7. You are handed two mystery materials and told to determine which one accepts


negative charges more easily. Using a positively charged, helium-filled balloon that is


tied to a tabletop with a 1 m long string, describe a simple experiment that will help you


identify the more attractive material.

Answer:

Nope.

Explanation:

No. The Moon rotates on its own axis at the same rate that it orbits around Earth. That means we always see the same side of the Moon from our position on Earth. The side we don't see gets just as much light, so a more accurate name for that part of the Moon is the "far side."

No, we can't see the similar quantity of the illuminated side of the Moon from the planet (Earth).

Thus the above answer is correct.

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Complete Question:

Football player A has a mass of 110 kg, and he is running down the field with a velocity of 2 m/s. Football player B has a mass of 120 kg and is stationary. What is the total momentum after the collision?

Answer:

Total momentum = 220 Kgm/s.

Explanation:

Given the following data;

For footballer A

Mass, M1 = 110kg

Velocity, V1 = 2m/s

For footballer B

Mass, M1 = 120kg

Velocity, V1 = 0m/s since he's stationary.

To find the total momentum;

Momentum can be defined as the multiplication (product) of the mass possessed by an object and its velocity. Momentum is considered to be a vector quantity because it has both magnitude and direction.

Mathematically, momentum is given by the formula;

\( Momentum = mass * velocity \)

a. To find the momentum of A;

\( Momentum \; A = 110 * 2 \)

Momentum A = 220 Kgm/s.

b. To find the momentum of B;

\( Momentum \; B = 120 * 0 \)

Momentum B = 0 Kgm/s.

c. To find the total momentum of the two persons;

\( Total \; momentum = Momentum \; A + Momentum \; B \)

Substituting into the equation, we have;

\( Total \; momentum = 220 + 0 \)

Total momentum = 220 Kgm/s.

The total momentum after the collision will be 220 Kgm/s.Momentum is equal to its mass multiplied by its velocity.

The measurement of mass in motion is called momentum. Momentum is equal to its mass multiplied by its velocity. Mathematically it is given as;

Momentum = Mass x Velocity

The given data in the problem is;

m₁ is the mass of player A= 110 kg

m₂  is the mass of player B= 120 kg

v₁ is the velocity of player A= 2m/s

v₂  is the velocity of player B=0m/s

P is the total momentum=?

The momentum of player A;

\(\rm P_A= m_A \times v_A \\\\ \rm P_A= 110 \times 2 \\\\ \rm P_A= 220 \ Kgm/sec\)

The momentum of player B;

\(\rm P_B= m_B \times v_B \\\\ \rm P_B= 120 \times 0 \\\\ \rm P_B= 0 \ Kgm/sec\)

The total momentum is given by;

Total momentum = momentum of the player A+ momentum of the player B

\(\rm P= P_A+P_B \\\\ \rm P= 220+0 \\\\ \rm P=220 \ m/sec\)

Hence the total momentum after the collision will be 220 Kgm/s

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Answer:

Explanation:

magnetic field B = (3 i + 8 x 2 j )x 10⁻³ T

= (3 i + 16 j )x 10⁻³ T

L = - i ( unit length of conductor )

Force F = I ( L x B ) , I is current

= 5 [ - i x ( 3i + 16 j ) 10⁻³]

= 5 ( - 16 k ) x 10⁻³

F = - 80 x 10⁻³ k

Answer:

hanbebdgsgzjbzbsijxbzyuxhzhbz

Explanation:

auhsbsbgsyuahsiixhwgs6

Answer:

18000

Explanation:

To multiply (6.0 x 10^-5) by (3.0 x 10^8), we can multiply 6 by 3 and then 10^-5 by 10^8.

Then

(6.0 x 10^-5)(3.0 x 10^8) = (6.0x3.0) x (10^-5 x 10^8)

(6.0 x 10^-5)(3.0 x 10^8) = 18 x 10^3

(6.0 x 10^-5)(3.0 x 10^8) = 18000

Therefore, the answer is 18000

Answer:

The upper fixed point, or steam point, is the temperature of pure boiling water at normal atmospheric pressure. Note that the fixed points are defined using common physical phenomena so that they can be easily reproduced.

