We know that the momentum is conserved this means that:
\(p_{1i}+p_{2i}=p_{1f}+p_{2f}\)where
\(p=mv\)In this case the balls are moving opposite each other this means that the velocities have opposite sign, we also know that the 3 kg ball stops after the collision this means that it final velocity is zero, then we have:
\(\begin{gathered} (3)(2)-(1)(2)=(3)(0)+1v_{2f} \\ 6-2=v_{2f} \\ v_{2f}=4 \end{gathered}\)Therefore the velocity of the 1 kg ball after the collision is 4 m/s
the correct number of significant figures.)
(a)
(b) the product 0.0055 ✕ 445.3
(c) the product 18.10 ✕
a) The sum of 545, 36.2, 0.080, and 9.0 is 590.280. The correct number of significant figures is 590.280 (5).
b) The product of 0.0055 and 445.3 is 2.46015. The correct number of significant figures is 2.46 (3).
c) The product of 18.10 and pi is 56.829079. The correct number of significant figures is 56.829079 (8).
What are significant figures?Significant figures, also known as significant digits, are the digits in a number that carry meaning contributing to its precision. They are used to express the level of confidence in a measurement. The number of significant figures in a measurement or calculation represents the number of digits that are known with some level of certainty, plus one final digit that is estimated. For example, the number 12.34 has four significant figures, while the number 0.001234 has only two significant figures.
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A football is kickedat 23.4 m/s at a38.5° angle. How faraway does it land?(Unit = m)te
Given:
Initial velocity = 24.3 m/s
Angle = 38.5°
Let's find how far away the ball landed.
To find the distance, apply the projectile motion formula below:
\(R=\frac{V^2\sin (2\theta)}{g}\)Where:
g = 9.8 m/s^2
V = 23.4 m/s
θ = 38.5°
Thus, we have:
\(R=\frac{23.4^2\ast\sin (2\ast38.5)}{9.8}\)Solving further:
\(\begin{gathered} R=\frac{547.56\sin(77)}{9.8} \\ \\ R=\frac{547.56\cdot0.97437006}{9.8} \\ \\ R=\frac{533.52607267}{9.8} \\ \\ R=54.4\text{ m} \end{gathered}\)Therefore, the footabll lands 54.4 meters away
ANSWER:
54.4 m
FILL IN THE BLANK The magnitude of the force of the bottom block on the top block is _____ the magnitude of the force of the earth on the top block view available hint S
The magnitude of the force of the bottom block on the top block is equal to the magnitude of the force of the earth on the top block.
According to Newton's third law of motion, for every action, there is an equal and opposite reaction. In this case, the top block exerts a downward force on the bottom block, and the bottom block exerts an equal and opposite upward force on the top block.
Similarly, the earth exerts a downward gravitational force on the top block, and the top block exerts an equal and opposite upward gravitational force on the earth. Again, these forces form an action-reaction pair with equal magnitudes but opposite directions.
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How can astronomers use how long it takes an objects brightness to vary to say something about the physical size of the object?
Astronomers can use how long it takes an object's brightness to vary to estimate the physical size of the object through a method known as photometry. This method involves observing an object's brightness over time and analyzing the patterns of variation.
For example, consider a binary star system in which two stars orbit each other. As one star passes in front of the other, the combined brightness of the system will decrease. The duration of this decrease in brightness can be used to estimate the physical size of the stars, as the duration of the decrease is related to the size of the stars and the distance between them.
Similarly, if an asteroid or other small body passes in front of a star, the star's brightness will decrease for a short period of time. The duration of this decrease can be used to estimate the size of the asteroid, as the duration is related to the size of the asteroid and the distance between it and the observer.
In general, the size of an object can be estimated using photometry by comparing the observed variation in brightness to the expected variation based on the physical characteristics of the object. This can provide valuable information about the properties and behavior of celestial objects and can help astronomers to better understand the structure and evolution of the universe.
A car traveling along a motorway at 35ms-1, 50m behind another car travelling in the same direction at 30,m,s to the power minus1, 30 ms-1. how long does it take before the first car reaches the second.
Answer:
10 s
Explanation:
d = distance = rate x time
At time t, the first car reaches the second.
