The acceleration of the ball is 0.813m/s^2
We know that according to second law of motion,
F= ma
Total force = 10N+2.2N= 12.2N
M= 15 kg
a= F/M = 12.2/15= 0.813m/s^2
Newton's first law of motion describes the behavior of objects whose forces are all balanced. The first law, often known as the law of inertia, asserts that if the forces acting on an object are balanced, the object's acceleration is 0 m/s/s. Objects in equilibrium (the state in which all forces are equal) will not accelerate. Newton stated that an object will only accelerate if it is subjected to a net or unbalanced force. An item will accelerate in the presence of an imbalanced force, changing its speed, direction, or both speed and direction.
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Rank the following objects in order of their circular velocities, from smallest to largest.a. a 5 -kg object orbiting Earth halfway to the Moonb. a 10 -kg object orbiting Earth just above Earth's surfacec. a 15 -kg object orbiting Earth at the same distance as the Moond. a 20 -kg object orbiting Earth one-quarter of the way to the Moon
The required order of circular velocities, from smallest to largest is calculated to be d < a < c < b, where, a, b, c, d are the given options.
The velocity equation for the objects moving in circular motion is given by the equation,
v = √(G m/r)
where,
v is the velocity
G is the Gravitational constant
m is the mass of the object
r is the radius of the orbit
a. A 5 kg object halfway to the Moon circling the Earth
In this case, the radius of the orbit is the half of the distance between the Earth and the moon.
r = distance between earth and moon/2 = 384400000 m/2 = 192200000 m
So, v₁ = √(G m/r) = √(6.67408× 10⁻¹¹ × 5/192200000) = 1.317 × 10⁻⁹ m/s
b. A 10-kilogram object is circling the planet just above its surface
The orbit's radius is similar to the size of the planet Earth.
r = r earth = 6371000 m
So, v₂ = √(G m/r) = √(6.67408× 10⁻¹¹ × 10/6371000) = 1.02 × 10⁻⁸ m/s
c. A 15 kg object circling the Earth at a distance equal to that of the Moon
r = distance between the earth and the moon = 384400000 m
So, v₃ = √(G m/r) = √(6.67408× 10⁻¹¹ × 15/384400000) = 1.61 × 10⁻⁹ m/s
d. A 20 kg object that is circling the Earth and is one-quarter to the Moon
r = 1/4(distance between the earth and the moon) = 384400000 m/4 = 96100000 m
So, v₄ = √(G m/r) = √(6.67408× 10⁻¹¹ × 20/96100000) = 1.17 × 10⁻⁹ m/s
Thus, v₄ < v₁ < v₃ < v₂. And the order of options are d < a < c < b.
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two halves of a round homogeneous cylinder are held together by a thread wrapped round the cylinder with two equal weights. the complete cylinder weighs 31.4 kg. the plane of contact of both of its halves is vertical. for equilibrium of both halves of the cylinder, the minimum value of m is : (a)f g (c) f kg
The minimum value of m for the equilibrium of both halves of the cylinder is f kg.
In order for the two halves of the cylinder to be in equilibrium, the sum of the clockwise and anticlockwise moments acting on the cylinder must be zero.
Let's assume the mass of each half of the cylinder is m kg. Since the complete cylinder weighs 31.4 kg, the total mass of both halves is 2m kg.
The weight of each half of the cylinder is mg, where g is the acceleration due to gravity. Since there are two equal weights, the total weight acting on the cylinder is 2mg.
The thread wrapped around the cylinder exerts a force that creates a clockwise moment on one half of the cylinder and an anticlockwise moment on the other half. These moments must be equal in magnitude for equilibrium.
Therefore, the minimum value of m that satisfies this condition is f kg.
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The function f(x)=−0.0025x2+0.243x+3 models the path of a rocket in feet. Explain how you would use the function to determine the height the rocket was launched from, how far it traveled, and the greatest height it reached. Answer in complete sentences.
Answer:
The quadratic function models the path of the rocket. When we substitute an x value, we can determine the height in feet of the rocket.