Answer:

Steam point

Explanation:

The upper fixed point, or steam point, is the temperature of pure boiling water at normal atmospheric pressure.

Answer:

The functionality of a body can be restored with the help of appropriate flexibility and strengthening. Once everything is in place, you can exercise those muscles specifically for balance to put them to the test. Your body may then adjust, improving your general stability as you get better at completing those activities.

Answer:

The stability of an object is increased when the lower the centre of gravity is.

So we should try to lower the centre of gravity.

Number of bright fringes = 7

To calculate the number of bright fringes (visible maxima) in a diffraction pattern, we can use the formula for the diffraction grating equation:

n * λ = d * sinθ

Where n is the order of the bright fringe, λ is the wavelength of light (520 nm), d is the distance between adjacent slits in the grating, and θ is the angle of the diffracted light.

First, we need to find the distance between adjacent slits (d). The grating has 600 lines/mm, so we can calculate d as:

d = 1 / 600 lines/mm = 1/600 mm = 1.6667 * 10^(-6) m

Now, we can find the maximum order (n_max) that is visible using the grating equation:

n_max * 520 * 10^(-9) m = 1.6667 * 10^(-6) m * sin90°
n_max = 1.6667 * 10^(-6) m / 520 * 10^(-9) m
n_max ≈ 3.2

Since n must be an integer, the maximum order is n = 3.

To find the number of bright fringes, we count the orders on both sides of the central maximum (n = 0). So, there are 2 * 3 + 1 = 7 bright fringes in total.

The correct answer is b) 7.

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Answer:

15kg

Explanation:

mass = weight / gravitational field strength

mass = 150 / 9.8 = 15kg (nearest whole no)

The mass of the object on earth whose weight is 150 N will be 15.3 Kg

Mass is the amount of matter present inside a body. It is defined as the product of density and volume. It remains constant through out the universe. Mathematically -

M = ρV

where -

M is Mass

ρ is density

V is volume

Given is your weight on earth which is equivalent to 150 N.

We know that the weight of of an object is a force exerted by the earth towards its center. It can be written as -

W = mg

Weight of the object = [W] = 150 N

Acceleration due to gravity on earth = [g] = 9.8 m/s²

Substituting the values -

150 = m x 9.8

m = 150/9.8

m = 15.3 Kg

Therefore, the mass of the object on earth whose weight is 150 N will be 15.3 Kg.

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The initial potential energy of the diver is \(20,507.4 J\),  The final kinetic energy of the diver is \(1/2 (79 kg) \times (18.77 m/s)^2 = 14,030.3 J, C\). The velocity of the diver just before hitting the water is approximately \(18.77 m/s.\)

To resolve this issue, we can make use of energy conservation concepts. The diver only has potential energy at the beginning of the jump, which is transformed into kinetic energy as the diver falls toward the water.

A. The initial potential energy of the diver can be calculated as:

potential energy \(= mgh\)

Where m is the mass of the diver (79 kg), g is the acceleration due to gravity \((9.8 m/s^2)\) And h is the height of the diving board (27 m).

Therefore, potential energy \(= (79 kg) \times (9.8 m/s^2) \times (27 m) = 20,507.4 J\)

The initial potential energy of the diver is \(20,507.4 J.\)

B. All the initial potential energy has been transformed into kinetic energy right before the diver reaches the water. As a result, the diver's total kinetic energy can be determined as follows:

final kinetic energy \(= 1/2 mv^2\)

Where v is the diver's speed shortly before entering the water, and m is the diver's mass (79 kg).

We can compare the initial potential energy to the final kinetic energy by applying the law of conservation of energy:

\(mgh = 1/2 mv^2\)

Solving for v, we get:

v = \(\sqrt{2gh}\)

Where sqrt means square root.

