a 1.03 kg hammer moving at 1.25 m/s drive a nail 0.752 cm into a piece of lumber. what is the average resisting force this nail experiences as it is driven into the lumber
Answers
The average resisting force experienced by the nail is approximately 22.32 N.
To find the average resisting force experienced by the nail, we can use the equation for average force:
Average force = (mass × change in velocity) / time
In this case, the mass of the hammer is given as 1.03 kg and the velocity at which it is moving is 1.25 m/s. Since the hammer drives the nail into the lumber, we can assume that the time taken for the nail to be driven into the lumber is very small, so we can neglect it.
Now, we need to calculate the change in velocity of the hammer. Initially, the hammer is moving at 1.25 m/s, but after driving the nail, its velocity decreases to zero. So the change in velocity is:
Change in velocity = 0 - 1.25 = -1.25 m/s
Using these values in the formula, we have:
Average force = (1.03 kg × -1.25 m/s) / time
Since we can neglect the time, the average force simplifies to:
Average force ≈ (1.03 kg × -1.25 m/s) / 1 ≈ -1.2875 N
However, it is important to note that the negative sign only indicates the direction of the force. In this case, we are interested in the magnitude of the force, so we take the absolute value:
Average force ≈ |-1.2875 N| ≈ 1.2875 N
Therefore, the average resisting force experienced by the nail is approximately 1.2875 N or approximately 1.29 N (rounded to two decimal places).
The average resisting force experienced by the nail as it is driven into the lumber is approximately 1.29 N.
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Related Questions
THIS IS FOR AND EXAM. I NEED THIS IN A DETAILED SENTENCE I HAVE TO WRITE A SHORT ESSAY EXPLAINING THE ANSWERS.
A truck traveling down a road contains two wooden boxes in the center of the bed of the truck. One box has a mass of 25 kilograms (kg) and the second box has a mass of 100 kilograms (kg).
If the truck stopped suddenly, which box would most likely move more?
Why would one box move more than the other?
Answers
Answer:
Well I don't know a good sentence for you but it would be the first box. For the fact that the mass would be less and would have more room to move around and be less pushing onto the truck bed.
Annie has a soccer ball and a cake ball she kicks each ball with the same Force the soccer ball accelerates at 3 m per second squared and the kickball accelerates at 5 m per second squared use Newton's law to describe why the kickball has a greater acceleration
Answers
Explanation:
We can prove this by substituting with numerical values.
Say the force she kicked both balls with was 30 N. The mass of the soccer ball is 10kg and the mass of the kickball is 6kg.
Applying Newtons Second Law, F = ma
For the soccer ball:
30 = 10a
a = 30/10
a = 3
For the kickball:
30 = 6a
a = 30/6
a = 5
Hence the kickball will travel with a greater acceleration given the same force is acted upon and has a smaller mass than the soccer ball
Hope this helps, brainliest would be appreciated :)
batteries are used to power flashlights the energy stored in batteries is converted to light energy given off by flashlights what happens to the energy as it changes form? A) all of the energy is transformed into light energy. B) some of the energy transforms to thermal energy C) half of the energy is transformed to thermal energy. D) half of the energy is transformed to light energy.
Answers
Answer:
some of the energy is transformed to thermal energy
Answer:
some of the energy transforms to thermal energy
Explanation:
If a train travels 80 miles north, 60 miles east, what’s the magnitude of its total displacement? Find the solution by drawing a diagram. ____ miles.
Answers
Answer:
100 miles North East.
Explanation:
Please see attached photo for diagram.
In the attached photo, X represents the magnitude of the total displacement of the train.
Thus, we can obtain the value of X by using the pythagoras theory as illustrated below:
X² = 80² + 60²
X² = 6400 + 3600
X² = 10000
Take the square root of both side
X = √10000
X = 100 miles.
Therefore, the magnitude of the total displacement of the train is 100 miles North East.
For each of the following conditions, give an example of a (smooth) curve satisfying them or show such a curve is impossible 1. C has points of both positive and negative curvature but never zero curvature 2. C has a parametrization γ which has speed equal to 2 and curvature equal to 3 , with respect to some orientation. 3. C has a parametrization γ that has unit speed but zero acceleration
Answers
1. A curve with points of both positive and negative curvature but never zero curvature is possible. One example is the curve formed by a twisted ribbon.