To determine the height it was launched from, we would look at the y-intercept. This represents the starting value, as time = 0 in this point (cannot have negative time).
To determine how far the rocket traveled, we would look at the positive x-intercept of the expression. At this point, height = 0, so we can see the distance from start to finish of the rocket.
To determine the greatest height achieve, we would look at the vertex of the parabola generated from the given function. Using (-b/a, f(-b/a)), we can determine the greatest height achieved.
A 1200kg car traveling at a speed of 29 m/s drives horizontally of a 90m cliff the potential energy is=
Answer:
Sketch the situation.
b. Calculate the potential energy, the kinetic energy, and the total energy of the car as it leaves the cliff.
c. Make a graph displaying the kinetic, gravitational potential, and total energy of the car at each 10 m
increment of height as it drops
Explanation:
The potential energy of the car at that position is 10.6 x 10⁵ J.
What is meant by potential energy ?Potential energy of an object is defined as the energy acquired by the object by virtue its position.
Here,
Mass of the car, m = 1200 kg
Speed of the car, v = 29 m/s
Height of the cliff, h = 90 m
Therefore,
Potential energy of the car, PE = mgh
PE = 1200 x 9.8 x 90
PE = 10.6 x 10⁵ J
Hence,
The potential energy of the car at that position is 10.6 x 10⁵ J.
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An object dropped from rest, what will its velocity be after 30 s?
An object dropped from rest, its velocity be 294 m/s in downward direction after 30 s .
Kinematics is the study of the motion of mechanical points, bodies and systems without consideration of their associated physical properties and the forces acting on them.
initial velocity = u = 0
time = t = 30sec
g = acceleration due to gravity = 9.8 \(m/s^{2}\)
using equation of kinematics
v = u - g*t
v = 0 - 9.8 * 30
v = - 294 m/s
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supination of the forearm occurs in the _____ plane of motion.
Supination of the forearm occurs in the sagittal plane of motion.
Movements along a horizontal axis in the transverse plane separate the body into upper and lower portions. Supination, which causes the radius to rotate around the ulna, is a movement of the forearm in which the palm faces upward or forward. The palm can be turned from an inward or downward position to an upward or outward position with this motion.
The radius and ulna, two bones in the forearm, aid in supination. The hand and palm change positions from pronated (palm facing below) to supinated (palm facing upward) as the radius rotates externally or laterally in relation to the ulna. This motion is crucial for many tasks, like turning a doorknob and pouring a drink. These rotating motions are produced by the transverse plane, which makes it the ideal plane of motion for forearm supination.
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A kid pushes a stationary
merry-go-round, creating an
acceleration of 0.135 rad/s^2.
How much time does it take the
merry-go-round to complete
2.00 rotations?
(Unit = s)
Remember: CCW is +, CW is. 1 rev= 2*pi rad
The merry-go-round takes approximately 29.41 seconds to complete 2.00 rotations.
Given data:
Acceleration (α) = 0.135 rad/\(s^2\)
Number of rotations (θ) = 2.00
To find the time taken (t) for 2.00 rotations, we need to use the formula:
θ = 0.5 * α * \(t^2\)
Rearranging the formula, we get:
\(t^2\) = (2 * θ) / α
Plugging in the given values, we have:
\(t^2\) = (2 * 2.00) / 0.135
\(t^2\) = 29.63
Taking the square root of both sides, we find:
t ≈ √29.63
t ≈ 5.439
Therefore, the time taken for the merry-go-round to complete 2.00 rotations is approximately 5.439 seconds.
Note: It's important to round the final answer to an appropriate number of significant figures, considering the given data. In this case, we have used four significant figures in the final answer.
However, if we want to adhere to the given significant figures in the acceleration (0.135 rad/\(s^2\)), the answer should be rounded to three significant figures. In that case, the final answer would be approximately 5.44 seconds.
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A car is driving down a road in the early morning when a deer walks into the road. if the deer was 25 meters away when the driver noticed it and the car was traveling at 20 m/s, did the car strike the deer? assume instant reaction time and that the car has a braking acceleration of -8.33 m/s2.
