A 2650 kg truck traveling east at 39 km/h turns south and accelerates to 62 km/h A what is the magnitude of the trucks initial momentum?B what is the direction of the trucks initial momentum?C what is the magnitude of the trucks final momentum?D what is the direction of the truck final momentum?

Answer:

A plane mirror is placed to the right of an object. The image formed by the mirror will be a virtual image that appears to be on the left of the mirror.

Explanation:

The initial horizontal velocity of the football if a player kicks a football from ground level with a velocity of 27/ms at an angle of 30 degrees above the horizontal is 23.662 m/s.

To find the initial horizontal velocity (Vx) of the football, you can use the horizontal component of the velocity vector. The horizontal component of velocity is found by multiplying the velocity by the cosine of the angle of launch.

\(V_{x}\) = V × cos(angle)

where V is the initial velocity, the angle is the angle of launch (in this case, 30 degrees), and cos is the cosine function.

So, in this case, the initial horizontal velocity of the football would be:

\(V_{x}\) = 27 m/s × cos(30)

\(V_{x}\) = 27 m/s × 0.866

\(V_{x}\) = 23.662 m/s

So the initial horizontal velocity of the football, which moves in the x-direction, is approximately 23.662 m/s.

This means the football will move 23.662 m/s in x direction initially and if no air resistance acts upon the football, it will move at the same velocity in x direction throughout the motion.

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The two factors that affect current carrying capacity of an accumulator will be accumulator size and ambient temperature

Utilizing the compressible and decompressible properties of nitrogen gas, an accumulation vessel is used to store hydraulic pressure.

These key deciding elements are:

1. Accumulator Size: The current capacity increases as the circumference of the conductor increases.

2. Ambient Temperature: The greater the ambient temperature, the less heat is needed to raise the insulation's maximum operating temperature.

3. Accumulator identification:

4. Conditions for Installation:

Hence, the two factors that affect current carrying capacity of an accumulator will be accumulator size and ambient temperature

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Answer:

1distance --------- lightyear

2power------------- watt

3energy ----------- joule

4resistance ------ Ohm

5Force---------------- Newton

The magnitude of force F₂ is determined as 0.38 N.

The magnitude of force (F₂) is calculated by applying Newton's second law of motion as follows;

F = ma

where;

The resultant forces in the x-direction is given as

F₁cosθ₁  +  F₂cosθ₂ = maₓ

(1.5 cos35) + F₂(cos45) = 1.5 x 1

1.23 + 0.71F₂ = 1.5

0.71F₂ = 1.5 - 1.23

0.71F₂ = 0.27

F₂ = 0.27/0.71

F₂ = 0.38 N

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Answer: transverse wave

Explanation: the particles are moving up and down

Answer:

The two moments must be the same:

p1=p2

m1v1=m2v2

v2=(m1v1)/m2

v2=(90 kg x 0.9 m/s)/110kg=0.7 m/s

The Big Bang theory is the most widely accepted explanation for the origins of the universe, but it does not necessarily imply that the universe emerged from nothing.

It is possible that new discoveries or insights may shed light on this fundamental question in the future. The universe may have arisen from a pre-existing state or through some other natural process that we do not yet understand.

Instead, the theory describes how the universe underwent a rapid expansion from a very dense and hot state. The conditions and laws of physics that applied during the earliest moments of the universe may not necessarily be the same as those we observe today, and there are many unknowns and uncertainties in our understanding of these early stages.

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The velocity of this automobile as a function of time. At t = 5 seconds, the automobile is 90 meters from its initial position.

To determine the distance traveled by the automobile from its t = 0 initial position, we need to calculate the area under the velocity-time graph up to t = 5 seconds.

The graph shows the velocity of the automobile as a function of time. Let's assume that positive velocity represents forward motion, and negative velocity represents backward motion.

Since velocity represents the rate of change of displacement, the area under the velocity-time graph represents the displacement or distance traveled. In this case, the area will consist of two parts: the area above the x-axis (forward motion) and the area below the x-axis (backward motion).

To calculate the area, we can break it down into two separate integrals:

1. The area above the x-axis (forward motion):

Since the velocity is constant at 20 m/s for the first 4 seconds, the area is a rectangle:

Area1 = velocity * time = 20 m/s * 4 s = 80 m

2. The area below the x-axis (backward motion):

The velocity changes to -10 m/s at t = 4 seconds. From t = 4 seconds to t = 5 seconds, the velocity is -10 m/s. The area is a rectangle:

Area2 = velocity * time = -10 m/s * 1 s = -10 m

To find the total distance traveled, we add the absolute values of the areas:

Total distance = |Area1| + |Area2| = |80 m| + |-10 m| = 80 m + 10 m = 90 m

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Answer:

Explanation:

Given,

Let Alex be = x years

Then June will be = (7 + x) years

We know that,

Their total combined age is 29 years

Therefore,

By the problem,

=> x + (7 + x) = 29

=> 2x = 29 - 7

=> 2x = 22

=> x = 22 ÷ 2

=> x = 11

So,

Required age of June is = (7 + x) years

= (7 + 11) years

= 18 years (Ans)

Given the weight of the car, W = 8707 N, and the car moves a distance, s= 16.73 m, and final velocity, v = 5.84 m/s

Let the mass of the car be m and acceleration due to gravity g = 9.8 m/s^2

Also, weight is given by the formula,

Then, the mass of the car will be

The acceleration, a can be calculated by the formula

Here, u is the initial velocity, u=0.

