A 4.0-cm-tall candle flame is 2.0 m from a wall. You happen to have a lens with a focal length of 42cm.A) How many places can you put the lens to form a well-focused image of the candle flame on the wall? B) What are the distance between the candle and the lens for each location?

Answer:

C, T=D/S

Explanation:

Answer: -8.66 m/s2 (down)

Explanation:

Find the mass of the boulder:

F = ma

m=F/a = -3125N/9.8 m/s2 = 325 kg

F net = -3125 N + 370 N = -2815 N

now you can find a:

a = F/m = -2185 N / 325 kg = -8.66 m/s2

Answer:

the neutron star becomes a black hole

Answer:

neutron stars

Explanation:

not really sure of an explanation, but maybe try looking up for "What type of star ends up as a blackhole?" should help

The density of the ornamental metal is closest to the density of copper. The answer is (B) copper

The density of a substance is given by the mass of the substance divided by its volume:

density = mass / volume

We can use this formula to determine the density of the ornamental metal:

density = mass / volume = 0.445 kg / 5 x 10^3 m^3 = 8.9 x 10^-5 kg/m^3

Next, we can compare this density to the relative densities of gold, silver, copper, and zinc to identify the metal:

Gold: density = 19.3 x 10^3 kg/m^3

Silver: density = 10.5 x 10^3 kg/m^3

Copper: density = 8.9 x 10^3 kg/m^3

Zinc: density = 7.1 x 10^3 kg/m^3

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The amount of charge needed to create this situation is approximately 8.9876 x 10⁹ Coulombs.

It should be noted that 5.6104 x 10²⁸ elementary charges are needed to create this charge.

According to Coulomb's Law, the force of attraction or repulsion between two charges is proportional to the product of their magnitudes and inversely proportional to the square of their distance.

q = 1/4πε₀ ≈ 8.9876 x 10⁹ C

The amount of charge needed to create this situation is approximately 8.9876 x 10⁹ Coulombs.

Also, the number of elementary charges needed to create the charge calculated in the previous question is:

n = q/e = (8.9876 x 10⁹ C) / (1.6022 x 10^-¹⁹ C) ≈ 5.6104 x 10²⁸

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Answer:

8/15=0.53..., since the 3 is repeating, just stop at the 4th decimal place, thus

0.5333

Explanation:

Answer:

so basicly i cant do it for u because my computer is not leting me but you just got to search up answer or ask your teacher for help or like i do i say that i ternd it in and the teacher will say no you didint say that u did and she will say can u send it to me say no bc i deleted

Explanation:

hope this helps❤️

Answer:Its a Soild

Explanation:

The mechanical advantage of the screwdriver is 0.208.

Mechanical advantage is the ratio of the output force produced by a machine (especially a simple machine) to the applied input force.

The efficiency of a simple machine is determined by calculating their mechanical advantage (MA). Mechanical advantage is a measure of the force amplification attained by the machine.

According to this question, the screwdriver has a radius from the center to the outermost edge of the tip of 50.0 mm, and the radius of the handle of 240 mm. The mechanical advantage can be calculated as follows:

M.A = 50/240

M.A = 0.208

Therefore, 0.208 is the mechanical advantage of the simple machine.

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Answer: all of the above and yes

hope thsi helps

Answer:

Hey!

Your first answer is ALL OF THE ABOVE!

Your second answer is YES!

The reflection coefficient is approximately 0.025, which means that 2.5% of the incident wave intensity is reflected.

The amount of energy that is reflected depends on the difference in acoustic impedance between the two materials. Acoustic impedance is the product of the density and the speed of sound in the material.

\(R = [(Z2 - Z1)/(Z2 + Z1)]^2\)

Substituting the values into the formula for the reflection coefficient, we get:

\(R = [(Z2 - Z1)/(Z2 + Z1)]^2\)

\(R = [(1.1Z1 - Z1)/(1.1Z1 + Z1)]^2\)

\(R = [(0.1Z1)/(2.1Z1)]^2\)

\(R = 0.025\)

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C

becuz grasshopper can hear between 12-20kHz

The sequence a_n = cos(5/n) converges, and the limit is 1.

To determine whether the sequence converges or diverges, and find the limit if it converges, we will consider the sequence a_n = cos(5/n).

