(a) The magnitude of the net gravitational force exerted on the 33.0-kg object is 4.53 x 10^-7 N.
(b) The equilibrium point is 1.89 m from the 530-kg object, toward the 230-kg object.
(a) The magnitude of the net gravitational force exerted by the 230-kg and 530-kg objects on the 33.0-kg object is given by:
F = G(m1m3/r13^2) + G(m2m3/r23^2)
where G is the gravitational constant, m1 and m2 are the masses of the two objects, m3 is the mass of the 33.0-kg object, r13 is the distance between the 230-kg object and the 33.0-kg object, and r23 is the distance between the 530-kg object and the 33.0-kg object.
Plugging in the given values and solving for F, we get:
F = (6.67 x 10^-11 N(m/kg)^2)(230 kg)(33.0 kg)/(2.20 m)^2 + (6.67 x 10^-11 N(m/kg)^2)(530 kg)(33.0 kg)/(2.20 m)^2
F = 1.37 x 10^-7 N + 3.16 x 10^-7 N
F = 4.53 x 10^-7 N
Therefore, the magnitude of the net gravitational force exerted on the 33.0-kg object is 4.53 x 10^-7 N.
(b) To find the position where the net force on the 33.0-kg object is zero, we can use the concept of gravitational equilibrium. At this point, the gravitational forces from the two larger objects will cancel out, resulting in zero net force on the 33.0-kg object.
Let x be the distance from the 530-kg object to the equilibrium point. Then, the distance from the 230-kg object to the equilibrium point is 4.40 m - x.
Setting the gravitational forces from the two larger objects equal to each other, we have:
G(m1m3/(4.40 - x)^2) = G(m2m3/x^2)
Simplifying and solving for x, we get:
x = 1.89 m
Therefore, the equilibrium point is 1.89 m from the 530-kg object, toward the 230-kg object.
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at a distance of 15.0 m from a sound source, the intensity level is 60.0 db. what is the intensity level (in decibels) at a point 2.00 m from the source if the source radiates equally in all directions?
The inverse square law states that the intensity of sound decreases with the square of the distance from the source. We can use this law to determine the change in intensity level at the new distance. at a point 2.00 m from the source, the intensity level would be approximately 45.7 dB.
The formula to calculate the change in intensity level is given by:
\(ΔL = 20 * log10(d2/d1)\)
where ΔL is the change in intensity level, d1 is the initial distance, and d2 is the final distance.
Given that the initial distance (d1) is 15.0 m, the final distance (d2) is 2.00 m, and the initial intensity level is 60.0 dB, we can calculate the change in intensity level as follows:
ΔL = 20 * log10(2.00/15.0)
ΔL ≈ 20 * log10(0.1333)
ΔL ≈ -14.3 dB
To find the new intensity level, we add the change in intensity level to the initial intensity level:
New intensity level = Initial intensity level + ΔL
New intensity level = 60.0 dB + (-14.3 dB)
New intensity level ≈ 45.7 dB
Therefore, at a point 2.00 m from the source, the intensity level would be approximately 45.7 dB.
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A cylindrical container is filled with oil to a depth of 32cm. If the pressure exerted at the base of the container is known to be 2560pa then, how much is the density of the oil?
Answer:
Ro = 815.5 [kg/m³]
Explanation:
We must use the following equation to find the hydrostatic pressure exerted on the bottom of the cylinder.
\(P=Ro*g*h\)
where:
P = pressure = 2560 [Pa]
Ro = density [kg/m³]
g = gravity acceleration = 9.81 [m/s²]
h = elevation = 32 [cm] = 0.32 [m]
\(2560=Ro*9.81*0.32\\Ro=815.5 [kg/m^{3} ]\)
Answer:
800kg/m^3
Explanation:
roh=2560/0.32m×10m/s^2
800kg/m^3
Change 32 cm to m to make it more easier.
Gravitational acceleration is 10m/s^2.
HOPE THAT I HELPED YOU!