2. A curve with a parametrization γ having speed equal to 2 and curvature equal to 3 is possible. One example is the helix curve.
3. A curve with a parametrization γ having unit speed but zero acceleration is not possible. Such a curve would violate fundamental principles of motion.
1. To have points of both positive and negative curvature but never zero curvature, we can consider a twisted ribbon. Imagine a ribbon that is twisted in a way that its cross-section follows a sinusoidal wave pattern along its length. This ribbon curve will exhibit regions of positive and negative curvature, depending on whether the ribbon is twisting in a clockwise or counterclockwise manner. However, it will never have zero curvature since it is always twisted.
2. For a curve to have a parametrization γ with speed equal to 2 and curvature equal to 3, we can consider a helix curve. A helix is a spiral curve that extends in three dimensions. It has a constant radius and a constant rate of rotation, resulting in a constant curvature along the curve. By appropriately adjusting the parameters of the helix, such as the pitch and radius, we can achieve a curve where the speed is 2 units and the curvature is 3 units, satisfying the given conditions.
3. A curve with a parametrization γ having unit speed but zero acceleration is not possible. According to the fundamental principles of motion, the acceleration of an object is related to its curvature. In the context of parametrized curves, the acceleration is given by the second derivative of the position vector with respect to time. If the acceleration is zero, it implies that the second derivative of the position vector is zero, which means that the curve is a straight line. However, a straight line cannot have a unit speed parametrization since its speed would be infinite. Therefore, it is not possible for a curve to have a parametrization with unit speed but zero acceleration.
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calculate the density, in g/l, of sf6 gas at 27°c and 0.500 atm pressure.
Answers
The density of the SF₆ gas at the given pressure and temperature is 2.96 g/l.
The given parameters:
temperature of the SF₆ gas, T = 27 ⁰C = 273 + 27 = 300 Kpressure of the SF₆ gas, P = 0.5 atmThe molecular mass of the SF₆ gas is calculated as follows;
M of SF₆ = 32 + (6 x 19) = 146 g/mol
The density of the SF₆ gas is calculated by applying ideal gas law as follows;
\(PV = nRT\\\\PV = \frac{m}{M} RT\\\\PM = \frac{m}{V} RT\\\\PM = \rho RT\\\\\rho = \frac{PM}{RT}\)
where;
\(\rho\) is the density of the gasR is the ideal gas constant = 0.0821 L.atm/mol.K\(\rho = \frac{0.5 \times 146}{0.0821 \times 300} \\\\\rho = 2.96 \ g/l\)
Thus, the density of the SF₆ gas at the given pressure and temperature is 2.96 g/l.
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Assume a fabrication process improves the yield from 0.92 to 0.95. find the defects per area unit for each version of the technology given a die area of 200 mm.
Answers
The fabrication process improves the yield from 0.92 to 0.95. The defects per area unit for 0.92 and 0.95 technology are 0.042 per cm² and 0.026 per cm² respectively
The yield is increased by a manufacturing procedure from 0.92 to 0.95 the defects will be;
Given Data
Suppose the area of the die is 2 cm²
The defects per unit area with a yield of 0.92 and 0.95 must be determined
Solution
Equation for yield
Yield = 1/(1+(defects × die area/2)²
The yield equation has been rearranged
Defects = 2×(1√(yield)-1)/die area
First, we find for the technology of 0.92
Defects = 2×(1√(yield)-1)/die area
Putting the value of yield and die are 0.92 and 2 cm² respectively
Defects =2× (1√(0.92-1)/2
Defects = 0.042 per cm²
Now, find for the technology of 0.95
Putting the value of yield and die which are 0.95 and 2 cm² respectively
Defects=2× (1√(0.95-1)/2
Defects=0.026 per cm²
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at what angle in degrees is the first-order maximum for 450-nm wavelength blue light falling on double slits separated by 0.0450 mm?
Answers
The angular position of the first maximum is 0.572° for 450-nm wavelength blue light falling on double slits separated by 0.0450 mm.
What is the wavelength?
A waveform signal that is carried in space or down a wire has a wavelength, which is the separation between two identical places (adjacent crests) in the consecutive cycles. This length is typically defined in wireless systems in metres (m), centimetres (cm), or millimetres (mm) (mm).
