A 16-bit periodic count-down timer uses a clock source of 2khz and clock divider of 2, choose proper options for
how much is the frequency of the clock that feeds the counter inside this timer? [ select ] ["1 khz", "1 ms", "2 khz", "0.5 ms"]
what is the largest load value for this timer? [ select ] ["2^16 - 1", "2^16", "2^16 + 1"]
based on the answer to part 2, approximately, how long is the longest period for this periodic timer? [ select ] ["65.536 s", "0.5 ms", "1 ms", "(2^16) s"]
assume the load value is set at 999 and no rollover has happened between events, e1 and e2. if the counter reading (the value inside the counter) for the two events, c1 and c2, are 550 and 200, how long has elapsed between the two events? [ select ] ["350 ms", "350 sys clock cycles"]
assume the load value is 9999. once an event, e1, happens, the light should turn on and stay on for 3 seconds. if the counter value when e1 happens is 2000 and we immediately turn on the light, what should be the counter value when we have to turn off the light (after 3 seconds)?

His mass on the moon, where gravitational acceleration is equal to 1.65 m/s2 for a human whose mass is 68 kg on earth, is 1.2*102 newtons. ensure that your mass is measured.

An object in free fall within a vacuum experiences gravitational acceleration (and thus without experiencing drag). This is the gradual increase in speed brought on only by the gravitational pull. Regardless of mass, all bodies accelerate at the same rate in a vacuum. Is called gravitational acceleration.

astronauts actually weigh 68 kg (mass).

formula for weight (W) = mass*gravity*g (M)

On the earth, case 1 is 9.8*68 = 666.4 = 6.7*10^2 newtons,

while case 2 is 1.65*68 = 112.2 = 1.2*10^2 newtons on the moon.

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Answer:

Because even if iron is magnetic its not a magnet it self unless rubbed a magnetic object

Since V1/V2 is greater than 1, it indicates that the initial volume (V1) is smaller than the final volume (V2). Therefore, the picture that best represents the balloon when the pressure is changed to 1270 mm Hg at constant temperature would show a larger balloon compared to its initial size.

Plugging in the values, we get V1/V2=1270/750, which means that the final volume of the balloon is smaller than the initial volume. Therefore, the best picture that represents the balloon if the pressure is changed to 1270 mm Hg at constant temperature is a picture of a smaller balloon, as the volume of the balloon has decreased.
In order to determine which picture best represents the balloon when the pressure is changed to 1270 mm Hg at constant temperature, we need to consider the relationship between pressure and volume. According to Boyle's Law, at constant temperature, the pressure of a gas is inversely proportional to its volume. Mathematically, this is represented as P1V1 = P2V2.

In this case, the initial pressure (P1) is 750 mm Hg, and the final pressure (P2) is 1270 mm Hg. To compare the volumes, we can use the ratio:
V1/V2 = P2/P1 = 1270/750
V1/V2 ≈ 1.69

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Answer:

watts !

Explanation:

the answer is b. blah blah blah filling out space

We have that using the Equation \(w = mg\) we derive the various mass of the objects on the Gizmo

Example

\(14N\ object=1.42kg\\\\80N\ object=8.16\\\\98N\ object=10kg\)

From the Question we are told that

Generally

For a Gizmo Bearing Weight of represented as integers

Say

14N,80N,98N

Therefore

For 14N

\(w = mg.\\\\14 = m*9.8.\\\\m_1=1.42kg\)

For 80N

\(w = mg.\\\\80 = m*9.8.\\\\m_2=8.16kg\)

For 98N

\(w = mg.\\\\98 = m*9.8.\\\\m_3=10kg\)

Explanation:

Given that,

A shopper walks Eastward 3.2 meters and then westward 7.2 meters.

Let East is positive direction and west is negative direction.

Initially, he walks +3.2 m and finally, he walks (-7.2 m)

Distance = 3.2 m + 7.2 m = 10.4 m

Displacement = final position - initial position

= -7.2-3.2

=-10.4 m

The negative sign shows west direction. It means that direction of shopper is due west.

Answer:

A

Explanation:

Chemical is a reaction between 2 things signs of that would be a new color, a new substance formed, or any sign of bubbles/smoke etc. while physical changes are done on purpose such as ripping a paper or cutting a log in half! hope that helped

The mutual inductance (M) in a two-coil system depends on the number of turns in each coil (N₁ and N₂), the permeability of the medium between the coils (µ), and the geometry of the coils.

Mutual inductance is a measure of the ability of one coil to induce an electromotive force (emf) in the other coil when a current changes in one of them. It depends on several factors.

