Answer:
The value of the potential energy of the particle at point B is 85 joules.
Explanation:
According to the Principle of Energy Conservation, the energy cannot be created nor destroyed, only transformed. The particle at point A has kinetic and potential energy and receives a work due to an external conservative force (Work-Energy Theorem), whose sum is equal to potential energy at point B. Mathematically speaking, the expression that describes the phenomenon is:
\(K_{A} + U_{A} + W_{A \rightarrow B} = U_{B}\)
Where:
\(K_{A}\) - Kinetic energy at point A, measured in joules.
\(U_{A}\) - Potential energy at point A, measured in joules.
\(W_{A \rightarrow B}\) - Work due to conservative force from A to B, measured in joules.
\(U_{B}\) - Potential energy at point B, measured in joules.
The initial kinetic energy of the particle is:
\(K_{A} = \frac{1}{2}\cdot m \cdot v^{2}\)
Where:
\(m\) - Mass, measured in kilograms.
\(v\) - Velocity, measured in meters per second.
If \(m = 0.4\,kg\) and \(v = 10\,\frac{m}{s}\), then:
\(K_{A} = \frac{1}{2}\cdot (0.4\,kg)\cdot \left(10\,\frac{m}{s} \right)^{2}\)
\(K_{A} = 20\,J\)
Finally, the value of the potential energy at point B is:
\(U_{B} = 20\,J + 40\,J + 25\,J\)
\(U_{B} = 85\,J\)
The value of the potential energy of the particle at point B is 85 joules.
The potential energy of the particle at point B is 85 J.
Given to us:
Mass of the particle, \(m=0.40\ kg\)
velocity of the particle, \(v= 10\ m/s\)
potential energy of the particle, \(PE= 40\ J\)
Workdone from pt. A to B, \(WD_{(A\rightarrow B)} = 25\ J\)
Calculating the kinetic energy of the particle,
\(\begin{aligned}KE&= \frac{1}{2}mv^2 \\\\&=\frac{1}{2}\times0.40\times (10)^2\\\\&=20 J\\\end{aligned}\)
According to the Principle of Energy Conservation,
The energy cannot be created nor be destroyed, it can only be transformed from one form to another.Therefore,
Also,
Total Energy at point A ,
\(\begin{aligned}(TE)_A &= Kinetic\ Energy+ Potential\ Energy+ Internal Energy+ Workdone\\ &=KE_A+ PE_A+UE_A+ WD_{(0\rightarrow A)}\\&=20+40+0+0\\&=60\ J\end{aligned}\)
Total Energy at point B,
\(\begin{aligned}(TE)_B &= Kinetic\ Energy+ Potential\ Energy+ Internal Energy+ Workdone\\ &=KE_B+ PE_B+UE_B+ WD_{(A\rightarrow B)}\end{aligned}\)
As the total energy is conserved from point A to B and also an external work is done on the particle. we can write the above equation as,
\(\begin{aligned} TE_B&=KE_B+ PE_B+UE_B+ WD_{(A\rightarrow B)}\\&=(KE_B+ PE_B+UE_B)+ WD_{(A\rightarrow B)}\\&= TE_A+ WD_{(A\rightarrow B)}\\&=60+25\\&=85\ J\end{aligned}\)
Therefore, the total energy for the particle at point B is 85 J but as the particle is not moving neither work is done at point B, the total energy of the particle is the potential energy of the particle.
Hence, the potential energy of the particle at point B is 85 J.
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PLEASEEEE
Calculate the mechanical advantage of a ramp if the box you are trying to move has a mass of 10 kilograms, the
board is 15 feet long and the height of the ramp is 5 feet.
Answer:
add answer +5 so so so so so
Answer:
3 trust me
Explanation:
Please help me with the highlighted part! I dont know the answer.
Diamond, graphite and fullerenes (substances that include nanotubes and 'buckyballs' , such as buckminsterfullerene) are three allotropes of pure carbon. In all three allotropes, the carbon atoms are joined by strong covalent bonds, but in such different arrangements that the properties of the allotropes are very different.
