Answer:1m/s
Explanation: As the stationary ball is hit by the moving ball ,the two moves together after collision, with a single velocity. The attached photo further explains how the answer is calculated
When stationary ball is hit by the moving ball, both the balls moves together after collision. The final velocity of the object after collision is 1 m/s.
When stationary ball is hit by the moving ball, both the balls moves together after collision
The conservation of momentum,
\(\bold {m_1 u_1 + m_2u_2 = (m_1+m_2) V}\\\)
Where,
m1 - initial mass = 20 kg
m2 - final mass =10 kg
u1 - initial velocity = 0 m/s (object at rest)
u2 - final velocity = 3 m/s
V- velocity after collision = ?
Put the values int he formula and calculate for V2,
\(\bold { 10 \times 0 + 20 \times 3 = (10+20) V}\\\\\bold {V = \dfrac {30}{30}}\\\\\bold {V = 1\ m/s}\)
Therefore, final velocity of the object after collision is 1 m/s.
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How do I find the mass in kg
To find the mass in kilograms, you need to know the object's weight in newtons and the acceleration due to gravity. The formula for finding mass is mass = weight / acceleration due to gravity. So if you have an object with a weight of 100 N and the acceleration due to gravity is 9.8 m/s^2, the mass would be 10.204 kg.
The mass of the block is 0.025 kg or 25 g, when the spring has k = 28 N/m, and compresses 0.11 m before bringing the block to rest.
When a block is dropped onto a spring with k=28 N/m, the block has a speed of 3.2 m/s just before it strikes the spring. If the spring compresses an amount of 0.11 m before bringing the block to rest, what is the mass of the block?The formula for the spring potential energy is given as follows; PE = (1/2) kx² where k is the spring constant and x is the amount of deformation of the spring. Substituting the values given;PE = (1/2) 28 (0.11)²PE = 0.16972 J. According to the law of conservation of energy, the potential energy stored in the spring at maximum compression is equal to the kinetic energy the block had before it struck the spring;KE = (1/2) mv²where m is the mass of the block and v is its velocity.Substituting the values;0.16972 = (1/2) m (3.2)²m = 0.025 kg or 25 gTherefore, the mass of the block is 0.025 kg or 25 g.For more questions on mass
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Question 6 of 10
How would you change the distance between two charged particles to
increase the electric force between them by a factor of 16?
A. Reduce the distance by a factor of 4.
B. Increase the distance by a factor of 4.
C. Reduce the distance by a factor of 16.
D. Increase the distance by a factor of 16.
SUBMIT
Reduce the distance by a factor of 4 change the distance between two charged particles to increase the electric force between them by a factor of 16.
Thus, When charged things interact with other objects, there is an electric force present in the system.
The electric force between them is appealing because positive charges are attracted to negative charges. For two positive charges or two negative charges, the electric force is repellent.
A typical illustration of this is what happens when two balloons are rubbed on a blanket. When you rub the balloons against the blanket, electrons from the blanket transfer to the balloons, leaving the blanket positively charged and the balloons negatively charged.
Thus, Reduce the distance by a factor of 4 change the distance between two charged particles to increase the electric force between them by a factor of 16.
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A spring is 50 cm in length when not compressed. The spring is then compressed by 35 cm by a force of 100N What is the k value of this spring?
Answer:
k=6.666
Explanation:
F=kx
100=k 50-35
100=k*15
k=6.666
PLEASE HELP ALL I NEED IS A DRAWING, i posted this like 100 times please help.
Answer:
Hope this helps
Explanation:
A crossbow is fired horizontally off a cliff with an initial velocity of 15 m/s. If the arrow takes 4s to hit the ground, what is the range of the projectile?
Answer:
The range of the projectile is 60 m
Explanation:
Horizontal Motion
When an object is thrown horizontally with a speed vo from a height h, it describes a curved path ruled exclusively by gravity until it eventually hits the ground.
