Answers
We are asked to determine the magnification of a concave mirror. To do that we will use the following formula:
\(M=\frac{h_i}{h_0}=-\frac{d_i}{d__0}\)Where:
\(\begin{gathered} M=\text{ magnification} \\ h_0=\text{ height of the object} \\ h_i=\text{ height of the image} \\ d_0=\text{ distance of the object } \\ di=\text{ distance of the image} \end{gathered}\)We are given the following values:
\(\begin{gathered} h_0=5cm \\ d_0=2.7cm \\ h_i=14.3cm \end{gathered}\)Therefore, we can use the following to determine the magnification:
\(M=\frac{h_i}{h_0}\)Substituting the values:
\(M=\frac{14.3cm}{5cm}\)Solving the operation:
\(M=2.86\)Therefore, the magnification is 2.86
Related Questions
10The diagram above shows two pulses approaching each otherin a uniform medium. Which diagram best represents thesuper-position of the two pulses?
Answers
We have two pulses if we super position the two pulses is like we do the next operation
\(10-5=5\)10 is upwards we take it as a positive
5 is downwards we take it as a negative
therefore the digram will be
which object has a weight of about 22.5 n the book the rock the box the fish
Answers
Answer: The rock
Explanation:
A steel playground slide is 5.25 m long and is raised 2.75 m on one end. A 45.0 kg child slides down from the top starting at rest. The final speed of the child at the bottom is 6.81 m/s. Find the average force of friction between the child and the slide.
Answers
Answer:
\(F=32.24N\)
Explanation:
From the question we are told that:
Height \(h= 2.75 m\)
Length\(l = 5.25 m\)
Mass \(m=45kg\)
Final speed \(v_f=6.81\)
Generally the equation for Potential Energy P.E is mathematically given by
\(P.E=mgh\)
Therefore
Initial potential energy
\(P.E_1=45*9.8*2.75 \\\\P.E_1= 1212.75 J\)
Generally the equation for Kinetic Energy K.E is mathematically given by
\(K.E=0.5mv^2\)
Therefore
Final kinetic energy
\(K.E_2= 1/2*45*6.81*6.81 \\\\K.E_2= 1043.46J\)
Generally the equation for Work_done is mathematically given by
\(W=P.E_1-K.E_2\\\\W=169.3\)
Therefore
\(F=\frac{W}{d}\\\\F=\frac{169.3}{5.25}\)
\(F=32.24N\)
Solve for the mass of a planet with an orbital radius of 4 AU and an orbital period of 4 Earth years,
orbiting a star whose mass is 3 solar masses.
Answers
The mass of the planet orbiting through the path can be calculated using its period of orbit, and radius . Here, the mass of the planet be 7.11 × 10³⁰ kg.
What is orbital period ?The orbital period of a spatial object is the time taken to revolve around a star or another spatial object through out an elliptical orbit.
The mass of the star can be calculated using the formula :
m = 4 π r³/G T²
given,
r = 4 Au = 4 × 1.5 × 10¹¹ m
T = 4 years = 12.6 × 10⁷ seconds.
G = gravitational constant 6.67 × 10⁻¹¹ m³/kg s²
Then M = 4 × 3.14 × (4 × 1.5 × 10¹¹ m)³/ 6.67 × 10⁻¹¹ m³/kg s² × ( 12.6 × 10⁷ s)²
= 7.11 × 10³⁰ kg.
Therefore, the mass of the planet is 7.11 × 10³⁰ kg..
Find more on orbital period :
https://brainly.com/question/6502290
#SPJ9
A thin infinite nonconducting sheet with uniform surface charge density σ = 11.0·10-6 C/m2 lies in the y-z plane. A charge Q = 6.50 μC is located on the x axis at a distance x= 30.00 cm from the sheet as shown.
Find the magnitude of the electric field at a point P with the coordinates x= y= 30.00 cm, z= 0.
What work must be done against the electric forces in order to move the charge Q from the position x= 30.00 cm to the position x= 20.00 cm on the x axis?
Answers
The electric field's magnitude at point P with coordinates is 8.85 mm. E= 2ϵ o/σ and l= 10 −7 ∧2×50×8.85×10 −12
How can one determine the surface charge of an infinite line?E=σ2ϵ0. The proximity of P to the infinitely charge sheet has no bearing on this. The lines of something like the magnetic charge are continuous, homogenous parallel lines.