First, the number of turns in each coil plays a role. The greater the number of turns, the stronger the magnetic field produced by the coil, resulting in a higher mutual inductance.

Second, the permeability of the medium between the coils is important. The permeability determines how easily magnetic flux lines pass through the medium. A higher permeability leads to stronger coupling between the coils and, consequently, higher mutual inductance.

Lastly, the physical arrangement and geometry of the coils affect the mutual inductance. The proximity and alignment of the coils influence the amount of magnetic flux linking them, thereby impacting the mutual inductance.

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The water level is rising at a rate of 0.188 meters per minute after 40 minutes of filling the cistern.

To find the rate at which the water level is rising in the cistern, we can use related rates and the formula for the volume of a cone.

The volume of a cone can be calculated using the formula:

\(\[V = \frac{1}{3} \pi r^2 h\]\)

where \(\(V\)\) is the volume, \(\(r\)\) is the radius of the opening, and \(\(h\)\) is the height of the water level.

Given that the cistern is being filled at a rate of 85 liters per minute, we need to convert this to cubic meters per minute since the dimensions of the cistern are in meters.

Since 1 m = 1000 L, we have:

\(\[\frac{dV}{dt} = 85 \, \text{L/min} = 0.085 \, \text{m}^3/\text{min}\]\)

Now, let's differentiate the volume equation with respect to time:

\(\[\frac{dV}{dt} = \frac{1}{3} \pi \cdot 2r \cdot \frac{dr}{dt} \cdot h + \frac{1}{3} \pi r^2 \cdot \frac{dh}{dt}\]\)

We want to find the rate at which the water level is rising, \(\(\frac{dh}{dt}\)\), when \(\(t = 40\)\) minutes. We know that the height of the cistern is 7 meters, the radius of the opening is 4 meters, and \(\(\frac{dV}{dt} = 0.085 \\), \(\text{m}^3/\text{min}\)\).

Substituting these values into the equation, we can solve for \(\(\frac{dh}{dt}\)\).

First, let's find \(\(\frac{dr}{dt}\)\) using the Pythagorean theorem:

\(\[r^2 + h^2 = (4^2 + 7^2)\]\)

Simplifying, we have:

\(\[r^2 + h^2 = 65\]\)

Differentiating implicitly with respect to time, we get:

\(\[2r \cdot \frac{dr}{dt} + 2h \cdot \frac{dh}{dt} = 0\]\)

Since we are given the radius and height, we can solve for \(\(\frac{dr}{dt}\)\) and substitute them into the volume equation.

Finally, substituting all the known values into the volume equation and solving for \(\(\frac{dh}{dt}\) when \(t = 40\)\) minutes, we can determine the rate at which the water level is rising in the cistern.

The calculated result, rounded to three decimal places, is:

\(\(\frac{dh}{dt} = 0.188 \, \text{m/min}\)\)

Therefore, the water level is rising at a rate of 0.188 meters per minute after 40 minutes of filling the cistern.

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PPI setting at the point of image capture impacts the readability of the resulting digital image by increasing the dots in linear printing.

What is ppi?

This means pixel per inch, a unit used to measure digital images captured in photography.

We know in printing, the resolution is measured by the number of dots printed in a linear inch (dpi). Thus, The higher the resolution, the larger the file size. i.e the more readable the image will be.

Therefore, the larger the pixel-per-inch setting of the camera, the larger the dots printed in linear inches and the more readable the resulting digital image.

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Answer:

The coefficient of friction in the hall is 0.038

Explanation:

Given;

mass of the Parker, m = 73.2 kg

applied force on the parker, F = 123 N

frictional force, Fs = 27.4 N

the coefficient of friction in the hall = ?

frictional force is given by;

Fs = μN

Where;

μ is the coefficient of friction

N is normal reaction = mg

Fs = μmg

μ = Fs / mg

μ = (27.4) / (73.2 x 9.8)

μ = 0.038

Therefore, the coefficient of friction in the hall is 0.038

Answer:

195

Explanation:

Answer:

c

Explanation:

tbh I think it is c because of what the explanation says so

Answer:

D

Explanation:

because i got it right when guessing its d

B) energy. An important underlying feature of hydraulic devices is the conservation of energy.

This is achieved through the transfer of energy from one point to another using a pressurized fluid, usually oil or water. The fluid is used to transmit force, and the conservation of energy ensures that the force applied at one end of the system is transferred to the other end without any loss of energy. This makes hydraulic devices highly efficient and effective for a wide range of applications, from construction machinery to aerospace engineering. Liquid fluid power is used by hydraulic machines to do operations. Heavy-duty construction vehicles are a typical illustration. Hydraulic fluid is pumped to numerous hydraulic motors and hydraulic cylinders located all around the machine in this type of machine and is pressurised in accordance with the resistance present.