Because of their distinctive structural makeup, graphite and diamond are distinct materials. Both have extremely high melting points due to their giant covalent structures. Diamond is incredibly strong and hard due to the four covalent links that each carbon atom in the mineral has with other carbon atoms. However, because each carbon in graphite is connected to three other carbons, it forms in layers.
Even though graphite is used to make pencils, despite the fact that each carbon atom only has three bonds, the layers are actually highly strong and have delocalized "free" electrons between them. Graphite appears soft because these electrons act as a lubricant between layers, allowing them to slide over one another. Graphite conducts electricity due to the free electrons. Diamond does not carry electricity because it lacks these free electrons.
There are more than three allotropes of carbon. These include diamond, graphite, graphene, carbon nanotubes, fullerenes, and carbon nanobuds.
Diamond
In a three-dimensional array, four additional carbon atoms are covalently attached to each carbon atom in a diamond. In essence, a diamond is one enormous molecule.
Graphite
The carbon atoms in graphite are bonded together in sheets of connected hexagons that resemble chicken wire. In essence, each sheet is a single molecule.
Each carbon atom in a sheet establishes solid covalent bonds with three other carbon atoms. The only forces keeping the sheets packed together are the modest intramolecular forces.
Graphene
In the form of a single sheet of graphite that is only one atom thick, graphene is made up entirely of carbon.
Nanocarbon tubes
Graphene sheet wrapped into a cylindrical tube of carbon atoms is how a carbon nanotube looks. Each atom connected to three other atoms, and the tube is one atom thick.
C60 and buckminsterfullerene
A single sheet of carbon atoms that has been folded into a spherical is what makes up buckminsterfullerene. Three additional atoms are connected to each carbon atom. With a carbon atom at each of the 20 hexagonal and 12 pentagonal corners, sixty carbon atoms are arranged in the shape of a ball.
There are numerous other known carbon balls, such as C70, C76, C84, and C540. They are collectively referred to as "buckyballs" or "fullerenes" and have varying amounts of pentagons and hexagons.
Nanocarbon buds
An allotrope of carbon called carbon nanobuds has fullerene-like "buds" that are covalently bonded to the sidewalls of carbon nanotubes.
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A roller coaster is at a peak of 20m and has a mass of 900kg. What is the potential energy of the roller coaster?
O 100000 J
10000 J
O 9.8 J
O 176400 J
The potential energy of the roller coaster is 176,400 J (joules).
The potential energy of an object is given by the formula PE = mgh, where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height or vertical position of the object.
In this case, the roller coaster is at a peak of 20m and has a mass of 900kg. The acceleration due to gravity, g, is approximately 9.8 \(m/s^2\).
Using the formula, we can calculate the potential energy:
PE = mgh
= (900 kg)(9.8 \(m/s^2\))(20 m)
= 176,400 J
Therefore, the potential energy of the roller coaster is 176,400 J (joules).
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A student has a displacement of 304 m north in 180 s. What was the student's average velocity?
Given : Unknown: Equation: Substitution: Solve:
Subject is Physics
Answer:
v = 1.69 m/s
Explanation:
Given that,
Displacement of the student is 304 m due North and it takes 180 s.
We need to find the student's average velocity. Using formula of velocity.
Velocity = displacement/time
\(v=\dfrac{304\ m}{180\ s}\\\\v=1.69\ m/s\)
Hence, the student's average velocity is 1.69 m/s.
The student's average velocity will be "1.69 m/s".
Displacement and Velocity:The main distinction between velocity as well as speed would be that velocity, like speed, seems to have a direction and therefore it is a vector quantity.
This same distance travelled together along a straight line throughout a particular direction from either the beginning point is defined as displacement. Because displacement has both size as well as the direction, it's a vector quantity.
Given values:
Displacement, d = 304 mTime, t = 180 sWe know,
The velocity (v):
= \(\frac{Displacement}{Time}\)
By substituting the values, we get
= \(\frac{304}{180}\)
= \(1.69 \ m/s\)
Thus the answer above is correct.
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Calculate the gravitational potential energy of an object with 100 kg as mass, colocated to 40 m of height. (g = 10 m/s^2)
Hello!!