E = /20r is the magnitude of the electric field produced by an infinite line that is uniformly charged, where r is the distance between the line and the spot where the field is being measured and represents the linear charges density.
The formula is = Q 0. The electric field produced by an infinite thin sheet that is equally charged is given by the equation E=20n, where E is just the electric field, is the area positive charge, and 0 is the electric constant.
To know more about infinite line visit:
brainly.com/question/14568868
#SPJ1
What is the current in a 160V circuit if the resistance is 200?
Answers
R=2ø
I = ? I= v/r
I= 120r/ 10
Answer 12Amps
. A gas cylinder contains 30 liters of diatomic nitrogen gas at 273 K and a pressure of 140 atm. If the temperature is increased to 300 K, how much will the internal energy of the gas increase?
Answers
Answer:
If the temperature is increased to 300 K, the gas molecules will have an increase in kinetic energy. This will increase the internal energy of the gas as kinetic energy is one type of internal energy. However, the pressure will also increase as the gas molecules hit the walls of the cylinder with more force. This increase in pressure will decrease the internal energy of the gas as it takes more energy to compress the gas molecules.
Explanation:
electricity is one kind of
Answers
Answer:
I think electricity is one kind of energy
A plank AB 3m long weighing 20kg and with center of gravity 2m from the end A carries a load of mass 10kg at the end A it rests on two supports CandD.
1, compute the values of the reaction forces R1 and R2 at C and D.
2, how far from D and on which side of it must a mass of 24kg be placed on the plank so as to make the reactions equal? What are their values.
3,without this 24kg what vertical force applied at B will just lift the plank clear of D? What is then the reaction at C.
Answers
The answers are 1) The value of R2 is not relevant as it implies a downward force on the plank, 2) The reactions at C and D are 66.3 N and 90 N, respectively, and 3) The vertical force at B to lift the plank clear of D is 686.4 N. The reaction at C is zero, and the reaction at D is 61.4 kg.
1) R1 and R2 at C and D respectively are given by the equation R2 = (m1 + m2)g - R1, where m1 and m2 are the masses of the plank and load, respectively, and g is the acceleration due to gravity. Hence, substituting values R2 = (20 + 10) × 9.81 - R1 = 294.3 - R1. Now, taking moments about D, the following equation can be obtained: (20 × 1 + 10 × 3)g = R1 × 2 + R2 × 3 = 2R1 + 3 × (294.3 - R1) = 882.9 - R1, from which R1 = 343.7 N and R2 = 294.3 - 343.7 = -49.4 N. Since the support at D can only push the plank upwards and cannot pull it downwards, a negative value for R2 implies that the plank is actually being pulled downwards by an external force. Therefore, the value of R2 is not relevant. 2) The total weight of the plank and the load acting at the end A is 20 + 10 = 30 kg. For the reactions at C and D to be equal, the 24 kg mass must be placed at a distance x from D such that x × 30 = 24 × 6, from which x = 12/5 = 2.4 m. Since the 24 kg mass is being placed to the left of the plank, it will cause the reaction at C to decrease and that at D to increase. Thus, if R is the vertical force applied at B, then taking moments about D gives 20g × 1 - 10g × 3 + R × 6 = 0, from which R = 90 N. Taking moments about C gives R × 3 - 10g × 2 = 0, from which R = 66.3 N. 3) The vertical force applied at B that will just lift the plank clear of D is the weight of the plank and the load acting at the end A plus the weight of the part of the plank that is to the right of D. The weight of the plank and the load acting at the end A is 20 + 10 = 30 kg, and the weight of the part of the plank that is to the right of D is 24 × 1.6 = 38.4 kg. Therefore, the vertical force applied at B that will just lift the plank clear of D is (20 + 10 + 38.4)g = 686.4 N. The reaction at C is zero because the plank is not being supported there anymore. The reaction at D is the same as the weight of the plank and the load acting at the end A plus the weight of the part of the plank that is to the right of D, which is 20 + 10 + 24 × 1.6 = 61.4 kg.For more questions on acceleration
https://brainly.com/question/460763
#SPJ8
A 30kg metal ball is dropped from a height of 12.5 m.
a. Find the final velocity when the ball hits the ground.
b. Find the time it takes for the ball to hit the ground.
Answers
From conservation of linear momentum, the final velocity is 15.7 m/s and the time taken is 1.6 s
What is Velocity ?Velocity can be defined as a distance travel in a specific direction per time taken. It is a vector quantity.
