9. calculate the ph of a buffered solution prepared by dissolving 21.5 g benzoic acid and 37.7 g sodium benzoate in 200.0 ml of solution.

The alkali metals are a group of elements in the periodic table that consist of lithium (Li), sodium (Na), potassium (K), rubidium (Rb), cesium (Cs), and francium (Fr).

These elements are characterized by their similar properties, and they are all located in Group 1 (also known as Group IA) of the periodic table.

The alkali metals are known for their high reactivity and low ionization energy. They are also highly reactive with water, and they can easily lose an electron to form a positively charged ion, which is why they are called "alkali" metals. They are silvery-white in color, and they have low densities and melting points.

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Andrea Ghez's favorite star is known as SO-2 and it is her favorite star because this star goes around the universe in a short period. I do not have a favorite star because I do not know a lot about stars.

Andrea Ghez is female astrophysicst who was born in the United States known for being one of the few women in the world who have gotten the Nobel Prize in Physics. During her life, Andrea has studied the center of the universe, black holes and the stars. Moreover, she was known for giving a TED talk in whiich she explained about stars and black holes.

In the TED talk given by Andrea Ghez she mentions her favorite star is the  SO-2 as "it goes around in only 15 years".

I do not have a favorite star because I do not know a lot about stars, although I believe studying them is very interesting.

Note: This question is incomplete; here is the missin information:

TED Talk- Andrea Ghez

"Now, most astronomers have a favorite star, and mine today is a star that's labeled up there, SO-2. Absolutely my favorite star in the world. And that's because it goes around in only 15 years. And to give you a sense of how short that is, the sun takes 200 million years to go around the center of the galaxy"

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0.5 moles of KOH contained in 250 mL of a 2.0 M solution of KOH.

Molarity is a measure of the concentration of a solution, defined as the number of moles of solute per liter of solution.

It is commonly denoted as "M" and has units of moles per liter (mol/L). The molarity of a solution can be calculated by dividing the number of moles of solute by the volume of the solution in liters.

Given:

Volume = 250 ml

250 mL = 0.25 L

Molarity = 2.0 m

To calculate the number of moles of KOH in a solution, the formula is:

Moles of solute = Molarity x volume of solution (in liters)

Use the formula:

Moles of KOH = 2.0 M x 0.25 L

Moles of KOH = 0.5 moles

Thus, there are 0.5 moles of KOH in 250 mL of a 2.0 M solution of KOH.

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Answer:

A, 4Fe 3O2 → 2Fe2O3

Answer:

Explanation:

47 i took the test

Silver (Ag) has 47 protons, 60 neutrons, and 47 electrons in each atom. Based on this information, the mass number of the silver would be 107.

The total number of protons present in an atom is known as the atomic number of that atom. The atomic number has no correlation either with the number of neutrons or the number of electrons present inside an atom.

As given in the problem Silver (Ag) has 47 protons, 60 neutrons, and 47 electrons in each atom.

The atomic number of the silver =  number of protons

                                                     = 47

The mass number of the silver = number of protons + number of neutrons

                                                   =47 + 60

                                                   =107

Thus, based on the given information the mass number of the silver would be 107.

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Answer:

I believe the answer is y-axis

Explanation:

Sorry if it's not I just wanted to help you in return for helping me!!

Answer:

Y axis I think

Explanation:

Answer:

\({ \rm{2H {}^{ + } _{(aq)} + CO {}^{2 - } _{3(aq)} \: \: \: {}^{ { \huge{\dashrightarrow} }} _{ \huge{ \dashleftarrow}} }} \: \: { \rm{H _{2} CO _{3(aq)} }}\)

Answer:

24.7 grams H₂O

Explanation:

To find the mass of water, you should (1) convert from grams HCl to moles (via molar mass from periodic table), then (2) convert from moles HCl to moles H₂O (via mole-to-mole ratio from equation), and then (3) convert from moles H₂O to grams (via molar mass from periodic table).

