9. If 100 J of work is done in 20 second the power is ..

200-watts
20,000watts
5 watts
80watts

Answer:

To Avoid accidents and injuries

Explanation:

Safety measures are vital dancing as this may prevent bad things like accidents and injuries from happening.

When dancing,the safety of dancers is a must to be observed and considered.

Dancers are also most likely to exert their full potential if they know that they are safe no matter what happen....

HAVE A GOOD DAY....

The force which acts on the third charge placed in between the two charges can be expressed as,

Here, F is the net force, k is the force constant, q1 is the first charge, q2 is the second charge, q3 is the second charge and r is the distance between first and third charge. Since the third charge is placed in midway of both the charges therefore,

Plug in the known values in the expression,

Therefore, the net force which acts on the third charge is -18 N in which negative sign indicates that the direction of force is towards the negative charge of the system.

Answer:

The generated sound wave will not be able to reflect off of the object.

Explanation:

The statement that best describes this situation is: The generated sound wave will not be able to reflect off of the object.

An ultrasound machine is a device that is used to capture images in the human body for review by a medical examiner. The machine gives off sound waves that are reflected off body structures.

So, for the ultrasound machine being described, the absence of kidney stones will cause a non-reflection of the object to be captured.

Since the machine is in good working condition, the sound wave will be generated.

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The average frictional force exerted on the block by the rough section of the surface D 4N.

Frictional force is the force exerted between two objects when they are in contact and one object is moving relative to the other. It is caused by the microscopic irregularities on the surface of the objects, which cause them to stick together and resist relative motion. Frictional forces are always present, and can be beneficial in some cases, but can also cause wear and other forms of damage if too great. Frictional forces can be reduced by applying a lubricant, such as oil or grease, which reduces the surface area of contact and allows the objects to move more easily.

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The statement true about sound waves is " Sound moves faster in the ocean than in the air."  The correct option is C.

Sound waves travel much faster in water (such as the ocean) compared to air. The speed of sound in air is around 343 meters per second at room temperature, while in water, it is about 1,500 meters per second. The denser medium of water allows sound waves to propagate more quickly.

A. Sound would move faster in a pool of water than in a pool of Jello: This statement is not true. Sound actually moves faster in water compared to Jello. The speed of sound depends on the medium it travels through, and in general, sound travels faster in denser materials. Water is denser than Jello, so sound waves would move faster in water.

B. Sound would move faster in a pool of rubber than in a pool of diamonds: This statement is not true. Sound waves do not travel faster in rubber compared to diamonds. In fact, the speed of sound in a material depends on its elasticity and density. Diamonds are much denser and have a higher elasticity compared to rubber, so sound waves would move faster in diamonds than in rubber.

D. Sound moves faster in a lake than in the ocean: This statement is not true. Sound waves do not travel faster in a lake compared to the ocean. The speed of sound in water depends on several factors, including temperature, salinity, and pressure. In general, the speed of sound is higher in the ocean compared to lakes due to the higher salinity and pressure in the ocean.

Therefore, C. Sound moves faster in the ocean than in the air: This statement is true.

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When the teacher asked the student to make words out of the jumbled word gzeysktqix, the student was being tested on his ability to unscramble words. Unscrambling words is the process of taking a word or series of letters that are out of order and rearranging them to form a word that makes sense.

When trying to unscramble a word, it is important to look for any patterns that can help identify smaller words within the jumbled letters. This can help make the process easier and quicker. For example, in the jumbled word gzeysktqix, one might notice that the letters "sktqix" appear together.

This could indicate that these letters could potentially form a word. By looking at the remaining letters, one could notice that the letters "g", "z", "e", and "y" could also form smaller words. After some rearranging, the letters can be unscrambled to form the words "sky", "zig", "sex", and "yet". These are just a few examples, as there are likely many other words that can be formed from this jumbled word.