How do you calculate a wavelength?
The Greek symbol lambda (λ) is typically used to represent a wave's length. Wavelength is defined as the product of a wave train's frequency (f) and speed (v) in a medium.
It is given that the wavelenghth of the incident light is 450 nm, and that the distance between the centres of the two slits is 0.0450 mm, hence we have
d= 0.0450 × \(10^{-3}\) m
λ= 450 × \(10^{-9}\) m
Substituting the givens in equation we can find the angular position of the first order maximum m=1, where
Angle = \(sin^{-1}\) (1×λ)/d
= \(sin^{-1}\) (450×\(10^{-9}\))/(0.0450 × \(10^{-3}\))
= \(sin^{-1}\) (10.0 × \(10^{-2}\))
= 0.572°
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State four (4) Forms (abstracts) that the liberated prisoner confronts and the copy of each of those Forms (tangible, finite, concrete, identifiable by sensory perception).
Answers
The four abstract forms and their tangible copies that apply to the liberated prisoner in the myth of Plato's cave are:
1. Astonishment.
Copy: Elevation of the eyebrows and opening of the mouth.2. Anger.
Copy: Screaming.3. Happiness.
Copy: Laugh.4. Alienation:
Copy: Crying.The feelings of the liberated prisoner in the myth of Plato's cave.
Once the prisoner is released by figures that do not correspond to shadows but to tangible beings that can lift him or even pull or drag him, the first form he must experience is astonishment, identifiable by his copy, which would be the raising of the eyebrows and / or or the opening of its mouth reflecting that shape.
Next, the myth of the cave tells us that the man was forced to leave the cave, for which the experienced form must have been anger, reflected in his copy that would be possible shouts towards the people who take him out of the cave and they make you walk on rough terrain.
Later, once the liberated man accustoms his eyes and can see more defined forms such as trees, people or even the sun, his form is joy, whose copy is laughter, out of laughter if that is the case, being now aware of a whole new that I did not know.
Once the freed prisoner returns to the cave, having a different concept about the reflected shadows to which his companions are accustomed, the abstract form is alienation, followed by his copy that is crying, since he will surely be excluded by his acquaintances. , which I would be trying to help.
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What natural process is responsible for the shape of the mushroom rock?
(PLEASE HELP ME!!!!!)
Answers
Answer:
A mushroom rock, rock pedestal, or gour is a typical mushroom-shaped landform that is formed by the action of wind erosion. ... In some cases, harder rocks are arranged horizontally over a softer rock, resulting in such erosion.
Explanation:
Answer:
wind erosion
Explanation:
Which of the following statements accurately describes the atmospheric patterns that influence local weather?
A High and low pressure systems and warm and cold fronts typically move from east to west across the globe bringing temperature changes and precipitation caused by convection in the atmosphere and oceans.
B Local weather is determined by the temperature of the different layers of the atmosphere.
C As the temperature of air changes, the pressure of the air also changes. This difference causes convection of air masses, resulting in high and low pressure systems and warm and cold fronts that move across the globe.
D Air masses over warm bodies of water bring high pressure systems to coastal regions.
Answers
Answer: A
Explanation:
Well the high and lows effect the humidity the more humidity the more hot it is so the high brings higher temperatures.
High and low pressure systems and warm and cold fronts typically move from east to west across the globe bringing temperature changes and precipitation caused by convection in the atmosphere and oceans. This statement describes the atmospheric patterns that influence local weather.
What is fronts in geology ?A front is a weather system which a boundary separating two different types of air. Cold front and warm front. One type is different from other by humidity difference and temperature difference, One type of air is usually denser than the other.
Cold fronts often come with thunderstorms or other types of extreme weather. They usually move from west to east. Cold fronts move faster than warm fronts because cold air is denser, meaning there are more molecules of material in cold air than in warm air.
Warm fronts usually show up on the tail end of precipitation and fog. As they overtake cold air masses, warm fronts move slowly, usually from north to south. Because warm fronts aren't as dense or powerful as cold fronts, they bring more moderate and long-lasting weather patterns. Warm fronts are often associated with high-pressure systems, where warm air is pressed close to the ground. High-pressure systems usually indicate calm, clear weather.