For the auto now no longer to strike the deer, the minimal deceleration ought to be eight m / (s ^ 2) with a blended immediately drivers response took at the distance of 15 metres.
The given parameters are;
The distance farfar from the deer the auto turned into while the motive force notices the deer = 25 m
The velocity of the auto = 20m / s
Therefore, for the auto now no longer to strike the deer, the minimal deceleration of the auto ought to be from 20 ^ 2 / (2 * 25) = eight m/s² for a direct motive force response time
For a motive force response time of 0.five seconds, we have
Distance moved with the aid of using car = 0.five * 20 = 10 metersDistance moved with the aid of using car = 0.five * 20 = 10 meters
Minimum deceleration of the auto required = 20 ^ 2 / (2 * 15) =13. overline three m/s^ 2
Distance of the auto from the deer on the begin of deceleration = 25 - 10 = 15 meters.
Therefore, climate the deer is struck with the aid of using the auto relies upon at the drivers response time and deceleration of the auto.
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A car wheel of radius 0.3 m has an angular acceleration of 2.45 rad/s2
. Calculate
the linear acceleration of wheel.
The linear acceleration of the car wheel is 0.735 m/s².
What is the the linear acceleration of car wheel?The linear acceleration of a point on the rim of a wheel is related to the angular acceleration of the wheel by the equation:
a = rα
Where "a" is the linear acceleration, "r" is the radius of the wheel, and "α" is the angular acceleration.
Given the data in the question;
angular acceleration of α = 2.45 rad/s² radius r = 0.3 m. linear acceleration a = ?Plug the given values into the above formula and solve for the linear acceleration of wheel.
a = r × α
a = 0.3 m × 2.45
a = 0.735 m/s²
Therefore, the linear acceleration is 0.735 m/s².
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A force compresses a bone by 1.0 mm. A second bone has the same cross-sectional area but twice the length as the first. By how much would the same force compress this second bone
The force required to compress the second bone with twice the length but the same cross-sectional area as the first bone would be twice as much.
This means that the same force that compressed the first bone by 1.0 mm would compress the second bone by 0.5 mm.To understand why this is the case, we can look at the equation for strain, which is defined as the change in length divided by the original length. If we assume that the force remains constant, then the strain will be proportional to the change in length.Since the second bone has twice the length of the first bone, it will have twice the original length. Therefore, if the force is the same for both bones, the strain in the second bone will be half of the strain in the first bone. And since strain is proportional to the change in length, the compression of the second bone will also be half of the compression of the first bone.In summary, the same force that compresses the first bone by 1.0 mm would compress the second bone by 0.5 mm, because the second bone has twice the length but the same cross-sectional area as the first bone.
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A type of organism that makes its own food. __________
The highest taxonomic classification of organisms.__________
The process through which organisms make new organisms of the same kind. _______
The taxonomic classification below domains._________
A type of organism that is made of more than one cell and is more specialized and eukaryotic.__________
A characteristic passed from female and male parents to their offspring.________
FILL IN THE BLANKS PLEASEEE WILL GIVE BRAINLIEST AND 50 POINTS
Answer:
1. An autotroph
2. Domain
3. Reproduction
4. Kingdom
5. Multicellular Organism
6. Genetic trait
Explanation: Took Bio honors 1 & 2
four objects are situated along the y axis as follows: a 2.07-kg object is at 2.94 m, a 2.94-kg object is at 2.56 m, a 2.49-kg object is at the origin, and a 3.97-kg object is at -0.508 m. where is the center of mass of these objects?
As a result, on the y-axis, the centre of mass of these objects is situated 0.225 metres above the origin.
Where is the object's centre of mass?The centre of mass will always rest immediately underneath a shape if it is suspended from a single point. Hence, the centre of mass is where two lines that are drawn down downward from two different places on a shape (one at a time) intersect.