Plugging in the values, we get:

\(v = sqrt(2 x 9.8 m/s^2 x 27 m) = 18.77 m/s\)

The final kinetic energy of the diver is \(v = sqrt(2 x 9.8 m/s^2 x 27 m) = 18.77 m/s\)

C. The velocity of the diver just before hitting the water is approximately

\(18.77 m/s.\)

Therefore, The velocity of the diver just before hitting the water is approximately \(18.77 m/s.\)

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The potential difference in a series circuit is the sum of the individual voltage drops across each component.

In a series circuit, the components are connected one after another in a single path, forming a loop. The potential difference, also known as voltage, is shared among the components in the circuit. Since the components are connected in series, the same current flows through each component and the potential difference is divided among them.

In this configuration, the potential difference across each component adds up to the total potential difference across the circuit. Therefore, the potential difference in a series circuit can be described as the sum of the individual voltage drops across each component.

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      Maybe this graph can help?

Yes you can, with using scientific experiment.

Ask a question -- Do background Research -- Construct a Hypothesis --Test with an Experiment -- Procedure working? -- Yes or no? -- Analyze Data and Draw Conclusions

With an experiment you can discover if its correct or not.

Hope this helps ! <3

Answer:

At 23.5 deg north of the equator this person would see the sun directly overhead at the summer solstice at noon

The enthalpy change for the reaction when 1 mole of FeCl₂(s) is 433.6 kJ/mol.

Reaction is the process of responding to a stimulus or action. It is an immediate response that is often instinctive and largely involuntary. Reaction is a natural process that helps us to adapt to our environment and survive. It can be physical, such as a reflex action, or emotional, such as feeling happy or sad.

The enthalpy change for a reaction is calculated by dividing the total amount of heat produced by the number of moles of product produced. In this case, 8.60 kJ of heat was produced when 1.42 g of iron reacted with 1.80 g of chlorine, yielding 3.22 g of FeCl₂(s). To calculate the enthalpy change per mole, we must convert the mass of FeCl₂(s) to moles. We can do this by taking the mass of FeCl₂(s) and dividing it by the molar mass of FeCl₂(s), which is 162.20 g/mol.

(3.22 g FeCl₂(s)) / (162.20 g/mol FeCl₂(s)) = 0.0198 mol FeCl₂(s)
We can now calculate the enthalpy change for the reaction when 1 mole of FeCl₂(s) is produced.
Enthalpy change = (8.60 kJ of heat) / (0.0198 mol FeCl₂(s)) = 433.6 kJ/mol.

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Answer:

You decide to drop two different objects from a tall building and discover that one of the objects lands on the ground five seconds before the other object. What can you conclude? Newton's second law is not valid because each object should experience the same force of gravity and therefore should land at the same time.

Explanation:

You decide to drop two different objects from a tall building and discover that one of the objects lands on the ground five seconds before the other object. What can you conclude? Newton's second law is not valid because each object should experience the same force of gravity and therefore should land at the same time.

You decide to drop two different objects from a tall building and discover that one of the objects lands on the ground five seconds before the other object. What can you conclude? Newton's second law is not valid because each object should experience the same force of gravity and therefore should land at the same time.

The required uniform deceleration of the car is 0.4167 m/s² and the speed of the car as it passes the light is 20.62 m/s.

Deceleration is a term used to describe the rate at which an object slows down or decreases its velocity. It is the negative acceleration, indicating a change in velocity in the opposite direction of motion. Deceleration can occur when an object is slowing down, coming to a stop, or changing its direction of motion.

Given information

Motorist's initial speed (u) = 54 km/h = 15 m/s

Distance of traffic light from the motorist (s) = 240 m

Time during which traffic light remains red (t) = 24 s

(a) To find the uniform deceleration of the car.

We have to calculate the rate of deceleration because the motion of the car is not in uniform motion. As the car is moving ahead and we have to find the rate of deceleration of the car when the motorist wishes to pass the light without stopping just as it turns green again.

Now, we can apply the first equation of motion to calculate the deceleration of the car.

