A 1.5 V battery is connected to a 250 μF capacitor. How much charge is found on the capacitor plates?

Answer:

10.61 m/s

Explanation:

To find the final speed, we will use the conservation of momentum in each direction, so we can write the following equations:

Where m1 and m2 are the mass of the vehicles, v1 and v2 are their respective velocities in each direction, and Vfx and Vfy are the final velocities in each direction.

If one of the vehicles is headed north, its horizontal velocity Vx = 0 m/s. In the same way if the other is headed east, its vertical velocity Vy = 0m/s

Therefore, we can replace the values and solve the first equation as:

In the same way, we can solve the second equation as:

Now, we know that the vertical and horizontal speed was 7.5 m/s. So, we can calculate the final speed using the Pythagorean theorem as:

So, the speed after the collision was 10.61 m/s

Answer:

El resorte se comprime 0.38 m.

Explanation:

La distancia de compresión del resorte se puede calcular por conservación de la energía:

\( \Sigma E_{i} = \Sigma E_{f} \)

\( E_{p} = E_{e} \)

\( mgh = \frac{1}{2}kx^{2} \)   (1)

En donde:

\(E_{i}\) y \(E_{f}\): son las energías inciales y finales

\( E_{p}\): es la energía potencial gravitacional

\(E_{e}\): es la energía potencial elástica

m: es la masa = 1.50 kg

g: es la gravedad = 9.81 m/s²

h: es la altura

k: es la constante de fuerza = 320 N/m    

x: es la distancia de compresión

Dado que el objeto está 1.20 m sobre el resorte, entonces h es:

\( h = 1.20 + x \)  (2)

Entonces, introduciendo la ecuación (2) en (1) y resolviendo para x tenemos:

\( \frac{1}{2}kx^{2} - xmg - 1.20mg = 0 \)  

\( 160x^{2} - 14.72x - 17.66 = 0 \)  

Resolviendo la ecuación cuadrática anterior tenemos:

x₁ = -0.29 y x₂ = 0.38

Tomando el valor positivo entonces, el resorte se comprime 0.38 metros.

Espero que te sea de utilidad!  

The mechanical power expended when transporting the wheelchair is 25 Watts

Power is defined as  the amount of energy transferred or converted per unit time. The unit of power is measured in Watts. The higher units are kilowatts, megawatts etc.

The formula for calculating the power expended is expressed as:

Power = Workdone/Time

Since workdone = force * distance, the formula for power will be:

Power = Force*distance/Time

Given the following parameters

Force = 50N

distance = 0.5m

time = 1 second

Substitute to determine the power

Power = 50*0.5/1

Power = 25/1

Power = 25Watts

Hence the mechanical power expended when transporting the wheelchair is 25 Watts

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Answer:

4 target heart rate. is the answer

Explanation:

hope its right

Answer:

B

Explanation:

The appropriate choice to address the concern of interference from Earth's atmosphere would be:

B. Digital; digital signals can be designed to minimize the effect of interference.

why does something fall faster if it is heavier?

➪ First of all I would like to inform you that this statement is not true. The acceleration does not depend on the mass of the object. Heavier things have a greater gravitational force AND heavier things have a lower acceleration. It turns out that these two effects exactly cancel to make falling objects have the same acceleration regardless of mass.

Lets see

According to Newton's second law

\(\\ \rm\rightarrowtail F=ma\)

\(\\ \rm\rightarrowtail F\propto m\)

\(\\ \rm\rightarrowtail m\propto \dfrac{1}{a}\)

So heavier objects fall faster than lighter ones .

The word done will be 120 joules if we lift an object with a force of 20 N off the ground.

Work is the application of force to a task. It is directly correlated with both the amount of force applied to the object and its motion. The equation below can be used to calculate work: Work is equal to force times distance. The Newton meter is the SI unit of work (N m).

W = Fd is the formula for the amount of work W that a constant force does on an object. It is determined by multiplying the force's intensity by the distance the object moves in the force's direction.

