A 1 kg block sliding to the right on a level, frictionless surface with a speed
of 2 m/s collides and sticks to a second 1 kg block sliding to the left. after
the collision, the blocks are motionless. what was the speed of the second
1 kg block before the collision?

gas is the answer for this question

can you make me a brainlist

Answer:

The moon is 400x smaller but it's also 400x closer so it looks the same size even though it's not

Explanation:

To solve this we must be knowing each and every concept related to moon. Therefore, the moon is able to fully block the sun from our view on earth as  it is 400 times.

Any celestial object that revolves around a planet, such as the eight main planets, dwarf planets, or minor planets, is referred to as a moon. In order to distinguish the moon from other celestial bodies that circle other bodies, the term "natural satellite" may also be used to describe the moon.

The Galilean moons orbiting Jupiter, called after astronomer as well as discoverer Galileo Galilei, were the first moons found outside of the moon of Earth. The moon is significantly smaller than the sun. The moon is able to fully block the sun from our view on earth as the moon appears the same size despite the fact that it's 400 times smaller because it is 400 times closer and hence smaller.

Therefore, the moon is able to fully block the sun from our view on earth as  it is 400 times.

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Answer:

The force of gravitational attraction is 8.454 x 10⁻⁸ N.

Explanation:

Given;

mass of the boy, m₁ = 78 kg

mass of the girl, m₂ = 65 kg

distance between the boy and the girl, r = 2 meters

The force of gravitational attraction is given as;

\(F = \frac{Gm_1m_2}{r^2}\)

where;

G is gravitational constant = 6.67 x 10⁻¹¹ Nm²/kg²

r is the distance between two masses, m₁ and m₂

\(F = \frac{Gm_1m_2}{r^2} \\\\F = \frac{(6.67 \times 10^{-11})(78 \times 65)}{2^2}\\\\F = 8.454 \times 10^{-8} \ N\)

Therefore, the force of gravitational attraction is 8.454 x 10⁻⁸ N.

A mountain 9.0 km from a person exerts a gravitational force on him equal to 2.20% of his weight. The mass of the mountain is 8,72,181.35 * \(10^{11}\).

Firstly, we know that gravitational force is 2.20% of weight. So,

Let the gravitational force = \(F_{g}\)

weight of the person = w

So, now we know that

\(F_{g}\) = 0.022 w

We know that weight = mass * g = mg, here m is the mass of person

\(F_{g}\) = 0.022 mg

Now, we also know that

\(F_{g}\) = (G m M)/r²,

where G is gravitational constraint = 6.6743 × 10-11 m³ kg-1 s-²

M = mass of the mountain

and r is the distance between person and mountain = 9km = 9000 m

So,

0.022 mg = (G m M)/r²

[0.022 * g * r²]/ G = M

[0.022 * 9.8 * (9000)²] /  6.6743 × \(10^{-11}\) = M

= [0.2156 * 27000000] /  6.6743 × \(10^{-11}\) = M

= 5821200 / 6.6743 × \(10^{-11}\) = M

= 8,72,181.35 * \(10^{11}\) = M

So, the mass of the mountain is 8,72,181.35 * \(10^{11}\).

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Answer:

Homework · Free food · Loosing and robbing pencil · Forgetting book at home · Waiting for a Play time · My first bit · Lunch sharing · Assembly lines- standing in last just ...

Explanation:

The acceleration of the block is 6.4 m/s².

To calculate the acceleration of the block, we need to consider the forces acting on it.

The applied force is 40 N, and since it is the only horizontal force in the direction of motion, it is the net force acting on the block.

The frictional force opposing the motion is 8 N.

The acceleration, we can use Newton's second law, which states that the net force acting on an object is equal to its mass multiplied by its acceleration (F = ma).

The net force is the difference between the applied force and the frictional force:

40 N - 8 N = 32 N.

Now, we can plug the values into Newton's second law:

32 N = 5 kg × a.

Solving for the acceleration (a), we get

a = 32 N / 5 kg

a = 6.4 m/s².

Therefore, the acceleration of the block is 6.4 m/s².

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The gravitational potential energy (GPE) of the nickel will increase as it falls to the ground due to the force of gravity acting on it.

When an object falls, it gains kinetic energy, which is the energy of motion. As an object falls, it gains kinetic energy at the expense of its potential energy.