Convert 5 (mi/hr) to [m/s]
Answer:
2.2352 m/s
Explanation:
divide the number of meter in a mile by the number of second in an hour
From laboratory measurements, we know that a particular spectral line formed by hydrogen appears at a wavelength of 121.6 nanometers (nm). The spectrum of a particular star shows the same hydrogen line appearing at a wavelength of 121.8 nm. What is the receding speed of the star? c = 3x10^5 km/s
Answer:
\(v=-4.93\times 10^{5}~m/s\) [negative sign denotes that it is moving away]
Explanation:
Actual wavelength of hydrogen spectral lines, \(\lambda=121.6~nm\)
Apparent wavelength of hydrogen spectral lines from a star, \(\lambda'=121.8~nm\)
So, shift in wavelength:
\(\Delta \lambda=\lambda'-\lambda\)
\(\Delta \lambda=121.8-121.6\)
\(\Delta \lambda=0.2~nm\)
Using Doppler's shift:
\(\frac{\Delta \lambda}{\lambda} =-\frac{v}{c}\)
\(\frac{0.2}{121.6} =-\frac{v}{3\times 10^8}\)
\(v=-4.93\times 10^{5}~m/s\) [negative sign denotes that it is moving away]
two cars, one of mass 1500 kg, and the second of mass 2400 kg, are moving at right angles to each other when they collide and stick together. the initial velocity of the first car is 11 m/s in the positive x direction and that of the second car is 20 m/s in the positive y direction. what is the magnitude of the velocity of the wreckage of the two cars immediately after the collision?
The magnitude of the velocity of the wreckage of the two cars immediately after the collision is 10 m/s.
Conservation of Linear MomentumGiven Data
Mass M1 = 1500 kgMass M2 = 2400 kgInitial Velocity V1 = 11 m/sinitial Velocity V1 = 20 m/sfinal Velocity V3 = ??Using the law of conservation of momentum:
m1 * v1 + m2 * v2 = (m1 + m2) * v3Substituting our given data into the expression we have
(1500 kg * 11 m/s) + (2400 kg * 20 m/s) = (3900 kg) * v339000 kg * m/s = 3900 kg * v3v3 = 10 m/sBy definition, linear momentum is the result of an object's mass and velocity. The whole momentum is conserved in closed systems. This implies that the total amount of moments prior to and following a collision are identical. A fundamental principle of physics, conservation of linear momentum is used to the study of object interactions such as collisions, explosions, and other interactions.
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a hammer taps on the end of a 5.0-m-long metal bar at room temperature. a microphone at the other end of the bar picks up two pulses of sound, one that travels through the metal and one that travels through the air. the pulses are separated in time by 8.20 ms .
We can substitute the given values into the equation to find the speed of sound in the metal bar. Just plug in L = 5.0 m, Δt = 8.20 × \(10^{-3\) s, and the speed of sound in air (v_air).
To solve this problem, we can use the fact that the speed of sound in air and in the metal bar are different.
Let's denote the speed of sound in air as v_air and the speed of sound in the metal bar as v_metal.
- Length of the metal bar (L) = 5.0 m
- Time difference between the two pulses (Δt) = 8.20 ms = 8.20 × \(10^{-3\) s
We know that the time it takes for the sound to travel through the air can be calculated using the formula: Δt_air = L/v_air. Similarly, the time it takes for the sound to travel through the metal bar can be calculated using: Δt_metal = L/v_metal.
We are given the time difference between the two pulses, Δt = Δt_metal - Δt_air. Substituting the values, we get: Δt = L/v_metal - L/v_air.
We can solve this equation for v_metal by rearranging the terms: v_metal = L / (Δt + L/v_air).
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A Body is said to be in equilibrium when its:-
a) Acceleration is uniform
b) Speed is uniform
c) Speed and acceleration are uniform
d) Speed is uniform
I need the right answer. Please quick
Answer:
speed i uniform
Explanation:
if the speed is constant
Answer:
A
Explanation:
if it has a constant acceleration
a ball is swung in a vertical circle such that at one point along its circular path the forces exerted on the ball can be represented by the free body diagram. the magnitude of the tension force exerted on the ball, t, is twice that of the force due to gravity exerted on the ball from earth, fg. what is the location of the ball, and what is the magnitude of the centripetal acceleration of the ball?
Location of the ball is top of the circle and acceleration is 3g.
Since tension force is more, surely ball is having net force upward and hence, the location of the ball in this case is top of the circle.
Any object that moves in a circle has an acceleration vector towards the center of that circle. This is known as Centripetal acceleration.
total force/ net force when ball is top of the circle is sum of tension force and gravity force.