Given that 30kg metal ball is dropped from a height of 12.5 m.
a. Find the final velocity when the ball hits the ground.
The maximum K.E of the ball at it final velocity will be equal to its maximum P.E at height 12.5 m. That is,
K.E = P.E
1/2mv² = mgh
Where
m = 30 Kgg = 9.8 m/s²h = 12.5 mv = ?Substitute all the parameters
1/2 × 30 × v² = 30 × 9.8 × 12.5
v² = 245
v = √245
v = 15.65 m/s
b. The time it takes for the ball to hit the ground can be found through
h = ut + 1/2gt²
but u = 0
h = 1/2gt²
Substitute all the necessary parameters
12.5 = 1/2 × 9.8 × t²
12.5 = 4.9t²
t² = 12.5/4.9
t² = 2.55
t = √2.55
t = 1.6 s
Therefore, the final velocity when the ball hits the ground is 15.65 m/s and the time it takes for the ball to hit the ground is 1.6 s
Learn more about Velocity here: https://brainly.com/question/24445340
#SPJ1
Philosophy:The Big Picture Unit 7
Why does Marx’s workers’ paradise resolve the problems of capitalism?
I KNOW C IS INCORRECT SO CHOOSE OUT OF A,B OR D
A. Everything is free, and no one has to work.
B. Workers are divided into three classes, much like in Plato’s ideas.
C. There is no currency in the paradise so no economic problems.
D. People work for their own good instead of a factory owner’s.
Answers
Answer:
B
Explanation:
If you cross of what you don't think are the answers then it makes it easier to narrow it down to what the answers are.
Hope this helps!
1) Prove that for the adiabatic process of gas pVr =const ; r=Cp/Cv *
2) Write down the expression for the number of molecules of N2 gas having speeds in the interval (100m/s ; 102m/s) for one mole of gas at T=300K
3) Demonstrate how to obtain the Boltzmann Distribution of Energies from the Maxwell-Boltzmann distribution of speeds.*
Answers
For an adiabatic process of gas PV(^r)= Constant, where r = Cp/Cv , Cp, and Cv are constants for a particular gas.
What is an ideal gas?It is an imaginary gas for which the volume occupies by it is negligible, this gas does not exist in a practical situation and the concept of an ideal gas is only the theoretical one.
Universal Gas Equation for the ideal gas,
PV=nRT
By differentiating on both sides: P.dV + V.dP = n.R.dT…. (1)
For the adiabatic process, the expansion or compression of gas occurs at a very fast rate which makes no heat transfer. Therefore, dQ= 0
A/c to First Law of TD: dQ=dU+ dW, implies dU= -dW=-P.dV ….. (2)
But dU= n.Cv. dT …. (3) Combining 2 and 3, we get: n.dT= -P.dV/Cv …..(3)
Using R= Cp-Cv, the gas law gives: from 1 and 3.
n.dT= (P.dV + V.dP)/(Cp-Cv) = -PdV/Cv
On rearranging terms we get, (dP/P)+((Cp/Cv)*(dV/V))=0
Cp and Cv are constants for a particular gas, hence integrating,
Ln(P)+ r.Ln(V)=constant (replacing Cp/Cv = r or Gamma)
Hence, P.V(^r)= constant is termed an adiabatic equation.
To learn more about ideal gas from here, refer to the link;
brainly.com/question/8711877
#SPJ1
In which part of a lab report would be the following sentence most likely occur? “Since the data showed that the
Answers
Answer:
most likely be included in the analysis section of a lab report
Explanation:
A cello string vibrates with a frequency of 64 Hz. If the wavelength of the waves in the string is 180 cm, calculate the wave speed.
Answers
Answer: The wave speed of the cello string is 115.2 m/s.
Explanation:
The wave speed (v) can be calculated using the formula:
v = f * λ
where
f = frequency (64 Hz)
λ = wavelength (180 cm)
To convert the wavelength from cm to meters we divide by 100
λ = 180 cm / 100 = 1.8 m
so
v = 64 Hz * 1.8 m = 115.2 m/s
So, the wave speed of the cello string is 115.2 m/s.
what is the change of entropy if 536 g of gold are melted?
Answers
Answer: Therefore, the change in entropy when 536 g of gold are melted is 0.132 J/K.
Explanation: To calculate the change in entropy when 536 g of gold are melted, we need to know the entropy of fusion of gold and the temperature at which it melts.
The entropy of fusion of gold is 2.35 J/g·K, and the melting point of gold is 1064 °C or 1337 K.