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Answer:

. The distance traveled by the object. The time taken to travel .The direction of travel

PLEASE MARK MY ANSWER AS THE BRAINLIEST❤❤

In order to describe the velocity of an object, the distance traveled by the object, the time taken to travel, and the direction of travel. Therefore, option (B) is correct.

Velocity can be described as a vector measurement of the direction and motion of an object. The velocity of a body can be defined as the rate of change in the object’s position w.r.t. time taken.

The velocity of an object is a vector quantity as it carries both magnitude and direction. A mathematical formula common way to determine velocity can be shown as:

v = d / t

where v is the velocity, d is the distance moved, and t is the time taken by the object.

Although the S.I. unit for the velocity of an object is m/s and can also represent as miles per hour (mph), and kilometers per hour (kph).

Therefore, we need distance traveled, time taken, and direction to describe the velocity of an object.

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An object of mass m is moving in a circle of radius R with a constant speed of v.The magnitude of the net force on the object moving in a circle is equal to the centripetal force, which is given by  |F_net| = |F_c| = (m × v^2) / R.

The magnitude of the net force on an object moving in a circle with a constant speed is given by the centripetal force.

The centripetal force (F_c) can be calculated using the equation:

F_c = (m × v^2) / R

where F_c is the centripetal force, m is the mass of the object, v is the speed of the object, and R is the radius of the circle.

Therefore, the magnitude of the net force on the object moving in a circle is equal to the centripetal force, which is given by:

|F_net| = |F_c| = (m × v^2) / R

Where |F_net| denotes the magnitude of the net force.

It's important to note that the net force is always directed towards the center of the circle, providing the necessary inward force to keep the object moving in a circular path.

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I got you! :D

this is my essay i wrote for my teacher.

Every storm cloud has a silver lining; in the case of space weather, that lining is the aurora borealis, more commonly known as the Northern Lights. (Viewers in the southern hemisphere are treated to an equivalent version called the aurora australis, or Southern Lights.) The phenomenon is best observed on a clear, cold night around the spring or autumn equinox. Find an open patch of sky well away from the interfering lights of the city, and you may catch a glimpse of the spectacle: curtains of pale light-green and blue, sometimes red or violet-shimmering above the northern horizon for minutes or even hours at a time.

Auroras occur when electrons and protons from the Sun strike gas molecules in Earth's upper atmosphere. As the solar particles encounter Earth's magnetosphere, they are drawn along the magnetic field lines and funneled toward the North and South poles. There, high above Earth's surface, they collide with atmospheric molecules, energizing them and causing them to glow. The colors that result depend on the gas molecules involved. The brightest and most common auroral color, a brilliant yellow-green, is produced by the glow of oxygen molecules roughly 60 miles above Earth. Ionized nitrogen molecules emit blue light when hit by solar particles; neutral nitrogen molecules emit a purplish-red light. All-red auroras are rare; they are caused by the glow of oxygen atoms 200 miles above Earth. The size and intensity of the aurora varies from night to night, and moment to moment, depending on the strength of the solar wind. On April 6, 2001, a large geomagnetic storm produced an aurora that was seen as far south as Alabama. The scientific understanding of auroras has advanced enormously in recent years with the launch of satellites designed expressly to study them. Instruments aboard NASA's Polar spacecraft monitor ultraviolet radiation and chemical changes in the upper atmosphere, effectively offering an up-to-the-minute report on the shape and intensity of the aurora. The Imager for Magnetopause-to-Aurora Exploration (IMAGE) spacecraft, launched in 2000, studies Earth's magnetosphere in astounding detail. It can watch auroras evolve over a period of hours, and can even see auroras flickering in the far-ultraviolet wavelength. Recently and for the first time, scientists observed a phenomenon known as "black auroras." A black aurora isn't really an aurora at all: it's the dark, empty space within a colorful aurora where one would otherwise expect auroral activity to be visible. Nonetheless, black auroras exhibit distinct patterns, including curls, rings and writhing black patches. Nowadays, scientists often can forecast a spectacular aurora hours or days in advance, so it's worth checking space weather websites (See Related Links) with some regularity.