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Answer:

A. reduce the amount of soil by one-half and apply the same amount of force

Explanation:

All the equations of motion are as follows, Displacement (s) equation, Final velocity (v) equation, Average velocity (v_avg) equation, Displacement (s) equation with average velocity, and Displacement (s) equation.

In terms of its motion as a function of time, equations of motion define how a physical system behaves. In more detail, the equations of motion define how a physical system behaves as a collection of mathematical functions expressed in terms of dynamic variables.

In conclusion, equations of motion define how a physical system behaves in terms of how its motion changes over time.

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The velocity of the car 1 can be seen from the calculation as 20 m/s West

A coordinate system or point of view used to observe motion is known as a frame of reference. It can be used as a guide when describing an object's position, speed, and acceleration. Different frames of reference may result in various motion observations.

The relative velocity is the velocity of an object or observer as observed from a particular frame of reference.

We can see that the velocity of the car 1 is;

45 m/s - 25 m/s

= 20 m/s West

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The reason why photons take about 170,000 years to reach the surface of the Sun while neutrinos take only approximately three minutes for the same trip lies in the interaction of these particles with matter.

Photons are electromagnetic radiation and they interact strongly with the charged particles present in the dense plasma of the Sun's core. These interactions cause frequent scattering and absorption, resulting in a random walk-like path for the photons. As a result, they experience numerous collisions and absorptions, which significantly slows down their journey to the Sun's surface. The process is often referred to as "radiative diffusion."

On the other hand, neutrinos are electrically neutral particles that interact only very weakly with matter. This weak interaction allows neutrinos to pass through the dense plasma of the Sun's core almost unimpeded. Neutrinos can traverse matter, including the Sun, without being significantly absorbed or scattered, making their journey from the core to the surface much faster than photons.

The differing interaction strengths of photons and neutrinos with matter explain why photons take much longer to reach the Sun's surface compared to neutrinos. This phenomenon highlights the unique properties and behavior of these fundamental particles in the realm of astrophysics and particle physics.

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The force actually being used to push the mower along the ground is 191 N.

When the physics student exerts a force of 250 N along the handle of the push mower, it's important to consider the components of this force that contribute to the actual force used to push the mower along the ground.

To determine the force used to push the mower along the ground, we need to find the horizontal component of the applied force. The angle of 40° indicates that the applied force can be broken down into two components: the horizontal component and the vertical component. The vertical component of the force is perpendicular to the direction of motion and does not contribute to pushing the mower forward.

To find the horizontal component, we can use trigonometry. The horizontal component is given by the formula:

Horizontal component = Applied force * cos(angle)

Plugging in the values, we get:

Horizontal component = 250 N * cos(40°)

Calculating this value, we find that the horizontal component of the applied force is approximately 191 N.

Therefore, the force actually being used to push the mower along the ground is 191 N. This is the component of the applied force that contributes to the forward motion of the mower, while the remaining vertical component is directed perpendicular to the ground and does not assist in pushing the mower forward.

By exerting a force of 250 N along the handle at a 40° angle, the student effectively applies 191 N of force to push the mower along the ground, ensuring efficient use of their effort while considering the environmental impact.

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For a star with 4 times the sun's mass is about 100 times more luminous than the sun the main sequence lifetime is 25 times shorter than the Sun's.

The sequence lifetime of a star refers to the lifespan of a star celestial body which can be estimated by analyzing the amount of light and mass, in this case, it is equal to 100 / 4 = 25 times shorter than the Sun's.

Therefore, with this data, we can see that the sequence lifetime of a star depends on its light and mass.

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The magnitude of the displacement vector refers to the length or amount of the displacement vector. Displacement is the change in position of an object. Displacement is a vector quantity, which means it has both magnitude and direction. In this question, a figure skater is gliding along a circular path of radius 3.93 m.

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At sunset, the Moon will be in the western horizon and its believers will point their arms towards the west.

During the first quarter, its believers will point their arms towards the southwest.

