A 4 cm diameter "bobber" with a mass of 3 grams floats on a pond. A thin, light fishing line is tied to the bottom of the bobber, and from the bottom hangs a 10 gram lead weight. The density of lead is 11.3 g/cm3. What fraction of the bobber's volume is submerged, as a percent of the total volume

The negatively charged sphere Z is most likely to leave the electric field near the center of plates, which is closest to letter Y.

Physical field that surrounds electrically charged particles and exerts force on all the other charged particles in the field is called an electric field.

Negatively charged sphere labeled Z will experience a force due to  electric field created by parallel plates. Since the vector is pointing right, we can assume that electric field is also pointing right.

Electric field lines are perpendicular to plates and are equally spaced. Therefore, electric field is uniform in magnitude and direction between the plates.

As the negatively charged sphere Z travels horizontally between plates, it will experience force in the direction opposite to electric field due to its negative charge. This force will cause sphere to slow down and  stop.

Since the electric field lines are equally spaced between the plates, electric field will be strongest at the edges of plates and weakest in the center. Therefore, negatively charged sphere Z is most likely to leave the electric field near the center of plates, which is closest to letter Y.

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The equivalent temperature in Celsius scale is (86°F − 32) × 5/9 = 30°C

Take the °F temperature and subtract 32

Multiply this number by 5.

Divide this number by 9 to obtain your answer in °C.

The formula to convert °F to °C is:

T(°C) = (T(°F) - 32) × 5/9

converting 86 degrees Fahrenheit into degrees Celsius:

T(°C) = (86°F - 32) × 5/9

T(°C) = 30 °C

(86°F − 32) × 5/9 = 30°C

When doing the temperature conversion, one quick way to make certain you did the conversion right is to remember Fahrenheit temperatures are higher than the corresponding Celsius scale until you get down to -40°, which is where the Celsius and Fahrenheit scales meet. Below this temperature, degrees Fahrenheit are lower than degrees Celsius.

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When two magnets are close to each other, the magnets experience a repulsive or attractive force. The magnetic field strength is affected by the orientation of the magnet.

The direction in which the bar magnet obtains its maximum magnetic property is called the orientation of the magnet. The magnetic field strength depends on the orientation of the magnet.

The magnetic field lines emerge from the north pole and end in the south pole. When the two bar magnets of opposite poles face each other, an attractive force will be produced and magnetic field strength increases.

When the bar magnet of the same poles faces each other, repulsive force will produce and magnetic field strength decreases. Hence from the orientation of the bar magnet,  the magnetic field strength gets affected.

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Answer:

Uh, I could be wrong but doesn’t it mean that the wave and particle are reacting together to make light? I think it’s something like that... I hope this helps!

The arrows are drawn in the figure which shows gravitational forces on each person on earth.

Gravitational force is force of attraction between two masses. Gravitational force(F) between two bodies is directly proportion to the product of masses(m₁,m₂) of two bodies and inversely proportional to square of distance(r) between them. mathematically it is written as,

F∝ m₁.m₂

F ∝ 1/r²

F = G m₁,m₂÷r²

where G is gravitational constant, whose value is 6.6743 × 10⁻¹¹ m³ kg-1s⁻².

Force is expressed in Newton N in SI unit. its dimensions are [M¹L¹T⁻²].

This is analogous with coulomb's law which gives force between two charges.

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Answer:

5 m/s

Explanation:

5000/1000=5 m/s

:))

1. It is unethical for Demario to cheat

2. Demario should not engage in cheating himself

3. Demario should not turn in cheating classmates without careful consideration

4. Reporting classmates may harm relationships, create animosity, and potentially lead to severe disciplinary actions.

A virtue ethics perspective may also be useful in this circumstance. Demario should make an effort to respect moral principles like honesty, fairness, and integrity while taking the potential repercussions into account and exhibiting empathy for his fellow students.

By employing this strategy, Demario behaves responsibly, deals with the problem subtly, encourages fairness in the educational setting, and upholds his or her own moral standards.

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The separation distance in B is a number times greater than in A, then the force of attraction in B is less than A.

The force of attraction between two charged object is determined by applying Coulomb's law.

Coulomb's law states that the force of attraction or repulsion between two charged objects is directly proportional to the product of the charges and inversely proportional to the square of the distance between the charges.

Mathematically, this law is written as;

F = Kq₁q₂/r²

where;

From the formula given above, as the distance of separation increases, the magnitude of the force of attraction between the charges decreases. Also, as the distance of separation between the charges decreases, the magnitude of the force of attraction between the charges increases.

