A 21-tooth pinion rotating at 1500 rpm meshes with a 35- tooth gear in a sour gear reducer. Both pinion and cear are manufactured to a quality level of 9. A reliability of 0.9 hasbeen specified and the transmitted tangential load is 10 kN.Conditions are such that Ay = 1.7. It is proposed that standard 25 tull-depth teeth be used, with both pinion and gear hobbed from an AISI 4140 nitnided steel. The module is 4 and the face width 50 mm. Assume that the life of the oinion will be less than that of the gear. Assume the lubricant bulk temperature does not exceed 250°F, both driver and driven devices are smcom-running. gears are sold disc. Use the averace value for the uncorrected bendina-fatigno strength. Assume that the reducer is used for critical serviceapplicationsCalculate the bending stress

The element present in the fluorescent light is mercury. To determine which gas is present, you can conduct a gas test.

The element present in a fluorescent light is mercury. When electricity is passed through the mercury vapor, it produces ultraviolet light that causes the phosphor coating inside the bulb to glow, creating visible light.

To determine which gas is present, you can analyze the emission spectrum of the light and compare it to known spectra of various gases. As for the gases present in air, they mainly include nitrogen (78%), oxygen (21%), and trace amounts of other gases like argon, carbon dioxide, and neon.

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Large hydroelectric dams have significant environmental consequences for areas nearby.

Therefore, Making decisions about the development of hydroelectric dams requires balancing the environmental costs against the advantages of clean, renewable electricity.

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The correct answer is (D) it will boil only.

If we slowly pump out all the air over a bowl of water until it is in a vacuum, the water will boil. This is because the boiling point of water is directly related to the pressure of the surrounding atmosphere.

At standard atmospheric pressure (1 atm), the boiling point of water is 100 degrees Celsius. As the pressure decreases, the boiling point also decreases. When the pressure is reduced to a very low level, the boiling point can become so low that the water will boil at room temperature.

When the air is pumped out of the bowl of water, the pressure above the water decreases, which reduces the boiling point of the water. Eventually, the boiling point will reach room temperature, and the water will begin to boil. However, as the water boils, it will also evaporate and the temperature of the remaining water will decrease. This is because the process of evaporation removes heat from the water, causing it to cool. If the pressure is reduced even further, the boiling point of the water will drop even lower, and the water will eventually freeze. However, it is unlikely that a vacuum pump would be able to reduce the pressure enough to cause the water to freeze before it boils. Therefore, the correct answer is (D) it will boil only.

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Answer:

R and I will also change, but V will remain constant.

Explanation:

The current magnitude in each of the three branches of the circuit below are 1.25 A, 0.924 A and 0.31 A respectively

According to Ohm's law,

V = I R

V = Voltage

I = Current

R = Resistance

In loop 1,

33 I1  + 76 ( I1 - I2 ) - 48 + 20 ( I1 - I2 ) = 22

129 I1 - 96 I2 = 70  → ( 1 )

In loop 2,

76 ( I1 - I2 ) + 51 I1 + 8.5 + 42 I2 + 20 ( I1 - I2 ) = 0

- 96 I1 + 189 I2 = 56.5  

I1 = ( 189 I2 - 56.5 ) / 96  → ( 2 )

Sub ( 2 ) in ( 1 ),

129 ( 189 I2 - 56.5 ) / 96 - 96 I2 = 70

( 24381 I2 - 7288.5 ) / 96 = 96 I2 + 70

24381 I2 - 7288.5 = 9216 I2 + 6720

15165 I2 = 14008.5

I2 = 0.924 A

I1 = ( 189 * 0.924 - 56.5 ) / 96

I1 = 1.25 A

I3 = I1 - I2

I3 = 1.25 - 0.924

I3 = 0.31 A

Therefore, the current magnitude in each of the three branches of the circuit below are:

The given question is incomplete. The complete question is:

Determine the current magnitude and direction of flow in each of the three branches of the circuit below. The circuit is shown in the image attached.

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Balloon A is positively charged, and balloon C is negatively charged. If balloon A approaches balloon C, there will be an electrostatic force of attraction between them.

When two objects carry opposite charges, they exert an attractive force on each other. This force is known as the electrostatic force and follows Coulomb's law. According to Coulomb's law, the magnitude of the electrostatic force between two charged objects is directly proportional to the product of their charges and inversely proportional to the square of the distance between them. In this scenario, since balloon A is positively charged and balloon C is negatively charged, they have opposite charges. Therefore, the electrostatic force between them will be attractive. The magnitude of the force depends on the charges of the balloons and the distance between them. It is important to note that without specific information about the charges of the balloons and their distance, it is not possible to determine the exact magnitude of the force. To calculate the force, you would need the values of the charges and the distance between the balloons.

