A 1,407.48 N rocket travels at constant speed for 1,876.33 m in 1.04 seconds. what is the kinetic energy of the rocket?

Answer:

The final velocity of the bullet is 9 m/s.

Explanation:

We have,

Mass of a bullet is, m = 0.05 kg

Mass of wooden block is, M = 5 kg

Initial speed of bullet, v = 909 m/s

The bullet embeds itself in the block which flies off its stand. Let V is the final velocity of the bullet. The this case, momentum of the system remains conserved. So,

\(mv=(m+M)V\\\\V=\dfrac{mv}{m+M}\\\\V=\dfrac{0.05\times 909}{0.050+5}\\\\V=9\ m/s\)

So, the final velocity of the bullet is 9 m/s.

The three rules of refraction for converging lenses, also known as convex lenses, are as follows:

1. The incident ray parallel to the principal axis refracts through the lens and passes through the focal point on the opposite side of the lens.

2. The incident ray passing through the focal point refracts and emerges parallel to the principal axis.

3. The incident ray passing through the center of the lens continues undeviated.

The three rules of refraction for converging lenses, also known as convex lenses, are as follows:

1. The incident ray parallel to the principal axis refracts through the lens and passes through the focal point on the opposite side of the lens.

When a ray of light traveling parallel to the principal axis (the horizontal line passing through the center of the lens) enters a converging lens, it refracts and bends toward the principal axis. After refraction, the ray passes through the focal point on the opposite side of the lens. This rule is essential in understanding the behavior of light rays in converging lenses.

2. The incident ray passing through the focal point refracts and emerges parallel to the principal axis.

When a ray of light passes through the focal point before entering the lens, it refracts and emerges parallel to the principal axis. This rule implies that light rays that enter the lens at different angles converge and meet at the focal point on the opposite side.

3. The incident ray passing through the center of the lens continues undeviated.

When a ray of light passes through the center of a lens, it continues in a straight line without deviating from its path. This rule is derived from the fact that the refractive index of the lens material is the same throughout, resulting in no change in the direction of light passing through the center of the lens.

These rules of refraction for converging lenses help in understanding how light rays interact with the lens and how the lens focuses incoming light. By applying these rules, one can predict the behavior of light rays and determine the location and characteristics of images formed by converging lenses.

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The force acting on the electron is 1.92 x 10^-17 N.

The problem states that an electron of charge 1.6 x 10^-19 is located in a uniform electric field of 120 Vm^-1, and it asks us to determine the force acting on it.

We can use Coulomb's law, which states that the force between two point charges is proportional to the product of their charges and inversely proportional to the square of the distance between them. If the charges are of opposite signs, the force is attractive, while if the charges are of the same sign, the force is repulsive.

The formula for Coulomb's law is F = kq1q2/r^2, where F is the force between the charges, k is Coulomb's constant, q1 and q2 are the magnitudes of the charges, and r is the distance between them.

Since the electron has a charge of 1.6 x 10^-19 C, and the electric field strength is 120 Vm^-1, we can use the equation F = qE to find the force acting on it.

F = qE = (1.6 x 10^-19 C)(120 Vm^-1) = 1.92 x 10^-17 N.

Therefore, the force acting on the electron is 1.92 x 10^-17 N.

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Answer:

B a current flowing through a coil of wire :)

Explanation:

Explanation:

Answer is explained in the above image.

Answer:Refraction

Explanation:

or the bending of the path of the waves, is accompanied by a change in speed and wavelength of the waves.

Two forces f1=(8i+3j)N and f2=(4i+6j) are acting on 5kg object then  the magnitude of the resultant force is 15 N and the direction of the resultant force is approximately 36.87 degrees from the positive x-axis.

The acceleration of the object in the x-component (\(a_x\)) is 2.4  \(m/s^{2}\), and the acceleration in the y-component (\(a_y\)) is 1.8  \(m/s^{2}\).

The magnitude of the acceleration of the object is 3  \(m/s^{2}\).

To find the magnitude and direction of the resultant force, we need to add the two given forces together.

Given:

f1 = (8i + 3j) N

f2 = (4i + 6j) N

To find the resultant force (\(F_res\)), we simply add the corresponding components:

\(F_res\) = f1 + f2

= (8i + 3j) + (4i + 6j)

= (8 + 4)i + (3 + 6)j

= 12i + 9j

The magnitude of the resultant force (\(|F_res|\)) can be found using the Pythagorean theorem:

\(|F_res|\)= \(\sqrt{(12^2) + (9^2)}\)

= \(\sqrt{144 + 81}\)

= \(\sqrt{225}\)

= 15 N

So, the magnitude of the resultant force is 15 N.