Hence option A is correct
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which boundary type adds to the lithosphere? how does it do this
Answers
Divergent boundaries are the result of the upward movement of material from the mantle. This leads to sea floor spreading and the creation of new lithosphere.
1) What happens to the capacitor voltage and current functions as the power supply voltage increases? What if decreases?
2)What happens to the capacitor voltage and current functions as the resistance increases? What if decreases?
Answers
1. If the power supply voltage increases, the capacitor voltage and current will increase, and if it decreases, the capacitor voltage and current will decrease.
2. If resistance increases, capacitor charges more slowly with lower current and lower final voltage. If resistance decreases, capacitor charges more quickly with higher current and higher final voltage.
What happen when the power supply voltage increases?1. If the power supply voltage increases, the capacitor voltage will increase and the capacitor current will increase as well until the capacitor reaches its maximum voltage. At that point, the capacitor will stop charging and the current will drop to zero.
On the other hand, if the power supply voltage decreases, the capacitor voltage will decrease and the capacitor current will decrease as well until the capacitor reaches its minimum voltage. At that point, the capacitor will stop discharging and the current will drop to zero.
What happen the resistance increases or decreases?2. If the resistance increases, the capacitor voltage will increase more slowly and the capacitor current will decrease. This is because the higher resistance slows down the rate at which the capacitor charges or discharges.
On the other hand, if the resistance decreases, the capacitor voltage will increase more quickly and the capacitor current will increase as well. This is because the lower resistance allows the capacitor to charge or discharge more quickly.
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why is ruben confident that this is a reliable source
Answers
Answer:
Why is Ruben confident that this is a reliable source? The source contained advertisements of promotional products. The source focused solely on the global spread of other diseases. The information was provided by a governmental source
If an object that was held steady (0 speed) and then dropped, how many meters would it fall in one second?
Answers
Answer:
h = 4.905 m
Explanation:
In order to find the distance covered by the object in 1 second, we can use the second equation of motion:
\(h = v_i t + \frac{1}{2}gt^2\\\)
where,
h = distance covered = ?
vi = initial speed = 0 m/s
g = acceleration due to gravity = 9.81 m/s²
t = time = 1 s
Therefore,
\(h = (0\ m/s)(1\ s)+\frac{1}{2}(9.81\ m/s^2)(1\ s)^2\\\\\)
h = 4.905 m
Two towers of a radio station are 400 m apart along an east-west line. The towers act as point sources radiating at a frequency of 1. 0 x 10! Hz. Radio waves travel at a speed of 3. 0 x 10"m/s. Determine the first angle at which the radio signal strength is at a maximum for listerners who are on a line 20. 0 km north of the station
Answers
The first angle at which the radio signal strength is at a maximum for listerners is 48.6°
The difference in the distance travelled by the waves from the two towers reaching a point P on the north-south line is given by:
δ = d₁ - d₂
where d₁ and d₂ are the distances from towers A and B, respectively, as shown in the diagram.
Using simple trigonometry, we have:
d₁ = AD = OB sin θd₂ = BD = OA sin θ
Therefore,δ = d₁ - d₂= (OB sin θ) - (OA sin θ)= (OB - OA) sin θ= AB sin θ= 400 sin θ∴ δ = 400 sin θ
The condition for maximum signal strength at the point P is when the path difference is equal to one wavelength (λ).
δ = λ ⇒ 400 sin θ = λ ⇒ sin θ = λ/400
The wavelength is given by the relation
λ = c/f, where c is the speed of light and f is the frequency of the wave.
Substituting the values, we get
λ = 3.0 × 10⁸ / 1.0 × 10⁶ = 300 m∴ sin θ = λ/400 = 300/400 = 0.75
Thus, the first angle at which the radio signal strength is at a maximum for listeners who are on a line 20.0 km north of the station is:
θ = sin⁻¹ (λ/400) = sin⁻¹ (0.75) = 48.6°
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Atoms of which pair of elements will form ionic bonds in a compound?
A. Li and Al
B. C and o
C. Co and Fe
D. K and Br The answer is D
Answers
Answer:
The answer D ...............
Among the given pair of elements potassium (K) and bromine (Br) forms an ionic compound. Thus, option D is correct.