(35 m/s)t = (30 m/s)t + 50 m solve this for t
(5 m/s)t = 50 m
t = (50m) / (5 m/s) = 10 s
double check the answer:
(35 m/s)(10 s) = (30 m/s)(10 s) + 50 m
350 m = 350 m
How do I find the mass in kg
To find the mass in kilograms, you need to know the object's weight in newtons and the acceleration due to gravity. The formula for finding mass is mass = weight / acceleration due to gravity. So if you have an object with a weight of 100 N and the acceleration due to gravity is 9.8 m/s^2, the mass would be 10.204 kg.
The mass of the block is 0.025 kg or 25 g, when the spring has k = 28 N/m, and compresses 0.11 m before bringing the block to rest.
When a block is dropped onto a spring with k=28 N/m, the block has a speed of 3.2 m/s just before it strikes the spring. If the spring compresses an amount of 0.11 m before bringing the block to rest, what is the mass of the block?The formula for the spring potential energy is given as follows; PE = (1/2) kx² where k is the spring constant and x is the amount of deformation of the spring. Substituting the values given;PE = (1/2) 28 (0.11)²PE = 0.16972 J. According to the law of conservation of energy, the potential energy stored in the spring at maximum compression is equal to the kinetic energy the block had before it struck the spring;KE = (1/2) mv²where m is the mass of the block and v is its velocity.Substituting the values;0.16972 = (1/2) m (3.2)²m = 0.025 kg or 25 gTherefore, the mass of the block is 0.025 kg or 25 g.For more questions on mass
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This is one popular brand of exercise machine for a crossword puzzle
Answer:
Aerobics I think.
Explanation:
How are magnetic fields like vectors?
Answer:Magnetic fields from two sources add up as vectors at each point, so the strength of the field is not necessarily the sum of the strengths1. Magnetic fields are vectors, which means they have direction as well as size. Therefore, the sum of two magnetic fields is not simply the sum of their magnitudes2.
Explanation:
The earliest mineral observed to showmagnetic properties is called
A leadstone
Blodestone
Cloadstone
Dnone of the above
E all of the above
Answer:
B: lodestone
Explanation:
Each magnet has its magnetic poles, north (N) and south (S). Diversified ones are attracted and reptiles of the same name are repelled, similarly to charges, so it was considered possible to separate the magnet at the north and south poles.
Magnetic properties can be lost if the magnet is exposed to high temperatures if it falls or due to some mechanical shocks.
How is the periodic table of elements organized?
A) Groups and periods
B) Groups and columns
C) Periods and rows
D) Periods and columns
A
Explanation:
Groups and Periods.
I need help plissss..............
The epiphyseal, or growth, plates close at relatively younger ages in which of the following groups?
The epiphyseal, or growth, plates close at relatively younger ages in boys and girls. That is option E.
What are growth plates ?The growth plate which is also called the epiphyseal plate is defined as the area of tissue near the ends of long bones in children and teens that determines the future length and shape of the mature bone.
The growth plate is made up of the following layers such as:
proliferation zone,hypertrophic cartilage zone,calcified cartilage zone, and ossification zone.The epiphyseal plate is known to close at relatively younger age for boys and girls because of Estrogen and testosterone release at puberty which initiates closure of the epiphyseal plates.
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Complete question:
The epiphyseal, or growth, plates close at relatively younger ages in which of the following groups?
a. boys
b. girls
c. early maturers
d. a and c
e. b and c
A punter wants to kick a football so that the football has a total flight time of 4.70s and lands 56.0m away (measured along the ground). Neglect drag and the initial height of the football.
How long does the football need to rise?
What height will the football reach?
With what speed does the punter need to kick the football?
At what angle (θ), with the horizontal, does the punter need to kick the football?
Answer:
Explanation:
How long does the football need to rise?
4.70/3 = 2.35 s
What height will the football reach?
h = ½(9.81)2.35² = 27.1 m
With what speed does the punter need to kick the football?
vy = g•t = 9.81(2.35) = 23.1 m/s
vx = d/t = 56.0/4.70 = 11.9 m/s
v = √(vx²+vy²) = 26.0 m/s
At what angle (θ), with the horizontal, does the punter need to kick the football?
θ = arctan(vy/vx) = 62.7°
Mars has two moons, Phobos and Deimos. Phobos orbits Mars at a distance of 9380 km from Mars's center, while Deimos orbits at 23,500 km
from the center.
