Answers
ANSWER:
The image distance is 4.11 cm
The image height is 1.8 cm
STEP-BY-STEP EXPLANATION:
The image distance is found by using the mirror-thin lens equation, just like this:
\(\frac{1}{s}+\frac{1}{s^{\prime}}=\frac{1}{f}\)We solve and calculate for s':
\(\begin{gathered} \frac{1}{s^{\prime}}=\frac{1}{f}-\frac{1}{s} \\ \frac{1}{s^{\prime}}=\frac{s-f}{f\cdot s} \\ s^{\prime}=\frac{f\cdot s}{s-f} \\ \text{ replacing} \\ s=3.2 \\ f=1.8 \\ s^{\prime}=\frac{1.8\cdot3.2}{3.2-1.8} \\ s^{\prime}=4.11 \end{gathered}\)The lateral magnification of the lens is founds in terms of the object and image distances, just like this:
\(\begin{gathered} M=-\frac{s^{\prime}}{s} \\ \text{ replacing} \\ M=-\frac{-4.11}{3.2}=1.29 \end{gathered}\)The magnitude of the lateral magnification of the lens is found in terms of the objetc and image heights:
\(\begin{gathered} |M|=\frac{h^{\prime}}{h} \\ h^{\prime}=|M|\cdot h \\ \text{ replacing} \\ h^{\prime}=1.29\cdot1.4 \\ h^{\prime}=1.8 \end{gathered}\)Related Questions
of 72.0 units. If the mass of Object 1 is halved AND the mass of object 2 is tripled, then the new gravitational force will be units.
Answers
Answer:
youtg jugre contact coming call details
Approximately 20.0gm of milk at 6.0oC is added into a cup containing 270.0 gm of weak tea. The specific heat of weak tea is 3.91 x 103J kg-1 oC-1 and the final temperature of the milk - tea mixture is 85.0oC. Given the initial temperature of the weak tea is 90.0oC, what is the specific heat of milk?
Answers
Answer:
4161 J/kg·°C
Explanation:
We can use the principle of conservation of energy to solve this problem, which states that the total heat energy in a closed system is constant. The heat lost by the tea is equal to the heat gained by the milk.
Let's first calculate the heat lost by the tea:
Q(tea) = mcΔT
Q(tea) = (0.27 kg)(3910 J/kg·°C)(90.0°C - 85.0°C)
Q(tea) = 6555 J
where m is the mass of tea, c is the specific heat of tea, and ΔT is the change in temperature.
Next, let's calculate the heat gained by the milk:
Q(milk) = mcΔT
Q(milk) = (0.02 kg)(c)(85.0°C - 6.0°C)
Now we can equate the two expressions:
Q(tea) = Q(milk)
6555 J = (0.02 kg)(c)(79.0°C)
Solving for c, we get:
c = 4161 J/kg·°C
Therefore, the specific heat of milk is approximately 4161 J/kg·°C.
what is the work done on the object by the machine.
Answers
What does the atomic numbers equal? A number of protons in the atomic nucleus B number of protons and neutrons in the atomic nucleus C number of neutrons in the atomic nucleus
Answers
number of protons
explanation:the atomic number of an atom is equal to the number of protons
A 230,000 V-rms power line carries an average power PAV = 250 MW a distance
of 200 km. If the total resistance of the cables is 10 ohms, what is the resistive
power loss?
a. 1.0 MW
b. 2.5 MW
c. 5.4 MW
d. 12 MW
e. 10 kW
Answers
The power loss over the given distance in which the current is carried is 12 MW.
option D is the correct answer.
What is the current carried in the power line?