The force will be

Thus, the force is 905.34 N

Steps to formulate a logical, reasonable perspective to any situation are: gather information, identify problem, analyze the situation, consider assumptions, generate solutions, evaluate options, consider your values, make decision and monitor and adjust

Here are the six questions that you can apply to formulating a logical, reasonable perspective to any situation:

What are the issues that should be addressed?

What are the relevant facts and data related to this problem or issue?

What assumptions am I making about the problem or issue?

What are the possible solutions or outcomes, and what are the pros and cons of each?

What are my values and priorities related to this problem or issue?

What additional information do I need to make an informed decision or come to a reasonable conclusion?

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Answer:

The speed each person travels and the distance they travel depends on their mass, friction of the scooter, etc. How would the distance moved by the scooter boards compare if one person had a lot more mass than the other person? The person with less mass would move away faster and would likely move a greater distance.

Answer:

Explanation:

Given:

F = Fₓ·i + Fy·j

S = Sₓ·i + Sy·j

Fₓ = 3 N

Fy = - 2 N

Sₓ = 5 m

Sy = 2 m

_________

A - ?   - Work

α - ? - Angle

F = 3·i - 2·j

S = 5·i + 2·j

The work is numerically equal to the scalar product of the displacement force

A = (F·S) = 3·5 + (-2)·2 = 15 - 4 = 11 J

Modules:

| F | = √ (3² + (-2)² ) = √ (9 + 4) = √ 13

| S | = √ (5² + 2² ) = √ (25 + 4) = √ 29

Angle:

cos α = (F·S) / ( |F| · |S| ) = 11 / ( √13 · √29) ≈ 0,5665

α ≈ 55.5°

As a result, the picture behind the mirror is virtual, upright, and enlarged.

You will find that the properties of an image (SALT) created in a concave mirror depend on the object's position. A) if the item is larger than C. Size, attitude, and location are all important considerations.

The image will be true, but reversed and much reduced. To obtain a crisp flame image, move the burning candle towards the mirror while moving the screen away from it. The size of the inverted picture grows.

Concave mirrors may create both physical and virtual images. A virtual and enlarged picture is produced when the item gets closer to the mirror. When the item is placed further away from the mirror,.

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Why the ocean near Christchurch is a different temperature than we'd expect for its latitude (distance from the equator)? Water moving from the equator is warmer than would be expected based on latitude, and so is warmer than the air it passes.

Changes to prevailing winds affect ocean currents. Changes to ocean currents affect how much energy is brought to (or taken away from) a location. In El Niño years, the prevailing winds that normally drive a warm current from the Equator past New Zealand are disrupted and may stop or even reverse.

Answer:

The blending of the fundamental tone with overtones produces the Sound Quality of Musical Instruments of an instrument.

The blending of the fundamental tone with overtones produces the sound quality of Musical Instruments  of an instrument.

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Answer:

Explanation:

The first question asks for the object's height. That is a y-dimension thing so we will use the one-dimensional formula:

\(v^2=v_0^2+2a\)Δx and we are looking for delta x, which is the displacement of the object (here, the height since displacement in the y-dimension is height). Before we do that, though, we need to know the initial upwards velocity, which is found in:

\(v_{0y}=100sin(60)\\v_{0y}=90\frac{m}{s}\)

And we also have to know from previous physics experience that the final velocity of an object at its max height is 0. Filling in:

\(0=(90)^2+2(-9.8)\)Δx

\(0=8000-20\)Δx and

-8000 = -20Δx so

Δx = 400 m

Now for the time it was in the air...we will use the simple equation

\(v=v_0+at\\0=90-9.8t\\-90=-9.8t\\t=9\)

So the object is in the air for 9 seconds. Now we go to the other dimension, the x-dimension, to find out how far it goes horizontally. We will use the equation:

Δx = \(v_0t+\frac{1}{2}at^2\) but first we have to find the horizontal velocity, which is NOT the same as the upwards velocity.

\(v_{0x}=100cos(60)\\v_{0x}=50\frac{m}{s}\)

And another thing we need to know prior to solving problems like this is that the acceleration in the x-dimension is ALWAYS 0. Filling in the equation:

Δx = \(50(9)+\frac{1}{2}(0)(9)^2\)

Δx = 500 m

Kendrick walks 128 meters to the grocery store + 204 meters to the shoe store + 28 meters to the fast food restaurant + 199 meters back home = 559 meters.

So the total distance that Kendrick walks is 559 meters.

Distance is a scalar quantity that represents the amount of space between two points in a given direction. It is typically measured in units such as meters, kilometers, miles, or feet. Distance is a measure of the separation between two points in space and does not account for direction. Distance is not affected by rotations, translations, or other changes in position of the objects.

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A plane flying initially at 100 m/s uses an acceleration of 5 m/s² to reach a velocity of 150 m/s in 10 seconds.