The change in entropy when gold is melted can be calculated using the formula:
ΔS = Q/T
where ΔS is the change in entropy, Q is the heat absorbed during the process, and T is the temperature at which the process occurs.
The heat absorbed when gold is melted can be calculated using the formula:
Q = m × ΔH_fus
where m is the mass of the gold and ΔH_fus is the enthalpy of fusion of gold, which is 64.9 kJ/mol.
Converting the mass of gold to moles:
536 g / 196.97 g/mol = 2.72 mol
The heat absorbed by the gold when it is melted is:
Q = 2.72 mol × 64.9 kJ/mol = 176.2 kJ
Finally, we can calculate the change in entropy:
ΔS = Q/T = 176.2 kJ / 1337 K = 0.132 J/K
1)What is the pressure at point D in kPa ?
2)Temperature at point D
3)What is the net work done on the gas as it is taken through four cycles?
4)What is the internal energy of the gas when it is at point A?
5)What is the total change in internal energy of this gas during four complete cycles?
Answers
The answer is 1) The pressure at point D is 80 kPa. 2) The temperature at point D is 800 K. 3) The net work done on the gas over four cycles is zero. 4) The internal energy of the gas at point A is 100 J. 5) The total change in internal energy during four complete cycles is zero.
The total change in internal energy of this gas during four complete cycles is zero. The given diagram represents the Carnot cycle involving four stages. The four stages of the Carnot cycle are reversible and follow an ideal gas that is placed in a cylinder with a movable piston.Let's solve each question asked one by one.1) From the graph, it can be observed that the pressure at point D is 0.08 M Pa, which is equal to 80 kPa. Hence, the pressure at point D in kPa is 80 kPa.2) Temperature at point D The isotherm at point D is about 800 K. Hence, the temperature at point D is 800 K.3) The net work done on the gas as it is taken through four cycles is zero because the Carnot cycle is a cycle that has four stages. In each cycle, the net work done is the area enclosed by the cycle. Therefore, for a complete cycle, the net work done is zero because the area enclosed is a loop.4) The internal energy of the gas when it is at point A is 100 J because the internal energy of the gas is directly proportional to the temperature and volume. Here, at point A, the temperature is 500 K, and the volume is 2 m³, so the internal energy of the gas when it is at point A is 100 J.5) The Carnot cycle is a reversible cycle that is used to determine the efficiency of heat engines. It is a closed cycle that does not involve any net energy exchange with the surroundings. Therefore, the total change in internal energy of this gas during four complete cycles is zero since the initial and final states are the same. Hence, the total change in internal energy of this gas during four complete cycles is zero.For more questions on the Carnot cycle, click on:
https://brainly.com/question/25819144
#SPJ8
I have multiple voltage sources of different rating like 5V,6V,1V and 20V draw schematic diagram using these sources to power a light of rating 11 volt
Answers
Answer:
add molecules
A 5 kg block is pulled along a horizontal surface by a 28N force to the right. Compute
the acceleration of the block if the surface is
a)
smooth,
b)
rough with a coefficient of kinetic friction of 0.23 between the block and the
surface.
[ 5.6ms 2,3.4ms]
Answers
(a) Without friction, Newton's second law tells us the net horizontal force is such that
28 N = (5 kg) a
a = (28 N) / (5 kg)
a = 5.6 m/s²
(b) With friction (magnitude f ), we get a net horizontal force such that
28 N - f = (5 kg) a
and a net vertical force such that
n - w = 0
since the block is only being pulled horizontally, where w is the weight of the block and n is the magnitude of the normal force. So
n = w = (5 kg) (9.8 m/s²)
n = 49 N
Friction is proportional to the normal force such that
f = µ n
We're given µ = 0.23, so
f = 0.23 (49 N)
f ≈ 11 N
Solve for a :
28 N - 11 N = (5 kg) a
a = (17 N) / (5 kg)
a = 3.4 m/s²
Which of the following are evidence of what happened in the past?
A.
volcanoes and plate movement
B.
weathering and rain
C.
weather and erosion
D.
earthquakes and climate
Answers
Answer:
A
Explanation:
volcanoes and plate movement
SuperPointParticleDog is playing tug of war with two other dogs, Isaac and Newton. Isaac is pulling with a force of 255 N, 13 degrees North of East on one rope attached to a ball. Newton is pulling with a force of 156 N, 34 degrees South of East on another rope attached to the ball. If the ball is moving with constant momentum toward SuperPointParticleDog, what is the East/West component of her force on the ball?
Answers
The East/West component of SuperPointParticleDog's force on the ball is -115.7 N. (Westward).
How to explain tje informationIsaac's force:
Magnitude: 255 N
Angle: 13 degrees North of East
x-component: 255*cos(13) = 245.1 N (Eastward)
y-component: 255*sin(13) = 58.1 N (Northward)
Newton's force:
Magnitude: 156 N
Angle: 34 degrees South of East
x-component: 156*cos(34) = 129.4 N (Westward)
y-component: 156*sin(34) = 86.5 N (Southward)
Now we can add the x- and y-components of the forces to find the net force:
Net force:
x-component: 245.1 N - 129.4 N = 115.7 N (Eastward)
y-component: 58.1 N - 86.5 N = -28.4 N (Southward)
The net force has an Eastward component of 115.7 N. Therefore, the East/West component of SuperPointParticleDog's force on the ball is -115.7 N. (Westward).
Learn more about force on
https://brainly.com/question/12970081
#SPJ1
compare the times of all sunsets during the same period what do you observe
Answers
Answer:
Theres no given?
Explanation:
Well, whatever.
I observed the shift of their sunset time.
Examples like:
January to June = their sunset time increased while
July to December = their sunset time decreased
Please I need help!!
Answers
Answer: A
Explanation:
plz answer as fast as u can plz
Answers
Answer:
C Power of battery will increase
.A 7.5 kg bowling ball would require what force to accelerate it down an alleyway at a rate of
3.2 m/s² down the alley
Answers
Newton's second law tells us that force is directly proportional to mass and acceleration, such that:
F = m aWhere force is measured in newtons (N).
The three fundamental laws of Newton are:
Law of inertia: every body resists change.Force Law: Force equals mass times acceleration.Law of action/reaction: every action will have a particular reaction.Newton's laws are fundamental to understanding the interaction between bodies. Today they are still valid, although at the atomic level it has some exceptions that quantum mechanics studies.
A 7.5 kg bowling ball would require what force to accelerate it down an alleyway at a rate of 3.2 m/s² down the alley
Data:
m = 7.5 kg
F = ?
a = 3.2 m/s²
The formula to calculate the force is: F = m * a
We clear, but in this case it is not necessary, since we only want to calculate the force.
F = m * a F = 7.5 kg * 3.2 m/s² F = 24 NThe force you need to accelerate down the alley is 24 Newtons.
Planet X has a mass m and a radius r. Planet Y has a mass ½ m and a radius ¼ r. An identical tennis ball of mass mt sits on both planets’ surfaces. How does the magnitude of the gravitational force on planet X compare to the magnitude of the gravitational force on planet Y?
Answers
The gravitational force on planet X is one-eight (¹/₈) of the magnitude of gravitational force on planet Y.
What is the gravitational force on both planets?
The gravitational force on each planet is directly proportional to the product of mass of the planet and the tennis ball and inversely proportional to the square of the radius of the planets.
F = GmM/r²
where;
G is universal gravitation constantm is the mass of the tennis ballM is the mass of the planetsr is the radius of the planetThe gravitational force on planet X is written as;
F_X = Gm(mt) / r²
where;
m is the mass of planet Xmt is the mass of the tennis ballr is the radius of the planet xThe gravitational force on planet Y is written as;
F_y = G(½m)(mt) / (¼r)²
F_y = ½(Gm(mt) / (¹/₁₆ r²)
F_y = (16 Gm mt)/(2r²)
F_y = 8(G m(mt) ) / r²
F_y = 8(F_X)
F_X = ¹/₈(F_Y)
Learn more about gravitational force here: https://brainly.com/question/27943482
#SPJ1
A hot air balloon is rising upward with a constant speed of 3.80m/s. When the balloon is 4.25m above the ground, the balloonist accidentally drops a compass over the side of the balloon. How much time elapses before the compass hits the ground
Answers
We can calculate the time taken by the compass to hit the ground by using kinematic equations of motion. The motion of the compass is a free-fall motion since it is only under the influence of gravity. When the compass is dropped, it is initially at rest.