The current carried in the power line is calculated by applying Ohms law as follows;
V = IR
P = IV
I = P/V
where;
P is the average power of the lineV is the voltageI is the currentI = (250 x 10⁶) / (230,000)
I = 1,086.96 A
The power loss over the given distance in which the current is carried is calculated as;
P = I²R
where;
R is the resistance of the wireP = (1,086.96²) x 10
P = 11.8 x 10⁶ W
P ≈ 12 x 10⁶ W
P = 12 MW
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Imagine that a proton released at rest from point A moves in response to the electric field of a fixed charge distribution along a path that takes it through point B. If the potential has a value of 3500 V at A and -1500 V at B, what is the proton's speed as it passes point B
Answers
The speed of the proton is \(9.79*10^5m/s\)
Data;
potential difference (A) = 3500Vpotential difference (B) = -1500VVelocity of The ProtonThe work done to move through a potential velocity 'v' is q
The potential difference 'v' is the difference between A and B
\(V = 3500-(-1500) = 5000v\)
But the work is converted into kinetic energy of proton.
\(q_pV = \frac{1}{2}m_pV^2\\\)
Let's substitute the values and solve for the velocity
\((1.6*10^-^1^9)*(5000)=\frac{1}{2}(1.67*10^-^2^7)v^2\\v^2 = \frac{2* 1.6*10^-^1^9 * 5000}{1.67*10^-^2^7}\\ v = \sqrt{9.58*10^1^1} \\v = 9.79 * 10^5m/s\)
The speed of the proton is \(9.79*10^5m/s\)
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A long straight wire carrying a current of 3A flowing in a direction parallel to the unit vector 1 (i+j+ k) is placed in a √√3 --↑ this is the a magnetic field of (0.75i + 0.4k)T. What is the magnetic force per unit length of the wire? A. (0.69i-0.61j - 1.3k )N/m.. B. (0.39i-0.4j-2.3 k )N/m C.(0.49i-0.51j - 1.37k )N/m D. (0.59-0.71j-0.13k )N/m
Answers
The magnetic force per unit length of the wire is (C) (0.49i - 0.51j - 1.37k) N/m.
To calculate the magnetic force per unit length of the wire, we can use the formula:
F = I * (L x B),
where F is the force, I is the current, L is the length vector of the wire, and B is the magnetic field.
Given:
Current, I = 3A
Length vector, L = √√3 * (i + j + k)
Magnetic field, B = 0.75i + 0.4k
Let's calculate the cross product of L and B:
L x B = | i j k |
|√√3 √√3 √√3|
|0.75 0 0.4|
To evaluate this cross product, we calculate the determinants:
(i) component: (√√3 * 0 - √√3 * 0.4) = -0.4√√3
(j) component: (-√√3 * 0.75 - √√3 * 0) = -0.75√√3
(k) component: (√√3 * 0.75 - √√3 * 0) = 0.75√√3
Now, multiply the cross product by the current:
F = 3A * (-0.4√√3i - 0.75√√3j + 0.75√√3k)
Simplifying this expression gives:
F = (-1.2√√3i - 2.25√√3j + 2.25√√3k) N
Therefore, the magnetic force per unit length of the wire is approximately (-1.2√√3i - 2.25√√3j + 2.25√√3k) N/m.
Comparing the given answer options, the closest match is C. (0.49i - 0.51j - 1.37k) N/m.
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A boy slides down a hill on a sled (total mass of 32 kg) and coasts onto a flat plain with a speed of 5.5 m/s. Friction between the sled and the snow exerts an average force of magnitude 32 N on the sled. How far (in m) does the sled travel before stopping? (Note: First, find the acceleration of the boy using Unit Two material, then use this to compute the distance using Unit One material.)
Answers
The distance which the sled which is weighing 32 kg and has a speed of 5.5 m/s will travel before stopping is 15.1 meters.
What is Friction?
Friction is the force which resists the sliding or rolling of one solid object over the another object. Frictional forces, such as the one traction needed to walk without slipping, may be beneficial, however they also present a great measure of opposition to the motion of object.
In this problem, we are to utilize the kinematic equation in the form;
Vf² = Vi² + 2aD
where, Vi is the initial velocity, Vf is the final velocity, a is the acceleration and D is the distance traveled.