1 HCl + KOH --> 1 H₂O + KCl

Molar Mass (HCl): 1.008 g/mol + 35.45 g/mol
Molar Mass (HCl): 36.458 g/mol

Molar Mass (H₂O): 2(1.008 g/mol) + 16.00 g/mol
Molar Mass (H₂O): 18.016 g/mol

50 g HCl        1 mole HCl          1 mole H₂O           18.016 g
--------------  x  ------------------  x  -------------------  x  -------------------  = 24.7 g H₂O
                        36.458 g           1 mole HCl          1 mole H₂O

Answer:Main Answer:

The mass of CO2 released in the production of 123,000 g of H2 gas is 265,200 g.

Explanation: From the given equation, we can see that the production of 4 moles of H2 requires the combustion of 1 mole of CH4, resulting in the release of 2 moles of H2O and 1 mole of CO2. The molar mass of H2 is 2 g/mol, and the molar mass of CO2 is 44 g/mol. Therefore, the mass of CO2 released in the production of 123,000 g of H2 is (123,000/2) x (1/4) x 44 = 265,200 g.

Answer:

9

Explanation:

7 is neutral anything higher than 7 is a base anything lower than 7 is an acid.

Components of atoms are called subatomic particles and generally include the proton, electron, and neutron.

What are subatomic particles?

Proton:

Proton and neutron make the nucleus of an atom and hence are called nucleons.

Electron:

Electrons are subatomic particles that revolve around nucleus of an atom.

Neutron:

Neutrons are named for their neutral nature as unlike protons and electrons they dont carry any charge

Protons and electrons are subatomic particles which are equal in a neutral atom

What are ions?

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Answer:

1) H2

2) Chlorine

3) Lead bromide

Answer:

number 3.

Explanation:

Answer:

3

Explanation:

Empirical formula tells us the relative ratios of different atoms in a compound.

The chemical formula for a compound obtained by composition analysis is always the empirical formula.

How to calculate Empirical formula:

Linalyl acetate (bergamot oil):

              Carbon               Hydrogen                  Oxygen

                73.41 %                   10.29 %                  16.30 %

             73.41 / 12               10.29 / 1                   16.30 / 16

               6.11                          10.29                        1.01

            6.11 / 1.01                10.29 / 1.01                1.01 / 1.01

                 6                            10                                1

          Empirical formula : C₆H₁₀O

Thus we can conclude that empirical formula of linalyl acetate is  C₆H₁₀O

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The empirical formula for Linalyl acetate expresses the relative proportions of different atoms in a compound.

Linalyl acetate is a phytochemical found in a variety of flowers and spice plants. It is an important component of bergamot and lavender essential oils. It is the linalool acetate ester, and the two are frequently found together.

Hence, the empirical formula describes the relative proportions of different atoms in a compound. The chemical formula for a compound obtained through composition analysis is always the empirical formula.

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37 percent is the increase in percentage.

The air bubbles locked in ice sheets as well as glaciers over Earth's previous three glacial cycles are used in the second graph to depict carbon dioxide (CO2) levels during those periods. Human activities had boosted atmospheric CO2 approximately 50% since the start of the industrial era (in the 18th and 19th centuries), bringing it to 150% of it's own value in 1750.

Actually 282 ppm means 282 gm of CO2 is in 1 million gm of air similarly 382 ppm means 387 gm is in 1 million gm of air . Increase in mass of CO2 387-282 = 105 gm .

So percentage increase= (105× 100)÷282= 37%

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Answer:

In the formation of 1 formula unit of Al2O3 in the reaction 4Al + 3O2 → 2Al2O3, a total of 12 electrons are transferred, with each aluminum atom gaining 3 electrons through oxidation and each oxygen molecule gaining 4 electrons through reduction.

Explanation:

In the oxidation-reduction reaction equation: 4Al + 3O2 → 2Al2O3, the reaction involves the oxidation of aluminum (Al) and the reduction of oxygen (O2). The formation of 1 formula unit of the product Al2O3 involves the transfer of a specific number of electrons.

To determine the number of electrons transferred, we need to look at the change in oxidation states of the elements involved. In this case, aluminum (Al) is oxidized from an oxidation state of 0 to +3, while oxygen (O) is reduced from an oxidation state of 0 to -2.

