The image is formed 80 cm behind the lens, The image is 20 cm tall and is located 80 cm behind the lens.
Given:
Object height, h_o = 4.0 cm
Object distance, d_o = -16 cm (as the object is in front of the lens, the distance is negative)
Focal length, f = -20 cm (as the lens is diverging, its focal length is negative)
To find:
a. Image position, d_i
b. Image height, h_i
Solution:
a. The image position can be found using the lens formula :-
1/f = 1/d_i 1/d_o
Substituting the given values, we get:
1/-20 = 1/d_i + 1/-16
Simplifying and solving for d_i, we get:
d_i = -80 cm
b. The magnification produced by the lens is given by:
m = -d_i / d_o
Substituting the given values, we get:
m = (-(-80)) / (-16) = 5
Since the magnification is positive, the image is virtual and upright. The height of the image can be found using :- h_i = m * h_o
Substituting the given values, we get : h_i = 5 * 4.0 = 20 cm
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what is physical effect
Physical effects refer to the changes or alterations that occur in the physical properties of an object or system, as a result of a physical force or interaction.
What is physical effects?Physical effects are the modifications or changes that take place in an object's or system's physical characteristics as a result of a physical force or interaction.
These effects can be observed and measured through various physical phenomena, such as temperature, pressure, density, electric fields, and magnetic fields, among others.
Examples of physical effects include the deformation of a material under stress, the heating or cooling of an object when it is exposed to a heat source or cold environment, the change in pressure of a gas when it is compressed or expanded, the flow of electric current through a conductor, and the generation of magnetic fields around a magnet or current-carrying wire.
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If you wanted to discover the youngest stars you could find in some grouping of stars in the Galaxy, which type of star group would be the best to search?
Answer:
Associations Clusters
Explanation:
There is three basic type of clusters, globular clusters, open clusters, associations clusters. Associations cluster consist of younger stars that is younger than globular and open clusters stars.
To discover the youngest stars you could find in some grouping of stars in the Galaxy, type of star group would be the best to search is Associations Clusters.
What is galaxy?A galaxy is a massive cluster of gas, dust, billions of stars, and their solar systems that are all bound together by gravity. Earth is a planet in our solar system where we call home.
A galaxy cluster, also known as a cluster of galaxies, is a formation made up of hundreds to thousands of galaxies that are gravitationally coupled to one another.
There is three basic type of clusters, globular clusters, open clusters, associations clusters. Associations cluster consist of younger stars that is younger than globular and open clusters stars.
To discover the youngest stars in the galaxy the best group is Associations cluster.
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What type of motion do star trails result from?
Answer:
Star trails reflect Earth's rotation, or spin, around its axis. The Earth makes a complete rotation relative to the backdrop stars in a period of about 23 hours and 56 minutes.
During a baseball game, a batter hits a ball directly back to the pitcher who catches it. An observer flying over the stadium at a speed of 0.75c, measures 0.658 s as the time between the two events (hitting and catching the ball). What is the proper time interval between the two events? a. 0.658 s b. 0.435 s c. 0.994 s d. 0.288 s
e. 0.715 5
The proper time interval between the two events is 0.435 s. Hence, the correct option is (b) 0.435 s.
Given that an observer flying over the stadium at a speed of 0.75c, measures 0.658 s as the time between the two events (hitting and catching the ball).
To find the proper time interval between the two events.
The time interval measured by the observer is called the "dilated" time interval (t').
The proper time interval (Δt) is found using the formula,
Δt = t' / γ
where
γ = 1 / √[1 - (v/c)²] is the Lorentz factor, v is the velocity of the observer, and c is the speed of light.
Given:
v = 0.75c, t' = 0.658 s, and
c = speed of light = 3 × 10⁸ m/s
Thus,
γ = 1 / √[1 - (v/c)²]
= 1 / √[1 - (0.75)²]
= 1 / √(0.4375)
= 1 / 0.6614
= 1.5126
Therefore, Δt = t' / γ
= 0.658 / 1.5126
≈ 0.435 s
Therefore, the proper time interval between the two events is 0.435 s. Hence, the correct option is (b) 0.435 s.
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A car is traveling as its speed changes from rest to 25 m/s in 5 s. What is the acceleration of the race car in m/s2?