Given,
Mass of boy and sled (m) = 32 kg
Speed of boy and sled (Vi) = 5.5 m/s
Average force (F) = 32 N
Using the equation for Newton's Second Law of Motion with the friction force opposing the motion:
Fs = ma
a = Fs/ m
a = -32/ 32
a = -1m/s²
Plugging the values in the obtained acceleration into the kinematic equation, we get:
(0)² = (5.5)² + 2(-1)D
D = (5.5)²/ 2
D = 30.25/ 2
D = 15.1 meters
The distance which the sled will travel before stopping is 15.1 meters.
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A weightlifter works out at the gym each day. Part of her routine is to lie on her back and lift a 43 kg barbell straight up from chest height to full arm extension, a distance of 0.53 m .
Part A: How much work does the weightlifter do to lift the barbell one time?
Part B: If the weightlifter does 23 repetitions a day, what total energy does she expend on lifting, assuming a typical efficiency for energy use by the body?
Part C: How many 500 Calorie donuts can she eat a day to supply that energy?
Answers
Answer:
A) Workdone = 223.57 N-m
B) 22357 J of energy
C) Number of donuts = 10.7 donuts
Explanation:
A) The work done is calculated from the formula;. Work done = Force × Distance
We are given;
Mass; m = 43 kg
Distance = 0.53 m
Force(weight) = mg = 43 × 9.81
Thus;
Work done = 43 × 9.81 × 0.53
Workdone = 223.57 N-m
B) We are told she does 23 repetitions a day.
Thus, we assume 23% efficiency.
So, Work = Energy
Thus;
At 100% efficiency;
Energy = (223.57/100%) × 23 repetitions = 5142.11 J
Now, since she is only 23% efficient, she will expend; 5142.11/0.23 J = 22357 J of energy to do 5390 J of work.
C) from conversions; 4.18 J = 1 calorie
Thus;
22357 J ÷ 4.18 J/cal = 5348.565 calories
We how many 500 calorie donuts she can eat in a day to supply that energy.
Thus;
Number of donuts = 5348.565 cal ÷ 500 cal /donut
Number of donuts = 10.7 donuts
Match the role played in a group to the scenario that portrays the role.
dysfunctional role
functional role
maintenance role
Dione is a supervisor who engages her team in team-building activities. She makes
sure that every member has an equal say on different matters. She listens to her team
members' inputs and values their opinions.
Dean is quite mean to his team members. He keeps looking for flaws in others, and if
someone performs badly or makes a mistake, he is quick to pounce on them. He also
tries to pit one member against the other, creating an unhealthy working environment.
Ronald assigns tasks to his team members depending on their abilities. He is clear
about what is expected of the member based on the assigned task. He encourages the
team to be supportive of one another and boost the overall team spirit.
Donna creates opportunities for her team members to interact with one another and
function as a productive team. She encourages her team to collectively find solutions
to problems and discuss topics based on the members' personal experiences and
knowledge.
task role
Answers
The role played in the group by the different members are:
Maintenance role - Dione Dysfunctional role - Dean Task role - Ronald Functional role - Donna How are the roles played in the group ?Dione locks in her group in team-building exercises, which makes a difference reinforce their connections and advances collaboration. Dean's mean-spirited behavior, steady feedback, and endeavors to form clashes among group individuals are counterproductive.
Ronald relegates errands to his group individuals based on their capabilities, ensuring that each part contains a part that adjusts with their aptitudes. Donna makes openings for her group individuals to connected with each other and work as a beneficial group.
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what happens if we add a lump of ice to a tumbler containing water? how does heat flow?
Answers
Answer:
The ice will melt
Heat flows from the water to the ice
Explanation:
If we add a lump of ice to a tumbler containing water, the ice lump will melt in the water.
This is a simple physical change of state from solid to liquid.
At the end both the solid ice and the original liquid maintains the liquid state.
