A 1.25 x 10-4 C charge is moving5200 m/s at 37.0° to a magnetic fieldof 8.49 x 10-4 T. What is the magneticforce on the charge?

So, the final velocity of the ball when it is 2.101 above the ground is 13.99 m/s or can be rounded to 14 m/s.

Hi ! In this question, I will help you. This question will addopt the principle of final velocity in free fall. Free fall is vertical downward movement that occurs when any object dropped without initial velocity. In othee word, the object that falls is only affected by the presence of gravity and its initial high. In general, the final velocity in free fall can be expressed by this equation :

\( \boxed{\sf{\bold{v = \sqrt{2 \times g \times h}}}} \)

With the following condition :

We know that :

Note :

At this point (2.101 m above the ground), the object can still complete its movement up to exactly 0 m above the ground.

What was asked :

Step by Step

\( \sf{v = \sqrt{2 \times g \times \Delta h}} \)

\( \sf{v = \sqrt{2 \times g \times (h_1 - h_2)}} \)

\( \sf{v = \sqrt{2 \times 9.8 \times (12.09 - 2.101)}} \)

\( \sf{v = \sqrt{19.6 \times 9,989}} \)

\( \sf{v \approx \sqrt{195.78}} \)

\( \boxed{\sf{v = 13.99 \: m/s \approx 14 \: m/s}} \)

So, the final velocity of the ball when it is 2.101 above the ground is 13.99 m/s or can be rounded to 14 m/s.

Answer:

false

Explanation:

Answer:

Velocity of the two balls after collision: \(60\; \rm m \cdot s^{-1}\).

\(100\; \rm J\) of kinetic energy would be lost.

Explanation:

Because the question asked about energy, convert all units to standard units to keep the calculation simple:

The two balls stick to each other after the collision. In other words, this collision is a perfectly inelastic collision. Kinetic energy will not be conserved. The velocity of the two balls after the collision can only be found using the conservation of momentum.

Assume that the system of the two balls is isolated. Thus, the sum of the momentum of the two balls will stay the same before and after the collision.

The momentum of an object of mass \(m\) and velocity \(v\) is: \(p = m \cdot v\).

Momentum of the two balls before collision:

Based on the assumptions, the sum of the momentum of the two balls after collision should also be \(30\; \rm kg \cdot m \cdot s^{-1}\). The mass of the two balls, combined, is \(0.1\; \rm kg + 0.4\; \rm kg = 0.5\; \rm kg\). Let the velocity of the two balls after the collision \(v\; \rm m \cdot s^{-1}\). (There's only one velocity because the collision had sticked the two balls to each other.)

These two values are supposed to describe the same quantity: the sum of the momentum of the two balls after the collision. They should be equal to each other. That gives the equation about \(v\):

\(0.5\, v = 30\).

\(v = 60\).

In other words, the velocity of the two balls right after the collision should be \(60\; \rm m \cdot s^{-1}\).

The kinetic energy of an object of mass \(m\) and velocity \(v\) is \(\displaystyle \frac{1}{2}\, m \cdot v^{2}\).

Kinetic energy before the collision:

The two balls stick to each other after the collision. Therefore, consider them as a single object when calculating the sum of their kinetic energies.

Sum of the kinetic energies of the two balls right after the collision:

\(\displaystyle \frac{1}{2} \, m \cdot v^{2} = \frac{1}{2}\times 0.5\; \rm kg \times \left(60\; \rm m \cdot s^{-1}\right)^2 = 900\; \rm J\).

Therefore, \(1000\; \rm J - 900\; \rm J = 100\; \rm J\) of kinetic energy would be lost during this collision.

Answer:

128

Explanation:

Answer:

54 degrees

Explanation:

temperature would decrease because you aren’t close to other bodies with similar temperatures, you are now surrounded by air that is cooler than you. the molecules move from hot to cold always.

Temperature is a unit used to describe hotness or coldness. It can be stated in terms of any number of arbitrary scales and shows the direction in which heat energy will naturally flow, i.e., from a hotter body to a colder body (one at a lower temperature).

Temperature is not the same as the energy of a thermodynamic system; for instance, an iceberg has a significantly larger total heat energy than a match, despite the fact that a match is burning at a much higher temperature.

As opposed to extensive characteristics, like mass or volume, temperature is referred to as an intense property—one that is independent of the quantity of matter being considered—along with pressure, density, and other comparable properties.