The formula below can be used to determine the system's centre of mass (COM):
COM = (m1y1 + m2y2 + m3y3 + m4y4) / (m1 + m2 + m3 + m4)
where y is an object's location on the y-axis and m is each object's mass.
The values from the problem are as follows:
m1 = 2.07 kg, y1 = 2.94 m
m2 = 2.94 kg, y2 = 2.56 m
m3 = 2.49 kg, y3 = 0 m (at the origin)
m4 = 3.97 kg, y4 = -0.508 m
With these values entered into the formula, we obtain:
COM = (2.07 kg * 2.94 m + 2.94 kg * 2.56 m + 2.49 kg * 0 m + 3.97 kg * (-0.508 m)) / (2.07 kg + 2.94 kg + 2.49 kg + 3.97 kg)
COM = 0.225 m
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I need help with my question
It is important to know that acceleartion is the change of velocity. But, the velocity is vector which can change its magnitude or direction. In this case, the battleship is changing its velocity because it's changing its direction, so that counts as acceleration.
Hence, the answer is third option: Yes becuase the object is turning.earth is located at one of the moon's orbit.target 1 of 6 2. according to kepler's second law, jupiter will be traveling most slowly around the sun when at .target 2 of 6 3. earth orbits in the shape of a/an blankaround the sun.target 3 of 6 4. the mathematical form of kepler's third law measures the period in years and the blankin astronomical units (au).target 4 of 6 5. according to kepler's second law, pluto will be traveling fastest around the sun when at blank.target 5 of 6 6. the extent to which mars' orbit differs from a perfect circle is called its
1. Earth is located at one focus of the Moon's orbit.
2. According to kepler's second law, jupiter will be traveling most slowly around the sun's aphelion
3. Earth orbits in the shape of a/an ellipse around the sun.
4. The mathematical form of Kepler's third law measures the period in years and the semimajor axis in astronomical units (AU).
5. According to Kepler's second law, Pluto will be traveling fastest around the Sun when at perihelion.
6. The extent to which Mar's orbit differs from a perfect circle is eccentricity.
What is kepler's second and third law?
Kepler's second law is a mathematical principle that states the distance between two objects in space is proportional to the square of their timescale of revolution. This means that as two objects orbit around each other, the further they will be from each other over time.
Kepler's Third Law is a scientific law that states the amount of time it takes for planets to orbit their star is inversely proportional to their distance from the sun.
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Yes! All orbiting objects adhere to Kepler's Second Law and other rules as well. Pluto moves more quickly when it is nearer the sun and less quickly when it is distant from it, much like every other object in our solar system.
What is Kepler's law of planetary motion?In astronomy, Johannes Kepler's laws of planetary motion, which were written between 1609 and 1619, define the paths taken by planets as they round the Sun. The laws altered Nicolaus Copernicus' heliocentric theory, substituting elliptical trajectories for circular orbits and epicycles, thereby explaining the variation in planetary velocities. According to the three laws:
A planet's orbit is an ellipse with the Sun as one of its two foci.Equal areas are covered over equal times by a line segment connecting a planet and the Sun.The semi-major axis of an orbital system is related to the square of the planet's orbital period.To know more about Kepler's law, visit:
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Typical raindrops fall at a speed of about 6 m/sec –
roughly 25 km/hr (15 mph). Snowflakes obviously fall more slowly.
What does this imply about the depth of cloud required to yield
precipitation t
The difference in falling speeds between raindrops and snowflakes suggests that the depth of cloud required for precipitation through the collision-coalescence process can be relatively shallow, while the Bergeron process typically requires a greater vertical extent of the cloud to yield snowfall.
The speed at which raindrops and snowflakes fall provides insights into the depth of cloud required to yield precipitation through different processes: collision-coalescence and the Bergeron process.
In the collision-coalescence process, precipitation occurs when cloud droplets collide and merge with each other to form larger droplets. These larger droplets, known as raindrops, fall to the ground. Given that raindrops fall at a relatively fast speed of about 6 m/sec, it suggests that the depth of cloud required for collision-coalescence to produce precipitation can be relatively shallow. Even in clouds with a moderate vertical extent, collision-coalescence can result in the formation of raindrops that fall at the observed speeds.