Each aluminum atom gains three electrons during the oxidation process, as its oxidation state increases from 0 to +3. Considering that there are four aluminum atoms in the reaction, a total of 4 × 3 = 12 electrons are transferred due to the oxidation of aluminum.

On the other hand, each oxygen molecule (O2) gains four electrons during the reduction process, as its oxidation state decreases from 0 to -2. Since there are three oxygen molecules in the reaction, a total of 3 × 4 = 12 electrons are transferred due to the reduction of oxygen.

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Answer:

option c

Explanation:

E = hf

E= energy

h = Planck constant

f = frequency

E = 6.6 X 10^-34 X 4 X 10^14

E = 2.64 X 10^-19J

Answer

Procedure

Considering the following chemical equation, which is already balanced

C₃H₈ + 5O₂ → 3CO₂ + 4H₂O

We assume there is enough oxygen to react with all propane and thus, propane is the limiting reactant

Therefore we use the equation to determine the amount of propane

189.68g CO₂ /

doAnswer:

Explanation:

i  don¨t lf it rigtht but i thnk it C3h8 an a thank u

Answer:

\(\boxed {\boxed {\sf 19.3 \ g/cm^3}}\)

Explanation:

We are asked to calculate the density of gold. The density of a substance is its mass per unit volume. It is calculated using the following formula.

\(\rho= \frac{m}{v}\)

The mass of the sample is 96.5 grams. The volume of the sample is 5.00 cubic centimeters.

Substitute the values into the formula.

\(\rho= \frac{ 96.5 \ g}{5.00 \ cm^3}\)

Divide.

\(\rho= 19.3 \ g/cm^3\)

The density of gold is 19.3 grams per cubic centimeter.

The measure of the total energy radiated by a star in one second is called luminosity.

Luminosity represents the intrinsic brightness of a star and is a measure of the total power output in terms of energy. It is an important characteristic of a star that indicates its size and temperature.

Luminosity is typically expressed in units of watts or solar luminosities (the luminosity of our Sun). Flux, on the other hand, refers to the amount of energy received per unit area per unit time, and it is influenced by the distance between the star and the observer. Apparent magnitude and absolute magnitude are measures of a star's brightness as observed from Earth and at a standard distance, respectively, and they are related to luminosity but not the direct measure of energy radiated.

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Percentage by mass of water in CuSO4.5H20 is 36.07% .

In this problem we have - copper(II) sulfate pentahydrate and it's molecular formula is (CuSO₄.5H₂O) .

There are 5 molecules of water are present.

Now we calculate it's molar mass-

We know that-

molar mass of Cu = 63.5u

Molar mass of SO₄ = 96 u

Molar mass of H₂O = 18 u

Now, molar mass of (CuSO₄.5H₂O) = 63.5 + 96 + 5 × 18

Now, molar mass of (CuSO₄.5H₂O) = 249.5u

And mass of water in CuSO₄.5H₂O = 90 u

now mass percentage of water = mass of water ÷ Total mass ×100

now mass percentage of water = 90 ÷ 249.5 × 100

now mass percentage of water =  36.07 %

So we find out mass percent by dividing given mass with total mass and then multiplying it with hundred and it came out to be 36.07 % .

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Answer:

36.1

Explanation:

False. The statement that the Martian polar caps are mainly frozen methane and ammonia is false. The Martian polar caps primarily consist of water ice and carbon dioxide (CO₂) ice.

The Martian polar caps, also known as the Martian ice caps, are composed mainly of water ice. These caps are analogous to Earth's polar ice caps and contain a significant amount of frozen water. The water ice at the Martian poles is mixed with carbon dioxide ice, which forms a seasonal cap of dry ice during the colder Martian winters.

Methane (CH₄) and ammonia (NH₃) are present in trace amounts in the Martian atmosphere, but they are not the primary constituents of the polar caps.
Methane on Mars is a particularly interesting topic of study, as its presence has been detected and is attributed to various potential sources such as geological activity or microbial life. However, it is not a dominant component of the polar caps.

So, the main constituents of the Martian polar caps are water ice and carbon dioxide ice, while methane and ammonia are present in smaller quantities in the Martian atmosphere but do not primarily compose the polar caps.