Acceleration is the change in velocity over time.

A plane is flying initially at 100 m/s (u) and it accelerates to 150 m/s (v) in 10 s (t). We can calculate its acceleration using the following expression.

a = v - u / t = (150 m/s - 100 m/s) / 10 s = 5 m/s²

A plane flying initially at 100 m/s uses an acceleration of 5 m/s² to reach a velocity of 150 m/s in 10 seconds.

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Answer:

Option (2)

Explanation:

From the figure attached,

Horizontal component, \(A_x=A\text{Sin}37\)

\(A_x=12[\text{Sin}(37)]\)

     = 7.22 m

Vertical component, \(A_y=A[\text{Cos}(37)]\)

    = 9.58 m

Similarly, Horizontal component of vector C,

\(C_x\)  = C[Cos(60)]

     = 6[Cos(60)]

     = \(\frac{6}{2}\)

     = 3 m

\(C_y=6[\text{Sin}(60)]\)

    = 5.20 m

Resultant Horizontal component of the vectors A + C,

\(R_x=7.22-3=4.22\) m

\(R_y=9.58-5.20\) = 4.38 m

Now magnitude of the resultant will be,

From ΔOBC,

\(R=\sqrt{(R_x)^{2}+(R_y)^2}\)

   = \(\sqrt{(4.22)^2+(4.38)^2}\)

   = \(\sqrt{17.81+19.18}\)

   = 6.1 m

Direction of the resultant will be towards vector A.

tan(∠COB) = \(\frac{\text{CB}}{\text{OB}}\)

                  = \(\frac{R_y}{R_x}\)

                  = \(\frac{4.38}{4.22}\)

m∠COB = \(\text{tan}^{-1}(1.04)\)

             = 46°

Therefore, magnitude of the resultant vector will be 6.1 m and direction will be 46°.

Option (2) will be the answer.

The angular velocity at 0.200 s is 2.7 rad/s . The blade turned 0.086 revolutions in 0.200 s. The tangential velocity at 0.200 s is 1.01 m/s.

Given that the radius = 0.750 m /2 = 0.375 m

Using the formula;

v = u + at

v = ?

u = 1.57 rad/s

t = 0.200 s

a = 5.65 rad/s²

Hence, v = 1.57 rad/s + (5.65 rad/s²)  0.200 s

v = 2.7 rad/s

Given that;

ω = θ/t

Where;

ω = angular velocity

θ = angle turned

t = time taken

2.7 rad/s = θ/0.200 s

θ = 2.7 rad/s × 0.200 s

θ = 0.54 rad

If 1 revolution = 6.283 radians

x revolutions = 0.54 radians

x = 1 revolution × 0.54 radians/6.283 radians

x = 0.086 revolutions

The tangential speed at  0.200 s is obtained from

v = ωr

ω = angular velocity

v = linear velocity

r = radius of the circular path

v = 2.7 rad/s × 0.375 m

v = 1.01 m/s

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Answer:

Honestly, I don't know ¯\_(ツ)_/¯

Explanation:

Answer:

Having a chronic disease

Explanation:

When body is changing its velocity at a constant rate then the body is said to be in uniform acceleration.

When a body is changing its velocity at different rates than my body is said to be moving with non uniform acceleration.

acceleration - The rate of change of velocity with respect to time.

It is a vector quantity.

a = dv / dt

SI unit is m/s²

direction of acceleration is the direction of change in velocity.

types of acceleration

When body is changing its velocity at a constant rate then the body is said to be in uniform acceleration.

When a body is changing its velocity at different rates than my body is said to be moving with non uniform acceleration.

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Element molecules consist of a single type of atom and are held together by covalent bonds. The model would have uniform-colored balls connected by sticks representing these bonds.

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Answer:

a) When moving towards a high pressure center the pressure values ​​increase in the equipment

b) This area is called high prison since the weight of the atmosphere on top is maximum

Explanation:

A) A high atmospheric pressure system is an area where the pressure is increasing the maximum value is close to 107 Kpa, the other side as low pressure can have small values ​​85.5 kPa.

When moving towards a high pressure center the pressure values ​​increase in the equipment

B) This area is called high prison since the weight of the atmosphere on top is maximum

in general they are areas of good weather

Answer:

\(V=1.86m/s\)

Explanation:

Mass of bullet \(M_B=6.11g\)

Velocity of bullet \(V_B=366m/s\)

Mass of first block \(M_b_1=1206g\)

Velocity of block \(V_b=0.662m/s\)

Mass of second block \(M_b_2=1550g\)

Generally the total momentum before collision is mathematically given as

\(P_1=0.006kg*366+0+0\)

\(P_1=2.196kg\ m/s\)

Generally the total momentum after collision is mathematically given as

\(P_2=(1.206kg*0.633)+(1.550+0.00611)V\)

\(P_2=0.763398+1.55611V\)

Generally the total momentum is mathematically given as

\(P_1=P_2\)

\(2.196=0.763398+1.55611V\)

\(V=\frac{2.196+0.763398}{1.55611}\)

\(V=1.86m/s\)