What are ionic compounds?Ionic compounds between metals and non-metals. Metals are electrons rich and they will easily lose electrons. Non-metals are electron deficient and they easily gain electrons from metals.
The positive charge gained by the metal through electron losing and negative charge of the non-metal will electrostatically attracts each other and form the ionic bond.
Potassium is an alkali metal containing one valence electrons. Bromine contains 7 valence electrons and they need one mole electrons to achieve octet. Thus, K and Br forms an ionic compound.
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Figure 4: Index Fossils, Scientists use index fossils to match rock layers. Interpret Diagrams: Label the layers to match the first area shown. Circle the fossil or fissils. What can you infer about the history of Location 4?
Answers
Answer:
kamalong with me to the butter fly and bee
Please help ASAP. A car engine with a mass of 1750 kg can exert 215 000 W. a) How long will it take the car to reach 95.0 km/h if the car is 100% efficient? b) If it actually takes the car 6.5 s to reach 95.0 km/h, what is the efficiency of the car?
Answers
✔ First step : calculate the kinetic energy that this car requires to reach 95 km/h
95/ 3,6 ≈ 26,4 m/s
Ec = ½ m x V²
With Ec in J; m in kg; and V in m/s
Ec = ½ 1750 x 26,4² Ec ≈ 610 000 J✔ Knowing that the car has a p power of 215,000 W, so :
T = E/P
T = 610 000/215 000 T ≈ 2.8 s The car takes 2.8 s to reach 95 km/h QUESTION②)N = 2,8/6,5 x 100 = 43.07
The car efficiency is 43 %If you travel 450 meters in 40 seconds, what is your average speed in meters per
second?
A)11.25
B)40
C)450
D)18000
Answers
Answer:
The answer is a 11.25m/s
4. A 2.00 kg object is accelerated uniformly from rest to 3.00 m/s while moving 1.5 m across a
level frictionless surface. Calculate the power output.
Answers
The power output of 2.00 kg object is accelerated uniformly from rest to 3.00 m/s while moving 1.5 m across a level frictionless surface is 24.09 watts.
What is power?In science, power is the time required to do work or provide energy, expressed as work done W or energy transferred divided by the time interval t - or W/t. A fixed amount of work can be done for a long time with a low-powered engine, or for a short time with a high-powered engine. The unit of power is work (or energy) per unit of time. Such as foot pounds per minute, joules (or watts) per second, and ergs per second. Force can also be expressed as the product of the force required to move an object and the object's velocity in the direction of the force. If the magnitude of the force F is measured in pounds and the velocity ν is measured in feet per minute, then the power is equal to Fν foot pounds per minute.
Given,
Mass of object (m) = 2.00 kg
Distance covered (s) = 1.5 m
Velocity of object (v) = 3.00 m/s
For calculation of acceleration:
v² = u² + 2as
3² = 0 + 2 × a × 1.5
9 = 3a
a = 2 m/s²
For calculation of time:
s = ut + ¹/₂at²
1.5 = 0 × t + ¹/₂ × 2 × t²
1.5 = t²
t = 1.22 sec.
For calculation of gravitational force:
F = mg
F = 2 × 9.8
F = 19.6 N
For calculation of work done:
W = F × s
W = 19.6 × 1.5
W = 29.4 J
For calculation of power output:
P = W/t
P = 29.4/1.22
P = 24.09 watts
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collision 1: the 4-wheeler collides with the go-cart. the final speed of the 4- wheeler is 70 m/s. find the final speed of the go-cart in this inelastic collision.
Answers
The final speed of the go-cart in this inelastic collision is 70 m/s. The result is obtained by using the concept of inelastic collision.
What is inelastic collision?The inelastic collision of two objects occur when some of the kinetic energy is lost, converted to other forms. It means that the law of conservation of kinetic energy doesn't apply.
In this case, both objects will stick together and move together with the same speed. The law of conservation of momentum applies.
m₁v₁ + m₂v₂ = m₁v₁' + m₂v₂'
Where
m₁ and m₂ is the mass of two objectsv₁ and v₂ is the initial speed of two objects before collisionv₁' and v₂' is the final speed of two objects after collisionThe 4-wheeler collides with the go-cart in inelastic collision.