The horizontal component of the velocity is always constant because no acceleration acts in that direction, thus:
\(v_x=v_o\)
The vertical component of the velocity changes in time because gravity makes the object fall at increasing speed given by:
\(v_y=g.t\)
The horizontal distance is calculated as a constant speed motion:
\(x = v_x.t\)
Knowing the crossbow is fired horizontally at vo=vx=15 m/s and it takes t=4 s to hit the ground, thus the range of the projectile is:
x = 15*4 = 60
The range of the projectile is 60 m
A 150-g apple is falling from a tree. What is the impulse that Earth exerts on it during the first 0.50m of its fall? The next 0.50 m ?
The impulse that Earth exerts on the apple during the next 0.50m of its fall is:
Δp = m * v2 - m * v1 = 0.15 kg * 4.43 m/s - 0.15 kg * 3.13 m/s = 0.16 Ns.
The impulse that Earth exerts on an object is equal to the change in momentum of the object. The momentum of an object is given by:
p = m * v
where p is momentum, m is mass, and v is velocity.
During free fall, the velocity of the object increases due to the acceleration due to gravity, which is approximately 9.81 m/s^2. Therefore, the velocity of the apple after falling a distance of d is:
v = sqrt(2gd)
where g is the acceleration due to gravity and d is the distance fallen.
The change in momentum of the apple during the first 0.50m of its fall is:
Δp = p2 - p1 = m * v2 - m * v1
where p1 is the initial momentum, p2 is the final momentum, v1 is the initial velocity (which is 0), and v2 is the final velocity after falling a distance of 0.50m.
Plugging in the values:
m = 150 g = 0.15 kg
g = 9.81 m/\(s^2\)
d = 0.50 m
The final velocity of the apple after falling 0.50m is:
v2 = sqrt(2gd) = sqrt(29.810.50) = 3.13 m/s
Therefore, the impulse that Earth exerts on the apple during the first 0.50m of its fall is:
Δp = m * v2 - m * v1 = 0.15 kg * 3.13 m/s - 0.15 kg * 0 m/s = 0.47 Ns
For the next 0.50m of its fall, the initial velocity is now 3.13 m/s and the final velocity after falling another 0.50m is:
v2 = sqrt(2gd) = sqrt(29.811.00) = 4.43 m/s.
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B. On a separate sheet of paper, describe the different ways of generating electric power.
Answer:
These all different sources of energy add to the store of electrical power that is then sent out to different locations via high powered lines. It is the energy from the sun that is harnessed using a range of technologies such as solar heating, solar architecture, photovoltaics, and artificial photosynthesis.
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Discuss the consequences of poor health and safety when using non-ionising and ionising radiation technologies and the prevention and safety measures employed.
Poor health and safety practices when using non-ionizing and ionizing radiation technologies can have significant consequences. Here are some potential consequences and the prevention and safety measures employed to mitigate them.
Consequences of poor health and safety:
Non-Ionizing Radiation:
Thermal Effects: Prolonged exposure to high levels of non-ionizing radiation, such as from radiofrequency waves (RF) or microwaves, can lead to thermal effects, including tissue heating and burns.Ionizing Radiation:
Acute Radiation Syndrome (ARS): High doses of ionizing radiation, such as those experienced during a nuclear accident or radiation therapy accidents, can lead to ARS, which includes symptoms like nausea, vomiting, fatigue, and potentially fatal damage to vital organs.Prevention and safety measures:
Non-Ionizing Radiation:
Time, Distance, and Shielding: Minimize exposure time to non-ionizing radiation sources, maintain a safe distance from the source, and use shielding materials (e.g., lead aprons, and protective barriers) to reduce exposure.Compliance with Guidelines: Follow national and international guidelines and regulations regarding safe exposure limits for different types of non-ionizing radiation sources. For example, adherence to specific absorption rate (SAR) limits for mobile devices.Ionizing Radiation:
Risk Assessment and Minimization: Conduct thorough risk assessments to identify potential hazards, establish safety protocols, and minimize radiation exposure through engineering controls and administrative measures.Personal Protective Equipment (PPE): Use appropriate PPE, such as lead aprons, gloves, and goggles, to protect against direct radiation exposure.Training and Education: Provide comprehensive training and education to workers who handle ionizing radiation sources to ensure they are aware of the risks, safety protocols, and proper handling procedures.Monitoring and Dosimetry: Regularly monitor radiation levels in the workplace and ensure that employees wear dosimeters to measure their radiation exposure.Regulatory Compliance: Adhere to applicable regulations and standards, such as those set by radiation protection agencies and authorities, to ensure compliance with safety measures and limits on radiation exposure.know more about ionizing radiation here:
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The chart shows data for four moving objects.