\(F_{net\) = T + mg
Because of this net force, there is centripetal acceleration towards the center.
so, T + mg = ma
2mg + mg = ma
3mg = ma
a = 3 × force of gravity
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6) a metal sphere in free space has a radius of a. a total charge q is placed on the sphere. assume that the resulting surface charge density is distributed uniformly on the surface of the sphere. solve for the electric field vector at the surface of the sphere (just outside the sphere), by using only knowledge of boundary conditions. (note that there is no electric field inside the sphere, due to the faraday cage effect.)
The electric field vector at the surface of the metal sphere (just outside the sphere) is E = q / (4πa²ε₀) in the radial direction away from the center of the sphere.
To determine the electric field vector at the surface of a metal sphere with radius 'a' and a total charge 'q' distributed uniformly on the surface, we will consider the boundary conditions and the fact that there is no electric field inside the sphere (due to the Faraday cage effect).
Step 1: Begin with Gauss's law for electric fields, which states that the electric flux through a closed surface is equal to the enclosed charge divided by the permittivity of free space (ε₀):
Φ = ∮E • dA = Q_enclosed / ε₀
Step 2: Consider a Gaussian surface just outside the metal sphere, such as a slightly larger sphere with radius (a + Δa), where Δa is very small. Since the charge is uniformly distributed, we can treat the electric field E as constant on this Gaussian surface.
Step 3: Calculate the enclosed charge within the Gaussian surface. In this case, it is equal to the total charge on the metal sphere, which is 'q'.
Step 4: Calculate the area of the Gaussian surface, A = 4π(a + Δa)² ≈ 4πa², since Δa is very small.
Step 5: Plug the values into Gauss's law:
E ∮dA = q / ε₀
E(4πa²) = q / ε₀
Step 6: Solve for the electric field E:
E = q / (4πa²ε₀)
So, the electric field vector at the surface is E = q / (4πa²ε₀) in the radial direction away from the center of the sphere.
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What causes melting of the mantle beneath Reunion?
addition of volatites
a decrease in pressure
an increase in pressure
heat transfer
The melting of the mantle beneath Reunion, an island located in the Indian Ocean, is primarily caused by heat transfer. The mantle is a layer of the Earth located between the crust and the core.
Reunion Island is situated above a hotspot, which is an area where a plume of hot material rises from deep within the Earth's mantle. As this plume ascends, it transfers heat to the surrounding mantle rocks, causing them to reach temperatures that are sufficient for melting to occur. The melting of the mantle generates magma, which eventually rises to the surface, forming volcanic activity on Reunion Island.
While heat transfer is the main driver of mantle melting beneath Reunion, other factors such as the addition of volatiles (gases and fluids) and changes in pressure can also play a role. The introduction of volatiles can lower the melting temperature of rocks, making them more prone to melting. However, the exact role of volatiles in the melting process beneath Reunion is not as significant as heat transfer.
Pressure changes can also influence melting, but in the case of Reunion, the effect is minimal. Melting occurs more readily as pressure decreases, which is why some melting is observed at shallower depths in the mantle. However, the pressure changes in the mantle beneath Reunion are not substantial enough to be the primary cause of melting.
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Is DNA the nucleic acid that carries genetic information?
Deoxyribonucleic acid (DNA) is the nucleic acid that carries genetic information in the human body.
Deoxyribonucleic acid or DNA is the molecule that carries the genetic information for the development and functioning of an organism in the human body. DNA is made of two connected strands that wind around each other to resemble a twisted ladder -a shape referred to as a double helix. Thus, DNA is the nucleic acid that performs the function of carrying genetic information that is to be transferred from one generation to the next generation.
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a 1800 kg sports car accelerates from rest to 32.0 m/s in 5.20 s. what is the average power output of the automobile engine?
The average horsepower of today's vehicles, when taken into account for each new model, ranges from 200 to 250.
What is a motor's maximum power?The ratio of a motor's speed to torque determines its power. The speed that produces the most power is around halfway between the loaded speed. No torque at highest speed. and the stagnant condition. highest torque with no speed. The power output in watt is about equal to 9.57 x (torque) x (rpm).We are given : mass of sports car, m = 1000 kg. car accelerates from rest to final speed v = 95 km/h = 95×518 =26.39 m/s.