Final speed of the 4-wheeler, v₁' = 70 m/sFind the final speed of the go-cart!
Note that this is an inelastic collision. In this case, the 4-wheeler and go-cart will stick together and move with the same speed.
The formula for conservation of momentum will be
m₁v₁ + m₂v₂ = m₁v₁' + m₂v₂'
m₁v₁ + m₂v₂ = (m₁ + m₂)v'
It means that
v₁' = v₂' = v'
The final speed of the go-cart is the same with the final speed of the 4-wheeler.
v₂' = v₁' = 70 m/s
Hence, the go-cart will have the final speed of 70 m/s.
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One Newton is equivalent to
A. 1 kg/s2
B. 1 kg*m/s
C. 1 kg*m/s2
D. 1 kg/s
Answers
Answer:
B
Explanation:
During most of its lifetime, a star maintains an equilibrium size in which the inward force of gravity on each atom is balanced by an outward pressure force due to the heat of the nuclear reactions in the core. But after all the hydrogen "fuel" is consumed by nuclear fusion, the pressure force drops and the star undergoes a gravitational collapse until it becomes a neutron star. In a neutron star, the electrons and protons of the atoms are squeezed together by gravity until they fuse into neutrons. Neutron stars spin very rapidly and emit intense pulses of radio and light waves, one pulse per rotation. These "pulsing stars" were discovered in the 1960s and are called pulsars.
Part A. A star with the mass (M=2.0×1030kg) and size (R=3.5×108m) of our sun rotates once every 35.0 days. After undergoing gravitational collapse, the star forms a pulsar that is observed by astronomers to emit radio pulses every 0.200 s . By treating the neutron star as a solid sphere, deduce its radius.
Part B. What is the speed of a point on the equator of the neutron star? Your answer will be somewhat too large because a star cannot be accurately modeled as a solid sphere.
Answers
The radius of star is \(97.22*10^{3} m\).
Using the angular formulas can determine the radius using both values neutron star and the the knowing star. So,
L=I*w
\(L_{1}=I_{1}*w_{1}=L_{2}=I_{2}*w_{2}\)
\(I_{1}*w_{1}=I_{2}*w_{2}\)
where,
I=Inertia of the star
w=angular velocity
\(I=\frac{2*m*r^{2}}{5}\\w=\frac{2\pi}{t}\)
Notice the angular velocity determinate by the time and the Inertia have the radius value. So,
\(\frac{2}{5}*m*r_{sn}^{2}*\frac{2\pi }{t_{1}}=\frac{2}{5}*m*r_{s}^{2}*\frac{2\pi }{t_{2}}r_{sn}^{2}*\frac{1}{t_{1}}=r_{s}^{2}*\frac{1}{t_{2}}r_{sn}^{2}=r_{s}^{2}*\frac{t_{1}}{t_{2}}\\t_{1}=0.2s\\t_{2}=30day*\frac{24hr}{1day}*\frac{60minute}{1hr}*\frac{60seg}{1minute}=2.592*10^{6}s\\r_{sn}=3.5*10^{8}m*\sqrt{\frac{0.2s}{2.592*^{6}s}}\\r_{sn}=97.22*10^{3} m\)
So the radius of the star is \(97.22*10^{3} m\).
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particles that are found in the sun's plasma
Answers
Answer:
This plasma mostly consists of electrons
show that the period of the simple harmonic motion of a mass hanging from a spring is 2p2l>g, where l denotes the amount (beyond its natural length) that the spring is stretched when the mass is at equilibrium
Answers
The time period of a simple pendulum is
\(2\pi\sqrt{ \frac{l}{g} }\)
The time period of the simple pendulum is given above where, l= natural length and g= acceleration due to gravity. Now mass M that is hanging from the spring and we also need to know the spring constant. By Hooke's law weight of the mass hanging from the spring is equal to the spring constant K times the length of the amount. (Mg=Kx). The spring is stretched beyond its natural length when the masses at equilibrium. Now we can solve for K, which equals to Mg/x. The angular frequency(ω) of simple harmonic motion is given by √k/√m. We can now substitute it so that we get squared of mg over l divided by M and these to cancel so that we remain with the square root of G Overall. Finally, we can determine the period of simple harmonic motion t by taking 2π dividing by angular frequency(ω).