For calculate the GPE let's applicate the formula:
\(\boxed{GPE = m g h}\)
\(\textbf{Being:}\)
\(\sqrt{}\) GPE = Gravitational potential energy = ?
\(\sqrt{}\) m = Mass = 100 kg
\(\sqrt{}\) g = Gravity = 10 m/s²
\(\sqrt{}\) h = Height = 40 m
⇒ \(\text{Then let's \textbf{replace it according} we information:}\)
\(GPE = 100 \ kg * 10 \ m / s ^{2} * 40 \ m\)
⇒ \(\text{Let's resolve it: }\)
\(GPE = 40000 \ J\)
\(\textbf{Result:}\\\text{The gravitational potential energy is \textbf{40 000 Joules}}\)
Answer:
What ever, thanks for the points
Explanation:
It’s an assessment Jane multiplied 825x22 and got 3,300. Flynn multiples the same numbers and got 18,150 Which student is correct?
In order to determine which student is correct, multiply the given numbers, as follow:
8 2 5
x 2 2
1 6 5 0
1 6 5 0
1 8 1 5 0
As you can notice, the result of the multiplcation is 18,150, hence, Flynn is right.
Focus question: Does Newton's 1st law of motion apply to the importance of wearing a seat belt?
Choose the answer choice that provides the best claim to the focus question.
Yes.
No.
No, Newton's 1st law of motion does not apply to the importance of wearing a seat belt.
Yes, Newton's 1st law of motion applies to the importance of wearing a seat belt
no is the correct answer
Explanation:
A boy fired a 40.0g rock with his slingshot. The rock is in contact with the elastic band for 0.5s and its speed as it leaves the weapon is 60.0m/s. Find the average force exerted by the band on the rock
Answer: 4.8N
Explanation: Using Force (N) = Mass (Kg) * Acceleration (m/s2)
We know the Mass, but its in grams. convert it into kg.
40g / 1000 = 0.04 KG
Then we need to find the acceleration. We can find it by the given values
acceleration = Delta S / Delta T. Or Change in speed / Change in time
So, 60m\s / 0.5s = 120m\s2
now we can use f=ma
X= 0.04 * 120
X= 4.8N
Great Company manufactures and sells a product whose peak sales occur in the third quarter. Management is now preparing detailed budgets for 20x4- the coming year and has assembled the following information to assist in the budget preparation: The company’s product selling price is Br. 20 per unit. The marketing department has estimated sales in units as follows for the next six quarters.
Answer:
Explanation:
Quarter 1 - 10,000 units
Quarter 2 - 12,000 units
Quarter 3 - 16,000 units
Quarter 4 - 14,000 units
Quarter 5 - 10,000 units
Quarter 6 - 8,000 units
Based on this information, the total estimated sales revenue for the next six quarters is Br. 480,000.
Calculate the displacement in meters of a motorcycle that has a speed of 100 kilometers per hour if it has circulated for 50 minutes
Hello..!
To calculate its displacement, we first apply the data to the problem.
Data:
V = 100km/hT = 50minD = ?Now, we apply a conversion.
Conversion:
100km/h • (1000m/1km) • (1h/3600s) V = 27.7m/s50min • (60s / 1min) T = 3000sThen, we apply the formula that is.
Formula:
D = V • TFinally we develop the problem.
Developing:
D = (27.7m/s) • (3000s)D = 83100mThe displacement of the bike is 83100 meters.
Answer:
83,333.33 m (2 d.p.)
Explanation:
\(\boxed{\sf Speed=\dfrac{Distance}{Time}}\)
Given values:
Speed = 100 k/hTime = 50 minutesAs there are 60 minutes in one hour, convert minutes into hours by dividing by 60:
\(\implies \sf Time=\dfrac{50}{60}=\dfrac{5}{6}\;hour\)
Substitute the values into the formula and solve for distance:
\(\implies \sf 100=\dfrac{Distance}{\frac{5}{6}}\)
\(\implies \sf 100=Distance \times \dfrac{6}{5}\)
\(\implies \sf Distance=\dfrac{100 \times 5}{6}\)
\(\implies \sf Distance=\dfrac{250}{3}\;km\)
\(\implies \sf Distance=83.33333...\;km\)
At there are 1000 meters in one kilometer, convert kilometers into meters by multiplying by 1000:
\(\implies \sf Distance=83.33333...\times 1000=83333.33\;m\;(2\;d.p.)\)
Which set of changes is most likely to cause the current in an electrical circuit
to stay the same?