1. Recognize that we are dealing with a limit of a sequence as n approaches infinity: lim (n→∞) cos(5/n).

2. Recall that the cosine function is continuous and well-defined for all real numbers.

3. Apply the limit laws to the given expression: lim (n→∞) cos(5/n) = cos(lim (n→∞) 5/n).

4. Evaluate the limit inside the cosine function: lim (n→∞) 5/n = 0, since the numerator is constant and the denominator approaches infinity.

5. Substitute the limit back into the cosine function: cos(0).

6. Evaluate the cosine function at 0: cos(0) = 1.

So, the sequence a_n = cos(5/n) converges, and the limit is 1.

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When a filament electron interacts with an outer shell electron of tungsten but does not remove it, the most likely outcome is the production of a bremsstrahlung photon. Therefore, the correct answer is D) brems photon.

Bremsstrahlung radiation, also known as braking radiation, occurs when a charged particle (in this case, the filament electron) is deflected by the electric field of an atomic nucleus (the outer shell electron of tungsten). As the filament electron is decelerated, it emits a photon with energy equal to the lost kinetic energy. The energy of the bremsstrahlung photon depends on the initial energy of the filament electron. In this scenario, since the outer shell electron is not removed, the filament electron loses a portion of its kinetic energy, resulting in the emission of a bremsstrahlung photon. The given options of 50 keV photon and 70 keV photon are less likely because they suggest a specific energy value, which might not correspond to the actual energy of the bremsstrahlung photon produced in this particular interaction. The option of heat (C) is less probable since it implies a non-radiative transfer of energy, whereas bremsstrahlung photons are characterized by their electromagnetic radiation.

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Answer:

Charges B and C are negative

Explanation:

• We are certain of a law of magnetism that states "Field lines move from positive charge to negative charge"

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Answer:

B and C are negative.

Explanation:

This is because according to the law of charges in electric field line it says that the lines forming the electric field move from the positive terminal to the negative terminal,hence making B and C be negative as the lines are moving into them.

Hi there!

Recall Newton's Law of Universal Gravitation:

\(\large\boxed{F_g = \frac{Gm_1m_2}{r^2}}\)

G = Gravitational Constant

m1, m2 = mass of objects (kg)

r = distance between objects (m)

There is an INVERSE-SQUARE relationship between the gravitational force and the distance between the objects, so:

\(F_g = \frac{Gm_1m_2}{(\frac{1}{4}r)^2} = F_g = \frac{Gm_1m_2}{\frac{1}{16}r^2}\)

\(= 16G\frac{m_1m_2}{r^2} = 16F_g\)

Thus, the gravitational force between the objects would INCREASE by a factor of 16.

To draw vectors C⃗ = A⃗ + B⃗ and D⃗ = A⃗ − B⃗, plot vector A⃗ starting from the origin, then add B⃗ to its terminal point for C⃗ and subtract B⃗ from A⃗ for D⃗.

1. Begin by drawing a coordinate system or grid on a piece of paper or a graphing software.

2. Identify the initial point for vector A⃗. Let's assume it starts at the origin (0, 0).

3. Determine the magnitude and direction of vector A⃗. Suppose A⃗ has a magnitude of 4 units and a direction of 30 degrees above the positive x-axis.

4. From the initial point of A⃗, draw an arrow that represents vector A⃗ with the determined magnitude and direction.

5. Repeat steps 2-4 for vector B⃗. Suppose B⃗ starts at the origin (0, 0), has a magnitude of 3 units, and is directed 45 degrees below the positive x-axis.

6. Draw vector B⃗ from its initial point with the appropriate magnitude and direction.

7. To find vector C⃗, add vectors A⃗ and B⃗ algebraically. Place the initial point of vector B⃗ at the terminal point of vector A⃗, and draw an arrow from the initial point of A⃗ to the terminal point of B⃗. This represents vector C⃗.

8. To find vector D⃗, subtract vector B⃗ from vector A⃗. Place the initial point of vector B⃗ at the terminal point of vector A⃗, and draw an arrow from the initial point of A⃗ to the terminal point of B⃗. This represents vector D⃗.

By following these steps, you will have accurately drawn vectors C⃗ = A⃗ + B⃗ and D⃗ = A⃗ − B⃗. Remember to label the vectors appropriately for clarity.

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The length of string is 16.0 kg·m²/s

What is Mass?