Therefore, temperature would decrease because you aren’t close to other bodies with similar temperatures, you are now surrounded by air that is cooler than you. the molecules move from hot to cold always.

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The fired bullet will: hit the ground second.

option C is the correct answer.

The vertical velocity of an object is the velocity of the object along the y axis.

The vertical velocity of an object decreases as the moves upwards, and eventually becomes zero at the maximum height due to the influence of acceleration due to gravity.

As the object begins to descend, the vertical velocity starts to in increase and eventually becomes maximum before the object hits the ground.

The horizontal velocity of an object remains constant because it is not affected by acceleration due to gravity in the horizontal direction.

Thus, the bullet fired from a gun will travel longer distance than the bullet dropped from same height due to influence of gravity.

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Answer:

PE = 137.2931 J

Explanation:

PE = 137.2931 J

The size of the angle θ of a point object moving from point A to point B along a circular path is 2πR / L.

To understand this, consider a simple example. Suppose that a point object that moves from point A to point B along a circular path with a radius of 1 meter. The distance between points A and B is also 1 meter. Therefore, the size of the angle θ is equal to 2π × 1 / 1 = 2π radians.

In general, the size of the angle θ = ratio of the circumference of the circle to the distance between points A and B. The circumference of the circle is equal to 2πR, where R = radius of the circle. Therefore, the size of the angle θ is equal to 2πR / L.

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Complete question:

A point object moves from point A to point B along a circular path with a radius R. What is the size of the angle θ?

Explanation:

Total frictional force = 500 N

Magnitude of frictional force on 10 kg block = 500 N/3 = 166.67 N

Magnitude of frictional force on 15 kg block = 500 N/3 x 2 = 333.33 N

Direction of frictional force on 10 kg block = Left

Direction of frictional force on 15 kg block = Left

a. commutator frequently causes the loop of wire to turn

Answer:

Refer to the step-by-step Explanation.

Step-by-step Explanation:

Simplify the equation with given substitutions,

Given Equation:

\(mgh+(1/2)mv^2+(1/2)I \omega^2=(1/2)mv_{_{0}}^2+(1/2)I \omega_{_{0}}^2\)

Given Substitutions:

\(\omega=v/R\\\\ \omega_{_{0}}=v_{_{0}}/R\\\\\ I=(2/5)mR^2\)\(\hrulefill\)

Start by substituting in the appropriate values: \(mgh+(1/2)mv^2+(1/2)I \omega^2=(1/2)mv_{_{0}}^2+(1/2)I \omega_{_{0}}^2 \\\\\\\\\Longrightarrow mgh+(1/2)mv^2+(1/2)\bold{[(2/5)mR^2]} \bold{[v/R]}^2=(1/2)mv_{_{0}}^2+(1/2)\bold{[(2/5)mR^2]}\bold{[v_{_{0}}/R]}^2\)

Adjusting the equation so it easier to work with.\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2=\dfrac12mv_{_{0}}^2+\dfrac12\Big[\dfrac25mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\)

\(\hrulefill\)

Simplifying the left-hand side of the equation:

\(mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\)

Simplifying the third term.

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2}\cdot \dfrac{2}{5} \Big[mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\)

\(\\ \boxed{\left\begin{array}{ccc}\text{\Underline{Power of a Fraction Rule:}}\\\\\Big(\dfrac{a}{b}\Big)^2=\dfrac{a^2}{b^2} \end{array}\right }\)

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2 \cdot\dfrac{v^2}{R^2} \Big]\)

"R²'s" cancel, we are left with:

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5}mv^2\)

We have like terms, combine them.

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{7}{10} mv^2\)

Each term has an "m" in common, factor it out.

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)\)

Now we have the following equation:

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)=\dfrac12mv_{_{0}}^2+\dfrac12\Big[\dfrac25mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\)

\(\hrulefill\)

Simplifying the right-hand side of the equation:

\(\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac12\cdot\dfrac25\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}^2}{R^2}\Big]\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\cdot\dfrac{v_{_{0}}^2}{R^2}\Big]\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15mv_{_{0}}^2\Big\\\\\\\\\)

\(\Longrightarrow \dfrac{7}{10}mv_{_{0}}^2\)

Now we have the equation:

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)=\dfrac{7}{10}mv_{_{0}}^2\)

\(\hrulefill\)

Now solving the equation for the variable "v":

\(m(gh+\dfrac{7}{10}v^2)=\dfrac{7}{10}mv_{_{0}}^2\)

Dividing each side by "m," this will cancel the "m" variable on each side.