A. Decreasing voltage and keeping resistance constant
B. Increasing voltage and increasing resistance
C. Increasing voltage and keeping resistance constant
D. Keeping voltage constant and increasing resistance
Answer:
D: keeping voltage constant and increasing resistance.
Explanation:
The current in an electrical circuit is determined by Ohm's law, which states that the current is directly proportional to the voltage and inversely proportional to the resistance.
Mathematically, Ohm's law can be expressed as:
I = V/R
where I is the current, V is the voltage, and R is the resistance.
We need to make sure that the right-hand side of the equation remains constant to keep the current in the circuit the same. Therefore, we can look at each set of changes and see how they affect the right-hand side of the equation.
A. Decreasing voltage and keeping resistance constant:
If we decrease the voltage (V) and keep the resistance (R) constant, the right-hand side of the equation becomes smaller. This means that the current (I) will also decrease, so this set of changes will not cause the current to stay the same.B. Increasing voltage and increasing resistance:
If we increase both the voltage (V) and resistance (R), the right-hand side of the equation can go either way, depending on which one increases more. However, in most cases, the current (I) will increase, so this set of changes will not cause the current to stay the same.C. Increasing voltage and keeping resistance constant:
If we increase the voltage (V) and keep the resistance (R) constant, the right-hand side of the equation becomes larger. This means that the current (I) will also increase. Therefore, this set of changes will not cause the current to stay the same.D. Keeping voltage constant and increasing resistance:
If we keep the voltage (V) constant and increase the resistance (R), the right-hand side of the equation becomes smaller. This means that the current (I) will decrease. Therefore, this set of changes is most likely to cause the current in an electrical circuit to stay the same.So, the correct answer is D: keeping voltage constant and increasing resistance.
Does fg increase or decrease when one mass increases
Answer:
It increases because fg means Force of gravity so When the mass of the two objects increases with mass and increases the distance between an object
There you go!!!
A model rocket is fired straight up from the top of a 45-m-tall building. The rocket has only enough fuel to burn for 4.0 s. But while the rocket engine is burning fuel, it produces an upward acceleration of 55 m/s2. After the fuel supply is exhausted, the rocket is in free fall and just misses the edge of the building as it falls back to the ground. Ignoring air resistance, calculate (a) the height above the ground and the velocity of the rocket when its fuel runs out; (b) the maximum height of the rocket; (c) the time the rocket is in the air; and (d) the rocket's velocity the moment before it hits the ground.
Answer:
a)y = 485 m , v = 220 m / s , b) y = 2954.39 m , c) t_total = 51 s ,
d) v = 240.59 m / s
Explanation:
a) We can use vertical launch ratios for this exercise
the speed of the rocket the run out the fuel is
v = v₀ + a t
the rocket departs with initial velocity v₀ = 0
v = a t
v = 55 4
v = 220 m / s
the height at this point is
y = y₀ + v₀t + ½ a t²
y = y₀ + 1/2 a t²
y = 45 + ½ 55 4²
y = 485 m
b) the maximum height of the rocket is when its speed is zero
for this part we will use as the initial speed the speed at the end of the fuel (v₀´ = 220 m / s) and the height of y₀´ = 485 m
v² = v₀´² + 2 g (y-y₀´ )
0 = v₀´² + 2 g (y-y₀´ )
y = y₀´ + v₀´² / 2g
y = 485 + 220 2/2 9.8
y = 2954.39 m
c) the time that the rocket is in the air is the acceleration time t₁ = 4 s, plus the rise time (t₂) plus the time to reach the ground (t₃)
let's calculate the rise time
v = v₀´- g t
v = 0
t₂ = v₀´ / g
t₂ = 220 / 9.8
t₂ = 22.45 s
Now let's calculate the time it takes to get from this point (y₀´´ = 2954.39 m) to the floor
y = y₀´´ + v₀´´ t - ½ g t²
0 = y₀´´ - ½ g t²
t = √ (2 y₀´´ / g)
t = √ (2 2954.39 / 9.8)
t = 24.55 s
the total flight time is
t_total = t₁ + t₂ + t₃
t_total = 4 + 22.45 + 24.55
t_total = 51 s
d) the veloicda right now
v = vo + g t
v = 9.8 24.55
v = 240.59 m / s
Question 15 of 25
A horticulturist is planning a garden that is 1 mx 3 m. She uses a model to
plan it. Which dimensions could she use to make a scale model?
