A 15 kg dog jumps out a stationary sled which has a mass of 40 kg. If
the dog's velocity is 1.2 m/s, what is the velocity of the sled?l

Answer:

7.447

Explanation:

Answer:

magnitude is 1382.59 N/C

Explanation:

Given the data in the question;

The time taken is;

t = x / v

we substitute;

t = ( 2 × 10⁻²) / ( 5.69  × 10⁶ )

t = 3.5149 × 10⁻⁹ s

next, the acceleration is;

a = 2y/t² = [2( 0.150 × 10⁻²)] / [ ( 3.5149 × 10⁻⁹ )² ]

a =  2.42826 × 10¹⁴ m/s²

now, the electric field is;

E = ma / q

we know that;

mass of electron m = 9.11 × 10⁻³¹ kg,

charge of electron q = 1.60 × 10⁻¹⁹ coulomb

we substitute

E = ( 9.11 × 10⁻³¹ )(2.42826 × 10¹⁴) / 1.60 × 10⁻¹⁹

E = 2.21214 × 10⁻¹⁶  / 1.60 × 10⁻¹⁹

E = 1.3826 × 10²¹

E = 1382.59 N/C

Therefore, magnitude is 1382.59 N/C  

Answer:

Explanation:

Question 1 (1 point)

According to theory, which term best describes the universe before the big bang?

a small densely packed ball of matter

Question 2 (1 point)

Which example is used as evidence that the universe began with the big bang?

Question 2 options:

leftover energy in the form of background radiation in the universe from the event

Question 3 (1 point)

How do scientists use the Doppler effect to understand the universe?

to determine motion of objects

Question 4 (1 point)

The Doppler effect indicates that the universe is expanding because_________.

Which phrase best completes the sentence.

light from other galaxies is red shifted

Question 5 (1 point)

What does a blue shift in light from stars indicate?

The stars are moving closer.

Answer:

mechanical weathering

Explanation:

Answer:

Mechanical weathering is responsible for the composition of a rock

Explanation:

The answer is (D)

The force (expressed in N), the egg experience upon hitting the ground is 3.5N.

When two or more forces are acting on the system of objects, then the to attain equilibrium, net force must be zero.

Given is an 0.07 kg egg and toss if from a window 30 m above the ground. The egg reaches and maintains a falling speed of 0.5 m/sec. Upon reaching the ground, the egg rapidly decelerates to 0 m/sec over the course of only 0.01 seconds.

F = m x (Vf -Vi)/t

F = 0.07 x (0 - 0.5)/0.01

F = -3.5N

Thus, the magnitude of force on egg upon hitting the ground is 3.5N.

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Answer:

5.9 cm

Explanation:

We'll begin by calculating the spring constant (K) of the spring. This can be obtained as follow:

Force (F) = 15 N

Extention (e) = 3 cm

Spring constant (K) =.?

F = Ke

15 = K × 3

Divide both side by 3

K = 15 / 3

K = 5 N/cm

Therefore, the spring constant (K) is 5 N/cm.

Now, we shall determine how far the spring will stretch when a 3 kg candy is placed on the spring balance.

This can be obtained as follow:

First, we shall determine the weight of the object.

Mass of object = 3 Kg

Acceleration due to gravity (g) = 9.8 m/s²

Weight (W) =?

W = mg

W = 3 × 9.8

W = 29.4 N

Finally, we shall determine how far the spring will stretch as follow:

Weight (W) = Force (F) = 29.4 N

Spring constant (K) = 5 N/cm

Extention (e) =?

F = ke

29.4 = 5 × e

Divide both side by 5

e = 29.4 / 5

e = 5.88 ≈ 5.9 cm

Therefore, the spring will stretch 5.9 cm when a 3 kg candy is placed on the spring balance.

a. Total energy is 0.098 J

b. Potential and Kinetic Energies is 0.032 sin^2(8.08t) J

c. Velocity at x is -0.808 sin(8.08t) m/s

d. Potential and Kinetic Energies at x is 0.016 sin^2(8.08t) J

We can use the following formulas for the energy, velocity, and potential and kinetic energies of a simple harmonic oscillator:

where ω = √(k/m) is the angular frequency.