What is the ratio of the orbital period of Deimos to that of Phobos?
Answer:
The ratio is \(\frac{T_1}{T_2} = 3.965 \)
Explanation:
From the question we are told that
The radius of Phobos orbit is R_2 = 9380 km
The radius of Deimos orbit is \(R_1 = 23500 \ km\)
Generally from Kepler's third law
\(T^2 = \frac{ 4 * \pi^2 * R^3}{G * M }\)
Here M is the mass of Mars which is constant
G is the gravitational constant
So we see that \(\frac{ 4 * \pi^2 }{G * M } = constant\)
\(T^2 = R^3 * constant \)
=> \([\frac{T_1}{T_2} ]^2 = [\frac{R_1}{R_2} ]^3\)
Here \(T_1\) is the period of Deimos
and \(T_1\) is the period of Phobos
So
\([\frac{T_1}{T_2} ] = [\frac{R_1}{R_2} ]^{\frac{3}{2}}\)
=> \(\frac{T_1}{T_2} = [\frac{23500 }{9380} ]^{\frac{3}{2}}]\)
=> \(\frac{T_1}{T_2} = 3.965 \)
The given values are:
Radius, r = 23500 kmDistance = 9380 kmWe know the formula,
→ \(v = \frac{2 \pi r}{T}\)
then,
→ \(\sqrt{\frac{GM_{mars}}{r} } =\frac{2 \pi r}{T}\)
or,
→ \(T = 2 \pi \sqrt{\frac{r^3}{GM_{mars}} }\)
Now,
The orbital period of Deimos will be:
\(= 2 \pi \sqrt{\frac{(23500)^3}{GM_{mars}} }\)
The orbital period of Phobos will be:
\(= 2 \pi \sqrt{\frac{(9380)^3}{GM_{mars}} }\)
hence,
The ratio will be:
→ \(\frac{T_{deimos}}{T_{Phobos}}\) = \(\frac{2 \pi \sqrt{\frac{(23500)^3}{GM_{mars}} } }{2 \pi \sqrt{\frac{(9380)^3}{GM_{mars}} }}\)
= \(\sqrt{(\frac{23500}{9380})^3 }\)
= \(3.96\)
Thus the above answer is correct.
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please help me !
1. Suppose that the temperature drops 25 degrees overnight. When you get into your car the next morning, your low tire pressure light comes on. Explain, in terms of the ideal gas law, why this happened (assume air is an ideal gas). (10 points)
Answer:
The drop in temperature overnight causes a decrease in the average kinetic energy of the air molecules inside the tires. According to the ideal gas law, this leads to a decrease in tire pressure. The low tire pressure light in vehicles is triggered when the pressure falls below a certain threshold, alerting the driver to check and adjust the tire pressure.
Explanation:
The ideal gas law, represented by the equation PV = nRT, relates the pressure (P), volume (V), number of moles (n), and temperature (T) of an ideal gas. In this case, we can analyze how the drop in temperature affects the tire pressure.
When the temperature drops, according to the ideal gas law, the pressure of a gas will decrease if the volume and the number of moles remain constant. This is because the decrease in temperature causes a decrease in the average kinetic energy of the gas particles, leading to less frequent and less forceful collisions with the tire walls, resulting in a decrease in pressure.
In the context of the tire pressure, the air inside the tires behaves as an ideal gas. When the temperature drops overnight, the air inside the tires also cools down, causing a decrease in its temperature. As a result, the average kinetic energy of the air molecules decreases, leading to a decrease in pressure inside the tires.
The low tire pressure light comes on as a result of this drop in pressure. The tire pressure monitoring system in modern vehicles is designed to detect significant deviations from the recommended tire pressure. When the pressure drops below a certain threshold, typically due to temperature changes or a puncture, the light is triggered to alert the driver to check and adjust the tire pressure.
Therefore, the drop in temperature overnight causes a decrease in the average kinetic energy of the air molecules inside the tires, resulting in a decrease in tire pressure, which triggers the low tire pressure warning light.
Hope this helps!
the distance between an object and its real image is 40 cm, if the magnification is 3, calculate the object and image distance if the focal length of the lens is 15 cm
The object distance of the lens is 10 cm and the image distance of the lens is 30 cm.