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Answer:

Explanation:

Virtual images are always right side up while real images are always upside down. Therefore, the is a virtual image that is smaller than the original.

Answer:

B. At the exact bottom

Explanation:

This is because his acceleration is at its max, which means his speed is at a max. HOPE THIS HELPS!

Answer:

B, At the exact bottom

Explanation:

i got it right

Answer:

Explanation:

the directions may change

Or they will repel and become opposite sides

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Answer: \(CBr_4\) : carbon tetrabromide

Explanation:

\(CBr_4\) is a covalent compound because in this compound the sharing of electrons takes place between carbon and bromine. Both the elements are non-metals. Hence, it will form covalent bond.

The naming of covalent compound is given by:

1. The less electronegative element is written first.

2. The more electronegative element is written second. Then a suffix is added with it. The suffix added is '-ide'.

3. If atoms of an element is greater than 1, then prefixes are added which are 'mono' for 1 atom, 'di' for 2 atoms, 'tri' for 3 atoms and so on.

Hence, the correct name for \(CBr_4\) is carbon tetrabromide.

Answer:

Carbon tetrabromide ~ CBr4

Chlorine monofluoride~ ClF

Explanation:

EDGU 2021

Answer:

The change on the Celsius scale is 27.22 °C.

Explanation:

The conversion of Fahrenheit to Celsius is the following:

\(T = \frac{5}{9}(^{\circ} F - 32)\)

So, we need to convert T₁ and T₂ from °F to °C:

\(T_{1} = \frac{5}{9}(^{\circ} F - 32) = \frac{5}{9}(- 4 - 32) = -20 ^{\circ} C\)

\(T_{2} = \frac{5}{9}(^{\circ} F - 32) = \frac{5}{9}(45 - 32) = 7.22 ^{\circ} C\)

Hence, the change on the Celsius scale is:

\( \Delta T = T_{2} - T_{1} = 7.22 - (-20) = 27.22 ^{\circ} C \)

Therefore, the change on the Celsius scale is 27.22 °C.

I hope it helps you!

The composition of a star is determined from the red or blue shift of spectral lines in a spectrum, the width of the spectral lines in the spectrum.

The study of light and other radiation absorption and emission by matter is called spectroscopy. Electromagnetic radiation into its constituent wavelengths, in a spectrum, just like a prism splits light into a rainbow of colors.

The composition of a star is determined from the red or blue shift of spectral lines in a spectrum, the width of the spectral lines in the spectrum.

Hence, option D is correct.

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Answer:

This is because a thermometer is designed to measure the temperature of a substance.

Explanation:

A thermometer is a device which is used to measure the temperature of a body which is known as the measure of the degree of the hotness or coldness of a body.

Temperature is measured in degree Celsius or Kelvin and it is entirely different from thermal energy which is measured in Joules.

The materials of thermometer that are designed to measure temperature only. Therefore, it is not possible to measure thermal energy.

Thermal Energy of a system is defined as the total kinetic energy possessed by the system. And temperature of a system is termed as the measure of average of kinetic energy of particles within the system.

Temperature is generally measured by Thermometers. And it is not possible to measure thermal energy due to following reasons:

Thus, thermometers are only used for the purpose of measuring temperatures, rather than thermal energy due to its design specifications.

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Explanation:

Density=mass/volume

density= 3.5 g ÷ 5.5cm

density=0.63

If the observed variation in flux is due to a variation in the intrinsic luminosity of the quasar, what was the variation timescale at the time the light was emitted will be found and Rmax is equals to 1.3*10^15 cm.

In particle physics experiments the energy available for the production of new effects is the most important parameter. The required large centre of mass energy can only be provided with colliding beams where little or no energy is lost in the motion of the centre of mass system (cms).

Besides the energy the number of useful interactions (events), is important. This is especially true when rare events with a small production cross section σp are studied.

The quantity that measures the ability of a particle accelerator to produce the required number of interactions is called the luminosity and is the proportionality factor between the number of events per second dR/dt and the cross section σp.

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A hydrogen atom is in its ground state (nᵢ = 1) when a photon impinges upon it. The atom absorbs the photon, which has precisely the energy required to raise the atom to the nf = 3 state. (a) The photon's energy that was absorbed is approximately 1.51 eV (negative sign indicates absorption).(b)option B and C are correct.

To determine the photon's energy and the energies of photons that might be emitted when the hydrogen atom returns to the ground state, we can use the energy level formula for hydrogen atoms:

E = -13.6 eV / n^2

where E is the energy of the electron in the atom, and n is the principal quantum number.