The amount of GPE gained will be equal to the mass of the nickel multiplied by the acceleration due to gravity and the change in height from the worker's pocket to the ground. Specifically, the change in GPE = 0.005 kg \(* 9.8 m/s^2 * 169\)*  m. As the nickel falls it will accelerate and its kinetic energy will increase as well. The nickel will convert the potential energy into kinetic energy and also will gain velocity as it falls, reaching a terminal velocity.

When the nickel reaches the ground, all of its potential energy will have been converted into kinetic energy.

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Answer:

\( \green{ \sf \: \: 1.6 \: m {s}^{ - 2} \: \: \: is \: the \: correct \: answer}\)

Explanation:

\( \sf \: \huge{g } _{ \small{moon}} = \frac{ {\huge{g}}_{earth}}{6} \\ \\ \sf \implies \: \sf \: \huge{g } _{ \small{moon}} = \frac{ 9.8}{6} = 1.6 \: \: m {s}^{ - 2} \)

a) D2022 = $1.9975, D2023 = $2.27715, D2024 = $2.60554, D2025 = $2.98868, D2026 = $3.43243

b) Po = $13.63

c) Dividend yield = 13.85%, Capital gains yield = 74.52%, Expected total return = 88.37%. Dividend yield = 17.89%, Capital gains yield = -23.29%, Expected total return = -5.40%.

a) Dividend is the distribution of earnings to shareholders. Expected dividend for each year can be calculated as follows:

D2022 = D0 (1 + g) = $1.75 (1 + 0.14) = $1.9975

D2023 = D2022 (1 + g) = $1.9975 (1 + 0.14) = $2.27715

D2024 = D2023 (1 + g) = $2.27715 (1 + 0.14) = $2.6055415

D2025 = D2024 (1 + g) = $2.6055415 (1 + 0.14) = $2.98868161

D2026 = D2025 (1 + g) = $2.98868161 (1 + 0.14) = $3.432429195

b) The present value of dividends expected in 2022, 2023, 2024, 2025 and 2026 can be calculated using the following formula:

PVD = D / (1 + r)t

where

PVD = present value of dividends expected

D = dividend expected in a future year

t = number of years from now

r = required rate of return

PVD2022 = $1.9975 / (1 + 0.12)¹ = $1.77700934579

PVD2023 = $2.27715 / (1 + 0.12)² = $1.88843867485

PVD2024 = $2.6055415 / (1 + 0.12)³ = $1.99719364693

PVD2025 = $2.98868161 / (1 + 0.12)⁴ = $2.10928913223

PVD2026 = ($3.432429195 + ($3.432429195 * 1.05)) / (1 + 0.12)⁵ = $2.25661605368

The present value of the stock price that should exist at the end of 2026 can be calculated using the constant growth equation:

Po = D1 / (r - g)

where

Po = price of stock today

D1 = dividend expected at the end of 2026r = required rate of return

g = expected growth rate

Po = $3.60484320761

Total present value of all dividends expected plus the present value of the stock price at the end of 2026 can be calculated using the formula:

Total PV = PVD2022 + PVD2023 + PVD2024 + PVD2025 + PVD2026 + PoTotal PV = $1.77700934579 + $1.88843867485 + $1.99719364693 + $2.10928913223 + $2.25661605368 + $3.60484320761 = $13.6333900619

The value of the stock today, Po, is $13.63.

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At time t = 0, the velocity and acceleration of an object are represented by the equations a. (t) = 8 hati + 0 hatj - 0 hatk, and a. (0) = 8 hati + 0 hatj - 0 hatk.

The particle position is given as

\underset{r}{\rightarrow}(t) = 4 t2\hat{i} + 2.4 \hat{j} - 5.6 t \hat{k}

velocity is given as the derivative of position relative to time

1 (t) = dx(t)/dt

1 (t) = (d/dt) (4 t2\hat{i} + 2.4 \hat{j} - 5.6 t \hat{k})

1 (t) = (8t) \hat{i} + 0 \hat{j} - 5.6 \hat{k}

acceleration is given as the derivative of velocity relative to time

a. (t) = d1 (t)/dt

a. (t) = (d/dt) ((8t) \hat{i} + 0 \hat{j} - 5.6 \hat{k})

a. (t) = 8 \hat{i} + 0 \hat{j} - 0 \hat{k}

velocity is given as

1 (t) = (8t) \hat{i} + 0 \hat{j} - 5.6 \hat{k}

at t = 0

1 (0) = (8(0)) \hat{i} + 0 \hat{j} - 5.6 \hat{k}

1 (0) = 0\hat{i} + 0 \hat{j} - 5.6 \hat{k}

acceleration is given as

a. (t) = 8 \hat{i} + 0 \hat{j} - 0 \hat{k}

at t = 0

a. (0) = 8 \hat{i} + 0 \hat{j} - 0 \hat{k}

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Answer:

So let's first start with the base which is a rectangle remember that the formula to solve the area

Explanation:

To steadily increase the velocity of something, it requires c. constant net force.