To find the direction of the resultant force, we can use trigonometry. The direction can be represented by the angle θ between the positive x-axis and the resultant force vector. We can calculate θ using the inverse tangent function:

θ = arctan(9/12)

= arctan(3/4)

≈ 36.87 degrees

Therefore, the direction of the resultant force is approximately 36.87 degrees from the positive x-axis.

Now let's calculate the acceleration of the object in the x and y components. We know that force (F) is related to acceleration (a) through Newton's second law:

F = ma

For the x-component:

\(F_x\)= 12 N

m = 5 kg

Using  \(F_x\)= \(ma_x\), we can solve for \(a_x\):

12 N = 5 kg * \(a_x\)

\(a_x\)= 12 N / 5 kg

\(a_x\) = 2.4 \(m/s^{2}\)

For the y-component:

\(F_y\) = 9 N

m = 5 kg

Using \(F_y\) = \(ma_y\), we can solve for \(a_y\):

9 N = 5 kg * \(a_y\)

\(a_y\) = 9 N / 5 kg

\(a_y\)= 1.8  \(m/s^{2}\)

So, the acceleration of the object in the x-component (\(a_x\)) is 2.4  \(m/s^{2}\), and the acceleration in the y-component (\(a_y\)) is 1.8  \(m/s^{2}\).

To find the magnitude of the acceleration (|a|), we can use the Pythagorean theorem:

|a| = \(\sqrt{(a_x^2) + (a_y^2)}\)

= \(\sqrt{(2.4^2) + (1.8^2}\)

= \(\sqrt{5.76 + 3.24}\)

= \(\sqrt{9}\)

= 3  \(m/s^{2}\)

Therefore, the magnitude of the acceleration of the object is 3  \(m/s^{2}\)

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Answer:

because well I dont even know sorryy but you got this

The potential energy of the roller coaster is 176,400 J (joules).

The potential energy of an object is given by the formula PE = mgh, where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height or vertical position of the object.

In this case, the roller coaster is at a peak of 20m and has a mass of 900kg. The acceleration due to gravity, g, is approximately 9.8 \(m/s^2\).

Using the formula, we can calculate the potential energy:

PE = mgh

= (900 kg)(9.8 \(m/s^2\))(20 m)

= 176,400 J

Therefore, the potential energy of the roller coaster is 176,400 J (joules).

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Answer:

6km

Explanation:

Answer:

5 cm - 53 degrees

Explanation:

\( \sqrt{ {4}^{2} + {3}^{2} } = 5cm\)

\( \tan ^{ - 1} (4 \div 3) \) = 53°

D. Basketball

the answer is Basketball.

it is the most popular youth team sport for girls

in the united states

Answer:

1425kgm/s

Explanation:

Given parameters:

Mass  = 95kg

Velocity  = 15m/s

Unknown:

Momentum  = ?

Solution:

The momentum of a body is the amount of motion it posses;

  Momentum  = mass x velocity

Insert the parameters and solve;

 Momentum  = 95 x 15  = 1425kgm/s

Answer:

4m

Explanation:

you divide 20m/s by 5 seconds

Answer:

adrenaline cortisol

Explanation:

Answer:

L = 2.1 m

Explanation:

From Young's Double Slit Experiment, the formula for the distance between two consecutive dark or bright fringes, called fringe spacing, is derived as:

Δx = λL/d

where,

Δx = distance between first and second dark fringe = 4 mm = 4 x 10⁻³ m

λ = wavelength of light = 575 nm = 5.75 x 10⁻⁷ m

d = distance between the slits = 0.3 mm = 3 x 10⁻⁴ m

L = Distance from slits to screen = ?

Therefore,

4 x 10⁻³ m = (5.75 x 10⁻⁷ m)(L)/(3 x 10⁻⁴ m)

L = (4 x 10⁻³ m)/(1.92 x 10⁻³)

L = 2.1 m

b) The motion will be either created, stopped, or changed.

An unbalanced force is said to act on an object if the sum of all forces acting on it is non-zero. This means that some force is acting on the object, so the object experiences an acceleration equal to F = ma.

Force Imbalance:

Thus, there will be some change in motion in the object if multiple forces applied are unbalanced.

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Answer:b…………………………….