The heat will flow from the ice to the water in the tumbler. Heat generally flows from a body at higher temperature to one with a lower temperature. The water has a higher temperature when compared to the ice. So, heat flows from the liquid water to the ice until thermal equilibrium is reached.Mercury has a radial acceleration of 3.96 × 10−2 m/s2 and its orbital period is T = 88 days. What is the radius of Mercury’s orbit, assuming a circular orbit?
Answers
Answer: 58,045,522,878.8 meters
Explanation:
Ok, the data we have is
Period = T = 88 days
Radial acceleration = ar = 3.96x10^-2 m/s^2
And we know that the equation for the radial acceleration is:
ar = v^2/r = r*w^2
Where v is the velocity. r is the radius and w is the angular velocity.
And we know that:
w = 2*pi*f
where f is the frequency, and:
T = 1/f.
Then we can write:
w = 2*pi/T
and our equation becomes:
ar = r*(2*pi/T)^2
Now we solve this for r.
First we need to use the same units in both equations, so we want to write T in seconds.
T = 88 days,
A day has 24 hours, and one hour has 3600 seconds:
T = 88*24*3600 s =7,603,200s
Then:
3.96x10^-2 m/s^2 = r*(2*3.14/7,603,200s)^2
r = (3.96x10^-2 m/s^2) /(2*3.14/7,603,200s)^2 = 58,045,522,878.8 meters
Potential energy can be converted into kinetic energy, a good example of this is when a pole-vaulter bends the pole during a leap. When the pole is bent the most, does it store elastic or gravitational potential energy? Question 7 options: Only gravitational potential energy because that is more powerful than elastic potential energy. It has neither elastic or gravitational potential energy. The pole stores elastic potential energy when the pole is bent because its shape is change from its natural shape and it will want to go back to its original form, just like a spring or stretched elastic material. The pole stores gravitational potential energy because it is bent from its natural shape when off the ground.
Answers
Answer:
The pole stores elastic potential energy when the pole is bent because its shape is change from its natural shape and it will want to go back to its original form, just like a spring or stretched elastic material.
Question:
Why did you lie about being in college?
Answer:
The pole stores gravitational potential energy because it is bent from its natural shape when off the ground.
Explanation: i took the test
If u have a box with mass of 10kg and u push with a force of 200 N what is the acceleration of the box ?
Answers
Answer:
20m/s²
Explanation:
force = mass*acceleration
acceleration = force ÷ mass
acceleration = 200N ÷ 10kg
acceleration = 20m/s²
URGENT
A force of 35 N is used to stretch a spring 15 cm beyond its normal length. What is the
increase in the spring's energy?
Answers
Answer:
5.25 J
Explanation:
W = PE = (f)(x)
PE = 35N*0.15m
PE = 5.25 N*m
1 N*m = 1 J
PE = 5.25 J
If you are told an image has been made by a single optic that has a positive focal length, which is true?
Answers
If you are told an image has been made by a single optic that has a positive focal length, The options that are true are:
The image is real. (Option A)
The image is virtual. (Option B)
The image has a positive image distance. (Option C)
The image has a negative image distance. (Option D)
The image is inverted. (Option E)
The image is upright.(Option F)
The image was made with a converging optic. (Option G)
The image was made with a diverging optic. (Option H)
If the optic is a lens, it is convex. (Option I)
If the optic is a mirror, it is convex. (Option K)
What is Focal Lenght?The focal length of an optical system is the inverse of the system's optical power; it measures how strongly the system converges or diverges light.
A system with a positive focus length converges light, whereas a system with a negative focal length diverges light.
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Full Question:
If you are told an image has been made by a single optic that has a positive focal length, which is true?
a. The image is real.
b. The image is virtual.
c. The image has a positive image distance.
d. The image has a negative image distance.
e. The image is inverted.
f. The image is upright.
g. The image was made with a converging optic.
h. The image was made with a diverging optic.
i. If the optic is a lens, it is convex.
j. If the optic is a lens, it is concave.
k. If the optic is a mirror, it is convex.
l. If the optic is a mirror, it is concave.
An object is released from a rocket moving upwards at a speed of 8.9 m / s.
What is the downward acceleration of this object?