In the 1970s, with the aid of the Hubble Space Telescope, it became apparent that Earth is not the only planet with auroras. On both Jupiter and Saturn, auroras appear pink due to the large amounts of hydrogen in those planets' atmospheres. Jupiter's aurora has proved to be particularly intriguing. On Earth, the aurora is powered by a barrage of charged particles from the Sun. On Jupiter, auroras are generated instead by volcanic particles from the Jovian moon Io. These particles become ionized, expand and then are trapped in Jupiter's tremendous magnetic field. Rotating once every ten hours, Jupiter generates auroras many times more powerful than those on Earth. However, Earth's auroras remain unique in one respect: they are (at times, anyway) green. Indeed, Earth is the only known planet with green auroras, because it is the only known planet with an oxygen-rich atmosphere. As scientists look deeper into the universe for signs of other, potentially habitable worlds, auroras are one clue they examine. If a distant, unknown planet has shimmering green auroras, that's a strong indication that its atmosphere is rich in oxygen, perhaps enough to support life. Whether that life is capable of appreciating the auroras well, that's another issue.

Answer:

Explanation:

People should care about sexual harassment for many reasons. such as, sexual harassment is a very serious and touchy topic. Sexual harassment should not be tolerated and can ruin many peoples mental health.

The k-factor for the hexagonal lattice of 1.4 cm radius natural uranium rods and graphite, with a lattice pitch of 20 cm, is approximately 0.907.

To calculate the k-factor for a hexagonal lattice of uranium rods and graphite, we need to determine the number of uranium rods within a given area and the total area of the unit cell.

1. First, let's calculate the area of the hexagonal unit cell:

The lattice pitch is given as 20 cm, which is the distance between the centers of adjacent uranium rods.

The radius of the uranium rods is 1.4 cm, so the distance between their centers is twice the radius, which is 2.8 cm.

The distance between the centers of the graphite rods will also be 2.8 cm.

Now, we can calculate the area of the hexagonal unit cell using the formula:

Area = (3√3/2) * (distance between centers)^2

Area = (3√3/2) * (2.8 cm)^2

Area ≈ 21.2 cm^2

2. Next, we need to determine the number of uranium rods within the unit cell.

The hexagonal lattice arrangement allows for 1 uranium rod at the center and 6 uranium rods surrounding it.

Total number of uranium rods in the unit cell = 1 (center) + 6 (surrounding) = 7 rods

3. Finally, we can calculate the k-factor using the formula:

k = (1 - (ρ_graphite/ρ_uranium)) * (Number of uranium rods/Area)

The density of uranium (ρ_uranium) is approximately 19.1 g/cm^3.

The density of graphite (ρ_graphite) is approximately 2.26 g/cm^3.

k = (1 - (2.26 g/cm^3 / 19.1 g/cm^3)) * (7 rods / 21.2 cm^2)

k ≈ 0.907

Therefore, the k-factor for the hexagonal lattice of 1.4 cm radius natural uranium rods and graphite, with a lattice pitch of 20 cm, is approximately 0.907.

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The slope of a cold front is steeper than that of a warm front.

A warm front and a cold front are two different fronts associated with a mid-latitude low-pressure system. A cross-sectional view of these fronts can be helpful in better understanding their characteristics and structure. Let's take a look at the horizontal cross-section of these fronts:

Image showing the Horizontal Cross section of a warm front and a cold front for a mid-latitude low pressure system:

The 150 isobar is shown in bold.