What is the engine's specific power?One way to gauge an engine's performance in a car or power plant is by looking at its power rating or power-to-weight ratio. Its definition is its output of power divided only by mass, usually expressed in units as W/kg or hp/lb.
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The PV system is operating in a location where the annual average daily incident solar energy (the insolation) on the array equals 200 kWh/m2/day. Calculate the average amount of solar energy incident on the PV array each day in kWh/day.
The average amount of solar energy incident on the PV per day is 10000 kWh/day.
Equation
An equation is an expression that shows the relationship between two or more numbers and variables.
Let the PV array has an area equal to 50 square meters. Hence:
Average amount of solar energy incident on the PV per day = 200 kWh/m²/day * 50 m² = 10000 kWh/day.
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A student fires a cannonball vertically upwards with a speed of 22.0m/s from a height of 40.0m. On the descent, the cannonball misses the building and lands on the ground. Determine all unknowns and answer the following questions. Neglect drag and horizontal motion of the cannonball.What was the cannonball's maximum height (measured from the ground)? With what speed did the cannonball strike the ground? What was the cannonball's total flight time?
We are given that an object is launched with an initial height and we are asked to determine its maximum height. To do that we will determine first the time it takes the object to reach the maximum height which is given by the following formula:
\(t=\sqrt[]{\frac{2v_0}{g}}\)Where:
\(\begin{gathered} t=\text{ time for maximum height} \\ v_0=\text{ initial velocity} \\ g=\text{ acceleration of gravity} \end{gathered}\)Replacing the values we get:
\(t=\sqrt[]{\frac{2(22\frac{m}{s})}{9.8\frac{m}{s^2}}}\)Solving the operations we get:
\(t=2.12s\)Now, to determine the height associated with this time we will use the following formula:
\(h=h_0+v_0t-\frac{1}{2}gt^2\)Where:
\(h_0=\text{ initial height}\)In this case, the initial height is 40 meters. Replacing the known values:
\(h=40m+(22\frac{m}{s})(2.12s)-\frac{1}{2}(9.8\frac{m}{s^2})(2.12s)^2\)Solving the operations:
\(h=64.61m\)Therefore, the maximum height the ball reaches measured from the ground is 64.61 meters.
Now we are asked to determine the final velocity of the object. To do that, we will use the following formula:
\(2gh=v^2_f-v^2_0\)Where:
\(\begin{gathered} h=\text{ }initial\text{ height} \\ v_f=\text{ final velocity} \end{gathered}\)Now we solve for the final velocity first by adding the square of the initial velocity:
\(2gh+v^2_0=v^2_f\)Now we take the square root to both sides:
\(\sqrt{2gh+v^2_0}=v^{}_f\)Replacing the known values:
\(\sqrt[]{2(9.8\frac{m}{s^2})(40m)+(22\frac{m}{s})^2}=v_f\)Solving the operations:
\(35.6\frac{m}{s}=v_f\)Therefore, the final velocity is 35.6 meters per second directed towards the ground.
Now we are required to determine the time the object stays in the air. To do that we will use the following formula:
\(v_f=v_0-gt\)We will solve for "t" first by subtracting the initial velocity from both sides:
\(v_f-v_0=-gt\)Now we divide both sides by the acceleration of gravity with the negative sign:
\(\frac{v_f-v_0}{-g}=t\)Now we replace the values, but we need to have into account that since the final velocity is directed towards the ground its sign is negative:
\(\frac{-35.6\frac{m}{s}-22\frac{m}{s}}{-9.8\frac{m}{s}}=t\)Solving the operations:
\(5.87s=t\)Therefore, the cannonball's total time is 5.87 seconds.
I honestly don't know how to answer the last part of this question, it makes no sense to me:
A SR-71 reconnaissance aircraft, the world's fastest aircraft, is flying east at 3000 km/h. If the plane encounters a cross-wind of 300 km/h that is directed to the north,what is the magnitude and direction of its resultant velocity? If the border is a straight north/southline, will it take more, less or the same time to reach the eastern border of the country with the cross wind vs. without the crosswind? Explain
The resultant velocity of the aircraft is 3015 Km/hr while the direction is 5.7 degrees North of east
What is the resultant velocity?The resultant vector is that vector that has the same effect is magnitude and direction as the two vectors acting together. Recall that velocity is a vector quantity. This implies that the magnitude and the direction of the velocity is very important.