What is the image and object distance?The object and image distance formed by the lens is calculated by applying the following lens formula.
v + u = 40 ------- (1)
v/u = 3 ------------ (2)
v = 3u
Substitute v into equation (1);
3u + u = 40
4u = 40
u = 40/4
u = 10 cm
The image distance = 3u
= 3 x 10 cm
= 30 cm
Thus, the object distance is 10 cm and the image distance is 30 cm.
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100%
The table shows the change in the percentage of paved surfaces in an area of Washington, D.C. from
Year Percentage of Paved Surfaces
1984
22
2010
26
In what two ways does the change in paved surfaces affect the climate?
A. Paved surfaces react with rainwater to form carbon dioxide.
B. Paved surfaces break down and release carbon dioxide over time.
C. Paved surfaces absorb more heat than vegetated or lighter colored surfaces.,
D. Paved surfaces release more heat from geologic processes in Earth's interior.
E. Paved surfaces generate greenhouse gas emissions during production of the needed materials.
Paved surfaces absorb more heat than vegetated or lighter colored surfaces.
Paved surfaces generate greenhouse gas emissions during production of the needed materials.
options C and E.
In what two ways does the change in paved surfaces affect the climate?Climate change refers to long-term shifts in temperatures and weather patterns.
The two ways in which the change in paved surfaces affect the climate is determined as follows;
Paved surfaces absorb more heat than vegetated or lighter colored surfaces.Paved surfaces generate greenhouse gas emissions during production of the needed materials.Thus, option C and E are the correct answers.
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What is the equivalent resistance of a circuit that contains three 10.0 Ω
resistors connected in series to a 6.0 V battery?
Ο A. 0.600 Ω
Ο Β. 60.0 Ω
Ο C. 16.0 Ω
Ο D. 30.0 Ω
Question :
What is the equivalent resistance of a circuit that contains three 10.0 Ω resistors connected in series to a 6.0 V battery?Options given :
A. 0.600 ΩΒ. 60.0 ΩC. 16.0 ΩD. 30.0 ΩSolution :
As we know that,
When a circuit is connected in series resistance is calculated by :
Rs = R1 + R2 + R3 .... RnHere,
R is resistanceAs a circuit contains three resistors. So R1 , R2 and R3 would be :
R1 = 10 ΩR2 = 10 ΩR3 = 10 ΩNow,
>> Rs = 10 + 10 + 10
>> Rs = 30 Ω
Therefore,
Option D is correct.The equivalent resistance in the circuit is 30.0 Ω. The correct option is D.
What is Ohm's law?Ohm's law is a fundamental principle of electric circuits that describes the relationship between electric current, voltage, and resistance. It states that the electric current flowing through a conductor between two points is directly proportional to the voltage across the two points, and inversely proportional to the resistance between them.
Mathematically,
V = IR
Where V = is the voltage across the conductor in volts (V),
I = is the electric current flowing through the conductor in amperes (A),
R =is the resistance of the conductor in ohms (Ω).
This relationship can also be expressed in terms of power, using the formula:
P = VI
Where P = is the power in watts (W),
V = is the voltage in volts (V),
I = is the current in amperes (A).
Ohm's law is named after the German physicist Georg Simon Ohm, who first published it in 1827 as a result of his experiments with electric circuits. Ohm's law is widely used in electrical engineering and is essential for understanding and designing electronic devices and circuits.
Here in this question,
The equivalent resistance of resistors in series is the sum of their individual resistances.
Now, the equivalent resistance of three 10.0 Ω resistors connected in series is:
Req = R1 + R2 + R3
Req= 10.0 Ω + 10.0 Ω + 10.0 Ω
Req= 30.0 Ω
Using Ohm's law, we can find the current flowing through the circuit:
I = V/R
= 6.0 V/30.0 Ω
I = 0.2 A
Therefore, the equivalent resistance of the circuit is 30.0 Ω (Option D).
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A 10kg bowling ball is moving at 10 m/s when it strikes a 3.0kg bowling pin at rest after the collision tge pin moves foward at 12m/s what is the speed of the bowling ball aftdd the collision
The speed of the bowling ball after the collision is 4 m/s.
What is momentum?The momentum is defined as the product of the mass and the velocity of the body.