According to Newton's second law of motion, the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. Mathematically, this is represented as F = ma, where F is the net force, m is the mass, and a is the acceleration.  When a constant net force acts on an object, it causes the object to accelerate at a constant rate. This acceleration leads to a steady increase in the object's velocity.

It is important to note that a steadily increasing force would result in an object experiencing an increasing acceleration, which would cause the velocity to increase at an increasing rate rather than steadily. On the other hand, a decreasing force would result in a decreasing acceleration, causing the velocity to increase at a slower rate or even decrease. In conclusion, to steadily increase the velocity of an object, a constant net force must be applied to it. This constant force leads to a constant acceleration, which in turn results in a steady increase in the object's velocity.

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Answer:

I think it is   To make a higher pitch, stretch the rubber band more

Explanation:

I'm not too sure. Sry if u got it wrong

Answer:

To make a higher pitch ,pluck the rubber band more

Answer:

maximum height: p(t) = Vo * t - 1/2 * g * t^2

p’(t) = v(t) = 0 = Vo - g*t. So, maximum height occurs when t = Vo / g

p(Vo / g) = Vo^2/g - 1/2 * g * (Vo/g)^2

Vo = 10 m / s. Let’s approximate g = 10 m / s^2

p(Vo / g) = 10^2 / 10 - 1/2 * 10 * (10/10)^2 = 10 - 5 = 5 meters (approximately)

Calculation of time:

v = u + gt

0 = 10√2 + (-10)t

-10√2 = -10t

2 = √2s

The goal of the lab is to investigate the relationship between density and buoyancy. The lab aims to determine how different objects or substances behave in fluids and understand the principles of density and buoyancy through experimental observations and calculations.

The goal of the lab or the question being addressed in the lab report is to investigate and understand the concepts of density and buoyancy. Density refers to the measure of how much mass is contained within a given volume, while buoyancy refers to the upward force exerted on an object submerged in a fluid, such as water or air.

The lab report aims to explore the relationship between density, mass, and volume by conducting experiments and analyzing data. It may involve measurements of different objects or substances, determining their masses and volumes, and calculating their densities. The report may also involve experiments related to buoyancy, such as determining the buoyant force on an object and investigating factors affecting buoyancy.

By conducting the lab and analyzing the obtained results, the lab report aims to provide a deeper understanding of these fundamental concepts in physics and to demonstrate the principles of density and buoyancy through practical experimentation. The report may also include discussions of the significance and applications of density and buoyancy in various fields, such as engineering, architecture, and fluid dynamics.

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Answer:

9758 how many significant figures

Answer:

false

Explanation:

most prototypes are and perfect and they are build to find our mistakes

When a magnet experiences a quench due to resistance and loss of superconductivity, the time for the current to drop to half of its initial value will be significantly reduced.

The loss of superconductivity in a magnet occurs due to resistance, which results in increased heating. This heat causes the liquid helium surrounding the magnet to boil away, leading to a loss of the superconducting state. As the superconducting state is lost, the magnet's ability to carry current efficiently decreases. Consequently, there is a rapid decline in the current flowing through the magnet. This phenomenon highlights the importance of maintaining the low-temperature environment necessary for superconductivity to prevent the loss of the superconducting state and ensure the magnet operates optimally.

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Answer:

4s

Explanation:

Using the formula of motion as follows:

V = u + at

Where;

V = final velocity (m/s)

U = initial velocity (m/s)

a = acceleration (m/s)

t = time (s)

Based on the provided information, v = 160m/s, u = 100m/s, a = 15m/s², t = ?

V = u + at

160 = 100 + 15t

160 - 100 = 15t

60 = 15t

t = 60/15

t = 4seconds.

Therefore, the time it takes for the plane to complete this increase in speed is 4s.

The directions of the magnetic field vector and the magnetic force vector can be determined using the right-hand rule. When you extend your right hand so that your thumb points in the direction of the particle's velocity vector, and your fingers curl in the direction of the magnetic field vector, the palm of your hand will indicate the direction of the magnetic force vector.