The first equation of motion can be written as,

s = ut + (1/2)at²

where u = initial speed = 15 m/s

t = 24 s (time during which traffic light remains red)

s = distance covered by the car = 240 m

We know that after the car passes the traffic light, its final velocity will be zero because the car will be at rest after it passes the traffic light.

We have, final velocity of the car = 0

Putting the values in the above equation, we get

240 = 15 x 24 + (1/2) a(24)²

240 = 360 + 288a

240 - 360 = 288a

-120 = 288a

Dividing both sides by 288, we get

- 120/288 = a/2.4

a = - 0.4167 m/s²

Therefore, the rate of deceleration of the car is 0.4167 m/s²

(b) To find the speed of the car as it passes the light

As the car passes the traffic light, its final velocity will be zero because the car will be at rest after it passes the traffic light.

We can use the third equation of motion to find the speed of the car as it passes the light because the initial velocity of the car is known.

The third equation of motion can be written as:

v² = u² + 2as

where u = initial speed = 15 m/s

a = deceleration of the car = - 0.4167 m/s²

s = distance covered by the car = 240 m

v = final velocity of the car = ?

Putting the values in the above equation, we get:

v² = 15² - 2(- 0.4167) (240)

v² = 225 + 200v² = 425

v = √425

v = 20.62 m/s

Therefore, the speed of the car as it passes the light is 20.62 m/s

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No. of harmonics = frequency of the highest harmonic / frequency of the fundamental frequency No. of harmonics = 96.802 / 30.8677 No. of harmonics = 3.1359 ≈ 3 harmonics.

The lowest pitch (B0) of the contrabass clarinet has frequency 30.8677 Hz. We are to find the number of harmonics that appear below 100 Hz. The formula for the harmonic frequency is given by; fn = nf1 Where, fn is the frequency of the nth harmonic n is the number of harmonics f1 is the fundamental frequency If we take the highest frequency that is less than 100 Hz, it is 96.802 Hz. The fundamental frequency of the clarinet is; B0 = 30.8677 Hz.

The fundamental frequency is also f1. The number of harmonics appearing below 100Hz is thus; No. of harmonics = frequency of the highest harmonic / frequency of the fundamental frequency No. of harmonics = 96.802 / 30.8677No. of harmonics = 3.1359 ≈ 3 harmonics.

Therefore, there are three harmonics that appear below 100 Hz.

No. of harmonics = frequency of the highest harmonic / frequency of the fundamental frequency

No. of harmonics = 96.802 / 30.8677

No. of harmonics = 3.1359 ≈ 3 harmonics.

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The present value of the following single amounts are as follows;

PV for FV = $20,000, I =7%, N =10 years is $10,155.84

PV for FV = $14,000, I =8%, N =12 years is $4,489.92

PV for FV = $25,000, I =12%, N =20 years is $2,590.11

PV for FV = $40,000, I =10%, N =8 years is $18,520.89.

Future value (FV) =$20,000,

Interest rate (I) =7%,Time (n) = 10 years

The present value (PV) can be calculated as follows;

PV = FV / (1 + i)n = 20000 / (1 + 0.07)10PV = 20000 / 1.96715PV = $10,155.84

Future value (FV) =$14,000,

Interest rate (I) =8%,

Time (n) = 12 years

The present value (PV) can be calculated as follows;

PV = FV / (1 + i)n = 14000 / (1 + 0.08)12PV = 14000 / 3.12159PV = $4,489.92

Future value (FV) =$25,000,

Interest rate (I) =12%,Time (n) = 20 years

The present value (PV) can be calculated as follows;

PV = FV / (1 + i)n = 25000 / (1 + 0.12)20PV = 25000 / 9.64632PV = $2,590.11

Future value (FV) =$40,000,Interest rate (I) =10%,Time (n) = 8 years

The present value (PV) can be calculated as follows;

PV = FV / (1 + i)n = 40000 / (1 + 0.1)8PV = 40000 / 2.15893PV = $18,520.89

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Answer:

Spring tides occur when the moon is full or new. Earth, the moon, and the Sun are in a line. The moon’s gravity and the Sun’s gravity pull Earth’s crust and ocean water. This causes tides to be higher than normal.