Object
Initial Velocity
Final Velocity
Change in
(m/s)
(m/s)
Time (s)
29
6
X>N
10
34
12
12
40
20
28
8
Which object has the greatest acceleration?
W
x
Y
Z
Answer:
Explanation:
The chart shows data for four moving objects.
Object
Initial Velocity
Final Velocity
Change in
(m/s)
(m/s)
Time (s)
29
6
X>N
10
34
12
12
40
20
28
8
Which object has the greatest acceleration?
W
x
Y
Sanjay and Ting, each with a mass of 25 kg, are riding opposite each other on the edge of a 150 kg, 3.0-m-diameter playground merry-go-round that's rotating at 15 rpm. Each walks straight inward and stops 35 cm from the center.
What is the new angular velocity, in rpm?
Express your answer in revolutions per minute.
The merry-go-round's new angular velocity is 0.321 rpm.
Calculation-
the system's overall angular momentum is:L = Iω
The moment of inertia of a solid disk rotating about its centre is given by:
\(I = (1/2)mr^2I = (1/2)(150 kg)(1.5 m)^2 = 168.75 kg·m^2\)
initial angular momentum of the system
L = Iω = \((168.75 kg·m^2)(15 rpm)(2π/60 s) = 52.36 kg·m^2/s\)
The new angular velocity is determined by:
L = I'ω'
where L represents the system's initial angular momentum.
The system's new moment of inertia is:
\(I' = I - 2mr^2\)
we get:
\(I' = 25 kg - 2(168.75 kg/m2)(0.35 m)^2 = 162.88 kg·m^2\)
We get the following by substituting into the conservation of angular momentum equation:
L = I'ω'
\((162.88 kg/m2) / 52.36 kg/m2\)
ω' = 0.321 rpm
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help pls i don’t know what to dooooooo
Explanation:
distance from ground
mass
amount of compression
Gun was fired with a muzzle velocity of 350m/s, mounted at an angle of 45’ above the ground. Neglecting air resistance, compute for the following;
*Maximum height reached
*Range of the projectile
*Total time of flight
Answer:
Maximum height, h = 3062.5m
Total time of flight, T = 49.49secs or 50secs approx.
Range, R = 12250m
Explanation:
Given data:
U = 350m/s
Angle = 45°
Assume g = 10m/s
At the greatest height, v = 0
Therefore,
V^2 = U^2 sin^2 × angle - 2×g×h
Substituting values:
0^2 = 350^2 sin^2 (45) - 2 × 10 × h
Let h = maximum height reached
Rearranging gives:
350^2 sin^2(45) = 2 x 10 x h
h = 350^2 sin^2(45)/2×10
h = 122500 x 0.5/20
h = 61250/20
h = 3062.5m
2)Total time of flight, T
T = 2U sin(angle)/g
= 2x350 sin(45)/10
= 494.9747/10
= 49.49secs or 50sec approx.
3) Range of projectile, R
R = U^2 sin2(angle)
= 350^2 sin2 (45)
= 122500 x 1/10
= 12250m
A force of 400-N pushes on a 25-kg box horizontally. The box accelerates at 9 m/s? Find the coefficient of kinetic friction between the box and floor.
