a 4 kg box sits on a table. the side of the box facing the table measures 20cm x 30 cm. the pressure on the table is

Answer: it’s c

Explanation:I put that as my answer for an assignment and got it right

The correct option is the speed of the cart increases as the cart rolls down the ramp because the forces acting on the cart are unbalanced.

The push or pull on a mass-containing item changes its velocity. An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude.

Given that in the question there is a child who is doing experiment for an investigation, a student measures the speed of a cart as it rolls down a ramp. The student then records data in the table given in question we see that speed increases as cart goes down.

The speed of the cart increases as the cart rolls down the ramp because the forces acting on the cart are unbalanced.

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A) The mass of 28.76 mL of acetone is approximately 22.7 g.

B) The volume of 6.40 g of acetone is approximately 8.12 mL.

A) To determine the mass of 28.76 mL of acetone, we need to know the density of acetone. The density of acetone is approximately 0.789 g/mL. Therefore, we can calculate the mass as follows:

Mass = Volume * Density

Mass = 28.76 mL * 0.789 g/mL

Performing the calculation:

Mass ≈ 22.67564 g

Rounding the result to the correct number of significant figures, the mass of 28.76 mL of acetone is approximately 22.7 g.

B) To determine the volume of 6.40 g of acetone, we can rearrange the formula:

Volume = Mass / Density

Volume = 6.40 g / 0.789 g/mL

Performing the calculation:

Volume ≈ 8.116 g/mL

Rounding the result to the correct number of significant figures, the volume of 6.40 g of acetone is approximately 8.12 mL.

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The claim that Diego made and supported with the table is that 10+x2 is always greater then 2x, however this is not correct.

Diego is wrong because when x becomes 6 or greater than 6, 10+x² will no longer be greater than 2ˣ. Lets say that x becomes 6 and we plug it into the two equations, we will have the following:

10 + 6² = 46 and

2ˣ= 2 raised to the power of 6 = 64

Now in this case, Diego has been proved wrong because the value obtained fromt he second equation is greater than that of the first equation. So, it is not reasonable to agree with Diego's submission.

Question:

The table represent the following data:

x values: 1, 2, 3, 4, 5

10 + x2:   11, 14, 19, 26

2x:         2, 4, 8, 16,

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Answer: Chemical bond

Explanation:  This force is of an electric nature, and the attraction between electrons of one atom to the nucleus of another atom contributes to what is known as chemical bonds.

The ratio of the deflection when each is connected in turns to a cell of e.m.f 25 V and internal resistance 50 ohms is 13: 12

Internal resistance can be described as the resistance within a battery, or other voltage source, that causes a drop in the source voltage when there is a current.

The parameters given are :

Coil 1 = 50 turns

Coil 2 = 500 turns

Resistance 1 = 1022

Resistance 2 = 6002

Internal resistance = 50 ohms

Emf = 25v

I = 25/ 50+ 10

I = 25/60

I = 5/ 12 A

\(I_{2}\) = 25/50+ 600

 = 25/ 650

 = 5/ 130 A

The ratio of the deflection when each is connected in turns to a cell of e.m. 25 V and internal resistance 50 ohms =

Q1/ Q2

Q1 = N1 x B x \(I_{1}\) / c

Q2 = N2 x B x \(I_{2}\) / c

therefore Q/ Q2 = (50 x 5/12 )/ (500 x 5/130)

Q1 / Q2 = 12/ 13 which 13: 12

Therefore, The ratio of the deflection when each is connected in turns to a cell of e.m. 25 V and internal resistance 50 ohms is 13: 12.

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Answer: The image is at a distance of 24 cm on the right of the lens, it will be an inverted, real image and has a height of 7 cm.