(a) To find the energy of the photon that was absorbed by the hydrogen atom to raise it from the ground state (nᵢ = 1) to the nf = 3 state, we need to calculate the energy difference between the two states:

ΔE = Ef - Ei = (-13.6 eV / 3^2) - (-13.6 eV / 1^2)

Calculating the value of ΔE:

ΔE = -13.6 eV / 9 + 13.6 eV

= -1.51 eV

Therefore, the photon's energy that was absorbed is approximately 1.51 eV (negative sign indicates absorption).

(b) When the hydrogen atom returns to the ground state, it can emit photons with energies corresponding to the energy differences between the excited states and the ground state. We need to calculate these energy differences and check which values are present among the given options.

ΔE1 = (-13.6 eV / 1^2) - (-13.6 eV / 3^2) = 10.20 eV

ΔE2 = (-13.6 eV / 1^2) - (-13.6 eV / 4^2) = 10.20 eV

ΔE3 = (-13.6 eV / 1^2) - (-13.6 eV / 5^2) = 12.10 eV

ΔE4 = (-13.6 eV / 1^2) - (-13.6 eV / 6^2) = 12.10 eV

ΔE5 = (-13.6 eV / 1^2) - (-13.6 eV / 7^2) = 13.55 eV

ΔE6 = (-13.6 eV / 1^2) - (-13.6 eV / 8^2) = 13.55 eV

ΔE7 = (-13.6 eV / 1^2) - (-13.6 eV / 9^2) = 13.55 eV

Comparing the calculated energy differences with the given options:

(A) 1.89 eV: This energy difference does not match any of the calculated values.

(B) 12.1 eV: This energy difference matches ΔE3 and ΔE4.

(C) 10.2 eV: This energy difference matches ΔE1 and ΔE2.

(D) 13.6 eV: This energy difference does not match any of the calculated values.

Therefore option B and C are correct.

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Work by gravity plus work by water equals 0 or 2692 = F *1.10 or F = 2447 Newtons

As work-energy, you could:

Since she began and concluded at rest, her initial and final K are both zero. Total work = ΔK.

Gravity: force * distance

mgΔh = 67 * 9.8 * 4.10 = 2692 Joules.

Force * Dist =- F *1.10

Work by gravity + work by water  =  0

2692 - F *1.10   = 0  

2692  =  F *1.10    

F = 2447 Newtons!

Because gravity continues to affect her even when she is submerged, take note of the total distance she travels: 3.00 + 1.10!

Work now being done by the water: Because of the force pushing up on her as she descends, the equation  is negative. Work is negative when the directions of force and distance are in opposition.

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It is true that because of stellar nucleosynthesis, the spectra of old stars show more heavy elements than those of young stars.

The process by which stars create and synthesize new elements through nuclear processes inside their cores is known as stellar nucleosynthesis.

Stars go through a variety of nuclear fusion processes that produce heavier elements as they grow older and go through different stages of their life cycles.

In the course of stellar evolution, stars can undergo nuclear events that result in the production of elements up to iron in their cores, such as the burning of hydrogen and helium.

As a result, while studying the spectra of elderly stars, we frequently discover that heavy metals are more abundant than in the spectra of young stars.

The older stars have had more time to go through nucleosynthesis processes and build up heavier elements in their atmospheres, which is why this is the case.

Thus, the given statement is true.

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Your question seems incomplete, the probable complete question is:

State true or false. because of stellar nucleosynthesis, the spectra of old stars show more heavy elements than those of young stars.

Answer:

\(0.00074m\) \(=\) \(7.4*10^{-4}m\)

Explanation:

Given

\(0.00074m\)

Required

Express as scientific notation

The scientific notation of a number is: \(a * 10^{b}\)

Where \(1 \le a \le 9\)

This implies that:

\(0.00074m = 7.4 * 10^b\)

Next, is to determine the value of b.

Count the number of point to move from the current point location to 7.4.

If the point moves backward, b will be negative, else b will be positive.

So:

\(0.00074m\)      \(b=-4\)

Hence:

\(0.00074m\) \(=\) \(7.4*10^{-4}m\)

Answer:

The answer is A) 247 J, which is the closest to the calculated value.

Explanation:

To calculate the work done on the bag, we need to use the formula:

work = force x distance x cos(theta)

where force is the weight of the bag (mg), distance is the length of the room, and theta is the angle between the force and the displacement (which is zero since the force and displacement are in the same direction).

First, let's calculate the force:

force = weight of the bag = mg = (6.00 kg) x (9.81 m/s^2) = 58.86 N

Next, let's calculate the distance:

distance = length of the room = 4.220 m

Now, we can calculate the work done:

work = (58.86 N) x (4.220 m) x cos(0) = 247.68 J

Where Vp is the primary voltage, Vs is the secondary voltage, Np is the number of loops in the primary coil, and Ns is the number of loops in the secondary coil.

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(a) The maximum stress at a point on the inside of the transverse hole in a solid shaft of diameter 2.5-in with a 0.5-in diameter hole and 60 kip-in torque is 18.25 ksi, using Table A-16.