Explanation:

The current is 1.13* 10^{-4}A

Given that r = radius of the coil = 4 cm = 0.04 m

Area of coil is given as

A = πr²

A = (3.14) (0.04)² = 0.005024 m²

N = Number of turns = 500

R = Resistance = 600 Ω

B = magnetic field = (0.0120)t + (3 x 10⁻⁵) t⁴

Taking derivative at both the side

\( \frac{dB}{dt} = (0.120 + (12 \times 10^-5)t^3)\)

Induced current is given as

\(i= (\frac{NA}{R} )( \frac{db}{dt} )\)

\(i \: = (\frac{NA}{R})(12 \times 10 ^{-5} )t^3\)

substituting the value t = 5

\(i = ( \frac{(500)(0.005024)}{600}) (12 \times 10 ^{-5} )5^3\)

\(i = 1.13 \times 10 ^{ - 4} A\)

Hence the current is

\(1.13 \times 10^-4A\)

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The Electric current is 1.11* 10^{-4}A


Given that the coil's radius is 3.55 cm (0.35 m),

The formula for the coil's area is A = r2 A = (3.14) (0.35)2 = 0.005024 m2.

R = Resistance = 600 N = Number of spins = 500 B = Magnetic field = (0.0120)

t + (3 x 10⁻⁵) t⁴

The number t = 5 is substituted for taking the derivative at both the induced current and the electric current.

The Electric current is therefore 1.11* 10^{-4}A
Electric current - The rate of electron passage in a conductor is known as electric current. The ampere is the electric current's SI unit. Electrons are little particles that are part of a substance's molecular structure. These electrons can be held loosely or securely depending on the situation.

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Answer:

A. 1.4 m/s to the left

Explanation:

To solve this problem we must use the principle of conservation of momentum. Let's define the velocity signs according to the direction, if the velocity is to the right, a positive sign will be introduced into the equation, if the velocity is to the left, a negative sign will be introduced into the equation. Two moments will be analyzed in this equation. The moment before the collision and the moment after the collision. The moment before the collision is taken to the left of the equation and the moment after the collision to the right, so we have:

\(M_{before} = M_{after}\)

where:

M = momentum [kg*m/s]

M = m*v

where:

m = mass [kg]

v = velocity [m/s]

\((m_{1} *v_{1} )-(m_{2} *v_{2})=(m_{1} *v_{3} )+(m_{2} *v_{4})\)

where:

m1 = mass of the basketball = 0.5 [kg]

v1 = velocity of the basketball before the collision = 5 [m/s]

m2 = mass of the tennis ball = 0.05 [kg]

v2 = velocity of the tennis ball before the collision = - 30 [m/s]

v3 =  velocity of the basketball after the collision [m/s]

v4 = velocity of the tennis ball after the collision = 34 [m/s]

Now replacing and solving:

(0.5*5) - (0.05*30) = (0.5*v3) + (0.05*34)

1 - (0.05*34) = 0.5*v3

- 0.7 = 0.5*v

v = - 1.4 [m/s]

The negative sign means that the movement is towards left

Answer:

A. 1.4 m/s to the left

Explanation:

Answer: C: Feet

Explanation: Why...

Answer:

It's dimension is (d) [M L-1 T-1]

The total distance covered by the car is 300 miles.

The total displacement covered by the car is zero.

The average speed of the car is 17.88 m/s.

The average velocity of the car is also zero.

Distance between the points A and B, d = 150 miles

Time taken by the car to travel from A to B, t₁ = 3 hours

Time taken by the car to travel from B to A, t₂ = 5 hours

a) Given that the car travelled from A to B and then back to A.

Therefore, the total distance covered by the car is,

Distance = 2 x d

Distance = 2 x 150

Distance = 300 miles

Since the car is travelling from A to B and then returning back to the initial point A, the total displacement covered by the car is zero.

b) The speed with which the car travelled from A to B is,

v₁ = d/t₁

v₁ = 150/3

v₁ = 50 miles/hr

v₁ = 22.35 m/s

The speed with which the car travelled from B to A is,

v₂ = d/t₂

v₂ = 150/5

v₂ = 30 miles/hr

v₂ = 13.41 m/s

Therefore, the average speed of the car is,

v = (v₁ + v₂)/2

v = (22.35 + 13.41)/2

v = 17.88 m/s

As, the total displacement of the car is zero, the average velocity of the car is also zero.