O A. 0.5 mx 1.5 m
O B. 50 cm x 100 cm
O C. 1 mx 2 m
D. 16 cm x 36 cm
SUBMIT
Answer:
0.5 m x 1.5 m
if you can help me out and tell me where does 1-14 go the words are on top thanks here is a template to use that will help the both of us THANKS GUYS :)
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Note that the above image depicts the Movement of Lithospheric Plates. See the attached image accordingly.
Movement of Lithospheric PlatesThe movement of lithospheric plates is a geologic process that occurs due to the movement of hot, molten material in the Earth's mantle. The lithosphere, which is the rigid outer layer of the Earth's surface, is broken up into several large plates that move relative to each other. These movements are driven by the convection of material in the mantle and the forces generated at plate boundaries.
There are three main types of plate boundaries: divergent, convergent, and transform. Divergent boundaries occur where plates move away from each other, creating new oceanic crust. Convergent boundaries occur where plates collide, causing subduction, volcanic activity, and mountain formation. Transform boundaries occur where plates slide past each other.
The movement of lithospheric plates is responsible for a range of geologic phenomena, including earthquakes, volcanic activity, and the formation of mountain ranges and ocean basins.
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The equipment shown below can be used to carry out which process?
The equipment shown below can be used to carry out the electrolysis process.
What do you mean by an electrolysis ?The term electrolysis is defined as a process of decomposing ionic compounds into their elements by moving a direct electric current direct the compound in a fluid form.
An example of an electrolysis process is between an impure copper anode and a pure copper cathode in a temperature-controlled, quiet solution of copper sulfate with a constant current source linking the two electrodes.
Thus, The equipment shown below can be used to carry out the electrolysis process.
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Your question is incomplete, missing image is attached below:
The equipment shown below can be used to carry out which process?
I'm not quite sure how the formula works. I thought it was
55*6*9.81 = N
Weight * acceleration * gravity = N
My answer was wrong. Could anyone help me understand this question, please?
"When landing after a spectacular somersault, a 55.0 kg gymnast decelerates by pushing straight down on the mat. Calculate the force (in N) she must exert if her deceleration is 6.00 times the acceleration of gravity."
Answer:
See the explanation below.
Explanation:
Of course yes, after my explanation you will understand very well how to analyze this type of problems.
First, we must differentiate the weight of the mass, the mass has units of kilograms or pounds, while the weight is the product of the mass by gravitational acceleration. In this way, we have the following formula for the weight of anybody.
w = m*g
where:
w = weight [N] (units of Newtons]
m = mass [kg]
g = gravity acceleration = 9.81 [m/s²]
When we have the product of these units [kg]*[m/s²], We are always going to get as a result the units of Newtons [N], The Newton is a unit of force.
Now, to solve this problem we must use Newton's second law, which tells us that the sum of forces on a body must be equal to the product of mass by acceleration.
ΣF = m*a
where:
ΣF = forces acting over the gymnast [N]
m = mass = 55 [kg]
a = desacceleration = 6*9.81 = 58.86 [m/²]
Now we have two forces acting over the gymnast the first one is his or her weight (the mass by the gravity acceleration) and the second force is the one made it by his or her legs upwards in order to be standing. Let's take as positive signs the movements and forces upwards and negative downwards
- (m*g) + Fl = m*a
where:
Fl = force made it by the legs [N]
As the deceleration is upward because it prevents the person from continuing to go down, it is taken as a positive sign.