Answer:
a=2 m/s²
Explanation:
v=u+at
25=15 +5a
5a=10
a=2 m/s²
A hot air balloon is acted on by two forces. One force is its weight, equal to
2448 newtons. The second force is a buoyant force acting straight up,
equal to 2448 newtons. What change in the motion of the balloon will
result from the action of these two forces?
no change
rising
falling
Answer:
no change
Explanation:
The Newton's Second Law of motion states that when an unbalanced force is applied to an object, it causes an accelerated motion in the object, in the direction of the unbalanced force. So, if there is no unbalanced force, then there is no motion. In this case both the forces have same magnitude and opposite direction. Therefore, the unbalanced force will be zero:
Unbalanced Force = Upthrust - Weight
Unbalanced Force = 2448 N - 2448 N
Unbalanced Force = 0 N
hence, there will be no motion in the vertical direction. Therefore, the correct option is:
no change
Remi travels 160 meters in 4 seconds. What was Remi's initial speed if her final velocity was 6.9 m/s?
Answer:
73.1 m/s
Explanation:
Given:
Δx = 160 m
v = 6.9 m/s
t = 4 s
Find: v₀
Δx = ½ (v + v₀) t
160 m = ½ (6.9 m/s + v₀) (4 s)
v₀ = 73.1 m/s
when you go out to your car one cold winter morning you discover a 0.80- cm thick layer of ice on the windshield, which has an area of 1.2 m2 . if the temperature of the ice is -7.0 ∘c , and its density is 917 kg/m3 , find the heat required to melt all the ice.
The heat required to melt all the ice is Q = 2204.49 kJ
Mass = Density * Volume and Volume = Area * Width
The area of the ice is 1.2m² and the width is 0.80cm
Then volume of ice = 1.2 m² * 0.008 m = 0.0096 m³
So there is a mass of ice on the windshield
Mass (m) = 917 kg/m³ * 0.0096 m³ = 0.9312kg
The heat that must be reached in order for ice to melt
Q sen is the sensible heat up to melting temperature (T m = 0°C , assuming pressure =1 atm as windshield is exposed to atmosphere)
Let Q lat be the latent heat of melting ice at its melting temperature
1) Q sen = m ice * c ice * ( T final - T initial) = 0.9312 kg * 2.108 kJ / Kg °C ( 0°C - (-7°C)) = 13.74 kJ
2) Q lat = m ice * L ice = (0.9312 kg * 335 kJ/kg ) = 311.952kJ
Thus Q sum = Q sen + Q lat = 13.74 kJ + 311.952 kJ = 325.692 kJ
This is the minimum amount of heat required, since we have not considered heat losses to the surroundings.
The specific heat of ice (c ice) is 2.108KJ/Kg°C and the latent heat of ice and snow (L ice) is 335KJ/Kg
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Which of the following actions is an example of an improvement in human capital?
A
Michelle applies for a job as a mechanical engineer at Honeywell.
B.
Marcus hires three workers for his thriving electrical business.
C.
Hawk Builders of Phoenix builds two new hospitals.
D.
Frank's Furniture trains all of its employees to use computers.
Answer: D
Explanation:
Frank’s Furniture trains all of its employees to use computers is an example of an improvement in human capital.
A square wave can be synthesized as a series of odd harmonics with amplitudes
an=1na,n=1,2,3...., where a is the amplitude of the fundamental f1. Given that
a=10−3m find the amplitudes of the first five harmonics in the series of the square wave.
A square wave can be synthesized as a series of odd harmonics, where the amplitude of each harmonic is given by the formula an = 1/(na). In this case, the amplitude of the fundamental frequency (a) is 10^-3 m.
We are asked to find the amplitudes of the first five harmonics in the series.