Answer:
0.69Explanation:
Using the Newtons law of motion;
\(\sum Fx = ma_x\\Fm - Ff = ma_x\)
Fm is the moving force = 400N
Ff is the frictional force = μR
μ is the coefficient of kinetic friction
R is the reaction = mg
m is the mass
a is the acceleration
The equation becomes;
\(Fm - \mu R = ma_x\\Fm - \mu mg = ma_x\\400- \mu (25)(9.8) = 25(9)\\400 - 254.8 \mu = 225\\- 254.8 \mu = 225 - 400\\- 254.8 \mu = -175\\ \mu = \frac{-175}{- 254.8} \\\mu = 0.69\)
Hence the coefficient of kinetic friction between the box and floor is 0.69
The coefficient of kinetic friction between the box and the floor is 0.714.
Friction: This can be defined as the force that tends to oppose two surfaces in motion.
The question above can be solved using the formula
F-ma = mgμ................. Equation 1
Where F = Force applied to push the box, m = mass of the box, a = acceleration of the box, μ = coefficient of kinetic friction, g = acceleration due to gravity.
make μ the subject of the equation
μ = (F-ma)/mg................ Equation 2
From the question,
Given: F = 400 N, m = 25 kg, a = 9 m/s²,
Constant: g = 9.8 m/s²
Substitute these values into equation 2
μ = [400-(25×9)]/(25×9.8)
μ = (400-225)/245
μ = 175/245
μ = 0.714
Hence, the coefficient of kinetic friction between the box and the floor is 0.714.
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A soccer ball is dropped from a height of 2 m and falls to the floor.
What is the relationship of the potential and kinetic energies of the ball as the ball falls to the floor?
O A. The kinetic energy of the ball will increase as its potential energy is stored during the fall to the floor.
O B. The potential energy of the ball will transform into kinetic and thermal energy while it falls to the floor.
c.
The kinetic energy of the ball will increase, and its potential energy will be constant until it hits the floor.
O D. The potential energy of the ball will completely transform into kinetic energy just before it hits the floor.
Answer:
d your welcome ehhehe:)
___________________ uses the heat energy from the Earth. This type of alternative energy can be installed basically anywhere in North Carolina.
A) wave energy
B) solar energy
C) nuclear energy
D) geothermal energy
Answer:
Geothermal!!
Explanation:
Geo means earth! Just like Hydro means water, and Pyro means fire :)
Answer:
The Answer is D). Geothermal energy
Explanation:
Hope this helps!!!!!
A man pulls a box with an applied force of 500N. He pulls the box 100.0 m. About how much work does he do? Question options: 0.5 J 50,000 J 5,000 J 2 J
Workdone:-
\(\\ \tt\longrightarrow Force\times Displacement \)
\(\\ \tt\longrightarrow 500(100)\)
\(\\ \tt\longrightarrow 50000J\)
describe how the volume of a floating object such as a cork can be found.fully describe please step by step.
Answer:
Explanation:
Use Archimedes' principle, that states something of this nature: "The buoyant force acting on an object immersed in a fluid is equal to the weight of the fluid displaced"
Say, you take a cube of wood(for example) and place it in a bucket of water. Your cube is bound to sink, until, the upthrust force equals its weight.
Where does this upthrust come from?
As the cube sinks, it displaced some volume of water(if the bucket were full you would see water pouring out)
Archimedes simply stated that: Upthrust,
U=mg
Example: One way to measure the volume of any irregular object (in your case, a stone) is to submerge it completely under water and measure the change in the height of the water level. This change in the water level (let's say it goes from 50 mL to 65 mL) indicates that the stone has a volume of 15 mL.Example:Subtract the first volume from the second volume to calculate the volume of the stone. For example, if you recorded 40 fluid ounces the first time, and 50 fluid ounces the second time, the stone volume is 10 fluid ounces.If the Earths atmosphere is air, then why doesn't the land fall? How is all the lava and water IN earth?
Answer:
Its stored in there
Explanation:
And air has little mass
Consider the circuit in Figure 5 with e(t) = 12sin(120pit) V. When S1 and S2 are
open, i leads e by 30°. When SI is closed and S2 is open, i lags e by 30°. When S1 and S2 are closed, i has an amplitude 0.5A. What are R, L, and C?
Based on the information, it should be noted that the resistance R is 0.5 Ω.