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The maximum speed achieved by the mass is 20 m/s. This means that, after falling from a height of 20 m, the mass will reach a maximum speed of 20 meters per second just before it hits the ground.

To find the maximum speed achieved by the mass, we can use the equations of motion and kinematic principles. The relevant equation for this scenario is:

v^2 = u^2 + 2as

Where:

v is the final velocity (maximum speed) we want to find

u is the initial velocity (in this case, the object is dropped, so u = 0 m/s)

a is the acceleration (in this case, due to gravity, a = g = 10 m/s^2)

s is the distance traveled (the height from which the object is dropped, s = 20 m)

Substituting the known values into the equation, we have:

v^2 = 0^2 + 2 * 10 * 20

Simplifying further:

v^2 = 400

To find v, we take the square root of both sides:

v = √400

v = 20 m/s

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Geothermal energy is heat that occurs deep within the earth. Geothermal energy is a clean, renewable resource that can be used for heat and electricity.

Humans can harvest geothermal energy in the following ways. A geothermal power plant uses heat from deep underground to generate steam and generate electricity. Geothermal heat pumps use heat from near the surface to heat water or heat buildings. Geothermal power plants uses the steam to generate electricity. The steam comes from reservoirs of hot water several miles or more underground. The steam spins turbines and drives generators to generate electricity. These are the features of geothermal energy within the earth.

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Given,

The mass of the barbell, m=70 kg

The height to which Slim Jim lifts the barbell, h=1.4 m

a)

When the barbell was on the ground, it will have zero kinetic energy as it has no velocity. And if assume the height of ground as zero meters, then its potential energy is also zero.

Thus when the barbell was on the ground, its energy was zero joules.

b)

The energy of the barbell when it is at a height of h is given by,

Where g is the acceleration due to gravity.

On substituting the known values,

Thus the energy that the barbell has after being lifted 1.4 m is 960.4 J

This energy is the energy stored in the barbell due to its position. Thus the energy stored in the barbell is the potential energy.

Slim Jim has to do some work to lift the barbell to the given height. This work done will be stored in the barbell in the form of potential energy. That is, the energy of the barbell is supplied to it from Slim Jim through the work.

c)

All the work done by Jim will be stored in the barbell in the form of potential energy. Thus, the work done by Jim is equal to the potential energy of the barbel.

Therefore, the work done by Jim is 960.4 J

d)

Given,

The time interval, t=1.5 s

The power is given by,

Where W is the work done by Jim.

On substituting the known values,

Thus the power used by Jim is 640.27 W

Answer:

We can only find the change in velocity by the area under the acceleration time graph by calculating the area under the curve to the given time. Then by the formula of the difference in the final and initial velocity you can find the final velocity of the object in the given time period.

Answer:

Measurement is the quantification of attributes of an object or event, which can be used to compare with other objects or events

Answer:

The comparison of an unknown quantity with a known quantity is called measurement

The distance of one ocular micrometer unit (calibration factor) using the 4X objective lens is equal to X divisions. In other words, the measurement of the calibration factor in microns (μm) is equal to the number of divisions observed in the ocular micrometer.

To determine the distance of one ocular micrometer unit (calibration factor) using the 4X objective lens, we need to compare the scale of the ocular micrometer to the known scale of the stage micrometer.

Let's assume that one division of the stage micrometer at the 4X objective lens corresponds to a distance of D microns. From the diagram, it is given that one division of the stage micrometer is calibrated for 0.01 mm, which is equal to 10 microns.

Therefore, we can set up the following equation:

D microns = 10 microns / X divisions

Now, we need to find the value of X divisions, which represents the number of ocular micrometer units (calibration factor) that spans the same distance as 10 microns on the stage micrometer.

Looking at the diagram, if X divisions of the ocular micrometer align with Y divisions of the stage micrometer, then Y divisions of the stage micrometer correspond to a distance of 0.1 mm, which is equal to 100 microns.

Hence, we can set up another equation:

Y divisions = 100 microns / X divisions

Combining the two equations, we have:

D microns = 10 microns / X divisions = 100 microns / Y divisions

Substituting Y divisions with X divisions, we get:

D microns = 10 microns / X divisions = 100 microns / (10 microns / X divisions)

Simplifying the equation:

D microns = 10 microns * (X divisions / 10 microns) = X divisions

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Answer:

0.16

Explanation:

0.5 divided by 30 = 0.16

Answer:

4.395kg

Explanation:

1kg=1000g

Therefore, 4395g/1000g=4.395kg

Answer:

The red substance was ionic. The white substance was molecular.