Answers
Answer:
9.81 m/s²
Explanation:
It is given that the upward speed of the object is 8.9 m/s.
An object is released.
Now, we know that if the object is released then it will move under the control of gravity which means that the initial velocity of the rocket will not affect the acceleration of the object.
Hence, the downward acceleration of the object will be equal to g i.e. 9.81 m/s².
1,000 J of energy are needed to melt 10 g of a solid substance that is already at its melting point. What is the heat of fusion of the substance?
Answers
1,000 J of energy are needed to melt 10 g of a solid substance that is already at its melting point , the heat of fusion of the substance is 548 joules .
What is heat of fusion ?Heat of fusion, also known as enthalpy of fusion or latent heat of fusion, is the amount of energy required to melt or freeze a substance under constant pressure conditions. When it comes to chemistry, "fusion" is basically synonymous with "melting." In the classroom, heat of fusion is typically used when a substance is at its melting or freezing point. In such instances, most people consider heat of fusion to be a constant.
Water, for example, has a heat of fusion of 334 J/g at its melting point of 0°C. At 0°C, one grams of liquid water requires 334 Joules of energy to completely freeze into ice. In addition, one grams of ice requires 334 Joules of energy to melt entirely.
q = m×∆Hf
q: Total change in heat energy (in Joules)
∆Hf: Heat of fusion of substance (in Joules per gram)
m: Mass of substance (in grams)
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Which part of the diagram indicates the amplitude of the wave?
Answers
The left vertical line part of the diagram indicates the amplitude of the wave.
The amplitude of a wave or vibrating body is defined as the maximum displacement or distance generated by a point on the wave or body compared to its position of equilibrium. It is the same as the length of the vibration path divided by half.
The wave's amplitude is shown by the left vertical line in the figure, which depicts the highest displacement or distance that a spot on a wave or moving body can make compared to its equilibrium position. So the left vertical line part of the diagram indicates the amplitude of the wave.
The figure of the question is attached.
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Rank the six combinations of electric charges on the basis of the electric force acting on q1.
a.
q1= +1nC
q2= -1nc
q3= -1nc
b.
q1= -1nC
q2= +1nc
q3= +1nc
c.
q1= +1nC
q2= +1nc
q3= +1nc
d.
q1= +1nC
q2= +1nc
q3= -1nc
e.
q1= -1nC
q2= -1nc
q3= -1nc
f.
q1= +1nC
q2= -1nc
q3= +1nc
Answers
Answer:
Largest; options A & B
2nd largest; Option F
3rd Largest; Option D
Smallest; Options E & C
Explanation:
Looking at the charges, basically, the net force of the charge q1 is the sum of charges q2 and q3.
When 2 charges are opposite, the force will be attractive but if they are same, then the force will be repulsive.
Thus, the order of the forces is;
I) Largest: q1= +1nC, q2= -1nc, q3= -1nc and (q1= -1nC, q2= +1nc, q3= +1nc)
II) Second largest is: q1= +1nC, q2= -1nc, q3= +1nc
III) Third largest: q1= +1nC, q2= +1nc, q3= -1nc
IV) Smallest: (q1= -1nC, q2= -1nc, q3= -1nc) and (q1= +1nC, q2= +1nc, q3= +1nc)
can anyone write for me all the equation of linear motion
Answers
All the equations of motion are as follows, Displacement (s) equation, Final velocity (v) equation, Average velocity (v_avg) equation, Displacement (s) equation with average velocity, and Displacement (s) equation.
Equations of MotionIn terms of its motion as a function of time, equations of motion define how a physical system behaves. In more detail, the equations of motion define how a physical system behaves as a collection of mathematical functions expressed in terms of dynamic variables.
s = ut + (1/2)at^2v = u + atv_avg = (u + v) / 2s = v_avg * ts = (u + v) / 2 * tv^2 = u^2 + 2asIn conclusion, equations of motion define how a physical system behaves in terms of how its motion changes over time.