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Answer:

Alfred Wegener

Explanation:

The airplane's vector angular momentum relative to a wheat farmer on the ground directly below the airplane is 11.61 × 10⁹ j kg m²/s and this value does not change as the airplane continues its motion along a straight line.

Its angular momentum relative to the summit of Pikes Peak is 2.7 × 10⁶ R j kg m²/s, where R is the position vector of the wheat farmer relative to the summit of Pikes Peak.

a) The momentum of the airplane relative to the wheat farmer can be calculated as, Momentum, p = m × v

Thus, Momentum, p = 15000 × 180

Momentum, p = 2.7 × 10⁶ kg m/s

The position vector of the airplane relative to the wheat farmer is given as, 4300 j

The vector angular momentum of the airplane relative to the wheat farmer is given as,

L = r × p

L = 4300 j × 2.7 × 10⁶ kg m/s

L = 11.61 × 10⁹ j kg m²/s

Therefore, the airplane's vector angular momentum relative to a wheat farmer on the ground directly below the airplane is 11.61 × 10⁹ j kg m²/s.

(b) No, this value does not change as the airplane continues its motion along a straight line.

(c) The momentum of the airplane relative to the summit of Pikes Peak can be calculated as, Momentum, p = m × v

Thus, Momentum, p = 15000 × 180 Momentum, p = 2.7 × 10⁶ kg m/s

The position vector of the airplane relative to the summit of Pikes Peak is r' = R + 4300 j

The vector angular momentum of the airplane relative to the summit of Pikes Peak is given as,Vector angular momentum,

L' = r' × p

L' = (R + 4300 j) × 2.7 × 10⁶ kg m/s

L' = R × 2.7 × 10⁶ kg m/s + 4300 j × 2.7 × 10⁶ kg m/s

L' = (2.7 × 10⁶ R) j kg m²/s

Therefore, its angular momentum relative to the summit of Pikes Peak is 2.7 × 10⁶ R j kg m²/s, where R is the position vector of the wheat farmer relative to the summit of Pikes Peak.

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Answer:

looking at aircraft of a similar size and performance, the propeller diameter is generally in the region of 1.4 – 1.8 m (4.6 ft to 6.0 ft).

Explanation:

Explanation:

Objects 1 and 2 attract each other

with a gravitational force of 72.0 units. If the distance separating Objects 1 and 2 is changed to four times the original value (i.e , quadrupled), then the new gravitational force will be units.

I apologize, but I can't help with the specific calculations you've provided. Calculating forces and friction coefficients requires specific numerical values and equations. However, I can explain the concepts and provide a general understanding of the questions you've asked.

3.1 To calculate the magnitude of the force exerted by the athlete vertically on the track, you need the vertical component of the force applied. If the angle of 50° is measured from the horizontal, you can calculate the vertical component using the equation: horizontal force = force × sin(angle).

3.2 To calculate the magnitude of the force exerted by the athlete horizontally on the track, you need the horizontal component of the force applied. Using the same angle of 50° measured from the horizontal, you can calculate the horizontal component using the equation: vertical force = force × cos(angle).

3.4 To determine the minimum value of the static friction coefficient, you would need additional information such as the mass of the athlete. In addition, you would need the normal track force. The coefficient of static friction is a dimensionless value that represents the maximum frictional force that can exist between two surfaces without causing them to slip. The formula to calculate static frictional force is static frictional force = coefficient of static friction × normal force.

3.5 To determine the resultant force exerted on an object when three forces are applied, you need to calculate the vector sum of the forces. You can add forces vectorially by breaking them down into their horizontal and vertical components. You can also sum up the components separately, and then combine them to find the resultant force.

Please provide more specific numerical values or equations if you would like assistance with the calculations.

Answer:

Which most likely has the greatest conductivity?

a warm plastic rod

a cool rubber tube

a warm copper wire

Explanation:

The warm copper wire most likely has the greatest conductivity.

Conductivity is a measure of how easily a material can conduct electricity. Metals like copper are known for having high electrical conductivity due to the presence of free electrons that can move easily through the material when an electric field is applied.

Non-metallic materials like plastic and rubber generally have low electrical conductivity because they do not have free electrons available for conduction.

Additionally, the temperature of the material can also affect its conductivity. As temperature increases, the movement of atoms and molecules in the material also increases, which can cause a decrease in electrical conductivity.

Therefore, of the materials listed, the warm copper wire is most likely to have the greatest conductivity due to its metallic properties and elevated temperature.

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