g = 4.5 m/s^2\)

The weight of the satellite at the surface of the planet is

W = m g = 6463 x 4.5 = 29083.5 N

Answer:

they are related because..

Explanation:

Physical properties can be observed or measured without changing the composition of matter. Physical properties include: appearance, texture, color, odor, melting point, boiling point, density, solubility, polarity, and many others

The relation is ; Reflectivity and solubility are both physical properties of substances and are measured in relation to given variable ( i.e. incident ray for reflectivity and solvent for solubility )

Reflectivity ( aka optical property ) and solubility are both physical properties of any substance. while reflectivity of an object is measured as the amount of light an object reflects in relation to the light incident on it ( incident ray ), solubility is the amount of a substance that will dissolve in a given solvent at a given temperature.   a

Hence we can conclude that the relation between reflectivity and solubility is that they are both physical properties of substances and are measured in relation to given variable ( i.e. incident ray for reflectivity and solvent for solubility ).

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Answer:

Explanation:

For resistance , the expression is as follows .

R = ρ L / S where ρ is specific resistance , L is length of wire and S is cross sectional area .

cross sectional area = π x ( .5 x 10⁻³ )²

S = .785 x 10⁻⁶ m²

Putting the values

R = 2.82 x 10⁻⁸ x .50 / .785 x 10⁻⁶

= 1.796 x 10⁻² ohm .

The mass of the planet is  5.98 × 10^24 kg.

To calculate the mass of the planet, we can use Kepler's Third Law of Planetary Motion. This law states that the square of the period of revolution of a planet around the sun is directly proportional to the cube of the semi-major axis of its orbit.

First, we need to convert the period of the satellite's orbit to seconds. We know that there are 60 minutes in an hour, so the period can be expressed as (6 × 60 + 12) minutes, which equals 372 minutes. Multiplying this by 60 seconds, we get a period of 22,320 seconds.

Next, we need to find the semi-major axis of the orbit. In a circular orbit, the semi-major axis is equal to the radius of the orbit. Therefore, the semi-major axis is 8.8 × 10^6 m.

Now, we can apply Kepler's Third Law to calculate the mass of the planet. The formula is T^2 = (4π^2/GM) × a^3, where T is the period of revolution, G is the gravitational constant, M is the mass of the planet, and a is the semi-major axis of the orbit.

Rearranging the formula, we can solve for the mass of the planet:
M = (4π^2/G) × a^3 / T^2

Plugging in the values, we get:
M = (4 × π^2 / 6.67430 × 10^-11) × (8.8 × 10^6)^3 / (22,320)^2

Evaluating this expression, we find that the mass of the planet is approximately 5.98 × 10^24 kg.

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90.1 g of ice are still present in the container. Calculating the heat received by the ice to melt and the heat lost by the tea is necessary until it reaches an equilibrium temperature of 33.1 ◦C .

Consider how much energy is required to melt one kilogramme of ice at zero degrees to produce one kilogramme of water at zero degrees. The energy required to melt one kilogramme of ice is determined by Q = mLf = (1.0 kg)(334 kJ/kg) = 334 kJ using the equation for a change in temperature.

In order to calculate how much heat is gained by the ice melting, we must first calculate how much heat is lost by the tea as it cools from 33.1 °C to 0.0 °C.

Tea loses the following amount of heat: q1 = m1CT1 = 0.185 kg) (4186 J/kg C) (33.1 C - 0.0 C) = 26298.93 J.

Heat required for ice to melt is given by the formula: q2 = m2Hf = (0.0903 kg)(333.55 kJ/kg) = 30062.56 J

We may set q1 = q2 to get the mass of ice still present because the system is in thermal equilibrium:

m2 = q2/Hf = 333.55 kJ/kg / 30062.56 J = 0.0901 kg

Finally, we round the mass to two significant digits and convert it to grammes:

m2 = 90.1 g

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Answer:

s=0.204m

Explanation:

Assuming that the arrow is thrown horizontally and there is no air resistance, we can use the following formula to calculate the launch angle 0:

tan(0) = opposite/adjacent = height/distance

where opposite is the height that the arrow reaches and adjacent is the distance to the balloon.