(b) The maximum stress in a hollow shaft of an outside diameter 2.5-in and inside diameter 1.5-in with a 0.5-in diameter hole and 60 kip-in torque is 16.19 ksi, using the formula for maximum shear stress in a hollow shaft.

a) Let's assume that the shear stress distribution over the cross-section of the shaft is linear. Therefore, the maximum shear stress will occur at the surface of the hole.

The torque on the shaft is given by:

T = 60 kip.in

The polar moment of inertia of the shaft is:

J = π/32 (\(D^4 - d^4\)) = π/32 ((\(2.5)^4\) - (\(0.5)^4\)) = 3.505 \(in^4\)

where D is the diameter of the shaft and d is the diameter of the hole.

The maximum shear stress τmax is given by:

τmax = Tc / J

where c is the shaft radius, c = D/2.

τmax = (60 kip.in) (1.25 in) / (3.505 \(in^4\)) = 21.4 ksi

Using Table A-16, we can see that the maximum allowable shear stress for a shaft made of cold-drawn steel is 30 ksi. Therefore, the stress is within the allowable limit.

(b)Now, let's consider a hollow shaft with an outer diameter of 2.5 in and an inner diameter of 1.5 in. The polar moment of inertia of the hollow shaft is:

J = π/32 (\(D^4 - d^4\)) = π/32 \(((2.5)^4 - (1.5)^4) = 1.376 in^4\)

The maximum shear stress τmax is given by:

τmax = Tc / J

where c is the radius of the shaft, c = (D + d)/4 = 1.5 in

τmax = (60 kip.in) (1.5 in) / (\(1.376 in^4\)) = 65.5 ksi

Using Table A-16, we can see that the maximum allowable shear stress for a shaft made of cold-drawn steel is 30 ksi.

Therefore, the stress is not within the allowable limit, and the design needs to be revised.

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Answer:

70mi/h

1mile =1609 meters

1hour=3600 seconds

So,

70×1609/3600

112,630/3600

31.286 m/s

Hope this helps you

To solve this problem, you can use the equations of motion for rotational motion under constant acceleration:

ωf = ωi + αt --(1)

θ = ωit + 0.5αt^2 --(2)

where ωi is the initial angular velocity, ωf is the final angular velocity, α is the angular acceleration, t is the time elapsed, and θ is the angular displacement.

Using equation (1), we can find the angular acceleration of the wheel:

α = (ωf - ωi)/t

= (30.0 rad/s - 10.0 rad/s)/20.0 s

= 1.0 rad/s^2

Using equation (2), we can find the total angular displacement of the wheel during the 20.0 seconds:

θ = ωit + 0.5αt^2

= 10.0 rad/s × 20.0 s + 0.5 × 1.0 rad/s^2 × (20.0 s)^2

= 400.0 rad

To find the time at which the wheel has undergone half of this angular displacement, we can use equation (2) again:

θ/2 = ωit + 0.5αt^2

Rearranging and solving for t, we get:

t = [(-ωi) ± sqrt(ωi^2 + 2αθ)]/α

Since we are looking for a positive time, we take the positive root:

t = [(-10.0 rad/s) ± sqrt((10.0 rad/s)^2 + 2 × 1.0 rad/s^2 × 400.0 rad)]/1.0 rad/s^2

≈ 12.4 s

Therefore, the answer is B, 12.4 s.

Answer:

a = 7.35 ft / s²

Explanation:

For this exercise we must use the kinematics relations

        x = v₀ t + ½ a t²

as the runner leaves the starting line his initial velocity is zero

        x = ½ a t²

        a = \(\frac{2x}{t^2}\)

let's reduce the distance to foot

        x = 60 yd (3ft / 1yd) = 180 ft

let's calculate

         a = 2 180 / 7²

         a = 7.35 ft / s²

The maximum weight limit for light-duty ladders depends on the specific ladder and its manufacturer's specifications. However, as a general guideline, light-duty ladders usually have a maximum weight limit of around 200 pounds.

It's important to note that exceeding the maximum weight limit of a ladder can be dangerous and may result in accidents or injuries. When using a ladder, it's essential to read and follow the manufacturer's guidelines and weight limits to ensure safe and proper use.

If the user's weight or the weight of the materials being carried exceeds the ladder's maximum weight limit, a heavier-duty ladder should be used instead.

In summary, the maximum weight limit for light-duty ladders is typically around 200 pounds, but it's important to check the manufacturer's specifications for the specific ladder being used.

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When an engineering team reaches the stage of iterating to improve the solution in the engineering design process, there are various activities that the team might be doing. One of the most crucial activities at this stage of the design process is testing. Here are a few things that an engineering team might do to test and improve the solution:

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