The resultant velocity would now be obtained by considering the directions of the two velocities hence we have to work geometrically and not algebraically. We have to know that the plane is flying east at 3000 km/h. If the plane encounters a cross-wind of 300 km/h that is directed to the north
Thus the resultant velocity is;
R = √(3000)^2 + (300)^2
R = √9 * 10^6 + 9 * 10^4
R = 3015 Km/hr
The direction of this resultant velocity is;
Tan-1 (300/3000)
= 5.7 degrees North of east
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1.Convert 340 cm into m *(answer=0.34m)
2.What is the weight of potatoes of mass 75kg on the surface of the earth? *(ans=735 N)
[g=9.8 m/s^2
[g=9.8 m/s^2]
3.The weight of body is 420 N.Calculate its mass. *(42.857 kg)*
Answers are all given so i just need the process please (i will mark you brainliest please..
Answer:
1.for the first one 100centimeters make 1 meter therefore
100cm-1m
340cm-x
340/100
=3.4
the answer is supposed to be 3.4, maybe there's a mistake with the question or the answer
2.the weight of a body is given by the formula
mass×gravity,in this case the mass is 75kg and the gravity is 9.8
weight=75×9.8
=735N
3.for this one the mass of a body is given by the formula
mass=weight/gravity
=420/9.8
=42.8kg
I hope this helps
Sketch curves representing the variation of the molar Gibbs free energy with temperature at the pressure corresponding to a triple point for an element. Repeat this sketch for a pressure slightly above and slightly below the triple point. Also draw the curves at 100 atm and compare.
J .Willard Gibbs created a new function that is now known as the Gibbs potential or Gibbs energy change (G). Pressure and temperature fluctuations have no effect on this function.
The Gibbs energy change of a system depends only on its current state, not on how it got there.
At constant pressure and temperature, a thermodynamic system can perform its maximum (or reversible) amount of work, which is referred to as Gibbs energy. In terms of thermodynamics, reversible work refers to a unique technique that ensures the system is in complete equilibrium with its surroundings.If both the extensive properties (U, G, and A) and the intensive properties (temperature and pressure) are constant, a thermodynamic system is said to be in equilibrium. Or there is no change overall in any of the properties. According to the following equation, the system is said to be at equilibrium if the reaction is reversible and the Gibbs free energy is zero.
A + B ⇄ C + D
ΔrG = 0
It is also known as the Gibbs energy for a reaction in its standard state.
0 = ΔrG + RT in K
ΔrG = - RT in K
or
ΔrG = - 2.303RT in K
ΔrG = ΔrH - TΔrS = - RT in K
For endothermic reactions, the value of ΔrH should be high and positive; if K is less than 1, little of the product is expected to form. The value of ΔrH is big and negative in the case of an exothermic reaction, and even the value of ΔrG is likely to be large and negative. When this occurs, the value of K will be significantly more than 1. Strong exothermic processes will supposedly have a higher value of K. Kilo Joule, which is frequently denoted as kJ/mol, is the unit used to measure Gibbs free energy.
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In a parallel circuit with a single power source, The current that leaves and reenters the power source is called _____?
Answer:
total current
Explanation:
In a parallel circuit, the current leaves the power source and then splits into multiple branches that have individual components. Each branch operates independently of the other branches, and the current flows through each component and then recombines and enters back into the power source.
Because each branch is independent, the current flowing in each branch can be different, depending on the resistance of the components in that branch. However, the total current entering the circuit is equal to the sum of the currents in each branch, as long as the circuit is properly wired.
So the total current that leaves and reenters the power source in a parallel circuit is equal to the sum of the currents in each branch, and this is known as the total or overall current of the circuit.
Two negative charges that are both
- 5.0 x 10 C push each other apart with a force of 15N. How far apart are the two charges?
Two negative charges that are both - 5.0 x 10⁵ C push each other apart with a force of 15N. Then, the distance between the two charges will be 1.22 meters.
What is Electrostatic force?The electrostatic force exists between two charges placed at a distance of some magnitudes. The magnitude of electrostatic force depends on the magnitude of each charge and also the distance between the two charges. When any two positive charges or two negative charges are brought together, then the two charges repel each other.