\(\Longrightarrow gh+\dfrac{7}{10}v^2=\dfrac{7}{10}v_{_{0}}^2\)

Subtract the term "gh" from either side of the equation.

\(\Longrightarrow \dfrac{7}{10}v^2=\dfrac{7}{10}v_{_{0}}^2-gh\)

Multiply each side of the equation by "10/7."

\(\Longrightarrow v^2=\dfrac{10}{7}\cdot\dfrac{7}{10}v_{_{0}}^2-\dfrac{10}{7}gh\\\\\\\\\Longrightarrow v^2=v_{_{0}}^2-\dfrac{10}{7}gh\)

Now squaring both sides.

\(\Longrightarrow \boxed{\boxed{v=\sqrt{v_{_{0}}^2-\dfrac{10}{7}gh}}}\)

Thus, the simplified equation above matches the simplified equation that was given.  

The correct asnwer is D. The permanent magnets cause the metal loop in the

electromagnet to turn.

In an electric motor, the permanent magnets cause the metal loop in the

electromagnet to turn. So, option (D) is correct.

An electrical device that transforms electrical energy into mechanical energy is an electric motor. The majority of electric motors work by creating force in the form of torque imparted to the motor shaft through the interplay of the magnetic field of the motor and electric current in a wire winding.

In an electric motor, their remains a permanent magnet to produce constant magnetic field. When electric current is passed through the conducting loop, it acts ling electromagnet and begins to rotate. Thus an electric motor works. Hence, option(D) is correct.

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Answer:

71m/s

Explanation:

when you convert it you get 158.822 miles per hour

The head loss doubles when the average velocity is doubled.

The vector quantity velocity (v), denoted by equation v = s/t, quantifies dislocation (or shift in position, s), over change in time (t).

Velocity is the pace and direction of the an object's movement, whereas speed is the timekeeping at which an object is travelling along a path.In other words, velocity is a vector, whereas speed is indeed a scalar value.

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Answer: The scenario violates the second law of thermodynamics.

Explanation: The second law states that heat cannot be converted into work without some loss of usable energy, and that the amount of usable energy in a closed system will always decrease over time. Therefore, the machine described in the scenario cannot exist because it would violate the second law by converting all of the heat into electricity without any loss of usable energy.

The electric potential energy stored in the capacitor is 4.70 x 10^-8 Joules.

The electric potential energy stored in a capacitor is given by the formula:

U = (1/2) * C * V^2

where U is the potential energy in Joules, C is the capacitance in Farads, and V is the voltage across the capacitor in Volts.

In this case, we are given that the capacitor stores 9.40 x 10^-10 C of charge at 50.0 V. However, we are not given the capacitance value. Therefore, we cannot calculate the potential energy directly using the above formula.

To find the capacitance value, we can use the formula:

C = Q / V

where Q is the charge stored in the capacitor and V is the voltage across the capacitor.

Substituting the given values, we get:

C = 9.40 x 10^-10 / 50.0

= 1.88 x 10^-11 F

Now we can use the formula for electric potential energy to find the energy stored in the capacitor:

U = (1/2) * 1.88 x 10^-11 * (50.0)^2

= 4.70 x 10^-8 J

Therefore, the electric potential energy stored in the capacitor is 4.70 x 10^-8 Joules.

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Answer:

velocity = 44.3m/s

Explanation:

From the law of motion.

v = u + at

v = 8.6 + (2.1 x 17)

v = 8.6 + (35.7)

v = 44.3m/s after 2.1m/s²

Answer:

Motor cortex

Both hemispheres have a motor cortex, with each side controlling muscles on the opposite side of the body (i.e, the left hemisphere controls muscles on the right side of the body).

Explanation:

Explanation:

Given that:

a→ = (i^ - 2j^ + 2k^)/3

b→ = (-4i^ - 3k^)/5

c→ = j^

Now,

| a | = √{(1/9) + (4/9) + (4/9)} = √{(1+4+4)/9} = √{(9/9)} = 1

| b | = √{(9/25) + (16/25)} = √{(9 + 16)/25} = √(25/25) = 1

| c | = 1

Now,

Let us assume that

⇛d→ = xi^ + yj^ + zk^ which makes equal angle

⇛α, β, γ with a→, b→, c→ respectively.