During the full moon, its believers will point their arms towards the east.

During the third quarter phase, its believers will point their arms towards the northwest.

During the new moon phase, the Moon is located between the Sun and the Earth, so it rises and sets at approximately the same time as the Sun. Therefore, at sunset, the Moon will be in the western horizon and its believers will point their arms towards the west.

During the first quarter phase, the Moon is located at a right angle to the Earth and the Sun. It rises at around noon and sets at around midnight. Therefore, at sunset, the Moon will be located in the southern horizon, and its believers will point their arms towards the southwest.

During the full moon phase, the Moon is on the opposite side of the Earth from the Sun, so it rises as the Sun sets and sets as the Sun rises. Therefore, at sunset, the Moon will be located in the eastern horizon, and its believers will point their arms towards the east.

During the third quarter phase, the Moon is also located at a right angle to the Earth and the Sun, but on the opposite side of the first quarter. It rises at around midnight and sets at around noon. Therefore, at sunset, the Moon will be located in the northern horizon, and its believers will point their arms towards the northwest.

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For an ideal mixture of two or more substances, the mixing entropy can be derived based on the same principles as for ideal gases. The reason is that ideal mixtures also have particles that are in constant random motion, and the entropy of mixing is still related to the number of possible ways the particles can be arranged.

In an ideal mixture, the assumption is that the molecules of different substances are the same size and shape, and have the same intermolecular forces with each other as they do with their own kind. This means that there are no attractive or repulsive forces between particles of different types, which simplifies the calculation of the entropy of mixing.

The mixing entropy of an ideal mixture is determined by the number of possible ways the molecules of the two substances can be distributed among the available volume. Just as in the case of ideal gases, this leads to an increase in entropy when the two substances are mixed, as there are more ways to distribute the molecules than when they are separated.

Therefore, the concept of an ideal mixture allows us to apply the same principles of thermodynamics to denser systems as we do for ideal gases, which makes it a useful tool for studying a wide range of physical and chemical processes involving mixtures.

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The mixing entropy formula applies to ideal mixtures because there are no intermolecular forces between different species, there are no volume changes upon mixing, and the mixing is completely random.

An ideal mixture is a hypothetical mixture of gases, liquids or solids where the components are assumed to behave as an ideal gas, and where the two types of molecules are the same size and interact with each other in the same way as molecules of the same type (same forces, etc.). In an ideal mixture, the mixing entropy formula applies due to the following reasons:

Therefore, the mixing entropy formula applies to ideal mixtures because there are no intermolecular forces between different species, there are no volume changes upon mixing, and the mixing is completely random.

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According to the question: the net force on the roof is 8.45 kN.

The vector sum of the forces operating on a particle of object is known as the net force in mechanics. The original forces' impact on the motion of the particle is replaced by the net force, which is a single force. In accordance with Newton's second rule of motion, it causes the particle to accelerate at a rate equal to the sum of all those actual forces.

The net force on the roof is equal to the air pressure multiplied by the surface area of the roof. The air pressure is equal to the density of the air multiplied by the wind speed squared. Therefore, the net force on the roof can be calculated as follows:
Force = (density x wind speed²) x surface area
Force = (1.29 kg/m² x (40 m/s)²) x (250 cm²)
Force = 8.45 kN
Therefore, the net force on the roof is 8.45 kN.

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Answer:

66 m/s

Explanation:

Since momentum of the body is conserved

mv=mv

0.25 kg×66m/s=0.25 kg×v

v =0.25kg×66m/s

0.25 kg

v =66m/s

Answer:

Option c.

Explanation:

Inverse of a statement is defined as the statement in which both hypothesis and conclusion are in negative form.

In the given sentence, "If today is Tuesday, then I have Geometry class", hypothesis is "If today is Tuesday" and the conclusion is "I have Geometry class.".

Inverse of the given statement is :

If today is not Tuesday, then I do not have Geometry class.