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Need to fill in the blank
Answers
Neglecting drag, the cannonball's initial height, and its horizontal motion, the maximum height rise is 110.45 metres, the time it takes for the ball to rise is 4.7 seconds, and the overall flight duration is 9.4 seconds.
Equation:
A pupil propels a cannonball 47.0 metres per second vertically upward.
assuming that the acceleration brought on by gravity is 10 m/s2.
Using the equation U2 = 2gH, the cannonball's highest point will be determined.
where H is the height the cannonball reaches.
When all the figures are put together, 47*47 = 2*10*H
H = 110.45 metres.
The cannonball's ascent time would be given by t=(2H/g).
When all the values are put together, t = (2*110.45/10)t = 4.7 seconds.
The cannonball's total flight time, T, is equal to the sum of its rise and descent times.
The ratio of ascent to descent is time.
Time of ascension = 4.7 Seconds since there is no other acceleration present and it is motion under gravity.
T = 2×(time of ascent) (time of ascent)
9.4 seconds are equal to T = 2*4.7.
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Which material is a good heat conductor ?
Answers
Answer:
wood lighters gasoline hope it helps
Explanation:
03.03 LC)
The refraction of a sound wave occurs when the sound wave
stops at a boundary between media
bounces off the boundary between media
bends as it passes through the boundary between media
changes frequency after it passes through the boundary between media
Answers
The refraction of a sound wave occurs when the sound wave bends as it passes through the boundary between media. Refraction occurs when there is a difference in the speed of sound waves in two different media.
The bending of the sound wave occurs because the speed of sound changes as it passes from one medium to another. The amount of bending depends on the angle of incidence and the difference in speed between the two media. If the speed of sound is higher in the second medium than the first, then the wave bends away from the normal. If the speed of sound is lower in the second medium than the first, then the wave bends towards the normal. If the sound wave is incident perpendicular to the boundary, then there is no bending of the wave and no refraction occurs. Refraction of sound waves is an important phenomenon in our daily lives. It is the reason why we can hear sound around corners or why we can hear someone talking in another room even if the door is closed. The refraction of sound waves is also used in medical imaging, such as in ultrasound, where the sound waves are refracted as they pass through different tissues in the body.For more such questions on sound wave, click on:
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A piece of wire has a resistance of 8 ohms. What
is the resistance of a second piece of wire of the
same composition, same diameter, and at the
same temperature, but with one half the length
of the first wire?
Answers
Answer:
4 ohms
Explanation:
R = PL/A
P is resistivity
L is length and is halved
A cross sectional area, the same so
R = P(L/2)/A = 4
The resistance of the wire when the length is half will be 4 ohms. Resistance is directly propotional to the length in the given condition,
What is resistance?Resistance is a type of opposition force due to which the flow of current is reduced in the material or wire. Resistance is the enemy of the flow of current.
The given data in the problem is;
The resistance in a piece of wire is R = 8 ohms.
D₁=D₂
T₁=T₂
L₂=0.5L₁
The formulas for the resistance in the wire will be;
\(\rm R= \frac{\rho L}{A} \\\\ \rm R= \frac{\rho L}{\frac{\pi}{4D^2} }\)
If all the given values are constant the resistance is inversly propotional to the length.
If the length is half the value of the resistance is also half;
\(\rm R'=\frac{R}{2} \\\\ \rm R'=\frac{8}{2} \\\\ \rm R'=4 \ ohm\)
Hence the resistance of the wire when the length is half will be 4 ohms.
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Compare sound and earthquake waves
Answers
When materials vibrate, waves are created that travel through the substance, and this energy is what we hear as sound. Earthquakes are earth vibrations that cause the (potential) energy held within rocks to be released (as a result of their pressure-generating relative positions). Seismic waves are produced by earthquakes.
How do sound waves and earthquakes compare?
The waves lose energy as they move through the air with sound or through the ground with shaking during an earthquake. Therefore, a band can be heard louder close to the stage than farther away, and an earthquake can be felt more strongly close to the fault than farther away.