So this becomes
\(t = 2\pi\sqrt{ \frac{l}{g} }\)
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Discovering outer space had been an ancient goal of humanity. The first rocket launched ever was by the
American college professor and scientist Robert Goddard who built and flew the world's first liquid propellant
rocket on March 16, 1926. Its flight, though unimpressive (it climbed only 12.5 meters), was the forerunner of
the Saturn V Moon rocket 43 years later. Answer the following question using your math and science skills.
While launching a rocket into space, the rocket thrust (force) is calculated to be 20,000 N.
OOD
a) The mass of the rocket is approximately 3,000 kg, what would be the acceleration of the launched rocket?
b) The rocket starts from rest, what would be the final speed after 5 min?
Answers
The earliest known observations of the night sky date back to ancient civilizations such as the Babylonians, Egyptians, and Chinese, who recorded the positions of stars, planets, and other celestial bodies.
Explain about goal of humanity:Discovering outer space has been a goal of humanity for centuries. Throughout history, people have looked to the stars with a sense of wonder and curiosity, trying to understand the nature of the universe. a) To calculate the acceleration of the launched rocket, you can use the formula:However, it wasn't until the 20th century that humans were able to physically explore space. With the development of rocket technology, scientists were able to launch spacecrafts beyond Earth's atmosphere, allowing for the study of celestial bodies and the exploration of the Solar System and beyond.a = F / m
where F is the force (thrust) acting on the rocket and m is the mass of the rocket.
In this case, F = 20,000 N and m = 3,000 kg
So, a = 20,000 N / 3,000 kg = 6.67 m/s²
b) To calculate the final speed of the rocket after 5 minutes, you can use the formula:
v = a * t
where v is the final speed, a is the acceleration and t is the time.
In this case, a = 6.67 m/s² and t = 5 minutes = 300 seconds.
So, v = 6.67 m/s² * 300 seconds = 2,001 m/s
It's worth noting that the acceleration and final speed calculations are assuming that the rocket thrust is constant during the entire flight, which is not the case in reality, thrust changes during different stages of the rocket's flight.To learn more about goal of humanity refer to:
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In Europe, a large circular walking track with a
diameter of 0.900 km is marked in angular distances in
radians. An American tourist who walks 3.00 mi daily
goes to the track. How many radians should he walk?
Answers
Answer: 10.67
Explanation:
First, we needed to calculate the radius and this will be:
= Diameter / 2
= 0.900km / 2
= 0.450km
Since s = 3.00miles, we need to convert it to kilometers and this will be:
1mile = 1.6km
3 miles = 3 × 1.6km = 4.8km
Radians = s/r = 4.8/0.45 = 10.67
Which situation describes the highest rate of power?
A. A weight lifter does 500 joules of work in 1.5 seconds.
B. A weight lifter does 800 joules of work in 0.5 seconds.
C. A weight lifter doch 800 joules of work in 1.5 seconds.
D. A weight lifter does 500 joules of work in 0.5 seconds.
Answers
The situation B describes the highest rate of power. The value of power in the situation A IS 1600 Watt.
What is average power?Average power is a ratio of total work done by the body to the total time. Its unit is the watt. It is also defined as the rate of total work done by the body.
Power is defined as the rate of work done. Mathematically found as;
\(\rm P = \frac{W}{t} \\\\ P=\frac{800}{0.5} \\\\ p= 1600 \ Watt\)
Hence, the situation B describes the highest rate of power. The value of power in the situation A is 1600 Watt.
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What type of cells provide humoral immunity ?
Answers
Answer:
Antibody molecules that are secreted by plasma cells mediate the humoral immune response. The antigen that binds to the receptor of the B-cell antigen signals B cells and is internalized and transformed into peptides that activate the armed helper at the same time.
Explanation:
Answer:
B cells
Explanation:
Humoral immunity or humoural immunity is the aspect of immunity that is mediated by macromolecules found in extracellular fluids such as secreted antibodies, complement proteins, and certain antimicrobial peptides. Humoral immunity is named so because it involves substances found in the humors, or body fluids. It contrasts with cell-mediated immunity. Humoral immunity is also referred to as antibody-mediated immunity.