1. For the first harmonic (n = 1), the amplitude is:
a1 = 1/(1 * 10^-3) = 1000 m
2. For the second harmonic, since n = 2 is not an odd integer, we skip it.
3. For the third harmonic (n = 3), the amplitude is:
a3 = 1/(3 * 10^-3) = 333.33 m
4. For the fourth harmonic, again n = 4 is not odd, so we skip it.
5. For the fifth harmonic (n = 5), the amplitude is:
a5 = 1/(5 * 10^-3) = 200 m
To summarize, the amplitudes of the first five harmonics in the square wave series are as follows: a1 = 1000 m, a3 = 333.33 m, and a5 = 200 m. Note that only odd harmonics contribute to the square wave, and even harmonics are not included in this analysis. The string vibrates at twice the fundamental frequency, which is the lowest possible standing wave. A wave is the vibration of a string. A vibrating string produces a sound with a constant frequency, or pitch, due to resonance. If the length or tension of the string is properly adjusted, a melodic tone will be created.
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What is a small sacle industry?
pls hurrryyyy!!!!!!!! please
Answer:
The penguins are gliding foward without stopping because there is no external force changing their state.
Explanation:
Newtons first law states that every object will remain at rest or in uniform motion in a straight line unless compelled to change its state by the action of an external force.
An organism that breaks down dead plants and animals, returning matter back into the soil, is called a
A.
herbivore.
B.
producer.
C.
competitor.
D.
decomposer.
Answer:
d. decomposer
Explanation:
they play a critical role in the flow of energythrough an ecosystem. They break apart dead organisms into simpler inorganic materials, making nutrients available to primary producers
why are unit of length mass and time independent with each other?
Collision 1: Blue Cart Initially at Rest Set the initial blue cart velocity to 0 m/s. Set the mass values to different values. Run the simulation and record the mass and velocity values. Before Collision After Collision mRed = _________ kg mBlue = _________ kg Use mass and velocity values to complete the following momentum table. Before Collision After Collision ∆Momentum Red Cart ________kg x _______m/s = ____________kg•m/s ________kg x _______m/s = ____________kg•m/s Blue Cart ________kg x _______m/s = ____________kg•m/s ________kg x _______m/s = ____________kg•m/s
Answer:
it is very hard but i am trying to help you.
Explanation:
Study the images of Earth’s crust and mantle in two different areas.
How is Item A different from Item B?
A. The crust under the ocean in Item A is thicker than the crust under the mountain in Item B.
B. The mantle under the ocean in Item A is thinner than the mantle under the mountain in Item B.
C. The crust in Item A is found partially below sea level as compared to the crust in Item B.
D. The mantle in Item A is located far below a mountain as compared to the mantle in Item B.
Answer:
The crust in Item A is found partially below sea level as compared to the crust in Item B.
Explanation:
You're welcome!
Answer: c. The crust in Item A is found partially below sea level as compared to the crust in Item B.
Explanation:
what is the hydrostatic force against a horizontal sqaure 2ft x 2ft at the bottom of a 3ft pool, liquid density
By following these steps, you will find the hydrostatic force acting against the horizontal square at the bottom of the 3ft pool with the given liquid density.
To calculate the hydrostatic force against a horizontal square (2ft x 2ft) at the bottom of a 3ft pool, you can follow these steps:
Step 1: Find the pressure at the bottom of the pool.
Hydrostatic pressure (P) can be calculated using the formula:
P = ρgh
where ρ (rho) is the liquid density, g is the acceleration due to gravity (32.2 ft/s²), and h is the depth of the pool (3ft).
Step 2: Calculate the hydrostatic pressure.
Use the given liquid density (ρ) and plug in the values into the formula:
P = ρ * 32.2 * 3
Step 3: Find the area of the horizontal square.
Area (A) = length × width = 2ft × 2ft = 4ft²
Step 4: Calculate the hydrostatic force.
Hydrostatic force (F) can be calculated using the formula:
F = PA
Substitute the calculated pressure (P) and area (A) into the formula:
F = P * 4
By following these steps, you will find the hydrostatic force acting against the horizontal square at the bottom of the 3ft pool with the given liquid density.
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safety is one of the main concerns surrounding nuclear power. one issue is that once fission in a reactor has been started, additional heat is produced from post-fission radioactive decays and will continue even after the reactor is shut off. for which of the essential safety functions does this cause the most trouble?
The essential safety function that is most troubled by the additional heat produced from post-fission radioactive decays, which continues even after the reactor has been shut off, is called decay heat removal. Decay heat is the heat that is produced as a result of nuclear fission and radioactive decay of the nuclear fuel inside the reactor even after the reactor has been shut down and the control rods have been inserted into the core to stop the nuclear reaction.