F = kq₁q₂/ r²
where, F is the electrostatic force,
k is Coulomb's constant, q₁ and q₂ are the two charges,
r is the distance between the two charges
F = 15 N,
K = 9 × 10⁹ Nm²C⁻²
q₁ and q₂ = -5.0 × 10⁵ C
F = kq₁q₂/ r²
r² = \(\sqrt{(kq1q2/ F)}\)
r = \(\sqrt{(9X10^9X-5X10^5X-5X10^5/ 15)}\)
r = √(225 × 10¹¹× 10¹⁰/ 15)
r = √(1.5× 10²⁰)
r = 1.22m
Therefore, the distance between the two charges will be 1.22 meters.
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An electron is currently in energy level 3. Which electron jump starting from energy level 3 would emit the lowest energy photon?
emit.jpeg
3 → 5
3 → 2
3 → 4
3 → 1
An electron jump refers to the transition of an electron between different energy levels in an atom. Energy levels represent the specific amounts of energy that an electron can have within an atom.
When an electron transitions from a higher energy level to a lower one, it emits a photon, which is a particle of light. In the given question, an electron is currently in energy level 3. To emit the lowest energy photon, the electron must make a jump to the closest lower energy level. Among the provided options, the electron jump from energy level 3 to energy level 2 (3 → 2) is the transition that would emit the lowest energy photon.
This is because the energy of a photon is directly proportional to the difference in energy levels between the initial and final states of the electron. A smaller difference in energy levels results in a lower energy photon being emitted. In this case, the transition from energy level 3 to energy level 2 has the smallest difference, resulting in the emission of the lowest energy photon.
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the best way to study warm (1000 k) young stars forming behind an interstellar dust cloud would be to use a. blue light b. ultraviolet light c. x-rays d. infrared light
The best way to study warm (1000 K) young stars forming behind an interstellar dust cloud would be to use infrared light. So option d is correct.
Interstellar dust clouds can block or scatter shorter-wavelength light, such as blue light and ultraviolet light, making it difficult to observe objects behind them. However, longer-wavelength infrared light can penetrate through the dust cloud with less scattering and absorption, allowing us to study the objects hidden behind the dust.
Infrared light is particularly effective for studying warm objects, as they emit most of their radiation in the infrared range. By using infrared telescopes and detectors, astronomers can observe the thermal radiation emitted by the young stars and study their formation and evolution processes.Therefore option d is correct.
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A slinky is traveling down the stairs, like in the video clip below. What is the total KINETIC ENERGY of the slinky at the bottom of the stairs (just before it stops moving) IF the Height of the stairs is 2 meters, the weight of the slinky is 4.41 Newtons, its spring constant is 0.84 N/m, and the distance the slinky is initially stretched (to get it going) is 0.25 meters??
Answer:
8.79 J
Explanation:
Given that a slinky is traveling down the stairs, like in the video clip below. What is the total KINETIC ENERGY of the slinky at the bottom of the stairs (just before it stops moving) IF the Height of the stairs is 2 meters, the weight of the slinky is 4.41 Newtons, its spring constant is 0.84 N/m, and the distance the slinky is initially stretched (to get it going) is 0.25 meters??
Total energy = mgh
Total energy = 4.41 × 2 = 8.82 J
Elastic potential energy = 1/2 × Ke^2
Elastic potential energy = 1/2 × 0.84 × 0.25^2
Elastic potential energy = 0.02625
Also,
Total energy = P.E + K.E
Substitute them into the formula above
8.82 = 0.02625 + K.E
K.E = 8.82 - 0.02625
K.E = 8.79375
K.E = 8.79 J
Therefore, the KINETIC ENERGY of the slinky at the bottom of the stairs is 8.79 Joules approximately
Hi, can you please help me?
What's the value of v
What is the displacement of the object when its initial position is 10 m and the final position -20 m?
Answer:
-30m
Explanation:
displacement = final position - initial position, or d = -20-10
How does the direction of acceleration change when the masses on an Atwood's machine are switched, and how can this be explained using Newton's laws of motion?
The acceleration of the system still depends only on the difference in mass between the two masses, but the direction of the net force has changed, so the direction of acceleration has also changed.
When the masses are different, the system accelerates in the direction of the heavier mass. According to Newton's second law, the net force acting on each mass is equal to its mass times its acceleration:
F1 = m1a
F2 = m2a
where F1 and F2 are the tensions in the rope on either side of the pulley. Since the rope is inextensible and the pulley is ideal, the tension in the rope is the same on both sides, so F1 = F2 = T, where T is the tension in the rope.