Mass is a fundamental property of matter that quantifies the amount of substance or material present in an object. It is a scalar quantity, meaning it only has magnitude and no direction. Mass is commonly measured in units such as kilograms (kg), grams (g), or other appropriate units depending on the context.

a. Mass: 2.0 kg

Velocity: 2.0 m/s

Length of string: 2.0 m

Angular momentum: 8.0 kg·m²/s

b. Mass: 3.0 kg

Velocity: 1.0 m/s

Length of string: 2.0 m

Angular momentum: 6.0 kg·m²/s

c. Mass: 1.0 kg

Velocity: 3.0 m/s

Length of string: 2.0 m

Angular momentum: 6.0 kg·m²/s

d. Mass: 2.0 kg

Velocity: 1.0 m/s

Length of string: 4.0 m

Angular momentum: 2.0 kg·m²/s

e. Mass: 2.0 kg

Velocity: 2.0 m/s

Length of string: 4.0 m

Angular momentum: 8.0 kg·m²/s

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A 2-meter long massless rod supports a 12-Newton weight. The left end of the rod is held in place by a frictionless pin. In each case, a vertical force F is applied at different positions along the rod.

When the vertical force F is applied at the left end of the rod (0 meters from the left end), the entire weight of 12 Newtons is supported by the left end, and there is no force acting on the right end of the rod. The left end acts as a pivot point, and the rod remains in rotational equilibrium.

When the vertical force F is applied at the midpoint of the rod (1 meter from the left end), the weight of 12 Newtons is evenly distributed between the left and right ends of the rod. Each end supports a force of 6 Newtons. The rod remains in rotational equilibrium as the torques on both sides of the pivot point are balanced.

If the vertical force F is applied beyond the midpoint, closer to the right end of the rod, a greater portion of the weight is supported by the right end. This results in an imbalance of torques, causing the rod to rotate counterclockwise around the left end.

In summary, the distribution of weight and the position of the applied force determine the rotational equilibrium of the rod. When the applied force is at the left end, the rod remains stable. When the force is at the midpoint, the rod is also in equilibrium. However, if the force is applied beyond the midpoint, the rod will rotate.

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The minimum force required to pull the bottom box out from under the top box, we need to consider the forces involved. First, let's analyze the static case, where the boxes are not moving.

In this situation, the maximum static frictional force between the boxes can be calculated using the formula Fstatic = µs * N, where µs is the coefficient of static friction and N is the normal force.

The normal force acting on the bottom box is equal to its weight, N1 = m1 * g, where g is the acceleration due to gravity.

The maximum static frictional force between the boxes is then Fstatic = µs * N1.

If the applied force on the string is less than or equal to Fstatic, the bottom box will not move.

Now, if we want to calculate the minimum force necessary to overcome static friction and start moving the bottom box, we consider the force of kinetic friction, which is given by Forcekinetic = µk * N1.

The minimum force required to move the bottom box is equal to the force of kinetic friction, Fmin = Forcekinetic = µk * N1.

By substituting the given values, we can calculate the minimum force needed.

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Earth is allowed to have the most water of any earth or moon in the Solar System.

The Sun and the objects that circumvent it make up the gravitationally bound system known as the Solar System. The Sun accounts for the vast maturity of the system's mass, while Jupiter accounts for the remainder.

Albeit multitudinous heavenly bodies in the Planetary group have a hydrosphere. Oceanic water covers 71 of Earth's face, making it the only known Elysian body with stable bodies of liquid water. This water is necessary for life on Earth.

Ah, it feels good to be back home,- the main earth with open fluid water at the face at" room temperature" in lakes, swell, aqueducts, yet in addition in strong structure as ice covers and icy millions. Earth also has underground liquid water, ice, and water vapor in its atmosphere, which is a perk.

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Answer:

556

Explanation:

Answer:    

Explanation:

The kinetic energy of the bullet-block system is equal to the potential energy of the bullet-block system when it reaches its maximum height.

According to the principle of conservation of linear momentum, momentum before collsion is equal to momentum after collision. Let us now answer the questions individually.

1) The momentum of the bullet before collsion = (0.001 Kg * 35 m/s) = 0.35 Kgms-1

2) The kinetic energy of the bullet before collision = 0.5 * 0.001 * (35 m/s)^2 = 0.6125 J

3) Velocity after collsion is obtained from;

(0.001 Kg * 35 m/s) + (2 kg * 0 m/s) = (0.001 Kg + 2 kg) v

v = 0.35/2.001 =

v=0.1749 m/s

4) Total kinetic energy after collison = 0.5 * (0.001 Kg + 2 kg) * (0.1749 m/s)^2

= 0.031 J

5) The maximum possible potential energy of the bullet-block system when it reaches its maximum height = Total kinetic energy after collison = 0.031 J

6) The  maximum possible height of the bullet-block system is obtained from;

PE = mgh

h = 0.031 J/(0.001 Kg + 2 kg) * 9.8 ms-2

h = 0.0015 m or 0.15 cm

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Answer:

\(vf=vi+at\\vf=15\\vi=0\\a=?\\t=5\\\\15=0+a5\\a=\frac{15}{5} \\a=3\)

Therefore the acceleration is 3m/s^2

Explanation:

We will be using the kinematics big five equations. Specifically, the one without displacement (d).

Write out your values and substitute the, into the equation.

Solve for a.

Note. Starts from stop so vi=0

Answer:

825 Joules of energy would be correct if my math is right.

Answer:

Energy conversion

Explanation:

We regularly use automobile which runs on the chemical energy of the fuels such as diesel and petrol, the chemical energy from the fuel would convert into the thermal energy which is used to drive the engine of the vehicle,further the thermal energy converted into the mechanical energy which is used to drive the prime mover of the automobile.

It can be defined as the form of the energy in which heat is transferred from one body to another body due to their molecular movements, thermal energy is also known as heat energy.

We frequently utilize vehicles that operate on chemical energy from fuels like diesel and gasoline.

This chemical energy is transformed into thermal energy, which drives the engine of the vehicle, and then mechanical energy, which drives the prime mover of the vehicle.

Thus, we can say that the transfers and transformations of energy are necessary to operate the technology.

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Given data

*The given distance is s = 128 m

*The initial speed of the motorcycle is u = 0 m/s

*The final speed of the motorcycle is v = 32.6 m/s

The expression for the acceleration of the bike is given by the kinematic equation of motion as

Substitute the known values in the above expression as

Hence, the acceleration of the bike undergoes is a = 4.15 m/s^2

From the diagram it is clear that F is less than 8 N.

The term force is that which causes a push or a pull. A force is said to have acted on a body when the body in motion stops or an acceleration is given to a body that is at rest or the direction of the object that is in motion changes.

Having said this, we know that force is a vector quantity. This implies that force has both magnitude and direction. The direction of the force also has to do with the direction that that the force would cause the object to move.

Let us now look at the object as shown, we can see that the force that acts on the left hand side has a magnitude of about eight Newton. We are now to use this to deduce the correct statement.

We can then say from what we have in the diagram that the force F as shown to the right is less than 8 N.

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Answer:

= 7.88 × 10^-12 T

Explanation:

From the above question, we are told that:

Kinetic Energy of the proton is K. E = 10.0 MeV

Step 1

We convert 10.0 MeV to Joules

1 Mev = 1.602 × 10-13 Joules

10.0 MeV = 10.0 × 1.602 × 10^-13 Joules = 1.602 × 10^-12 J

Hence, the Kinectic energy of a proton = 1.602 × 10^-12 J

Step 2

Find the Speed of the Proton

The formula for Kinectic Energy =

K.E = 1/ 2 mv²

Where

m = mass of the proton

v = speed of the proton

K.E of the proton = 1.602 × 10^-12 J

Mass of the proton = 1.6726219 × 10^-27 kilograms

Speed of the proton = ?

1.602 × 10^-12J = 1/2 × 1.6726219 × 10^-27 × v²

1.602 × 10^-12J = 8.3631095 ×10^-28 × v²

v² = 1.602 × 10^-12/8.3631095 ×10^-28

v = √(1.602 × 10^-12/8.3631095 ×10^-28)

v = 43772331.227m/s

v = 4.3772331227 × 10^7m/s

Approximately = 4.4 × 10^7 m/s

Step 3

Find the Magnetic Field of that region of space

The formula for Magnetic Field =

B = m v / q r

We are told that the proton executes a circular orbit, hence,

mv = √2m(KE)

m = Mass of the proton = 1.6726219 × 10^-27 kg

K.E of the proton = 1.602 × 10^-12 J

v = speed of the proton = 4.4 × 10^7 m/s

q = Electric charge = 1.6 × 10^-19 C

r = radius of the orbit = 5.80Ã10^10 m

= 5.8 × 10^10m

Magnetic Field =

=√ (2 × 1.6726219 × 10^-27 kg × 1.602 × 10^-12 J) /( 1.6 × 10^-19 C × 5.80 × 10^10 m)

= 7.88 × 10^-12 T

The magnetic field in that region of space is approximately 7.88 × 10^-12 T