Therefore, the decay heat removal function is one of the most important safety functions of a nuclear power plant. This is because, if the decay heat is not removed from the reactor core, the core can overheat and cause a nuclear meltdown, which can have catastrophic consequences. Several cooling systems are used to remove decay heat from the reactor core, such as the primary coolant system, the secondary coolant system, and the emergency cooling system.
These systems remove heat from the reactor core and transfer it to the environment outside the power plant through a series of heat exchangers. It is essential to keep these cooling systems working in case of an emergency shutdown. If they fail, the reactor core will become too hot and could melt, releasing radioactive material into the environment, and leading to serious health risks and environmental damage.
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A car of mass 1470 kg is on an icy driveway
inclined at an angle of 40◦. The acceleration of gravity is 9.8 m.
If the incline is frictionless, what is the acceleration of the car Answer in units of m/s
Answer:
a = 7.5 m / s²
Explanation:
For this exercise let's use Newton's second law, let's create a coordinate system with the x axis parallel to the plane and the y axis perpendicular to the plane
Y axis
N - W cos θ = 0
N = mg cos θ
X axis
W sin θ = m a
mg sin θ = m a
a = g sin θ
let's calculate
a = 9.8 cos 40
a = 7.5 m / s²
A string 0.5 m long is used to whirl a 1.0 kg stone in a vertical circle at a uniform velocity
of 5.0 m/s. What is the force?
A force is an effect that changes, or accelerates, the velocity of a mass-moving object (such as one that is traveling from a state of rest).
Thus, It is a vector quantity since it can be a push or a pull and always has magnitude and direction. It is denoted by the letter F (formerly P) and is measured in newtons (N), the SI unit of force.
The net force acting on an object is equal to the rate at which its momentum varies over time, according to Newton's second law in its original formulation.
According to this equation, the acceleration of an item is directly proportional to the net force acting on it, is in the direction of, and has a constant mass.
Thus, A force is an effect that changes, or accelerates, the velocity of a mass-moving object (such as one that is traveling from a state of rest).
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The centripetal force acting on the stone, during the circular motion is 314.07 N.
Length of the string, L = 0.5 m
Mass of the stone attached to the string, m = 1 kg
Velocity with which the stone is moving through the vertical circlr, v = 5 m/s
Length, L = 2πr
Therefore, the radius of the circular path,
r = L/2π
r = 0.5/(2 x 3.14)
r = 0.0796 m
The expression for the centripetal force acting on the stone, during the circular motion is given by,
F = mv²/r
F = 1 x 5 x 5/0.0796
F = 25/0.0796
F = 314.07 N
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The world speed record on water was set on October 8, 1978 by Ken Warby. If Ken drove his motorboat a distance of 1500 m in 8.102s, how fast was his boat moving in meters per second and kilometers per hour?
Answer:
317.52 mi/hr
Explanation:
First convert Meters into miles as the answer is required in miles/ h
1000m = 0.62 mi
Now, convert second into hours
7.45s = 0.0001 hr
The speed of the boat would be
v = 0.62/0.0001
=317.52 mi/hr
(ii) a person scuffing her feet on a wool rug on a dry day accumulates a net charge of -34 mc. how many excess electrons does she get, and by how much does her mass increase?
The person gets 34 million excess electrons but her mass does not increase.
What is the mass ?Mass is a measure of the amount of matter in an object. It is typically measured in kilograms (kg), though other units like grams (g) and pounds (lbs) are also used. Mass is different from weight, which is a measure of the force of gravity on an object. Mass is constant in all gravitational fields, while weight changes depending on the strength of the gravitational field.
The person scuffing her feet on the wool rug is accumulating a net charge of -34 mc (microcoulombs). This means that she is gaining 34 million electrons. However, this does not increase her mass, since electrons have a very small mass compared to the overall mass of a person.
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A student completes a PET experiment using chloroplasts from leaves lacking pigments that absorb in the 550 nm to 600 nm wavelength range. Which color of light should they avoid in their experiment if they want to measure activity at different wavelengths? Absorbance 360 760 460560660 Wavelength (nm) O Blue O Orange O Yellow O Red O Violet Light Absorption Spectrum of Spinach Extract
The student should avoid using yellow light if they want to measure activity at different wavelengths.