How to calculate the resistanceWhen S1 and S2 are open, i leads e by 30°. In this case, the circuit consists of only the inductor (L) and the capacitor (C) in series. Therefore, the impedance of the circuit can be written as:
Z = jωL - 1/(jωC)
Since i leads e by 30°, we can express the phasor relationship as:
I = k * e^(j(ωt + θ))
Z = jωL - 1/(jωC) = j(120π)L - 1/(j(120π)C)
Re(Z) = 0
By equating the real parts, we get:
0 = 0 - 1/(120πC)
Let's assume that there is a resistance (R) in series with the inductor and capacitor. The impedance equation becomes:
Z = R + jωL - 1/(jωC)
Z = R + jωL
Im(Z) = ωL > 0
Substituting the angular frequency and rearranging the inequality, we have:
120πL > 0
L > 0
This condition implies that the inductance L must be greater than zero.
When S1 and S2 are closed, i has an amplitude of 0.5 A. In this case, the impedance is:
Z = R + jωL - 1/(jωC)
Since the amplitude of i is given as 0.5 A, we can express the phasor relationship as:
I = 0.5 * e^(j(ωt + θ))
By substituting this phasor relationship into the impedance equation, we can determine the value of R. The real part of the impedance must be equal to R:
Re(Z) = R
Since the amplitude of i is 0.5 A, the real part of the impedance must be equal to 0.5 A: 0.5 = R
Therefore, the resistance R is 0.5 Ω.
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what current flows through the 75 ohm resistor in the circuit below?
The current that flows through the 75 ohm resistor in the circuit shown below is 0.12A.
How to calculate current?The current flowing through a circuit can be calculated using the Ohm's law equation as follows;
V = IR
Where;
V = voltage (V)I = current (A)R = resistance (ohm)According to this question, a circuit is shown in the above image. A 75 ohm resistor is given alongside a voltage of 9V. The current can be calculated as follows;
9 = I × 75
I = 0.12A
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Two car (A) and (B) start from the rest at the same instant of time t=0 . From the points M and N respectively in uniformly accelerated rectilinear motion and in opposite directions as shownin the adjacent figure give acceleration of (A) is 4m/s² and that (B) is 2m/s² .MN 30km At the instant t the car (A) covered a distance d¹ and B covers a distance d² 1 determine as a function of t d¹and d² . 2 deduce the time meeting 2 cars . 3 answer the preceding questions but consider that car (B) in uniform rectilinear motion with a speed of 10 m/s
To solve the problem, let's break it down into three parts:
1. Determining the distance covered by cars A and B as a function of time:
For uniformly accelerated rectilinear motion, we can use the following equation to calculate the distance covered:
distance = initial velocity * time + (1/2) * acceleration * time^2
For car A:
The initial velocity is 0 m/s, and the acceleration is 4 m/s².
So, the distance covered by car A at time t is:
d¹(t) = 0.5 * 4 * t^2 = 2t^2
For car B:
The initial velocity is 0 m/s, and the acceleration is -2 m/s² (opposite direction to car A).
So, the distance covered by car B at time t is:
d²(t) = 0.5 * -2 * t^2 = -t^2
2. Deducing the time of meeting for the two cars:
To find the time of meeting, we need to set the distances covered by both cars equal to each other:
2t^2 = -t^2
Simplifying the equation:
2t^2 + t^2 = 0
3t^2 = 0
Since the equation equals zero, the only solution is t = 0. This means that the two cars meet at the starting point at t = 0.
3. Considering car B in uniform rectilinear motion with a speed of 10 m/s:
If car B is moving at a constant speed of 10 m/s, it means its acceleration is 0 m/s². Therefore, the equation for car B's distance covered becomes:
d²(t) = initial velocity * time = 10 * t = 10t
Now, we can answer the preceding questions using this new equation for car B.
1. The distance covered by car A at time t is still d¹(t) = 2t^2.
The distance covered by car B at time t is now d²(t) = 10t.
2. The time of meeting for the two cars can be found by setting the distances equal to each other:
2t^2 = 10t
Simplifying the equation:
2t^2 - 10t = 0
2t(t - 5) = 0
From this equation, we have two solutions:
t = 0 (the initial meeting point)
t = 5 seconds (when the two cars meet again after 5 seconds)
Therefore, the cars meet again after 5 seconds.