So, According to the statement,

⇛cos α = cos β = cos γ

⇛{(d→.a→)/(| d→ || a→ |)} = {(d→.b→)/(| d→ || c→|)} = {(d→.c→)/(| d→ || c→ |)}

⇛[{x-2y+2z}/{3√(x²+y²+z²)} = [{-4x - 3z}/{5√(x²+y²+z²)} = {y/√(x²+y²+z²)}

⇛{(x² - 2y + 2z)/3} = {(-4x - 3z)/5} = y

On Taking first and third member, we get

⇛{(x² - 2y + 2z)/3} = y

⇛{(x² - 2y + 2z)/3} = y/1

On applying cross multiplication then

⇛1(x² - 2y + 2z) = 3(y)

⇛x² - 2y + 2z = 3y

⇛x² - 2y + 2z - 3y = 0

⇛x² - 2y - 3y + 2z = 0

⇛x² - 5y + 2z = 0 --------Eqn(1)

Now,

Taking second and third member, we get

⇛ {(-4x - 3z)/5} = y

⇛ {(-4x - 3z)/5} = y/1

On applying cross multiplication then

⇛1(-4x - 3z) = 5(y)

⇛-4x - 3z = 5y

⇛-4x - 5y - 3z = 0 --------Eqn(2)

Now, solving equation (1) and equation (2) using cross multiplication method, we get

⇛{x/(-15 - 10)} = {y/(8 - 3)} = {z/(5 + 20)}

⇛(x/-25) = (y/5) = (z/25)

⇛(x/-5) = (y/1) = (z/5)

⇛(x/5) = (y/-1) = (z/-5)

⇛x = 5k

⇛y = -k

⇛z = -5k

So,

⇛d→ = 5k^ - kj^ - 5kk^

As,

⇛| d→ | = 1

⇛√(25k² + k²+ 25k²) = √(51)

⇛√(26k² + 25k²) = √(51)

⇛51k² = √(51)

⇛k² = 1

⇛k = ±1

Thus,

⇛d→ = ± (5i^ - j^ - 5k^)

Answer: So, required vector is

⇛d→ = 5i^ - j^ - 5k^

and

⇛| d→ | = √(25 + 1 + 25) = √(26 + 25) = √(51)

Please let me know if you have any other questions.

It should be noted that the vectors of magnitude √51 that makes equation angles with the three vectors will be 5i - j - 5k.

From the information given, the following can be depicted:

a = (i^ - 2j^ + 2k^)/3

b = (-4i^ - 3k^)/5

c = j^

After applying cross multiplication, the first equation will be x² - 5y + 2z = 0 and the second equation will be -4x - 5y - 3z.

Solving the equations further will be:

[x/(-15 - 10)] = [(y/(8 - 3)] = [z(5 + 20)]

= (x/-25) = (y/1) = (z/5)

= (x/5) = (y/-1) = (z/-5)

Therefore, x = 5k, y = -k, and z = -5k.

In conclusion, the required vector is 5i - j - 5k.

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equal in magnitude but opposite in direction

\($\begin{aligned} (a) &=1 m^{3} \\ V_{1} &=110 \times 10^{3} \mathrm{~Pa} \\ T_{1} &=15+273=288 \mathrm{~K} \end{aligned}$\)

\($c_{p}=1005 \frac{\mathrm{J}}{\mathrm{kg} K}$\)

\($P_{2}=1400 \times 10^{3} \mathrm{~Pa}$\)

\((i)$$P_{1} V_{1}^{1 / 3}=P_{2} V_{2}^{1 / 3}$$\)

\($\Rightarrow \quad\left(\frac{110}{1400}\right)=\left(\frac{V_{2}}{1}\right)^{\$ 1 \cdot 3} \Rightarrow V_{2}=A \cdot 85 \times 10^{4} / \ln ^{3}$\)

\($\Rightarrow \quad V_{2}=0.1413 \mathrm{~m}^{3}$\)

\($T_{2}=T_{1}\left(\frac{p_{2}}{p_{1}}\right)^{\frac{1 \cdot 3 \cdot 1}{1 \cdot 3}}=$\) \($288\left(\frac{1400}{110}\right)^{\frac{1 \cdot 3-1}{1 \cdot 3}}=518 \mathrm{~K}$\)