We can use the law of conservation of momentum to solve this problem, which states that the total momentum of a system remains constant in the absence of external forces. The initial momentum of the system (bowling ball + bowling pin) is:
pi= m₁v₁ + m₂ v₂
= 10 kg x 10 m/s + 3 kg x 0 m/s
= 100 kg m/s
where m₁ is the mass of the bowling ball, v₁l is its velocity before the collision, m₂ is the mass of the bowling pin, and v'₂ is its velocity before the collision (which is zero since it's at rest).
After the collision, the momentum of the system is:
pf = m₁v'₁ + m₂ v'₂
Where v'₁ is the velocity of the bowling ball after the collision, and v'₂ is the velocity of the bowling pin after the collision.
Since momentum is conserved, we have:
pi= pf
Substituting the values we know, we get:
100 kg m/s = 10 kg x v'₁ + 3 kg x 12 m/s
Solving for v'₁, we get:
v'₁ = (100 kg m/s - 3 kg * 12 m/s) / 10 kg
v'₁ = 4 m/s
Therefore, the speed of the bowling ball after the collision is 4 m/s.
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Pls hurry!! which organisms have no consumers to feed on them?
Explanation:
All living organisms metabolize. That is the definition of life. So jr answer is no animal or organism that does not consume food.
Explain why the subatomic particle that is not a part of the nucleus stays bound to the atom. For full credit, you must include the charges of all subatomic particles in your explanation.
The subatomic particle that is not a part of the nucleus which stays bound to the atom is the electron and is to maintain relative stability.
What is Electron?This is defined as a sub atomic particle which is negatively charged and revolve around the nucleus. In an atom the number of electron is usually equal to the number of the proton which is positively charged and present in the nucleus.
The electron not being in the nucleus is a a result of it wanting to maintain stability because its presence will produce a wavelength which will break the nucleus apart.
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Mention 2 everyday applications each of conduction, convection and radiation
Answer:
Conduction: Touching a stove and being burned. Ice cooling down your hand. .
Explanation:
A kiddie roller coaster car has a mass 100 kilograms. At the top of a hill, it’s moving at a speed of 3 meters/second. After reaching the bottom of the hill, its speed doubles. The car’s kinetic energy at the bottom is what?
(1/2)mv^2 = (1/2) * 100 * (2*3)^2 = 1800 [J]
Calculate the surface density of atoms in the (111) plane of the body centered cubic lattice. Assume the lattice constant a=5 angstroms. Assume the atoms to be hard spheres, with closest atoms touching each other.
The surface density of atoms in the (1,1,1) plane of the BCC lattice is 0.16 atoms/angstrom².
To calculate the surface density of atoms in the (1,1,1) plane, we first need to determine how many atoms are in the plane. Since the plane passes through the center of the unit cell, it intersects one-eighth of each of the corner atoms and the full central atom. Therefore, the total number of atoms in the (1,1,1) plane is:
N_atoms = 1 + 8*(1/8) = 2
Next, we need to calculate the area of the (1,1,1) plane. To do this, we can consider the lengths of the sides of the unit cell. Since the BCC lattice has a cubic unit cell, all sides have length a=5 angstroms. The (1,1,1) plane passes through the center of the unit cell and intersects the sides at a 45-degree angle. The distance from the center of the unit cell to the midpoint of one of the sides is a/sqrt(2), so the length of the diagonal of the square face of the unit cell is 2a/√(2) = a√(2). The area of the square face is then (a√(2))² = 2a².
The (1,1,1) plane intersects the square face at a 45-degree angle, so its area is 2*a²/2 = a².
The surface density of atoms is the number of atoms per unit area. Dividing the number of atoms in the (1,1,1) plane by the area of the plane gives:
surface density = N_atoms / area
= 2 / a² = 2 / (5 angstroms)² = 0.16 atoms/angstrom²
Therefore, the surface density of atoms in the (1,1,1) plane of the BCC lattice is 0.16 atoms/angstrom².
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a bike accelerates from 0 m/s to 5 m/s in 4.5s.Then continues at a Constant speed for another 2.5s How far does it move?