Given that k = 19.6 N/m, A = 0.100 m, x = -(0.100 m) cos 8.08t, and v = (0.808 m/s) sin 8.08t, we can find the values of E, U, and K as follows:

(a) Total Energy:

E = 1/2 k A^2 = 1/2 * 19.6 * 0.1^2 = 0.098 J

(b) Potential and Kinetic Energies:

U = 1/2 k x^2 = 1/2 * 19.6 * (-0.1 cos(8.08t))^2 = 0.098 cos^2(8.08t) J

K = 1/2 m v^2 = 1/2 * (0.1) * (0.808 sin(8.08t))^2 = 0.032 sin^2(8.08t) J

(c) Velocity at x = 0.050 m:

When x = 0.050 m, cos(8.08t) = -0.5, so we have:

v = -ωA sin(ωt) = -ω(0.1) sin(8.08t) = -0.808 sin(8.08t) m/s

(d) Potential and Kinetic Energies at x = A/2:

When x = A/2 = 0.050 m, cos(8.08t) = -0.5, so we have:

U = 1/2 k x^2 = 1/2 * 19.6 * (0.050)^2 = 0.0245 J

K = 1/2 m v^2 = 1/2 * (0.1) * (0.808 sin(8.08t))^2 = 0.016 sin^2(8.08t) J

Note that the sum of potential and kinetic energies at any point in time is equal to the total energy, which is constant.

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Answer:A sound wave is a pressure disturbance that travels through a medium by means of particle-to-particle interaction.As one particle becomes disturbed,it exerts a force on the next adjacent particle, disturbing that particle from rest and transporting the energy through the medium.Like any wave,the speed of a sound wave refers to how fast the disturbance is passed from particle to particle.While frequency refers to the number of vibrations that an individual particle makes per unit of time, speed refers to the distance that the disturbance travels per unit of time.

Since the speed of a wave is defined as the distance that a point on a wave (such as a compression or a rarefaction)travels per unit of time,it is often expressed in units of meters/second (abbreviated m/s). In equation form, this is speed = distance/time

The faster a sound wave travels,the more distance it will cover in the same period of time.If a sound wave were observed to travel a distance of 700 meters in 2 seconds,then the speed of the wave would be 350 m/s. A slower wave would cover less distance - perhaps 660 meters - in the same time period of 2 seconds and thus have a speed of 330 m/s.Faster waves cover more distance in the same period of time.

The speed of any wave depends upon the properties of the medium through which the wave is traveling.Typically there are two essential types of properties that affect wave speed - inertial properties and elastic properties.Elastic properties are those properties related to the tendency of a material to maintain its shape and not deform whenever a force or stress is applied to it.A material such as steel will experience a very small deformation of shape and dimension when a stress is applied to it.Steel is a rigid material with a high elasticity.On the other hand,a material such as a rubber band is highly flexible;when a force is applied to stretch the rubber band,it deforms or changes its shape readily.A small stress on the rubber band causes a large deformation.Steel is considered to be a stiff or rigid material,whereas a rubber band is considered a flexible material. At the particle level,a stiff or rigid material is characterized by atoms and/or molecules with strong attractions for each other.The phase of matter has a tremendous impact upon the elastic properties of the medium.For this reason,longitudinal sound waves travel faster in solids than they do in liquids than they do in gases.Even though the inertial factor may favor gases,the elastic factor has a greater influence on the speed (v) of a wave,thus yielding this general pattern:solids > liquids > gases The density of a medium is an example of an inertial property.The greater the inertia (i.e.mass density) of individual particles of the medium,the less responsive they will be to the interactions between neighboring particles and the slower that the wave will be. However,within a single phase of matter,the inertial property of density tends to be the property that has a greatest impact upon the speed of sound.Like any liquid,water has a tendency to evaporate.As it does,particles of gaseous water become mixed in the air.The temperature will affect the strength of the particle interactions an elastic property.At normal atmospheric pressure,the temperature dependence of the speed of a sound wave through dry air is approximated by the following equation:

v = 331 m/s + (0.6 m/s/C)•T

where T is the temperature of the air in degrees Celsius.Using this equation to determine the speed of a sound wave in air at a temperature of 20 degrees Celsius yields the following solution.

v = 343 m/s

(The equation itself does not have any theoretical basis;it is simply the result of inspecting temperature-speed data for this temperature range.Other equations do exist that are based upon theoretical reasoning and provide accurate data for all temperatures.The speed of light as it travels through air and space is much faster than that of sound;it travels at 300 million meters per second or 273,400 miles per hour.Visible light can also travel through other things besides through air and through space.The speed of light in water is approximately 2.26×108 2.26 × 10 8 meters per second.

Answer:

Because the matter in solid objects doesn't move

Explanation:

Logic

Answer:

q = 5 C

Explanation:

The electric field is defined as the force experienced by a unit charge when it is brought into the field. Hence, the formula used to find the electrical field is given as follows:

E = F/q

where,

E = Electric Field Magnitude = 10 N/C

F = Force Experienced by the test charge = 50 N

q = Magnitude of the Charge = ?