For a positively charged particle, the magnetic force vector will be perpendicular to both the velocity vector and the magnetic field vector. The velocity vector will remain unchanged in each case, as the magnetic field does not affect the speed of the particle. However, the direction of the velocity vector may be altered due to the influence of the magnetic force.

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Angular momentum is conserved in collisions due to the principle of conservation of angular momentum. This principle states that the total angular momentum of a closed system remains constant, provided no external torques are acting upon it.

In both parts i and ii, we consider closed systems where external torques are not present. In part i, we have a collision where both linear and angular momentum are conserved. This occurs in a situation like an isolated spinning object or when two objects collide elastically without any friction between them.
In part ii, linear momentum may not be conserved, possibly due to friction or other external forces acting on the objects. However, angular momentum is still conserved. This happens because, despite the change in linear momentum, the net torque acting on the system remains zero. Therefore, the total angular momentum of the system is conserved, as dictated by the principle of conservation of angular momentum.
In summary, angular momentum is conserved in both parts i and ii because the principle of conservation of angular momentum holds true, as long as no external torques are acting upon the closed system. Even when linear momentum is not conserved, the total angular momentum remains constant due to the absence of net external torques.

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Answer:

DE HECHO EL SONIDO DÍ PUEDE ATRAVESAR LAS PAREDES, PERO

CUANDO ENTRA EN LA PARED, EL SONIDO VIAJA MÁS RÁPIDO QUE EN EL

AIRE Y CUANDO SALE DEL OTRO LADO, EL SONIDO VA A UNA

VELOCIDAD ALTA, POR ESTO LSA VOCES SE ESCUCHAN AUNQUE NO

MUY CLARAS.

Explanation:

The reaction force is string pulling on the Nellie when a tether ball in a horizontal circular path over her head .

A reaction force is a force that acts in the opposite direction to an action force. i.e. Newton's third law of motion describes action and reaction forces and the law states that for every action force, there is an equal and opposite reaction force.

There are Newton's three law of motion which can be describe as ,

The first law is can be stated as, an object will not change its motion unless a external force acts on it.

The second law is describe as, the force on an object is equal to its mass times its acceleration. i.e.

F = ma

In above equation F is force , m is mass and a is acceleration on an object.

The third law can be explained as, when two objects interact, they apply forces to each other of equal magnitude and opposite direction.

Therefore , from the above discussion can be said as Nellie whirls a tether ball in a horizontal circulars path over her head. if the action force is nellie pulling on the string, the reaction force is string pulling on the Nellie.

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The efficiency of the engine is zero, since the net work done by the engine is zero.

The efficiency of the heat engine is calculated as follows;

During the isothermal expansion, the work done by the gas is calculated as;

W₁ = nRT ln(V₂/V₁)

where;

W₁ = (1 mol)(0.08206 L.atm/mol/K)(272 K) ln(29.3 L/15.7 L)

W₁ = 13.93 L.atm

1 L.atm = 101.325 J

13.93 L.atm = ?

= 13.93 x 101.325 J

= 1,411.5 J

The heat absorbed by the gas is equal to the work done, since it is isothermal process.

Q₁ = -W₁ =  -1,411.5 J

The heat lost by the gas is calculated as follows;

Q₂ = nCvΔT

Q₂ = (1 mol)(21 J/K)(105 K - 272 K)

Q₂ = -3,507 J

During the compression process, the work done on the gas is calculated as;

W₃ = -nRT ln(V₂/V₁)

W₃ = -(1 mol)(0.08206 L.atm/mol/K)(272 K) ln(29.3 L/15.7 L)

W₃ = -13.93 L.atm

W₃ =  -1,411.5 J

So the heat rejected by the gas is equal to the work done on the gas.

Q₃ = -W₃ = 1,411.5 J

The heat absorbed by the gas during constant volume is calculated as:

Q₄ = nCvΔT

Q₄ = (1 mol)(21 J/K)(272 K - 105 K)

Q₄ = 3,507J

The net work done by the engine during the cycle is calculated as;

W(net) = W₁ + W₃

W(net) =1,411.5 J - 1,411.5 J = 0

The net heat absorbed by the engine during the cycle is calculated as;

Q(in) = Q₁ + Q₄

Q(in)  = - 1,411.5 J + 3,507J

Q(in)  = 2,095.5 J

The efficiency of the engine is calculated as;

eff. = W(net)/Q(in) x 100%

eff.  = 0/2,095.5 J  x 100%

eff.  = 0%

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The vectors addition  allows finding that the answer for the addition of a series of vectors by vector and analytical methods is

Vectors are magnitudes that have modulus and direction, so the addition must be done with vector algebra.