\((ii) $W=\frac{P_{1} v_{1}-P_{2} V_{2}}{n-1}=\frac{\left(110 \times 10^{3} \times 1\right)-\left(1400 \times 10^{3}\right)(0.1413)}{1.3-1}$\)

\($\Rightarrow W=-292.73 \mathrm{~kJ}$\)

\((iii) $\quad \Delta U=m C_{V} \Delta T$\)

\($=\frac{p_{1} V_{1}}{p_{1}}\left( R-C_{p}\right) \times\left(T_{2}-T_{1}\right)$\)

\($=\frac{110 \times 10^{3} \times 1(-287+1005)(518-288)}{287 \times 288}$\)

\($\Delta U=219.77 \mathrm{~kJ}$\)

\((iv)$$Q-W=\Delta U$$\)

\($\Rightarrow Q-(-292.73)=219.7 7$\)

\($\Rightarrow Q=-72.96 \mathrm{~kJ}$\)

\($\rightarrow$\) Heat is flowing form surrounding

(b) Since, Tempererature is contant So, change in Internal energy \($\Rightarrow \Delta U=m C_{v} \Delta T^{\circ} \Rightarrow \Delta U=0$\)

What is Internal energy ?

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Answer:

The answer is C!

Explanation:

Answer:

C- the modern atomic theory contains over 200 years of research.

Explanation:

Given,

the distance from Redd's door to the park, s=15 m

The total distance is the sum of the distance from her door to the park and the distance from the park to her door.

That is,

The displacement is defined as the shortest distance from the starting and ending point of a path. The starting and ending point of Redd's path is the door.

Therefore the total displacement is zero meters.

Therefore, distance = 30 m

and displacement = 0 m

Energy flows from the Sun to producers, then to primary consumers, secondary consumers, and potentially to tertiary consumers, forming a pyramid-shaped structure that represents the transfer of energy through different trophic levels in an ecosystem.

Energy flows in a specific order through various components of an ecosystem, starting with the Sun and progressing through producers and consumers. This flow of energy is known as the energy pyramid or trophic levels.

At the base of the energy pyramid is the Sun, which is the ultimate source of energy for most ecosystems on Earth. Sunlight provides the energy needed for photosynthesis, a process carried out by plants, algae, and some bacteria, collectively known as producers. These organisms convert solar energy into chemical energy through photosynthesis, using carbon dioxide and water to produce glucose and oxygen. This process captures and stores energy in the form of organic compounds.

The next level in the energy pyramid consists of primary consumers, also known as herbivores. These are animals that feed directly on producers, such as grazing animals or insects that consume plants. Herbivores obtain energy by consuming plant material and breaking down the organic compounds present in the plants into simpler forms, such as sugars and amino acids, through digestion.

Above the primary consumers are the secondary consumers, which are carnivores or omnivores that feed on herbivores. They obtain energy by consuming primary consumers and breaking down the organic compounds in their prey through digestion. This energy transfer continues up the trophic levels, with each level consuming the one below it.

At the top of the energy pyramid are tertiary consumers, which are typically apex predators. They are carnivores that consume other carnivores. Tertiary consumers obtain energy by consuming secondary consumers and breaking down the organic compounds in their prey.

It's important to note that energy is not efficiently transferred between trophic levels. Only a fraction of the energy consumed at each level is converted into biomass and passed on to the next level. This inefficiency is due to processes such as respiration, heat loss, and incomplete digestion.

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The general formula for the conservation of energy for both the hoop and the cylinder can be expressed as: Etotal = Ekinetic + Epotential

Energy is the capacity of a system or object to do work. It is the ability to cause change by transferring energy from one object to another. Energy can take many forms, such as kinetic energy (energy of motion), potential energy (stored energy), thermal energy (energy from heat), electrical energy (energy from the flow of electrons), chemical energy (energy stored in chemical bonds), and nuclear energy (energy stored in the nucleus of an atom).

Where Etotal is the total energy, Ekinetic is the kinetic energy and Epotential is the potential energy.

Therefore, the general formula for the conservation of energy for both the hoop and the cylinder can be expressed as:

Etotal = (1/2 mv2) + (mg * h)

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Answer:

A. 234

Explanation:

An alpha particle is a Helium atom which has a mass number of 4 and atomic number of 2. So, an alpha particle decay cause the mass number to decrease by 4 units.

So 238 - 4 = 234

The answer is A

Explanation:

v = 1300/ 4

v = 325m/s

wavelength = 325/13000

=0.025 m