Please note that the distances calculated above are in terms of t, the time elapsed since t = 0.
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A set of pulleys is used to lift a piano weighing 1,000 newtons. The piano is lifted 3 meters in 120 seconds. How much power was used?
Answer:
25 watts
Explanation:
Power=work/time
work=force x distance
1000 × 3
=3000 Joules
power= 3000/120
=25 watts
If A set of pulleys is used to lift a piano weighing 1,000 newtons. The piano is lifted 3 meters in 120 seconds. Then the power used is equal to 25 watts.
What is power?Power is the rate at which work is done or energy is transferred. It is a physical quantity that measures how quickly energy is used or transformed.
P=W/s
Where W= work done in joules.
s= time in seconds.
Power is typically measured in watts (W), which is equivalent to joules per second (J/s). In simple terms, power can be defined as the amount of work done or energy transferred per unit of time.
Here in the question,
To calculate the power used to lift the piano, we need to use the formula:
Power = Work / Time
The work done in lifting the piano is given by:
Work = Force x Distance
Where
Force = the weight of the piano, which is 1,000 newtons,
Distance = the height to which it is lifted, which is 3 meters.
Then, the work done is:
Work = 1,000 N x 3 m = 3,000 joules
The time taken to lift the piano is 120 seconds.
Now we can substitute these values in the formula for power:
Power = Work / Time
Power = 3,000 joules / 120 seconds
Power = 25 watts
Therefore, the power used to lift the piano is 25 watts.
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Newton's Third Law of Motion
Answer:
Whenever one body exerts a force on a second body, the first body experiences a force that is equal in magnitude and opposite in direction to the force that it exerts
Explanation:
Answer: According to Khan Academy "Newton's third law: If an object A exerts a force on object B, then object B must exert a force of equal magnitude and opposite direction back on object A.
Explanation: This law represents a certain symmetry in nature: forces always occur in pairs, and one body cannot exert a force on another without experiencing a force itself. We sometimes refer to this law loosely as action-reaction, where the force exerted is the action and the force experienced as a consequence is the reaction.
We can readily see Newton’s third law at work by taking a look at how people move about. Consider a swimmer pushing off from the side of a pool, as illustrated below.
A swimmer pushes on the wall with her feet, which causes the wall to push back on her feet due to Newton's third law."
Hope this helps ^_^ and have a great day
Hello anyone have the answer for Newton's Third Law of Motion
Newton's Third Law of Motion states that for every reaction, there is always an equal but an opposite reaction.
Newton's law is proposed by Sir Isaac Newton. He is an English physicist and he proposed three laws of motion.
The first law of motionThe second law of motionThe third law of motionNewton's Third Law of Motion states that for every reaction, there is always an equal but an opposite reaction.
Examples of Newton's Third Law of Motion are:
Rowing a boatAttraction of paper clip to a magnetRecoil of a gunLearn more about Newton's law here:
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2 An electric kettle is marked "230V, 1.5 kW.
a Explain what these numbers mean.
b Calculate the correct fuse that should be used.
c Explain why a 230V, 100 W bulb glows more brightly than a 230 V, 60 W
bulb when both are connected to the mains supply.
The power needed to boil the water is divided by the element's power output, and the result is multiplied by 100 to get the efficiency of the kettle as a percentage. The answer is 79 %.
To Find the efficiency of electric kettle ?We are informed that
Electric kettle power is 1 kW.
Electric kettle voltage is 230 V.
The time it takes the kettle to bring the water to boiling point is 7.5 minutes.
1 kg = mass of water.
Heat generated equals V x I x t + Pt.
generated heat = 1000 W x 7.5 x 60
Heat absorbed equals (100 - 15) x 1 x 4200 = 4200 x 85
Efficiency is determined by multiplying the heat produced by the heat absorbed by 100.
= 4.2 x 85 x 10^3 / 4.5 x 10^5 x 100
= 357 / 4.5 = 79 %
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Consider the steel spring in the illustration.