Therefore,

10 N/C = 50 N/q

q = 50 N/(10 N/C)

Therefore,

q = 5 C

Answer:

D. Zero

Explanation:

A machine can only do work if it is operational

Step 1: Use Pictures

Research how other ads (especially Newspaper ads) market their toothpaste. Usually they just show a picture of a tube of toothpaste with either their target demographic using it or the toothpaste squirting out.

Step 2: Accentuate the Good Stuff

Make sure your audience is aware of all the benefits and give them evidence so they can determine if it's the best choice for them, and be sure to list all ingredients and list all additional components that sets it apart from other brands. Think of this step as a resume for your toothpaste. Obviously don't lie about what your toothpaste can do, but you want your potential customers to consider buying it.

Step 3: Focus Group (Feedback)

Post some results of how well your toothpaste was received by a group of people. Keep it sweet and simple and straight to the point. (Gather a diverse group of people who are in your target demographic to try the toothpaste, and ask for their opinions, make tweaks if needed and test again until a good chunk of people like it, that's how you get support for your brand of toothpaste.)

Step 4: Spark the Press

Reach out to local newspapers/magazines and show them your portfolio of people's feedback on your toothpaste, and with whatever money you have, you'll be paying them to allow you to put your ad in their paper (sometimes it can be vise versa).

Hope this helps, this is just a short summery of what I learned in Entrepreneurship.

Answer:

The vertical component of the velocity can be found using the formula:

V₀y = V₀ * sin(θ)

where V₀ is the initial velocity, θ is the angle of projection, and V₀y is the vertical component of the velocity.

Substituting the given values, we have:

V₀y = 48 * sin(53°)

Using a calculator, we can evaluate sin(53°) to be approximately 0.799:

V₀y = 48 * 0.799

V₀y ≈ 38.352

Therefore, the vertical component of the velocity with which the ball was launched is approximately 38 meters/second, which corresponds to option B.

Answer:

B.) 38 meters/second

Explanation:

Answer:

Twice as much

Explanation:

D 5-7 Be the only person I know of is the Book with all men and men and people experience the first of the wisdom and

The acceleration produced will be one-half as much.

Acceleration is rate of change of velocity with time. Due to having both direction and magnitude, it is a vector quantity. SI unit of acceleration is meter/second² (m/s²).

From Newton's 2nd law of motion; it can be written that:

Force = mass × acceleration

acceleration = force/mass.

Now, according to the question, an unbalanced force of 2 newtons applied to a given mass produces an acceleration.

So, when  an unbalanced force of 1 newton is applied to the same mass, the force applied on the object becomes half.

Hence, from the equation, the acceleration produced will be one-half as much.

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Answer:

D.

Explanation:

Answer:

A. underwater mountain ranges are very common

Explanation:

got it right on the quiz

Answer:

Option #3 is your answer.

Explanation:

Answer:

A “shifting baseline” in the context of marine locations (and the video this question is linked to) is that our expectations of what the ocean can produce is not fully realized due to us having not seen the best in our lifetime.

Explanation:

Not the best but should be better than the other answer. It takes what was said by Snelgrove into account instead of just guessing or ignoring half of the answer.

A “shifting baseline” in terms of marine locations  is that the expectations of what the ocean can produce. He means huge fish and nowadays you can get the same fish but only half its size.

A shifting baseline can be defined as a type of change where a system is measured against previous reference points represent a significant changes from an  earlier state of the system.

The concept was discovered by the fisheries scientist Daniel Pauly in his paper "Anecdotes and baseline shifting syndrome of fisheries".

He described that the way which radically depleted fisheries were evaluated by experts used the state of the fishery at the start of their  baseline.

Areas which swarmed with a specific species may have experienced long term decline which is considered the appropriate reference point for current populations.

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Answer:

A

Explanation: I dont really understand. But,Most likely A

Answer:

Explanation:

If we assume the car is a point mass in a frictionless world

and v is the initial velocity and the launch is from horizontal ground with no initial vertical velocity

The time to drop 2 m will be

s = ½at²

t = √(2s/a)

t = √(2(2)/9.8)

t = 0.638876...

t = 0.64 s

v = d/t

v = 6 / 0.638876...

v = 9.39148

v = 9.4 m/s

The speed of light in material B is 1.6625 × 108 m/s.

The refractive index of a material is its optical density relative to that of a vacuum.

Material B has a refractive index of nB, and its speed of light is vB.

The speed of light in material A is given as 1.25 x 108 m/s.