Explanation: To determine the position of the image of the object, use the Lens Equation, which is described by:

\(\frac{1}{f} = \frac{1}{u} +\frac{1}{v}\)

where

f is focal length;

u is distance of the object from the lens;

v is distance of the image of the pbject from the lens;

Calculating the position of the image will be:

\(\frac{1}{v} =\frac{1}{f} - \frac{1}{u}\)

\(\frac{1}{v} = \frac{1}{8} - \frac{1}{12}\)

\(\frac{1}{v} = \frac{1}{24}\)

v = 24 cm

Note that the distance of the image from the lens is positive. This means that the formed image is positioned at the right of the lens and is inverted.

For the height of the image, it can be used the Magnification (M) of an image:

M = \(\frac{h_{i}}{h_{o}} = \frac{v}{u}\)

where:

\(h_{i}\) is the height of the image

\(h_{o}\) is the height of the object

For this image:

\(\frac{h_{i}}{3.5} = \frac{24}{12}\)

\(h_{i} =\) 2 * 3.5

\(h_{i}\) = 7 cm

The image formed for this lens is 24 cm on the right of the lens, inverted related to the object and has height of 7 cm.

The average speed for the total trip can be calculated by adding up the total distance traveled (193.0 km + 254.3 km + 245.9 km = 693.2 km) and dividing it by the total time taken (2.6 h + 3.8 h + 3.5 h = 10.9 h). the formula to calculate average speed is distance.

the average speed of the entire trip, which means we need to consider the total distance traveled and the total time taken. We are given the distances and times for each day, so we add them up to get the total distance and time. We then use the formula for average speed to calculate the answer. It is important to note that we should use significant figures in our answer, which means we round the answer to two decimal places as there are only two significant figures in the given distances and times.

Total distance = Distance on Day 1 + Distance on Day 2 + Distance on Day 3Total distance = 193.0 km + 254.3 km +  245.9 kmTotal distance = 693.2 km Total time = Time on Day 1 + Time on Day 2 + Time on Day 3 Total time = 2.6 h + 3.8 h + 3.5 h Total time = 9.9 h the average speed for the total trip.Average speed = Total distance /
Average speed = 693.2 km / 9.9 hAverage speed = 70.02020202 The given values have three significant figures, so round the answer to three significant figures.Average speed = 70.0km/h I apologize for the mistake in my main answer. The correct average speed for the total trip is 70.0 km/h.

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The energy of a photon is given as 3.03×10−19 J/atom. The wavelength of the photon is 656 nm (option D).

The energy of a photon is given by the equation E = hc/λ, where h is Planck's constant (6.626 x 10^-34 J s), c is the speed of light (2.998 x 10^8 m/s), and λ is the wavelength of the photon. To find the wavelength of the photon, we can rearrange the equation to λ = hc/E. Substituting the given energy of the photon (3.03 x 10^-19 J/atom) into the equation gives a wavelength of 656 nm, which is option D in the given choices. Therefore, the correct answer is option D, and we can use the equation E = hc/λ to calculate the wavelength of a photon if we know its energy.

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Answer:

under developed soil horizons

(a) The electric field at a point 5.0 cm from the negative charge and along the line between the two charges is -2.58825 x 10⁵ N/C, directed towards the negative charge. (b) The force on an electron placed at that point is 2.58825 x 10⁻⁵ N, directed towards the positive charge.

The electric field at a point due to a point charge is given by the equation E = k * q / r², where E is the electric field, k is the electrostatic constant (k = 9 x 10⁹Nm² /C² ), q is the charge, and r is the distance between the charges.

(a) To find the electric field at a point 5.0 cm from the negative charge, we need to calculate the electric field due to both charges and then subtract the electric field due to the positive charge from the electric field due to the negative charge.

The electric field due to the negative charge (q2) is given by E2 = k * q2 / r², where q2 = -6.4 x 10⁻⁸  C and r = 5.0 cm = 0.05 m.

Plugging in the values, we get E2 = (9 x 10 Nm² /C² ) * (-6.4 x 10 C) / (0.05 m)² = -2.58825 x 10⁵ N/C.

The negative sign indicates that the electric field due to the negative charge is directed towards the negative charge.

(b) To find the force on an electron placed at that point, we need to calculate the force due to both charges and then subtract the force due to the positive charge from the force due to the negative charge.

The force between two charges is given by the equation F = k * |q1 * q2| / r², where F is the force, q1 and q2 are the charges, and r is the distance between the charges.

The force on the electron due to the negative charge (q2) is given by F2 = k * |q2 * e| / r², where q2 = -6.4 x 10⁻⁸ C, e is the charge of an electron (e = -1.6 x 10⁻¹⁹ C), and r = 5.0 cm = 0.05 m.

Plugging in the values, we get F2 = (9 x 10⁹ Nm²/C²) * |-6.4 x 10⁻⁸ C * -1.6 x 10⁻¹⁹ C| / (0.05 m)² = 2.58825 x 10⁻⁵ N.

The positive sign indicates that the force on the electron is directed away from the negative charge, which is towards the positive charge.

So, the answers to the given questions are:

(a) The electric field at a point 5.0 cm from the negative charge and along the line between the two charges is -2.58825 x 10⁵ N/C, directed towards the negative charge.

(b) The force on an electron placed at that point is 2.58825 x 10⁻⁵ N, directed towards the positive charge.

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Answer: By increasing speed over a fixed period of time, you increase

the distance you travel in that period of time. If you drive 20 mph

for an hour, you go 20 miles. If you drive 30 mph for that same

hour, you go 30 miles. Just like you knew you would.

Explanation:

Answer:

B

Explanation:

Answer:

potential energy because if your on a rolloer coaster wacth the vid

Answer:

gravitational energy

Answer:

The locus of points where the electric field due to these lines is zero is;

Along the line between the lines closer to line#1 than line #2

Explanation:

The charges on the parallel lines #1 and #2 = Positive linear charge

The charge density on line #2, λ₂ = 2 × The charge density on line #1, λ₁

Therefore, we have;

λ₂ = 2 ×  λ₁

Electric field strength, E, is given as follows;

\(E = \dfrac{\lambda}{2\cdot \pi\cdot \epsilon_0\cdot d}\)

Therefore;

\(E_1 = \dfrac{\lambda_1}{2\cdot \pi\cdot \epsilon_0\cdot d}\)

\(E_2 = \dfrac{\lambda_2}{2\cdot \pi\cdot \epsilon_0\cdot d} = 2 \times\dfrac{\lambda_1}{2\cdot \pi\cdot \epsilon_0\cdot d}\)

E₂ = 2·E₁

E₂/2 = E₁

E₂/(2·d) = E₁/d

The strength of the electric field at a given distance from line #2 is 2 times the strength of the electric field from line #1 at the same distance

Therefore the strength of the electric field will be the same at a point twice the distance from line #2 than from line #1 which is a point closer to line #1 than line #2.

When two iron bars attract each other no matter which ends are placed close together, both are not magnets. Rather, both iron bars are ferromagnetic substances.

Iron and its alloys, cobalt, nickel, and some other rare-earth metals are ferromagnetic substances that can become magnetic when exposed to a magnetic field. To create a magnet, these substances can be magnetized by placing them in a magnetic field. Magnets also possess magnetic forces, which can be observed when two magnets are placed near to each other.

Magnets are substances that have the ability to produce a magnetic field around themselves. Magnets have north (N) and south (S) poles that are oppositely charged. Opposite poles (N-S) attract, whereas like poles (N-N, S-S) repel.

When two iron bars are brought close to each other, they will attract one other because both bars will experience opposite magnetic fields, causing a magnetic attraction.

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6.21 cm

where

Given:

solving step-wise:

\(\dashrightarrow \mathrm{T}=2 \pi \sqrt{\dfrac{\mathrm{L}}{\mathrm{g}}}\)

\(\sf \dashrightarrow \mathrm{0.5}=2 \pi \sqrt{\dfrac{\mathrm{L}}{\mathrm{9.8}}}\)

\(\dashrightarrow \mathrm{\dfrac{0.5}{2 \pi } }=\sqrt{\dfrac{\mathrm{L}}{\mathrm{9.8}}}\)

\(\dashrightarrow\sqrt{\dfrac{\mathrm{L}}{\mathrm{9.8}}}= \mathrm{\dfrac{0.5}{2 \pi } }\)

\(\sf \dashrightarrow{\dfrac{\mathrm{L}}{\mathrm{9.8}}}= (\mathrm{\dfrac{0.5}{2 \pi } })^2\)

\(\sf \dashrightarrow{{\mathrm{L}}= (\mathrm{\dfrac{0.5}{2 \pi } })^2*9.8\)

\(\sf \dashrightarrow{{\mathrm{L}}=0.06205922 \ m\)

\(\sf \dashrightarrow{{\mathrm{L}}=6.2059\ cm\)

\(\sf \dashrightarrow{{\mathrm{L}}=6.21\ cm\)             { rounded to nearest hundredth }

Let's see

\(\\ \rm\rightarrowtail T=2\pi \sqrt{\dfrac{l}{g}}\)

\(\\ \rm\rightarrowtail 0.5=2\pi \sqrt{\dfrac{l}{9.8}}\)

\(\\ \rm\rightarrowtail 0.783=\pi \sqrt{l}\)

\(\\ \rm\rightarrowtail 0.2494=\sqrt{l}\)

\(\\ \rm\rightarrowtail \ell=0.0622m\)

An electrically charged object can be used to attract any object with an opposite charge.

This is due to the fundamental principle that opposites attract and repel in physics.

Electric charge is a fundamental property of matter that gives rise to electromagnetic interactions. An electric charge, whether positive or negative, produces an electric field that surrounds it. This field exerts a force on any other charge in its vicinity that is either attracted to or repelled from it. Electric charge is a fundamental property of matter that produces a variety of electric phenomena. When the charge is concentrated in a localized region of space, the object is electrically charged. When there is a net accumulation of charge in an object, it becomes electrically charged. An electrically charged object produces an electric field in its vicinity, which exerts a force on other charged objects. An electrically charged object can be used to attract objects with an opposite charge or repel objects with the same charge.

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Answer:

ooh mmk

Explanation:

I think it’s b. 1350.0 KVA because if you calculate the peak load of the sawmill, it is directly related to the answer and of course you can check your work along the way to make sure it’s correct! :)

The researcher's observation that more auxin collects in the sides of stems and roots that are not exposed to light is likely due to the phenomenon of phototropism.

In the process of phototropism, light influences the direction and rate of growth of plant cells. In particular, light induces the cells on one side of a stem or root to create less auxin than the cells on the shaded side. Less auxin is produced on the lighted side and more auxin is produced on the shaded side as a result. The hormone auxin is essential for controlling the growth and development of plants. Auxin generally promotes cell growth and elongation at greater concentrations while inhibiting cell elongation at lower concentrations. Since the cells on the lighted side of the stem or root will contain less auxin when there is light.

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Answer:

8/15=0.53..., since the 3 is repeating, just stop at the 4th decimal place, thus

0.5333

Explanation:

Answer:

60a in a circuit with a 12v battery

Explanation:

60a in a circuit with a 12v battery

The density of O2 at cruising altitude, relative to sea-level, is approximately 0.379 times the density at sea-level.

The density of O2 at cruising altitude of 36,000ft, relative to sea-level, can be calculated using the relationship between pressure and altitude. At higher altitudes, the pressure decreases, which affects the density of gases.

To find the density of O2 at cruising altitude, we can compare the pressure at that height to the pressure at sea-level. The pressure decreases with altitude, so we need to determine the ratio of the pressures.

Assuming the temperature does not differ with increased altitude, we can use the ideal gas law equation:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature.

At sea-level, the pressure is around 1 atmosphere (atm). At cruising altitude, the pressure is lower. The relationship between pressure and altitude can be approximated using the barometric formula:

\(P = P0\cdot e^(-h/H)\)

where P0 is the pressure at sea-level, e is the base of the natural logarithm, h is the altitude, and H is the scale height.

In this case, we can substitute the given values: P0 = 1 atm, h = 36,000ft, and H = 8,400ft (approximately).

Using the barometric formula, we can calculate the pressure at cruising altitude:

\(P = 1 atm \cdot e^(-36,000ft/8,400ft)\)

P ≈ 0.379 atm

Now, to find the density of O2 at cruising altitude relative to sea-level, we can use the ideal gas law. The number of moles remains constant, so we can compare the densities using the ratio of the pressures:

Density at cruising altitude / Density at sea-level = Pressure at cruising altitude / Pressure at sea-level

Density at cruising altitude / Density at sea-level = 0.379 atm / 1 atm

Density at cruising altitude / Density at sea-level ≈ 0.379

Therefore, the density of O2 at cruising altitude, relative to sea-level, is approximately 0.379 times the density at sea-level.

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The expression for the radius and height of the cone can be obtained from

the property of a function at the maximum point.

Reasons:

The part used to form the cone = A sector of a circle

The length of the arc of the sector = The perimeter of the circle formed by the base of the cone.

\(Volume \ of \ a \ cone = \dfrac{1}{3} \cdot \pi \cdot r^3 \cdot h\)

θ/360·2·π·s = 2·π·r

Where;

s = The radius of he circular sheet metal

h = s² - r²

3·r²·s² - 4·r⁴ = 0

3·r²·s² = 4·r⁴

3·s² = 4·r²

\(\underline{\left \right. The \ radius, \, r =\sqrt{ \dfrac{3}{4}} \cdot s}\)

\(\underline{The \ height, \, h =\sqrt{s^2 - \dfrac{3}{4}\cdot s^2} = \dfrac{s}{2}}}\)

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The film "American Beauty" highlights the negative impact of capitalism and patriarchy on the lives of its characters. In today's media, harmful gender stereotypes are still prevalent and can send damaging messages to young people.

The film American Beauty explores the role of capitalism and patriarchy in shaping the lives of its characters. The character of Lester Burnham, played by Kevin Spacey, embodies the destructive effects of these systems on men's lives. Lester is a middle-aged man who feels trapped in his corporate job and loveless marriage, and he seeks to reclaim his life by rejecting the values of capitalism and patriarchy. However, his attempts to break free from these systems ultimately lead to his downfall.

The media today continues to perpetuate images that reinforce gender inequality and promote harmful stereotypes. For example, women are often portrayed as overly sexualized objects for male consumption, while men are portrayed as aggressive and dominant. These images can send damaging messages to young people about their roles and expectations in society. Young people may internalize these messages and believe that certain behaviors or attitudes are acceptable or expected based on their gender. This can perpetuate gender inequality and reinforce harmful gender norms and stereotypes. It is important for media creators to consider the impact of their images on young people and strive to promote positive and diverse representations of gender in media.

Therefore, The movie "American Beauty" emphasizes the detrimental effects of capitalism and patriarchy on its protagonists' lives. Harmful gender stereotypes are still pervasive in today's media and might give young people false impressions.

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Answer:

The answer is D.

Explanation:

Answer:

As a result, if the field lines are close together (that is, the field line density is greater), this indicates that the magnitude of the field is large at that point. If the field lines are far apart at the cross-section, this indicates the magnitude of the field is small. (Figure) shows the idea.

Explanation:

Answer: Choice A)

Explanation:

x for a smaller magnet at the position marked zin

Hi there!

\(\large\boxed{D. \text{ } 3.0 kg}}\)

Use the following equation to solve:

F = ma, where:

F = Force (N)

m = mass (kg)

a = acceleration (m/s²)

Thus:

15 = 5m

15/5 = m

mass = 3 kg