Yellow light should not be used since it lacks the pigment necessary to absorb wavelengths between 550 and 580 that will cause it to be completely ineffective.
Color Wavelength (nm)
Red 650 - 800
Orange 590 - 640
Yellow 550 - 580
Blue 460 - 480
Indigo 440 - 450
Violet 390 - 430
In physics, a periodic wave's wavelength is the length over which its form repeats. It is a characteristic of other spatial wave patterns as well as traveling and standing waves.
It is the separation between two consecutive positions on a wave that correspond to the same phase, such as two close-by crests, troughs, or zero crossings. The reciprocal of wavelength is the spatial frequency. Wavelength is usually denoted by the Greek letter lambda ().
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Analyzing a blood sample usually involves which type of separation method?
Answer:(D.)
Explanation:
A small canon is placed on top of a fortification the cannon ball leaves the muzzle of the canon with a speed of 85 m/s
Answer:
Speed of cannonball just before it hits the ground is 90.77 m/s
Explanation:
Complete Question
A small cannon is placed on top of a fortification. the cannonball leaves the muzzle of the cannon with a speed of 85 m/s at an angle of 25°c above the horizontal. just before the cannonball hits the ground, the vertical component of velocity is 48 m/s downward. what is the speed of the cannonball just before it hits the ground? ignore air resistance.
Solution
Given
Speed = 85 m/s
The angle = 25 degrees
When it will hit the ground, then vertical velocity = 48 m/s
However, in the projectile motion, the horizontal component will not change
Vr = V cos (theta) = 85 * cos25
Speed of cannonball just before it hits the ground is
V’ = Sqrt (48^2 + (85 * cos 25)^2) = 90.77 m/s
answerplease …..(i had to cut off answet C but it is they have a shiny appearance
Metals have shiny apperances
Select the equation of the line parallel to y = -4x - 6 that passes through the point (1, 2).
O y= 4x-4
O y= 4x+6
O y= 4x+6
O None of the other answers are correct
O y=4x-4
2. What do you understand by balanced and unbalanced force
Balanced forces are forces that do not result to change in motion while unbalanced forces are forces that result to change in motion.
What is force?Force is defined as the product of mass and acceleration of an object. That is Force = mass × acceleration.
Balanced force is a type of force that do not result to change because the forces are equal in size and opposite.
Unbalanced force is a type of force that result to change because forces on the opposite sides are not equal.
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The first hill of a roller coaster is 42.0 meters high. The bottom of the first hill is 4.2 meters off the ground.The roller coaster cart has a mass of 4500 kg.
Calculate its potential energy at the top of the first hill.
Calculate its potential energy at the bottom of the first hill.
Challenge- What is the velocity of the cart at the bottom of the first hill?
Answer:
1.89*10⁶J
Explanation:
because 4500kg * 42m*10m/s² is 1890000J
A rock is thrown upward with a velocity of 27 meters per second from the top of a 35 meter high cliff on the way back down. When will the Rick be 5 meters from ground level? Round your answer to two decimal places
Given data
*The given veloicty of the rock is u = 27 m/s
*The given height of the cliff is h = 35 m
*The given height of the Rick from the ground level is s = 5 m
*The value of the acceleration doue to gravity is g = 9.8 m/s^2
The formukla for the time taken by the Rick at 5 meters from the ground level is given as
\(s=h+ut+\frac{1}{2}at^2\)Substitute the known values in the above expression as
\(\begin{gathered} 5=(35)+(27)(t)+\frac{1}{2}(9.8)t^2 \\ 4.9t^2-27t-30=0 \\ t=6.45\text{ s} \end{gathered}\)Hence, the time taken by the Ric at 5 meters above the ground lel is t = 6.45 s
Answer:
6.45 s
Explanation:
df = final position = 5 m a = accel of gravity = -9.81 m/s^2
do = original position = 35 m vo = original velocity = 27m/s
df = do + vot + 1/2 at^2
5 = 35 + 27t - (1/2)9.81t^2
-4.905 t^2+ 27t +30 = 0
Use quadratic formula a = -4.905 b = 27 c = 30
to find t = 6.45 s
(Ignore the negative value found with the Quadratic Formula)