Substituting T for F1 and F2 in the above equations and subtracting the second equation from the first, we get:
m1a - m2a = T - T
(m1 - m2)a = 0
Since the tension cancels out, the acceleration of the system depends only on the difference in mass between the two masses.
If the masses are switched, then the direction of the net force changes, and the system accelerates in the direction of the new heavier mass. The net force acting on each mass is still given by the above equations, but the masses are switched, so m1 is now the smaller mass, and m2 is the larger mass.
Substituting T for F1 and F2 in the above equations and subtracting the first equation from the second, we get:
m2a - m1a = T - T
(m2 - m1)a = 0
Since the tension cancels out, the acceleration of the system still depends only on the difference in mass between the two masses.
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Please urgent science question explaining needed
Answer:
what is the question? there isn't one
An object appears red when viewed with white light. What color would it appear when viewed with blue light?
Answer:
Colour of any object is by the colour of light it reflects i.e if white light is incident on the object,it will reflect blue color.so it will appear blue.But if red light is incident on it,it will not reflect that and absorb it.so as it will not reflect any light it will appear black.
Explanation:
Interference patterns, a characteristic of waves, arise when X rays pass through a crystalline material like gold. What occurs when a beam of electrons passes through the same material
When a beam of electrons passes through the same material, the electrons bounce off the gold, proving the particle nature of electrons.
What are electrons?The electrons are the spinning objects around the nucleus of the atom of the element in an orbit.
Interference patterns which is a characteristic of waves, arise when X rays pass through a crystalline material like gold.
The X rays ionize the electrons and they jump off from the gold. This represents the particle nature of electrons.
Thus, when a beam of electrons passes through the same material, the electrons bounce off the gold, proving the particle nature of electrons.
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Which climate favors mechanical weathering?
Cold climate favors rapid mechanical weathering, since the cold seasons cause the rock to contract.
What is mechanical weathering and what climate they favour?Mechanical weathering, sometimes referred to as physical weathering and disaggregation, causes rocks to break down. Water, whether liquid or solid, is usually present during mechanical weathering. For instance, liquid water can seep through fractures and fissures in rock.
Cold climates promote mechanical weathering because they force rocks to contract and compress during the colder months. The rocks degrade and break at higher temperatures. Temperature fluctuations cause the expansion and contraction of rock (with cold). As this continues repeatedly, the structure of the rock deteriorates. It breaks down over time.
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a student placed 700g of water at 28C in a freezer. After 6 minutes and 15 seconds the water was transformed into ice. Calculate the latent heat of fusion given that 235200J of heat energy was transferred during the change of state
The latent heat of fusion is 335714.29 J/kg.
To calculate the latent heat of fusion, we can use the equation:
Q = m * L
Where:
Q = heat energy transferred
m = mass of the substance
L = latent heat of fusion
Given:
Mass of water (m) = 700 g = 0.7 kg
Heat energy transferred (Q) = 235200 J
To find the latent heat of fusion (L).
Since the water is being transformed into ice, we know that the heat energy transferred during this phase change is equal to the latent heat of fusion.
Rearrange the equation to solve for L:
L = Q / m
L = 235200 J / 0.7 kg
L ≈ 335714.29 J/kg
Therefore, the latent heat of fusion is approximately 335714.29 J/kg.
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i if a wheel 212 cm in diameter takes 2.25 s for each revolution, find its (a) period and (b) angular speed in rad/s.
(a) The period of a wheel can be found by dividing the time it takes for each revolution by the number of revolutions per period.
(b) The angular speed of the wheel in rad/s can be determined by dividing 2π (the full angle in radians) by the period.
(a) To find the period of the wheel, we divide the time it takes for each revolution (2.25 s) by the number of revolutions per period. Since the wheel completes one revolution per period, the period is equal to the time per revolution. Therefore, the period of the wheel is 2.25 s.
(b) The angular speed of the wheel can be calculated by dividing the full angle in radians (2π) by the period. Since the wheel completes one revolution per period, the angle traversed is 2π radians. Dividing 2π by the period of 2.25 s gives us the angular speed of the wheel in rad/s. Thus, the angular speed of the wheel is approximately 2.79 rad/s.
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