Thus, the magnitude of the force of attraction between charged objects is a function of the magnitude of the charges and distance of separation between the charges.

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Acceleration is the rate of change of velocity, so if velocity is linear, the acceleration is the slope of its graph.

Here, the line passes through the points (0, 1) and (0.5, 3), so its slope is

(3 m/s - 1 m/s) / (0.5 s - 0 s) = (2 m/s) / (0.5 s) = 4 m/s²

Answer:

2.4 m/s". 1

Explanation:

A jet with mass m = 8 x 10* kg jet accelerates down the runway for takeoff at 2.4 m/s". 1

Answer:

The accuracy and precision of a result depend on several factors, including:

1. Quality of the measurement tools - Using high-quality measurement instruments can lead to more accurate and precise results.

2. Calibration of instruments - Instruments should be calibrated regularly to ensure accurate and precise readings.

3. Skill of the person performing the measurement - The person performing the measurements must have proper training and knowledge of the tool they're using.

4. Sample size - Increasing the sample size can lead to more accurate results.

5. Sampling bias - If the sample used for the measurement is biased, it can lead to inaccurate or imprecise results.

6. Experimental design - Proper experimental design can help reduce measurement errors and increase accuracy.

The work-energy theorem states that the change in the kinetic energy of an object will be equal to the net work done on the object.

Mathematically, it can be expressed as;

ΔKE = W

Where; ΔKE represents the change in kinetic energy of the object,

W represents the net work done on the object.

This theorem states that when work is done on an object, it results in a change in its kinetic energy. If work is done on an object, its kinetic energy increases, and if work is done by an object, its kinetic energy decreases.

This theorem is a fundamental principle in physics that relates the concepts of work and energy, and it is often used to analyze the motion and behavior of objects in various physical systems.

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Answer:

A) P = 3.3 × 10^(-11) Pa

B) Amplitude of electric field = 1.931 N/C

Amplitude of magnetic field = 6.44 × 10^(-9) T

C) μ_av = 1.65 × 10^(-11) J/m³

D) 50% each for the electric and magnetic field

Explanation:

A) First of all let's calculate intensity.

I = P_av/A

We are given;

P_av = 777 KW = 777,000 W

Distance = 5 km = 5000 m

Thus;

I = 777000/(2π × 5000²)

I = 0.00495 W/m²

Now, the average pressure would be given by the formula;

P = 2I/C

Where C is speed of light = 3 × 10^(8) m/s

P = (2 × 0.00495)/(3 × 10^(8))

P = 3.3 × 10^(-11) Pa

B) Formula for the amplitude of the electric field is gotten from;

E_max = √[2I/(εo•c)].

Where εo is the Permittivity of free space with a constant value of 8.85 × 10^(−12) c²/N.mm²

I and c remain as before.

Thus;

E_max = √[(2 × 0.00495)/(8.85 × 10^(−12) × 3 × 10^(8))]

E_max = √3.72881355932

E_max = 1.931 N/C

Formula for amplitude of magnetic field is gotten from;

B_max = E_max/c

B_max = 1.931/(3 × 10^(8))

B_max = 6.44 × 10^(-9) T

C) Formula for average density is;

μ_av = εo(E_rms)²

Now, E_rms = E_max/√2

Thus;

E_rms = 1.931/√2

μ_av = 8.85 × 10^(−12) × (1.931/√2)²

μ_av = 1.65 × 10^(-11) J/m³

D) The energy density for the electric and magnetic field is the same. So both of them will have 50% of the energy density.

Answer:

the angular velocity of the car is 12.568 rad/s.

Explanation:

Given;

radius of the circular track, r = 0.3 m

number of revolutions  per second made by the car, ω = 2 rev/s

The angular velocity of the car in radian per second is calculated as;

From the given data, we convert the angular velocity in revolution per second to radian per second.

\(\omega = 2 \ \frac{rev}{s} \times \frac{2\pi \ rad}{1 \ rev} = 4\pi \ rad/s = 12.568 \ rad/s\)

Therefore, the angular velocity of the car is 12.568 rad/s.

The power required to lift the water to the surface at a rate of 0.23 m³/s and at a height of 23m deep is 52.9 kW.

Power is obtained from the ratio of work and time and the power is measured in watts (W). P = W/t where W is the work done by the system and t is the time taken to do work.

From the given,

rate of electric pump = 0.23 m³/s

depth of the well = 23m

density of water = 1000 kg/m³

work done=?

work done (w)= m×g×h, where m is the mass of water, g is the acceleration due to gravity and is equal to 10 m/s², and h is the height.

Density = mass/volume

mass = density ×volume

        = 10³ × 0.23

Work done= 0.23×10³×10×23

                   = 52.9 ×10³ W

work done on the pump is 52.9 KJ

Power = work done / time (time = 1sec)

           = 52.9 × 10³ J/ 1 sec

          = 52.9 kW

Hence, the power to lift the water to the surface is 52.9 kW.

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The car can take this curve at a speed of 18.8 m/s without skidding to the outside of the curve

The maximum speed at which a car can take a curved road without skidding outward is given by the formula:

v = √(g * r * (cos(theta) + (mu * sin(theta))/mu_s))

where:

v = velocity of the car

g = acceleration due to gravity (9.8 m/s^2)

r = radius of curvature of the road (36 m)

theta = angle of banking of the road (25 degrees)

mu = coefficient of friction between the tires and the road (0.87)

mu_s = coefficient of static friction between the tires and the road (0.87)

So the maximum speed at which the car can take this curve without skidding is:

v = √(9.8 * 36 * (cos(25) + (0.87 * sin(25))/0.87))

v = √(9.8 * 36 * (0.9063 + 0.4696))

v = √(9.8 * 36 * 1.376)

v = √(352.48)

v = 18.8 m/s

Therefore, the car can take this curve at a speed of 18.8 m/s without skidding to the outside of the curve.

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(C)

Explanation:

The circle has a radius r = 0.5 m, which means that its circumference C is

\(C = 2\pi r = 2\pi(0.5\:\text{m}) = 3.14\:\text{m}\)

One revolution means that the stopper travels a distance equal to the circumference of the circle so the velocity of the stopper is

\(v = \dfrac{C}{t} =\dfrac{3.14\:\text{m}}{0.2\:\text{s}} = 15.7\:\text{m/s} \approx 16\:\text{m/s}\)

From the law of conservation of momentum, your velocity after you throw it will be 0.5 m/s

Momentum is the product of mass and velocity. It is measured in Kgm/s

If you weigh 40kg and are standing still on a skateboard and throw a 1kg ball to the left (negative velocity) at a velocity of -20m/s, From the law of conservation of momentum, your velocity after you throw it can be calculated.

MV = mv

where

Substitute all the parameters into the formula

40V = 1 × 20

V = 20/40

V = 0.5 m/s

Therefore, your velocity after you throw it will be 0.5 m/s

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Answer:

211,520 N/m^2

Explanation:

To calculate the gauge pressure at section 2, we can apply Bernoulli's equation, which states that the total energy of a fluid in a horizontal flow remains constant. Bernoulli's equation is expressed as:

P1 + 0.5 * ρ * u1^2 + ρ * g * z1 = P2 + 0.5 * ρ * u2^2 + ρ * g * z2

Given the information provided:

P1 = 200 kN/m^2

u1 = 5 m/s

d1 = 10 cm = 0.1 m (converted to meters)

d2 = 8 cm = 0.08 m (converted to meters)

z1 = z2 (since the tube is horizontal)

ρ = 960 kg/m^3 (density of the fluid)

We can calculate the velocity at section 2 (u2) using the continuity equation, which states that the mass flow rate is constant in an incompressible fluid:

A1 * u1 = A2 * u2

A1 = (π/4) * d1^2 (area at section 1)

A2 = (π/4) * d2^2 (area at section 2)

Substituting the values and solving for u2:

(π/4) * d1^2 * u1 = (π/4) * d2^2 * u2

(0.785) * (0.1)^2 * 5 = (0.785) * (0.08)^2 * u2

0.03925 = 0.03925 * u2

u2 = 1 m/s

Now we can substitute all the known values into Bernoulli's equation:

200 kN/m^2 + 0.5 * 960 kg/m^3 * (5 m/s)^2 = P2 + 0.5 * 960 kg/m^3 * (1 m/s)^2

Simplifying the equation:

200000 N/m^2 + 0.5 * 960 kg/m^3 * 25 m^2/s^2 = P2 + 0.5 * 960 kg/m^3 * 1 m^2/s^2

200000 N/m^2 + 12000 N/m^2 = P2 + 480 N/m^2

212000 N/m^2 = P2 + 480 N/m^2

P2 = 211520 N/m^2

Therefore, the gauge pressure at section 2 is 211,520 N/m^2.

ANSWER:

STEP-BY-STEP EXPLANATION:

1)

For the case of m1, the force scheme would be like this:

We do the summation of force in each direction:

The distance traveled by the object during the time interval from t = 2 s to t = 3s is 3m. Option C.

From the formula d = ½ at2 the displacement is proportional to the square of time. If you run twice as far from the rest, the displacement will quadruple (or 4m). Since the object has already moved 1 m in the first second, the remaining 3 m have moved in time intervals from 1 to 2 seconds.