(a) Find the pitch, solid height, and number of active turns.
(b) Find the spring rate. Assume the material is A227 HD steel.
(c) Find the force �
�
F s
required to close the spring solid.
(d) Find the shear stress in the spring due to the force �
�
F s
.
Pitch 0.396, solid height 12 turns, number of active turns 1.755 Spring rate is 1.08N/3, force is 81.9N and the stress in the spring is 3.85Kspi
How does science define force?The term "force" has a specific meaning in science. At this point, describing a force as a push or a pull is perfectly appropriate. A strength is not something an item "has in it" or that it "contains." One thing experiences a force from another. There are both living things and non-living objects with in concept of a force.
What exactly are power and its unit?Force: Force is just a physical factor that alters or has the potential to alter an object's state of motion or motion and its form. Newton is the SI unit of force.
(a) Pitch, solid height, number of active turns
\(N_{t}\)= 12.5 coils
pitch = 4.75/12
=0.396
The ends are squared along 1/4 turns on each end
\(N_{a}\)= 12.5-0.5
=12 turns
Solid height: solid stack is 13 wire diameter
\(L_{s}\)= 13(0.135) = 1.755
(b) Spring rate
\(K=\frac{d^{2}c }{8D^{3}N_{a} }\)
\(= \frac{3.4^{4}*78.6*10^{3} }{8*46.6^{3}*12 }\)
\(= 1.08 N/3\\\) or 6.08 uof/in
(c) Force
\(F_{v}=K(L_{0}- L_{1} =1.08 (12.-44.2)\\ =81.9N or 18.2 Lbf\)
(d) c= D/d = 1.865/0.135 = 13.81
\(K_{b}=\frac{4(13.81)+2}{4(13.81)-3} = 1.096\)
\(T_{s}-K_{B} = \frac{8F_{D} }{nd^{3} } = 1.096 * \frac{8(18.2)(1.865)}{(0.135^{3} )}=3.85 Kpsi\)
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how does a football work
Answer:
As the football travels up, gravity slows it down until it reaches a point where it stops briefly at its highest peak; then the football comes down, and gravity accelerates it until it hits the ground hard.
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If in the figure below, the friction between the block and the incline is negligible, (a) how much must the object on the right weigh if the 200-N block is to remain at rest? Ans: 115 N (b) if the system remains at rest when F= 220 N. What are the magnitude and direction of the friction force on the 200-N block? Ans: 105 N down the incline 200 N Fw 35.0⁰
The magnitude of the acceleration and its direction however depends on the resultant force.
What is the resultant force?
In a system of forces, the resultant force is the force that has the same effect in magnitude and direction as all the forces acting together.
In an inclined plane, the friction, weight and applied force all act together on the object. The magnitude of the acceleration and its direction however depends on the resultant force.
This question is incomplete as the diagrams are missing hence the numerical values can not be computed.
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A new planet is discovered orbiting the Sun, and scientists have determined that the semi-major axis of its orbit is 10.5 AU. How many Earth years will it take for this
planet to orbit the Sun once?
Answer:
30.2 Earth years for the new planet to orbit the Sun once.
Explanation:
An AU (astronomical unit) is the average distance from the Earth to the Sun, approximately 93 million miles or 150 million kilometers. So a semi-major axis of 10.5 AU is roughly equivalent to 987.5 million miles or 1.58 billion kilometers.
The time it takes for a planet to orbit the Sun is called its orbital period. The formula for calculating the orbital period of a world is:
T = 2π * √(a^3 / G(M_s)), where T is the orbital period, a is the semi-major axis, G is the gravitational constant, and M_s is the mass of the Sun.
Since the mass of the Sun is known, we can use the formula to calculate the orbital period of the new planet:
T = 2π * √(10.5^3 / (4π^2)) ≈ 30.2 Earth years
So, it will take approximately 30.2 Earth years for the new planet to orbit the Sun once.
Average formula is...?
Answer:
total sum of all numbers/ number of items in the set
Explanation: