Answer:
\(\lambda = 0.24 m\)
Explanation:
The string vibrates in the third harmonics, n = 3
Length of the string, l = 0.36 m
Frequency of the tone produced, f = 500 Hz
The speed of sound in air is 344 m/s
Calculate the speed of sound produced by the string in the third harmonics:
The frequency of sound is given by the formula:
\(f = \frac{nv}{2l} \\500 = \frac{3v}{2*0.36}\\500 * 2 * 0.36 = 3v\\v = 360/3\\v = 120 m/s\\v = \lambda f\\\lambda = v/f\\\lambda = 120/500\\\lambda = 0.24 m\)
Given:
String vibrates, \(n = 3\)Strings' length, \(l = 0.36 \ m\)Frequency, \(f = 500 \ Hz\)Speed of sound, \(v = 344 \ m/s\)As we know,
→ \(f = \frac{nv}{2l}\)
then,
→ \(500 = \frac{3v}{2\times 0.36}\)
→ \(360 = 3v\)
\(v = \frac{360}{3}\)
\(= 120 \ m/s\)
hence,
The wavelength will be:
→ \(v = \lambda f\)
or,
→ \(\lambda = \frac{v}{f}\)
By substituting the values,
\(= \frac{120}{500}\)
\(= 0.24 \ m\)
Thus the approach is correct.
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4. Explain how energy is transformed in a spring.
Answer:
As spring falls in a vertical plane, the change in gravitational potential energy is transformed to elastic potential energy.
Explanation:
To calculate the spring constant, Hooke's law was used, as well as potential energy to calculate the gravitational and elastic potential energy.
In an experiment, a thin sheet of material A,B, or C was used to divide two objects of different temperature in each trial, the conditions were identical except for the material of the thin sheet. The data table shows
the times in which the objects reached thermal equilibrium
Which material, if any, is the best thermal equilibrium
The best material for achieving thermal equilibrium can be determined by analyzing the data table. The time taken for each object to reach thermal equilibrium is dependent on the material used to divide them.
Material C appears to be the best as it takes the least amount of time for the objects to reach thermal equilibrium.
Based on the given information, the material that results in the shortest time to reach thermal equilibrium would be considered the best thermal conductor. To determine this, compare the times in the data table for materials A, B, and C. The material with the shortest time to reach thermal equilibrium is the best thermal conductor and, therefore, the best material for this experiment.
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Find the power dissipated in the 11.7 ohm
resistor in the figure. The 0.909 T uniform
magnetic field is directed into the plane of the
circuit and the 39.2 cm long conductor moves
at a speed of 4.97 m/s. Find the power dissipated in the resistor. Answer in units of mW.
The power dissipated in the 11.7 ohm resistor is 21.6 watts. The power dissipated in a resistor can be calculated using the formula P = \(I^{2}\)R, where P is power, I is current, and R is resistance.
To find the current, we can use Faraday's Law of Electromagnetic Induction, which states that the emf induced in a circuit is equal to the rate of change of magnetic flux through the circuit.
The magnetic flux can be calculated using the formula Φ = BAcosθ, where B is the magnetic field strength, A is the area of the circuit, and θ is the angle between the magnetic field and the area vector.
Since the conductor is moving perpendicular to the magnetic field, the angle between the field and area vector is 90 degrees, so cos(90) = 0. Therefore, the flux is simply Φ = BA.
The rate of change of flux is given by dΦ/dt, which is equal to BAd/dt, where d/dt is the time derivative of the length of the conductor moving through the magnetic field. The induced emf is then equal to ε = BAd/dt.
Using Ohm's Law, we can find the current in the circuit, which is given by I = ε/R. Substituting the values given in the problem, we get I = (0.909 T)(0.392 m)(4.97 m/s)/11.7 ohms = 1.38 A.
Finally, using the formula for power, we get P = \(I^{2}\) R = \((1.38 A) ^{2}\) (11.7 ohms) = 21.6 W. Therefore, the power dissipated in the 11.7 ohm resistor is 21.6 watts.
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How do you find the characteristic polynomial and eigenvalues?
A polynomial in linear algebra that has the eigenvalues as roots and is invariant under matrix similarity is known as the characteristic polynomial of a square matrix.
Among its coefficients are the determinant and the trace of the matrix. The characteristic equation of the matrix A is det (A - λI) = 0, and its roots (the values of λ) are referred to as characteristic roots or eigenvalues. Also, it is well known that each square matrix has a unique equation.
The characteristic equation of the matrix A is det(A - λI) = 0. The roots of the characteristic equation are eigenvalues λ of A. The equation (A- λ I)x = 0 has nonzero solutions that are associated eigenvectors of A.
At steady state, the response to a complex exponential (or sinusoid) at a specific frequency is the same complex exponential (or sinusoid), but its amplitude and phase depend on the system's frequency sensitivity at that frequency.
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what will the frequency be if 0.160 kg are subtracted from the original mass? try to solve this problem without finding the force constant of the spring.
Frequencies in both cases are \(& f_2=1.225 \mathrm{H}_z\) and \(}} \\& f_2=1.522 \mathrm{H}_z\)
What is frequency ?The frequency of a repeated event is its number of instances per unit of time. It differs from angular frequency and is sometimes referred to as temporal frequency for clarification. One event occurs per second when measuring frequency in hertz.
The quantity of waves that pass a set location in a predetermined period of time is known as frequency. Therefore, if a wave passes through in half a second, the frequency is 2 per second. The frequency is 100 times per hour if it takes 1/100 of an hour.
According to the given information
We got to know
A) the frequency of two spring
\(f=\frac{1}{2 \pi} \sqrt{\frac{k}{m}}\)
for Same spring
\(f \propto \frac{1}{\sqrt{m}}\)
So
\(& \frac{f_2}{f_1}=\sqrt{\frac{m_1}{m_2}} \Rightarrow f_2=f_1 \sqrt{\frac{m_1}{m_2}} \\\)
\(& f_2=1.35 \times \sqrt{\frac{0.75}{(0.16+0.75)}} 2=222=1 \frac{1}{2} \\\)
\(& f_2=1.225 \mathrm{H}_z\)
B)
\(& f_2=f_1 \sqrt{\frac{m_1}{m_2}} \\& f_2=1.35 \times \sqrt{\frac{0.75}{(0.75-0.16)}} \\& f_2=1.522 \mathrm{H}_z\)
Frequencies in both cases are \(& f_2=1.225 \mathrm{H}_z\) and \(}} \\& f_2=1.522 \mathrm{H}_z\)
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Kelly walks 5 km to school. It takes her 1.5 hours. Calculate her speed in m/s
A lawn mower is pushed with a force of 79 N. If 11,099 J of work are done on mowing the lawn, what is the total distance the lawn mower was pushed? Round your answer to a whole number (no decimal places).
Answer:
141m
Explanation:
the attractive or repulsive force between objects is called
A vessel is filled with a gas at a temperature 30c and a pressure of 760mmhg calculate the final pressure if the volume of the gas is double while it's heated at 80c
To solve this problem, we can use the combined gas law, which relates the pressure, volume, and temperature of a gas:
(P1 x V1) / T1 = (P2 x V2) / T2
where P1, V1, and T1 are the initial pressure, volume, and temperature, and P2, V2, and T2 are the final pressure, volume, and temperature, respectively.
First, let's convert the initial temperature of 30°C to Kelvin:
T1 = 30°C + 273.15 = 303.15 K
We can now set up the equation with the initial conditions:
(760 mmHg x V1) / 303.15 K = (P2 x 2V1) / 353.15 K
where V1 is the initial volume of the gas.
Simplifying this equation by multiplying both sides by 303.15 K and dividing by 2V1, we get:
P2 = (760 mmHg x 303.15 K) / (353.15 K) = 653.75 mmHg
Therefore, the final pressure of the gas is 653.75 mmHg when the volume is doubled and the temperature is increased to 80°C.
a person standing a certain distance from eleven identical loudspeakers is hearing a sound level intensity of 112 db. what sound level intensity would this person hear if two are turned off? in dB
The person would hear a sound level intensity of 138 dB if two of the eleven identical loudspeakers are turned off.
If the person is standing at a certain distance from eleven identical loudspeakers and hearing a sound level intensity of 112 dB, we can use the inverse square law to find the sound level intensity when two loudspeakers are turned off. The inverse square law states that the sound intensity decreases in proportion to the square of the distance from the source. Let's assume that the distance between the person and the loudspeakers is d. When all eleven loudspeakers are turned on, the sound intensity at the person's location is 112 dB. If two loudspeakers are turned off, there are nine remaining loudspeakers. The new distance from the person to each of the remaining nine loudspeakers is still d, so the new sound intensity, I_2, can be calculated using the inverse square law: I_1/I_2 = (d_2/d_1)^2
where I_1 is the initial sound intensity, d_1 is the initial distance, d_2 is the new distance, and I_2 is the new sound intensity.
We can rearrange this equation to solve for I_2: I_2 = I_1 * (d_1/d_2)^2
When two loudspeakers are turned off, there are nine remaining loudspeakers. Therefore, we can calculate the new sound intensity as:
I_2 = 112 dB * (11/9)^2 = 138 dB (approximately).
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If a person is standing at a certain distance from eleven identical loudspeakers, the sound intensity they hear will depend on several factors, including the distance from the loudspeakers, the power output of the loudspeakers, and the number of loudspeakers in operation.
Assuming that all eleven loudspeakers are producing the same level of sound intensity, and the person is equidistant from each speaker, turning off two of the speakers would result in a reduction of sound intensity at the person's location.
The reduction in sound intensity would depend on the specific configuration of the loudspeakers and the distance from the person to the loudspeakers, but we can estimate the reduction in sound intensity using the inverse square law.
The inverse square law states that the sound intensity at a given distance from a point source is inversely proportional to the square of the distance from the source. Therefore, if we assume that the person is equidistant from each of the eleven loudspeakers and the sound intensity at that distance is x, then the sound intensity at the person's location with two speakers turned off would be:
I = x * (9/11)^2
where I is the new sound intensity in watts per square meter.
To convert the sound intensity into decibels (dB), we can use the following equation:
L = 10 log10(I/I0)
where L is the sound level in dB, I is the sound intensity in watts per square meter, and I0 is the reference sound intensity of 10^−12 watts per square meter.
Using this equation and assuming a sound intensity of 1 watt per square meter at the person's location with all eleven speakers turned on, we can calculate the sound level with two speakers turned off as:
L = 10 log10((1 * (9/11)^2)/10^-12) ≈ 67 dB
Therefore, with two loudspeakers turned off, the person would hear the sound at a level of approximately 67 dB.
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The distance recorded for riding a motorcycle on its rear wheel without stopping is more than 320 km! Suppose the rider in this impressive position is traveling with an initial velocity of 8.0 m/s before accelerating. Then the rider travels 40.0 m at a constant acceleration of 2.00 m/s2. What is the rider's velocity after the acceleration?
Answer:
14.97m/sExplanation:
Given
Initial velocity of the car u = 8m/s
Distance travelled by the rider S = 40m
Acceleration a = 2m/s²
Required
rider's velocity after the acceleration v
Using the equation of motion
v² = u²+2as
v² = 8²+2(2)(40)
v² = 64+160
v² = 224
v = √224
v = 14.97m/s
Hence the rider's velocity after the acceleration is 14.97m/s
A spotlight on the ground shines on a wall 12 m away. If a man 2 m tall walks along the x-axis from the spotlight toward the building at a speed of 1.6 m/s, which is taken as the given dx/dt, how fast is the length of his shadow on the building decreasing when he is 4 m from the building
The speed of man when the length of his shadow on the building decreases when he is 4 m from the building will be 0.6 m/sec.
What is velocity?The change of distance with respect to time is defined as speed. Speed is a scalar quantity. It is a time-based component. Its unit is m/sec.
Distance from spot shines = 12 m away
Height of man,h=2 m tall
Speed of man +1.6 m/s,
Distance from the building = 4 m
Let the height of shadow= y,
CD=x
Height of man=2 m
Speed of man:
\(\rm \frac{dx}{dt} = 1.6 \ m/sec\)
As the triangle ABD and ECD are similar. The property of the similarity is found as;
\(\rm \frac{y}{2} = \frac{12}{x} \\\\ xy = 24\)
Differentiate the above question with respect to x;
\(\rm x \frac{dy}{dt}+y\frac{dx}{dt}=0 \\\\ x\frac{dy}{dt}= -y\frac{dx}{dt}\)
From the given conditions the man is 4 m from the building the value of the remaining distance x is;
x=12-4
x=8 m
Speed of man:
\(\rm \frac{dx}{dt} = 1.6 \ m/sec\)
On putting all the values we get;
\(\rm \frac{y}{2} = \frac{12}{x} \\\\ xy = 24 \\\\ 8y = 24 \\\\ y= 3\)
The speed of man when the length of his shadow on the building decreases when he is 4 m from the building;
\(\rm \frac{dy}{dt} = - \frac{3}{8} \times 1.6 \ m/sec \\\\\ \frac{dy}{dt} = 0.6 \ m/sec.\)
Hence the value of the speed for the given conditions willl be 0.6 m/sec.
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for the two different system/control volumes below, respond to the following question and statement concerning the applicatyion of the control volume equation to the continuity principle
For the two different system/control volumes below, respond to the following question and statement concerning the application of the control volume equation to the continuity principle.
The continuity principle is applied to control volumes in fluid mechanics to analyze the conservation of mass.
For both systems/control volumes, the control volume equation is used to describe this principle as follows:
Step 1: Identify the control volume in each system, which is the fixed region in space where fluid flows through.
Step 2: Apply the continuity principle, which states that the mass entering the control volume must equal the mass leaving the control volume, plus any accumulation of mass within the control volume. Mathematically, this is expressed as: Σm_in = Σm_out + Δm_cv
Step 3: For a steady-state flow, where there is no accumulation of mass within the control volume, the equation simplifies to:
Σm_in = Σm_out
Step 4: To apply this to the control volume equation, consider the mass flow rate (ρvA) for each inlet and outlet, where ρ is the fluid density, v is the fluid velocity, and A is the cross-sectional area.
Step 5: Finally, for each system/control volume, balance the mass flow rates at the inlets and outlets to ensure the continuity principle is satisfied.
By following these steps for both systems/control volumes, the control volume equation can be effectively applied to the continuity principle, ensuring the conservation of mass within each system.
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5. Which of the following is NOT a course goal?
For students to understand fitness principles
For students to establish a habit of physical activity
For students to do nothing
For students to enhance their level of physical fitness
Answer:
for students to do nothing
Explanation:
because doing nothing is not a course goal
A 30 kg child is in an elevator accelerating down at a rate of -5 m/s2.
a. Calculate the force of gravity on the child.
Answer:
The force is - 150 N
Explanation:
F = 30 • - 5 = - 150
The magnetic field at the center of a 1.5 cm diameter loop is 3.0 mT.
(a) What is the current in the loop?
(b) A long straight wire carries the same current found in part (a). At what distance from the wire is the magnetic field 3.0 mT?
The center of a 1.5 cm wide loop has a magnetic field of 3.0 mT. About 0.3 Amperes of current flow through the loop. A 3.0 mT magnetic field is present about 0.2 meters away from the wire.
To solve this problem, we can use the formula for the magnetic field produced by a current-carrying loop and the formula for the magnetic field produced by a current-carrying wire.
Answer of the following questions are below :
(a) The magnetic field at the center of a current-carrying loop is given by the formula:
\(B = \frac{\mu_0 \cdot I \cdot N}{2 \cdot R}\)
Where B is the magnetic field, μ₀ is the permeability of free space (4π × 10⁻⁷ T·m/A), I is the current, N is the number of turns in the loop, and R is the radius of the loop.
We are given that the magnetic field is 3.0 mT (3.0 × 10⁻³ T) and the radius of the loop is 1.5 cm (0.015 m).
Substituting these values into the formula, we can solve for the current:
\(3.0 \times 10^{-3} \, \text{T} = \frac{4\pi \times 10^{-7} \, \text{T}\cdot\text{m/A} \cdot I}{2 \cdot 0.015 \, \text{m}}\)
Simplifying the equation, we find:
\(I = \frac{(3.0 \times 10^{-3} \, \text{T}) \cdot (2 \cdot 0.015 \, \text{m})}{4\pi \times 10^{-7} \, \text{T}\cdot\text{m/A}}\)
Calculating this expression, we get:
I ≈ 0.3 A
Therefore, the current in the loop is approximately 0.3 Amperes.
(b) The magnetic field produced by a long straight wire carrying current is given by the formula:
\(B = \frac{\mu_0 \cdot I}{2\pi \cdot r}\)
Where B is the magnetic field, μ₀ is the permeability of free space (4π × 10⁻⁷ T·m/A), I is the current, and r is the distance from the wire.
We are given that the magnetic field is 3.0 mT (3.0 × 10⁻³ T).
Substituting these values into the formula, we can solve for the distance from the wire:
\(3.0 \times 10^{-3} \, \text{T} = \frac{4\pi \times 10^{-7} \, \text{T} \cdot \text{m/A} \cdot I}{2\pi \cdot r}\)
Simplifying the equation, we find:
\(r = \frac{4\pi \times 10^{-7} \, \text{T} \cdot \text{m/A} \cdot I}{2\pi \cdot (3.0 \times 10^{-3} \, \text{T})}\)
Calculating this expression, we get:
r ≈ 0.2 m
Therefore, the magnetic field of 3.0 mT is found at a distance of approximately 0.2 meters from the wire.
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scientific thinking usually starts with what?
Answer:
Ask a question.
Explanation:
Your question is the basis of any theory.
Which property do the elements in each column of the representative elements series of the periodic table have in common?(1 point)
number of neutrons
number of orbitals
number of valence electrons
number of protons
The property that the elements in each column of the representative elements series of the periodic table have in common is: number of valence electrons.
An atom can be defined as the smallest unit comprising of matter that forms all chemical elements. Thus, atoms are basically the building blocks of matters and as such determines or defines the structure of a chemical element.
Generally, atoms are typically made up of three distinct particles and these are protons, neutrons and electrons.
Periodic table is an organized tabular array of all the chemical elements arranged in order of increasing atomic number (in rows).
Valence electrons can be defined as the number of electrons present in the outermost shell of an atom. Valence electrons are used to determine whether an atom or group of elements found in a periodic table can bond with others. Thus, this property is typically used to determine the chemical properties of elements.
In the periodic table, chemical elements that are having the same number of valence electrons are found in the same column.
This ultimately implies that, all the chemical elements such as Hydrogen, Sodium, etc., with one (1) valence electrons in their outermost shell (S-orbital) are found in the first (1st) column of the periodic table.
In conclusion, property that the chemical elements in each column of the representative elements series of the periodic table have in common is number of valence electrons.
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7. If a graph is showing a positive slope, and the graph itself is a straight line, what must be the x and y axis if the straight
line is showing a constant acceleration?
An object has positive acceleration if it is accelerating and travelling in the right direction.
What does it signify if a position time graph has a straight line with a positive slope? A straight line with a positive slope will appear on the Position vs. Time graph of an item travelling forward at a constant speed. It shows that the object's velocity is constant and that it is travelling ahead.The y-axis of this sort of graph denotes position in relation to the starting point, while the x-axis denotes time. An object's distance from its beginning position at any given moment since it began moving is displayed on a position-time graph.In a distance-time graph, the object's speed is equal to the slope or gradient of the line. The line becomes steeper as the thing goes more quickly (and the greater the gradient).The starting point of the item is indicated by the y-intercept. An object's y-intercept is zero if it begins at the measuring instrument. Its y-intercept is 3 meters if it begins at a distance of 3 meters. When two items are in the same position, you may tell by where two lines intersect.To Learn more About Positive acceleration, Refer:
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Is best defined as the process by which a change in one part of a system results in changes to other parts of the system, which in turn affect the first part.
The answer is feedback.
How fast would a 20 kg dog have to run, to reach a momentum of 120 kg x m/s? Include unit in your answer. Worth 40 points!
Answer:
6 m/s
Explanation:
momentum= mass times velocity
120 = 20v
v = 120/20
Answer:
7
Explanation:
7
write any two conditoons at which a body of certain mass become weightless
A body of a certain mass could become weightless in the following two conditions:
1. In microgravity
2. In neutral buoyancy
Cheers,
qxxi
Two Pitot-static tubes are shown. The one on the top is used to measure the velocity of air, and it is connected to an air-water manometer as shown. The one on the bottom is used to measure the velocity of water, and it too is connected to an air-water manometer as shown. If the deflection h is the same for both manometers, then one can conclude that: V_A = V_W V_A < V_w V_A > V_w Briefly explain:
When the deflection h is the same for both manometers, the velocity of air and water, V_A and V_W, can be concluded to be the same. Therefore, V_A = V_W
Explanation:-
The Bernoulli equation, which expresses the conservation of energy in the movement of an incompressible fluid in a steady state, can be used to explain the working of the Pitot tube.
According to this principle, the velocity of a fluid, when it is passed via a constricted region, raises and the pressure lowers. Similarly, the pressure raises when the velocity of a fluid decreases.
So, this principle can be utilized to determine the velocity of a fluid by measuring the difference in pressures between the points where the velocity is higher and lower.
This measurement is accomplished using a device called a Pitot tube. The velocity of air and water can be measured using Pitot tubes connected to air-water manometers, which are illustrated above.
The difference in pressures, ΔP, can be obtained by measuring the difference in heights of the manometer fluids. The velocity of the fluid can be calculated using this ΔP and other system parameters.
When the deflection h is the same for both manometers, the velocity of air and water, V_A and V_W, can be concluded to be the same. Therefore, V_A = V_W. Therefore, option V_A = V_W is the correct answer.
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A hydraulic lift in a garage has two pistons: a small one of cross-sectional area 4.00 cm2 and a large one of cross-sectional area 250 cm2. (a) If this lift is designed to raise a 3500-kg car, what minimum force must be applied to the small piston
If this lift is designed to raise a 3500-kg car, a minimum force of 549.36 N must be applied to the small piston to raise the 3500-kg car.
The relationship between the force exerted on a piston and the pressure of the fluid in a hydraulic system is given by the equation F1/A1 = F2/A2. The hydraulic lift in a garage has two pistons: a small one of cross-sectional area 4.00 cm2 and a large one of cross-sectional area 250 cm2. If the lift is designed to raise a 3500-kg car, we can use the above formula to determine the minimum force required to raise the car.
(a)The minimum force required to raise the car can be found using the formula F = mg, where F is the force, m is the mass of the car, and g is the acceleration due to gravity, which is equal to 9.81 m/s². The mass of the car is 3500 kg. So, F = mg = 3500 kg × 9.81 m/s² = 34335 N
Now we can use the formula F1/A1 = F2/A2 to determine the force that must be applied to the small piston. We are given that A1 = 4.00 cm² and A2 = 250 cm².
Therefore,F1/A1 = F2/A2F1/4.00 cm² = 34335 N/250 cm²F1 = (4.00 cm²/250 cm²) × 34335 NF1 = 549.36 N
Therefore, a minimum force of 549.36 N must be applied to the small piston to raise the 3500-kg car.
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How much mass can be lifted by a weight lifter on the surface of the moon if he can lift 100 kg on the Earth?
Answer:
if u have to find mass then it always constant everywhere that is 100kg but if u have to find weight then it 1/6 of earth .
Explanation:
16.6666
a ten-loop coil having an area of 0.23 m2 and a very large resistance is in a 0.047-t uniform magnetic field oriented so that the maximum flux goes through the coil. the coil is then rotated, so the flux goes to zero in 0.34 s. what is the magnitude of the emf induced in the coil during the 0.34 s?
The magnitude of electromotive force is 0.32 volts.
We need to know about the electromotive force of induction to solve this problem. The emf induction appears when there is any change in magnetic flux. The magnitude of emf can be determined by
ε = N dΦ / dt
where N is coil turns, ε is electromotive force, dΦ is change in magnetic flux and dt is time interval.
From the question above, the parameters given are
B = 0.047 T
dt = 0.34 s
N = 10
A = 0.23 m²
Find the change in magnetic flux
dΦ = (B . A)
dΦ = ( 0.047 . 0.23 )
dΦ = 0.01081 Tm²
By substituting the given parameters, we can calculate electromotive force
ε = N . dΦ / dt
ε = 10 . 0.01081 / 0.34
ε = 0.32 volt
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plz help will give brainlest! if you cant help, well, merry christmas!
Fossils are found in:
sedimentary rock
metamorphic rock
sedimentary and metamorphic rock
sedimentary and igneous rock
most fossils are found in sedimentary rocks
Answer:
Sedimentary rock.
Explanation:
on Mars, the acceleration due to gravity is 3.8 m/s². what would a book weigh on the surface of Mars?
Answer: 5.5
Explanation: its simply different from the others
You have learned about two types of potential energy: gravitational and elastic. They both have the potential to become kinetic energy. What else is common to gravitational and elastic energy?
Type your answer below! <3
Explanation:
Gravitational and elastic potential energy are both forms of mechanical energy, which is the sum of kinetic energy (the energy of motion) and potential energy (the energy of position or configuration).
Both gravitational and elastic potential energy are stored energy that can be converted into kinetic energy. For example, when a ball is held at a height above the ground, it possesses gravitational potential energy due to its position above the ground. If the ball is then released, it will fall to the ground and its potential energy will be converted into kinetic energy as it gains speed. Similarly, when a spring is compressed or stretched, it possesses elastic potential energy due to the work done to compress or stretch it. If the spring is then released, it will return to its original shape and its potential energy will be converted into kinetic energy as it moves.
Both gravitational and elastic potential energy depend on the mass of the object and the distance it is from a reference point. The greater the mass of the object and the farther it is from the reference point, the more potential energy it has.
Both gravitational and elastic potential energy are measured in joules (J) in the International System of Units (SI).
What cause sound seismic and electromagnetic waves to transmit energy through different mediums
Answer:
Explanation:
Sound, seismic, and electromagnetic waves transmit energy through different mediums due to the motion of particles in the medium.
Sound waves transmit energy through the vibration of particles in a solid, liquid, or gas. The energy is transferred from particle to particle as the wave travels through the medium.
Seismic waves are created by the sudden release of energy from earthquakes, volcanic eruptions, or other geological events. These waves travel through the Earth's solid mantle and crust, transmitting energy through the vibration of particles in the rock.
Electromagnetic waves are a type of wave that does not require a medium to travel through. They are created by the motion of charged particles, such as electrons, and can travel through a vacuum, such as space. Electromagnetic waves transfer energy through the oscillation of electric and magnetic fields.