In actuality, sound in the air cannot match how quickly earthquake waves move. In rock, the compressional or "P" wave of an earthquake moves at the In actuality, sound in the air cannot match how quickly earthquake waves move. The speed of a P wave is typically 10,000 mph. The speed of sound through air is roughly 750 mph.
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A unit used to measure force is a
a. newton.
b. newton-meter.
c. joule.
d. watt.
Answers
Answer:
Newton
Explanation:
Newton's are the standard unit of force.
If a 1.5-Kg physics book measures 0.260 m x 0.210 m x 0.040 m, calculate the pressure applied by the standing book on the table. (Round off answer to two sig figs)
*
Answer choices:
P = 1,600 N/m^2
P = 1,800 N/m^2
P = 1,500 N/m^2
P = 1,700 N/m^2
Answers
The pressure applied by the standing book on the table is 1,800 N/m².
option B is the correct answer.
What is the pressure applied by the book?
The pressure applied by the standing book on the table is determined from the ratio of weight of the book and the area of the standing book.
Mathematically, the formula for the pressure of a material is given as;
P = F / A
where;
F is the applied force or weight of the object standing on another surfaceA is the area of the object in contact with another surfaceThe weight of the book , F = mg
where;
m is the mass of the bookg is acceleration due to gravityF = 1.5 kg x 9.8 m/s²
F = 14.7 N
The dimension of the book include;
height of the book, h = 0.26 mwidth of the book, w = 0.21 mthickness of the book, b = 0.04 mThe height of the book is not in contact with the surface of the table, so the area of the book in contact with the table becomes;
A = w x b
W = 0.21 m x 0.04 m
W = 8.4 X 10⁻³ m²
P = F / A
P = ( 14.7 N ) / ( 8.4 X 10⁻³ m² )
P = 1,750 N/m² ≈ 1,800 N/m²
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_____ involves relying on assumptions and beliefs about the world, whereas _____ involves making direct observations of the world.
Answers
Intuition involves relying on assumptions and beliefs about the world, whereas empirical observation involves making direct observations of the world.
Intuition refers to the process of using past experiences, beliefs, and assumptions to make quick, unconscious judgments or decisions about the world.
It is often associated with feelings or gut reactions and can be influenced by factors such as emotions, biases, and prior knowledge.
Empirical observation, on the other hand, refers to the process of gathering information about the world through direct sensory experience, such as seeing, hearing, touching, and measuring.
Empirical observations are the foundation of scientific inquiry as they provide the raw data that can be used to test and refine hypotheses and theories.
Unlike intuition, empirical observations are objective and uninfluenced by personal biases or assumptions.
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An environmentally conscious physics student 250 N
mows her lawn with a push mower, exerting
a force of 250 N along the handle as shown. 40°
How much force is actually being used to push
the mower along the grou
Answers
The force actually being used to push the mower along the ground is 191 N.
When the physics student exerts a force of 250 N along the handle of the push mower, it's important to consider the components of this force that contribute to the actual force used to push the mower along the ground.
To determine the force used to push the mower along the ground, we need to find the horizontal component of the applied force. The angle of 40° indicates that the applied force can be broken down into two components: the horizontal component and the vertical component. The vertical component of the force is perpendicular to the direction of motion and does not contribute to pushing the mower forward.
To find the horizontal component, we can use trigonometry. The horizontal component is given by the formula:
Horizontal component = Applied force * cos(angle)
Plugging in the values, we get:
Horizontal component = 250 N * cos(40°)
Calculating this value, we find that the horizontal component of the applied force is approximately 191 N.
Therefore, the force actually being used to push the mower along the ground is 191 N. This is the component of the applied force that contributes to the forward motion of the mower, while the remaining vertical component is directed perpendicular to the ground and does not assist in pushing the mower forward.
By exerting a force of 250 N along the handle at a 40° angle, the student effectively applies 191 N of force to push the mower along the ground, ensuring efficient use of their effort while considering the environmental impact.
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