Answer:
Below
Explanation:
First we will find the distance from when the bike is accelerating
Use this formula to find this :
d1 = ( vf - vi / 2 ) t
d1 = ( 5m/s - 0 m/s / 2 ) 4.5 s
d1 = (2.5)(4.5)
d1 = 11.25 m
Now we can find the distance for another 2.5 seconds
Since the car accelerated to 5 m/s, the constant velocity will be 5 m/s
Use this formula to find this :
d2 = vt
d2 = (5m/s)(2.5s)
d2 = 12.5 m
Finally we can add them up to get the total distance :
dt = 12.5 m + 11.25 m
dt = 23.75 m
*Make sure to round this number to how your teacher taught you
Hope this helps!
please give the answer of mass of electron in physics
Answer:
electron, lightest stable subatomic particle known. It carries a negative charge of 1.602176634 × 10−19 coulomb, which is considered the basic unit of electric charge. The rest mass of the electron is 9.1093837015 × 10−31 kg, which is only 1/1,836the mass of a proton.
Explanation:
I hope this will be helpful for you.
a current of a 6 flows through a light bulb for 12 s, how many coulombs of charge pass through the light bulb during this time
A current of a 6 flows through a light bulb for 12 s. The total charge that passes through the light bulb during the given time is 72 coulombs.
To calculate the total charge that passes through the light bulb, we need to use the formula Q = I * t, where Q represents the charge in coulombs, I represents the current in amperes, and t represents the time in seconds.
Step 1: Identify the known values:
Current (I) = 6 amperes
Time (t) = 12 seconds
Step 2: Calculate the charge using the formula:
Q = I * t
Step 3: Substitute the known values into the formula:
Q = 6 amperes * 12 seconds
Q = 72 coulombs
Therefore, the total charge that passes through the light bulb during the given time is 72 coulombs.
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Identify the direction of the net force acting on the object. Explain your reasoning
Answer:
See Below
Explanation:
I am not sure what you exact question is to know what direction it is but here is how you do it.
The direction of the net force is the direction of the largest force.
for example if you were to push a box forward with 100 newton's of force and someone pushed at the same time 50 newton's backwards on the box, the box would move forwards because the was a greater force on the box in a forward direction. hope this helps
Calculate the volume of a parallelepiped with sides give as
a
=
(
7,2
,
4
)
,
b
=
(
4,7
,
6
)
and
c
=
(
3,4
,
7
)
Select one:
105
cubic units
125
cubic units
115
cubic units
135
cubic units
To calculate the volume of a parallelepiped given the sides, we can use the scalar triple product. The formula for the volume of a parallelepiped with sides a, b, and c is:
Volume = |a · (b × c)|
where · represents the dot product and × represents the cross product.
Using the given sides:
a = (7, 2, 4)
b = (4, 7, 6)
c = (3, 4, 7)
First, calculate the cross product of b and c:
b × c = (7*7 - 4*4, 6*3 - 7*7, 4*4 - 2*3)
= (49 - 16, 18 - 49, 16 - 6)
= (33, -31, 10)
Next, calculate the dot product of a and the cross product (b × c):
a · (b × c) = 7*33 + 2*(-31) + 4*10
= 231 - 62 + 40
= 209
Finally, take the absolute value of the result to obtain the volume:
Volume = |209| = 209 cubic units
Therefore, the correct answer is:
209 cubic units
. The force of gravity on the Moon is said to be one-sixth of that on the Earth. What would a mass of 12 kg weigh; (a) on the Earth
A. The weight of the mass on the earth is 117.6 N
A. The weight of the mass on the moon is 19.56 N
How do i determine the weight of the mass?Weight is defined as follow:
Weight (W) = mass (m) × Acceleration due to gravity (g)
W = mg
Now we shall determine the weight. Details below:
A. Weight on earth
Mass (m) = 12 KgAcceleration due to gravity on earth (g) = 9.8 m/s² Weight on earth (W) =?Weight (W) = mass (m) × Acceleration due to gravity (g)
Weight (W) = 12 × 9.8
Weight on earth = 117.6 N
B. Weight on moon
Mass (m) = 12 KgAcceleration due to gravity on earth (g) = 9.8 m/s² Acceleration due to gravity on moon (g) = (1/6) × 9.8 = 1.63 m/s² Weight on moon (W) =?Weight (W) = mass (m) × Acceleration due to gravity (g)
Weight (W) = 12 × 1.63
Weight on moon = 19.56 N
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Complete question:
The force of gravity on the Moon is said to be one-sixth of that on the Earth. What would a mass of 12 kg weigh; (a) on the Earth (b) on the moon