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The final volume of the solution would be 1200 mL when a 500.0 mL solution of 2.40 M KCl is diluted to 1.00 M as dilution involves adjusting the concentration by adding a solvent (usually water) while keeping the number of moles constant.

M₁V₁ = M₂V₂

Where: M₁ = initial concentration, V₁ = initial volume ,M₂ = final concentration, V₂ = final volume

In this case, 

M₁ = 2.40 M (initial concentration), V₁ = 500.0 mL (initial volume) ,M₂ = 1.00 M (final concentration) ,V₂ = ? (final volume)

M₁V₁ = M₂V₂

(2.40 M)(500.0 mL) = (1.00 M)(V₂)

Now, for V₂:

V₂ = (2.40 M)(500.0 mL) / (1.00 M)

V₂ = 1200 mL

The final volume of the solution would be 1200 mL 

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To determine which cubic unit cell strontium (Sr) crystallizes in, we need to calculate its atomic packing factor (APF) for each of the three cubic unit cells:



simple cubic (SC), body-centered cubic (BCC), and face-centered cubic (FCC).The APF is the fraction of space in a unit cell that is occupied by atoms. It is calculated as follows:APF = (number of atoms in a unit cell x volume of each atom) / volume of the unit cellFor a cubic unit cell, the volume of the unit cell is given by:volume of unit cell = a^3where a is the length of the side of the cube.For a simple cubic unit cell, there is only one atom at each corner of the cube. The length of the side of the cube (a) is equal to twice the atomic radius (2r). Therefore, the volume of each atom is:volume of atom = (4/3) x pi x r^3 = (4/3) x pi x (216.3 pm)^3 = 2.613 x 10^-23 cm^3The volume of the unit cell is:volume of unit cell = a^3 = (2r)^3 = 8 x (216.3 pm)^3 = 9.295 x 10^-22 cm^3The number of atoms in a simple cubic unit cell is 1, so the APF is:APF = (1 x 2.613 x 10^-23 cm^3) / (9.295 x 10^-22 cm^3) = 0.281For a body-centered cubic unit cell, there is one atom at each corner of the cube and one atom at the center of the cube. The length of the side of the cube (a) is equal to four times the atomic radius (4r/√3). Therefore, the volume of each atom is:volume of atom = (4/3) x pi x r^3 = (4/3) x pi x (216.3 pm)^3 = 2.613 x 10^-23 cm^3The volume of the unit cell is:volume of unit cell = a^3 = (4r/√3)^3 = (64/3) x (216.3 pm)^3 = 6.452 x 10^-22 cm^3The number of atoms in a body-centered cubic unit cell is 2, so the APF is:APF = (2 x 2.613 x 10^-23 cm^3) / (6.452 x 10^-22 cm^3) = 0.68For a face-centered cubic unit cell, there is one atom at each corner of the cube and one atom at the center of each face of the cube. The length of the side of the cube (a) is equal to two times the square root of two times the atomic radius (2√2r). Therefore, the volume of each atom is:volume of atom = (4/3) x pi x r^3 = (4/3) x pi x (216.3 pm)^3 = 2.613 x 10^-23 cm^3The volume of the unit cell is:volume of unit cell = a^3 = (2√2r)^3 = 32 x (216.3 pm)^3 = 1.238 x 10^-21 cm^3The number of atoms in a face-centered cubic unit cell is 4, so the APF is:APF = (4 x 2.613 x 10



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The empitical formula shows the simplest ratio of elements in a compound (not the total number of atoms in the molecule).

So to find the empirical formula we need to calculate how many moles of each atom we have in this sample. Then we will see the ratio of each element.

We are given the mass, so to convert it to moles we use the molar mass. For this we go to the periodic table and see that the values for each element are:

Na (sodium): 22,99 g/mol

H (hydrogen): 1 g/mol

P (phosphorus): 25,81 g/mol

So we calculate the moles of each element as follows:

And as we see, for every 0.833 moles of Na we have the same number of moles of P, so the ratio of these elements in the molecule is 1 to 1.

As for the hydrogen:

So the ratio Na to H is 1 to 2.

Now we can write the empirical formula as follows=