Answer:

The product of (wavelength) x (frequency) is always the same number ... the wave's speed.  

So if the wavelength is somehow reduced to  1/4  its original length, the frequency is immediately multiplied by 4 .  That's the only way their product can remain the same.

Explanation:

Answer:

Astrophysicists study the physics of the universe. “Astrophysics” is a term that is often used interchangeably with “astronomy.” Atomic, molecular, and optical physicists study atoms, simple molecules, electrons, and light, as well as the interactions among them

Explanation:

Answer:

To solve the problem, we use the equations of equilibrium to find the tension in each cable holding up the loudspeaker. Since the loudspeaker is in equilibrium, the sum of the forces acting on it is zero. The weight of the loudspeaker is calculated first, and then we use trigonometry to find the horizontal and vertical components of the tension in one of the cables. We then apply the equation of equilibrium in the y direction to find the tension in each cable. The final answer is that the tension in each cable is approximately 81.1 N, which balances the weight of the loudspeaker.

___

Given:

Mass of loudspeaker (m) = 15.0 kg

Distance from ceiling (h) = 1.00 m

Length of cable (l) = 2.70 m

Acceleration due to gravity (g) = 9.80 m/s^2

Weight of loudspeaker:

Fg = mg

Fg = (15.0 kg)(9.80 m/s^2)

Fg = 147 N

Horizontal and vertical components of tension in one cable:

sinθ = h/l

sinθ = 1.00 m / 2.70 m

θ = sin^(-1)(1.00/2.70)

θ ≈ 21.6°

T_x = T sinθ

T_y = T cosθ

where T is the tension in the cable.

Equation of equilibrium in y direction:

ΣF_y = 2T cosθ - Fg = 0

Solving for T:

2T cosθ = Fg

T = Fg / (2 cosθ)

Plugging in the values:

T = (147 N) / (2 cos(21.6°))

T ≈ 81.1 N

Answer:

Like a personal trainer? Personal trainers don't do a lot of physical activity, they mostly warm up their clients and tell them what kind of workouts to do. But their are also coaches, and they don't do much either. So you're not benefiting much out of that.  

Explanation:

The magnitude of the linear acceleration is zero for all points on the chain. The angular accelerations of the two sprockets can be related as  α\(_{Front}\) / α\(_{Rear}\) = ω\(_{Front}\) * t\(_{Rear}\) / ω\(_{Rear}\) * t\(_{Front}\)

There are two set of point that is needed to be taken into consideration. The points in between the two sprockets and points in which the chain is in contact with the sprocket. In the former set of points, the linear velocity is constant. So its linear acceleration will be zero. In the latter set of points, the tangential velocity ( Linear velocity in circular motion ) is constant. So the tangential acceleration ( Linear acceleration in circular motion ) will be zero.

Since the chain is constantly changing direction while on the sprocket, it will always have angular acceleration.

α = ω / t

α = Angular acceleration

ω = Angular velocity

t = Time

α\(_{Front}\) / α\(_{Rear}\) = ω\(_{Front}\) * t\(_{Rear}\) / ω\(_{Rear}\) * t\(_{Front}\)

Therefore,

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The minimum deceleration required to stop the car in 35 meters is 40000 m/s^2.

Deceleration is defined as  the decrease in speed as the body moves away from the starting point.

The minimum deceleration required can be calculated using the equation of motion:

d = v^2 / (2 * a)

where d is the distance, v is the initial velocity, and a is the acceleration.

Rearranging the equation to solve for a:

a = v^2 / (2 * d) = (3500 m/s)^2 / (2 * 35 m) = 40000 m/s^2

In conclusion, , the minimum deceleration required to stop the car in 35 meters is 40000 m/s^2.

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Answer:

4.167m/sec

Explanation:

1km=1000m

1.5km=1500m

1min=60sec

6min=360sec

In 360sec they travel 1500m

In 1 sec they travel=1500m/360

1sec=4.167m