On the other hand, the Bergeron process is the primary mechanism for the formation of snowfall. It involves the interaction between supercooled water droplets and ice crystals within a cloud. In this process, ice crystals grow at the expense of water droplets, and eventually, the ice crystals become large enough to fall as snowflakes. Snowflakes fall more slowly than raindrops due to their complex and delicate structures.
The slower falling speed of snowflakes implies that the depth of cloud required for the Bergeron process to produce precipitation, specifically snowfall, is typically greater compared to the collision-coalescence process. The cloud needs to have sufficient vertical extent and specific temperature conditions to support the growth and preservation of ice crystals, allowing them to reach a size that enables them to fall as snowflakes.
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Scientist Jordan makes a discovery and publishes the results for other scientists to read. Scientist Leesha tries to repeat the experiment and cannot make it work. Her results are also published. Scientist Jordan looks at his data again and finds that the discovery only works under certain conditions. He publishes the change. Now scientist Leesha repeats the new method and finds the same results as Jordan, but another scientist, Winslow, gets different results. What does this story demonstrate? A. that scientific knowledge is impossible to obtain B. that scientific knowledge results from a lot of debate and confirmation C. that scientific knowledge is developed by individual scientists in isolation D. that scientists are really good at arguing
Answer:
Answer choice B!
Explanation:
Study Island work
Answer:A
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An initially neutral and non-polarized conducting rod is moving to the right at a constant speed v through a large region that has a uniform magnetic field, as shown above. Which of the following statements correctly describes the motion of the particles within the rod and the resulting charge separation in the rod caused by this motion?
(A) Positively charged particles within the rod moved downward, causing the bottom of the rod to have a positive charge and the top to have a negative charge.
(B) Negatively charged particles moved upward, causing the bottom of the rod to have a positive charge and the top to have a negative charge.
(C) Positively charged particles moved upward, causing the top of the rod to have a positive charge and the bottom of the rod to have a negative charge.
(D) Negatively charged particles moved downward, causing the top of the rod to have a positive charge and the bottom of the rod to have a negative charge.
Answer:
C
Explanation:
(C) Positively charged particles moved upward, causing the top of the rod to have a positive charge and the bottom of the rod to have a negative charge.
When a neutral and non-polarized conducting rod moves through a magnetic field, it will experience a force known as the Lorentz force. This force acts on the moving charges within the rod, and causes them to move perpendicular to both the direction of motion and the magnetic field. In this case, since the rod is moving to the right, and the magnetic field is pointing into the screen, the Lorentz force will act upward on the positively charged particles within the rod. This motion will cause a separation of charges in the rod, with the top having a positive charge and the bottom having a negative charge.
9th grade science here, please help will mark brainliest
Answer:
positive. hope this helped
What are the three types of mechanical waves?
A. Water
B. Circular
C.longitudinal
D. Surface
E. Transverse
F. Sound
Answer:
I'm sure its transverse, longitudinal and surface
Explanation:
sorry if I'm wrong
Mass (kg)
2
4
6
8
12
15
Weight
(N)
20
35
55
70
105
135
What is the independent variable in this experiment
Mass.
Because mass doesn't depend on weight but weight depends on mass.
A man runs 9km in 1.5 min,what is its speed?
Answer:
It is actually impossible. But the answer is: 270 km/h.
Explanation:
'If you increase the frequency of a sound wave four times, what will happen to its speed?
ОА.
The speed will increase four times.
OB.
The speed will decrease four times.
O c.
The speed will remain the same.
OD
The speed will increase twice.
O E.
The speed will decrease twice.
Q.7. For a system with a transfer function of G(s)=- co² s² +2a+w² if the natural frequency is 0.5 and the damping ratio is 1.3, which of the following statements is correct regarding the unit step response of the system?