After that, it falls down to the ground with the acceleration due to gravity. Given that the balloon is rising upward with a constant speed of 3.80m/s. Hence, the velocity of the compass when it is dropped will be equal to the velocity of the balloon, which is 3.80m/s. The acceleration due to gravity is 9.81m/s². We can use the following kinematic equation of motion to calculate the time taken by the compass to hit the ground: `y = vi * t + 0.5 * a * t²`, where `y` is the height, `vi` is the initial velocity, `a` is the acceleration, and `t` is the time taken.We know that the initial height of the compass is 4.25m, the initial velocity is 3.80m/s, and the acceleration due to gravity is 9.81m/s². We need to find the time taken by the compass to hit the ground. Using the above kinematic equation, we get:`0 = 3.80t + 0.5 * 9.81 * t²`Simplifying the equation, we get:`4.905t² + 3.80t = 0`Factorizing the equation, we get:`t(4.905t + 3.80) = 0`Solving for `t`, we get:`t = 0` (since time cannot be negative)`t = -3.80/4.905 = -0.776s`We ignore the negative value of time since time cannot be negative. Hence, the time taken by the compass to hit the ground is `t = 0.776s`.Answer: `0.776s`For such more question on acceleration
https://brainly.com/question/460763
#SPJ8
A mass oscillates on a spring, bouncing up and down 5 times per second. From the highest position to the
lowest position of the mass is a distance of 16 cm.
Answers
Answer:
i kinda dnt knw srry wanted the points for the answer
Explanation:
A parallel plate capacitor with plates of area (A) and plate separation (d) is charged so that the potential difference between its plates is (V). While the capacitor is still connected to the power source and its plate separation is decreased to d/4, which statement is correct? The charge on the plates is decreased to one-fourth its original value. The capacitance is unchanged. The voltage between the plates is decreased to one-fourth its original value. The charge on the plates is increased four times its original value. The voltage between the plates is increased four times its original value. The charge on the plates is unchanged.
Answers
The correct statement is (d) The charge on the plates is increased four times its original value.
What is parallel plate capacitor?
A parallel plate capacitor is a type of capacitor that consists of two parallel conductive plates separated by a dielectric material. It is a type of capacitor used in electrical circuits to store electrical energy. The plates are usually made of metal and the dielectric material is usually a thin non-conductive material like paper or plastic. The size of the capacitor is determined by the distance between the plates and the dielectric material.
This is because the charge on the capacitor plates is proportional to the voltage across the plates and the capacitance, which is given by the formula C = ε_0 * A / d, where ε_0 is the electric constant and A is the area of the plates.
When the plate separation is decreased to d/4, the capacitance of the capacitor becomes C' = ε_0 * A / (d/4) = 4 * ε_0 * A / d, and thus the charge on the plates becomes Q' = C' * V = 4 * Q.
Therefore, The charge on the plates is increased four times its original value is the correct answer.
To learn more about parallel plate capacitor from the link
https://brainly.com/question/12733413
#SPJ4
an ac generator is connected across the terminals of a 3.25-µf capacitor. determine the frequency at which the capacitive reactance is 375 ω.
Answers
The frequency at which the capacitive reactance is 375 ω and the Capacitance of 3.25 μF is 131 s⁻¹.
Capacitance is the ability or capacity of the substance to collect and store electrical energy and the unit of capacitance is Farad (F). Capacitive reactance is the term that measures the opposition to current flow in the AC circuits and the unit of capacitive reactance is the ohm(Ω).
From the given,
The capacitive reactance (Xc) = 375ω
capacitance (C) = 3.25μF
capacitive reactance Xc = 1/(2π×f×C)
Frequency (f) = 1/(2π×Xc×C)
= 1/(2×3.14×375×3.25×10⁻⁶)
= 131 s⁻¹.
Thus, the frequency of the capacitive reactance is 131 s⁻¹.
To learn more about Capacitive reactance:
https://brainly.com/question/31871398
#SPJ1
In the past, people with severe mental illness sometimes had a surgery performed where doctors would remove or damage part of the frontal lobe. This surgery is referred to as
Answers
In the past, people with severe mental illness sometimes had a surgery performed where doctors would remove or damage part of the frontal lobe. This surgery is referred to as lobotomy.
What is a Surgery?This is referred to as the branch of medical practice that treats injuries, diseases, and deformities by the physical removal, repair, or readjustment of organs and tissues, often involving cutting into the body.
Lobotomy on the other hand is designed to treat a psychological condition and it involves using a sharp surgical tool to sever the neural connections between the frontal lobe, which controls higher cognitive functions, such as memory etc.
Read more about Surgery here https://brainly.com/question/5619846
#SPJ1