There are graphical and analytical methods to perform the vectors addition

We decompose the vectors in the coordinate system that we see as the adjoint.

Vector A

             \(A_y\) = 60 j ^ mm

            Aₓ = 0  

Vector B

             Bₓ = -30 i ^ mm

            \(B_y\) = 0

Vector C

Module   C = 40 mm

Angle      θ = 150º

let's use trigonometry

            cos 150 = \(\frac{C_x}{C}\)

            sin 150 = \(\frac{C_y}{C}\)

            Cₓ = C cos 150

            \(C_y\) = C sin 150

            Cₓ = 40 cos 150 = -34.64 mm

            \(C_y\) = 40 without 150 = 20 mm

Vector D

 Module D = 50 mm

 Angle   θ = 240º

           cos 240 = \(\frac{D_x}{D}\)

           sin 240 = \(\frac{D_y}{D}\)

           Dₓ = D cos 240

           \(D_y\) = D sin 240

           Dₓ = 50 cos 240 = -25 mm

           \(D_y\) = 50 without 240 = -43.30 mm

We perform the sum of each component

x-axis

            Rₓ = Aₓ + Bₓ + Cₓ + Dₓ

            Rₓ = 0 -30 -34.64 -25

            Rₓ = -89.64 mm

y-axis

           \(R_y = A_y + B_y + C_y + D_y\)

          \(R_y\) = 60 + 0 + 20 -43.30

          \(R_y\) = 36.7 mm

We construct the resulting vector

For the module we use the Pythagoras' theorem

           R = \(\sqrt{R_x^2 +R_y^2}\)

           R = \(\sqrt{89.64^2 + 36.7^2}\)

           R = 96.86 mm

For the angle we use trigonometry

           tab θ’= \(\frac{R_y}{R_x}\)

           θ'= tan⁻¹ \(\frac{R_y}{R_x}\)

           θ’= tan⁻¹ \(\frac{36.7}{89.64}\)

           θ ’= 22.26º

Since the x component is negative, the angle is in the second quadrant

To measure from the positive side of the x axis

            θ = 180 - θ '

            θ = 180 -22.26

            θ = 157.26º

In conclusion using the vectors addition we can find that the answer for the sum of a series of vectors by vector and analytical methods is

      R = 96.86 mm          

       θ = 157.26º

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If work is done on an object, the object has more energy than it did before. This energy can come from increases in kinetic energy, potential energy, and/or internal energy.

The energy transferred into an object by an external force is the work done on that object. The unit of work is the joule (J). Work can be expressed as a dot product of the force and the displacement, as given below:

W = F . d

Energy is the capacity of a system to do work. There are many different forms of energy, which can be classified as kinetic, potential, or internal energy.

Kinetic energy is the energy of motion. The kinetic energy of an object of mass m and velocity v is given by the equation below:

K = (1/2)mv²

Potential energy is the energy that a system possesses because of its position in a gravitational or electric field. A body's potential energy depends on its mass, height, and position. An object has gravitational potential energy when it is in a position that can potentially fall to a lower height. A system's electric potential energy is a result of the potential difference between two points.

Internal energy is the energy that a system possesses due to the motion of its atoms and molecules. The total energy of a system is the sum of its kinetic and potential energy. The internal energy of a system is the sum of the energy associated with the motion and position of its atoms and molecules. When energy is transferred to a system by an external force, some of that energy is converted to internal energy.

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The expected phase lag of the signal passing through the first-order low-pass RC filter with a time constant of RC-5s is -63.4 degrees.

The time constant (RC) and cutoff frequency of a first-order low-pass RC filter define it. By applying the formula = -tan1(2fRC), where f is the signal's frequency, one may determine the phase angle of the filter. The filter's time constant in this instance is RC-5s, and the frequency of the signal is 1/Hz. When we enter these variables into the calculation, we get the result = -tan1(2(1/)(5)) = -tan1(10). The phase angle is roughly -63.4 degrees, according to a calculation. In relation to the input signal, this means that the filter's output will be -63.4 degrees delayed.

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earth orbits the sun once every 365.25 days. find the average angular speed of earth about the sun.

99×10−7 rad/s.