At neap tide, the moon and the Sun are at right angles to each other. This happens during the first and third quarters of the lunar cycle. At neap tide, the Sun’s gravity and the moon’s gravity are balanced. High tides are lower; low tides are higher.

Answer:

Relative humidity is a measure of the percentage of water vapor in the air in a particular area

Answer: relative humidity

Explanation:

The form of energy stored in a stretched spring is elastic potential energy. When a spring is stretched or compressed, it possesses potential energy due to the deformation of its structure.

This potential energy is called elastic potential energy because it is associated with the elasticity of the spring.

As the spring is stretched, work is done to overcome the forces within the spring that resist the change in its length. This work is converted into potential energy, which is stored in the spring. The amount of potential energy stored in the spring is directly proportional to the amount by which it is stretched or compressed.

When two forces are simultaneously applied to a spring in opposite directions, it may result in elongation or contraction of the spring, depending on the magnitude and direction of the forces. If the applied forces are strong enough to overcome the spring's elasticity, the spring will undergo deformation and exhibit elongation or contraction. This deformation is a manifestation of the stored elastic potential energy being converted into mechanical energy.

Shear, bending, and intermolecular binding energy are not directly related to the stretching of a spring.

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Answer:

whats the question??????

The final velocity of the second person after the collision is determined as 1.6 m/s to the right.

The final velocity of the second person is determined by applying the principle of conservation of linear momentum.

m1u1 + m2u2 = m1v1 + m2v2

85.2(0) + 65.4(0) = 85.2(-1.2) + 65.4(v2)

0 = -102.24 + 65.4v2

65.4v2 = 102.24

v2 = 1.56 m/s to the right

Thus, the final velocity of the second person after the collision is determined as 1.6 m/s to the right.

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The angle is 21.0°.

When two straight lines or rays intersect at a single endpoint, an angle is created. The vertex of an angle is the location where two points come together.

Given:

R = 225m

\(m_{c}\) = 1125kg,​

\(m_{t}\)=2250kg

​v = 65mph = 29.1m/s

g = 9.8 m/s²

It is necessary to use the formula below in order to correctly manipulate these numbers:

\(a_{rad}\) = v²/R

a) \(\sum F_{x} =nsin\theta = ma_{rad}\)

\(\sum F_{y} = ncos\theta+ (-mg) =0\)

The centripetal acceleration, a rad = dfracv2, and the horizontal component of the normal force are both present in the acceleration in the x-direction. \(a_{rad}\) =v²/R. Since there should be no acceleration in the y-direction (i.e., no slipping off the road), the y-component is set to zero. The acceleration in the y-direction is the result of adding the vertical component of the normal force with the acceleration caused by gravity.

solving \(\sum F_{y}\) for n yields n = mg/cosθ

Substituting this into \(\sum F_{x}\) using \(a_{rad}\) = v²/R

yields mg/cosθ ×sinθ = mv²/R

solving for θ yields tanθ = v²/gR (or) θ = \(a_{rad}\) v²/gR

As a result, the angle solely depends on the curve's radius and speed. The results are obtained by incorporating those values with the gravitational acceleration constant.

\(a_{rad}\) (29.1)²/22.5×9.8 = \(a_{rad}\) (0.384) = 21.0°.

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Answer:

Sample Response: If temperature and surface area increase, then the time it takes for sodium bicarbonate to completely dissolve will decrease, because increasing both factors increases the rate of a chemical reaction.

Explanation:

For weightless object, gravity is equal to centripetal acceleration. The radius of the loop is calculated as 8 km.

The property of the motion of an object traversing a circular path is known as centripetal acceleration. Any object that is moving in circle and has an acceleration vector pointed towards center of that circle is Centripetal acceleration.

As Centripetal Acceleration formula is;

a = v²/r

Given, V-  velocity =  280 m/s

And we know that for weightless object,

Gravity =  centripetal acceleration

So, a =  g

given, g =9.8 m/s²

So,9.8 = 280²/r

r= 8000 m

Radius of the loop = 8 km

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