This means that the velocity and net force in the direction normal to the plane must be zero. Assuming the plane is frictionless means that the plane exerts no force on the block parallel to the surface. For angular frictionless tilt, the acceleration is the result of the gravitational acceleration multiplied by the sine of the angle.

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A VfL (Vertical Field LED) backlighting system is commonly used in LCD (Liquid Crystal Display) televisions.

LCD TVs rely on a backlight to illuminate the liquid crystal layer, which controls the passage of light to create the visual image. The VfL technology is a specific type of LED backlighting arrangement used in certain LCD TV models. In a VfL backlighting system, the LEDs (Light-Emitting Diodes) are positioned vertically along the edges of the LCD panel.

The light emitted by these LEDs is directed across the panel using light guides or optical films, illuminating the liquid crystal layer uniformly. One advantage of VfL backlighting is its ability to provide consistent illumination across the LCD panel, reducing any potential inconsistencies in brightness or color uniformity. The vertical orientation of the LEDs allows for more precise control over light distribution, improving overall image quality.

Additionally, VfL backlighting offers potential advantages in terms of power efficiency. By selectively dimming or turning off specific zones of LEDs, local dimming techniques can be employed to enhance contrast and black levels, resulting in improved picture quality while conserving energy. It's important to note that VfL backlighting is just one of several backlighting technologies available for LCD TVs.

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Hooke's Law can be given as follows sometimes:

The restoring force of a spring is equal to the spring constant multiplied by the displacement from its normal position:

F = -kx

Where, F = Restoring force of a spring (Newtons, N)

k = Spring constant (N/m)

x = Displacement of the spring (m)

The negative sign relates to the direction of the applied force and by convention, the minus or negative sign is present in F = -kx. The restoring force F is directly proportional to the displacement (x), according to Hooke's law. When the spring is compressed, the displacement (x) is negative. It is zero when the spring is at its original length and positive when the spring is extended.

Practically, Hooke's Law is applicable only within a limited frame of reference, and through experimenting, this statement proves to be true. Because materials cannot be compressed beyond a certain size or expanded beyond a certain size without some permanent deformation or change of their original state.

The law only applies under some conditions such as a limited amount of force or deformation. Factually, many materials will noticeably deviate from Hooke's law even before those elastic limits are reached.

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Answer: 45 degree

Explanation:

Since Range = Ucosø × T

Where T = total time.

Range = distance covered

T = 2usinø/ 2g

If you substitute T into the range formula, you will get

R = (Ucosø×2Usinø) / 2g

But in trigonometry, 2sinøcosø = sin2ø

Substitute it into the formula

R = Usin2ø/ 2g

If ø = 45 degree

R = Usin(2 × 45)/2g

R = Usin90 / 2g

But sin 90 = 1

Therefore,

Range R = U/2g

Therefore, 45 degree angle would be use for the greatest distance when the projectile leaves at zero height above ground.

Answer:

∴ the angle for greatest distance is 90°, where Vy = 0

Explanation:

maximum height of a projected object is highest vertical position of the trajectory object which depends on the initial velocity

formula for maximum height

H= u² sin²θ/2g

if θ = 90°, then sin²90° = 1

∴ the angle for greatest distance is 90°, where Vy = 0

for horizontal distance,

the range of a projectile is the horizontal distance.

R = u² sin2θ/g

if θ = 45°, then 2θ  = 90°

∴sin 90°= 1

Answer:

less dense than water

Explanation:

85 g / 100cm^3 = .85 gm/cm^3

density of water = 1 gm/cm^3   <===so the liquid is less dense than water

Answer:

okay did you park it LOL

Explanation:

The answer to the question What shape is the graph produced by a force vs acceleration graph is A. Linear

Since Force, F = ma where m = mass and a = acceleration. For constant mass, F ∝ a. That is, F is directly proportional to acceleration, a.

Since this is a linear relationship, the graph of force vs acceleration will be linear.

The answer to the question What shape is the graph produced by a force vs acceleration graph is A. Linear

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According to the diagram the equivalent resistance of the group is

40.05 ohms

The equivalent resistance is calculated by investigating the diagram to note that R2 and R3 are in parallel and both are in series to R1

Resistors in parallel is solved by

Resistors in parallel = 1/25.4 + 1/70.8

Resistors in parallel = 0.0535 ohms

Equivalent resistance

Equivalent resistance = Resistors in parallel + Resistor in series

Equivalent resistance = 0.0535 + 40

Equivalent resistance = 40.0535

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