Rearranging the formula, we get:

0 = arctan(height/distance)

0 = arctan(height/3)

Taking the tangent of both sides, we get:

tan(0) = tan(arctan(height/3))

tan(0) = height/3

Now, we need to find the height of the arrow. Using the kinematic equation:

v^2 = u^2 + 2as

where v is the final velocity (0m/s, at maximum height), u is the initial velocity (2m/s), a is acceleration (-9.8m/s^2, due to gravity) and s is the distance travelled vertically until the arrow reaches maximum height.

At maximum height, the final velocity is 0m/s. Therefore, we have:

0 = (2m/s)^2 + 2(-9.8m/s^2)s

Solving for s, we get:

s = 0.204m

Therefore, the height of the arrow is approximately 0.204m.

Answer:

firing a bullet

parade

swimming on a straight line

elevators

playing slide

Answer:

s = d/t = 20 m/40 s = 0.5 m/s

Explanation:

A swimmer swims a distance of 20 m in a time of 40 seconds, then the speed of the swimmer is 0.5 m/s.

The speed of an entity, which is a scalar quantity in regular usage and kinematics, can be defined as the size of the change in direction per unit time or the size of the change in position over time for an object. The initial speed is the upper limit of maximum pace as the duration of a time interval gets closer to zero.

The average pace of the object over an amount of time is computed by subtracting its distance traveled by the length of the interval. Velocity and speed are not the same.

As per the given data provided by the question,

Distance, d = 20 meters

Time, t = 40 seconds

Then average speed, s = d/t

s = 20/40

s = 0.5 m/s.

Therefore, the average speed of the swimmer is 0.5 m/s.

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It would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.

1. The decay rate of a radioactive isotope is proportional to the number of radioactive atoms present in the sample at any given time.

2. The decay rate can be expressed as a function of time using the formula: R(t) = R₀ * \(e^{(-\lambda t\)), where R(t) is the decay rate at time t, R₀ is the initial decay rate, λ is the decay constant, and e is the base of the natural logarithm.

3. The half-life of a radioactive isotope is the time it takes for half of the radioactive atoms in a sample to decay. In this case, the half-life is given as 210 days.

4. Using the half-life, we can find the decay constant (λ) using the formula: λ = ln(2) / T₁/₂, where ln(2) is the natural logarithm of 2 and T₁/₂ is the half-life.

5. Substituting the given half-life into the formula, we have: λ = ln(2) / 210.

6. Now, we need to find the time it takes for the decay rate to fall to 0.58 of its initial rate. Let's call this time "t".

7. Using the formula for the decay rate, we can write: 0.58 * R₀ = R₀ * e^(-λt).

8. Simplifying the equation, we get: 0.58 = \(e^{(-\lambda t\)).

9. Taking the natural logarithm of both sides, we have: ln(0.58) = -λt.

10. Substituting the value of λ from step 5, we get: ln(0.58) = -(ln(2) / 210) * t.

11. Solving for t, we have: t = (ln(0.58) * 210) / ln(2).

12. Evaluating the expression, we find: t ≈ 546.

13. Therefore, it would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.

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Change aspect of personality can occur by working hard and being focused on the changes you want to make.

A personality change can occur when an individual learns new habit. This new habit is developed or learnt through habitual responses that have stuck.

Thus, we can conclude that changing your habitual responses over time is one way to create personality change.

The only correct option is,  working hard and being focused on the changes you want to make.

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Answer:

Brain imaging aka Neuroimaging explores a series of mechanisms such as cognition, information processing, and brain changes in the functioning state. In addition, MRI, Magnetic resonance imaging, is a medical imaging test that produces detailed images of the brain.

Explanation:

The boat must have moved, despite not being seen to move, because its relative position to the dock has changed. This phenomenon is known as relative motion .

Everything is always in motion, but the way we perceive it depends on our frame of reference.

In this scenario, the dock was the frame of reference for the initial position of the boat. When the boat moved to the cove, its position relative to the dock changed, and the dock was no longer an appropriate frame of reference. The boat's motion is now relative to the cove instead.

It is important to note that relative motion depends on the chosen frame of reference. If we were to choose the boat as the frame of reference, then it would be the dock that appears to move, not the boat. This is because motion is always relative to a chosen frame of reference.

In conclusion, the boat must have moved because its position relative to the dock changed. The concept of relative motion reminds us that motion is always relative to a chosen frame of reference, and that the way we perceive motion depends on our chosen frame of reference.