- (55*9.81) + Fl = (55*58.86)
Fl = (55*58.86) + (55*9.81)
Fl = 3776.85 [N]
I hope you can understand :)
A punching machine is capable of delivering up to 440 kips of force. The machine was designed to punch 4in diameter circles out of 2014-T6 aluminum (E = 10.6x103 ksi, shear strength = 70 ksi). What is the maximum thickness of aluminum plate which the machine can punch through? (4 points)
Material up to 0.375 inches thick can be worked on by modern mechanical punch presses.
Explain about the modern mechanical punch?A mechanical flywheel, which stores energy to assist the machine run, is coupled to a motor in mechanical punches. Depending on the particular punch being used, these punches can create punches ranging in size from 5mm to 500mm.
Under pressure, the press moves the tool set as it is put together. Drawing is a method of metal forming in which a product is created by directing the flow of sheet metal into a hollow while applying force with a punch. Forming of sheet material into deep, recessed pieces using a plastic flow of the material processed in presses and dies.
A punching machine is a machine tool used to punch and emboss flat sheet materials in order to create form characteristics needed as mechanical elements or to increase the static stability of a sheet section.
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A kettle transfers 1000) of energy every 2 seconds. Calculate its power.
statics and strength of materials
The magnitude of the force P provided that the stress in the part AB is two times that of BC part is 0.8 kN.
What is the force P?The magnitude of the force P provided that the stress in the part AB is two times that of BC part is calculated as follows;
Take moment about the joint to determine the magnitude of the force along part BC.
120 kN x 750 mm = F x 1000 mm
F = ( 120 kN x 750 mm ) / ( 1000 mm )
F = 90 kN
Stress is given as force divided by area. The following equation can be used to determine the magnitude of force P.
Stress in AB = 2 times stress in BC
P/A₁ = 2F/A₂
where;
A₁ is the area of segment ABA₂ is the area of segment BCA₁ = πd²/4 = π(50 x 10⁻³)²/4
A₁ = 1.96 x 10⁻⁵ m²
A₂ = πd²/4 = π(75 x 10⁻³)²/4
A₂ = 4.42 x 10⁻³ m²
P/A₁ = 2F/A₂
P = (2F x A₁) / (A₂)
P = (2 x 90 kN x 1.96 x 10⁻⁵ m² ) / ( 4.42 x 10⁻³ m² )
P = (2 x 90,000 N x 1.96 x 10⁻⁵ m² ) / ( 4.42 x 10⁻³ m² )
P = 798.2 N
P = 0.798 kN
P ≈ 0.8 kN
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Mark and Nancy both take three measurements of the length of a pencil that is 15.1 cm. Mark records 15.0, 15.0, and 15.1 cm. Nancy records 15.1, 15.2, and 15.2 cm. Which of the following statements is true about Mark and Nancy's measurements?
A. Mark's measurement is more precise.
B. Nancy's measurement is more accurate.
C. Mark's measurement is more accurate.
D. Both sets of measurements are equally accurate and precise.
friction between 2 objects cause which part of the atom to jump from one object to the other
a. atoms
b. protons
c. neutrons
d. electrons
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The same amount of thermal energy was added to two equal masses of Aluminum and Iron. The specific heat of Aluminum is double the specific heat of iron. If the temperature of the Aluminum's mass changes by /\T, what is the change in the Iron's mass temperature?
Answer:
it is double the temperature change of iron
How to solve conservation of momentum
Answer:
Step 1: List the mass and velocity of the object. Step 2: Convert any values into SI units (kg, m, s). Step 3: Multiply the mass and velocity of the object together to get the momentum of the object.
The drawing shows four situations in which two very long wires are carrying the samecurrent, although the direction of the currents may be different. The point P in the drawings is equidistant from each wire. Which one (or more) of these situations gives rise to a zero net magnetic field at P?
Situation (a) results in a zero net magnetic field at point P. Option 1 is correct.