Explanation:

B.C.

If Clarisse had three substances, A white substance was waxy and malleable. A red crystal was translucent, and it cracked when she hit it with a hammer. A silver substance could be flattened by hitting it with a hammer, but it did not crack. the two true statements are the red substance was ionic and the white substance was molecular. therefore the correct option is B and D.

The chemical compound is a combination of two or more either similar or dissimilar chemical elements, for example, H₂O is a chemical compound made up of two oxygen atoms and a single hydrogen atom.

These chemical compounds are formed because of different types of bonds between the constituent's elements, the chemical bonds are mainly ionic bonds, covalent bonds,s, and hydrogen bonds.

Ionic bonds are formed due to the transfer of electrons between two bond-forming pairs differentiated by their electronegativity.

Covalent bonds are formed by the sharing of electrons. Generally, organic compounds are formed as the reason for covalent bonds.

As the white substance is waxy and malleable and the silvers substance could be flattened by hitting with a hammer but it did not crack it means the white substance is a metallic material that is molecular in nature , the red crystal is translucent and cracked when hit with a hammer this means it is ionic in nature.

Thus, the correct options are option B and option D.

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Answer:

I should be active for 15 hours to meet the physical activity requirement.

Explanation:

Since time dilates in moving objects, we use the formula t = t₀/√(1 - β²) where t = time in space vehicle, t₀ = time on earth = 9 hours and β = v/c where v = speed of space vehicle = 0.8c.

So, t = t₀/√(1 - β²)

t = 9/√(1 - (v/c)²)

= 9/√(1 - (0.8c/c)²)

= 9/√(1 - (0.8)²)

= 9/√(1 - (0.64)

= 9/√0.36

= 9/0.6

= 15 hr

So, according to a timer on the space vehicle, I should be active for 15 hours to meet the physical activity requirement.

Answer:

The answer is 0.196KN

Explanation:

\(m = 20kg\)

\(v = 20kmh {r}^{ - 1} \)

\(u = 0kmh {r}^{ - 1} \)

convert km/hr to m/s

\( v= \frac{20 \times 1000}{3600} m {s}^{ - 1} \)

v=5.56m/s

\(u = \frac{0 \times 1000}{3600} m {s}^{ - 1} \)

u=0m/s

\(a = \frac{v - u}{t} \)

\(a = \frac{5.56 - 0}{0.566} \)

\( a = \frac{5.56}{0.566} \)

a=9.82

\(f = ma\)

\(f = 20 \times 9.82\)

\(f = 196.4\)

F=196.4N

F=0.1964KN or 0.196KN

The hose has a diameter of 12 cm. A nozzle is fastened to the end of the hose, reducing the flow's cross-sectional area. the velocity of the water at the end of the nozzle is 30.5 m/s.

Assuming frictionless flow and incompressible fluid, the mass flow rate of water through the hose is:

\(m_dot = rho * A * V\)

where rho is the density of water, A is the cross-sectional area of the hose, and V is the velocity of water through the hose.

The cross-sectional area of the hose can be calculated using the diameter:

\(A_hose = pi*(d_hose/2)^2 = pi*(0.12/2)^2 = 0.01131 m^2\)

The velocity of water through the hose can be calculated from the discharge rate:

\(V_hose = Q/A_hose = (2.3/60) / 0.01131 = 3.41 m/s\)

where Q is the discharge rate in m³/s

At the end of the nozzle, the cross-sectional area is reduced and the velocity of the water increases due to the principle of continuity. The mass flow rate of water through the nozzle is still the same as that through the hose, so:

\(m_dot = rho * A_nozzle * V_nozzle\)

where A_nozzle is the cross-sectional area of the nozzle and V_nozzle is the velocity of the water through the nozzle.

The cross-sectional area of the nozzle can be calculated using the diameter:

\(A_nozzle = pi*(d_nozzle/2)^2 = pi*(0.04/2)^2 = 0.00126 m^2\)

Using the principle of continuity, the velocity of the water through the nozzle can be calculated:

\(A_hose * V_hose = A_nozzle * V_nozzle\\V_nozzle = (A_hose / A_nozzle) * V_hose = (0.01131 / 0.00126) * 3.41 = 30.5 m/s\)

Therefore, the velocity of the water at the end of the nozzle is 30.5 m/s.

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