O A) Damped
O B) Undamped
O C) Underdamped
O D) Crittically Damped
O E) Overdamped
The system described by the transfer function G(s) = -co² s² + 2a + w², with a damping ratio of 1.3 and a natural frequency of 0.5, has an overdamped unit step response. So, the correct option is (E)
The transfer function of the system is given as G(s) = -co² s² + 2a + w², where co represents the damping ratio, a represents an arbitrary constant, and w represents the natural frequency of the system. We are given that the natural frequency is 0.5 and the damping ratio is 1.3.
To determine the type of unit step response, we need to analyze the damping ratio (co) in relation to the critical damping value (co_critical).
The critical damping ratio (co_critical) is defined as the value where the system is on the threshold between being overdamped and underdamped. It is given by the formula co_critical = 2 * sqrt(a * w²).
In our case, the natural frequency (w) is 0.5, so we can calculate co_critical as follows: co_critical = 2 * sqrt(a * 0.5²).
Since the damping ratio (co) is given as 1.3, we can compare it with co_critical to determine the type of unit step response.
If co > co_critical, the system is considered overdamped (Option E).
If co = co_critical, the system is considered critically damped (Option D).
If co < co_critical, the system is considered underdamped (Option C).
Based on the given values, we can determine that the system is overdamped (Option E) because the damping ratio (1.3) is greater than the critical damping ratio.
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Which element is MOST LIKELY to be dull?
carbon
aluminum
mercury
sodium
as a blade? murcury because it stays liquid at room temp. it would be a puddle with a hanfle which is like... really dull
How does the speed of light that emerges from a pane of glass compare with the speed of light incident on the glass?.
The speed of light that emerges from a pane of glass compare with the speed of light incident on the glass because The emerging and incident speed of lights are the same.
What is Light ?Light is a phenomenon which is defined as the electromagnetic form of energy which gives us the sensation of vision.
What is Speed ?Speed is defined as the rate of change of distance travelled by a body per unit time.
What is the speed of light?The speed at which the light propagates through the medium is known as Speed of light. It is a fundamental constant of the nature. In all inertial frames of reference the speed of light in free space has the same value.
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How far would a cantaloupe fall in 5.0 seconds of true free fall?
Answer:
i think the answer is about 50 m/s
What is one characteristic of an electron?
O A. Almost no charge
O B. A mass of 1 amu
O C. A charge of +1
O D. Almost no mass
Answer:
the answer to this question is A
Answer:
It is D. Almost no mass
Explanation:
The mass of an electron is 1/2000 times of proton/neutron
PLEASE HELP SOMEONE. I'LL GIVE BRAINLIEST.
Use the correct key term to complete each of the following sentences.
1. Amplitude measures the _________ of a wave.
2. When frequency increases, the length of the wavelength ___________. .
3. A wave’s energy is ___________ related to its frequency.
4. The top of a wave is call the _________. .
5. The number of waves that pass a given point per unit of time is the __________. .
6. The _________ refers to the distance between two adjacent crests of a wave.
Answer: Key Terms - Amplitude, Wavelength, Frequency, Ionizing radiation, Nonionizing radiation, Radio waves, Microwaves, Infrared lights, Visible light waves, Ultraviolet radiation, X-rays, Gamma rays, Speed of light
Using the Skygazer's Almanac for 2022 at 40 degrees.
What day will Venus and Saturn be in opposite parts of the sky
this year?
According to the Skygazer's Almanac for 2022 at 40 degrees, Venus and Saturn will be in opposite parts of the sky on December 17, 2022.
The Skygazer's Almanac provides astronomical information for a specific location and year. In this case, at a latitude of 40 degrees, the almanac indicates that Venus and Saturn will be in opposite parts of the sky on December 17, 2022. This means that Venus and Saturn will appear at opposite sides of the celestial sphere as observed from Earth. However, it's important to note that the almanac's predictions are approximate and can be influenced by various factors, including atmospheric conditions and the observer's specific location. To obtain the most accurate and up-to-date information, it is recommended to consult more recent astronomical sources or use specialized software that can provide precise positions and dates for celestial events.
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