The vertical structure of a warm front:

In a mid-latitude low-pressure system, a warm front represents the leading edge of a warm, moist air mass as it approaches a region of cold, dry air. In general, the warm air moves toward the cold air in the form of a low-level wedge. The warm front is associated with a gradual decrease in temperature and pressure as one moves from the warm side to the cold side of the front. The steepness of the frontal slope is gradual. The slope is gradual because the warm air rises over the cool air.

The vertical structure of a cold front:

A cold front represents the leading edge of a cold, dry air mass as it advances toward a region of warm, moist air. It is usually associated with a line of clouds, precipitation, and thunderstorms. The frontal slope is steeper than that of a warm front, with a temperature drop of several degrees Celsius per kilometer of ascent. The cold air moves in a downward motion to the ground and forces the warm air up. This motion creates clouds, precipitation, and sometimes thunderstorms. Therefore, the slope of a cold front is steeper than that of a warm front.

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The correct choice is ~ A

Bikes don't require gasoline for their functioning, so it causes less air pollution.

Answer:

[A] Bikes do not require gasoline.

Explanation:

[Question] :

Why is riding a bike better for the environment than driving a car?

Answer choices Explanation:

[A] Bikes do not require gasoline.

That True as well as it doesn't require gasoline which protect the environment

[B] That also True but it doesn't explain why riding a bike is better for environment

[C] Bikes require more energy to move.

That True for humans we have to ride it but that doesn't given a reason on why riding a bike is better for environment

[D] Bikes require the building of more roads.

Why having a bikes require building of more roads?? Maybe car need more roads but I don't see a point to make more roads for bikes.

Hence, [A] Bikes do not require gasoline Given the best answer for riding a bike better for the environment than driving a car

Kavinsky

Answer:

its D

Explanation:

i just got it correct on a. p. e. x. :)

Answer:

How long does the ball fall is t_2 =  13.66 (s).

From what height is the ball originally dropped is h=  913.90 (m).

Explanation:

The heat energy transfer process responsible for transferring heat energy from the Earth to the air directly above it is conduction.

Conduction is a form of heat transfer in which heat moves from one object to another by direct contact without the requirement of any physical motion of the objects themselves.

Conduction occurs when a heat source, such as the Earth's surface, transfers heat energy to the air molecules in contact with it. The air molecules, which are heated by conduction, then move and collide with other air molecules in the surrounding area, eventually spreading the heat throughout the atmosphere.

Convection is another type of heat transfer that plays a significant role in the transfer of heat from the Earth's surface to the atmosphere. This occurs as air that is heated by conduction rises, creating convection currents that move heat throughout the atmosphere as air circulates in the environment.

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Answer:

The atomic radius of a chemical element is a measure of the size of its atoms, usually the mean or typical distance from the center of the nucleus to the boundary of the surrounding shells of electrons.

Explanation:

Hope It Helps!

Answer:

Friction

Explanation:

Because the brake pad is rubbing alongside the wheel to slow the body of the car down

Answer:

B and D

Explanation:

Both a CD and alarm clock have magnetic properties of metal alloys and polymers.

Answer:

Flexibility is the ability of a joint or series of joints to move through an unrestricted, pain free range of motion. ... These soft tissues include: muscles, ligaments, tendons, joint capsules, and skin.

Explanation:

The speed of this child from this surface would be 14.69 m / s

We have the formula for energy conservation as:

E - potential = E - kinetic

We have the following details with which we are to solve the problem

weight of child w = 350 N

length of rope L = 7.2m

angle θ = 12 degrees

we would have the solution as

m x 9.8m/s² x (10.2 + 1.79 - 7.2 x cos 12) = 1/2 mv²

we would have to solve out the expression that we have above. Such that :

9.8m * (11.99 - 0.9781) = 1/2 mv²

107.9 m = 1/2 mv²

cancel out m

107.9 = 0.5v²

divide through by 0.5

107.9 / 0.5 = v²

215.8 = v²

v = √215.8

v = 14.69

Hence the speed of the child at the surface of the water would be given as 14.69 m / s

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When a material is reflective, it would cause the light that meets it to bounce off while a transparent material would make the light to pass through it.