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The reaction equations for the steps involved in the decay of U-238 to Ra-226 are;

\(^{238}_{92}U\ \rightarrow \ ^{234}_{90}Th \ + \ ^{4}_{2}He\)

\(^{234}_{90}Th \ \rightarrow \ ^{230}_{88}Ra \ + \ ^{4}_{2}He\)

\(^{230}_{88}Ra \ \rightarrow \ ^{226}_{86}Ra \ + \ ^{4}_{2}He\)

The radioactive equation for the decay of U-238 to Ra-226 is calculated as follows;

First the uranium atom (U-238) will decay thorium by emitting alpha particle as shown in the equation below;

\(^{238}_{92}U\ \rightarrow \ ^{234}_{90}Th \ + \ ^{4}_{2}He\)

The second stage is, the thorium will decay to radium by emitting alpha particles again as shown below;

\(^{234}_{90}Th \ \rightarrow \ ^{230}_{88}Ra \ + \ ^{4}_{2}He\)

The third, and final stage, the radium will decay to an isotope of radium again, by emitting alpha particle as shown below;

\(^{230}_{88}Ra \ \rightarrow \ ^{226}_{86}Ra \ + \ ^{4}_{2}He\)

Thus, the reaction equations for the steps involved in the decay of U-238 to Ra-226 are;

\(^{238}_{92}U\ \rightarrow \ ^{234}_{90}Th \ + \ ^{4}_{2}He\)

\(^{234}_{90}Th \ \rightarrow \ ^{230}_{88}Ra \ + \ ^{4}_{2}He\)

\(^{230}_{88}Ra \ \rightarrow \ ^{226}_{86}Ra \ + \ ^{4}_{2}He\)

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Answer:

Please see below as the answer is self- explanatory.

Explanation:

Question :-

Answer :-

Explanation :-

As per the provided information in the given question, we have been given that the Velocity of the ball is 12 m/s . Time is given as 36 sec . And, we have been asked to calculate the Acceleration .

For calculating the Acceleration , we will use the Formula :-

\( \bigstar \: \: \boxed{ \sf{ \: Acceleration \: = \: \dfrac{v \: - \: u}{t} \: }} \)

Where ,

Therefore , by Substituting the given values in the above Formula :-

\( \dag \: \: \: \sf { Acceleration \: = \: \dfrac{Final \: Velocity \: - \: Initial \: Velocity}{Time} } \)

\( \longmapsto \: \: \sf { Acceleration \: = \: \dfrac{0 \: - \: 12}{36}} \)

\(\longmapsto \: \: \sf {Acceleration \: = \: \dfrac{ \: 12 \: }{36}}\)

\(\longmapsto \: \: \sf {Acceleration \: = \: \dfrac{ \: 1 \: }{3}}\)

\( \longmapsto \: \bf {Acceleration \: = \: 0.33 \: m/s^{2}} \)

Hence :-

\( \underline {\rule {212pt} {4pt}} \)

The work and energy theorem allows finding the result for where the kinetic energy of the car is before stopping is:

    The energy becomes:

Work is defined by the scalar product of force and displacement.

          W = F . d

Where the bold indicate vectors, W is work, F is force and d is displacement.

The work energy theorem relates work and kinetic energy.

            W = ΔK = \(K_f - K_o\)

In this case the vehicle stops therefore its final kinetic energy is zero, consequently the work is:  

          W = - K₀

Therefore, the initial kinetic energy that the car has is converted into work in its brakes.  In reality, if assuming that there is friction, an important part is transformed into non-conservative work of the friction force, this work can be seen in a significant increase in the temperature of the discs on which the work is carried out.

In conclusion, using the work-energy theorem we can find the result for where the kinetic energy of the car is before stopping is:

    The energy becomes:

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Answer:

Explanation:

Given parameters:

Electrical energy  = 18J

Quantity of charge Q = 12C

Unknown:

Voltage  = ?

Solution:

The expression of electrical potential energy is given as:

      Electrical potential energy  = \(\frac{1}{2}\) c v²

c is the quantity of charge

v is the voltage

           18  =  \(\frac{1}{2}\)  x 12 x v²  

           18 = 6v²  

              v² = 3  

               v = 1.7v