In situation (a), the two wires are carrying currents in opposite directions. At point P, the magnetic field due to one wire will be in the opposite direction of the magnetic field due to the other wire. Since the two fields are equal in magnitude and opposite in direction, they cancel each other out, resulting in a net magnetic field of zero at point P.
In situations (b), (c), and (d), the currents are either in the same direction or the wires are at different distances from point P. In these situations, the magnetic fields due to the wires do not cancel each other out at point P, resulting in a nonzero net magnetic field. Therefore, only situation (a) gives rise to a zero net magnetic field at point P. Option 1 is correct.
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Diesel fuel is used in the engine of trucks that carry dirt fruit and other cargo. Fuel is burned in engines to make the motor move. Which of these is the main energy transformation as the truck engines use the fuel?
Answer: Fuel is burned in engines to make the motor move.
( Chemical to Mechanical )
Explanation:
during combustion of the diesel ( when the fuel is burnt in the engine of the vehicle, the diesel ( chemical energy ) is transformed or converted to Mechanical energy. This mechanical energy is what the truck uses in moving. Without the combustion of the fuel the vehicle won’t move and the combustion of diesel is achieved through compression unlike that of fuel.
3. An 18.0 N force pulls a cart against a 15.0 N frictional force. The speed of the cart increases 1.0 m/s every 5.0 s. What is the cart's mass?
Answer:
The total force on the cart is:
F = F(applied) - F(friction) = (18 N) - (15 N) = 3.0 N
The acceleration of the cart is:
a = (change in velocity)/(time) = (1.0 m/s)/(5.0 s) = 0.20 m/s^2
Using F = ma, the mass of the cart is:
m = F/a = (3.0 N)/(0.20 m/s^2) = 15 kg
PLS HELP!! This question was never fully solved!
An object moving at 13 m/s has a kinetic energy of 426 J. What is the mass of the object?
1.26 kg
2.52 kg
5.04 kg
65.5 kg
To find the mass of the object, we can use the formula for kinetic energy:
Kinetic energy (KE) = (1/2) * mass * velocity^2
Given that the kinetic energy is 426 J and the velocity is 13 m/s, we can rearrange the equation to solve for the mass:
mass = (2 * KE) / (velocity^2)
Substituting the given values:
mass = (2 * 426 J) / (13 m/s)^2
mass = (2 * 426 J) / (169 m^2/s^2)
mass = 852 J / 169 m^2/s^2
mass = 5.04 kg
Therefore, the mass of the object is 5.04 kg.
51 An electrician has to make eight connections from a switchboard to several outlets. Each
connection requires 50 centimeters of wire. How many meters of wire does the electrician need?
A.4,000 m
B.400 m
C.40 m
D.4 m
Answer:
Each connection requires 50 centimeters of wire, which is equal to 0.5 meters of wire. Therefore, for eight connections, the electrician would need:
8 * 0.5 = 4 meters of wire
Therefore, the correct answer is option D, 4 m.
:
A man puts a concave mirror with a focal length of 6cm in front of him to produce an upright image which is enlarged by three times. What is the distance between his face and the mirror in centimeters? (cm)
Therefore, the distance between the man's face and the mirror is 24 cm.
What is mirror?A mirror is a smooth, polished surface that reflects light in a way that preserves much of its original quality after the reflection. When light rays hit a mirror's surface, they bounce back at an angle that is equal to the angle at which they hit the mirror. Mirrors are used for a variety of purposes, including personal grooming, scientific experiments, and optical devices such as telescopes and microscopes. There are several types of mirrors, including flat mirrors, concave mirrors, and convex mirrors, each with their own unique properties and uses.
Here,
We can use the mirror equation to solve this problem:
1/f = 1/do + 1/di
where f is the focal length of the mirror, do is the object distance (distance between the object and the mirror), and di is the image distance (distance between the mirror and the image).
Since the image is upright and enlarged by three times, di = 3do.
Substituting di = 3do and f = -6cm (since the mirror is concave), we get:
1/-6 = 1/do + 1/(3do)
Simplifying this equation, we get:
-1/6 = 4/do
Multiplying both sides by -6do, we get:
do = 24 cm
To know more about mirror,
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