Light is a form of energy that produces a sensation that is visible to the optical eye. We know that a material is said to be transparent if the material can allow light to pass through it. A material is said to be reflective when it bounces off the rays of light that fall on it.

We can see that when light interacts with the transparent material, the light can pass through the material. If the light interacts with the reflective material then the light rays are seen to bounce off the light rays.

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Answer:

\(v_d=0.1\ mm/s\)

Explanation:

The current flowing through a conductor is given as:

\(I=neAv_d\\where\ A =area\ of\ conductor=\pi d^2/4=\pi(1*10^-3)^2/4=7.85*10^{-7}\\\\I=current\ flowing\ through\ the \ conductor=1.1A\\\\e=charge\ of \ electron=1.602*10^{-19}\\\\N_A=Avogadro \ constant=6.023*10^{23}\ mol^{-1}\\\\Density=9*10^3kg/m^3=9*10^6g/m^3\\\\n=\frac{6.023*10^{23}\ mol^{-1}*9*10^6\ g/m^3}{63\ g/mol} =8.604*10^{28}\ m^{3}\\\\v_d=\frac{I}{neA}=\frac{1.1}{8.604*10^{28}*1.602*10^{-19}*7.85*10^{-7}}=0.0001\ m/s\\\\v_d=0.1\ mm/s\)

Answer:

a stone rock

Explanation:

The metamorphic rock is produced by great heat and pressure and is never melted.  

• The rock, which get changed from one kind to another is known as the metamorphic rock.  

• It is produced from either sedimentary rock or igneous rock, the majority of the Earth's crust is formed of metamorphic rock.  

• The sedimentary and igneous rock turn into metamorphic rock due to intense heat from magma and pressure from tectonic shifting.  

• The rock in spite of becoming extremely hot and under a lot of pressure does not get melt. If it gets melt it is not a metamorphic rock, it is an igneous rock.  

• The metamorphism makes the composition and texture of the mineral to change. The formation of new textures takes place due to the process known as recrystallization.  

Thus, the rock is the metamorphic rock.

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Answer:

Ans

A) this element is aluminum, and it has 3 valence electrons

Explanation:

Plastics with a density less than or equal to 1.025 g/mL will float in seawater, while plastics with a density greater than 1.025 g/mL will sink.

Here are some examples of plastic densities:

Polyethylene terephthalate (PET) has a density of approximately 1.38 g/mL, so it will sink in seawater.

Polypropylene (PP) has a density of approximately 0.9 g/mL, so it will float in seawater.

High-density polyethylene (HDPE) has a density of approximately 0.95 g/mL, so it will float in seawater.

Polystyrene (PS) has a density of approximately 1.05 g/mL, so it will sink in seawater.

Based on the above examples, we can see that plastics such as polypropylene and high-density polyethylene will definitely float in seawater, while others such as polyethylene terephthalate and polystyrene will definitely sink. Other types of plastics with densities close to 1.025 g/mL may float or sink depending on their exact density and the conditions of the water, such as temperature and salinity.

Answer:

the impulse experienced by the egg is 0.053 kgm/s.

Explanation:

Given;

mass of the egg, m = 60 g = 0.06 kg

initial velocity of the egg, u = 6 m/s

height moved by the egg, h = 50 cm = 0.5 m

Determine the final velocity of the egg as it moves upward;

v² = u² + 2(-g)h

v² = u² - 2gh

where;

v is the final velocity

-g is negative acceleration due gravity as it moves upward

v² = 6² - 2(9.8 x 0.5)

v² = 26.2

v = √26.2

v = 5.12 m/s

The impulse applied to the egg is the change in linear momentum;

J = ΔP

ΔP = mu - mv

ΔP = m(u - v)

ΔP = 0.06(6 - 5.12)

ΔP = 0.053 kgm/s

Therefore, the impulse experienced by the egg is 0.053 kgm/s.