The refractive indices of materials A and B have a ratio of nA/nB = 1.33.

We will use the formula:

nA/nB = vB/vA = nA/nB.

Therefore, nA/nB = vB/1.25 x 108 m/s.

This equation can be rearranged to give the speed of light in material B:

vB = nA/nB × 1.25 x 108 m/s.

Therefore, vB = 1.33 × 1.25 × 108 m/s.

We will perform this calculation:

vB = 1.6625 × 108 m/s.

Therefore, the speed of light in material B is 1.6625 × 108 m/s.

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Answer:

The direction of the magnetic field should be in the x and y coordinates alone, and their should be no change towards the z coordinate. Also the magnitude of the magnetic field in the z direction would be zero if there is no magnetic field in that coordinate.

The coordinate should be:

B = bi + bj

Work done by gravity when it moves from A to C will be 288.6 joule

Applying conservation of energy between point A and B,

7.4xgx5.9 = 1/2x7.4xv2 + 7.4xgx3.2

873.2 = 7.4v2 + 473.6

v = 7.34 m/s

It should be noted that to find velocity at C, which has come down to a height of 2 meter, it means it has travelled by 5.9-2 =3.9 m

so, v2 = 2gh = 20x3.9 =

v = 8.83 m/s

Work done by gravity when it moves from A to C = mxgx(5.9-2) = 288.6 joule

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The instantaneous speed of the ant at t=8s is equal to the slope of the segment between t=7s and t=9s, which is 1.5m/s.

To find the instantaneous speed of the ant at time t=8s, we need to calculate the derivative of the displacement function with respect to time. Since the displacement of the ant is given by a piecewise function, we need to differentiate each segment of the function separately and then piece them together. From 0s to 4s, the displacement of the ant decreases linearly from 6m to 2m. The slope of this segment is -1m/s. From 4s to 7s, the displacement of the ant is constant at 2m. The slope of this segment is zero. From 7s to 9s, the displacement of the ant increases linearly from 2m to 5m. The slope of this segment is 1.5m/s. Finally, from 9s to 10s, the displacement of the ant is constant at 5m. The slope of this segment is zero.

Therefore, the instantaneous speed of the ant at t=8s is equal to the slope of the segment between t=7s and t=9s, which is 1.5m/s. This means that the ant is moving upwards at a constant speed of 1.5m/s at time t=8s. It's important to note that the instantaneous speed of the ant tells us how fast it's moving at a specific moment in time. It's not the same as the average speed over a given time interval, which would be calculated by dividing the total displacement by the total time elapsed.

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Answer:

a. lower surface area, less resistence

b. more surface area, the load is split so no single tire overstrained

c. more surface area, more resistance against the sand. human steps sink down in the sand.

d. rapid change in air pressure on eardrums lead to somewhat-painful tension

e. air would always find its way in so no pressure difference can be achieved

(would indeed appreciate the brainliest if you appreciate the work)

We can deduce here that the maximum horizontal force that you can apply to the box is 150 pounds. Thus, the heaviest box that you can push up the ramp at a constant speed is 75 pounds.

Given the following:

Maximum horizontal force = 150 pounds

Coefficient of kinetic friction = 0.50

Weight of the box = 150 pounds

Angle of the ramp = 60°

Normal force = Weight of the box * Cosine of the angle of the ramp

= 150 pounds × Cos(60°)

= 75 pounds.

Force of friction = Coefficient of kinetic friction × Normal force

= 0.50 × 75 pounds

= 37.5 pounds

Maximum force that can be applied to the box = Weight of the box × Cosine of the angle of the ramp - Force of friction

= 150 pounds × Cos(60°) - 37.5 pounds

= 75 pounds

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Answer: periodic wave

Explanation:

i just took a test and got it right

Diffraction

The bending of waves around obstacle in its path is called diffraction.

When a sound wave bends around a barrier whose dimensinn is lesser than or equal to its wavelength, this phenomenon is referred to as diffraction.

The sound can be heard even though the source of the sound cannot be seen. e

The relative velocity of the car 2 with respect to car 1 is 70 m/s west. So, the correct option is C.

Velocity of the car 1 with respect to the ground, v₁ = 45 m/s west

Velocity of the car 2 with respect to the ground, v₂ = 25 m/s east

Let the direction towards the east be positive and the opposite direction towards the west be negative.

The expression for the relative velocity of the car 2 with respect to car 1 is given by,

v₂₁ = v₂ - v₁

v₂₁ = 25 - (-45)

Therefore, the relative velocity,

v₂₁ = 70 m/s west

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Attaching the image file here.